When you turn down the volume on the television, you reduce the _______ carried by the sound waves, so you also reduce their ________

Answer:

??????? umm what r u saying??? kinda confusing..............what does question why if you keep dieing in zombies on cold war u think im gunna rev you. i just got the key and the d.i.e remote and am geting the wonder wepon. but soon as that door explode you so quick to grab it you die. played me like a fool. why the heck you keep tryna exfil on round 15 BOI IF YOU DONT WQBFUFHJEWFHFNQC! packapunched knife to tier 1 head aS BOI!!! mean????????

very very very confusing

Explanation:

plz mark brainlyist :()

Standard atmospheric pressure is the average pressure exerted by the Earth's atmosphere at sea level under normal conditions. It is defined as 101.325 kPa or 1 atm and serves as a reference point for scientific measurements and comparisons related to atmospheric pressure.

Standard atmospheric pressure is the average pressure exerted by the Earth's atmosphere at sea level under normal conditions. It is defined as 101.325 kilopascals (kPa) or 1 atmosphere (atm). This pressure is used as a reference point for various scientific measurements and is crucial in fields such as meteorology, physics, and engineering.

Atmospheric pressure is caused by the weight of the air above a given point on the Earth's surface. The air is composed of molecules, mainly nitrogen (approximately 78%) and oxygen (approximately 21%), along with other trace gases. These molecules are in constant motion and exert a force on the surfaces they come into contact with, including the Earth's surface.

The standard atmospheric pressure of 101.325 kPa is equivalent to the pressure exerted by a column of mercury 760 millimeters (mm) in height in a barometer at sea level. This measurement was established as a reference point for atmospheric pressure, providing a consistent value for scientific calculations and comparisons.

It is important to note that atmospheric pressure can vary with altitude and weather conditions. As altitude increases, the atmospheric pressure decreases because the column of air above becomes thinner. In areas of high or low pressure systems associated with weather patterns, the atmospheric pressure deviates from the standard value.

The standard atmospheric pressure is a valuable reference in many applications. For instance, it is used as a standard for measuring gas pressure in laboratories and industrial processes. It is also used in meteorology to calculate and compare pressure systems and to study atmospheric phenomena such as wind patterns and weather changes.

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Final Answer:

If there is lower air pressure being "pushed" onto the surface of the water, then the water molecules do not need as much energy to overcome the force of atmospheric pressure pushing on the surface, and they can more easily escape and become a vapor. When the vapor pressure of the liquid is equal to the air pressure surrounding the liquid, it will boil. If you lower the air pressure, you will lower the temperature that water will boil at.

Explanation:

The boiling point of a liquid depends on the balance between the vapor pressure of the liquid and the external pressure, which is typically atmospheric pressure. When the external pressure is reduced, such as at higher altitudes or in a vacuum, the liquid molecules require less energy to escape the surface and become vapor. This is because there is less force pushing down on the liquid's surface, allowing for easier vaporization.

At lower air pressure, the water molecules can overcome the diminished force of atmospheric pressure more readily, requiring less heat energy to transition from liquid to vapor. When the vapor pressure of the liquid equals the surrounding air pressure, the liquid will start to boil.

Boiling point and vapor pressure are fundamental concepts in thermodynamics and phase transitions. Understanding how pressure affects the boiling point of liquids is crucial in various scientific and engineering applications, such as cooking, chemical processes, and high-altitude cooking.

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A wool sweater worn under a cotton jacket produces more static charges.

Static charge is an imbalance of electric charges within or on the surface of a material or between materials.

Static charges can be produced by two materials together (friction method).

A wool sweater worn under a cotton jacket (in the absence of lubricant like water) creates friction which enables more static charge to be produced.

Thus, a wool sweater worn under a cotton jacket produces more static charges.

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Answer:

the correct answers is a      W' = 6.2 N

Explanation:

In this exercise they give the description of a simple pendulum, its angular velocity

          w = \(\sqrt { \frac{g}{l} }\)

angular velocity is related to frequency and period

          w = 2π f = 2π / T

we substitute

          T = 2π \sqrt { \frac{l}{g} }  

          T² = 4π²  \(\frac{ l}{g}\)

With the period on Earth we can find the length of the pendulum

         l = \(\frac{ T^{2} g}{4 \pi ^2 }\)

         l = \(\frac{ 1^2 9.8}{ 4 \pi ^2}\)

         l = 0.25 m

this longitude is maintained on planet X, so we can find the value of the acceleration of gravity (g ’) on that planet

         g’ = \(\frac{4 \pi ^2 l}{T'^2}\)

          g’ = \(\frac{4 \pi ^2 0.25}{ 1.8^2}\)

          g’ = 3.05 m / s²

therefore the weight of the body on this planet is

           W ’= m g’

the mass is invariable in all systems

           W ’= 2.0 3.05

           W ‘= 6.1 N

When examining the correct answers is a

Answer:

I. force

II. electricity.

III. energy.

iv. pressure.

v. volume.

Answer:

The horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g.

Explanation:

This is because, the projectile has both vertical and horizontal components of velocity. But, its vertical component of velocity changes as the object moves whereas, its horizontal component of velocity remains constant.

Also, the projectile has only vertical component of acceleration and no horizontal component of acceleration since, its horizontal component of velocity remains constant. Thus, no change in the horizontal component of velocity.

The vertical component of acceleration is equal to -g since, the weight is the only vertical force acting on it.

So, the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g.

Both the balloon are gaining a negative charge by rubbing on the wool. Two like charges will repel each other. Therefore, the balloons will repel each other.

When a material rub on a surface (conducting or non-conducting) the material gets negatively charged by the flow of electrons. When this negatively charged material comes in contact with other object it will temporarily polarize the second one and gets attracted. This is called static electricity where the electrons pass from to positive pole of the polarised object.

Here, when the balloons are rubbed on the sweater wool, they gets a negative charge. Two negatively charged objects will repel each other. Hence the balloons will repel each other.

The distance up to which the balloons repel depends on the magnitude of charge they gained. If these balloons comes in a contact with other neutral object it will attracts to it by polarizing it.

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Answer:

\(\pi 1 = \frac{h}{l}\)

\(\pi 2 =\) б / \(l^2gp\)

\(\frac{h}{l} =\) Ф ( б / \(l^2gp\) )

Explanation:

Develop a suitable set of dimensionless parameters for this problem

The set of dimensionless parameters for this problem is :

\(\pi 1 = \frac{h}{l}\)

\(\pi 2 =\) б / \(l^2gp\)

\(\frac{h}{l} =\) Ф ( б / \(l^2gp\) )

and they are using the pi theorem, MLT systems

attached below is a detailed solution

Answer:

Oh! I just learned abt this

Explanation:

the body is said to be in equilibrium if it is resting or moving with uniform velocity.

Answer: The body is said to be in balance if it is at rest or moving at a uniform speed. In other words, if the body's linear and angular acceleration is zero, the body is said to be in balance. 1

The equation to calculate the approximate volume of Mercury (or any sphere) is:

V = (4/3)πr^3

Where V is the volume, π (pi) is a mathematical constant approximately equal to 3.14159, and r is the radius of the sphere.

Therefore, to calculate the approximate volume of Mercury, we can use the equation:

V = (4/3)π(1516)^3

Answer:

3 x 10⁻⁹km

3 x 10⁻⁴cm

2.73 x 10⁶μm

Explanation:

 A micron is a subunit of measurement usually for length dimensions.

                     1μm   = 1 x 10⁻⁶m

a. How many microns make up 3km;

         Now convert to meter first;

                 1000m  = 1km

           So, 3km will be made up of 3000m

So;

          1 x 10⁻⁶m    =     1μm  

         3000m  =   \(\frac{3000}{1 x 10^{-6} }\)   = \(\frac{3 x 10^{3} }{ 1 x 10^{-6} }\)   = 3 x 10⁻⁹km

b.  How many centimeters equal 3.0 μm?

            Since;

                        1μm   = 1 x 10⁻⁶m

                         3μm  = 3 x 1 x 10⁻⁶  = 3 x 10⁻⁶m

So;

            100cm  = 1m;

                  1m  = 100cm

             3 x 10⁻⁶m  = 3 x 10⁻⁶  x 10²   = 3 x 10⁻⁴cm

c. How many microns are in 3.0 yd?  

              1yd  = 0.91m

              3yd  = 3 x 0.91  = 2.73m

So;

            1 x 10⁻⁶m    =     1μm  

              2.73m will give \(\frac{2.73}{1 x 10^{-6} }\)   = 2.73 x 10⁶μm

A featureless ice giant with layers of methane and water vapor is Kepler-47c. Any planet that has been discovered outside of our solar system is an exoplanet.

Nearly all of the 866 exoplanets known as of June 2013 are found within the Milky Way Galaxy, orbiting 671 stars. The first exoplanet found that is a component of a multi-planet system orbiting two stars is Kepler-47c.

Kepler-47c is an ice giant, almost the same size as Neptune. It is located in the area of its host star known as the habitable zone, which is where liquid water may exist on a planet's surface.

Planets located in this region are more likely to be livable worlds since liquid water is an essential component of life.

Therefore, A featureless ice giant with layers of methane and water vapor is Kepler-47c. Any planet that has been discovered outside of our solar system is an exoplanet.

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A.  The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min

A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:

EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.

Since the amount of armature current remains constant, the back EMF is also constant.

Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:

IF = (250 V - EA)/(RF + R₁)

At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.

If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.

Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:

kϕN/IF1 = kϕN/IF2

N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min

Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:

N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min

where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.

Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.

A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.

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The sentence that describes anxiety best is a) Anxiety episodes are normal, during them people experience worry about every situation

The paragraph explains that while having the odd attack of anxiety is natural, anxiety disorders are characterised by severe, excessive, and chronic concern and terror over ordinary events. It also clarifies how anxiety disorders can cause recurrent episodes of extremely severe panic.

A sensation of worry, dread, and unease is known as anxiety. Sweating, agitation, and tension may be experienced, along with a quick heartbeat. It might be a typical response to stress. For instance, while dealing with a challenging issue at work, one can have anxiety prior to a test or when making a crucial choice. A person may find it useful for coping. For some with anxiety disorders, the terror can be incapacitating and last for a long time.

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The torque about the axis of rotation on the left produced by force F1onB is 600 Nm and the torque about the axis of rotation on the left produced by force F2onB is also 600 Nm. Force F3onB must be exerted at a distance of 0.5 m from the axis of rotation to balance the torques produced by F1onB and F2onB.

F1onB Torque: 600 Nm

F2onB Torque: 600 Nm

F3onB Distance: 0.5 m

1. To determine the torque about the axis of rotation on the left produced by force F1onB, we need to calculate the moment arm. The moment arm is the perpendicular distance from the axis of rotation to the line of action of the force. The moment arm for F1onB is 0.5 m, so the torque produced by F1onB is 600 Nm (F1onB x Moment Arm).

2. To determine the torque about the axis of rotation on the left produced by force F2onB, we need to calculate the moment arm. The moment arm for F2onB is 0.5 m, so the torque produced by F2onB is also 600 Nm (F2onB x Moment Arm).

3. To determine the distance from the axis of rotation at which F3onB must be exerted to balance the torques produced by F1onB and F2onB, we need to use the equation Torque = Force x Moment Arm. Since the total torque must equal 0, we can set up the following equation: 600 Nm + 600 Nm + (F3onB x Moment Arm) = 0. Solving for the Moment Arm, we get Moment Arm = -0.5 m, which is the distance from the axis of rotation at which F3onB must be exerted to balance the torques produced by F1onB and F2onB.

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Answer:

7.5 × 10^14 Hz

Velocity of light = 3×10^8m/s

Frequency = (3×10^8)/(4 x 10^-7)

= 7.5 × 10^14 Hz

Explanation:

Q1. Given:

v = 0 m/s

a = -5.5 m/s²

t = 3.5 s

Find: Δx

Δx = vt − ½ at²

Δx = (0 m/s) (3.5 s) − ½ (-5.5 m/s²) (3.5 s)²

Δx ≈ 33.7 m

Q2. Given:

Δx = 400 m

v₀ = 7.0 m/s

v = 35 m/s

Find: a

v² = v₀² + 2aΔx

(35 m/s)² = (7.0 m/s)² + 2a (400 m)

a = 1.47 m/s²

The length of the pendulum is measured from the lower part of the wooden clamp, because the center of gravity is at the center of the bob.

The simple pendulum's length, l is determined by measuring it from the point of suspension to the center of gravity (center of the bob), which is the place where all of this sphere's mass is concentrated.

The center of the mass will exactly reside in the center of the bob when we take the bob's dimensions into account.

As a result, the total length is now equal to the length of the string plus the bob's radius. The length is thus measured from the lower part of the wooden clamp.

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We need the position vectors of a particle at two points along its path and also know the time it took to move from one point to the other to find the instantaneous velocity but not the average velocity.

We need to take a moment to be able to explain to ourselves again the meaning of the term velocity. Let us recall that the term velocity would have to do with the change in the position of an object with time.

We know that the velocity is a vector quantity and as such we must have to look at the direction in which the distance that has been covered has passed through and this is something that we must keep in  mind as we work through this question.

Now, we know that the velocity is the change in position as such we need the two positions of the object and the approximate time taken to make the change.

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Answer:

the  acceleration of the Ping Pong ball is  200 m/s²

Explanation:

Given;

mass of  Ping Pong ball, m = 0.0029 g = 2.9 x 10⁻⁶ kg

mass of tennis ball, m = 0.058 g = 5.8 x 10⁻⁵ kg

acceleration of the tennis ball, a = 10 m/s²

The force applied to the tennis ball is calculated as;

F = ma

F = 5.8 x 10⁻⁵ x 10

F =  5.8 x 10⁻⁴ N

The acceleration of the Ping Pong ball is calculated as;

a = F/m

a = ( 5.8 x 10⁻⁴ N) / (2.9 x 10⁻⁶)

a = 200 m/s²

Therefore, the  acceleration of the Ping Pong ball is  200 m/s²

Answer:

Explanation:

(a) To find the density of the oil, we can use the formula for pressure difference in a fluid column:

ΔP = ρgh

where ΔP is the pressure difference, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height of the fluid column.

Plugging in the given values, we have:

0.125 atm = ρgh = ρ(9.81 m/s^2)(1.50 m)

Solving for ρ, we get:

ρ = 0.125 atm / (9.81 m/s^2 x 1.50 m) ≈ 0.00847 g/cm^3

Therefore, the density of the oil must be approximately 0.00847 g/cm^3.

(b) On Mars, the acceleration due to gravity is 0.379 times that of Earth, or g_Mars = 0.379g_Earth. The pressure difference between the top and bottom of the oil column will be:

ΔP_Mars = ρgh_Mars = ρg_Earth(0.379)(1.50 m)

Using the density we found in part (a), we have:

ΔP_Mars = (0.00847 g/cm^3)(9.81 m/s^2)(0.379)(1.50 m) / (1 atm/101325 Pa)

ΔP_Mars ≈ 0.019 atm

So, the pressure difference between the top and bottom of the oil column on Mars will be approximately 0.019 atm, or about 0.15 times the pressure difference on Earth.

Answer:

The pressure difference (in Earth's atmosphere) between the top and bottom of the oil column on Mars is 0.045 atm.

Explanation:

(a) To find the density of the oil, we can use the formula for pressure difference in a fluid column: ΔP = ρgh, where ΔP is the pressure difference, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height of the fluid column.

We know that the pressure difference is 0.125 atm, the height of the column is 1.50 m, and the acceleration due to gravity on Earth is 9.81 m/s². Plugging in these values, we get:

0.125 atm = ρ(9.81 m/s²)(1.50 m)

Solving for ρ, we get:

ρ = 0.00803 g/cm³

Therefore, the density of the oil must be 0.00803 g/cm³.

(b) If the vehicle is taken to Mars, where the acceleration due to gravity is 0.379g, we can use the same formula to find the pressure difference:

ΔP = ρgh

We know that the height of the column is still 1.50 m, but the acceleration due to gravity is now 0.379g. Plugging in these values, we get:

ΔP = (0.00803 g/cm³)(9.81 m/s²)(0.379)(150 cm)

Solving for ΔP, we get:

ΔP = 0.045 atm

Therefore, the pressure difference (in Earth's atmosphere) between the top and bottom of the oil column on Mars is 0.045 atm.

Answer: 44.76 kg

Explanation: There are two options for formulas to use here.

0=(m1)(V1f)+(m2)(V2f)

Or

(m1)(V1f) = —(m2)(V2f)

Both formulas should give you an answer of 44.763514, which can be rounded to the specifications of whatever your curriculum or teacher wants. Most likely 44.76.

Blessings to all of you in the Name of Jesus Christ our Savior!

The middle ear compensates through 1) the area ratio of the tympanic membrane to the oval window (about 17x) and 2) the ossicular lever action (about 1.3x).

A) Due to impedance mismatch, only a small fraction of sound energy enters the liquid (Z2) from air (Z1).

Transmission coefficient T = 4Z1Z2/(Z1+Z2)^2. Assuming Z1=1 (air) and Z2=3400 (water), T ≈ 0.001, meaning 0.1% sound energy enters the liquid, while 99.9% is reflected.

B) Loss in dB = 10*log10(1/T) ≈ 30 dB.

The middle ear compensates through 1) the area ratio of the tympanic membrane to the oval window (about 17x) and 2) the ossicular lever action (about 1.3x).

Combined, they provide 22x amplification (27 dB). Both mechanisms contribute significantly to compensate for the loss.

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Answer:

W = 1,049 10⁹ J

Explanation:

Work is defined by the relation

         W = F. d = F d cos θ

where tea is the angle between the forces and the displacement.

The total work is the sum of the work of each tug.

Tug 1

       W₁ = F d cos θ₁

the angle measured from the positive side of the x-axis is

       θ₁ = 14 + 90 = 104º

tugboat 2

             W₂ = F d cos θ₂

             θ₂ = 14

we substitute

             W = F d cos θ₁ + F d cos θ₂

             W = F d (cos θ₁ + cos θ₂)

let's calculate

             W = 1.80 10⁶  800 (cos 104 + cos 14)

             W = 1,049 10⁹ J

Answer:

the magnetic field is leaving the sheet

Explanation:

The magnetic force is given by the expression

        F = q v x B

where bold letters indicate vectors, the modulus of this expression is

       F = q v B sin θ

the direction of the force is given by the right hand rule, for a positive charge

the thumb indicates the direction of the speed, in this case from right to left

the palm the direction of the force, in our case upwards

the fingers extended the direction of the magnetic field, this case after fixing the other two components it points out of the blade

In short the magnetic field is leaving the sheet

Explanation:

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According to the give value of the mass of lemonade and change in the temperature, the specific heat capacity of the lemonade is 3.81 J/kg/k.

The formula for the specific heat capacity (C) = Q/ m × ΔT

Q is energy added and the value, which is 334J

m is the mass of the lemonade, which is 300g = 0.3 kg

Δ T is the change in temperature, which is 19°C =(273+19)= 292 K

So, C = 334/ 0.3 × 292

         = 3.81 J/kg/k

So the specific heat capacity of the lemonade is 3.81 J/kg/k.

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Answer:

According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Since Sharon's puck stops after the collision, all of its momentum is transferred to Kaylyn's puck. Therefore, the resulting momentum of Kaylyn's puck is equal to the initial momentum of Sharon's puck:

m1v1 = m2v2

where m1 and v1 are the mass and velocity of Sharon's puck before the collision, and m2 and v2 are the mass and velocity of Kaylyn's puck after the collision.

Substituting the given values:

0.3 kg × 6 m/s = 0.3 kg × v2

Simplifying:

1.8 kg m/s = 0.3 kg × v2

Dividing both sides by 0.3 kg:

v2 = 6 m/s

Therefore, the resulting velocity of Kaylyn's puck should be equal to the velocity of Sharon's puck before they collided, which is 6 m/s.

Answer: A. Equal to the velocity of Sharon's puck before they collided.

Answer:

4.47

Explanation:

Given data

vector 1 = 2m/s

vector 2= 4 m/s

The expression for the magnitude of two vectors is

|a| = √v1^2+ v2^2

substitute

|a| = √2^2+ 4^2

|a| = √4+ 16

|a| = √20

|a| = 4.47

Hence the magnitude of the two vectors is 4.47