When two substances that cannot dissolve each other are mixed, a mixture is formed.
A heterogeneous mixture that has very small dispersed particles and stays mixed for a long time is a .
A heterogeneous mixture that has larger dispersed particles that settle over time is a

Answer:

48 degress

Explanation:

An earthquake causes many different intensities of shaking in the area of the epicenter where it occurs. So the intensity of an earthquake will vary depending on where you are. Sometimes earthquakes are referred to by the maximum intensity they produce. In the United States, we use the Modified Mercalli Scale. Earthquake intensity is a ranking based on the observed effects of an earthquake in each particular place. Therefore, each earthquake produces a range of intensity values, ranging from highest in the epicenter area to zero at a distance from the epicenter.

The sun is the center of the solar system which is surrounded by the nine planets and they tend to orbit the sun in concentric circles with the sun as the center.

The term solar system has to do with the arrangement of the sun and the planets. The sun lies at the focus of the solar system. Now we know that there are nine planets that orbit around the sun. The distance between the planets and the sun depends on their relative proximity to each other.

Thus, the sun is the center of the solar system which is surrounded by the nine planets and they tend to orbit the sun in concentric circles with the sun as the center.

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The true statements are:Jupiter's Great Red Spot is in the southern hemisphere.The fastest wind speed recorded in our solar system is on Neptune.

Among the given statements, only two are true. Jupiter's Great Red Spot, a massive storm, is indeed located in the southern hemisphere of the planet. The Great Red Spot is a prominent feature on Jupiter, visible as a giant swirling storm system. On the other hand, the fastest wind speed recorded in our solar system, reaching speeds of up to 2,100 kilometers per hour (1,300 miles per hour), is found on Neptune.

The strong winds on Neptune contribute to its dynamic atmosphere and the formation of features like the Great Dark Spot. The remaining statements about Pluto, Saturn's moon Enceladus, and Uranus are not true according to our current understanding.

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Answer:

4b: comets

5a: supercluster

5b: they just changed 4b's solar system for milky way. I think it is still comets. if not, then just say black holes.

Answer:

false

Explanation:

As both parents contribute half of the new organism's genetic material, the offspring will have traits of both parents, but will not be exactly like either parent

Answer:

False

Explanation:

The only time you end up like your parent is asexual reproduction

While Jupiter is larger than Earth, it is still much smaller than the sun or a comet. Therefore, the correct answer is (2) a comet.  

Based on our current knowledge, Jupiter's composition is most like that of an asteroid. Jupiter is a gas giant, primarily composed of hydrogen and helium, with trace amounts of other elements such as methane, ammonia, and water. Jupiter is a gas giant, which means that it is composed mainly of gas rather than solid matter. The gas giants in our solar system, including Jupiter, are believed to have formed from a swirling disk of gas and dust that surrounded the sun in the early days of the solar system.

The composition of Jupiter is primarily hydrogen and helium, with trace amounts of other elements such as methane, ammonia, and water. These elements combine to form the gas giant's atmosphere, which is made up of layers of different gases that extend from the planet's rocky core to its outer atmosphere. Therefore, the correct answer is (2) a comet.  

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Correct Question:

overall, jupiter's composition is most like that of group of answer choices

1. earth.

2. a comet.

3. the sun.

4. an asteroid.

Answer:

60 m/hStep-by-step

explanation:S = d/t

S= 360/60

S= 60

Given :

Objects 1 and 2 attract each other with a gravitational force of 72.0 units.

To Find :

If the distance separating objects 1 and 2 is tripled then the new gravitational force will be units.

Solution :

Let, initial distance is \(r_1\) and final distance is \(r_2\).

\(r_2 = 3r_1\)

We know, gravitational force is inversely proportional to the distance between the objects. So :

\(\dfrac{G_2}{G_1}=\dfrac{r_1^2}{r_2^2}\\\\G_2 = \dfrac{G_1 \times r_1^2}{r_2^2}\\\\G_2 = \dfrac{G_1\times r_1^2}{(3r_1)^2}\\\\G_2 = \dfrac{72}{9}\\\\G _2= 8\ units\)

Therefore, new gravitational force is 8 units.

Answer:

The statement that best describes nuclear fusion is;

Nuclei combine to form a heavier nucleus, releasing energy

Explanation:

In nuclear fusion, we have the reaction of the nuclei of two or more atoms coming together (combining) to form heavier elements and subatomic particles such as protons and neutrons accompanied by the release or absorption in energy depending on the difference between the mass of the reactants and the products

Some nuclear fusion reaction require an input of energy and such reactions are therefore not spontaneous

The best option is nuclei (two or more nuclei) combine to form a heavier nucleus, releasing energy.

Answer:

The answer is the last option or D

Explanation:

Nuclei combine to form a heavier nucleus, releasing energy.

Have a great day and stay safe!

To determine the mass of a beaker when it contains 100 cm³ of water, you need to consider the mass of the water as well as the mass of the beaker itself.

The density of water is approximately 1 g/cm³. This means that 1 cm³ of water has a mass of 1 gram.
Since the beaker contains 100 cm³ of water, you can calculate the mass of the water by multiplying its volume (100 cm³) by its density (1 g/cm³):
Mass of water = 100 cm³ × 1 g/cm³ = 100 g
Now, add the mass of the empty beaker (40 g) to the mass of the water (100 g) to find the total mass of the beaker when it contains 100 cm³ of water:
Total mass = Mass of beaker + Mass of water = 40 g + 100 g = 140 g
So, the mass of the beaker when it contains 100 cm³ of water is 140 grams.

According to the rule of conservation of mass, matter can be changed from one condition or form to another but cannot be created or destroyed. According to science's fundamentals, all of the matter that exists today was once something else before it was transformed into what it is today. Nuclear reactions, on the other hand, defy this law since they include modifications to the matter's core that can affect both the proton of the original substance and the neutron of a different element. This means that matter can both be formed and destroyed during nuclear processes.

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The magnitude of the force exerted on the car to accelerate is 0.5588m N

We got some values here,

v\(_{0}\) = 30 mil/h = 13,4112 m/s

v\(_{1}\) = 55 mil/h = 24,5872 m/s

t = 20 s

First, we should find the acceleration of the car

a = v/t

a = v\(_{1}\) - v\(_{0}\) / t\(_{1}\) - t\(_{0}\)

a = 24.5872 - 13.4112 / 20 - 0

a = 11.176 / 20

a = 0.5588 m/s\(^{2}\)

Now we got the amount of acceleration. We can found the force by the formula of: F = m.a but we are not given the mass value in the question. So, we can answer this question by this way

F = m.a

F = m × 0.5588 m/s\(^{2}\)

F = 0.5588m N

Acceleration (a) is the change in velocity (Δv) over the change of time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how quick velocity changes in meters per second squared (m/s\(^{2}\). Acceleration is also a vector quantity, so it includes both magnitude and direction.

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The distance the truck travel in given time is 216 m and the final velocity of acceleration at 0.5m/\(s^{2}\) for 30 seconds is 19 m /s

The following question has two parts

For part 1 we need to calculate the distance covered by the truck in 12 seconds

We know that

 s = ut + \(\frac{1}{2}a .t^{2}\) . . . . . . .  . . . . .(1)

where s = distance travelled

           u = initial velocity

           a = acceleration

           t  =  time in seconds

Now , As per the question

u = 6 m/s

a = 2 m/\(s^{2}\)

t  = 12 seconds

Putting the values in the equation (1)

                          s = 6 X 12 + \(\frac{1}{2}\) X 2 X 144

                          s = 72 + 144

                          s = 216 m

Therefore the distance travelled is 216 m

For part 2 we need to calculate the final velocity that Paco was driving

We know that

v = u + at . . . . . . . . . . .  .(2)

where v = final velocity

          u = initial velocity

          a = acceleration

           t = time in seconds

As per the question,

u = 4m/s

a = 0.5 m/\(s^{2}\)

t = 30 seconds

Putting in equation (2)

                                      v = 4 + 0.5 X 30

                                      v  =  4 + 15

                                      v = 19 m/s

Therefore the final velocity is 19 m/s

Therefore , the distance the truck travel in given time is 216 m and the final velocity of acceleration at 0.5m/\(s^{2}\) for 30 seconds is 19 m /s

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The final velocity of the scooter is 19 m/s.

Given:

Initial velocity of truck, u = 6 m/s

Acceleration of truck, a = 2 m/s²

Time taken by the truck, t = 12 s

Formula used:

s = ut + 1/2 at²

Where,

s = Distance travelled

u = Initial velocity

a = Acceleration

t = Time taken

Substituting the given values in the above formula, we get:

s = ut + 1/2 at²

 = 6(12) + 1/2 × 2 × (12)²

 = 72 + 1/2 × 2 × 144

 = 72 + 144

 = 216 m

Therefore, the truck travels 216 m in the given time.

Given:

Initial velocity of scooter, u = 4 m/s

Acceleration of scooter, a = 0.5 m/s²

Time taken by the scooter, t = 30 s

Formula used:

v = u + at

Where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time taken

Substituting the given values in the above formula, we get:

v = u + at

 = 4 + 0.5 × 30

 = 4 + 15

 = 19 m/s

Therefore, the final velocity of the scooter is 19 m/s.

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Answer:

  44.9 m

Explanation:

For ballistic motion in x-y coordinates, an appropriate equation can be ...

  y(x) = -4.9(x·sec(α)/v)² +tan(α)x + h0

where α is the angle of launch from the horizontal, and v is the magnitude of the launch velocity.

Here, we have v = 15 m/s, and α = 0, so the equation reduces to ...

  y = -4.9/225x^2 +44

For y = 0, we can find x to be ...

  x^2 = (44×225/4.9) ≈ 2020.41

  x ≈ 44.949

The stone hits the ground about 44.9 meters from the base of the cliff.

The values of x and y are 28° and 46.33° respectively, will make the lines parallel.

Since angle between two collinear lines is 180°,

5 x + 40° = 180°

5 x = 180 - 40

x = 140 / 5

x = 28°

Since corresponding angles are equal if the lines are parallel,

3 y - 1 + 40° = 180°

3 y = 180 -40 + 1

y = 139 / 3

y = 46.33°

Corresponding angles are the angles formed at same relative position at each intersection. When a transversal intersects two parallel line, the corresponding angles are equal.

Therefore, to make the line parallel the values of x and y should be 28° and 46.33° respectively.

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Answer:

the dimensions of a are T^2/M( that is per M square of T)

the dimensions of b is L^2

note: a minus sign is attached to both dimensions when working

Answer:

 temperature is -10

Explanation:

The type of circuit which have been made is the series circuit in this scenario.

This is a complete path which involves the whole electric current flowing through the various parts such as resistor etc..

There is only one path of current in which it does not undergo any form of split during motion.

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Answer:

Hi

Explanation:

OK so

I2 = U/R2

or

I2 = 12 : 68

I1 = U /R1

I1= 12 : 39

Answer:

Relax 5-Min guide

Explanation:

Answer:

c.

Explanation:

First thing's first, we need to find the Net Force of the system in order to solve for acceleration. Gravity and Normal Force cancel out, so we don't really have to worry about anything on the y-axis. However, looking at the x-axis, we see two forces: the Force of the push and Frictional Force.

This means that:

\(F_{net}\) = 500 - 100

\(F_{net}\) = 400 (N)

Recall that Force = Mass * Acceleration. Since we have the Force and Mass, we can easily solve for Accel:

F = ma

a = \(\frac{F}{m}\)

Plug the net force and mass into the equation:  

a = \(\frac{F}{m}\)

a = \(\frac{400}{50}\)

a = 8 (m/\(s^{2}\))

The box's acceleration is 8 m/\(s^{2}\)

If you have any questions about how I got to the answer, just ask :)

The magnitude of the EMF induced at the ends of the skipping rope is 3.4 × 10^-4 V. The energy stored in the magnetic field of an inductor with 8.0 mH of inductance when a steady current of 4.0 A flows through it is 64 mJ.

(a) To calculate the magnitude of the EMF induced at the ends of the skipping rope, we can use the formula ε = BLVsinθ, where ε is the induced EMF, B is the magnetic field, L is the length of the conductor, V is the velocity of the conductor, and θ is the angle between the velocity of the conductor and the magnetic field.

In this case:

B = 5.0 × 10^-5 T (given)

V = 8.2 m/s (given)

L = 12 m (given)

θ = 90° (as it is perpendicular to the magnetic field)

First, we calculate the value of B:

B = BVsinθ / L

B = (5.0 × 10^-5 T) × (8.2 m/s) × sin 90° / 12 m

B = 3.42 × 10^-6 T

Substituting the value of B in the first equation, we get:

ε = BLVsinθ

ε = (3.42 × 10^-6 T) × (12.0 m) × (8.2 m/s) × sin 90°

ε = 3.4 × 10^-4 V

Therefore, the magnitude of the EMF induced at the ends of the skipping rope is 3.4 × 10^-4 V.

(b) To calculate the energy stored in the magnetic field of an inductor, we can use the formula W = (LI^2) / 2, where W is the energy stored, L is the inductance, and I is the current flowing through the inductor.

In this case:

L = 8.0 mH

I = 4.0 A

Using the formula, we find:

W = (LI^2) / 2

W = (8.0 mH) × (4.0 A)^2 / 2

W = 64 mJ

Therefore, the energy stored in the magnetic field of an inductor with 8.0 mH of inductance when a steady current of 4.0 A flows through it is 64 mJ.

In the given problems, we calculated the magnitude of the EMF induced at the ends of the skipping rope using the magnetic field, length, velocity, and angle. We also determined the energy stored in the magnetic field of an inductor using the inductance and current.

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Expansion takes over the scale of larger galaxy clusters as galaxy clusters are gravitationally bound together under the influence of competing expansions. Expansions take on a larger size scale than galaxy clusters because galaxy clusters are the largest.

Scientists have found that galaxies are moving away from us at enormous speeds, which causes the sky to expand and multiply over time. Now the international fact about the expansion of the universe is a fact that mankind believes.

Technically, neither space nor objects in space are moving. Rather, it is the metric (which governs the size and geometry of spacetime itself) that changes in scale. As the spatial part of the universe's metric-time space increases in scale, objects become farther away from each other at ever-increasing speeds. To an observer anywhere in the universe, it appears that all of space is expanding, and all but the closest galaxies (those bound by gravity) are contracting at a rate proportional to their distance from the observer.

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Answer:

0.03s

Explanation:

Period of wave and its frequency are closely related. Period is the inverse of frequency.

The period of a wave is the time taken for a number of waves to pass through a particular point.

The frequency of a wave is the number of waves that passes through a point at a particular time.

So;

          f  = \(\frac{1}{T}\)  

f is the frequency

T is the period

   Period of the wave  = \(\frac{1}{30}\)   = 0.03s

Answer:

a

Explanation:

Answer:

0.38m/s

Explanation:

Given data

M1= 0.4kg

U1= 10m/s

M2= 70kg

U2= 0m/s

The system experiences an inelastic collision, the expression for inelastic collision is

M1U1+ M2U1= (M1+M2)V

Subsitute

0.4*10+ 70*0= (0.4+10)*V

4= 10.4V

4=10.4V

V= 4/10.4

V=0.38m/s

Hence the common velocity is 0.38m/s

The induced emf in one of the windings is approximately 10.1 millivolts. Using Faraday's Law, which states that the induced emf is equal to the rate of change of magnetic flux.

In this case, the solenoid is the source of the changing magnetic field.
Assuming that the solenoid has N windings, and the magnetic flux through one winding is given by Φ, then the induced emf in one winding is:

\(emf=-Ndi/dt\)
where the negative sign indicates that the induced emf opposes the change in magnetic flux.
Given that the current in the solenoid is decreasing at a rate of 40.0 A/s, we can use Ampere's Law to find the magnetic flux through one winding. Ampere's Law states that the magnetic field inside a solenoid is proportional to the current flowing through it:
\(B=UNI/L\)
where μ is the permeability of free space, N is the number of windings, I is the current, and L is the length of the solenoid.
Assuming that the solenoid is long enough that the magnetic field is approximately uniform inside it, the magnetic flux through one winding is:
Φ = B * A
where A is the cross-sectional area of the solenoid.
Substituting the above equations into the expression for the induced emf, we get:
emf = -μ × A × I × N² / L × dI/dt
Plugging in the given values, we get:
emf = -(4π × 10⁻⁷ T·m/A) × π × (0.01 m)² ×(N=1)× (I=40 A)² / (0.1 m) ×(-40.0 A/s)
emf ≈ 10.1 mV

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1. The resistance of the coil is 20 Ω

2. The new resistance of will be 200 Ω

3. The resistance of wire will be 2000 Ω

4. The current through the remote control is 0.33 A

5. The potential difference is 100 V

The resistance of the coil can be obtain as follow:

Voltage (V) = Current (I) × resistance (R)

120 = 6 × resistance

Divide both sides by 6

Resistance = 120 / 6

Resistance = 20 Ω

The new resistance can be obtain as follow:

L₁ / R₁ = L₂ / R₂

Inputting the given parameters, we have:

L / 100 = 2L / R₂

Cross multiply

L × R₂ = 100 × 2 L

L × R₂ = 200L

Divide both sides by L

R₂ = 200L / L

New resistance = 200 Ω

The new resistance can be obtain as follow:

R₁r₁² = R₂r₂²

Inputting the given parameters, we have:

500 × r² = R₂ × (0.5r)²

500 × r² = R₂ × 0.25r²

Divide both sides by 0.25r²

R₂ = (500 × r²) / 0.25r²

New resistance = 2000 Ω

The current can be obtained as follow:

Voltage (V) = Current (I) × resistance (R)

3 = I × 9

Divide both sides by 9

I = 3 / 9

Current = 0.33 A

The potential difference can be obtained as follow:

Potential difference (V) = Current (I) × resistance (R)

Potential difference = 2 × 50

Potential difference = 100 V

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They tell me I'm a god, I'm lost in the facade

Six-feet off the ground at all times, I think I'm feelin' odd

No matter what I make, they never see mistakes

Makin' so much bread, I don't care that they're just being fake

They tell me they're below me, I act like I'm above

The people blend together but I would be lost without their love

Can you heal me? Have I gained too much?

When you become untouchable, you're unable to touch

Is there a real me? Pop the champagne

It hurts me just to think and I don't do pain

Stayin' still, eyes closed

Let the world just pass me by

Pain pills, nice clothes

If I fall, I think I'll fly

Touch me, Midas

Make me part of your design

None to guide us

I feel fear for the very last time.

The required repulsion force is 1.11 x 10^-14 kilo-newtons.

The repulsion force between two electrons can be calculated using Coulomb's law, which states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. The formula for the force is given by:

F = k * (q1 * q2) / r^2

where F is the force in newtons, k is the Coulomb constant (8.99 x 10^9 N m^2/C^2), q1 and q2 are the magnitudes of the charges in coulombs, and r is the distance between them in meters.

Since electrons have a negative charge, the force between them is repulsive. If each student loses 0.01% of their electrons, the force can be calculated as follows:

q1 = q2 = (0.01%) * (1.6 x 10^-19 C) = 1.6 x 10^-21 C

r = 10 m

Substituting these values into the formula gives:

F = k * (q1 * q2) / r^2 = 8.99 x 10^9 N m^2/C^2 * (1.6 x 10^-21 C)^2 / (10 m)^2 = 1.11 x 10^-11 N

Converting the force from newtons to kilo-newtons gives:

F (in kn) = F (in N) / 1000 N/kn = 1.11 x 10^-11 N / 1000 N/kn = 1.11 x 10^-14 kn

So, the repulsion force between the two students, each losing 0.01% of their electrons, is approximately 1.11 x 10^-14 kilo-newtons.

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Answer:

FALSE

Explanation:

To answer this question we must clarify that for a given approach to exist there must be a transition between two atomic levels of the material.

For the emission, the transition between two determined states must also occur, therefore the radiation emitted is equal to that absorbed.

Consequently the statement is False