When you open the door to your house on a cold day, you feel a cold draft. What causes this?

Answer:

no

Explanation:

its made of a living organisim which in this case is oats

The average rate of the reaction during the time interval is 0.00176 M/s.

The chemical equation is as :

2HBr(g)  ---->  H₂(g)  +  Br₂(g)

a. The Rate of the reaction is the defined by the change in the concentration of the reactants and the change in the concentration of the product per unit time.

The rate of the reaction is as :

Rate = -1/2(Δ(HBr)/Δt = Δ(H₂)/Δt =Δ(Br₂)/Δt

b. Average rate of reaction after the 25 sec :

The rate = -1/2Δ(HBr)/Δt

The rate = -1/2 (0.512 M - 0.6 M)/(25 s-0 s)

The rate = -1/2 (-0.088)/25

The rate = 0.00176 M/s

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This question is incomplete, the complete question is :

Consider the reaction 2 hbr (g) ---> h2 (g) + br2 (g)

a.  express the rate of the reaction in terms of the change in concentration of each of the reactants and products.

b. in the first 25.0 s of this reaction, the concentration of hbr drops from 0.600 m to 0.512 m. calculate the average rate of the reaction during this time interval.

Answer:

Full answer in explanation

Explanation:

Hope this helps!

Answer:

Ans no 1. As magnesium used to react with oxygen and due to the reaction the mass (weight) of magnesium increases , this reaction between oxygen and magnesium which form magnesium oxide in the air by forming white smoke increases the mass of magnesium

Answer:

WATER

Explanation:

Water melting  point 0 c boiling 100c

The number of electrons present in the outermost shell is called valence electrons.

The number of electrons present in the last shell is called valence electrons. The atomic number of sodium is 11 and the atomic number of oxygen is 8.

There is 1 valence electron in sodium. The number of valence electrons in oxygen is 2.

The atomic number of iodine is 53. The number of the valence electron in iodine is 1. The atomic number of calcium is 20. The valence electron in calcium is 2.

Therefore, The number of electrons present in the outermost shell is called valence electrons.

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In this question, we need to find the value of pressure of a 15 grams sample of CO2 gas, and in order to find this value, we will be using the Ideal gas law formula, which is the following:

PV = nRT

Where:

P = pressure in atm

V = volume in liters, 20 Liters

n = number of moles

R = gas constant, 0.082

T = temperature in kelvin, 0°C = 273 K

The number of moles we need to find based on the mass in the question and based on the molar mass of CO2, 44g/mol:

44g = 1 mol

15g = x moles

44x = 15

x = 15/44

x = 0.34 moles of CO2 in 15 grams

Now we have the values to add to the formula:

P * 20 = 0.34 * 0.082 * 273

20P = 7.61

P = 7.61/20

P = 0.38 atm of pressure

The pressure will be 0.38 atm

Answer:

3 electrons

Explanation:

Nitrate needs 3 electrons to achieve a stable electron configuration

Three is the answer. it needs three to complete its shell

The net entropy change of the gas and its environment during the cycle is zero, as it is a closed cycle.

The net entropy change of the gas and its current circumstance during the cycle displayed in the p-V outline can't be resolved exclusively from the data given. Nonetheless, since process b-c is isothermal, the entropy change of the gas during that interaction is given by Q/T, where Q is the intensity consumed by the gas and T is the outright temperature at which the cycle happens. Since the interaction is isothermal, T is steady, so the entropy change of the gas during b-c is relative to Q. Assuming Q is positive, the entropy change of the gas is positive, implying that the gas ends up being more scattered during that cycle.

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The complete question is:

An ideal gas is taken around the cycle shown in this p-V diagram, from a to btoc Pb and back to a. Process b c is isothermal. What can you conclude about the net entropy change of the gas and its environment during the cycle? a) It is zero. b) It is positive c) It is negative. d) Two of A, B, and C are possible. e) All three of A, B, and C are possible 0 Two point charges and a point P lie at the vertices of an equilateral triangle as shown. Both point charges have the same magnitude q but opposite signs. There is nothing at point P. The net electric field that charges #1 and #2 produce at point P is in a) the ty-direction b) the-y direction c) the +x-direction. d) the-x-direction. ) none of the above. ) Charge #1 -q +q Charge #2 Constants R 8.314 mol K Isochoric Isobaric sothermal Adiabatic Constant Constant Constant No heat volume pressure temperature transfer Cice = 2.00e3 kg c steam2.00e3 kg c for water = 33.Se4 し,for water = 226e5 Na = 6,022e23- (efficiency) (carnot efficiency) On QH molecules .nole (adiabats only) (adiabats only) Nm pyr = constant TV"-1 = constant W71İ(pik-P2V2) (adiabats only) Any other needed constants should be given in the problems Heat and Temperature TKelvin = TCelcius + 273.15 EtotalB Misc Density 1 Dimension Thermal properties of matter Uniform (p+ (V-nb) = nRT NonUniform dm dL For Ideal Gas dm dA Ker = nRT (for degrees of freedom f) dv Valatonn.-5, Ynonatomic = 3 nonconservative forces-ΔΕ AL-Texternalt

KSCN or potassium thiocyanate will degrade the sample overtime. Therefore, we need to wait to add kscn to add just before absorbance measurements.

Potassium thiocyanate is a chemical compound used for the electroplating of metal surface and also used as an analytical reagent in colorimeter tests.

    Colorimeter is a device used for calculating the concentration of a sample or the absorbance of a sample through a certain wavelength of polarized light. Colorimeter runs on the application of Beer-Lambert's law also known as Beer's law that states that, the absorbance and concentration of a solution is directly proportional to each other.

    According to Beer-Lambert's law, we need to add a certain reagent such as- potassium thiocyanate or biuret's reagent to the solution as they deviate the polarized light and given the reading of the absorbance of the solution. Even though, the reagents help us in getting the correct result of the colorimetry test, it can also degrade the solution by breaking the compounds present in the solution.

Thus, we need to add the reagents right before taking the reading to prevent any kind of mishappening.

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D represents 222, E represents 86, F represents 234 and G represents 90.

These two chemical processes are an example of an alpha decay process. The process of heavier nuclei decaying into lighter nuclei and producing an alpha particle is known as alpha decay. The alpha particle also referred to as a helium nucleus, has a charge of +2 units.

\(\frac{A}Z} X=\frac{A-4}{Z-2} Y + \frac{4}{2} He\)

The isotope that was created has an atomic mass that is 4 units less and an atomic number that is 2 units less.

In the chemical equations, then:

\(\frac{86}{226}Ra =\frac{84}{222} Rn + \frac{4}{2} He\)

D stands for 222, and E for 86.

\(\frac{92}{238}U =\frac{90}{234}Rn + \frac{4}{2} He\)

F represents 234 and G represents 90.

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Answer:

0.895 mL

Explanation:

Using the formula;

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information provided in this question;

C1 = 15.54M

V1 = ?

C2 = 2.28M

V2 = 6.1 mL

Using C1V1 = C2V2

V1 = C2V2 ÷ C1

V1 = (2.28 × 6.1) ÷ 15.54

V1 = 13.908 ÷ 15.54

V1 = 0.895 mL

Answer:

write in English bro? can you?

Explanation:

I can't understand your language sorry .

C) Lacquer is the material made from the sap of a tree.

Lacquer is a material derived from the sap of the lacquer tree, scientifically known as Rhus vernicifera. The sap, commonly referred to as lacquer or resin, is harvested by making incisions in the bark of the tree. It is then collected and processed to create lacquer, which has been used for centuries in various cultures for decorative and protective purposes.

The sap of the lacquer tree undergoes a specific curing process that involves exposure to moisture and air. This process results in the formation of a durable and glossy finish. The lacquer can be applied to different surfaces, including wood, metal, or even paper, creating a smooth and shiny coating that enhances the appearance and provides protection against moisture and wear.

It is important to note that glaze, jade, and porcelain are not materials derived from the sap of a tree. Glaze refers to a glass-like coating applied to ceramics, while jade is a mineral used for carving and jewelry. Porcelain, on the other hand, is a type of ceramic material composed of clay, feldspar, and other minerals.

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The fully balanced redox reaction for K2C2O4 + KMnO4 is 10H2C2O4 + 16H+ + 2MnO4- → 2Mn2+ + 10C2O4^2- + 8H2O.

The fully balanced redox reaction under acidic conditions for the given reaction, K2C2O4 + KMnO4, can be constructed using the following half-reactions:

Oxidation Half-Reaction: 2H2C2O4 + 2H+ + 2e- → C2O4^2- + 2H2O

Reduction Half-Reaction: 5e- + 8H+ + MnO4- → Mn2+ + 4H2O

By multiplying the oxidation half-reaction by 5 and the reduction half-reaction by 2, we can ensure that the electrons will cancel out when the two half-reactions are combined. This results in the fully balanced redox reaction:

10H2C2O4 + 16H+ + 2MnO4- → 2Mn2+ + 10C2O4^2- + 8H2O

Therefore, under acidic conditions, the fully balanced redox reaction for K2C2O4 + KMnO4 is 10H2C2O4 + 16H+ + 2MnO4- → 2Mn2+ + 10C2O4^2- + 8H2O.

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Answer:

What can cause excessive pressure on the high side of an active self-contained recovery device? A closed recovery tank inlet valve or excessive air or other non condensables in the recovery tank (either A or B) Portable refillable tanks or containers used to ship recovered refrigerants must meet what standard(s)?

Explanation:

please mark me as brainliest thank you

Answer:

A because density DOES have a unit

Explanation:

Answer:

See explanation

Explanation:

Tyndall effect refers to the scattering of light in a solution. Tyndall effect occurs when the size of particles in the solution exceeds 1 nm in diameter. Such solutions are actually called false solutions.

In tincture of iodine, the size of particles in solution is less than 1 nm in diameter hence the solution does not exhibit Tyndall effect. Hence, tincture of iodine is a true solution.

Therefore, if the size of particles in solution exceeded 1nm in diameter, Tyndall effect is observed.

Answer:

368.92g

Explanation:

Firstly, let's balance the equation which is

2NO + O₂ ---> 2NO₂

Starting with 8.02 mol of NO let's calculate the moles of oxygen which is in a 2 : 1 molar ratio

2NO + O₂

2 : 1

8.02 mol : x mol

Moles of O₂ = 8.02 ÷ 2 = 4.01 mol

Doing the same thing for 18.75 mol of O₂ to calculate the number of moles of NO

2NO + O₂

2 : 1

x mol : 18.75 mol

Moles of NO = 18.75 × 2 = 37.5 however we are told we have 8.02 moles of NO, so we are unable to use 18.75 mol of O₂

Using 8.02 mol of NO to figure out the number of moles of NO₂ :

2NO : 2NO₂

They have the same molar ratio of 2 : 2, so the number of moles is 8.02

Using formula moles = mass / Molar mass

Rearranging to find mass = moles × molar mass

Molar mass of NO₂ = 14 + 16 + 16 = 46

Mass = 46 × 8.02 = 368.92g

Reaction:

2NO + O₂ → 2NO₂

determine the limiting reactant from the ratio of moles to the reaction coefficient

NO : O₂ = 8.02/2 : 18.75/1 = 4.01 : 18.75

NO as a limiting reactant (smaller ratio)

so mole NO₂ from limiting reactant (NO) :

= 2/2 x mole NO

= 2/2 x 8.02

= 8.02

mass NO₂ = mole x molar mass NO₂ = 8.02 x 46 g/mole = 368.92 g

Volume of ether required = 46ml

Fraction of solute present in water = q = \((\frac{Veq}{KdVeq + Veq}) ^{n}\)

0.304965 = 140/(7Veq + 140)

(7Veq + 140) = 140/0.304865 = 459.0698

Veq = 319.0698 / 7 = 45.5814 = 45.6ml

Volume of ether required = 46ml

Ethers are a type of compounds in organic chemistry that have an ether group—an oxygen atom joined to two alkyl or aryl groups. They are represented by the generic formula ROR′, where R and R′ stand for the alkyl or aryl groups. Ethers can be further divided into two types: symmetrical and unsymmetrical. Symmetrical ethers are those that have the same alkyl or aryl group on both sides of the oxygen atom, whereas unsymmetrical ethers have distinct groups. [1] Diethyl ether, sometimes known as "ether" (CH3CH2OCH2CH3), is a common example of the first group and serves as both a solvent and an anaesthetic. Since ethers are frequent connections in carbohydrates and proteins, they are also frequent in organic chemistry and even more so in biochemistry.

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Answer:

B & D

Explanation:

hey there,

< The answers you put are correct.

Products are the result. In this reaction, it would be PbCl2, Cl2, and H2O but H2O is not an answer choice so it would just be the other two. >

Hope this helped! Feel free to ask anything else.

Answer:

A answer is write answer

By utilizing microwave heating in the Fischer esterification reaction, researchers can achieve shorter reaction times, higher yields, and improved reaction efficiency compared to traditional heating methods.

“Heating” is a traditional technique known to humanity. It has been everchanging the way we live. There are an innumerable ways in which we have been generating heat and using the heat to do work. One of the key applications of “heat” has been the Industrial Process Applications.

One reaction that may be made more efficient using microwave (MW) heating is the synthesis of esters through the Fischer esterification reaction.

In the Fischer esterification, an alcohol reacts with a carboxylic acid in the presence of an acid catalyst to form an ester. The traditional heating method for this reaction involves refluxing the reaction mixture for several hours to achieve reasonable yields.

Using microwave heating in the Fischer esterification reaction can significantly reduce the reaction time and increase the reaction efficiency. MW heating provides rapid and efficient heating by directly transferring energy to the reactants, resulting in faster reaction rates and higher yields.

The MW heating method allows for more precise temperature control and selective heating of the reaction mixture. It can also promote better mixing and faster mass transfer, which enhances the reaction kinetics and reduces the formation of undesired by-products.

Overall, by utilizing microwave heating in the Fischer esterification reaction, researchers can achieve shorter reaction times, higher yields, and improved reaction efficiency compared to traditional heating methods.

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a. Solution B: [H₃O⁺] = 9.87x10⁻⁹ M; [OH⁻] = (molar)

b. Solution C: [HCl] = 0.123 M; pH =

c. Solution D: pH = 2.1; [OH⁻] = (molar)

a. In Solution B, the concentration of hydronium ions ([H₃O⁺]) is given as 9.87x10⁻⁹ M. This indicates the acidity of the solution. The concentration of hydroxide ions ([OH⁻]) is not provided.

b. In Solution C, the concentration of hydrochloric acid ([HCl]) is given as 0.123 M. To determine the pH, we need to calculate the negative logarithm of the hydronium ion concentration. pH = -log[H₃O⁺].

c. In Solution D, the pH is given as 2.1. This indicates the acidity of the solution. The concentration of hydroxide ions ([OH⁻]) is not provided.

To calculate the concentration of hydroxide ions ([OH⁻]) or determine the pH for each solution, more information is needed. Without the complete data, it is not possible to provide precise calculations or specific answers.

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As supplies of conventional oil from underground reservoirs decline, oil producers are turning to alternative sources such as unconventional oil and renewable energy.

As conventional oil reserves become depleted and harder to access, oil producers are increasingly exploring and extracting unconventional oil resources. These include shale oil, oil sands, and deepwater reserves. Shale oil, for example, is extracted through hydraulic fracturing, also known as fracking, which involves injecting high-pressure fluids into underground rocks to release oil and gas. Oil sands, on the other hand, require mining or steam-assisted gravity drainage (SAGD) techniques to extract bitumen, a heavy, viscous form of petroleum.

While unconventional oil sources provide additional supply, they often come with higher extraction costs and environmental challenges. The extraction processes can have significant environmental impacts, such as water contamination, habitat destruction, and greenhouse gas emissions. Therefore, the shift towards unconventional oil is not a long-term solution to the decline in conventional oil supplies.

To address the long-term challenges of declining conventional oil reserves and environmental concerns, oil producers are also investing in renewable energy sources. This includes diversifying their portfolios to include solar, wind, and hydropower projects. Many oil companies are recognizing the need to transition towards a more sustainable energy future, as renewable energy offers a cleaner and more abundant energy source.

In summary, as conventional oil supplies decline, oil producers are turning to alternative sources like unconventional oil and renewable energy. While unconventional oil provides a temporary solution, the focus on renewable energy represents a more sustainable long-term strategy for the energy industry.

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\(\\ \sf\longmapsto 1mole\:is\:a\:specific\:amount\:of\:particles\:of\:a\:substance .\)

\(\\ \sf\longmapsto It\:is\:Represented\:as\:mol\)

\(\\ \sf\longmapsto 1mol=6.023\times 10^{23}particles\)

Answer:

2 single, 0 double, and 1 triple

Explanation:

H-C≡C-H