When the filament breaks in one lamp in a parallel circuit, lamps in other branches of the circuit normally _________.
continue glowing as brightly
absorb energy from the damaged lamp
go out
continue glowing, but dimme

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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A particle with the potential energy diagram shown is located at point A and is moving to the right with a kinetic energy of 10.0 Joules. When the particle reaches point F, the speed of the particle has decrease

As the sum of potential and kinetic energy remains constant

Kinetic energy decreases when potential energy increases and vice versa.

When kinetic energy decreases speed will also decrease.

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Answer:

506.25

Explanation:

Since T = 2πm/Be the period of revolution of the electron is independent of velocity and radius of path

For an electron moving in a uniform magnetic field, the force on the electron is given by

F = Bev where

Also, this magnetic force equals the centripetal force on the electron, F'

F' = mv²/r where

Since both forces are equal,

F = F'

Bev = mv²/r

Be = mv/r

We know that angular speed, ω = v/r. So,

Be = mω

Also, angular speed, ω = 2π/T where T = period of revolution of electron

So, Be = m2π/T

Making T subject of the formula, we have

T = 2πm/Be

so, since T = 2πm/Be the period of revolution of the electron is independent of velocity and radius of path

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Answer:

9

Explanation:

i guess so

can you put a brainliest in me

Answer:

hope this helps

Explanation:

Relative density, or specific gravity, is the ratio of the density of a substance to the density of a given reference material. Specific gravity for liquids is nearly always measured with respect to water at its densest; for gases, the reference is air at room temperature.

The best way of presenting the information on density graphically would be to use a D, bar graph.

A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.

A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.

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Answer:

A reducing agent accepts electrons

Answer:

B. period of the sound wave

Answer:

lets go brandon!

Explanation:

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Answer:

Explanation:

this is like rubbing a balloon on your head to make your hair stand up.  Do that to the can.    The balloon is filled , ofc,  and then just rub the balloon on the can.  This will charge the can with static electricity.   :P

Answer:

the Earth's crust is broken into about 12 plates that float on hotter, softer rocks in the underlying mantle

Explanation:

Answer:

trueeeeeeee..........mmmm...........

The momentum of the sprinter of mass and velocity of 68 kg and 8 m/s respectively is  544 kgm/s

Momentum can be defined as the product of mass and velocity of a body.

To calculate the linear momentum of the sprinter, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitite the values into equation 1

Hence, the momentum of the sprinter is 544 kgm/s.

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The linear momentum of the sprinter with a mass of 68 kg that reaches a speed of 8 m/s during a race is 544kgm/s.

The momentum of a body in motion is the tendency of a body to maintain its inertial motion. It is the product of its mass and velocity, or the vector sum of the products of its masses and velocities.

The linear momentum of a body can be calculated as follows:

p = m × v

According to this question, a sprinter has a mass of 68kg and reaches a speed of 8 m/s during a race. The momentum can be calculated as follows:

p = 68kg × 8m/s

p = 544kgm/s

Therefore, 544kgm/s is the linear momentum of the sprinter.

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Answer:

46.5 N

Explanation:

attached is explanation

Answer:

The most common oxidation numbers for a given element

Answer:

Volcanic Eruptions

Explanation:

The volcano can start showing signs that it may be about to explode.

Answer:

Volcanic eruptions.

Explanation:

I had the same question on an assignment and I got it right.

Answer:

4.41N or 4.5N (check explanation)

Explanation:

450g = 0.45kg

F = ma

Using 10m/s² = 10(0.45) = 4.5N

Using 9.8m/s² = 9.8(0.45) = 4.41N

A student sets up four cups with 40 mL of water in each and adds different amounts of ice to each cup.

To determine the connection between the temperature change and the transfer of kinetic energy, the student can measure the initial and final temperatures of the water in each cup and the mass of the ice added to each cup. Then, the student can use the following equation to calculate the amount of heat transferred from the ice to the water

Q = m × c × ΔT

Where Q is the amount of heat transferred, m is the mass of the ice added, c is the specific heat capacity of water (4.184 J/g °C), and ΔT is the change in temperature of the water.

The student can then compare the amount of heat transferred from the ice to the water in each cup to the change in temperature of the water. If the temperature change is greater in a cup where more heat was transferred, this suggests a direct connection between the transfer of kinetic energy (as heat) from the ice to the water and the temperature change of the water.

Hence, This can be further supported by calculating the temperature change per unit of heat transferred, which should be approximately the same for each cup if there is a direct connection between the transfer of heat and the temperature change.

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For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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Answer:I would say live but not be treated right.

Explanation: My opinion.

Answer:

I would rather pass away and let my love ones have a good life

Explanation:

Answer:

The emf induced in this coil at the given time is 12 V

Explanation:

Given;

a coil with a self-inductance, L = 6.0 H

rate of change of current in the coil, di/dt = 2.0 A/s

The emf induced in this coil at t = 0 s, is calculated as;

\(emf = L \frac{di}{dt}\)

where;

L is the inductance (H)

\(\frac{di}{dt}\) is the rate of change of time (A/s)

Substitute in the given values and solve for the  emf

\(emf = L\frac{di}{dt} \\\\emf = 6*2\\\\emf = 12 \ V\)

Therefore, the emf induced in this coil at the given time is 12 V

Granite will heat up the quickest among dry soil, granite, water, and wet soil due to its lower specific heat capacity.

To determine which substance will heat up the quickest among dry soil, granite, water, and wet soil, we need to consider their specific heat capacities. The substance with the lowest specific heat capacity will heat up the quickest.

Specific heat capacity is defined as the amount of heat energy required to raise the temperature of a substance by a certain amount. Different substances have different specific heat capacities due to variations in their molecular structure and composition.

Water has a relatively high specific heat capacity of about 4.18 J/g°C, meaning it requires a significant amount of heat energy to raise its temperature. Dry soil and granite, on the other hand, have lower specific heat capacities compared to water.

Wet soil is a mixture of dry soil and water, and its specific heat capacity will lie between the values of dry soil and water. Since water has a higher specific heat capacity than dry soil, wet soil is expected to have a higher specific heat capacity than dry soil as well.

Therefore, based on the comparison of specific heat capacities, the substance that will heat up the quickest is granite. Granite has a lower specific heat capacity than water and wet soil, making it more susceptible to temperature changes. Dry soil and wet soil, including water, will heat up at a slower rate compared to granite.

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Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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$ 273

Explanation

what she earned is the difference in percentage, so

Step 1

find the difference in percentage

Step 2

now,find the value of that 0.39%,to do that we can use a rule of three, so

let x represents the value for 0.39 %

so

the proportion is

finally, solve for x

therefore the gain was $ 273

I hope this helps you

Correct answer:- Class 1

Class 1 aircraft are those whose weight or center-of-gravity limits can sometimes be exceeded by loading arrangements normally used in tactical operations. Therefore, limited loading control is needed.

The aircraft's airframe and powerplant (A&P) technician or repairman keeps accurate weight and balance records, noting any adjustments made as a result of repairs or modifications.

Similar to an airplane, if its center of gravity is too far off the range, it will be heavier on one side than the other and the pilot may lose control of it. The aircraft's longitudinal imbalance is what causes the nose and/or tail to be heavy.

An aircraft's center of gravity (CG) center of gravity (CG) of an aircraft is the point at which, if suspended at that location, the aircraft would balance. The center of gravity must stay within predetermined boundaries set by the aircraft manufacturer since it impacts the stability of the airplane.

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Class 1 aircraft are those whose centre of gravity or weight constraints may occasionally be exceeded by loading configurations typically used in tactical missions. As a result, restricted loading control is required.

A&P technician or repairman for the aircraft maintains accurate weight and balance records, noting any alterations made as a result of repairs or modifications. Like an aeroplane, if it has a centre of gravity that is too far off the range, it will be heavier on one side than the other and the pilot may lose control. The nose and/or tail of the aircraft are disproportionately heavy due to the longitudinal imbalance. The point at which, if held at that location, an aircraft would be in balance is called the centre of gravity (CG).

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The energies of the photon in each case are;

a) 2.5 * 10^-5 eV

b) 2.5 eV

c) 2.5 * 10^2 eV

We know that a photon is known to have an energy that can be measured or calculated by the use of the formula;

E = hc/λ

E = energy of the photon

h = Plank's constant

λ = Wavelength

c = Speed of light

Then;

a) E = 6.6 * 10^-34 * 3 * 10^8/5 * 10^-2 m

E = 3.96 * 10^-24 J or 2.5 * 10^-5 eV

b) E = 6.6 * 10^-34 * 3 * 10^8/500 * 10^- 9 m

E = 3.96 * 10^-19 J or 2.5 eV

c) E =  6.6 * 10^-34 * 3 * 10^8/5 * 10^- 9 m

E =  3.96 * 10^-17 or 2.5 * 10^2 eV

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