When Wangmo supplied 650 joules of heat to a small piece of brass, the temperature changed from 19°C to 45°C. If the specific heat capacity of the substance is 130 J/kg°C, what is the mass of brass piece taken by Wangmo?​

The determine the magnitude of the centripetal force acting on the car and driver, we can use the formula Fc = mv^2/r, where Fc is the centripetal force, m is the combined mass of the car and driver, v is the speed of the car, and r is the radius of the circular track.

The First, we need to convert the speed from Km/hr. to m/s by dividing 280 by 3.6, which gives us 77.78 m/s. Then, we can plug in the values into the formula: Fc = (820 kg) x (77.78 m/s) ^2 / (320 m). Simplifying this equation gives us a centripetal force of approximately 15,066 N. This means that the track is exerting a force of 15,066 N towards the center of the circular path, keeping the car and driver moving in a circular motion.  It is important to note that the determine the magnitude of the centripetal force increases as the speed or radius of the circular path increases. This force is also necessary for any object moving in a circular path, and without it, the object would move in a straight line instead.

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Mr. Hernandez can apply the principles of biomechanics when teaching his students how to properly train and exercise by using the concept of leverage.

For example, when teaching his students how to do a push-up, Mr. Hernandez can emphasize the importance of using the legs and core to generate leverage and lift the body off the ground. This will help his students use their muscles more efficiently and effectively, reducing the amount of force they need to exert and reducing the risk of injury.

Another example of using leverage in exercise is the use of resistance bands. Resistance bands are a versatile training tool that can be used to generate a wide range of resistance levels, from light to heavy. By using the bands to resist movement, Mr. Hernandez can help his students build strength and muscle tone while also using proper form and technique. This will help his students improve their performance and reduce the risk of injury.

Overall, by using the concept of leverage in his teaching, Mr. Hernandez can help his students train and exercise more efficiently and effectively, reducing the risk of injury and improving their performance.  

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Answer:

1 mole = 767.882 g

1 gram = 0.001 mole

Explanation:

The molar mass of CeAl₁₂O₁₉ is 770.686grams. The molar mass of a substance is the amount of substance which is present in one mole of the compound.

Molar mass of a substance is the mass in grams of one mole of the compound or chemical substance. In a chemical substance, the amount of entities which are present such as atoms, molecules, ions, is defined as a mole. A mole of any substance has 6.022 × 1023 molecules in it.

The molar mass of CeAl₁₂O₁₉  can be calculated as it is made up of three atoms which are Ce (Cerium), twelve atoms of Aluminium (Al), and nineteen atoms of O (Oxygen).

Atomic mass of Cerium = 140.116u

Atomic mass of Aluminium = 26.981539 u

The mass of 12 Aluminium atoms = 12 × 26.98 u

The mass of 12 Aluminium atoms = 323.76 u

Atomic mass of Oxygen =  15.999 u

The mass of 19 atoms of Oxygen = 303.81 u

Therefore, the mass of CeAl₁₂O₁₉ = 140.116 u + 323.76 u + 303.81 u

The molar mass of CeAl₁₂O₁₉ is 770.686 grams.

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Answer:

Explanation:

I think it's wrong but I tried my best..

Answer:

What is the gravity equation? — It is equal to 6.674×10-11 N·m²/kg². Did you notice that this equation is similar to the formula in Coulomb's law?

Explanation:

Answer:

Acceleration stress, physiological changes that occur in the human body in motion as a result of rapid increase of speed. ... A force of 3 g, for example, is equivalent to an acceleration three times that of a body falling near Earth.

The D. critical path is a series of events and activities with no slack time.

It is a path that defines the longest duration required to complete a project. It is significant in the project management methodology as it helps the project manager establish a timeline for the project while also identifying the activities that are most critical to the project's completion. If an activity on the critical path takes longer than anticipated, the whole project will be delayed, and if an activity is completed earlier than expected, then it might not be worth it to continue the project, and the client might not be willing to pay for it.

The critical path analysis allows managers to identify and control the critical factors that can impact a project's success, enabling them to focus on the most important areas and make informed decisions about the project. So the correct answer is D. critical path, is a series of events and activities with no slack time.

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The subsequent current in the series RLC circuit is given by the equation: i(t) = I * cos(5t - Φ), where I is the amplitude of the current and Φ is the phase angle.

To find the subsequent current, we need to calculate the amplitude (I) and the phase angle (Φ) of the current.

First, let's calculate the resonant frequency (ω) of the circuit:

ω = 1 / √(LC) = 1 / √(10 * 10^(-2)) = 1 / √1 = 1 rad/s.

The applied voltage can be written as E(t) = E * cos(ωt), where E is the amplitude of the voltage.

Comparing this with the given voltage E(t) = 200 * cos(5t), we can equate the angular frequencies: ω = 5.

Now, let's find the impedance (Z) of the circuit:

Z = √(R^2 + (Xl - Xc)^2),

where R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance.

R = 20 Ω

Xl = ωL = 1 * 10 = 10 Ω

Xc = 1 / (ωC) = 1 / (5 * 10^(-2)) = 20 Ω

Plugging in these values, we get:

Z = √(20^2 + (10 - 20)^2) = √(400 + 100) = √500 ≈ 22.36 Ω.

The amplitude of the current (I) can be calculated using Ohm's Law:

I = E / Z = 200 / 22.36 ≈ 8.94 A.

The phase angle (Φ) can be found using the relationship between resistance, inductive reactance, and capacitive reactance:

tan(Φ) = (Xl - Xc) / R = (10 - 20) / 20 = -0.5.

Therefore, Φ ≈ -0.464 rad.

The subsequent current in the series RLC circuit is given by i(t) = 8.94 * cos(5t + 0.464) A.

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The energy of the photon emitted when the electron in a hydrogen atom undergoes a transition from the n = 8 level to the n = 6 level is approximately 2.00 eV, which is closest to answer choice B) 0.21 eV.

To determine the energy of the photon emitted, we can use the formula:

E = hf = hc/λ

where E is the energy of the photon, h is Planck's constant, f is the frequency of the emitted radiation, c is the speed of light, and λ is the wavelength of the emitted radiation.

We can use the equation for the energy levels of hydrogen atoms:

En = -13.6/n² eV

where En is the energy of the nth energy level.

The energy difference between the two energy levels is:

ΔE = E_final - E_initial

= (-13.6/6²) - (-13.6/8²)

= 1.51 eV

We can convert this energy difference to the energy of the photon emitted by using the formula:

E = hc/λ = ΔE

λ = hc/ΔE

= (6.626 x 10⁻³⁴ J s) x (3 x 10⁸ m/s) / (1.51 eV x 1.602 x 10⁻¹⁹ J/eV)

= 495.5 nm

Now we can use the formula:

E = hc/λ

= (6.626 x 10⁻³⁴ J s) x (3 x 10⁸ m/s) / (495.5 x 10⁻⁹ m)

= 1.99 eV

Therefore, the energy of the photon emitted when the electron in a hydrogen atom undergoes a transition from the n = 8 level to the n = 6 level is approximately 2.00 eV, which is closest 0.21 eV.

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Answer:

Asteroid

Explanation: did the test

Answer:

A. Asteroid

Explanation:

edge2020

The height of the building is 42.4 meters.

Let's call the height of the building "h". We can use the following kinematic equations to solve for "h":

For the stone that is dropped from the top of the building:

h = (1/2)gt² (Equation 1)

For the stone that is thrown upwards from the ground:

y = vt - (1/2)gt² (Equation 2)

where;

We know that the two stones meet at exactly 5s after their release. This means that the distance travelled by the stone thrown upwards from the ground is equal to the height of the building, i.e.,

y = h

We can substitute this equation into Equation 2 and rearrange it to solve for "t":

h = vt - (1/2)gt²

h = 20t - (1/2)gt²

t = (2h/g - 20)/(-1) (Equation 3)

Now we can substitute Equation 3 into Equation 1 and solve for "h":

h = (1/2)g((2h/g - 20)/(-1))²

h = (1/2)g(2h/g - 20)²

h = (1/2)g(4h²/g² - 80h/g + 400)

Simplifying this equation by multiplying everything by 2g and moving all the terms to one side, we get:

4h² - 160h - 400 = 0

Solving this quadratic equation using the quadratic formula, we get:

h = (160 ± sqrt(160² + 4(4)(400))) / (2(4))

h = (160 ± sqrt(32,000)) / 8

We can ignore the negative solution, so:

h = (160 + 178.88) / 8

h = 42.4 meters

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Answer:

a

 \(v_f = 0.916 v_{ex}\)

b

 \(v_f = 1.05 v_{ex}\)

Explanation:

Considering question a

From the question we are told that

   The mass of the rocket is  \(m_o\)  

    The mass of the fuel which is in the rocket is  m = 0.6 M  

Generally given that the rocket burns all it fuel in a single stage , the final velocity of the rocket is mathematically represented as

          \(v_f = v_{ex} ln [\frac{m_o}{m_k} ]\)

Here \(m_k\) is the mass  of the rocket without fuel which is mathematically evaluated as

        \(m_k = m_o- m\)

=>      \(m_k = m_o -0.6m_o\)

=>    \(m_k = [1- 0.6] m_o\)

=>      \(v_f = v_{ex} ln [\frac{m_o}{[1 - 0.6]m_o} ]\)    

=>      \(v_f = 0.916 v_{ex}\)

Considering question b

From the question we are told that

   The mass of the fuel it burn at the first stage is  \(m = 0.3 m_o\)

     The mass of the first stage fuel tank \(m_1 = 0.1 m_o\)

    The mass of the fuel at the second stage is  \(m_f = 0.3m_o\)

Generally the  velocity of the rocket at the first stage  is mathematically represented as

           \(v_i = v_{ex} * ln [ \frac{m_o }{[1- m]m_o } ]\)

=>         \(v_i = v_{ex} * ln [ \frac{m_o }{[1- 0.3]m_o } ]\)

=>         \(v_i = v_{ex} * ln [ \frac{1 }{0.7 } ]\)  

=>         \(v_i =0.357 v_{ex}\)

Generally the mass of the rocket after first stage is  

    \(m_r = m_o - 0.3m_o -0.1m_o\)

=>   \(m_r = 0.6m_o\)

Generally the final  velocity of the rocket at the second stage is  

     \(v_f = v_i + v_{ex} * ln [\frac{m_r}{ m_f } ]\)

=>   \(v_f = v_i + v_{ex} * ln [\frac{0.6 m_o }{0.3mo } ]\)

=>   \(v_f = 0.357 v_{ex} + 0.693 v_{ex}\)

=>   \(v_f = 1.05 v_{ex}\)

Answer:

2250N

Explanation:

W= mg,

where W= weight

m= mass

g= acceleration due to gravity

Given that the body is 90kg, m= 90kg.

Acceleration due to gravity of planet

= 2.5(10)

= 25 m/s²

Weight of body on planet

= 90(25)

= 2250N

*Mass is the amount of matter an object has and is constant (same on earth and the planet).

Answer:

Here

mass=90kg

time=2.5second

acceleration due to gravity=10m/s

now,,,

Force=???

Force=mass*acceleration

Force=90*10

Force=900N

Answer:

B. a standing committee

Explanation:

got it right on Edmentum/Plato <3

We can use Ohm's Law to solve this problem. Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) between them. Mathematically, Ohm's Law can be expressed as:

I = V/R

We are given the current (I) for two different circuit configurations: I1 = 3.8 A for the original circuit with resistance R, and I2 = 2.8 A for the circuit with resistance R + 2 Ω. Let's use these values to solve for R.

From Ohm's Law, we know that:

I1 = V/R

Rearranging this equation, we get:

V = I1 * R

Similarly, for the second circuit configuration, we have:

I2 = V/(R + 2)

Rearranging this equation, we get:

V = I2 * (R + 2)

Since the voltage (V) is the same in both circuits (it's the voltage supplied by the battery or power source), we can equate the two expressions for V:

I1 * R = I2 * (R + 2)

Expanding this equation, we get:

I1 * R = I2 * R + 2 * I2

Solving for R, we get:

R = 2 * I2 / (I1 - I2)

Substituting the given values, we get:

R = 2 * 2.8 A / (3.8 A - 2.8 A) = 5.6 Ω

Therefore, the value of R is 5.6 Ω.

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Answer:

the answer for that is "A"

the set-up integral for the volume V cut out is:

V_cut out = ∫_0^h (π(7r)² - π(9R)²) the set-up integral for the volume V cut out is:

V_cut out = ∫_0^h (π(7r)² - π(9R)²) dh

How can we obtain the volume V cut out?

To set up an integral for the volume V cut out when a hole of radius 7r is bored through the middle of a cylinder of radius 9R > 7r at right angles to the axis of the cylinder, we will use the principle of volumes of solids of revolution. We will assume that the cylinder and the bored hole are both of the same height 'h'.

The volume of the cylinder can be found using the formula of the volume of a cylinder:

V_cylinder = πr²h

Where r is the radius of the cylinder.

Volume of the cylinder is given as;

V_cylinder = π (9R)² h

We are given that a hole of radius 7r is bored through the middle of the cylinder. The volume of the hole can be found by taking the difference between the volumes of two cylinders; one with radius 7r and height h and the other with radius 9R and height h. The volume of the hole can be found using the formula;

V_hole = πr²h - πr²h

Where r is the radius of the hole (7r) and h is the height of the cylinder. The radius of the cylinder is 9R. Therefore, the volume of the hole is given as;

V_hole = π(7r)²h - π(9R)²h

We can now set up the integral for the volume V cut out using the formula;

V_cut out = ∫_0^h (π(7r)² - π(9R)²) dh

By evaluating this integral, we can obtain the volume V cut out. Therefore, the set-up integral for the volume V cut out is:

V_cut out = ∫_0^h (π(7r)² - π(9R)²) dh

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Answer:

d.solid to liquid cause they were once on a fixed and started to slide.liquid particles slide along a container so it is a solid to liquid

Answer: B

Explanation: just did it on a p e x

The car will appear to be 10% lighter than its normal weight when traveling at a speed of about 16.7 m/s.

When the car is going over the top of the hill, the apparent weight of the occupants will be less than their actual weight due to the centrifugal force acting on them.

The centrifugal force acting on the occupants is given by:

Fc = ma

where Fc is the centrifugal force, m is the mass of the occupants, and a is the centripetal acceleration.

The centripetal acceleration is given by:

a = v^2 / r

where v is the velocity of the car and r is the radius of the hill.

The apparent weight of the occupants can be found using:

Wapp = Wactual - Fc

where Wactual is the actual weight of the occupants and Wapp is the apparent weight.

If the occupants appear to weigh 10% less than their average weight, then:

Wapp = 0.9 * Wactual

Substituting the equations for F and a we get:

0.9 * Wactual = Wactual - m * v^2 / r

Simplifying, we get:

m * v^2 / r = 0.1 * Wactual

v^2 = 0.1 * Wactual * r / m

We can express the weight in terms of mass using the formula:

W = m * g

where W is the weight, m is the mass, and g is the acceleration due to gravity.

Substituting, we get:

v^2 = 0.1 * m * g * r / m

v^2 = 0.1 * g * r

Solving for v, we get:

v = √(0.1 * g * r)

Plugging in the values, we get:

v = √(0.1 * 9.81 m/s^2 * 350 m)

v = 16.7 m/s

Therefore, the velocity of the car at which the occupants will appear to weigh 10% less than their average weight is approximately 16.7 m/s.

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The net force on the car is zero, since the car is moving at a constant velocity which means the forces acting on it are balanced.

If a vehicle is moving at a constant velocity, then there is no net force acting on it. This is because the net force is the sum of all the forces acting on an object, and if the vehicle is moving at a constant velocity, then the forces acting on it must be balanced.

If a vehicle is accelerating, then there is a net force acting on it. This is because acceleration is a change in velocity over time, and to change velocity, a net force must be applied to the object.

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Answer:

Electronegativity

Explanation:

Answer:

The property that determines an atom;s ability to attract electrons shared in a chemical bond is electronegativity.

Explanation:

Hope you have a great day :)

The chemical formula for dinitrogen tetroxide is C) N204.

Nitrogen that exists in its diatomic form, which is also known as molecular nitrogen or nitrogen gas, is referred to as dinitrogen. This form of nitrogen has two nitrogen atoms joined by a triple covalent bond, which satisfies the Lewis electron rules by having two lone, nonbonding electron pairs, one on each Nitrogen atom.

Whereas Dinitrogen tetroxide is colourless, Nitrogen dioxide is brown. As the temperature drops, the brown color's intensity falls. As a result, a drop in temperature results in a rise in Dinitrogen tetroxide. As temperature drops, equilibrium is pushed to the Dinitrogen tetroxide side.

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The approximate internal rate of return (IRR) for installing the device is estimated to be above 20%. Indicating that the actual IRR must be higher than 20% to move the NPV closer to zero.

To calculate the NPV for installing the device, we need to consider the cash flows and discount rate. The initial cost of the device is £500,000, followed by net revenues of £100,000 after one year and £500,000 after two years. The nuclear company's high discount rate of 20% reflects its limited borrowing capacity and alternative productive uses for its cash.

We can start by assuming an IRR higher than 20% and calculate the corresponding NPV. At a 20% discount rate, the NPV is already -£70,000. If the IRR were lower than 20%, the NPV would be even more negative, moving further away from zero.

Therefore, to move the NPV closer to zero, the IRR must be higher than 20%. By using trial and error to adjust the discount rate, we can find an approximate IRR that results in an NPV closer to zero. However, without knowing the exact timing and magnitude of the cash flows, it is challenging to provide an exact IRR estimate.

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Answer:

When focused light is projected onto the retina, it stimulates the rods and cones. The retina then sends nerve signals are sent through the back of the eye to the optic nerve. The optic nerve carries these signals to the brain, which interprets them as visual images.

Explanation:

Hope it will help u

A second rock is hurled at a speed of 3.750 m/s straight up. If this rock takes 2.848 s to fall to the ground, the rock was released from a height of 79.6 meters.

Let's assume that the positive direction is upwards, then the acceleration due to gravity is \(-9.81 m/s^2\).

We know that the time it takes for the rock to fall back to the ground is 2.848 s, which means that the total time of flight (i.e. the time it takes for the rock to reach the highest point and fall back down) is twice that, or 2 × 2.848 s = 5.696 s.

Using the equation for the time of flight, we can find the initial height h from which the rock was released:

\(h = (1/2)gt^2 = (1/2)(-9.81 m/s^2)(5.696 s)^2 = 79.6 m\)

Speed refers to the rate at which an object covers a distance over a period of time. It is a scalar quantity, which means it has only magnitude and no direction. The SI unit of speed is meters per second (m/s), but other units such as miles per hour (mph) and kilometers per hour (km/h) are commonly used as well.

Speed is an important concept in physics, as it is used to describe the motion of objects. The speed of an object can be constant or changing, depending on the forces acting on it. Acceleration is the rate at which an object's speed changes, and is measured in meters per second squared (m/s^2). In everyday life, speed is an important consideration for transportation, sports, and many other activities. It is also a crucial factor in safety, as exceeding safe speeds can lead to accidents and injuries.

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Answer:

Oxygen is an element that can be a solid, liquid or gas depending on its temperature and pressure. In the atmosphere it is found as a gas, more specifically, a diatomic gas. This means that two oxygen atoms are connected together in a covalent double bond.