when the raindrop reaches the ground, it won't kill you or even bruise you because its terminal velocity is just 10 m/s. calculate the work done by the air resistance on the raindrop. recall that positive work done on an object/system increases the energy of that object/system. again, assume that the falling raindrop maintains its shape so that no energy is lost to the deformation of the droplet.
________ Joules

Solution :

We all know that a bar magnet have two poles, the north pole and the south pole. These poles interacts with each other. The ends of the magnets having similar poles will push each other away while the poles with like charges will pull each others towards it.

The compass needle is also a magnet having south polarity as well as north polarity. When the compass needle is close to the bar magnet, it is opposite to the poles or along the poles. The compass needle shows the direction or is pointed towards the north. So when the compass needle is placed near the north pole of the bar magnet, the pointer of the compass needle points towards the north, i.e. it gets deflected because of he like charges. And when it is placed near the south pole of the magnet, it gets attracted towards it and is pointed towards the pole.

Now as we move the compass needle from the poles to the region that is between the poles, the compass needle pointer points towards the north direction every time. It show a deflection always. If we place the magnetic lines, we will see that the magnetic lines will exit from the north poles and enters the south pole of the bar magnet.  

Answer:

20 m/s

Explanation:

Answer:

0 m/s

Explanation:

Acceleration is a maximum at the lowest and highest positions.  The velocity is 0 at these positions.

Answer: This is the best I could do.

Explanation:

The potential energy of the system is 8.73 x Joules.

To calculate the potential energy of the system, we need to use the formula:

U = k(q1q2/r12 + q1q3/r13 + q2*q3/r23)

where U is the potential energy of the system, k is Coulomb's constant (9x\(10^{9}\) N\(m^{2}\)/\(C^{2}\)), q1, q2, and q3 are the charges of the particles (in Coulombs), and r12, r13, and r23 are the distances between the particles.

Since the charges are all the same and the triangle is equilateral, the distances between the particles are all the same and can be calculated using the Pythagorean theorem:

r12 = r13 = r23 = √(\(90^{2}\) + \((90/√3)^{2}\)) = 103.92 cm

Substituting the values into the formula, we get:

U = (9x\(10^{9}\) N\(m^{2}\)/\(C^{2}\)) x \((0.0000003 C)^{2}\) x [1/103.92 cm + 1/103.92 cm + 1/103.92 cm]

U = 8.73 x \(10^{-12}\)J

Therefore, the potential energy of the system is 8.73 x \(10^{-12}\) Joules.

This calculation shows that even small charges can have a significant effect on the potential energy of a system, especially when the distances between the charges are small. Additionally, the equilateral configuration of the charges results in equal distances between them, making the calculation simpler. The potential energy of a system of charges is an important concept in electrostatics and can be used to analyze and predict the behavior of electrically charged systems.

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The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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it would be the 3rd one. so C

Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.

To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.

The energy required to melt 1 kg of ice is 3.33×105 J/kg.

Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.

To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.

Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.

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The approximate mass of a dark star is 4.35 times the mass of the Sun.

To find the ratio of the mass of the dark star to the mass of the Sun, we can use the binary star formula, which states that the total mass of a binary star system is equal to the mass of the visible star divided by the sine of the angle between the line of sight and the line connecting the two stars:

m1 / sin i = (v² ×T) / (4 × pi² ×d)

where m1 is the mass of the visible star, v is the orbital velocity of the visible star, T is the orbital period of the visible star, i is the angle between the line of sight and the line connecting the two stars, and d is the distance between the two stars.

In this case, we are given the mass of the visible star (m1 = 6.9 Ms), the orbital velocity of the visible star (v = 270 km/s), the orbital period of the visible star (T = 18.1 days), and we can assume that the angle between the line of sight and the line connecting the two stars is 90 degrees (since we cannot see the dark star).

Substituting these values into the binary star formula, we get:

m1 / sin i = (270² × 18.1) / (4 ×pi² × d)

Since sin 90 = 1 and m1 = 6.9 Ms, we can simplify the equation to:

6.9 Ms = (270²× 18.1) / (4 × pi²× d)

Solving for d, we find that d = (270²× 18.1) / (4 × pi²× 6.9 Ms) = 2.43 x 10¹¹ meters.

Now that we know the distance between the two stars, we can use the binary star formula again to find the mass of the dark star. Substituting the values we have calculated into the binary star formula, we get:

m2 / sin i = (v²×T) / (4 × pi²× d)

where m2 is the mass of the dark star and v, T, and d are the same as before. Knowing that m1 = 6.9 Ms and sin i = 1, we can solve for m2 to find the mass of the dark star.

m2 = (v²×T × m1) / (4 × pi²× d)

Substituting the known values, we get:

m2 = (270²× 18.1 × 6.9Ms) / (4 × pi²× 2.43 x 10¹¹)

Simplifying, we find that the mass of a dark star is m2 = 8.7 Ms.

Therefore, the ratio of the mass of a dark star to the mass of the Sun is m2 / Ms = 8.7 / 1.99 = 4.35.

Therefore, the approximate mass of a dark star is 4.35 times the mass of the Sun.

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Answer:

The solar potential in Nepal is 50,000 terawatt-hours per year, which is 100 times larger than Nepal's hydro resource and 7,000 times larger than Nepal's current electricity consumption. Solar can easily meet all future energy needs in Nepal. Solar energy is cheaper than fossil fuels, nuclear and hydro.

Answer:

14m/s

Explanation:

Answer:

only in the column for metalloids

Explanation:

Did it on edge!

Franklin should place this property only in the column for metalloids, therefore the correct answer is option A.

The elements of the periodic tables that behave as metal, as well as the nonmetal in some chemical or physical aspects, are known as metalloids. Some examples of metalloids are Boron, silicon, germanium, arsenic, antimony, tellurium, etc.

Generally, metalloids have an intermediate position in the periodic table which is in between metals and nonmetals.

As given in the problem The table shows columns that Franklin uses to organize his notes on the properties of elements. His notes state that some elements are widely used in semiconductors, A 3-column table with 2 rows. The first row has entries as metals, metalloids, and nonmetals. The second row has entries nothing, nothing, nothing.

As metalloids are widely used as semiconductors across several electronic and electrical applications.

Thus, Franklin should only list this characteristic under metalloids, therefore the correct answer is option A.

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Answer:

15 N right

Explanation:

The 10 up and 10 down cancel each other out. =0

25right-10 left =15 right

0+15= 15N right

Answer:

The answer is 5×10‐⁵

Step-by-step Explanation:

\( \alpha = \frac{l2 - l1}{l1( \beta 2 - \beta 1)} \)

let ß be ø

\( \alpha = \frac{40.05 - 40}{40(45 - 20)} \)

\( \alpha = \frac{0.05}{40 \times 25} \)

\( \alpha = \frac{0.05}{1000}\)

\( \alpha = \frac{0.05}{1000}\)\( \alpha = 5.0 \times {10}^{ - 5} \)

The action that does NOT demonstrate a change in energy that causes motion or creates changes in other objects is a piece of paper in a notebook. Option C is correct.

A bowling ball rolling down a lane demonstrates kinetic energy as the ball is in motion and creating changes in other objects. A tennis racket hitting a ball demonstrates kinetic energy as the racket is in motion, striking the ball, and causing it to move.

A hot plate heating a pot of water demonstrates thermal energy as the hot plate is increasing the temperature of the water, causing it to boil and creating changes in other objects. A piece of paper in a notebook is not demonstrating any significant change in energy that causes motion or creates changes in other objects, as it is stationary and not interacting with any other objects in a significant way. Option C is correct.

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(a) The impulse between the marble and the floor is -3.23 Ns.

(b) The average force F between the marble and the floor is -32.3 N.

We can use the principle of conservation of energy to find the velocity of the marble just before it hits the ground:

Initial potential energy = mgh = 0.1 kg × 9.8 m/s² × 40 m = 39.2 J

Final kinetic energy = (1/2)mv²

39.2 J = (1/2) × 0.1 kg × v²

v = √(2 × 39.2 J / 0.1 kg) = 88.4 m/s

When the marble hits the ground, it experiences a force due to the floor that changes its momentum. The impulse J of this force can be calculated as:

J = Δp = mΔv

where;

The change in velocity is given by:

Δv = vf - vi

where;

We know that vi = 88.4 m/s, and we can find vf using the conservation of energy principle again:

Final potential energy = mgh = 0.1 kg × 9.8 m/s² × 10 m = 9.8 J

Initial kinetic energy = (1/2)mv² = (1/2) × 0.1 kg × (88.4 m/s)² = 389.8 J

389.8 J = 9.8 J + (1/2)mvf²

vf = √(2 × (389.8 - 9.8) J / 0.1 kg) = 56.1 m/s

Therefore, the impulse is:

J = mΔv = 0.1 kg × (56.1 m/s - 88.4 m/s) = -3.23 N·s

The negative sign indicates that the impulse is in the opposite direction to the initial velocity.

The average force F between the marble and the floor can be found using the formula:

F = J / Δt

where;

In this case, Δt = 0.1 s, so:

F = J / Δt = (-3.23 N·s) / 0.1 s = -32.3 N

Again, the negative sign indicates that the force is in the opposite direction to the initial velocity.

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When a mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth), the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.

The period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth) can be determined by using Kepler's third law which relates the period of revolution of a satellite to the average radius of its orbit.

Kepler's third law states that the square of the period of revolution of a satellite is proportional to the cube of the average radius of its orbit.

Mathematically, the law can be expressed as: T² = (4π² / GM) × R³Where T is the period of revolution, G is the gravitational constant, M is the mass of the earth, and R is the average radius of the orbit of the satellite.

To find the period of revolution of the given satellite, we can substitute the given values in the equation: R = 7480 km + 6370 km = 13850 kmM = 5.97 × 10²⁴ kgG = 6.67 × 10⁻¹¹ Nm²/kg²T² = (4π² / GM) × R³T² = (4π² / (6.67 × 10⁻¹¹ × 5.97 × 10²⁴)) × (13850 × 10³)³T² = 6.7182 × 10¹⁴ seconds²

Taking the square root of both sides, we get:T = 8.2079 × 10³ seconds

Therefore, the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.

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The current theory about the formation of the solar system is that it began as a cloud of dust and gas, known as the solar nebula which is the last response.

The nebula collapsed under its own gravity, forming a spinning disk with a bulging middle that became the sun. The remaining dust and gas in the disk coalesced into small bodies, which collided and stuck together, forming the planets.

This process, known as accretion, resulted in the four inner planets, which are small and rocky, and the four outer planets, which are large and gas-rich.

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Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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Answer:

13 g

Explanation:

Gold-198 has a half-life of approximately 3 days. If a 100 g sample of gold-198 decays for 9 days, approximately how much gold-198 remains in the sample?

13 g

Answer:

Answer:

0.484 m/s²

Explanation:

To solve this question, we would apply the formula for calculating gravitational acceleration at any distance.

g = GM/r², where

g = acceleration due to gravity

G = gravitational constant

r = radius of the meteoroid

Radius of the earth is given as 6371 km

The meteoroid is located at a distance 3.5 times the radius of the earth, so

r = R + 3.5R = 4.5R

r = 28670 km

Mass of the earth is, 5.97*10^24 kg

Now, we proceed to substitute our values into the earlier equation

g = GM/r²

g = (6.67*10^-11 * 5.97*10^24) / 28670²

g = 398.2*10^12 / 822*10^12

g = 0.484 m/s²

Thus, it's acceleration due to earth's gravitation is 0.484 m/s²

The time taken for the ball to reach its maximum height is 1 second.

To calculate the time taken for the ball to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the ball is thrown vertically upwards, so the initial velocity (u) is 10 m/s (considering upwards as positive) and the acceleration (a) is -10 m/s² (negative because it opposes the motion).

The final velocity (v) at the maximum height will be zero because the ball momentarily comes to a stop before reversing its direction. Therefore, we can rewrite the equation as:

0 = 10 - 10t

Simplifying the equation, we get:

10t = 10

Dividing both sides by 10, we find:

t = 1 second

Therefore, the time taken for the ball to reach its maximum height is 1 second.

During this time, the ball covers the distance required to reach the maximum height, overcoming the gravitational acceleration. After reaching the maximum height, it will start to descend towards the ground due to the gravitational pull.

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If a child pulls a waxed wooden sled across dry snow at a constant speed with a 2.6 N force, the mass of the sled is 6.63 kg

Since the waxed wooden sled is pulled across dry snow at a constant speed,

a = 0

∑ Fx = m ax

F - f = 0

2.6 - f = 0

f = 2.6 N

f = μ N

N = m g

f = Frictional force

μ = Co-efficient of friction

N = Normal force

m = Mass

g = Acceleration due to gravity

μ = 0.04

f = μ m g

2.6 = 0.04 * m * 9.8

0.392 m = 2.6

m = 6.63 kg

Therefore, the mass of the sled is 6.63 kg

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Answer:

1- 66mL

2-16mL

3-7.8mL

Explanation:

they are numbered from left to right, and have the number of the values. Dont forget the measurements, because sometimes if they are forgotten, they are counted wrong.

Lorentz transformation is a mathematical framework that describes how the coordinates of an event in space and time change for two observers in relative motion.

Consider two inertial frames of reference, S and S', moving relative to each other along the x-axis with a constant velocity v. Let an event occur at position (x, y, z, t) in frame S, and let (x', y', z', t') be the corresponding position in frame S'.

The transformation equations for space and time are given by:

\(x' = γ(x - vt)\\y' = y\\z' = z\\t' = γ(t - vx/c^2)\)

where\(γ = 1/√(1 - v^2/c^2)\) is the Lorentz factor, and c is the speed of light.

These equations show how the coordinates of an event in one frame of reference are related to the coordinates in another frame of reference that is moving relative to the first frame. They are known as the Lorentz transformations and are a fundamental aspect of special relativity.

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Complete Question

The image for this question is shown on the first uploaded image

Answer:

\(v = 3.4 \ m/s\)

Explanation:

From the question we are told that

   The mass of the collar is  \(m = 2 \ kg\)

    The original length is  \(L = 3.0 \ m\)

     The spring constant is  \(k = 3.0 \ N/m\)

Generally the extension of the spring  is  mathematically evaluated as

        \(e = 4 -3 = 1 \ m\)

Now with Pythagoras theorem we can obtain the length from A to B as

        \(AB = \sqrt{5 ^2 + 4^2}\)

       \(AB = 6.4 \ m\)

The  extension of the spring at B is  

     \(e_b = 6.4 - 3 = 3.4 \ m\)

According to the law of energy conservation

   The energy stored in the spring at point A +  the kinetic energy of the  spring =  The  energy stored on the spring at B

So

     \(\frac{1}{2} * k * e + \frac{1}{2} * m* v^2 = \frac{1}{2} * k * e_b\)

substituting values

    \(\frac{1}{2} * 3 * 1^2 + \frac{1}{2} * 2* v^2 = \frac{1}{2} * 3 * 3.4^2\)

=>   \(v = 3.4 \ m/s\)

Answer:

10

Explanation:

10 is answer because velocity is time /position. So time is 50 and position is 5

Answer:

R = (-2î − 6ĵ + 10k^)m

Explanation:

We are given;

D = (2î − 6ĵ)

Now, we want to find R such that,

D + R = −5Dĵ

Plugging in (2î − 6ĵ) for D in the R equation gives;

(2î − 6ĵ) + R = -5(2î − 6ĵ)j

(2î − 6ĵ) + R = -10k + 0

This is because in vector multiplication, i × j = k and j × j = 0

Thus;

(2î − 6ĵ) + R = -10k

Making R the subject gives;

R = -2î − 6ĵ + 10k^

Thus, the displacement vector R is;

R = (-2î − 6ĵ + 10k^)m