When three resistors are combined in series, the total resistance of the combination is __________.

In this case, the detergent is working because it acts as a cleaning agent.

Detergents are specifically designed to remove stains and dirt from fabrics. They contain surfactant molecules that have both hydrophobic (water-repelling) and hydrophilic (water-attracting) parts. When detergent is added to water, the hydrophobic part of the surfactant molecules attaches to the oily or greasy components of the stain, while the hydrophilic part interacts with water.

The surfactant molecules surround the stain, breaking it down into smaller particles called micelles. These micelles are then suspended in the water and can be easily rinsed away, along with the stain, when the garment is washed. Detergents also help to emulsify and solubilize other types of stains, including protein-based stains like egg stains.

It's important to note that the effectiveness of a detergent in removing stains is not necessarily determined by being the best brand, being very acidic, acting as a catalyst, or being an ion. Different detergents may have different formulations and ingredients that affect their cleaning properties.

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Answer:

FN=-Fg -> Fg=mg -> Fg = 238 kg*9.8 m/s^2 ->

Fg = -2432.4 so FN = 2432.4 -> FF = μs*FN ->

FF = 0.22*2332.4 N -> FF = 513.128 ->

Fapplied > 513.128 N

Explanation:

...

Answer:

pulling

Explanation:

When stretching, the right way to stretch is to stretch until one feels the tension pull in the muscle. This pull is then held and sustained for a period of about 15 to 60 seconds. This considered the safest way to stretch, and it gives the muscles and connective tissue time to “reset” the stretch reflex.

Answer:

First, to be a barrier keeping the constituents of the cell in and unwanted substances out and, second, to be a gate allowing transport into the cell of essential nutrients and movement from the cell of waste products.

Explanation:

It has two functions

Answer:

وؤتي يتنييوتينستصميوخصز ءتث. ثنصطث

Answer:

In physics, a state of matter is one of the distinct forms in which matter can exist. Four states of matter are observable in everyday life: solid, liquid, gas, and plasma.

...

To From Gas

Solid Deposition

Liquid Condensation

Plasma Ionization

Time required to 200 meter long train to pass through a 160 meter tunnel at a speed of 18 meters per second is 11.1s.

Given, length of train 200 meter

Length of tunnel is 160 meter

Speed = 18 m/s

Formula of Speed = distance/ time

Time = Distance/speed

Time = 200/ 18

Time = 11.1 s.

Hence, time required to 200 meter long train to pass through a 160 meter tunnel at a speed of 18 meters per second is 11.1s.

Speed is the time rate at which an object is moving along a direction, whilst velocity is the rate and direction of an item's motion. Put every other manner, speed is a scalar value, while velocity is a vector.

The Italian physicist Galileo Galilei is credited with being the first to measure pace by way of thinking about the distance covered and the time it takes. Galileo defined pace as the distance covered per unit of time.

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Thus, the weight of the roof 1.422 × 10⁵ Newton.

A force is an effect that can modify the velocity of an item in physics. A force can cause an object with mass to alter its velocity, or accelerate (for example, moving from a condition of rest). An obvious way to define force is as a push or a pull. Being a vector quantity, a force also has magnitude and direction. It is expressed as a newton in the SI system (N). The sign F represents force.

Given that,

Speed of air (V) = 180 km/hour

                         = (180 km ÷ 1 hour) × (1000 m ÷ 1 km) × (1 hour ÷ 3600 sec)

                         = 50 m/sec

Area (A) = 6.4 m × 14.0 m = 89.6 m²

Density of air (ρ) = 1.27 kg/m³

Now, we can say weight must equal to the lift force

Thus, \(F_{air}\) = 1/2 ρV²A

                = 1/2 × 1.27 × (50)² × (89.6)

                = 142240 Newton

                = 1.422 × 10⁵ Newton

Thus, the weight of the roof 1.422 × 10⁵ Newton.

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The complete question is as follows:

A 180-km/h wind blowing over the flat roof of a house causes the roof to lift off the house. If the house is 6.4 m x 14.0 m in size, estimate the weight of the roof. Assume the roof is not nailed down.

Answer:

Let's define:

The position zero will be in the first point where the truck and police car meet. (So the initial position of both vehicles is zero)

Then, the position equation for the truck is:

T(t) = 20m/s*t

Where t is our variable, time in seconds.

Now, at t = 5s, the car starts accelerating.

Ac(t) = 2m/s^2                    for( t ≥ 5s)

For the velocity of the car, we must integrate that.

V(t) = (2m/s^2)*(t - 5)           for (t ≥ 5s)

Where i introduced a little change in the variable because the velocity of the car starts to increase for t larger than 5 seconds.

For the position of the car we integrate again.

C(t) = (1m/s)*(t - 5)^2            for (t ≥ 5s)

Now, let's answer the questions:

Determine the time at which the speed of the truck is equal to the speed of the police car.

Then we must have:

V(t) = (2m/s^2)*(t - 5)  = 20m/s.   (Remember that we only can use times requal or larger than 5 seconds).        

2m/s^2*t - 10m/s = 20m/s

2m/s^2*t = 30m/s

t = (30/2) s = 15s

The velocities of both vehicles will be the same after 15 seconds.

t1 = 15s

How the positions will compare at this time?

The easier thing will be to evaluate the position equation of each vehicle in this time:

T(15s) = 20m/s*15s = 300m

C(15s) = (1m/s^2)*(15s - 5s)^2 = (1m/s^2)*(10s)^2 = 100m.

Then we can see that the truck is 200m ahead of the car.

But remember that the police car is accelerating, so the velocity will keep increasing meaning that eventually, the car will catch the truck.

Gravitational force is not related to other force because it is related to gravity.

Electrostatic force and magnetic force are link to each other because both have charges. Electrostatic force is type of force that is present between two electrically charged particles. They can either be a repulsive or attractive force.

So we can conclude that Gravitational force is not related to other force because it is related to gravity.

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a. The time for it to come to rest is (-1.5 rad/s)/α.

b. Its angular acceleration is -0.000356 rad/s²

c. The time required for the first 20 revolutions is approximately 17.1 seconds.

Radian per second is used to measure angular speed. Both angular velocity and angular speed are represented using the same formula. Unlike angular speed, which simply describes magnitude, angular velocity is a vector term that expresses both direction and magnitude.

(a) The final angular speed of the flywheel is 0, and the initial angular speed is 1.5 rad/s. Therefore, the change in angular speed is Δω = 0 - 1.5 = -1.5 rad/s. Let α be the constant angular acceleration. We can use the equation:

Δω = αΔt

Solving for Δt, we get:

Δt = Δω/α = (-1.5 rad/s)/α

(b) To find the angular acceleration α, we can use the equation:

ωf² = ωi² + 2αΔθ

where ωf is the final angular velocity, ωi is the initial angular velocity, Δθ is the change in angle (in radians), and α is the angular acceleration.

Since the flywheel turns through 40 revolutions, or 80π radians, we have:

ωf² = (1.5 rad/s)² + 2α(80π rad)

At the final angular velocity, ωf = 0, so we can simplify to:

0 = (1.5 rad/s)² + 2α(80π rad)

Solving for α, we get:

α = -(1.5 rad/s)² / (2(80π rad)) ≈ -0.000356 rad/s²

(c) To find the time required for the first 20 revolutions, we can use the equation:

Δθ = ωiΔt + 1/2α(Δt)²

where Δθ is the angle turned during the time interval, ωi is the initial angular velocity, and α is the angular acceleration. We want to find Δt for Δθ = 20 revolutions, or 40π radians.

Using the values of ωi and α from parts (a) and (b), we get:

40π rad = (1.5 rad/s)Δt + 1/2(-0.000356 rad/s²)(Δt)²

Simplifying and solving for Δt, we get:

Δt ≈ 17.1 s

Therefore, the time required for the first 20 revolutions is approximately 17.1 seconds.

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The second allowed energy of an electron is 4 times the first allowed energy.

The first allowed energy can be calculated using the following equation:

En = n²h² / 8mL²where n is the principal quantum number, h is Planck's constant, m is the mass of the electron, and L is the length of the region of space to which the electron is confined.

The value of the first allowed energy is given by;E1 = h² / 8mL²

The value of h = 6.626 x 10^-34 J·s, and the value of m = 9.11 x 10^-31 kg.

Therefore, we have:E1 = (6.626 x 10^-34 J·s)² / 8(9.11 x 10^-31 kg)(0.300 x 10^-9 m)² = 3.69 x 10^-19 J

The second allowed energy of the electron, E2, is given by:E2 = 4E1= 4 × 3.69 x 10^-19 J= 1.48 x 10^-18 J

The answer is 1.48 x 10^-18 J.

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It is more likely that the storm you observed, which passed over you after an hour, was a mesoscale convective system (MCS) rather than an air mass thunderstorm.

Air mass thunderstorms typically form and dissipate within the boundaries of a single air mass. They are generally short-lived and do not typically travel large distances. Therefore, it is less likely for an air mass thunderstorm to travel from a location far to the west to your current location within just an hour.

On the other hand, mesoscale convective systems are larger-scale weather systems that can cover hundreds of miles and persist for several hours or even longer. They often have organized structures, such as squall lines or clusters of thunderstorms, and can move over significant distances. It is more plausible for a mesoscale convective system to travel from a distant location to your area within the span of an hour.

Considering the time and distance covered, the fact that the storm passed over you after an hour suggests that it was likely a mesoscale convective system.

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Explanation:

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 The charge Q is uniformly distributed throughout the sphere. The correct answer is (B)

When a solid conducting sphere is given a positive charge Q, the charge will distribute itself evenly throughout the surface of the sphere due to the repulsion of like charges. This is known as the "Faraday's ice pail experiment".

According to the principle of electrostatics, the charge on a conductor always resides on its surface and distributes itself in a way that the electric field inside the conductor is zero. Since the charge on a conductor always resides on its surface, it follows that the charge Q in this case must be uniformly distributed throughout the surface of the sphere.

Option (A) is not true because the charge is not concentrated at the center of the sphere. If the charge was concentrated at the center of the sphere, the electric field would not be zero inside the conductor, which contradicts the principle of electrostatics.

Option (C) and (D) are not true because the density of the charge does not change radially outward from the center. If the density decreased or increased radially outward, the electric field inside the conductor would not be zero, which again contradicts the principle of electrostatics.

Option (E) is not true because the charge is distributed throughout the entire volume of the sphere, not just on its surface. A solid conductor has free charges that can move throughout its entire volume, so the charge will distribute itself throughout the entire volume of the sphere until the electric field inside the conductor is zero.

Therefore, the correct answer is (B) it is uniformly distributed throughout the sphere.

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After three half-lives, 1/8 (or 0.125) of the parent isotope remains. Thus, 0.125 times the parent atoms. The daughter isotope would be equivalent to the remaining parent isotope, 0.125 times the original number of parent atoms.

After three half-lives, the parent isotope has exponentially decayed, forming the daughter isotope. Each half-life reduces the parent isotope by half and increases the daughter isotope. Three half-lives have passed, reducing the parent isotope to 1/8 of its initial level. The rock sample would have 1/8 of the parent isotope.

The daughter isotope would have accumulated during decay. After three half-lives, the daughter isotope would have reached 3/8 of the parent isotope as each half-life creates one-half of it. After three half-lives, the rock sample would have 1/8 of the parent isotope and 3/8 of the daughter.

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The correct answer is that the magnitude of the force F3 applied to the third box is equal to the magnitude of the force F1 applied to the first box.

The magnitude of the force F3 that the handler applies to the third box can be compared to the magnitude of the force F1 applied to the first box by using the equation F = ma.

For the first box, the force F1 is equal to the mass of the box (m) multiplied by the acceleration of the box (a), or F1 = ma.

For the third box, the force F3 is equal to the mass of the box (m/2) multiplied by the acceleration of the box (2a), or F3 = (m/2)(2a).
Simplifying the equation for F3 gives us F3 = ma.

Therefore, the magnitude of the force F3 applied to the third box is equal to the magnitude of the force F1 applied to the first box.
In other words, F3 = F1.

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Answer:

\(1.27\:\text{s}\)

Explanation:

We can use the following kinematics equation to solve this problem:

\(v_f=v_i+at\)

Solving for \(t\):

\(-24.5=-12.1+-9.8t,\\-12.4=-9.8t,\\t=\frac{-12.4}{-9.8}\approx \boxed{1.27\:\mathrm{s}}\)

Answer:

4.96×10¯¹⁰ N

Explanation:

The following data were obtained from the question:

Mass 1 (M1) = 300 Kg

Mass 2 (M2) = 300 Kg

Separating distance (r) = 110 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Gravitational force (F) =?

The gravitational force between the two goal posts can be obtained as follow:

F = GM1M2 / r²

F = 6.67×10¯¹¹ × 300 × 300 / 110²

F = 6.003×10¯⁶ / 12100

F = 4.96×10¯¹⁰ N

Therefore the gravitational force between the two goal posts is 4.96×10¯¹⁰ N

You can start the problem by using the formula for capacitance, C = Q/V, where C is the capacitance, Q is the charge stored on the capacitor, and V is the potential difference across the capacitor.

A capacitor is a passive electrical component that stores electrical energy in an electric field. It consists of two conductive plates, separated by an insulating material called the dielectric. When a voltage is applied across the conductive plates, an electric field is created, which stores energy in the dielectric. The ability of a capacitor to store electrical energy is measured in farads (F).

Given that Capacitor 2 has half the capacitance and twice the potential difference as Capacitor 1, you can express the capacitance and potential difference of Capacitor 2 in terms of those of Capacitor 1.

C₂ = 1/2 × C₁ V₂ = 2 × V₁

You can use these equations to find the ratio of the stored energy in the two capacitors. The stored energy in a capacitor is given by the formula U = 1/2CV², where U is the stored energy, C is the capacitance, and V is the potential difference.

Uc1 = 1/2C₁V₁² Uc2 = 1/2C₂V₂²

By substituting the values of C₂ and V₂ in terms of C₁ and V₁, you can find the ratio of the stored energy in the two capacitors:

Uc1/Uc2 = (1/2C₁V₁²) / (1/2×(1/2C₁) (2V₁) ²) Uc1/Uc2 = 1/8

The ratio of stored energy in the two capacitors is 1/8.

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minimum time interval to stop should be = 0.08 seconds whereas the friction minimum stopping distance  = 0.64 m.

Which four forms of friction are there?

The force that prevents one solid item from moving across another is known as friction. Static friction, sliding friction, rolling friction, and fluid friction are the four main categories of friction.

What is frictional force, exactly?

Two surfaces that come into contact and glide against one another produce frictional force. The following variables impact the frictional force: Surface roughness and the amount of force pressing them together have the biggest an impact on these forces.

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Answer:

• Momentum always depends on the mass and speed/velocity of the body in motion.

Explanation:

\({ \tt{momentum = mass \times velocity}} \\ \)

Answer:

A lightbulb has 25 W stamped on it. What does this mean?:

These labels mean that each lightbulb has Its respective power delivered to It when It Is connected to a constant

Explanation:

Answer:

Gravity

Explanation:

It is gravity because the sun's gravity pulls all the planets towards itself and keeps the planets in the sun's orbit

Answer:

D

Explanation: