When you move a magnet into a coil of wires, it induces a current in the wires. When you take the same magnet and move it in the opposite
direction through the coils, it still induces a current. What is differnet about the currents created in these situations?

Gravity provides the force needed for circular orbits, while velocity determines the size of the orbit. Kepler's laws relate orbit period, semi-major axis, and orbital velocity. The greater the gravitational force, the faster the object must move to maintain a stable orbit.

The relationship between gravity and velocity of orbiting objects is that gravity provides the centripetal force needed to maintain a circular orbit, and the velocity of the orbiting object determines the size of the orbit.

The greater the gravitational force between two objects, the faster an object must move to remain in a stable orbit around it. This relationship is described by Kepler's laws of planetary motion, which state that the square of the period of an orbit is proportional to the cube of the semi-major axis of the orbit.

This means that objects in larger orbits take longer to complete a full orbit than objects in smaller orbits, and the velocity required to maintain a circular orbit is proportional to the size of the orbit.

The velocity required for a stable orbit is known as the orbital velocity, and it depends on the mass of the object being orbited and the distance from it.

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Answer: I hope you have a great day. And I hope this helps.

Explanation: Scientific ideas don't need to be resourced in a book: For example, they need to be published in a peer-reviewed journal.

Furthermore, public favoring is not material: global warming is accepted in the scientific community despite a lack of popular favoring.

The correct answer is: They are new ideas. (and once they're accepted they can become laws).

Answer:

The lifting force of a balloon is equal to the weight of the air it displaces, minus the weight of the balloon itself and any cargo it is carrying. We can calculate the lifting force using the following formula:

Lifting force = (4/3) x π x r^3 x ρair x g - m_balloon - m_cargo

where:

- r is the radius of the balloon (in meters)

- ρair is the density of air (in kg/m^3), which we'll assume is 1.2 kg/m^3 at sea level and standard temperature

- g is the acceleration due to gravity (in m/s^2), which we'll assume is 9.81 m/s^2

- m_balloon is the mass of the balloon (in kg)

- m_cargo is the mass of the cargo (in kg)

- π is pi (approximately 3.14)

Substituting in the values given in the problem, we get:

Lifting force = (4/3) x π x (7.15 m)^3 x (1.2 kg/m^3) x 9.81 m/s^2 - 930 kg - m_cargo

Simplifying and solving for m_cargo, we get:

m_cargo = (4/3) x π x (7.15 m)^3 x (1.2 kg/m^3) x 9.81 m/s^2 - 930 kg - Lifting force

Plugging in the lifting force we want the balloon to have, which we'll call L, we get:

m_cargo = (4/3) x π x (7.15 m)^3 x (1.2 kg/m^3) x 9.81 m/s^2 - 930 kg - L

Assuming we want the balloon to lift 5000 kg of cargo, we can solve for L:

L = (4/3) x π x (7.15 m)^3 x (1.2 kg/m^3) x 9.81 m/s^2 - 930 kg - 5000 kg

L = 281,581 N

Therefore, to lift 5000 kg of cargo, the balloon needs to have a lifting force of approximately 281,581 N.

Given information: The average method reports the following unit data for the forming department. Units completed in the forming department are transferred to the painting department. Production cost information for the forming department follows.

Direct materials:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Direct materials cost = $202,500

Conversion costs:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Conversion cost = $189,000

a. Calculation of equivalent units of production for both direct materials and conversion for the forming department:
Equivalent units of production = Units completed during the period + (Ending work in process inventory * Degree of completion)
Direct materials:
Equivalent units of production = 45,000 + (5,000 * 50%) = 47,500 units

Conversion costs:
Equivalent units of production = 45,000 + (5,000 * 60%) = 48,000 units

b. Calculation of the cost per equivalent unit of production for both direct materials and conversion for the forming department:
Cost per equivalent unit of production = Total cost for the period / Equivalent units of production

Direct materials:
Cost per equivalent unit of production = $202,500 / 47,500 units = $4.26 per unit

Conversion costs:
Cost per equivalent unit of production = $189,000 / 48,000 units = $3.94 per unit

c. Calculation of the cost assigned to the forming department's output using the weighted average method:
Total cost = Cost of units transferred out + Cost of ending work in process inventory
Cost of units transferred out = Number of units transferred out * Cost per equivalent unit of production
Cost of ending work in process inventory = Number of units in ending work in process inventory * Cost per equivalent unit of production

Direct materials:
Cost of units transferred out = 40,000 * $4.26 per unit = $170,400
Cost of ending work in process inventory = 5,000 * $4.26 per unit = $21,300
Total cost = $170,400 + $21,300 = $191,700

Conversion costs:
Cost of units transferred out = 40,000 * $3.94 per unit = $157,600
Cost of ending work in process inventory = 5,000 * $3.94 per unit = $19,700
Total cost = $157,600 + $19,700 = $177,300

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I am going to assume that the rider starts at rest. Using the equation for kinetic energy, the answer would be equivalent to \(\frac{1}{2} (100)(11)^{2}\). The final answer would be 50 N.

Answer:

2250N

Explanation:

W= mg,

where W= weight

m= mass

g= acceleration due to gravity

Given that the body is 90kg, m= 90kg.

Acceleration due to gravity of planet

= 2.5(10)

= 25 m/s²

Weight of body on planet

= 90(25)

= 2250N

*Mass is the amount of matter an object has and is constant (same on earth and the planet).

Answer:

Here

mass=90kg

time=2.5second

acceleration due to gravity=10m/s

now,,,

Force=???

Force=mass*acceleration

Force=90*10

Force=900N

Answer:

The correct answer is: Energy is conserved, and it cannot be created or destroyed. This is known as the law of conservation of energy, which states that in a closed system, the total amount of energy remains constant and cannot be created or destroyed, only transformed from one form to another. This means that energy can be converted from one form to another, such as from potential energy to kinetic energy, but the total amount of energy in the system remains the same.

The given statement “Particles are in motion” is indicating that particles have kinetic energy and are moving. Hence, this statement is not indicating a specific state of matter. Hence, None of these. is the right option.

However, based on the states of matter, we can say that the motion of the particles depends on the physical state of matter. The three states of matter are:

Solid: In this state of matter, the particles have the least amount of kinetic energy and are held tightly in their positions by intermolecular forces. As a result, they are only capable of vibrating around their mean positions. The vibrations increase with an increase in temperature.

Liquid: In this state of matter, the particles have more kinetic energy than solids and are held together by relatively weaker intermolecular forces. The particles in the liquid are constantly in motion, which allows them to slide past one another and take the shape of the container that they are in. As temperature rises, the kinetic energy also increases.

Gas: In this state of matter, the particles have the highest amount of kinetic energy and are held together by the weakest intermolecular forces. The particles are in constant, random motion and are free to move in any direction. This gives them the ability to take up all the available space in a container.

The question should be:

Decide which physical states are indicated in the following statement. "Particles are in motion" Choose all that apply. Particles are in motion. a) solid. b) liquid. c) gas. d) none of these.

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1. W = 50J

2. W = 6.9J

3. Work done is same as force  = 30N

4. P = 480W

1. Here given:

F = 25N

D = 2m

We have to find  W = ?

Work done Formula : W= F x D

By substituting ,

W = 25 x 2

W = 50J

2. Here given,

F = 15N

Angle = 30°

distance = 3m

W = 15* 3 * cos 30

= 6.9 J

3. Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. When we apply a force of 30N to a wall, it responds with the same force.

4. The work done will be calculated using the formula:

W = mass*gravitational acceleration*height.

Furthermore,

power = work done / time.

500 + 100 = total weight

600 N = total weight

Maintain the values in the formula -

Work completed = 600*4

2400J

P = 2400/5

= 480W

Hence, the power is 480 Watt.

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The answer would have to be 8.47 m/s/s because the backwards pull + the rate of speed it is going would have to be added to get the answer to compensate for the backwards pull

The energy transferred when the potential difference is 3000mV and the charge is 2 C is 6 J.

It is given in the question that:

The potential difference, V = 3000 mV

The charge, q = 2 C.

We have, 1000 mV = 1 V

Therefore, V = 3000 mV = 3 V

Energy is related to potential difference and charge by the formula,

Energy = Charge \(\times\) Potential Difference

Or, \(E=qV\)

Substituting the values of charge and potential difference as given,

E = 2 \(\times\) 3 = 6 J

Therefore, the energy is transferred when the potential difference is 3000 mV volts and the charge is 7.5 C is 90 Joules.

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Answer:

Explanation:

The mass of the object can be found by using the formula

\(m = \frac{f}{a} \\ \)

f is the force

a is the acceleration

From the question we have

\(m = \frac{44}{15.3} \\ = 2.875816...\)

We have the final answer as

Hope this helps you

Answer:

2.9

Explanation:

In the equation you get 2.88 but you round that to the nearest tenth so you get 2.9

The frequency of the sound wave is 1.07 × 10⁹ Hertz

Wavelength is simply the distance over which the shapes of waves are repeated.

From the wavelength, frequency and speed relation,

λ = v ÷ f

Where λ is wavelength, v is velocity/speed and f is frequency.

Given that:

Plug values into the above formula.

λ = v ÷ f

f = v / λ

f = ( 343 m/s ) / ( 3.2 × 10⁻⁷ m )

f = 1.07 × 10⁹ Hz

Therefore, the frequency is 1.07 × 10⁹ Hz.

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both Eduardo and Clara's tension forces are correctly labeled. Eduardo's tension force is to the left (500 N) and Clara's tension force is to the right (200 N). As for kinetic friction, it always opposes the direction of motion.

To explain, we need to first understand the concept of forces. A force is a push or a pull that can cause an object to move, accelerate, or change its direction. In this scenario, there are four forces acting on the box: Eduardo's tension force pulling to the left, Clara's tension force pulling to the right, the force of kinetic friction opposing the motion of the box, and the force of gravity pulling the box downward.

Therefore, the only force left to consider is the force of kinetic friction. Kinetic friction is the force that opposes the motion of an object as it slides along a surface. It always acts in the opposite direction of motion, so if the box is moving to the left (due to Eduardo's greater force), the force of kinetic friction should be acting to the right. If the force of kinetic friction were acting in the same direction as Eduardo's force (to the left), it would be pushing the box in the same direction that Eduardo is pulling, which would not make sense.

So, to answer your question, if Leon recorded the force of kinetic friction as acting to the left, then that force would have the wrong direction. You asked about a box being pulled by two ropes, with Eduardo pulling to the left with a force of 500 N and Clara pulling to the right with a force of 200 N. You want to know which force has the wrong direction in the table: tension by Eduardo, tension by Clara, kinetic friction, or gravity.

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Answer:

Part 1; The total energy = Constant = 200 J

Part 2; Midway, the potential energy = The kinetic energy = 100 J

Explanation:

Part 1

According to the first law of thermodynamics, energy is neither created nor destroyed but changed from one form to another

The total (mechanical) energy = Potential energy + Kinetic energy = Constant

The kinetic energy given to the ball changed vertically up = 200 J

Potential energy = Mass, m × Gravity, g × Height, h

Given that the mass m of the ball and the acceleration due to gravity, g, remain the same, we have;

Potential energy ∝ The height of the ball

The potential energy at ground level = 0 J (Height , h = 0)

∴ The total (mechanical) energy = 0 J + 200 J = 200 J

At the maximum height, the ball momentarily stops, and the kinetic energy = 0 J

Therefore;

The potential energy of the ball at the maximum height, \(h_{max}\), \(P.E._{max}\) = 200 J

∴  \(P.E._{max}\) = m·g·\(h_{max}\) = 200 J

Part 2

At midway we have, the height, h = (\(h_{max}\))/2

Therefore, \(P.E._{Midway}\) = (m·g·(\(h_{max}\)))/2 = (\(P.E._{max}\))/2 = (200 J)/2 = 100 J

The potential energy midway = 100 J

The  remaining 200 J - 100 J = 100 J is the kinetic energy remaining in the ball

The kinetic energy midway = 100 J

Therefore, the total energy midway = 100 J + 100 J = 200 J

The option that would NOT suggest an interaction effect is the "Two parallel lines." interaction effect. The correct answer is option(a).

When one independent variable's effect on the dependent variable varies according to the value of another independent variable, this is known as the interaction effect. In other words, the level of the other independent variable determines the impact of one independent variable on the dependent variable. For example, in a study on the effect of a new medication on blood pressure, the interaction effect would occur if the impact of the medication varies depending on the age of the patients.

Age would be the moderating variable in this example. According to the given options, two parallel lines would represent that the two independent variables being analyzed have no effect on the dependent variable, meaning that there is no interaction effect present. Therefore, option A would NOT suggest an interaction effect. The remaining options suggest an interaction effect as they indicate that there is an impact on the dependent variable based on the level of the independent variables.

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The steady-state speed that can be achieved with a maximum drive power of 1.0 MW is approximately 9.73 m/s.

To determine the steady-state speed that can be achieved with a maximum drive power of 1.0 MW (megawatt), we need to consider the driving resistance and the available power.

Given information:

Mass of the locomotive (m1): 50 tonnes = 50,000 kg

Mass of each car (m2): 15 tonnes = 15,000 kg

Number of cars (n): 20

Gradient of the track (θ): 2% = 0.02

Friction coefficient (μ): 1%

Gravitational acceleration (g): 9.81 m/s^2

Maximum drive power (Pmax): 1.0 MW = 1,000,000 W

First, let's calculate the total mass of the train:

Total mass (M) = Mass of locomotive + Mass of cars

M = m1 + (m2 × n)

M = 50,000 kg + (15,000 kg × 20)

M = 50,000 kg + 300,000 kg

M = 350,000 kg

Next, we can calculate the driving resistance:

Driving resistance (R) = Gravitational resistance + Rolling resistance

Gravitational resistance (Rg) = M × g × sin(θ)

Rolling resistance (Rr) = μ × M × g × cos(θ)

R = Rg + Rr

Substituting the given values:

Rg = 350,000 kg × 9.81 m/s^2 × sin(0.02)

Rr = 0.01 × 350,000 kg × 9.81 m/s^2 × cos(0.02)

R = Rg + Rr

Calculate Rg:

Rg = 350,000 kg × 9.81 m/s^2 × sin(0.02)

Rg ≈ 350,000 kg × 9.81 m/s^2 × 0.02

Rg ≈ 68,430 N

Calculate Rr:

Rr = 0.01 × 350,000 kg × 9.81 m/s^2 × cos(0.02)

Rr ≈ 0.01 × 350,000 kg × 9.81 m/s^2 × 0.9998

Rr ≈ 34,267 N

Calculate R:

R = Rg + Rr

R ≈ 68,430 N + 34,267 N

R ≈ 102,697 N

Now, we can calculate the maximum velocity (vmax) using the maximum power available:

Power (P) = Force (F) × Velocity (v)

P = R × v

vmax = Pmax / R

Substituting the given values:

vmax = 1,000,000 W / 102,697 N

vmax ≈ 9.73 m/s

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Answer:

C. Potential energy

D. Kinetic energy

Explanation:

The acceleration of the car between 2 and 5 seconds is 0m/\(s^{2}\).

How can the velocity time graph be used to determine the acceleration?

Calculating acceleration involves dividing the change in velocity, expressed in meters per second, by the time required for the change, expressed in seconds. The acceleration is measured in m/\(s^{2}\).

As we are aware, velocity = distance / time.

And acceleration = velocity / time.

The linear graph shows that the distance travelled at the time interval of 2 seconds is 10 m. Hence the velocity(\(v_{1}\)) =10/2 = 5m/s.

The graph shows that the distance travelled is 25 m at time interval of 5 seconds. Hence the velocity (\(v_{2}\)) =25/5 = 5m/s.

Acceleration between 2 and 5 seconds is now calculated as

(\(v_{1}\)-\(v_{2}\)) / (\(t_{2}\)-\(t_{1}\)) = (5-5)/(5-2) = 0 m/\(s^{2}\)

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The magnetic field created by the cable is by the center, under the condition that the magnetic field 41.0 cm away from a long, straight wire carrying current 6.00 A is 2930 nT.

Now let us solve the sub questions
(a) The magnetic field produced by a long straight wire carrying current decreases as the distance from the wire increases and is given by the formula:
B = μ₀I / 2πr

where
B =magnetic field strength,
I = current,
r = distance from the wire,
μ₀ = permeability of free space.

Applying the formula to evaluate r
r = μ₀I / (2πB)

Staging given values
r = (\(4\pi *10^{-7 }T m/A\)) × (6 A) / (\(2\pi * 293 * 10^{-9} T\))
r = 410 cm
(b)  The magnetic field produced by two parallel conductors carrying currents in opposite directions can be found using Ampere's law.
B = μ₀I / (2πd)

where
B = magnetic field strength,
I = current in one conductor,
d = distance between the conductors,
μ₀ = permeability of free space.

Applying the formula
B = (\(4\pi * 10^{-7} T m/A\)) × (6 A) / (\(2\pi * 3 * 10^{-3} m\))
B = \(1*10^{-4 }T\)
The point of interest is equidistant from each wire and located at a distance of
r = √(d² + (41/2)²)

r = √(3² + (41/2)²) mm

r = 20.5 cm
(c) Staging given values into B formula
0.1B = (\(4\pi * 10^{-7 }T m/A\)) × (6 A) / (2πd)
Evaluating for d
d = μ₀I / (20πB)
d = (\(4\pi * 10^{-7 }T m/A\)) × (6 A) / (20π × 0.293 T)
d = 0.064 m
(d) The magnetic field inside a coaxial structure comprised of concentric conductors bearing current I is identical to that of a line current I in free space. Therefore, we can use Ampere's law to find out what magnetic field does a line current create at points outside it.
B = μ₀I / (2πr)
where
B =magnetic field strength,
I = current
r = distance from the wire,
μ₀ = permeability of free space.
Using this formula and substituting given valves
B = (\(4\pi * 10^{-7 }T m/A\)) × (6 A) / (2π × r)

The magnetic field generated by each conductor will be equal but opposite in direction at any point outside both conductors.
Hence, we can find out what magnetic field does each conductor create separately and then subtract them to get net magnetic field.

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The correct conductor ampacity for a 10-horsepower, 230-volt, single-phase motor is option c. 62.5 A.

The ampacity of a conductor is a measure of the maximum amount of electrical current that can flow through it safely. The ampacity required for a motor is based on the size of the motor and the voltage of the electrical system. There are standard methods for determining the minimum ampacity for a given motor and voltage, such as the National Electric Code (NEC) and the American National Standards Institute (ANSI). The NEC and ANSI both state that the minimum ampacity for a 10-horsepower, 230-volt, single-phase motor is 62.5 amperes. It's important to note that using a conductor with ampacity lower than the recommended one may cause the motor to overheat and fail, leading to damage or even fire hazard.

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According to NASA, the sun makes up approximately 99.86% of the mass of the solar system. Most of the mass in the solar system is concentrated in the sun.

The majority of the mass in the solar system is located in the Sun. Although the planets contain a significant amount of mass, the Sun accounts for over 99% of the solar system's entire mass. The planets, moons, asteroids, and other bodies in the solar system are insignificant in comparison to the Sun.

The sun contributes 99.86 percent of the total mass of the solar system. The source of this information is the NASA website.According to NASA, the Sun makes up 99.86 percent of the entire mass of the solar system. The rest of the 0.14 percent is split up between all of the planets, dwarf planets, asteroids, comets, and other celestial bodies in the solar system. Hence, we can say that the sun is the main contributor to the total mass of the solar system.

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The electric potential V at point A is 8.756 V.

The charge of Q1 is 22.4 µC, the charge of Q2 is -30.6 µC, the charge of Q3 is 57.3 µC, the length of y is 50.1 cm, and the length of a is 50.1 cm.

The formula used in order to calculate the electric potential is:

Electric potential due to a point charge is,

V = kQ/r

where k is Coulomb’s constant, Q is the charge, and r is the distance from the point charge.

The electric potential of point A due to the three-point charges is,

\(\mathrm {V = V_1 + V_2 + V_3}\)

where V1 is the potential due to charge Q1, V2 is the potential due to charge Q2, V3 is the potential due to charge Q3.

In this case, the potential is calculated at point A. So, r for each point charge will be equal to √(a² + y²)

Charge Q1:

It is positive so, it attracts the negative charges towards it.

Distance from Q1 to A is

\(\mathrm{r_1= \sqrt{(a^2 + y^2)} = \sqrt{(50.1^2 + 50.1^2)} = 71.002\: cm}\)

Electric potential due to Q1 is given by:

V1 = kQ1/r1

Where \(\mathrm{k = 9 \times 10^9\; N m^2/C^2}\), \(\mathrm{Q_1 = 22.4\; \mu C = 22.4 × 10^{-6} \;C}\)

Putting the values in the above formula, we get

\(\mathrm{V_1 = \dfrac{9 \times 10^9 \times 22.4 \times 10^{-6}} { 71.002} = 2.825 V}\)

Charge Q2:

It is negative so, it repels the negative charges from it.

Distance from Q2 to A is \(\mathrm{r_2= \sqrt{(a^2 + y^2)} = \sqrt{(50.1^2 + 50.1^2)} = 71.002 \;cm}\)

Electric potential due to Q2 is given by:

V2 = kQ2/r2

where \(\mathrm{k = 9 \times 10^9 N m^2/C^2}\), \(\mathrm{Q_2 = -30.6 \;\mu C = -30.6 \times 10^{-6} C}\)

Putting the values in the above formula, we get

\(\mathrm{V_2 = \dfrac{9 \times 10^9 \times (-30.6 \times 10^{-6})} { 71.002} = -1.237 \;V}\)

Charge Q3:

It is positive so, it attracts the negative charges towards it.

Distance from Q3 to A is

\(\mathrm{r_3= \sqrt{(a^2 + y^2)} = \sqrt{(50.1^2 + 50.1^2)} = 71.002 \;cm}\)

Electric potential due to Q3 is given by:

V3 = kQ3/r3

where \(\mathrm{k = 9 \times 10^9\; N m^2/C^2}\), \(\mathrm{Q_3 = 57.3 \;\mu C = 57.3 \times 10^{-6} C}\)

Putting the values in the above formula, we get

\(\mathrm{V_3 = \dfrac{9 \times 10^9 \times 57.3 \times 10^{-6}} { 71.002 }= 7.168 V}\)

The total potential V at A due to the three-point charges is, V = V1 + V2 + V3= 2.825 - 1.237 + 7.168= 8.756 V

Therefore, the electric potential V at point A is 8.756 V.

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Answer:

proteins carbohydrates and fats

Explanation:

Answer:

Carbohydrates, Proteins, and Fats.

The wind velocity that will tip the truck over to its side is approximately 45.6 m/s. This is calculated by considering the torque exerted by the wind on the truck's side surface and comparing it to the torque due to the weight of the truck.

To determine the wind velocity that will tip the truck over, we need to calculate the critical wind speed at which the torque exerted by the wind on the truck's side surface overcomes the torque due to the weight of the truck.

The torque due to the wind can be calculated using the equation:

Torque (wind) = (1/2) * air density * velocity² * projected area * moment arm

The torque due to the weight of the truck can be calculated using the equation:

Torque (weight) = weight * moment arm

For tipping to occur, the torque due to the wind must exceed the torque due to the weight of the truck. Therefore, we set the two torques equal to each other and solve for the wind velocity.

(1/2) * air density * velocity² * projected area * moment arm = weight * moment arm

Simplifying the equation, we find:

velocity² = (2 * weight * moment arm) / (air density * projected area)

Substituting the given values:

weight = 5000 kg

moment arm = 0.75 m

air density = 1.1 kg/m³

projected area = length * height = 9 m * 2.5 m = 22.5 m²

We can now calculate the wind velocity:

velocity²  = (2 * 5000 kg * 0.75 m) / (1.1 kg/m³ * 22.5 m²)

velocity² = 204.55

velocity ≈ √204.55 ≈ 14.3 m/s

Therefore, the wind velocity that will tip the truck over to its side is approximately 14.3 m/s.

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Explanation:

V² = Vx² + Vy²

= [3.14 cos(30)]² + [2.71 cos(300)]²

= 9.23

V = root 9.23 = 3.038

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Answer:

the answers are "mass" and "distance"

Explanation:

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