When the switched on, what type of energy is moving through the circuit?

In the northern hemisphere, gyres rotate in the clockwise direction.

Therefore, the statement on question number 4 is false.

fjfjfj

Explanation:

rufifiriirifieif

Answer:it’s all of the above for the ck-12

Explanation:

Answer:

103.J

Explanation:

Given data

Mass= 5kg

Height= 2.1m

g=9.81m/s^2

Required

The potential energy

PE= mgh

substitute

PE= 5*9.81*2.1

PE=103.J

The prefixes are;

The metric system is one of the systems of measurement that is in common use. We know that there are many different systems of measurement that are in common use. However, the metric system is more current because is the system that helps us to be able to obtain a lot of the values that we use in science today.

Now the metric system  is  largely made up of the gram, the centimeter and the second. This has helped to make the measurement of scientific quantities very easy all over the world. We do have the subunits of these units in the metric system which are obtained by the use of prefixes.

Let us now write the prefixes;

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The lower mass limit of 0.08 solar masses for main-sequence stars is due to the conditions required for nuclear fusion to occur. Nuclear fusion is the process in which hydrogen atoms combine to form helium, releasing energy in the process.

Main-sequence stars generate energy through the fusion of hydrogen into helium in their cores. This process, known as hydrogen burning, occurs when the temperature and pressure in the core are high enough to overcome the electrostatic repulsion between hydrogen nuclei.
Objects with a mass below 0.08 solar masses, known as brown dwarfs, do not have sufficient mass to create the necessary core conditions for hydrogen fusion. The gravitational pressure in the core of such an object is not strong enough to raise the temperature to the required level for fusion to begin. Consequently, these low-mass objects do not shine like main-sequence stars and are considered substellar.
In contrast, main-sequence stars with masses above 0.08 solar masses have enough gravitational pressure in their cores to sustain hydrogen fusion, which produces the energy that makes them visible as stars. This lower mass limit is essential in distinguishing main-sequence stars from substellar objects and understanding the different mechanisms by which these celestial bodies generate energy.

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Answer:

The energy efficiency represents the things you can do with some amount of energy, and if you can do more with less, than it reduces the energy consumption.

Explanation:

The answer to this question is actually very simple. Imagine that you use only the half of the energy you produce, an efficiency of 50%. Lets say you need 5kJ, so you would need to produce 10kJ, because you can consume only the half. Now, imagine you increase the efficiency, you use exactly what you can generate, (efficiency of 100%). In this case, if you needed only 5kJ you would need to generate only 5kJ.

Answer:

Below

Explanation:

The time it take the ruler to fall .083 m is given by

  d = 1/2 a t^2       d = .083 m   a = 9.81 m/s^2

       t = .13 s

Answer:

Option D. 23.5 m

Explanation:

From the question given above, the following data were obtained:

Frequency = 200 Hz

Speed of sound in brass = 4700 m/s

Wavelength of sound in brass =?

We can obtain the wavelength of the sound in the brass by using the following formula as illustrated below:

Wave speed = wavelength × frequency

4700 = wavelength × 200

Divide both side by 200

Wavelength = 4700 / 200

Wavelength = 23.5 m

Thus, the wavelength of the sound in the brass is 23.5 m

Answer:

i dont undertsnad what do u ned hep wit?

Explanation:

Answer:

3 m/s^2

Explanation:

Acceleration = change in speed  /  change i time

                      = 15 m/s  / 5 s =  3 m/s^2

Answer:

Calculate the total distance travelled by the object - its motion is represented by the velocity-time graph below.

Here, the distance travelled can be found by calculating the total area of the shaded sections below the line.

½ × base × height.

½ × 4 × 8 = 16 m 2

(10 – 4) × 8 = 48 m 2

Explanation:

Answer:

Answer is letter B

Answer:  THE CORRECT ANSWER IS :  The partiles that make up material B are more closely packed together than the partiles that make up material A

Explanation:     I TOOK THE TEST    apex

A 110 horsepower automobile engine has a thermal efficiency of 28%. If the fuel has a 10,000 btu/lbm heating value, the rate of fuel consumption is calculated to be 99.96 lb/hr.

This is calculated using,

110 hp = 279888 btu/hr

Thermal efficiency = Brake Power output / Fuel Energy input

0.28 = 279888 / Fuel energy

Fuel energy = 999600 Btu/hr

Rate of fuel consumption = Fuel Energy / Heating value

= 999600 / 10000

= 99.96 lb/hr.

99.96 lb/hr is the rate of fuel consumption if the heating value of the fuel is 10,000 btu/lbm.

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It would grow to a very wide distance between the zero intensity locations.

When d is larger, there is more interference. Due to its dependence on L, the spacings between various fringes get smaller as the distance between the slits gets more. The space between various fringes grows as the light's wavelength rises because this is a wavelength-dependent property.

The intervals between maxima and minima on the screen are inversely proportional to the distance between the slits, the angles at which the difference between the two routes is equal to a multiple of half wavelengths, and the wavelength.

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PartA Using the mirror and magnification equations, the location of the image produced by the mirror is 0.354 m behind the mirror.

Part B Using the mirror and magnification equations, the magnification of the image produced by the mirror is 0.197.

Part A:
To find the location of the image produced by the concave mirror, we can use the mirror equation:

1/f = 1/o + 1/i

where f is the focal length, o is the object distance, and i is the image distance.

Plugging in the given values, we get:

1/0.69 = 1/1.8 + 1/i

Solving for i, we get:

i = -0.354 m

The negative sign indicates that the image is virtual and located behind the mirror.

Therefore, the location of the image produced by the mirror is 0.354 m behind the mirror.

Part B:
To find the magnification of the image produced by the mirror, we can use the magnification equation:

m = -i/o

where m is the magnification, i is the image distance, and o is the object distance.

Plugging in the given values, we get:

m = -(-0.354)/1.8

Simplifying, we get:

m = 0.197

Therefore, the magnification of the image produced by the mirror is 0.197.

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Answer:

7.52 × 1022 molecules

Explanation:

We know 32g of oxygen contains 6.022 × 1023 molecules. Therefore, 4g of oxygen have 7.52 × 1022 molecules. ( im not sure if its correct tho)

Most stars take millions of years to die. When a star like the Sun has burned all of its hydrogen fuel, it expands to become a red giant then when it fully runs out it then dies

Answer:

. When the core runs out of hydrogen fuel, it will contract under the weight of gravity.

Explanation:

Answer:

6.32s

Explanation:

Given parameters:

Length of track and distance covered  = 200m

Acceleration  = 10m/s²

Unknown:

Time taken to cover the track  = ?

Solution:

To solve this problem, we apply one of the motion equations as shown below:

       S  = ut + \(\frac{1}{2}\) at²  

S is the distance covered

t is the time taken

a the acceleration

u is the initial velocity

The initial velocity of Superman is 0;

 So;

     S  =  \(\frac{1}{2}\) at²  

        200  =  \(\frac{1}{2}\) x 10 x t²  

          200  = 5t²  

            t²  = 40

            t  = 6.32s

Answer:405

Explanation:Multiply 45x9.0=405

Answer:

405 Hz

Explanation:

Give the person on top Brainly

Answer: 44m/s

Explanation:

Answer:

(a) ω = 1.57 rad/s

(b) ac = 4.92 m/s²

(c) μs = 0.5

Explanation:

(a)

The angular speed of the merry go-round can be found as follows:

ω = 2πf

where,

ω = angular speed = ?

f = frequency = 0.25 rev/s

Therefore,

ω = (2π)(0.25 rev/s)

ω = 1.57 rad/s

(b)

The centripetal acceleration can be found as:

ac = v²/R

but,

v = Rω

Therefore,

ac = (Rω)²/R

ac = Rω²

therefore,

ac = (2 m)(1.57 rad/s)²

ac = 4.92 m/s²

(c)

In order to avoid slipping the centripetal force must not exceed the frictional force between shoes and floor:

Centripetal Force = Frictional Force

m*ac = μs*R = μs*W

m*ac = μs*mg

ac = μs*g

μs = ac/g

μs = (4.92 m/s²)/(9.8 m/s²)

μs = 0.5

Answer:

If a sound increases 5 db, the sound becomes three times louder.

Explanation:

The speed of a wave refers to how fast a disturbance or oscillation is travelling through a medium or space. It is typically measured in meters per second (m/s) and is calculated as the product of the wavelength of the wave (λ) and its frequency (f), or in symbols:

The speed of a wave (v) is given by the formula:

v = λf

where λ is the wavelength and f is the frequency.

Plugging in the values given:

λ = 0.285 m

f = 2.00 Hz

v = λf = (0.285 m)(2.00 Hz) = 0.570 m/s

Therefore, the speed of the wave is 0.570 m/s.

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Neutron stars are hot, compact remnant stars whose mass is typically between one and several times that of the sun, but their size is only 10 km or less.

A star is a luminous celestial body made up of hot plasma which is bounded together by the force of gravity. The source of light of stars is the plasma that constitutes them. The Sun is the star that is closest to Earth. Other stars are also visible at night with the unaided eye, but because of their great distances from Earth, they appear as stationary points of light.

The Sun is the star which is situated at the centre of the Solar System. It is a nearly perfect ball of hot plasma that has been heated to incandescence by nuclear fusion processes in its centre and radiates energy mostly as light, ultraviolet, and infrared radiation.

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Answer:

D. Increasing resistance and keeping current from A P E X :))

Explanation:

The decreasing resistance and keeping current constant leads decreasing in voltage option (C) is correct.

Voltage is the force applied by the power source to charged electrons in a conducting loop, allowing them to perform tasks such as igniting light.

As we know according to the ohm's law:

V = IR

Where 'V' is the volatge,

'I' is the current.

'R' is the resistance.

If we assume 'I' is constant

Then V∝R

As the resistance increases the voltage increases and vice versa.

Thus, the decreasing resistance and keeping current constant leads decreasing in voltage option (C) is correct.

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The car will coast for approximately 2087 meters before starting to roll back down the slope.

To solve this problem, we need to find the distance the car will travel up the slope before coming to rest. This distance is equal to the distance the car will coast down the slope before starting to roll back.

We can use the conservation of energy principle to find the initial potential energy of the car, which will be converted to kinetic energy as the car coasts up the slope. At the point where the car comes to rest, all of the initial potential energy will have been converted to gravitational potential energy.

The initial potential energy of the car can be found using the formula:

PE = mgh

where m is the mass of the car, g is the acceleration due to gravity, and h is the height the car has traveled up the slope.

Since the car comes to rest at the top of the slope, all of the initial potential energy is converted to gravitational potential energy at this point. The gravitational potential energy can be found using the formula:

PE = mgh

where m is the mass of the car, g is the acceleration due to gravity, and h is the height the car has traveled up the slope.

Since the gravitational potential energy is equal to the initial potential energy, we can set the two formulas equal to each other:

\(mgh = 1/2 mv^2\)

where v is the final velocity of the car at the point where it comes to rest.

We can solve for h, the height the car has traveled up the slope:

\(h = 1/2 v^2/g\)

We can then use the formula for the distance traveled up the slope to find the distance the car will coast down the slope before starting to roll back:

d = h/sin(theta)

where theta is the angle of the slope.

Plugging in the values given in the problem, we get:

\(h = 1/2 (40 sin(6))^2 / 9.81 = 215.5 m\)

\(d = 215.5 / sin(6) = 2087 m\)

Therefore, the car will coast for approximately 2087 meters before starting to roll back down the slope.

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The distance it will coast before starting to roll back down is approximately 776.55 meters up the slope.

To solve this problem, we will use the concepts of kinetic energy, potential energy, and the conservation of mechanical energy. Initially, the car has kinetic energy (KE) due to its velocity (40 m/s) and no potential energy (PE) since we assume it starts at the bottom of the slope. When the car comes to a stop, all its kinetic energy is converted to potential energy.

First, we need to find the kinetic energy:
KE = (1/2) * m * v²
where m is the mass of the car and v is its velocity (40 m/s).

Next, we'll find the potential energy when the car comes to a stop:
PE = m * g * h
where g is the acceleration due to gravity (9.81 m/s²) and h is the height the car reaches on the slope.

Since the mechanical energy is conserved, KE = PE. We can set up the equation:
(1/2) * m * v² = m * g * h

The mass (m) can be canceled from both sides, leaving:
(1/2) * v² = g * h

Now we can find the height (h):
h = (1/2) * v² / g = (1/2) * (40 m/s)² / 9.81 m/s² ≈ 81.46 m

To find the distance the car traveled along the slope (d), we'll use the sine of the angle (6.0 degrees):
sin(6.0) = h / d

Solving for d:
d = h / sin(6.0) ≈ 81.46 m / sin(6.0) ≈ 776.55 m

The car will coast approximately 776.55 meters up the slope before starting to roll back down.

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