Answer:
A peptic ulcer is a sore on the lining of your stomach or the first part of your small intestine (duodenum). If the ulcer is in your stomach, it is called a gastric ulcer. If the ulcer is in your duodenum, it is called a duodenal ulcer
example of unlile parallel forces
Answer:
Explanation:
In mechanical engineering, a parallel force system is a situation in which two forces of equal magnitude act in the same direction within the same plane, with the counter force in the middle. An example of this is a see saw.
Forces which are parallel and acting a similar way are called like parallel forces. Like Parallel forces are the forces that are parallel to each other and have the same direction. Unlike parallel forces are the forces that parallel yet have directions inverse to each other.
when the parallel force system is a situation in which two forces of equal magnitude act in the same direction within the same plane, Two forces that are parallel can either be in the same direction or in opposite directions.
(hope this helps can i plz have brainlist :D hehe)
A car accelerates at a rate of 4.00 m/swest for 5.0 seconds. What is the car's change in
velocity?
Answer:
20 m/s
Explanation:
Acceleration = Change in velocity/ time
4 = Change in Velocity/ 5
Change in velocity = 20 m/s
Imagine a cannonball is being launched from a cannon on a very high cliff. What mathematical ideas/concepts are involved
When a cannonball is being launched from a cannon on a very high cliff, the mathematical ideas and concepts that are involved are as follows; the distance and displacement concepts are involved.
Distance refers to the total length of the path taken during motion while displacement refers to the shortest distance between the initial and final position of an object. When the cannonball is launched, its distance and displacement will be determined and calculated. projectile motion concepts are involved. Projectile motion is the motion of objects thrown or projected into the air, subject to only the acceleration of gravity. The motion of the cannonball is subjected to gravity, air resistance, and initial velocity, and therefore, these concepts are involved. the trajectory concepts are involved. Trajectory refers to the path followed by an object in motion. The cannonball follows a curved path or trajectory when launched, and this trajectory is analyzed in the mathematical equations .Fourthly, the velocity, acceleration, and time concepts are involved. Velocity is the rate of change of distance with respect to time. Acceleration is the rate of change of velocity with respect to time, while time refers to the duration taken by an object in motion to travel from one point to another. These concepts are used in the main answer and calculations while analyzing the motion of the cannonball.
the mathematical concepts involved when a cannonball is launched from a cannon on a very high cliff are distance, displacement, projectile motion, trajectory, velocity, acceleration, and time. These concepts play a critical role in analyzing and calculating the motion of the cannonball.
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Identify trends in physical properties based on intermolecular forces
The Boiling point,melting point, surface tension and viscousity will increase while the Vapor pressure will decrease.
What are intermolecular forces?Intermolecular forces are the forces that bind two molecules together. Physical properties are affected by the strength of intermolecular forces
An increase in the strength of intermolecular forces increases will lead to an increase in force applied to break the barriers posed by the strength of the molecules.
This increased intermolecular strength will cause a rise in boiling point,melting point, viscousity and surface tension.
The Vapor pressure reduces with increasing intermolecular strength. Vapor pressure is the amount of vapor that is equilibrium with its own liquid or solid. Hence,with increasing intermolecular strength the amount of vapor that is in equilibrium with its own liquid will reduce.
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Marcel and Jose lifted 50 pounds as many times as they could. Marcel could lift the weight 25 times. Jose could lift the weight 30 times. Marcel and Jose can conclude that __________.
A.
Jose has better muscular endurance than Marcel
B.
Jose has better muscular strength than Marcel
C.
Marcel has better muscular strength than Jose
D.
Marcel has better muscular endurance than Jose
Answer:
A
Explanation:
What force is required to accelerate a 6 kg bowling ball at 2 m/s/s forward?
Answer:
12N
Explanation:
Force = mass * acceleration.
6 * 2 = 12
Taking into account the Newton's second law, the force required to accelerate a 6 kg bowling ball at 2 m/s² forward is 12 N.
In first place, acceleration in a body occurs when a force acts on a body. There are two factors that influence the acceleration of an object: the net force acting on it and the mass of the body.
Newton's second law states that this force will change the speed of an object because the speed and / or direction will change. These changes in velocity are called acceleration.
So, Newton's second law defines the relationship between force and acceleration mathematically. This law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object.
Mathematically, Newton's second law is expressed as:
F= m×a
where:
F = Force [N] m = Mass [kg] a = Acceleration [m/s²]In this case, you know:
F= ? m= 6 kg a= 2 m/s²Replacing:
F= 6 kg× 2 m/s²
Solving:
F= 12 N
Finally, the force required to accelerate a 6 kg bowling ball at 2 m/s² forward is 12 N.
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brainly.com/question/23845187?referrer=searchResults brainly.com/question/13959891?referrer=searchResultsWhen your car moves along the highway at constant velocity, the net force on it is zero. Why, then, do you have to keep running your engine? a. To keep things like your radio and air conditioning running b. In case you have to suddenly accelerate C. To overcome frictional forces
The reason you have to keep running your engine when your car is moving at a constant velocity on the highway is to overcome frictional forces.
So, the correct answer is C.
Understanding Frictional forcesWhen your car is moving along the highway at a constant velocity, the net force acting on it is zero. However, you still need to keep running your engine to overcome the frictional forces acting on your car.
Frictional forces such as air resistance, rolling resistance, and the resistance caused by the engine and transmission of your car all act against the motion of your car.
Therefore, your engine needs to continue to produce power to counteract these forces and maintain your car's speed.
Additionally, keeping your engine running is important to power essential features of your car, such as your radio and air conditioning, and to prepare for sudden acceleration needs, such as when merging onto a highway or passing another vehicle.
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(a) that the acceleration (A) will have no components that are identically zero. (B) may have some components that are identically zero. (C) will have only a z component that is identically zero. (D) will have an identically zero z component, and maybe an identically zero component in the x or y directio
Answer:
D.
Explanation:
acceleration in the z component = velocity in z component / time. The question states velocity in z component is zero. Therefore, acceleration in z component = 0/time = 0.
Now the question does not specify whether the other velocity vectors (x or y) is zero or not. So its D.
which of the following statements about seismic wave ray paths is most accurate?
In conclusion, seismic wave ray paths are a valuable tool for studying earthquakes and the interior structure of the Earth, and can be used to determine the location and strength of quakes and to study the composition of rocks in the Earth's interior.
Seismic wave ray paths refer to the paths followed by waves of energy that are produced by earthquakes. These waves are caused by the sudden movement of rocks along fault lines and can be felt thousands of miles away. As a result, scientists study seismic wave ray paths to learn more about earthquakes and the interior structure of the Earth. One of the most accurate statements about seismic wave ray paths is that they can be used to determine the location and strength of earthquakes. By analyzing the time and location of seismic wave arrivals, scientists can calculate the location of the earthquake's epicenter and estimate the strength of the quake. Another accurate statement about seismic wave ray paths is that they are influenced by the type of rock they pass through. Different types of rocks have different densities and elastic properties, which can cause seismic waves to change speed and direction as they pass through them. This phenomenon is known as refraction and is used by geologists to study the composition of the Earth's interior.
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assume the water interacts with the generator for ten percent (10.0%) of the time it took to fall. if it is at rest just before it exits the generator, how much power, in watts, does the water produce?
The water does not produce any power in this scenario, as the work done by the water is zero.
Assuming the water interacts with the generator for 10% of the time it took to fall and is at rest just before it exits the generator, we can calculate the power produced by the water.
To find the power, we need to know the work done by the water, which can be calculated using the formula:
Work = Force x Distance x Cos(angle)
Since the water is at rest before exiting the generator, it means that the force acting on it is equal to zero. Therefore, the work done by the water is also zero.
Power is defined as the rate at which work is done, which can be calculated using the formula:
Power = Work / Time
In this case, since the work done by the water is zero, the power produced by the water will also be zero.
Therefore, the water does not produce any power in this scenario.
With proper conclusion, the water does not produce any power in this scenario, as the work done by the water is zero.
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The flat rotation curves of spiral galaxies tell us that they contain a lot of dark matter. do they tell us anything about where the dark matter is located within the galaxy?
Yes, they tell us that dark matter is spread throughout the galaxy, with most located at large distances from the galactic center.
While modified gravity theories exist, it is very difficult to build a modified gravity theory that is consistent with all the observations we have (ranging from the solar system to the cosmos as a whole) and not run afoul of the data. The dark matter hypothesis, in the meantime, though not without issues of its own, can nonetheless deal with galaxy rotation curves and also other challenges from cosmology.
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.A state function does not depend on the system's past or future
True or false?
True. A state function, by definition, does not depend on the system's past or future. It only relies on the current state or condition of the system.
A state function is a property that is determined solely by the initial and final states of the system, regardless of the path taken to reach those states. Examples of state functions include temperature, pressure, volume, internal energy, enthalpy, entropy, and Gibbs free energy.
The independence from the system's past or future is a fundamental characteristic of state functions. It means that the value of a state function remains the same regardless of how the system arrived at its current state or what happens to it in the future. This property allows for the convenient analysis of thermodynamic processes and the calculation of changes in system properties using state functions.
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A block of weight w = 25.0 N sits on a frictionless inclined plane, which makes an angle θ = 30.0 ∘ with respect to the horizontal, as shown in the figure. (Figure 1)A force of magnitude F = 12.5 N , applied parallel to the incline, is just sufficient to pull the block up the plane at constant speed.
A: The block moves up an incline with constant speed. What is the total work Wtotal done on the block by all forces as the block moves a distance L = 3.80 m up the incline? Include only the work done after the block has started moving at constant speed, not the work needed to start the block moving from rest.
B :What is Wg , the work done on the block by the force of gravity w⃗ as the block moves a distance L = 3.80 m up the incline?
C: What is WF , the work done on the block by the applied force F⃗ as the block moves a distance L = 3.80 m up the incline?
D: What is WN , the work done on the block by the normal force as the block moves a distance L = 3.80 m up the inclined plane?
a ) The total work Wtotal done on the block by all forces = 0
b ) The work done on the block by the force of gravity = - 47.5 J
c ) The work done on the block by the applied force F = 47.5 N
a ) The total work Wtotal done on the block by all forces,
Since, only the work done after the block has started is considered, the total work done is the change in kinetic energy. Since, the block is moving at a constant speed there is no change in kinetic energy and so total work Wtotal done is zero.
b ) The work done on the block by the force of gravity,
Wg = Fg * h * cos θ
Fg = W = 25 N
sin 30 = h / 3.8
h = 1.9 m
Wg = 25 * 1.9 * cos 180
Wg = - 47.5 J
c ) The work done on the block by the applied force F,
WF = F * d * cos θ
WF = 12.5 * 3.8 * cos 0
WF = 47.5 N
d ) The work done on the block by the normal force,
Normal force acts perpendicular to the surface. The movement is towards the right side of the surface. So cos θ will be cos 90 which is equal to zero. So the work done will be zero.
Therefore,
a ) The total work Wtotal done on the block by all forces = 0
b ) The work done on the block by the force of gravity = - 47.5 J
c ) The work done on the block by the applied force F = 47.5 N
d ) The work done on the block by the normal force = 0
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FILL IN THE BLANK. Over time, hominin legs lengthened relative to trunk lengths which __________.
Over time, hominin legs lengthened relative to trunk lengths which allowed for more efficient bipedal locomotion.
As hominins evolved, their legs gradually became longer compared to their trunks. This change allowed for a more efficient form of bipedal locomotion. Walking on two legs became easier and more energy-efficient, as the longer legs allowed for a longer stride length and more efficient use of muscles.
In conclusion, the lengthening of hominin legs relative to their trunks was an important adaptation that allowed for the evolution of bipedal locomotion, which was crucial for the survival and success of early human ancestors.
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A power station that is being started up for the first time generates 6120 MWh of energy over a 10 hour period. (i) If the rated power at full capacity is 660 MW, calculate how long it takes the power station to reach its full power output. (You may assume a constant increase in power from zero to full power) (ii) State what type of power station can be started up fastest and explain why the start-up times for other types of power station are slower. Explain briefly, how this is relevant to optimising the usage of windfarms. c) What is the Bremsstrahlung effect and how can it be avoided in shielding design? d) Sketch the electromagnetic field output from an antenna, describing in detail the two main regions in the output field.
(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.
(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:
Energy = Power × Time
Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:
Time = Energy ÷ Power
Converting the energy to watt-hours (Wh):
Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh
Converting the power to watt-hours (Wh):
Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh
Now we can calculate the time:
Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours
Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.
(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.
In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.
This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.
(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.
In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.
(d) The electromagnetic field output from an antenna can be represented by two main regions:
Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.
Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation. The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.
The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.
In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.
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a spotlight on the ground shines on a wall 12 m away. if a man 2 m tall walks from the spotlight toward the building at a speed of 1.3 m/s, how fast is the length of his shadow on the building decreasing when he is 4 m from the building? (round your answer to two decimal places.) m/s
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed of 1.3 m/s. The length of his shadow on the building decreasing when he is 4 m from the building is 0.48 m/s.
What is meant by angles?An angle is a shape which can be determined by two rays or lines which is a shared terminal. The name "angle" comes from the Latin word "angulus," which means "corner."
The common terminal of the two rays can be known as the vertex and that can be referred to as an angle's sides. The angle in the plane does not always need to be in Euclidean space.
Here the Given values are,
Distance of man from building = x
∴ initially, x = 12
dx/dt = -1.3 m/s
Let, Shadow height = y
Now, we have to
Solve for \(\frac{dy}{dt}\), when x = 4m
From the attached diagram it's clearly seen that the similar triangles have with similar base/height ratios,
\(\frac{2}{12-x} = \frac{y}{12}\\\ y= \frac{24}{12-x} \\\frac{dy}{dt} =\frac{24}{(12-x)^{2}}*\frac{dx}{dt}\)
At x=4,
dy/dt will become,
= 24/(12-x)²× -1.3
Thus, y = - 0.48 m/s.
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An object is NOT accelerating. Is its motion changing?
Yes or No?
Answer:
Acceleration is 0. Acceleration is the change in velocity over time, so if acceleration is 0, the change in velocity is 0 no matter how much time passes. THIS DOES NOT MEAN VELOCITY IS 0. it only means that velocity is constant. In other words, the speed of motion will not change
Explanation:
When you toss a coin straight up, it moves upward, turns around, and drops. During this time the acceleration of the coin is zero throughout its up and down motion first decreasing, then increasing. downward and constant. upward and constant.
When you toss a coin straight up, the acceleration of the coin is downward and constant.
Gravity acts as a downward force on the coin throughout its motion. As the coin moves upward, the force of gravity slows it down until it reaches its highest point, known as the peak or apex.
At this point, the coin momentarily stops moving upward and starts to fall back down due to the force of gravity. During this entire upward and downward motion, the acceleration of the coin remains constant and directed downward.
According to Newton's second law of motion, the net force acting on an object is equal to its mass multiplied by its acceleration. In the case of the coin, the net force is the force of gravity pulling it downward, and the acceleration is constant.
The coin experiences a constant downward acceleration of approximately 9.8 m/s² (assuming no air resistance), regardless of whether it is moving upward or downward. Therefore, the correct answer is downward and constant.
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Questions -
4.3 Calculate the unknown forces X and Y for the
balanced beam shown.
1.0 m+
2.5 m
te)
X
400N
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value of \(X = 1000 \ N\) and \(Y = 1400 \ N\)
Explanation:
Considering the diagram,
Taking moment about the pivot , we have
\(X * 1 = 400 * 2.5\)
=> \(X = 1000 \ N\)
Generally given that the bar is at equilibrium then the upward forces is equal to the down ward force
So
\(Y = X + 400\)
=> \(Y = 1000 + 400\)
=> \(Y = 1400 \ N\)
muscle up lab for physics can someone help me with this question please. why might the horsepower for two activities using the same muscle group (running up the stairs and jumping or arm curls and push ups) yield different amounts of power?
Answer:
Work
Explanation:
The amount of work you put into the activities can affect different amounts of power. Since power is work/time and work is force/displacement, it depends on the amount of work you put into it to alter the power.
Sowwy if my explanation is wack :C
half-wave rectified power is obtained by placing a(n) _____ in one of the ac power lines.
Half-wave rectified power is obtained by placing a diode in one of the AC power lines.
A diode is an electronic component that allows current to flow in only one direction while blocking it in the opposite direction. By placing a diode in one of the AC power lines, it allows current to flow during half of the AC cycle while blocking it during the other half. This results in half of the waveform being rectified or converted to a unidirectional current.
The rectified output obtained through this arrangement is known as half-wave rectified power. It is commonly used in certain applications where a pulsating DC output is sufficient, such as in some low-power devices or for simple battery charging.
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17. A volleyball weighs about 300 grams.
Calculate the potential energy of a volleyball
that is in the air at a height of 15 m. (g = 9.8
m/s-). Round your answer to two decimals
and show the correct units of measure. Be
sure to convert units if necessary.
Answer:
PE = 44.1 J
Explanation:
Ok, to have the specific data, the first thing we must do is convert from grams to kilograms. Since mass must always be in kilograms (kg)
We have:
1 kilograms = 1000 grams.We convert it using a rule of 3, replacing, simplifying units and solving:
\(\boxed{\bold{x=\frac{gr*1\ kg}{1000\ gr}=\frac{300\ gr*1\ kg}{1000\ gr}=\frac{300\ kg}{1000}=\boxed{\bold{0.3\ kg}}}}\)==================================================================
Earth's gravity is known to be 9.8 m/s², so we have:
Data:
m = 0.3 kgg = 9.8 m/s²h = 15 mPE = ?Use formula of potencial energy:
\(\boxed{\bold{PE=m*g*h}}\)Replace and solve:
\(\boxed{\bold{PE=0.3\ kg*9.8\frac{m}{s^{2}}*15\ m}}\)\(\boxed{\boxed{\bold{PE=44.1\ J}}}\)Since the decimal number, that is, the number after the comma is less than 5, it cannot be rounded, then we have this result.
The potential energy of the volleyball is 44.1 Joules.
Greetings.
A spring was compressed by 2cm and then it was released and launched a toy car from the rest. If the force constant of the spring is 40 N/m, what is the final velocity of the toy car with the mass of 200g? assuming there is no friction force. a. 27m/s b. 0.5m/s c. 0.28m/s d. 16m/s
The final velocity of the toy car is 0.2 m/s. Therefore, none of the given option is correct.
We can apply the theory of mechanical energy conservation to determine the toy car's final velocity. When the spring is squeezed, the system's initial mechanical energy is stored there as potential energy. This potential energy is transformed into kinetic energy as the spring is released, launching the toy car.
The following formula can be used to determine the potential energy held in the spring:
Potential energy (PE) = 1/2 * k * x²
where x is the spring's compression distance and k is the spring's force constant. Adding the specified values:
k = 40 N/m
x = 0.02 m (since the spring is compressed by 2 cm which is equivalent to 0.02 m)
PE = 1/2 * 40 * (0.02)²
PE = 0.004 J
The toy car transforms this potential energy into kinetic energy. The following equation can be used to determine an object's kinetic energy:
Kinetic energy (KE) = 1/2 * m * v²
where m is the mass of the object and v is its velocity. Plugging in the given values:
m = 0.2 kg
KE = 0.004 J
0.004 = 0.5 * 0.2 * v²
v² = 0.004 / (0.5 * 0.2)
v² = 0.04
v = √0.04
v = 0.2 m/s
So, the final velocity of the toy car would be 0.2 m/s.
Therefore, none of the option is correct.
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Ava learns in her science class that the Sun is much larger than the Moon. When she looks at the Sun and the Moon in the sky, however, they appear to be about the same size. Which of the following best explains why this is true?
A.
The Moon is much older than the Sun.
B.
The Moon shines more brightly than the Sun.
C.
The Moon is much farther away from the Earth than the Sun is.
D.
The Moon is much closer to the Earth than the Sun is.
Please select the best answer from the choices provided
A
B
C
D
Answer:
D hope this helps plz mark brainliest
Explanation:
Smaller the surface area greater the gravitational force and vice–versa yes or no? justify the statement.
Answer:
It is true that Smaller the surface area greater the gravitational force and vice versa
Explanation:
The gravitational force depends on the distance between the two objects
F=GMm/r2
where G = gravitational constant
M = mass of one object
m = mass of second object
r is the distance between the two objects
Gravitational force is inversely proportional to the square of the distance between two objects. Hence, it can be said the Gravitational force is inversely proportional to the area and hence as the area increases gravitational force will decrease or vice versa
A car moves 4m in 2s. The speed is_____.
(t/d)
Answer:
2m/s.
Explanation:
Speed = Distance / Time
= 4m / 2s
= 2m/s.
Determine(a) the capacitance.
The question you provided is incomplete as it lacks the necessary information to determine the capacitance.
In order to calculate capacitance, you need to know the charge stored on the capacitor and the voltage across it. it lacks the necessary information to determine the capacitance.
Without these values or any other relevant details, it is not possible to provide a specific answer. In order to calculate capacitance you need to know the charge stored on the capacitor and the voltage across it.
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Blocks A and B have a mass of 8 kg and 12 kg respectively. Using the coefficients of static fiction indicated, determine the largest force P which can be applied to the cord without causing motion. There are pulleys at C and D. Express your answer to three significant figures and include the appropriate units. P =
The largest force P that can be applied to the cord without causing motion is approximately 95.4 N.
To determine the largest force P, we need to consider the forces acting on the system and the conditions for static equilibrium.
The blocks A and B are connected by a cord that passes over pulleys at C and D. The coefficient of static friction between block A and the surface it rests on is μ₁, and the coefficient of static friction between block B and the surface it rests on is μ₂.
For block A to remain in equilibrium, the force applied by the cord (P) must be less than or equal to the maximum static friction force (f₁) between block A and the surface:
P ≤ f₁ = μ₁ * m₁ * g
Similarly, for block B to remain in equilibrium, the force applied by the cord must be less than or equal to the maximum static friction force (f₂) between block B and the surface:
P ≤ f₂ = μ₂ * m₂ * g
where m₁ and m₂ are the masses of blocks A and B, g is the acceleration due to gravity.
Given that the masses of blocks A and B are 8 kg and 12 kg respectively, we need the coefficients of static friction (μ₁ and μ₂) to calculate the maximum force P.
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After release of jet, energy is lost by the engine. How principle of conservation of energy is obeyed in this condition.
Answer:
The principle of conservation of energy states that in a closed system, the energy can neither be created nor destroyed between interacting particles and remains constant or transformed from one form to another
In the jet engine, the release of jet changes the number of interacting particles in the engine, and given that energy cannot be created in the instantaneously closed system of the engine, energy is carried away and therefore lost by particles in the jet exhaust
The conservation of energy principle is therefore obeyed in the condition in which the jet engine losses energy by the release of jet
Explanation: