When traveling at 55mph, it takes approximately 211 feet to stop.
To determine how many feet you need to stop when traveling at 55 mph, you'll need to consider the following terms:
1. Speed: In this case, it's 55 mph.
2. Conversion factor: To convert mph to feet per second (fps), you need to multiply by 1.467.
3. Braking distance: The distance required to come to a complete stop from a certain speed, which is affected by factors such as the road conditions and vehicle's braking system.
Now, let's calculate the stopping distance:
Step 1: Convert the speed to feet per second.
55 mph × 1.467 = 80.685 fps
Step 2: Calculate the braking distance using the general rule of thumb (which assumes good road conditions and properly functioning brakes) that it takes 1.5 feet to stop for every 1 fps of speed.
80.685 fps × 1.5 = 121.028 feet
So, when traveling at 55 mph, you would need approximately 121 feet to stop. Please note that this is a rough estimate and can vary depending on factors such as road conditions and the efficiency of the vehicle's braking system.
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How are the angle of incidence and the angle of reflection related?
List two functions of blood plasma
Answer:
•Helps to maintain va proper pH in the body which supports cell function.
•Carries electrolytes such as sodium and potassium to our muscles.
If you shine a light of frequency 375hz on a double slit setup , and you measure the slit separation to be 950 nm and the screen distance to be 4030 nm away , what is the distance from the zero order fringe to the first order fringe ?
Answer:
y = 33.93 10⁵ m
Explanation:
This is an interference exercise, for the contributory interference is described by the expression
d sin θ = m λ
let's use trigonometry for the angle
tan θ = y / L
how the angles are small
tan θ = sin θ / cos tea = sin θ
we substitute
sin θ = y / L
d y / L = m λ
y = m λ L / d
the light fulfills the relation of the waves
c = λ f
λ = c / f
λ = 3 10⁸ /375
λ = 8 10⁵ m
first order m = 1
let's calculate
y = 1 8 10⁵ 4030 10-9 / 950 10-9
y = 33.93 10⁵ m
a set of charges sets up a force of 5.0x10-15 n in the -x direction on a small -25 ball. what is the strength and direction of the electric field at the position the small ball is located?
We can determine the direction of the electric field. The force on the small ball is in the -x direction, which means the electric field must also be in the -x direction. Therefore, the direction of the electric field is -x.
Based on the information given, we know that a set of charges is creating a force of 5.0x10-15 N in the -x direction on a small -25 ball. This force is caused by the electric field created by the charges.
To find the strength and direction of the electric field, we can use the formula:
Electric field strength (E) = Force (F) / Charge (q)
We know the force (F) is 5.0x10-15 N, but we don't know the charge (q) on the small ball. Therefore, we cannot calculate the exact strength of the electric field.
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what stresses you think of three things and describe what makes these situations stresssful how do they make you feel
Answer:
a lot stresses me out honestly like school work because we are virtual and it's hard cause you basically teaching yourself, secondly me maintaining to be happy i always put everybody's happiness before mine and it's just a lot for me, and lastly the thing that stresses me the most is me overthinking i ALWAYS overthink situations.
Explanation:
:/
Suppose the tilt of Earth's equator relative to its orbit were 30 ° instead of 23.5°. At what latitudes would the Arctic and Antarctic Circles be located?
_____ degrees latitude
The new position of the Arctic and Antarctic Circles would be located at 30° North and 30° South, respectively.
If the tilt of Earth's equator relative to its orbit were 30° instead of 23.5°, the location of the Arctic and Antarctic Circles would be affected. The Arctic Circle is defined as the latitude above which the sun does not set on the summer solstice and does not rise on the winter solstice. The same applies to the Antarctic Circle but in the Southern Hemisphere.
Currently, the Arctic Circle is located at 66.5° North and the Antarctic Circle is located at 66.5° South. If the tilt of Earth's equator relative to its orbit were 30°, the position of the Arctic and Antarctic Circles would be closer to the equator.
To determine the new position of the Arctic and Antarctic Circles, we can use the following formula:
θ = 90° - ϕ
where θ is the angle between the axis of rotation and the line perpendicular to the plane of the ecliptic, and ϕ is the tilt of the Earth's axis relative to the plane of the ecliptic.
If the tilt were 30°, then θ would be:
θ = 90° - 30° = 60°
Therefore, the new latitude of the Arctic and Antarctic Circles would be:
ϕ = 90° - 60° = 30°
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The new position of the Arctic and Antarctic Circles would be located at 30° North and 30° South, respectively.
If the tilt of Earth's equator relative to its orbit were 30° instead of 23.5°, the location of the Arctic and Antarctic Circles would be affected. The Arctic Circle is defined as the latitude above which the sun does not set on the summer solstice and does not rise on the winter solstice. The same applies to the Antarctic Circle but in the Southern Hemisphere.
Currently, the Arctic Circle is located at 66.5° North and the Antarctic Circle is located at 66.5° South. If the tilt of Earth's equator relative to its orbit were 30°, the position of the Arctic and Antarctic Circles would be closer to the equator.
To determine the new position of the Arctic and Antarctic Circles, we can use the following formula:
θ = 90° - ϕ
where θ is the angle between the axis of rotation and the line perpendicular to the plane of the ecliptic, and ϕ is the tilt of the Earth's axis relative to the plane of the ecliptic.
If the tilt were 30°, then θ would be:
θ = 90° - 30° = 60°
Therefore, the new latitude of the Arctic and Antarctic Circles would be:
ϕ = 90° - 60° = 30°
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what is the distance between a nodal plane of b⃗ and the closest antinodal plane of b⃗ ?
The distance between a nodal plane of b⃗ and the closest antinodal plane of b⃗ is half the wavelength of the wave represented by b⃗.
When considering a wave represented by b⃗, nodal planes are regions where the amplitude of the wave is zero, while antinodal planes are regions of maximum amplitude. The distance between a nodal plane and the closest antinodal plane can be determined by examining the properties of the wave.
A nodal plane occurs at the points where the displacement of the wave is zero. In contrast, an antinodal plane represents the points of maximum displacement. Since the distance between a nodal plane and the nearest antinodal plane is equivalent to half the wavelength, it implies that one-half of a wavelength encompasses a complete cycle of the wave.
To understand this concept further, imagine a wave propagating in space. As the wave oscillates, it goes through a complete cycle from a nodal plane to an antinodal plane and back to a nodal plane. The distance between these two distinct regions is half the wavelength. This relationship holds true for various types of waves, such as electromagnetic waves, sound waves, and water waves.
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Describe 2 potential problems or limitations of ratio
analysis.
A 57 kg pole vaulter running at 11 m/s vaults over the bar. Her speed when she is above the bar is 1.1 m/s. The acceleration of gravity is 9.8 m/s 2 . Find her altitude as she crosses the bar. Neglect air resistance, as well as any energy absorbed by the pole. Answer in units of m.
Answer:
Her altitude as she crosses the bar, h₂ is approximately 6.1 m
Explanation:
The given parameters of the motion of the pole vaulter are;
The mass of the pole vaulter, m = 57 kg
The speed with which the pole vaulter is running, u = 11 m/s
The speed of the pole vaulter when she crosses the bar, v = 1.1 m/s
The acceleration due to gravity, g = 9.8 m/s²
From the total mechanical energy, M.E. equation, we have;
M.E. = P.E. + K.E.
Where;
P.E. = The potential energy of the motion = m·g·h
K.E. = The kinetic energy of the motion = 1/2·m·v²
By the principle of conservation of energy, we have;
The change (loss) in kinetic energy, ΔK.E. = The change (gain) in potential energy, ΔP.E.
ΔK.E. = 1/2·m·(v² - u²)
ΔP.E. = m·g·(h₂ - h₁)
Where;
h₁ = The ground level = 0 m
h₂ = The altitude with which she crosses the bar
∴ 1/2·m·(v² - u²) = m·g·(h₂ - h₁)
(h₂ - h₁) = (v² - u²)/(2·g) = (11² - 1.1²)/(2·9.8) = 6.11173469388
h₂ = 6.11173469388 + h₁ = 6.11173469388 + 0 = 6.11173469388
h₂ = 6.11173469388
Her altitude as she crosses over the bar, h₂ ≈ 6.1 m.
A motorcycle travels at a constant 20 m/s for 10 s. How far has it traveled?
What is the mass of the block of iron that has a density of 7.87 g/cm3. Its volume measurements are 2 cm x 10 cm x 5 cm.
if the wave moves with the equation y(x,t) = 2 cos (300t +0.6x)
1- find the wave number
2- the angular frequency
3- speed of the wave
4- the direction of the wave
5- the frequency
6- the amplitude
7- the frequency
1. Wave number can be calculated by using the formula:
k = 2π/λ, where λ is the wavelength of the wave.
The equation of the wave is y(x,t) = 2 cos(300t + 0.6x).
Comparing with the standard equation of wave:
y(x,t) = A cos(kx - ωt + φ)
Hence, the wave number, k, which is equal to 0.6.
2. The angular frequency, ω, is given by the formula:
ω = 2πf, where f is the frequency of the wave.
Hence, the angular frequency is 300 radians per second.
3. The speed of the wave, v, is given by the formula:
v = λf = ω/k
The speed of the wave is:
v = (2π/0.6) * (1/300)
v ≈ 35.4 m/s
4. The direction of the wave can be determined by looking at the coefficient of x in the equation:
y(x,t) = 2 cos (300t + 0.6x)
Since the coefficient of x is positive, the wave is traveling in the positive x direction.
5. The frequency of the wave, f, is given by the formula:
f = ω/2π
Therefore, the frequency is 300/2π ≈ 47.7 Hz.
6. The amplitude of the wave is
7. The frequency is already determined above in part 5
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Suppose that you observe a spaceship passing in front of you at a relative velocity v=0.75c. According to a clock on Earth, 2.5 seconds passed in the spaceship clock.Find the time elapsed for an observer inside the spaceship.
Given,
The velocity of the spaceship in as observed by an observer at the earth, v=0.75c
The time interval as observed by the observer on the earth, t₁=2.5 s
The time elapsed in the ship's frame of reference is given by,
\(t_2=\frac{t_1}{\sqrt[]{1-\frac{v^2}{c^2}}}\)On substituting the known values,
\(\begin{gathered} t_2=\frac{2.5_{}}{\sqrt[]{1-\frac{(0.75c)^2}{c^2}}} \\ =\frac{2.5}{0.66} \\ =3.79\text{ s} \end{gathered}\)Thus the time elapsed for an observer in the spaceship is 3.79 s
12 x cos 50 = ?
Does anyone have the answer ? I forgot my my calculator.
12 x cos 50 = 7.713451316...
A magnifier allows one to look at a very near object by forming an image of it farther away. The object appears larger. To create a magnifier, one would use a.
In order to create a magnifier in convex lens, you should choose a short focal length that is lesser than 1 meter.
What is a convex lens?A convex lens is also referred to as converging lens and it can be defined as a type of lens that typically causes parallel rays of light with respect to its principal axis to come to a focus (converge) and form a real image.
In Science, a magnifier refer to an optical instrument that allow us to look at a very near object because its image is generally formed farther away. Thus, the image of the object appears to be much larger.
In this context, you should choose a short focal length that is lesser than 1 meter when you want to create a magnifier in convex lens because the nearer the object is to the lens, the larger would be the image formed.
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A 10 kg bowling ball that is 20 meters above ground has more gravitational potential energy than a 1000 kg wrecking ball that's on the ground (height is Om), True or False?
Answer:
True
Explanation:
The Gravitational potential energy is given by:
G = mgh
m = mass of body ; g = acceleration due to gravity ; h = height
G for a ball of mass 10kg ; height of 20 meters above the ground
G = 10kg * 9.8m/s² * 20m = 1960 kgm²/s²
G for a ball of mass 1000kg at height, 0 meters :
G = 1000 * 9.8 * 0 = 0
1960 > 0
Hence, Gravitational potential energy for 10kg ball at height 20m is greater Thammfor a 1000kg ball on the ground.
The solar wind is highly ionized plasma. Throughout its trajectory, it presents variations in temperature, density, pressure and speed, mainly due to the presence of eruptive phenomena such as Coronal Mass Ejections (CME). Assuming that on its journey between the Sun and the Earth (150X10^6 km), the temperature (1.3X10^5 K) and speed (450 km/s) remain constant. What kind of fluid is it? When an EMC is generated, the temperature (10^7 K) and the speed of the Solar Wind (10^3 km/s) increase and assuming that this increase remains constant along the same trajectory, what type of fluid will be the Solar Wind thanks to this disturbance?
laminar fluid <2100
transition 2,100-4,000
turbulent fluid >4000
Re=(Velocity)(Length)/ VISCOSITY
calculate the viscosity depending on the temperature
and explain in words the solution of the problem.
The solar wind, with a constant temperature of 1.3x10^5 K and a speed of 450 km/s, is a highly ionized plasma.
Due to the increase in temperature (10^7 K) and speed (10^3 km/s) during a Coronal Mass Ejection (CME), the solar wind becomes a turbulent fluid.The solar wind, which is a stream of charged particles (plasma) emitted by the Sun, exhibits characteristics of a highly ionized plasma. As it travels from the Sun to the Earth, the solar wind encounters variations in temperature, density, pressure, and speed. In this case, with a constant temperature of 1.3x10^5 K and a speed of 450 km/s, the solar wind can be classified as a highly ionized plasma.
During a Coronal Mass Ejection (CME), eruptive phenomena on the Sun's surface cause a sudden release of a large amount of plasma and magnetic fields into space. This disturbance leads to an increase in the temperature of the solar wind to around 10^7 K and an increase in its speed to approximately 10^3 km/s. This enhanced energy and velocity result in a significant disruption of the solar wind's flow, making it a turbulent fluid.
Turbulent fluids are characterized by chaotic and irregular motion, with strong fluctuations and mixing. The increased temperature and speed during a CME generate turbulent behavior within the solar wind, leading to the disruption and mixing of plasma particles along its trajectory.
To determine the type of fluid flow, the Reynolds number (Re) is often used. It relates the flow's characteristics, such as velocity and length, to the fluid's viscosity. In this case, since the solar wind is a plasma and has negligible viscosity, the Reynolds number is extremely high, well above the turbulent threshold of 4000. Therefore, the solar wind with increased temperature and speed due to a CME can be classified as a turbulent fluid.
In summary, the solar wind, with a constant temperature of 1.3x10^5 K and a speed of 450 km/s, is a highly ionized plasma. However, during a Coronal Mass Ejection (CME), the temperature and speed of the solar wind increase significantly, leading to turbulent fluid behavior.
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Calculate the efficiency of a hairdryer that has a total power input of 2000W and a useful power output of 1200W.
please help me answer this
Answer:
Earth's atmosphere is made up of a combination of gases. The major components of nitrogen, oxygen, and argon remain constant over time and space, while trace components like CO 2 and water vapor vary considerably over both space and time.
Explanation:
it is C
Answer:
c
Explanation: O n O
If a body of mass 4 kg moves at a velocity of 25 m/s and has a completely inelastic collision with a body of mass 10 kg, the final velocities of both the bodies is 14 m/s. Calculate the initial velocity of the body of mass 10 kg.
We are given the following information about an inelastic collision.
Mass of 1st object = 4 kg
Mass of 2nd object = 10 kg
Initial velocity of 1st object = 25 m/s
Final velocity of both objects = 14 m/s
Initial velocity of 2nd object = ?
In an inelastic collision, the momentum is conserved but the kinetic energy is not conserved.
Recall that the total momentum is conserved and given by
\(m_1u_1+m_2u_2=(m_1+m_2)v_2\)Let us substitute the given values and solve for initial velocity of the body (u2)
\(\begin{gathered} m_1u_1+m_2u_2=(m_1+m_2)v_2 \\ 4\cdot25+10\cdot u_2=(4+10)\cdot14 \\ 100+10\cdot u_2=196 \\ 10\cdot u_2=196-100 \\ 10\cdot u_2=96 \\ u_2=\frac{96}{10} \\ u_2=9.6\; \frac{m}{s} \end{gathered}\)Therefore, the initial velocity of the body of mass 10 kg is 9.6 m/s
Normal human body temperature is 98.6°F. What is this temperature expressed in Celsius (°C) and in Kelvin (K)?
Answer: 37 Celsius and 310.15 K
Explanation:
C/5 = (F-32)/9 = (98.6-32)/9 = 66.6/9 = 7.4
C = 7.4 * 5 = 37 so the temperature is 37 Celsius
K = C + 273.15 = 37 + 273.15 = 310.15 K
What do we call the study of solar system and the objects in it.
Answer:
I'm pretty sure it's called Astronomy
Explanation:
Hope this helps:)...if not then sorry for wasting your time and may God bless you:)
Answer: Astronomy
Explanation: Astronomy is objects we can see with our eyes, like the Sun , the Moon , the planets, and the stars . It also includes objects we can only see with telescopes or other instruments, like faraway galaxies and tiny particles.
I hope this helps ;o o;
Solving elastic collisions problem the hard way
Answer:
Solving elastic collisions problem the hard wayExplanation:
perfect drawing
(A) A small mass of 0.60 kg is rotated at the end of a string in a horizontal circle of radius 1.20 m. The string will break if the tension exceeds 60 N. What is the GREATEST frequency of revolution that is possible? (B) the same mass of 0.60 kg is now rotated at the end of another string at a constant speed, v, in a vertical circle of radius 1.20 m. the minimum tension in the string is 2.1N (I) state and explain where the tension in the string is maximum and minimum (ii) find the speed of the mass
(a) The maximum frequency of revolution is 4.0 rad/s.
b (i) The tension in the string is maximum when the object is at the top of its path and minimum when it is at the bottom of its path.
b (ii) The speed of the mass can be found using the minimum tension in the string is 2 m/s.
What is the maximum frequency of revolution?
The maximum frequency of revolution is given by the maximum tension in the string, which is 60 N.
T = mv² / r
where;
m is the mass of the object (0.60 kg), v is its linear speed, r is the radius of the circle (1.20 m).The linear speed is given by:
v = 2πrf
where;
f is the frequency of revolutionf = √T / (mr²))
f = √(60 / (0.60 x 1.20²))
f = 4.0 rad/s
(i) The tension in the string is maximum when the object is at the top of its path and minimum when it is at the bottom of its path. This is because the tension provides the centripetal force that keeps the object moving in a circular path.
(ii) The speed of the mass can be found using the minimum tension in the string, which is 2.1 N:
T = mv² / r = 2.1 N
Rearranging and solving for v, we get:
v = √(Tr / m)
v = √(2.1 x 1.20 / 0.60)
v = 2.0 m/s
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Tyler and his family drove from Atlanta to Baltimore. They traveled a total of 678 miles over 2 days.
What is the reference point in this scenario?
Atlanta
Baltimore
678 miles
2 days
Answer:
atlanta
Explanation:
just took the test
The reference point in this scenario is Atlanta.
What is reference point of the journey?The can be described as the starting point of the entire journey.
From the given statements the family started the journey from Atlanta and then traveled to Baltimore.
Atlanta is the start point (reference point) while Baltimore is the destination (finishing point).
Thus, the reference point in this scenario is Atlanta.
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The table provided shows data collected during an experiment .
Which of the following claims is supported by the data?
A. Gravitational force are proportional to the masses of the two objects.
B. Gravitational forces are strongest between objects with identical masses.
C. Gravitational forces are weakest when one object is more massive than the other.
Answer:
Explanation: the table shows during an experiment
Gravitational forces are strongest between objects with identical masses, claims are supported by the data. Option B is correct.
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
When mass increases and distance reduces, gravity rises. Gravity also lowers when the distance between two points grows and the mass decreases.
From the table, it is observed that gravitational forces are strongest between objects with identical masses, claims are supported by the data.
Hence, option B is correct.
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A force of 15 newtons is applied to an object with a mass of 5kilograms what will be the objects final velocity after 10 seconds
Answer:
See below
Explanation:
First, find acceleration from
F = m * a
then vf = a * t for the final velocity ...... Plug and chug
Question 2 of 10
which lines give the best example of a leading approach, as opposed to a
leaping approach?
o a. hot pavement under my feet
and machines make mistakes.
o b. hot pavement under my feet.
forget me as soon as you can.
o c. hot pavement under my feet
and my mouth dry as sand.
its c
Hot pavement under my feet and my mouth dry as sand. (Option C)
The lines that give the best example of a leading approach, as opposed to a leaping approach, are in option c: "hot pavement under my feet and my mouth dry as sand."
This is because the line is describing the immediate physical sensations and emotions the speaker is experiencing, suggesting a gradual and deliberate approach to the situation.
In contrast, a leaping approach would involve a sudden, impulsive action or decision, which is not evident in any of the given lines.
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the e. coli chromosome is 1.28 millimeters long. under optimal conditions the chromosome is replicated in 40 min. a. what is the distance travelled by one replication fork from the oric in 1 minute?
Under optimal conditions, the distance traveled by one replication fork from the oric in 1 minute is 0.032 millimeters.
To calculate the distance traveled by one replication fork from the origin of replication (oric) in one minute, we need to determine the speed of replication fork movement.
Given that the E. coli chromosome is 1.28 millimeters long and replication occurs in 40 minutes, we can calculate the speed of replication fork movement as follows:
Speed = Distance ÷ Time
Distance traveled by one replication fork in 40 minutes = 1.28 mm
Speed = 1.28 mm ÷ 40 min
= 0.032 mm/min
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If an object has a fast velocity, the dots on a ticker tape diagram will be _____.
very long
far apart
very short
close together
Answer:
If an object has a fast velocity, the dots on a ticker tape diagram will be far apart.