Which brand of fruit snacks costs less per pound? How much less?
Fruit Snacks
Brand A 55 lbs $59.40
Brand B 65 lbs $56.55
per pound.
Brand costs
less per pound
Brand A costs $? per pound. Brand B costs $? per pound.Brand A or B costs $? less per pound.
(Type integers or decimals.)

point slope form is

\(y-y_1 = m(x-x_1)\)

we can find m with

\(m = \frac{y_2-y_1}{x_2-x_1}\\ m = \frac{14-1}{-2-5} \\m = \frac{13}{-7} \\\)

\(y - 1 = \frac{-13}{7} (x-5)\\or\\y - 14= \frac{-13}{7} (x+2)\)

Answer:

2

Step-by-step explanation:

22/11=2

Answer:

7629.39453125

Step-by-step explanation:

The formula for the n-th term is:

\(k_n = \frac{5^{n-1}}{2^{n-2}}\)

So:

\(k_{10} = \frac{5^9}{2^8}\) = 1953125 / 256 = 7629.39453125

Answer:

7629.395 correct answer

The required GCF is 8.

The greatest common factor is that greatest number from the factors which divides the number completely.

For example take numbers 12 and 16.

The factors of 12 are 2×2×3.

And the factors of 16 are 2×2×2×2.

We can clearly see that the common factors are 2×2 which gives 4. So, 4 is the greatest common factor which divides both 12 and 16.

Here it is given to find the greatest common factor of 16 and 40.

Factors of 16 = 2×2×2×2

Factors of 40 = 2×2×2×5

We can see clearly the common factors are 2×2×2 which gives 8.

So, 8 is the greatest common factor.

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Answer:

54

Step-by-step explanation:

Given f(x) = 6(1 - x), what is the value of f(-8)?

F(-8)=6(1--8)        -- plug -8 into f(x) and x spots.

F(-)8=6(9)      ---then solve

F(-8)=54     --- so the function to f(-8) is 54

Answer:

n = 4

Step-by-step explanation:

36 = 13n - 4n

<=> 36 = (13-4).n

<=> 36 = 9n

<=> n = 36 / 9

<=> n = 4

1. The base pay Carter makes regardless of computer sales is $100

2. The linear relationship that shows the sales will be P = 100 + 10x

From the information given, Carter is a salesperson who sells computers at an electronics store and he makes a base pay amount each day and then is paid a commission for every computer sale he makes.

The starting salary is $100. This is the base pay.

The commission given is $10 per good sold. Therefore, the expression will be:

= 100 + 10x

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\( \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star\)

\(\textsf{ \underline{\underline{Steps to solve the problem} }:}\)

\(\qquad❖ \: \sf \: \angle1 \cong \angle2\)

( by corresponding angle pair )

\(\qquad❖ \: \sf \: \angle2 \cong \angle3\)

( given in the question )

\( \qquad \large \sf {Conclusion} : \)

\(\qquad❖ \: \sf \: \angle1 \cong \angle3\)

To find a vector v→4 such that the vectors v→1, v→2, v→3, and v→4 are orthonormal, the vector v→4 can be calculated as [0, -0.5, 0.5, -0.5].

For the vectors v→1, v→2, v→3, and v→4 to be orthonormal, they need to satisfy two conditions: they must be orthogonal (perpendicular to each other) and each vector must have a magnitude of 1 (unit length).

Given that v→1, v→2, and v→3 are provided, we can choose v→4 such that it is orthogonal to the other vectors and has a magnitude of 1. Since v→1, v→2, and v→3 are in R4, v→4 must also be a four-dimensional vector in R4.

Observing the pattern in the given vectors, we can see that v→4 can be chosen as [0, -0.5, 0.5, -0.5].

This vector satisfies the condition of orthogonality with v→1, v→2, and v→3 since its dot product with each of those vectors is zero.

Additionally, the magnitude of v→4 is

√(0^2 + (-0.5)^2 + 0.5^2 + (-0.5)^2) = √(0.5) = 1,

satisfying the condition of unit length.

Thus, v→4 = [0, -0.5, 0.5, -0.5] is a vector that makes the set of vectors orthonormal.

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Answer:

slope = - \(\frac{1}{2}\)

Step-by-step explanation:

calculate the slope m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (- 2, 1) and (x₂, y₂ ) = (2, - 1)

m = \(\frac{-1-1}{2-(-2)}\) = \(\frac{-2}{2+2}\) = \(\frac{-2}{4}\) = - \(\frac{1}{2}\)

Answer:

0.52

Step-by-step explanation:

250 females out of 479 total

250/479 = 0.5219206681

Rounded

0.52

The set 3 = y + 1 and x = -6 does not belong to the four sets of equations because it a linear equation with one variable.

Linear equation has only one variable. The linear equations in one variable is an equation which is expressed in the form of ax + b = 0, where a and b are two integers, and x is a variable and has only one solution

While simultaneous equations are two or more equations that are satisfied by the same set of values for the variables.

we can observe that the pairs;

y = 3x + 1

y = 3x - 1,

-2x + y = 2

-4x + 2y = 4 and,

y - 1 = 2(x + 4)

y + 3 = -5(x + 1)

all have more than one variable and can give the same set of values to satisfy for each pair.

But the set;

3 = y + 1 and x = -6 only have one variable each and will have only on solution.

In conclusion, only the set of equations 3 = y + 1 and x = -6 with one variable does not belong.

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\(\frac{18.6}{x} =0.02\)    X is the "something" in this problem

\(x=\frac{18.6}{0.02}\)

\(x=930\)

Hope this helped :)

This is the frequency distribution table for the given data set with a class width of 0.5 and a starting value of 97.0 degrees.

To construct a frequency distribution table for the given data set with a class width of 0.5 and a starting value of 97.0 degrees, we can follow these steps:

1. Determine the number of classes:

  To determine the number of classes, we calculate the range of the data by subtracting the smallest value from the largest value:

  Range = 99.4 - 97.0 = 2.4

  We can choose the number of classes as the range divided by the class width (0.5) and round it up to the nearest whole number:

  Number of classes = ceil(Range / Class width) = ceil(2.4 / 0.5) = ceil(4.8) = 5

2. Determine the class intervals:

  Starting with the given starting value (97.0 degrees), we can create class intervals by adding the class width repeatedly:

  Class intervals: 97.0 - 97.5, 97.5 - 98.0, 98.0 - 98.5, 98.5 - 99.0, 99.0 - 99.5, 99.5 - 100.0

3. Count the frequency of each class:

  Count how many data points fall into each class interval.

  - For the first class interval (97.0 - 97.5), we have:

    Frequency: 2 (97.1, 97.2)

  - For the second class interval (97.5 - 98.0), we have:

    Frequency: 4 (97.5, 97.6, 97.6, 97.8)

  - For the third class interval (98.0 - 98.5), we have:

    Frequency: 4 (98.0, 98.0, 98.2, 98.2)

For the fourth class interval (98.5 - 99.0), we have:

    Frequency: 5 (98.2, 98.3, 98.4, 98.6, 98.6)

  - For the fifth class interval (99.0 - 99.5), we have:

    Frequency: 4 (98.7, 98.7, 98.9, 99.1)

  - For the last class interval (99.5 - 100.0), we have:

    Frequency: 1 (99.4)

4. Create the frequency distribution table:

  Combine the class intervals and their corresponding frequencies into a table format.

  Class Interval   | Frequency

  -----------------|----------

  97.0 - 97.5      |     2

  97.5 - 98.0      |     4

  98.0 - 98.5      |     4

  98.5 - 99.0      |     5

  99.0 - 99.5      |     4

  99.5 - 100.0     |     1

This is the frequency distribution table for the given data set with a class width of 0.5 and a starting value of 97.0 degrees.

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Answer:

12x+6

x(12)+3  

Answer:

I would go with  B

Step-by-step explanation:

Among the options provided, the correct statement regarding multiple regression analysis is: b) Multiple regression analysis establishes a cause and effect relationship.

Multiple regression analysis is a statistical technique used to examine the relationship between a dependent variable and multiple independent variables. It aims to determine the extent to which the independent variables predict or explain the variation in the dependent variable.

However, it is important to note that multiple regression analysis alone cannot establish a cause and effect relationship between variables. While it can identify associations and quantify the strength of relationships, establishing causality typically requires additional evidence from experimental designs or other rigorous methods.

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Answer:

6553.6

Step-by-step explanation:

32^3 = 32 x 32 x 32 = 32768

32768 / 5 = 6553.6

Answer:

6,553.6

Step-by-step explanation:

32^3/5=6,553.6

Hope this helped!!

Bella was here :)

The most appropriate conclusion is: There is not enough evidence to conclude that the course improves SAT scores.

When conducting a hypothesis test, we start with a null hypothesis that assumes there is no difference or no effect between two groups or variables. In this case, the null hypothesis would be that the mean SAT score of students who took the course is not significantly different from the mean SAT score of students who did not take the course.

We then collect data and calculate a test statistic (such as a t-statistic) and a p-value. The test statistic measures the difference between the sample means and tells us how far apart they are in standard deviation units. The p-value measures the probability of observing the test statistic or a more extreme value if the null hypothesis is true.

If the p-value is smaller than the chosen level of significance (usually 0.05 or 0.01), we reject the null hypothesis and conclude that there is enough evidence to suggest that the two means are significantly different. If the p-value is larger than the chosen level of significance, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the two means are significantly different.

In this scenario, if the mean of the SAT scores of students who took the course is not significantly different from the mean of the SAT scores of students who did not take the course, it means that we failed to reject the null hypothesis. Therefore, we cannot conclude that the course has an effect on SAT scores. We can only say that there is not enough evidence to suggest that it does.

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Answer:

true

Step-by-step explanation:

if you rewrite \(sec\left(\frac{\pi }{2}\:-x\right)\) with trigonometric identities:

\(sec\left(\frac{\pi }{2}\:-x\right)\)    \(=\frac{1}{\sin \left(x\right)}\)

\(\frac{1}{\sin \left(x\right)}\)  \(=\csc \left(x\right)\)

so, yes,  \(sec\left(\frac{\pi }{2}\:-x\right)\)  \(=\csc \left(x\right)\)

hope this helps!!

The mode of the given data values is N/A (not applicable).Hence, the mean, median, and mode of the given data values are:Mean = 54.36Median = 55.5Mode = N/A (not applicable)

Given data values are 55, 56, 70, 61, 53, 57, 50, 73, 52, 69, and 2. We need to calculate the mean, median, and mode of this sample.So, let's first arrange the data values in ascending order:2, 50, 52, 53, 55, 56, 57, 61, 69, 70, 73

Mean:The mean is the sum of all the data values divided by the total number of data values. So, we can use the following formula to calculate the mean:

Mean = (sum of all the data values) / (total number of data values)Sum of all the data values = 55 + 56 + 70 + 61 + 53 + 57 + 50 + 73 + 52 + 69 + 2 = 598Total number of data values = 11

Therefore,Mean = (sum of all the data values) / (total number of data values) = 598 / 11 = 54.36 (rounded to two decimal places)Therefore, the mean of the given data values is 54.36.

Median:The median is the middle value of a sorted data set. Since the data set has 11 data values, the median is the average of the 6th and 7th values (counting from smallest to largest).

Therefore, the median is :Median = (55 + 56) / 2 = 55.5Therefore, the median of the given data values is 55.5.

Mode:The mode is the data value that appears most frequently in the data set. In this case, there is no data value that appears more than once. So, there is no mode.

Therefore, the mode of the given data values is N/A (not applicable).Hence, the mean, median, and mode of the given data values are:Mean = 54.36Median = 55.5Mode = N/A (not applicable)

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Answer:

y=7

y will equal to 7 when x is 2.5

The concentration of HCN that would produce a solution with a pH of 4.858 is approximately 1.17 x 10^(-5) mol/L.

To determine the concentration of HCN (hydrogen cyanide) that would produce a solution with a pH of 4.858, we can use the equation relating pH and the concentration of H+ ions in a solution:

pH = -log[H+]

First, we need to calculate the concentration of H+ ions corresponding to a pH of 4.858. Taking the antilog of both sides of the equation, we have:

[H+] = 10^(-pH)

[H+] = 10^(-4.858)

[H+] ≈ 1.17 x 10^(-5) mol/L

Since HCN is a weak acid, it partially dissociates in water, producing H+ ions. The concentration of HCN is equal to the concentration of H+ ions in the solution.

Therefore, the concentration of HCN that would produce a solution with a pH of 4.858 is approximately 1.17 x 10^(-5) mol/L.

Please note that the value provided is an approximation, and it is important to consider the temperature and other factors that might influence the dissociation of HCN in a solution.

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The regular polygon that has a rotation of 240 degrees to carry the polygon onto itself is the equilateral triangle.

Options

Equilateral triangle

Octagon

Rectangle

Pentagon

A polygon that can carry itself onto itself after a rotation of 240 degrees must obey the following rule:

Angle of rotation = 360/Sides

Next, we test the options:

Option (a) equilateral triangle

Angle of rotation = 360/3

Evaluate

Angle of rotation = 120

Next, we list the multiples of 120

120, 240, 360.....

See that 120 is a factor of 240.

This means that the equilateral triangle would be rotated onto itself when rotated by 240 degrees.

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The sum of first 100 terms of the series is  0.686 with error less than 0.00005

The given series is

Tₙ = \(\frac{1}{n_3 +1 }\)

Since, \(\frac{1}{n_3 +1 } < \frac{1}{n_3}\)

The given series is convergent by the comparison Test.

The remainder Tₙ for the comparison series ∑ 1/n³ was estimated in this example using the remainder estimate for the Integral Test.

There we found that

\(T_n \leq \int\limits^\infty_n {\frac{1}{x^3} \, dx\)

Solving the integration,

=> \(\int\limits^\infty_n \frac{-1}{2x^2}\, dx\)

=> \(\frac{1}{2n^2}\)

So, \(T_n \leq \frac{1}{2n^2}\)

Therefore , the reminder Rₙ for the given series satisfies

Rₙ ≤ Tₙ ≤ 1/2n²

with n = 100 we have

=> R₁₀₀ ≤ 0.00005

Using a programmable calculator , we find that

\(\sum^\infty_{n=1} \frac{1}{n^3 + 1} = \sum^\infty_{100=1} \frac{1}{n^3 + 1}\)

=>  0.686 (approximately)

with the error less than 0.00005

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On September 1, 2018, Dubai Company should record the following entry:

Debit: Cash (or Note Payable) - $120,000

Credit: Note Payable (or Cash) - $120,000

When Dubai Company borrows $120,000 from ADCB Bank by signing a 4-month, 12% interest-bearing note, they need to record the transaction in their books. The entry will depend on whether they received the cash or the note itself. If they received the cash, the entry would be a debit to Cash and a credit to Note Payable, both for $120,000. If they received the note, the entry would be a debit to Note Payable and a credit to Cash, both for $120,000.

The entry represents the initial recognition of the note payable on Dubai Company's books. It acknowledges the liability they have incurred by borrowing funds from ADCB Bank. The note payable will be due in 4 months and carries an interest rate of 12%. It is important for Dubai Company to accurately record this transaction to maintain proper financial records and fulfill their obligations to ADCB Bank.

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Answer:

0.001, 0.01, 0.1; it was already in ascending over :)

Hope this helps!

Answer:

0.001, 0.01, and 0.1

Step-by-step explanation:

Ascending order is least to greatest, and 0.1 is the greatest and 0.001 is the least. think if it as a fraction, what is more, 1/10 or 1/1000?

#1

Slope=

\(\\ \rm\Rrightarrow m=4-2/2-1=2\)

Equation in point slope form

\(\\ \rm\Rrightarrow y-2=2(x-1)\)

\(\\ \rm\Rrightarrow y-2=2x-2\)

\(\\ \rm\Rrightarrow y=2x\)

Graph attached

#2

Same like before

Equation of the line:-

\(\\ \rm\Rrightarrow y=3x\)

Graph attached