When designing a crankshaft, you want to be 99.9% certain that the fatigue limit of the material is in excess of the cyclic stresses it will realize in service. If the experimental fatigue limit for the material is 40 ksi, the actual limit must be at least...

Answer: quarter turn

Explanation:  There are two basic types of valves ball valves and quarter turn valves or unblocks the hole, either allowing or preventing fluid flow.

The statements in symbolic form using p and q will be:

It should be noted that symbolic information is information that is represented by systems of symbols.

It's possible that such a system may consist of one symbol. For instance, texts form an important type of symbolic information.

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Medium Voltage Circuit Breaker

Usually, medium voltage circuit breaker is to protect the transformer from voltage spikes on a distribution transformer.

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Different lever designs can be engineered and developed to alter the brake pedal effort required of the driver by using different levels of mechanical advantage.

Mechanical advantage can be defined as a ratio of the output force of a lever to the force acting on it (input force or effort), assuming no losses due to wear, flexibility, tear or friction.

This ultimately implies that, different lever designs can be suitably engineered and developed to alter the brake pedal effort (input force) that is required of the driver, especially by using different levels of mechanical advantage.

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The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb

F = P (Normal force)

Formula for moment at section

M = P(4 + 1.5/2)

= 4.75p

Solve for the cross sectional area

Area = \(\frac{\pi d^{2} }{4}\)

d = 1.5

\(\frac{\pi *1.5^{2} }{4}\)

= 1.767 inches²

\(\frac{\pi *0.75^4}{4}\)

= 0.2485inches⁴

Solve for the tensile force from here

\(\frac{F}{A} +\frac{Mc}{I}\)

30x10³ = \(\frac{P}{1.767} +\frac{4.75p*0.75}{0.2485} \\\\\)

30000 = 14.902 p

divide through by 14.902

2013.15 = P

The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb

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Answer:

What do u need it for just gaming or for streaming and other things

Answer:

The original seven wastes, or muda, are transportation, inventory, motion, waiting, overproduction, overprocessing and defects. ... When manufacturers are able to identify the seven wastes, they can correct and prevent further loss of time, money and other resources.

Explanation:

Answer:

transportation, inventory,motion, waiting,overproduction,overprocessing,and defects

Explanation:

they are often referred to by the acronym TIMWOOD

The term that is not designed to absorb collision energy is dimples.

What is an energy-absorbing mechanism?

Energy-absorbing mechanism is a safety mechanism that absorbs the kinetic energy that is generated during an impact.

The shock-absorbing material, which is intended to be compressed in a controlled manner under the impact, is the most basic component of this system.

What is the purpose of the design of a crush zone?

Crush zones are engineered areas of a vehicle that are designed to absorb and dissipate energy during a collision.

They are often constructed from a variety of materials, including high-strength steel, aluminum, magnesium, and other composites.

O Slots, crush zones, and reinforcements are all safety features that are designed to absorb collision energy and lessen the impact of a collision on the vehicle and its occupants.

These energy-absorbing mechanisms allow the vehicle to deform or collapse in a controlled manner, slowing down the rate of deceleration and reducing the amount of force transferred to the vehicle's occupants.

Dimples, on the other hand, are not an energy-absorbing mechanism.

Dimples are tiny indentations or bumps on the surface of a material that is often used to reduce aerodynamic drag. They are not designed to absorb collision energy.

Therefore, the answer is dimples.

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average stress value in kpa with a 6 hz frequency and 5,371 kpa of pressure. 4,342

What does the term "sinusoidal function" mean?

A function that is based on the sine function, a periodic function that oscillates smoothly between high and low values, is referred to as a sinusoidal function. Since the cosine function is simply a horizontal shift of the sine function, sinusoidal functions can also be built on it. A function that describes some occurrence is a mathematical model. Since sinusoidal functions are periodic, they can be utilized as models for objects that display periodic behavior. In some applications of periodic phenomena, however, the concept of frequency is utilized in place of the period.

Explanation

y (+)= A0 + Bsin (wt)

A0= 5371 +3,313/2 =4,342

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The volume displaced per minute (cfm) of the four-cylinder, four-cycle IC engine with a bore of 3.3 in and a stroke of 4.1 in when it is drawing 60 cfm of the mixture at approximately 1800 rpm is equal to 89.21 cfm (Option b).

The bore diameter of a four-cylinder, four-cycle IC engine is 3.3 inches and the stroke is 4.1 inches. The engine utilizes 60 cfm of the incoming mixture at 1800 rpm. We must determine the volume deposed per minute (cfm). The following formula was used:

Volume Displaced by the engine= bore² × 0.7854 × stroke × RPM × no. of cylinders ÷ 1728

In the above formula, we can substitute the following values:

Volume Displaced by the engine= 3.3² × 0.7854 × 4.1 × 4 × 1800 ÷ 1728= 89.21 cfm. Hence, the correct option is (b) 89.21 cfm.

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It can provide measurements of stars with a higher angular resolution than is possible with conventional telescopes.

The technician that is correct based on the information given is;

Technician B

However, older cars or those with turbo engines may still require oil changes every 3,000 to 5,000 miles. Whereas, with Synthetic oils the change intervals are higher than that provided by conventional oils and could be as high as over 15,000 miles or just once a year depending on if the engine is not used much or not.

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In the given circuit, the current i2 through resistor R2 can be determined using Kirchhoff's current law (KCL) and Ohm's law.

According to KCL, the sum of the currents entering and leaving a node in a circuit must be zero.

Applying KCL at node B in the circuit gives:

i1 + i2 = i3

Since the positive direction is taken to be downward, i1 can be expressed as

:(Va - Vb) / R1

Similarly, i3 can be expressed as:

(Vb - 0) / R3 = Vb / R3By

substituting these expressions in the KCL equation and simplifying, we get:i

2 = Vb (1 / R3 - 1 / R2) - (Va / R1)

This is the expression for i2 in terms of Va, Vb, R1, R2, and R3.

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The classification of the working surfaces are as follows;

A working surface is a flat surface on which various activities can be carried out.

In a construction system, the duty carried on a particular working surface varies from another. They can be categorized into heavy-duty, medium-duty, light-duty, and very light-duty.

The classification of the working surfaces are as follows;

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Answer:

8×10^-19 seconds

Explanation:

i=∆q/∆t

=> ∆t=∆q/i=50×1.6×10^-19/10=8×10^-19(s)

Answer:

This shows that the technological designs are similar to the scientific investigation processes.

Explanation:

Scientists carry out scientific investigations and discoveries. They learn from their environment by investigating the natural world. The scientist investigates by problem identification, research the related information, designing and conceptualizing, investigating and analyzing the results and deriving out conclusions.

Similarly the engineers follow the same step and provide solutions to the problems of the society through their products and technological designs. The engineers first identify the need of the product, design and implement the design to provide solution and then evaluate the solution. These are the similar steps that an engineer follow in a technological design of a product or a solution.

During the peak hour, it is expected that there will be a significant increase in traffic volume.

A freeway is being designed for a location in rolling terrain, where the expected free-flow speed (FFS) is 55 mi/h. During the peak hour, it is expected that there will be a significant increase in traffic volume.

To ensure safety and efficiency, the design of the freeway will need to take into account the topography of the rolling terrain, as well as the expected traffic flow during peak hours.

This will involve careful consideration of factors such as the number of lanes, interchanges, and access points, as well as the use of advanced traffic management systems to help regulate the flow of vehicles on the freeway. Ultimately, the goal is to create a safe and reliable transportation network that can accommodate the expected demand for many years to come.

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Using R, the built-in dataset "mtcars" can be loaded, and OLS regression can be performed to investigate the relationship between 1/4 mile time and the vehicle's number of cylinders, gross horsepower, rear axle ratio, weight, and number of carburetors. Residuals can be plotted to assess the presence of autocorrelation and heteroskedasticity, and a variance inflation test can be conducted to check for multicollinearity among the independent variables.

To perform the analysis, the "mtcars" dataset in R can be loaded using the command `data(mtcars)`. The OLS regression can be conducted using the `lm()` function with the dependent variable "1/4 mile time" and the independent variables "number of cylinders," "gross horsepower," "rear axle ratio," "weight," and "number of carburetors." The results of the regression analysis, including coefficients, p-values, and model fit statistics, can be obtained.

Next, the residuals of the regression model can be plotted using the `plot()` function to visually assess the presence of autocorrelation and heteroskedasticity. Additional statistical tests, such as the Durbin-Watson test for autocorrelation and the Breusch-Pagan test for heteroskedasticity, can be performed to quantitatively evaluate these issues.

Furthermore, the variance inflation factor (VIF) can be calculated for each independent variable to identify potential multicollinearity. The `vif()` function from the "car" package in R can be used to compute the VIF values. Higher VIF values indicate a stronger correlation between independent variables.

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The best description for the operation of a television remote control is option (c) encoding and transmitting. This is because the remote control encodes the user's input (e.g. pressing a button to change the channel) into a specific infrared signal, which is then transmitted from the remote control to the television receiver.

This is correct because the infrared signal from the remote control is not decoded or stored within the remote control. Instead, it is an encoded signal that is sent directly to the television receiver to perform a specific function. The encoding and transmission of the infrared signal is what allows the remote control to operate the television from a distance.

Option (a) decoding and storing is not correct because the remote control does not decode or store any signals. Option (b) storing and retrieving is also not correct because the remote control does not store any signals to be retrieved later. It only transmits an encoded signal in real-time to operate the television receiver.

Therefore, the correct description for the operation of a television remote control is encoding and transmitting. The remote control encodes the user's input into an infrared signal, which is then transmitted to the television receiver to perform a specific function. This allows the viewer to change channels or perform other functions from a distance.

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Answer:

Kindly check explanation

Explanation:

(a) μMN, (b) N/μm, (c) MN/ks2, and (d) kN/ms.

(a) μMN = (10^-6 * 10^6) = 10^(-6 + 6) = 10^0 = N

b) N/μm = N / 10^-6 m = 10^6 * N/m = MN/m

(c) MN/ks2 = 10^6N / (10^3 s)^2

10^6 N / 10^6s^2 = 10^6 * 10^-6 N /s^2 = N/s^2

D) kN/ms = 10^3N / 10^-3 s = 10^3 * 10^3 * N/s = 10^6N / s = MN/s

2)

a) 0.000431kg = 431 × 10^6 kg = 431 * 10^9g = 431Gg

b) 35.3 × 10^3 N

10^3 = kilo(K)

35.3 KN

C) 0.00532km = 5.32 * 10^3 km = 5.32 * 10^3 * 10^3 = 5.32 * 10^6 = 5.32Mm

3) Represent each of the following combinations of units in the correct SI form: (a) Mg/ms, (b) N/nm, and (c) mN/(kg⋅μs).

a) Mg/ms = 10^6g / 10^-3s = 10^6 * 10^3 g/s = 10^9 g/s = Gg/s

b) N/nm = N / 10^-9 m = 10^9 N/m = GN/m

c) mN/(kg⋅μs) = 10^6N / kg(10^-6s) = 10^12N/(kg.s)

= TN/(kg.s)

Answer:

This image is blurry redo the question

Explanation:

The overall gain of the signal differential from the voltage gain is 1.71V

Voltage gain is the ratio of the output voltage of a circuit to the input voltage. It is usually expressed as a ratio or a percentage. The voltage gain of a circuit is a measure of its amplification capability.

The small signal differential mode voltage gain is calculated as follows:

Gain = (Vout3 - Vout2) / (Vin+ - Vin-)

Gain = (Vout3 - Vout2) / (VCC - VEE)

Gain = (Vout3 - Vout2) / (10V- (-10V))

Gain = (Vout3 - Vout2) / 20V

Gain = (Vout3 - Vout2) / 20

Vout3 = (Rc2 / (Rc2 + R6)) * VCC

Vout3 = (20kΩ / (20kΩ + 16.5kΩ)) * 10V

Vout3 = 0.546 * 10V

Vout3 = 5.46V

Vout2 = (Rc1 / (Rc1 + R7)) * VEE

Vout2 = (20kΩ / (20kΩ + 5kΩ)) * (-10V)

Vout2 = (-3.75V)

Gain = (5.46 - 3.75) = 1.71V

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Answer:

1. 1111.5MPa

2. 56.1GPa

Explanation:

1. Longitudinal tensile stress can be obtained by obtaining the strength and volume of the fiber reinforcement. The derived formula is given by;

σcl = σm (1 - Vf) + σfVf

Substituting the figures, we will have;

45(1 - 0.30) + 3600(0.30)

45(0.70) + 1080

31.5 + 1080

= 1111.5MPa

2. Longitudinal modulus of elasticity or Young's modulus is the ability of an object to resist deformation. The derived formula is given by;

Ecl = EmVm + EfVf

Substituting the formula gives;

= 2.4 (1 - 0.30) + 131 (0.30)

= 2.4(0.70) + 39.3

= 16.8 + 39.3

= 56.1GPa

Using the appropriate relation, the longitudinal tensile stress and the longitudinal modulus are 1111.50 and 56.10 respectively.

Longitudinal tensile stress can be obtained using the relation :

Substituting the values into the relation:

45(1 - 0.30) + 3600(0.30)

45 × 0.70 + 1080

31.5 + 1080

= 1111.50 MPa

2.)

Longitudinal modulus of elasticity is obtained using the relation :

Substituting the values thus :

2.4 (1 - 0.30) + 131 (0.30)

= 2.4 × 0.70 + 39.3

= 16.8 + 39.3

= 56.10 GPa

Hence, the longitudinal tensile stress and the longitudinal modulus are 1111.50 and 56.10 respectively.

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The steel-frame structural support was a main feature in the development of t the floors, roof, walls and  skyscraper.

Steel frame is known to be a form of a building method that is used along with a skeleton frame that is made up of steel columns and  I-beams.

Conclusively, This is often used  in the construction of grid to aid the floors, roof and walls of any kind of building. It is also used in the construction of skyscraper.

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Answer:

I am in Eight Grade

Explanation:

A manufacturer begins with 25-cm x 15-cm rectangular pieces of plate steel 8-mm thick (it weighs 62.8 kg/m2 ). The corners are rounded off with a 2-cm radius and a 3-cm radius hole is drilled in the center.

The area of the rectangular plate with rounded corners is given by

A = (25-4r)(15-4r) + (πr^2)/2 - πr^2A = 375 - 100r + 8π

And, the weight of one such plate is given by

W = A × 0.008 × 62.8W = (375 - 100r + 8π) × 0.008 × 62.8W = 18.732 - 5.024r + 0.5024π

The manufacturer has 590 such plates,

So, the total weight of 590 such plates is590 × (18.732 - 5.024r + 0.5024π) kg≈ 11015 kg (rounded to the nearest kilogram)

Thus, the weight of 590 of the finished plates, rounded to the nearest kilogram for shipping purposes, is approximately 11015 kg.

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Answer:

4.30 gp

Explanation:

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The elevation and stationing of the high point, PVC, and PVT of the given vertical curve are;

High Point Station = 342+60

PVT Station = 340+00

PVC Station = 340+00

Elevation of High Point = 1350.0 ft

Elevation of PVT = 1325.0 ft

Elevation of PVC = 1345.0 ft

A 520-ft-long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and elevation 1325 ft. The initial grade is +4.0% and the final grade is 2.5%.

Determine the elevation and stationing of the high point, PVC, and PVT. A vertical curve is used to connect two tangents that have differing slope grades, and it is the arc of a parabola. The parabolic arc's vertex is referred to as the high point of the curve.

PVC (point of vertical curvature) is the point where the parabolic arc starts and the tangent line ends, and PVT (point of vertical tangency) is the point where the parabolic arc ends and the tangent line begins.

Therefore, by considering the given data, we can calculate the elevation and stationing of the high point, PVC, and PVT of the vertical curve in the following way;

Stationing of the curve = 340+00. High point of the curve = L/2 + 340+00 = 520/2 + 340+00 = 342+60PVC = 340+00. Elevation of PVC = Elevation of point of intersection + (Initial grade / 100) x Length of the curve 1325 + (4/100) x 520 = 1345 ft.

Elevation of PVT = Elevation of point of intersection + (Final grade / 100) x Length of the curve 1325 + (2.5/100) x 520 = 1350 ft.

Therefore, the elevation and stationing of the high point, PVC, and PVT of the given vertical curve are;

High Point Station = 342+60

PVT Station = 340+00

PVC Station = 340+00

Elevation of High Point = 1350.0 ft

Elevation of PVT = 1325.0 ft

Elevation of PVC = 1345.0 ft

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