Two spherical balls are placed so that their centers are 3.61 m apart. The
force between them is 1.65 x 10-7 N. If the mass of the smaller ball is 81 kg,
what is the mass in kilograms of the other ball?
Answer:
The mass of the other ball is 397.775 kg.
Explanation:
Gravitation is the force of mutual attraction that bodies experience due to the fact that they have a certain mass.
The universal law of gravitation is a classical physical law that describes the gravitational interaction between different bodies with mass.
The law was formulated by Newton, who deduced that the force with which two bodies of different masses are attracted only depends on the value of their masses and the square of the distance that separates them.
In other words, the Law of Universal Gravitation predicts that the force exerted between two bodies of masses M1 and M2 separated by a distance "d" is proportional to the product of their masses and inversely proportional to the square of the distance, that is:
\(F=G\frac{M1*M2}{d^{2} }\)
where:
F = It is the module of the force exerted between both bodies, and its direction is found on the axis that joins both bodies. G = It is the constant of Universal Gravitation, whose value is 6.67384*10⁻¹¹ \(\frac{N*m^{2} }{kg^{2} }\)In this case:
F= 1.65*10⁻⁷ NG= 6.67384*10⁻¹¹ \(\frac{N*m^{2} }{kg^{2} }\)M1= 81 kgM2= ?d= 3.61 mReplacing:
\(1.65*10^{-7} N=6.67384*10^{-11} \frac{N*m^{2} }{kg^{2} }\frac{81 kg*M2}{(3.61 m)^{2} }\)
Solving for M2:
\(M2=\frac{1.65*10^{-7} N*(3.61 m)^{2}}{6.67384*10^{-11} \frac{N*m^{2} }{kg^{2} }*81 kg}\)
M2= 397.775 kg
The mass of the other ball is 397.775 kg.
Mary pushed a box across the floor with 54N to the left and Doug helped her by exerting a force
of 75N to the left and another force of 20N was exerted on the box in the opposite direction,
what is the net force acting on the box? *
Help plzz
A block of mass
m1 = 4.50 kg
initially at rest on top of a frictionless, horizontal table is attached by a lightweight string to a second block of mass
m2 = 2.70 kg
hanging vertically from the edge of the table and a distance
h = 0.410 m
above the floor (as shown in the figure below). If the edge of the table is assumed to be frictionless, what is the speed with which the first block leaves the edge of the table? (Assume the first block leaves the edge of the table after the second block reaches the floor.)
The speed with which the first block leaves the edge of the table is 2.84 m/s.
Conservation of mechanical energy
Since both blocks are connected, they will travel at the same speed from the given position. The potential energy of the blocks at the given position will be converted to kinetic energy.
P.E = K.E
mgh = ¹/₂mv²
gh = ¹/₂v²
\(v = \sqrt{2gh}\)
The speed of the blocks from the given position is calculated as follows;
\(v = \sqrt{2 \times 9.8 \times 0.41} \\\\v = 2.84 \ m/s\)
Thus, the speed with which the first block leaves the edge of the table is 2.84 m/s.
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Question 1
Given an object's momentum and velocity, which equation can be used to
calculate the object's mass?
V
○ A. m-p
B. m=
vp
1
C. m-P
D. m-pv
Answer:
Explanation:
m=p/v
where m is mass, p is momentum and v is velocity
Mention 2 everyday applications each of conduction, convection and radiation
Answer:
Conduction: Touching a stove and being burned. Ice cooling down your hand. .
Explanation:
As the pendulum swings from position A to position B, what is the relationship of kinetic energy to potential energy (neglect friction)? (5 points)
The kinetic energy increase is equal to the potential energy decrease.
The potential energy increase is equal to the kinetic energy decrease.
The kinetic energy and potential energy remain the same.
The kinetic energy increase is more than the potential energy decrease.
As the pendulum swings from position A to position B, the potential energy decreases while the kinetic energy increases. According to the law of conservation of energy, the total energy in a system remains constant, neglecting friction. Therefore, the potential energy lost by the pendulum is converted into kinetic energy. The correct relationship of kinetic energy to potential energy as the pendulum swings from position A to position B is:
The potential energy decrease is equal to the kinetic energy increase.
So, the answer is option B.
Answer:
The potential energy increase is equal to the kinetic energy decrease.
Which of these units is most appropriate to use when measuring the mass of a person?
The SI unit of mass is the kilogram
Rasheeda made a model of a plant cell and labeled parts of the cell that are not found in animal cells. Which other part of the cell should Rasheeda label?
A) cytoplasm
B) large central vacuole
C) lysosomes
D) mitochondria
Answer:
Cytoplasm
Explanation:
Read each scenario below. Then select the answer that best completes each sentence.The power from a car engine is more than the power of a bicycle because a car engine does the same amount of work in time.Raul and Katrina equally shared a frozen lunch but heated each portion in two different microwaves. Katrina’s lunch was warm in one minute while Raul’s lunch took two minutes. The power used by Raul’s microwave must be the power used by Katrina’s because his microwave took time to do the same amount of work.
a)The power from a car engine is more than the power of a bicycle because a car engine does the same amount of work in less time.
b)Raul and Katrina equally shared a frozen lunch but heated each portion in two different microwaves. Katrina’s lunch was warm in one minute while Raul’s lunch took two minutes. The power used by Raul’s microwave must be the less than the power used by Katrina’s because his microwave took more time to do the same amount of work.
Explanation
work:work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement
so
Step 1
a)The power from a car engine is more than the power of a bicycle because a car engine does the same amount of work in less time.
power is given by:
\(P=\frac{\text{work done}}{time\text{ taken}}\)so, we can see the time is in the denominator, so as the car engine does the same work in less time, the power of the engine is more than the power of a bicycle
Step 2
Raul and Katrina equally shared a frozen lunch but heated each portion in two different microwaves. Katrina’s lunch was warm in one minute while Raul’s lunch took two minutes. The power used by Raul’s microwave must be the less than the power used by Katrina’s because his microwave took more time to do the same amount of work.
again, as the time is in the numerator
to more times, less power , so
\(\begin{gathered} P_{katr\in a}=\frac{W_{katr\in a}}{\text{time taken}} \\ as\text{ the shares ase equal , the work neccesary to warm it is the same, so} \\ W_{katr\in a}=W_{raul} \\ so \\ P_{katr\in a}=\frac{W_{katr\in a}}{\text{time taken}}=\frac{W_{katr\in a}}{1} \\ Praul=\frac{W_{katr\in a}}{\text{time taken}}=\frac{W_{katr\in a}}{\text{2}} \\ P_{raul}=\frac{W_{katr\in a}}{\text{2}}=\frac{P_{katr\in a}}{2} \\ P_{raul}=\frac{P_{katr\in a}}{2} \end{gathered}\)therefore,
the answer is
Raul and Katrina equally shared a frozen lunch but heated each portion in two different microwaves. Katrina’s lunch was warm in one minute while Raul’s lunch took two minutes. The power used by Raul’s microwave must be the less than the power used by Katrina’s because his microwave took more time to do the same amount of work.
I hope this helps you
Answer:
1. more than
2. less
3. less than
4. more
Explanation:
A wheel of radius 30.0 cm is rotating at a rate of 3.10 revolutions every 0.0710 s
Through what angle does the wheel rotate in 1.00 s?
To determine the angle through which the wheel rotates in 1.00 second, we can start by finding the angle covered in 0.0710 seconds and then scale it up to 1.00 second.
In 0.0710 seconds, the wheel completes 3.10 revolutions. One revolution corresponds to an angle of 360 degrees or 2π radians. Therefore, in 0.0710 seconds, the wheel rotates through an angle of:
Angle = 3.10 revolutions * 2π radians/revolution = 6.20π radians
To find the angle in 1.00 second, we can use proportional reasoning. Since the time increases by a factor of 1.00/0.0710, the angle covered will also increase by the same factor:
Angle in 1.00 second = 6.20π radians * (1.00/0.0710) = 87.32π radians
Approximately, the angle through which the wheel rotates in 1.00 second is 274.39 radians.
Therefore, the wheel rotates through an angle of approximately 274.39 radians in 1.00 second.
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HELP ASAP CORRECT ANSWER ONLY 10 PTS Collaboration, listening, and negotiating are considered __________ skills. interpersonal mathematical personal verbal
Answer:
Explanation:
verbal as they are all linked to communication and speaking
Insulator Problem. How does end A of the rod react when the ball approaches it after it has already made several contacts with the rod, such that a fairly large charge has been deposited at end A?strongly repelledstrongly attractedweakly attractedweakly repelledneither attracted nor repelled
As the charged ball reaches the rod's end A, it is strongly deflected away from it. Therefore, option (A) is the correct one.
What kinds of things are insulators used for?Materials that act as insulators stop electricity from flowing through them. Because materials resist electric current, insulators are used as a barrier against the potentially damaging effects of electricity. Insulators include materials like glass, air, timber, plastic, and rubber, to name a few.
What does the term "insulator" signify in science?a device that separates and supports conductors and is made of an electrical insulating material. a substance with weak heat or electrical conductivity. contrast with semiconductor
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a electric fire is connected to the city power grid (120 V) it draws a current of 6A what is its power rating?
Answer:
720 WattsExplanation:
Given:
Voltage (V) = 120 V Current (I) = 6ATo Find:
Power (P)Solution:
We know that electrical power is product of Voltage and current. So, Power formula is given by:
\( \\ \: \: \: \dashrightarrow \sf \: \: \: \underline{\boxed{\sf{ Power = Voltage \times Current}}} \\ \\ \)
On substituting the required values, we get:
\(~~~\dashrightarrow~~~~\) Power = 120 V × 6 A
\(~~~\dashrightarrow~~~~\)Power = 720 watts
Hence,
Power rating is 720 WattsA motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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Water flows steadily from an open tank as shown in the figure. (Figure 1)The elevation of point 1 is 10.0 m , and the elevation of points 2 and 3 is 2.00 m . The cross-sectional area at point 2 is 4.80×10−2 m2 ; at point 3, where the water is discharged, it is 1.60×10−2 m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. What is the gauge pressure p_gauge at point 2?
The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.
Step 1: Identification of the given data:
- Elevation at point 1 (h1) = 10.0 m
- Elevation at points 2 and 3 (h2 = h3) = 2.00 m
- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)
- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)
Step 2: Determination of the discharge rate:
As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.
Therefore, the discharge rate is 0 cubic meters per second.
Step 3: Determination of the gauge pressure at point 2:
To find the gauge pressure at point 2, we'll use Bernoulli's equation:
P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2
Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.
The equation simplifies to:
Patm + ρgh1 = P2 + ρgh2
We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:
\(P_g_a_u_g_e\) = P2 - Patm
Now let's substitute the given values into the equation:
\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm
\(P_g_a_u_g_e\) = ρgh1
Plugging in the values:
\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)
\(P_g_a_u_g_e\) = 98100 Pa
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A ball is thrown upwards with initial velocity 20 m/s. After reaching maximum height, on the way down it strikes a bird which is 10 m above the ground. What is the velocity of the ball when it hits the bird?
Freida wants to model the way atoms move when a substance changes its state. To do this, Freida makes a pyramid of marshmallows. Then, she knocked down the pyramid causing the marshmallows to fall. If the marshmallows represent the atoms in the substance, which change of state is Freida modeling?
Answer:melting 2020 edge
Explanation:
:)
Answer:
Melting
Explanation:
sometimes tectonic forces cause cracks to form in rock. If pieces of the rock move along these cracks, the cracks are called faults.
Scientists use the term faulting to refer to the formation of faults. Depending on the situation, faulting can act as a constructive or a destructive force. Which of the following best shows how faulting can act as a constructive force?
A.
Rock moves sideways along a fault with no change in elevation.
B.
Rocks are worn down as they grind past each other along a fault.
C.
Faulting produces an earthquake that causes a local bridge to collapse.
D.
Rock moves upward along faults to form a mountain range.
It's option D, rock moves upward along faults to form a mountain range
Explanation:
it's all colliding/pushing together so it all builds upward to make the mountain ranges
how to find input force
Answer: Calculate the work input in a pulley by using the previous readings in the correct mathematical equation. : Work (W) equals force (f) multiplied by distance (d), or W=fd. The work done by the pulley is the equation of weight (w) multiplied by height traveled (h).
Explanation:
A copper wire has a diameter of 1.947 mm. What magnitude current flows when the drift velocity is 1.79 mm/s
Answer:
72.5 A
Explanation:
There are about 13.6 coulombs of free electron charges in each cubic mm of copper. So, the rate of movement of charge is that quantity multiplied by the volume in the flow.
V = πr²h . . . . . volume of a cylinder
V = π(1.947 mm/2)²(1.79 mm/s) = 5.329 mm³/s
Then the charge flow rate is ...
(13.6 C/mm³)(5.329 mm³/s) = 72.5 C/s
The magnitude of the current is about 72.5 amperes.
______
Additional comment
The volume of free charge in copper can be computed from the density, molar mass, number of atoms in a mole, number of charges in a coulomb, and the number of free charges per atom. Some of the combinations of necessary calculations can be found with a web search, so it is not unreasonable to presume that the charge density is known.
1. A train is moving north at 5 m/s on a straight track. The engine is causing it to accelerate northward at 2 m/s^2.
How far will it go before it is moving at 20 m/s?
A) 83
B) 43
C) 39
D) 94
E) 20
Answer:
It will go up to 93.75 m before it is moving at 20 m/s
Explanation:
As we know that
\(v^2 - u^2 = 2aS\)
here v is the final speed i.e 20 m/s
u is the initial speed i.e 5 m/s
a is the acceleration due to gravity i.e 2 m/s^2
Substituting the given values in above equation, we get -
\(20^2 - 5^2 = 2*2*S\\S = 93.75\)meters
A lightning bolt has a current of 56,000 A and lasts for 80 x 10-6 seconds (80 μs). How much charge (in Coulombs) has flowed in this bolt?
Answer:
A cloud can discharge as much as 20 coulombs in a lightning bolt.
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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Question /
Which object is shown below?
A. Convex mirror
B. Convex lens
C. Concave lens
D. Concave mirror
SLIDNAT
Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?
The near point of a human eye is about a distance of 25 cm.
The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.
This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.
The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.
In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.
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If the 140 g ball is moving horizontally at 25 m/s , and the catch is made when the ballplayer is at the highest point of his leap, what is his speed?
Answer:
0.049 m/s
Explanation:
Let a 71 kg baseball player jumps straight up to catch a hard-hit ball.
Mass of the player, m = 71 kg
Mass of the ball, m' = 140 g = 0.14 kg
Initial velocity of the player, u = 0 (at rest)
Initial velocity the ball, u' = 25 m/s
We need to find the speed when the ballplayer is at the highest point of his leap. They will stick with each other. Let they move with the speed of V.
Using the conservation of momentum as follows :
\(mu+mu'=(m+m')V\\\\V=\dfrac{mu}{(m+m')}\\\\V=\dfrac{0.14\times 25}{(71+0.14)}\\\\V=0.049\ m/s\)
So, his speed at the highest point is 0.049 m/s.
The speed of ballplayer during taking the catch is 0.049 m/s.
Given data:
The mass of ball is, m = 140 g = 0.140 kg.
The speed of ball is, u = 25 m/s.
We need to find the speed when the ballplayer is at the highest point of his leap. They will stick with each other. Let they move with the speed of V.
Also, let a 65 kg baseball player jumps straight up to catch a hard-hit ball. Then according to the conservation of linear momentum,
\(mu+Mu'=(m+M)V\)
Here, u' is the initial speed of player. Since, the player was initially at rest, then u' = 0.
Solving as,
\((0.140 \times 25)+(65 \times 0)=(0.140+65)V\\\\\V= \dfrac{(0.140 \times 25)}{(0.140+65)}\\\\V = 0.049 \;\rm m/s\)
Thus, we can conclude that the speed of ballplayer is 0.049 m/s.
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A pulley consists of a large disk of radius R and a small disk of radius r that are welded together and mounted on a horizontal frictionless axle through their common centers. The moment of inertia of this pulley is I. A box containing a turkey of mass M is suspended from a rope wound around the large disk; a box containing a pumpkin of mass m is suspended from a rope wound around the small disk. The ropes do not slip on the disks. The system is released from rest and the turkey begins to descend, while the pumpkin is being lifted up.
Use forces and torques to derive an expression for the angular acceleration of the pulley, in terms of system parameters
The angular acceleration of the pulley is given by the expression α = (MgR - mgr) / I.
The forces acting on the system are the gravitational forces on the turkey and the pumpkin, which are Mg and mg, respectively. T
These forces create torques on the pulley, with the torque on the large disk being MgR and the torque on the small disk being -mgr. The negative sign on the torque of the small disk indicates that it is acting in the opposite direction of the torque on the large disk.
The sum of these torques is equal to the moment of inertia of the pulley times its angular acceleration, which can be written as:
MgR - mgr = Iα
Solving for the angular acceleration, α, we get:
α = (MgR - mgr) / I
This is the expression for the angular acceleration of the pulley in terms of the system parameters. It shows that the angular acceleration depends on the masses of the turkey and the pumpkin, the radii of the large and small disks, and the moment of inertia of the pulley.
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A 2000 kg car moves at a speed of 30 m/s. To reach this speed, it was necessary to burn 0.1 l of gas. Burning gas provides 30 MJ/l of source energy. Determine the energy efficiency (in %) of this car.
The energy efficiency of the car is approximately 16.7%.
The energy efficiency of a car is the ratio of the useful work output (in this case, the kinetic energy of the car) to the total energy input (in this case, the energy released by burning the gasoline). The equation for energy efficiency is:
Efficiency = Useful work output / Total energy inputThe useful work output can be calculated as the kinetic energy of the car using the equation:
KE = 0.5mv²where m is the mass of the car and v is its velocity.
Substituting the given values:
KE = 0.5 x 2000 kg x (30 m/s)² = 900,000 JThe total energy input is the energy released by burning 0.1 L of gasoline, which is:
Total energy input = 0.1 L x 30 MJ/L = 3 MJ = 3,000,000 JSubstituting these values into the equation for efficiency:
Efficiency = (900,000 J / 3,000,000 J) x 100% = 0.3 x 100% = 16.7%Therefore, the energy efficiency of the car is approximately 16.7%.
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an alcohol thermometer is preferred for a very cold region why
Answer:
freezing point of alcohol is - 117°C. So, it can measure the temperature of the very cold region.
Explanation:
Alcohol thermometer is preferred for a very cold region because its freezing point of alcohol is - 117°C. So, it can measure the temperature of the very cold region.
if the wet bulb depression is 3° and the dewpoint is 24°, what’s the relative humidity?
The relative humidity (RH) where the Wet Bulb Depression is 3° and the Dewpoint is 24° is given as 78.92%.
What is relative humidity?Relative humidity (RH) is a percentage ratio of the quantity of atmospheric moisture available to the amount that would exist present if the air was saturated.
The relationship between Relative Humidity, Air Temperature, and Dewpoint is given as follows:
RH = 100 *[\(e^{\frac{(\beta * Dp)}{(\lambda + Dp)}}\) / \(e^{\frac{(\beta * T)}{(\lambda + T)}}\)]
Where
RH = Relative Humidity
T = Air Temperature
Dp = Dewpoint
β = 17.625 and λ = 243.04°C; (revised Magnus coefficients)
e = 2.7182818 [exponential constant]
Note that Air temperature (T) is determined using the attached Dewpoint Psychrometer Table /chart
As given on the chart and in the question;
T = 28°
Dp = 24°
Hence,
RH = 100 x [\(e^{\frac{(17.625 * 24)}{(243.04+ 24)}}\) / \(e^{\frac{(17.625 * 28)}{(243.04+ 28)}}\) ]
RH = 100 x [ \(e^{(423/267.04)}\) )/ \(e^{(493.5/271.04)}\)]
RH = 100 x [\(e^{1.584}\)/\(e^{1.8207}\)]
RH = 100 x (4.874414/6.176578)
RH = 100 x 0.789177113929
RH = 78.9177113929
RH \(\approx\) 78.92%
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