When this astronaut goes
back to Earth, what will
happen?
A. His weight will increase.
B. His mass will increase.
C. Both his mass and weight will decrease.

Mountains, tops of buildings, and high-flying aircraft are all part of Earth's atmosphere, no matter how high they are. On the other hand, space doesn't belong to our atmosphere, it is outside of it. Having this in mind, the best location to place a telescope used to observe x-rays from stars is in space.

A telescope is an optical instrument that uses lenses, curved mirrors, or a combination of both to observe distant objects, or a variety of devices that emit, absorb, or reflect electromagnetic radiation to observe distant objects.

You can get started for less than $200. Once your budget exceeds $400, you will be able to purchase very capable telescopes. When you spend $600 or more, the scopes become more powerful and feature-rich.

The telescope made its debut in the Netherlands. The national government in The Hague discussed a patent application for a device that aided in "seeing faraway things as if they were nearby" in October 1608, according to the national government. It was made up of a convex and concave lens housed in a tube. Objects were magnified three or four times by the combination.

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Answer:

30MPH

Explanation:

30/5 = 6 x 5 = 30 mph

a)The aperture size of the radio telescope needs to be approximately 0.27 meters b)The aperture of a radio telescope needs to be much larger than that of an optical telescope because radio waves have much longer wavelengths compared to visible light. c)the resolving power of a telescope depends on the ratio of the wavelength of light.

a. To determine the aperture size of a radio telescope to achieve a resolution at 21 cm, we can use the Rayleigh criterion, which states that the minimum resolvable separation (δθ) is given by:

δθ = 1.22 * (λ / D)

Where λ is the wavelength of the radiation and D is the diameter of the telescope's aperture.

Given that the radio wavelength is 21 cm (or 0.21 m), and we want to achieve the same resolution as the optical telescope (1 second of arc), we can rearrange the formula to solve for D:

D = 1.22 * (λ / δθ)

D = 1.22 * (0.21 m / 1 second of arc)

Calculating the result:

D ≈ 0.27 m

Therefore, the aperture size of the radio telescope needs to be approximately 0.27 meters to achieve a resolution of 1 second of arc at a wavelength of 21 cm.

b. The Rayleigh criterion tells us that the resolution of an instrument is inversely proportional to the wavelength.

Since radio waves have longer wavelengths, the telescope's aperture needs to be larger to achieve the same resolution as an optical telescope. This is because a larger aperture collects more incoming waves and allows for finer spatial detail to be resolved.

c. The ability to resolve two objects using a telescope depends on the size of the aperture relative to the wavelength of the radiation. When it comes to resolving stars, the resolving power of a telescope depends on the ratio of the wavelength of light to the size of the telescope's aperture (λ/D).

Blue light has a shorter wavelength compared to red light. Since the resolving power is directly proportional to the wavelength, a shorter wavelength of blue light allows for better resolution.

Therefore, two predominantly blue stars can be resolved because their shorter wavelength allows for finer detail to be distinguished, while the same separation between two predominantly red stars cannot be resolved due to the longer wavelength.

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Answer:

[See Below]

Explanation:

Your average speed would be 204.35 mph.

Answer:

I think it's 7 × 10²

Explanation:

0.0035 time 200000 is 700 and 700 in scientific notation is 7 × 10²

Though i'm not certain if that is correct

Answer:

a) 50 rad/s

b) 39.8 rev

Explanation:

Given:

r = 0.36 m

v₀ = 0 m/s

a = 1.8 m/s

t = 10 s

a) Find: ω

v = at + v₀

v = (1.8 m/s) (10 s) + (0 m/s)

v = 18 m/s

ω = (18 m/s) / (0.36 m)

ω = 50 rad/s

b) Find: Δθ

Δx = v₀ t + ½ at²

Δx = (0 m/s) (10 s) + ½ (1.8 m/s) (10 s)²

Δx = 90 m

Δθ = (90 m) / (2π × 0.36 m)

Δθ = 39.8 rev

The relation between the COPref of the refrigeration cycle and the COPhp of the heat pump cycle is COPref + 1 = COPhp

The coefficient of performance (COP) of a heat pump cycle is defined as the ratio of the heat transferred from the hot reservoir to the work done by the cycle, i.e., COPhp = Qh / W. The thermal efficiency (eta) of a power cycle is defined as the ratio of the work done by the cycle to the heat input, i.e., eta = W / Qh.

Since the two cycles operate in parallel, they exchange heat with the same hot and cold reservoirs. Therefore, the heat transferred from the hot reservoir by the power cycle is equal to the heat absorbed by the heat pump cycle from the same reservoir. Let Qh be this common amount of heat.

The power cycle produces work, so its heat input is greater than its heat output. Let Qc be the amount of heat rejected by the power cycle to the cold reservoir. Then, Qh - Qc is the net heat input to the combined system.

The heat pump cycle absorbs heat from the cold reservoir and releases it to the hot reservoir, so its heat output is greater than its heat input. Let Qc' be the amount of heat absorbed by the heat pump cycle from the cold reservoir. Then, Qh + Qc' is the net heat output from the combined system.

Applying the first law of thermodynamics to the combined system, we have:

Qh - Qc = W + Qc'

Dividing both sides by Qh, we get:

1 - Qc / Qh = W / Qh + Qc' / Qh

Using the definitions of COPhp and eta, we have:

1 - COPhp = eta + Qc' / Qh

Rearranging, we get:

COPhp = 1 - eta + Qc' / Qh

Therefore, the relation between the COPhp of the heat pump cycle and the thermal efficiency eta of the power cycle is:

COPhp = 1 - eta + Qc' / Qh

b. The COP of a refrigeration cycle is defined as the ratio of the heat removed from the cold reservoir to the work done by the cycle, i.e., COPref = Qc / W. The COP of a heat pump cycle is defined as the ratio of the heat transferred from the hot reservoir to the work done by the cycle, i.e., COPhp = Qh / W.

Since the two cycles operate in parallel, they exchange heat with the same hot and cold reservoirs. Therefore, the heat removed from the cold reservoir by the refrigeration cycle is equal to the heat absorbed by the heat pump cycle from the same reservoir. Let Qc be this common amount of heat.

The heat pump cycle absorbs heat from the hot reservoir and releases it to the cold reservoir, so its heat output is greater than its heat input. Let Qh be the amount of heat released by the heat pump cycle to the hot reservoir. Then, Qc + Qh is the net heat output from the combined system.

Applying the first law of thermodynamics to the combined system, we have:

Qh = Qc + W

Dividing both sides by W, we get:

Qh / W = Qc / W + 1

Using the definitions of COPref and COPhp, we have:

COPref = Qc / W

COPhp = Qh / W

Therefore, the relation between the COPref of the refrigeration cycle and the COPhp of the heat pump cycle would be  COPref + 1 = COPhp

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The force that has been applied has a magnitude of 9N.

We have to note that the work that is done is the product of the force and the distance that the force has caused the object to move. Hence we define the force in physics as the product of the force and the distance that have been covered by a body.

In this case, we can see that;

Work done = Force * Change in the distance

Change in the distance = 27 m - 3m = 24 m

Work = 216 J

Force = ?

Thus;

Force = Work/Change in the distance

Force = 216/24

= 9 N

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For a successful landing the aircraft will need:

The formula for uniformly varied rectilinear motion (UVRM) and procedure we will use to solve this exercise is:

Where:

Information about the problem:

Applying the final velocity formula, and clearing the time we get:

vf = vi + (a * t)

t = (vf – vi) /a

t = (0 m/s – 87 m/s) /-8.55 m/s²

t = -87 m/s/ -8.55 m/s²

t = 10.1754 s

Applying the distance formula, we get:

x = (vf²-vi²)/ (2a)

x = [(0 m/s)²- (87 m/s)²]/ (2 * -8.55 m/s²)

x = (0 m²/s²- 7569 m²/s²)/ -17.1 m/s²

x =  -7569  m²/s²/ -17.1 m/s²

x = 442.63 m

By converting the distance units form (m) to (km) we have

x = 442.63 m * 1 km/1000 m

x = 0.44263 km

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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Answer:

300 Hz.

Explanation:

The frequency of a sound wave is the same as that of the source. For example, a tuning fork vibrating at a given frequency would produce sound waves that oscillate at the same frequency.

The frequency that you will hear when the tuning fork is stuck against a table is 300 Hz.

Frequency is a measurement of how often a repetitive event occurs in a given amount of time. It is commonly used to describe the rate at which waves oscillate or vibrate. The unit of frequency is hertz (Hz), which represents the number of cycles or oscillations per second.

For example, in the case of sound waves, frequency is related to the pitch of the sound. Higher frequency sound waves have a higher pitch, while lower frequency sound waves have a lower pitch. Similarly, in the case of electromagnetic waves such as light, frequency is related to the color of the light. Higher frequency electromagnetic waves correspond to colors such as blue and violet, while lower frequency electromagnetic waves correspond to colors such as red and orange.

The relationship between frequency, wavelength, and the speed of the wave is given by the formula:

frequency = speed of the wave / wavelength

This formula shows that the frequency of a wave is inversely proportional to its wavelength, assuming the speed of the wave remains constant. In other words, as the wavelength of a wave increases, its frequency decreases, and vice versa.

Frequency is an important concept in many fields, including physics, engineering, and communications. It is used to describe and analyze a wide range of phenomena, from the behavior of sound and light waves to the performance of electronic circuits and systems.

Here in the Question,

When a tuning fork is struck against a table, it vibrates at its natural frequency, which is determined by its physical properties such as its mass, shape, and material. The vibration of the tuning fork creates sound waves that travel through the air, and our ears perceive these waves as sound.

The frequency of the sound that we hear depends on the frequency of the sound waves that reach our ears. When the sound waves from the tuning fork travel through the air, they undergo a phenomenon called the Doppler effect, which causes the frequency of the sound waves to change depending on the relative motion between the source of the sound waves (the tuning fork) and the observer (our ears).

If the tuning fork is stuck against a table and is not moving relative to the observer, the frequency of the sound waves that reach our ears will be the same as the natural frequency of the tuning fork, which is given as 300 Hz in this case.

Therefore, the frequency that you will hear when the tuning fork is stuck against a table is 300 Hz.

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Number of oxygen molecules in each breath is 2.9X10^21

Given that the volume of air inside a breath (V) = 6.0×10^−4 m^3

oxygen in fresh air = 20%

volume of oxygen in fresh air = 20/100 x 6.0×10^−4 = 1.2x10-4m^3

pressure in the lungs (P)=  1.0×10^5 pa

Temperature of air (T) =300K

Using ideal gas equation find the number of moles of oxygen

PV = nRT

Then n = 1.0×10^5 x  1.2x10-4 / 8.314 x 300 = 4.8x10-3mol

We know the number of molecules in 1 mol is 6.023x10^23

Then the number of molecules in 4.8x10-3mol of oxygen is =

4.8x10-3molx 6.023x10^23 = 2.9x10^21

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Answer:

the formula for tension is mg + ma. T is equal to tension, N, kg-m/s^2

Explanation:

I hope it helps you

Answer:

Hey!

Your answer is...

T = mg + ma

Explanation:

T = tension, N, kg-m/s^2

m = mass, kg

g = gravitational force, 9.8 m/s^2

a = acceleration, m/s^2

HOPE THIS HELPS!!

answers

81.6 pounds rounded or just 81.571 if it needs to be exact

This one is leisure for people with common sense. Yellow is an assortment of two of the rudimentary colors, red and green. Yellow appears yellow because red light is being imaged in our eyes, so that's one thing. Green reflections are capable of being enthralled by the shirt; hopefully, this should be meticulous adequate for you to have a basic understanding of this "phenomenon". Cheers!

A yellow T-shirt appear yellow to human eye because it reflects both red and green lights and our eye detects it as a combination of two fundamental colors (red and green), which is yellow.

Color is a perception. Our eyes sense something (the sky, for instance), and information is transferred from our eyes to our brains informing us that it is a particular color (blue). Different combinations of wavelengths of light are reflected by objects. When our brains detect certain wavelength combinations, they transform them into the phenomena known as color.

There has three fundamental color: red, blue and green. Red and green lights are combined to create yellow light. If a shirt reflects both red and green light, it appears yellow to human eyes. These two fundamental colors of light must be present in the incident light for red and green light to reflect yellow light to human mind.

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Answer:

no photo

Explanation:

sorry i cannot see a photo can you send it to me?

Answer:

3.2 hours

Explanation:

400÷125=3.2

3.2 or 3 hours and 12 minutes.

if sufficiently high temperatures (R) are achieved in the laboratory, nuclear fusion (S) becomes a reality, and as a result, the world's energy problems (E) will be solved.

C=  Funding for nuclear fusion will be cut.

H =  Supply of hydrogen fuel is limited.

R = Sufficiently high temperatures are achieved in the laboratory.

S =  Nuclear fusion becomes a reality.

E = World's energy problems are solved.

We then represent the statements as:

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The summary of the interview with Steve Okamoto a roller coaster designer highlighted how he developed a fascination for rollercoasters and how he successfully learned how to build them.

The summary of the interview with Steve Okamoto is given below.

In an interview with Steve Okamoto, a roller coaster designer, he explained that his fascination with roller coasters began at a young age, and his interest in finding out how they worked led him to study mechanical engineering and product design. As a roller coaster designer, Okamoto's work involves studying site maps, designing how the parts of the ride will work together, and fitting coasters around existing rides and buildings. He also has to consider marketing goals and concerns in his designs, as most parks have some kind of theme. Okamoto recommends that students interested in designing roller coasters should focus on studying math and science, and understanding how energy is converted from one form to another as the cars move along the track.

Overall, Okamoto's work as a roller coaster designer involves a combination of mechanical engineering, product design, and consideration for marketing goals and existing park infrastructure. To design a successful roller coaster, he relies on his knowledge of math, science, geometry, and physics to calculate speeds, accelerations, and the coaster's curves, loops, and dips. His advice for students interested in designing roller coasters is to focus on studying math and science, and understanding how energy is converted throughout the coaster's track.

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Answer:

1200

Explanation:

Principal axis or optical axis is a virtual line that passes through

the center of the lens.

A lens is a transmissive optical tool that employs refraction to focus or disperse a light beam. A compound lens is made up of numerous simple lenses that are often aligned along a common axis, as opposed to a simple lens, which is made up of a single transparent piece.

Principal axis the line between the optical center and the centers of curvature of a lens's or a curved mirror's faces. Any one of three axis that are mutually perpendicular and around which a body has its greatest moment of inertia.

Principal axis or optical axis is a virtual line that passes through

the center of the lens.

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The average force acting on the ball is biggest in the with the cement floor case 2 when in the collision the ball bounce back to half of its initial height.

It is asked that in which case the average net force on the ball is highest.

According to impulse-momentum theorem,

Impulse I = F.Δt

where, F is the net average force and Δt is the time of contact during the collision.

In the case of collision with the rubber piece the time of contact of the ball and the ball increases by large amount while in the case of cement floor the time of contact is very very less.

The change in momentum which is equal to the Impulse is also biggest in the case of cement floor because the transfer of kinetic energy of the ball in the case of cement floor will be almost immediate.

The Bigger change in momentum and the smaller time of contact makes the average force on the ball is biggest in the case of cement floor case.

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The maximum speed of the mass during its oscillations is 1.21 m/s (approx)

Mass (m) = 1.9 kg

Spring stiffness (k) = 180 N/m

Initial displacement (x) = 17.1 cm = 0.171 mInitial velocity (v) = 2 m/s

The maximum speed of the mass during its oscillations can be calculated using the formula:v_max = Aω

Where A is the amplitude of oscillations and ω is the angular frequency of oscillations.

Amplitude of oscillations can be calculated as:

A = x = 0.171 m

The angular frequency of oscillations can be calculated as:ω = √(k/m)

Where k is the spring constant and m is the mass of the object.ω = √(180/1.9) = 7.09 rad/s

Therefore, the maximum speed of the mass during its oscillations will be:

v_max = Aω = 0.171 × 7.09 = 1.21 m/s (approx).

Oscillation of a system can be defined as a type of motion that repeats itself after a regular interval of time. Simple harmonic motion is the type of oscillatory motion in which the motion is repeated after a fixed interval of time and this type of motion is found in a system in which the restoring force is directly proportional to the displacement of the object from the equilibrium position.

An oscillatory system can be created using a mass and spring arrangement. This arrangement is widely used in various mechanical systems such as suspension systems, shock absorbers, etc.

The maximum speed of the mass during its oscillations is equal to the product of amplitude of oscillations and angular frequency of oscillations.

The amplitude of oscillations is equal to the initial displacement of the mass from its equilibrium position and the angular frequency of oscillations is calculated using the formula, ω = √(k/m), where k is the spring constant and m is the mass of the object.

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Heat that is emitted into the environment is harmful. The system's work output is zero.

The movement of mechanical energy from one item to another is referred to as work. Work is measured in the same units as energy since it is a movement of energy: joules (J). The total energy of an object will change as a force is applied to it across a distance. The object's kinetic energy will vary as a result of either acceleration or deceleration. Its potential energy will change, for instance, if it is raised up to a given height while being pulled by gravity.

Hence, sign are used based on the release and absorbed.

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The tension in the first rope, T1, is 805 N.

The tension in the second rope, T2, is 805 N.

(a) The tension in the first rope, T1, can be calculated by balancing the forces acting on the person in the vertical direction. The weight of the person, mg, acts downwards, and the tension in the rope, T1, acts upwards. Therefore:

T1 = mg

where m is the mass of the person and g is the acceleration due to gravity. Substituting the given values:

T1 = (82.0 kg)(9.81 m/s²) = 805 N

Therefore, the tension in the first rope, T1, is 805 N.

(b) The tension in the second rope, T2, can be calculated by balancing the forces acting on the person in the horizontal direction. The tension in the first rope, T1, acts to the left, and the tension in the second rope, T2, acts to the right. Therefore:

T2 = T1

Substituting the value of T1 obtained in part (a):

T2 = 805 N

Therefore, the tension in the second rope, T2, is 805 N.

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The motion of the ball as it moves from the top of the ramp and comes to rest against the block can be described as follows:

Velocity: The initial velocity of the ball as it is released from the top of the ramp can be calculated by using the kinematic equation v_f = v_i + at, where v_f is the final velocity, v_i is the initial velocity, a is the acceleration, and t is the time.

Distance: The distance traveled by the ball as it moves from the top of the ramp to the point where it comes to rest against the block can be calculated using the kinematic equation d = v_i*t + (1/2)at^2.

Acceleration: The acceleration of the ball can be calculated by using the formula a = (v_f - v_i) / t, where v_f is the final velocity, v_i is the initial velocity, and t is the time.

Force: The net force acting on the ball can be calculated using Newton's second law of motion, F = ma, where F is the net force, m is the mass of the ball, and a is the acceleration.

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Answer:

yes

Explanation: Work is done when there is movement. Therefore it was work was being done.

The group of stars that represents stars fusing hydrogen in their cores is known as the main sequence. This is the phase in a star's life cycle where the fusion of hydrogen into helium occurs in the stellar core.

Main sequence stars are the term used to describe the class of stars that fuse hydrogen in their centres. These stars, like our Sun, are in a stable stage of their evolution when the pressure from nuclear fusion reactions acting outside the star balances the gravitational pull coming from within. Protons unite to create helium nuclei during a process known as proton-proton fusion, which releases enormous amounts of energy in the form of heat and light.

Main sequence stars are distinguished by their hydrogen fusion in their cores, which is comparatively steady and persistent. The length of this phase varies with the star's mass, with more massive stars lasting less time during this phase because of their higher fusion rates. Depending on their mass, stars undergo several phases of evolution following the exhaustion of the hydrogen fuel in their cores, such as red giants or supernovae.

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