when you looked at solar activity on the heliophysics event registry website, on which date did you find activity on the sun?

Answer:

Velocity, V = 33.33 m/s

Explanation:

Given the following data;

Mass = 180grams to kilograms = 180/1000 = 0.18 kg

Kinetic energy = 100J

To find the speed;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

\( K.E = \frac{1}{2}MV^{2}\)

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Substituting into the equation, we have;

100 = ½*0.18*V²

Cross-multiplying, we have;

200 = 0.18*V²

V² = 200/0.18

V² = 1111.11

Taking the square root of both sides, we have;

Velocity, V = 33.33 m/s

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

The work was done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\) and at an angle of \(29^o\) 42.83 J.

When an object is moved over a distance by an external force, at least some of that force must be applied in the direction of the displacement. This is known as work in physics. Work may be estimated if the force acting along the path is constant by multiplying the length of the path by the component of the force acting along the path.

To express this formally, the work W is equal to the force f times the length d, or W = fd. The work is W = fd cos if the force is applied at an angle to the displacement.

Given:

The mass, m = 2 kg,

The acceleration, g = 9.81 \(m/s^2\),

θ = angle between block and surface kinetic friction = μ

Calculate the work done by the formula given below,

\(W_{fy}\) = F sinθ

\(W_{fy}\) =  (\(mgsin\)θ)/ (sinθ -  μ * cosθ)

Substitute the values

\(W_{fy}\)  = \((2*9.81 sin29^{o} )/sin29^o - 0.30cos29^o\)

\(W_{fy}\)  = 42.83 J

Therefore, the work done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\), and at an angle of \(29^o\) is 42.83 J.

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As the pendulum moves around the circle, the centripetal acceleration remains constant in magnitude but changes in direction. This is because the tangential velocity of the bob changes direction as it moves around the circle, but its speed remains constant.

The centripetal acceleration experienced by the bob of the conical pendulum is given by the formula \(a = v^2/r\),

Since the pendulum is rotating with a constant angular velocity, the tangential velocity is also constant, given by:

v = 2πr/T,

where T is the period of one revolution. The period is 60/20 = 3 seconds since the pendulum makes 20 revolutions per minute.

Thus, v = 2π*2/3 = 4.19 m/s.

Therefore, the centripetal acceleration is \(a = 4.19^2/2 = 8.77 m/s^2.\)

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--The complete Question is, A conical pendulum is set up in a non-inertial frame of reference that is rotating with a constant angular velocity. The length of the string is 2 meters, and the mass of the bob at the end of the string is 0.5 kg. The pendulum makes 20 revolutions per minute. What is the centripetal acceleration experienced by the bob, and how does this acceleration change as the pendulum moves around the circle?--

The formula for angular velocity as a function of time when it rises linearly can be used to address this issue:

ωz(t) = ωz,0 + αz t

If t is time, z,0 is the angular acceleration at rest, and z is the starting angular velocity.

Applying the information provided, we have:

ωz,0 = -6.00 rad/s (initial angular velocity)

z (6.0 s) = +4.0 rad/s (final angular velocity)

t = 6.00 s (time elapsed) (time elapsed)

The angular acceleration z is what we're looking for.

Using the formula's supplied values as substitutes, we obtain:

-6.00 rad/s + z = +4.00 rad/s (6.00 s)

When we simplify and find z, we obtain:

Z = (5.00 rad/s - 6.0 rad/s)

/6.00 s = 1.67 rad/s^2

As a result, the wheel's angular acceleration is 1.67 rad/s2.

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the work done to raise a 25kg book to a 1.5 m shelf is 367.5J and the potential energy of the book will be 367.5

Work done by a force is equal to the scalar product of the force applied and displacement. If d displacement happens on applying a force F, then work done, W by the force is

W = F. d

given:

mass, m = 25 kg

height, d = 1.50 m

work has to be done against the weight of the book, F = mg

work done W = F. d

W = mgd

W = (25) ×(9.8)×(1.50)

W = 367.5 J

This work is stored as the potential energy of the book.

Therefore, the work done to raise a 25kg book to a 1.5 m shelf is 367.5J and the potential energy of the book will be 367.5J

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The magnitude of the load on the crane before the collapse was 7871.48 N, which is well below the maximum load rating of 500 kg.To determine the load on the crane, we need to use the principles of static equilibrium.

The crane is in equilibrium when the sum of the forces acting on it is zero and the sum of the torques is also zero.The forces acting on the crane are tension in the cable and the weight of the horizontal beam. the torque is due to the weight of the horizontal beam.First, calculate the weight of the horizontal beam:

W = mgL = 85.105.0009.810 = 4168.52 N, where m is the mass per meter of length, g is the acceleration due to gravity, and L is the length of the beam.Now calculating the torque due to the weight of the beam :

τ = W*(h/2) = 4168.52*(2.250/2) = 4686.03 Nm, where h is the height of the horizontal beam. since the  crane is equilibrium, the tension in the cable must balance the weight of the beam which is  T = W. now  substituting the values we get :

=>12040 N = 4168.52 N + L=> 12040 N - 4168.52 N = 7871.48 N

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The resistance of the battery if a current of 23A flows through a circuit and the battery produces a potential difference of 9V is 0.39 ohms.

Resistance is the force that tends to oppose motion. It is measured in ohms. The resistance of a battery can be calculated using the following formula;

V = IR

Where;

According to this question, a current of 23A flows through a circuit and the battery produces a potential difference of 9V. The resistance can be calculated as follows:

R = V/I

R = 9/23

R = 0.39ohms

Therefore, 0.39ohms is the resistance of the battery.

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Answer:

C. resonating

an object being forced to vibrate at its natural frequency creates resonance

The centripetal acceleration of a ball of mass m moving at constant speed v in a horizontal circular path of radius r is constant in direction, but changing in magnitude.

A mathematical object's magnitude or size is a characteristic that indicates whether it is bigger or smaller than other objects of the same kind. Formally speaking, the size of an object is the visible outcome of an ordering—of the class of objects to which it belongs.

A magnitude is a measurement of a quantity's size. For instance, an earthquake's Richter scale magnitude, which reflects the size of the earthquake and typically ranges from 1 to 10, is measured. A magnitude 8 earthquake is far more problematic than a magnitude 3 earthquake.

Thus, option 2 is correct.

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Although damages caused by a hurricane depend on several factors, the most significant factor is the intensity of the storm.

The intensity of a hurricane is typically measured by the Saffir-Simpson Hurricane Wind Scale, which categorizes storms on a scale from 1 to 5 based on their sustained wind speeds. The higher the intensity, the greater the potential for destruction, as stronger winds can cause more significant structural damages to buildings, infrastructure, and vegetation. Additionally, high-intensity hurricanes can generate storm surges, which are massive waves that can inundate coastal areas, causing flooding and eroding shorelines. Aside from intensity, other factors contributing to hurricane damages include the size of the storm, the speed at which it is moving, and the angle of approach to the coastline. The size of the storm determines the area that will be affected, with larger storms causing more widespread damages. The speed of the storm's movement can influence the duration of its impact on a region, with slower-moving storms potentially causing more prolonged and severe damages. The angle of approach can also affect the severity of storm surges, as well as the distribution of wind and rain damages.
In summary, while hurricane damages are influenced by several factors, the most significant factor is the intensity of the storm, which determines the severity of the damages that can be inflicted on affected regions.

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The speed with which the car crosses the finish line is 6.26 m/s.

Apply the principle of conservation of energy and determine the speed of the ball.

K.E (bottom) = P.E (top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v = √(2 x 9.8 x 2)

v = 6.26 m/s

Thus, the speed with which the car crosses the finish line is 6.26 m/s.

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The systems that are most commonly described by schematics are electrical and mechanical systems. A schematic is a type of diagram that illustrates how a system works by showing the interconnections between components. It provides a visual representation of the system's architecture that is easy to read and interpret.

The schematic diagram displays the components of the system and their connections. Schematic diagrams can be used to explain complex systems in a simple way. They are particularly useful for illustrating how electrical and mechanical systems work.A mechanical schematic is a diagram that shows the mechanical components of a system, such as gears, belts, and pulleys. It provides a visual representation of how the system is designed to work, allowing engineers to identify potential problems and optimize the design. Electrical schematics, on the other hand, show the wiring and electronic components of a system. They provide a clear and concise representation of how electrical signals flow through the system, making it easy to identify potential problems and troubleshoot issues.

Schematic diagrams are used in a wide range of fields, from automotive and aerospace engineering to robotics and computer hardware design. They are an essential tool for engineers and designers who need to understand the inner workings of complex systems.

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Answer:

gravity

Explanation:

ok what i understand from your query is that a spring balance with a metal piece attached to it is weighing it down, a spring balance is measured in newtons (f=ma), the acceleration part is gravity (-9.81 m/s^2). The metal piece is attached to the string.

hope this answers your question and please take my answer with a grain of salt and refer to some webpages or videos

Answer:

1. Net force = 90 N

2. Acceleration = 9 m/s²

Explanation:

From the question given above, the following data were obtained:

Mass (m) of bag = 10 Kg

Force applied 1 (Fₐ₁) = 45 N

Force applied 2 (Fₐ₂) = 60 N

Force of friction (Fբ) = 15 N

Net force (Fₙ) =?

Acceleration (a) =?

1. Determination of the net force acting on the bag.

We'll begin by calculating the total force applied on the bag.

Force applied 1 (Fₐ₁) = 45 N

Force applied 2 (Fₐ₂) = 60 N

Total force applied = Fₐ₁ + Fₐ₂

Total force applied = 45 + 60

Total force applied = 105 N

Finally, we shall determine the net force acting on the bag. This is illustrated below:

Total force applied = 105 N

Force of friction (Fբ) = 15 N

Net force (Fₙ) =?

Net force (Fₙ) = Total force applied – Force of friction (Fբ)

Net force (Fₙ) = 105 – 15

Net force (Fₙ) = 90 N to the right

2. Determination of the acceleration of the bag.

Mass (m) of bag = 10 Kg

Net force (Fₙ) = 90 N

Acceleration (a) =?

Force (F) = mass (m) × acceleration (a)

90 = 10 × a

Divide both side by 10

a = 90 / 10

a = 9 m/s²

Thus, the acceleration of the bag is 9 m/s² to the right.

Answer:

Bar magnets are permanent magnets. This means that their magnetism is there all the time and cannot be turned on or off as it can with electromagnets .

Explanation:

Answer:

true

Explanation:

if all forces are equal then there would be no stronger force to give any net force so it would be zero

Answer:

C - 5.3s

Explanation:

a = v - u / t

so,

t = v - u / a

t = 180 - 100 / 15

t = 5.3s

Given that the number of turns in the primary coil is

The voltage in the primary coil is

The voltage in the secondary coil is

We have to find the number of turns in the secondary coil.

Let the number of turns in the secondary coil be denoted by

The formula to calculate the number of turns in the secondary coil is

Substituting the values, the number of turns in the secondary coil will be

Thus, the number of turns in the secondary coil is 50

An expression for the speed of a particle of rest mass m in terms of its total energy E v = c√[(E²)/(m²c²) - 1].

To derive the expression for the speed of a particle with rest mass m and total energy E, we will use the energy-momentum relation from special relativity. The relation is:
E² = (mc²)² + (pc)²
where E is the total energy, m is the rest mass, c is the speed of light, and p is the momentum of the particle. The momentum can be expressed as p = mv, where v is the speed of the particle. So, the equation becomes:
E² = (mc²)² + (mvc)²
Now, we will solve for v. First, factor out the common term m²c²:
E² = m²c²(1 + v²/c²)
Next, divide both sides by m²c²:
(E²)/(m²c²) = 1 + v²/c²
Subtract 1 from both sides:
(E²)/(m²c²) - 1 = v²/c²
Finally, multiply both sides by c² and take the square root to obtain v:
v = c√[(E²)/(m²c²) - 1]
This expression gives the speed of a particle with rest mass m and total energy E in terms of the speed of light c.

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Answer:

Final K.E. is four times initial KE

Explanation:

K. E. = 1/2 mv ^2        now double the speed

new K.E. = 1/2 m (2v)^2

               = 1/2 m 4 v^2

                = 4 * 1/2 m v^2    

Answer:

The final kinetic energy is 4 times the initial kinetic energy

Explanation:

Answer:

2.5m/s²

Explanation:

a = v/t

Where;

V = velocity (m/s)

a = acceleration (m/s²)

t = time (s).

According to the information provided in this question,

a = ?

v = 10m/s

t = 4

a = 10/4

a = 2.5m/s²

Answer:

1. C

2. B

3. B

Explanation:

Took assignment on edge

The

We would have to search at least 5,000,000,000 (5 billion) stars before we would expect to hear a signal.

To find out the number of stars that we will need to search to find a signal, we need to use the following formula:

This shows it is expected to find a civilization every 5 billion stars, and therefore it is necessary to search at least 5 billion stars before hearing a signal from any civilization.

Note: This question is incomplete; here is the complete question.

On average, how many stars would we have to search before we would expect to hear a signal? Assume there are 500 billion stars in the galaxy.

Assuming 100 civilizations existed.

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The resultant vector has a magnitude of approximately 8.4 m and points at an angle of about 10.3° east of north.

To find the resultant vector, first resolve the given vectors into their components.
Vector 1:
- x-component: 6.0 m * cos(30°) = 5.2 m (east)
- y-component: 6.0 m * sin(30°) = 3.0 m (north)
Vector 2:
- x-component: 4.0 m * sin(30°) = 2.0 m (west)
- y-component: 4.0 m * cos(30°) = 3.5 m (south)
Now, sum the components:
- x-total: 5.2 m (east) - 2.0 m (west) = 3.2 m (east)
- y-total: 3.0 m (north) - 3.5 m (south) = 0.5 m (north)
Next, calculate the magnitude of the resultant vector: sqrt(3.2^2 + 0.5^2) ≈ 8.4 m.

Lastly, find the angle: tan^-1(0.5/3.2) ≈ 10.3° east of north.

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The change in height of the mercury column for a temperature change of 26 °C is 0.000175 cm.

Mercury is the smallest and innermost planet in the Solar System. It is about one-third the size of the Earth and has no moons. It has a very thin atmosphere consisting almost entirely of a small amount of helium and sodium. Mercury's surface is heavily cratered and is similar in appearance to Earth's Moon. It has a very large iron core that makes up most of its mass.

The change in height of the mercury column is given by the equation:
Δh = V * β * ΔT
Where V is the volume of the mercury, β is the volume expansion coefficient of mercury, and ΔT is the change in temperature.
The volume of the mercury can be calculated as follows:
V = π * r² * h
Where r is the radius of the bulb and h is the height of the mercury column.
Substituting these values into the equation, we get:
Δh = π * (0.37/2)² * 0.0057 * 0.000182 * 26
Δh = 0.000175 cm
Therefore, the change in height of the mercury column for a temperature change of 26 °C is 0.000175 cm.

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Answer:

D

Explanation:

mN/s is the correct SI form for kN/ms.

Hence, Option B is correct.

Système Internationale, or SI, is the abbreviation for our metric system of measurements. It is a system that has been universally standardized, providing a common language between countries and among the various branches of science and technology. The International System of Units (SI), also known as the French Système International d'Unités, is a weights-and-measures system used internationally that extends the metric system of units. The metric system, also known as the International System of Units (SI), is the accepted unit of measurement on a global scale. The International Treaty of the Meter was signed on May 20, 1875, in Paris by seventeen nations, including the United States, and is now recognized as World Metrology Day worldwide.

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Answer:

the answer is B.

Explanation:

The ball that is thrown straight up has more kinetic energy and more speed than the ball that is thrown straight down. Both balls have the same kinetic energy and speed.

The kinetic energy of a body can be determined as the energy of a moving physical system because of its motion. Work has to be done on an object to change its kinetic energy.

The kinetic energy of the moving system can be expressed as K.E. = ½mv²  where ‘m’ is mass while ‘v’ is the velocity of the object.

The potential Energy of the physical system can be described as the energy stored due to its position. The mathematical formula for the calculation of the potential energy can be expressed in the form of P.E = m×g×h where ‘g’ is the gravitational acceleration, ‘m’ is the mass and ‘h’ is the height in meters

When two identical balls are thrown from a cliff, each with the same speed. One ball is thrown straight up, and the other ball is straight down. Both balls will have the same kinetic energy as well as speed.

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Answer:

The original length of the iron rod is approximately 572.189 meters.

Explanation:

This is a case of linear expansion, which is defined by the following differential equation:

\(\alpha = \frac{1}{L}\cdot \frac{dL}{dT}\) (1)

Where:

\(\alpha\) - Linear expansion coefficient, measured in \(\frac{1}{^{\circ}C}\).

\(L\) - Length of the element, measured in centimeters.

\(\frac{dL}{dT}\) - First derivative of the length of the element with respect to temperature, measured in centimeters per degree Celsius.

If we assume that thermal deformation are small regarding the length of the element, then we simplify (1) in the following form:

\(\alpha \approx \frac{\Delta L_{o}}{L\cdot \Delta T}\)

\(L_{f} -L_{o} = \alpha \cdot L_{o} \cdot \Delta T\)

\(L_{f} = L_{o}\cdot [1+\alpha\cdot (T_{f}-T_{o})]\) (2)

Where:

\(L_{o}\), \(L_{f}\) - Initial and final lengths of the element, measured in centimeters.

\(T_{o}, T_{f}\) - Initial and final temperatures of the element, measured in degrees Celsius.

Given that brass has a higher coefficient of linear expansion, it is suppose that initial length is less than the initial length of the iron element. Then, we have the following system of linear equations:

Brass

\(L = L_{o}\cdot [1+\alpha_{B}\cdot (T_{f}-T_{o})]\) (3)

Iron

\(L = (L_{o}+28)\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]\) (4)

Where \(\alpha_{B}\), \(\alpha_{I}\) are coefficients of linear expansion of brass and iron, measured in \(\frac{1}{^{\circ}C}\).

By equalizing (3) and (4), we have the following formula:

\(L_{o} \cdot [1+\alpha_{B}\cdot (T_{f}-T_{o})] = (L_{o}+28)\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]\)

\(L_{o} \cdot (\alpha_{B}-\alpha_{I})\cdot (T_{f}-T_{o}) = 28\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]\)

\(L_{o} = \frac{28\cdot [1+\alpha_{I}\cdot (T_{f}-T_{o})]}{(\alpha_{B}-\alpha_{I})\cdot (T_{f}-T_{o} )}\)

If we know that \(\alpha_{B} = 1.9\times 10^{-5}\,\frac{1}{^{\circ}C}\), \(\alpha_{I} = 1.2\times 10^{-5}\,\frac{1}{^{\circ}C}\), \(T_{o} = 20\,^{\circ}C\) and \(T_{f} = 90\,^{\circ}C\), then the initial length of the iron rod is:

\(L_{o} = \frac{28\cdot [1+\left(1.2\times 10^{-5}\,\frac{1}{^{\circ}C} \right)\cdot (90\,^{\circ}C-20\,^{\circ}C)]}{\left(1.9\times 10^{-5}\,\frac{1}{^{\circ}C}-1.2\times 10^{-5}\,\frac{1}{^{\circ}C} \right)\cdot (90\,^{\circ}C-20\,^{\circ}C)}\)

\(L_{o} = 57190.857\,cm\)

\(L_{o, I} = 57218.857\,cm\)

\(L_{o,I} = 572.189\,m\)

The original length of the iron rod is approximately 572.189 meters.