When converted to a household measurement, 9 kilograms is approximately equal to a

Neutrons and protons in an atom are acted upon by the strong force.

Strong force or strong nuclear force, a fundamental interaction of nature that acts between subatomic particles of matter. The strong force binds quarks together in clusters to make more-familiar subatomic particles such as protons and electrons.

Quarks are fundamental building blocks of matter. They are most commonly found inside protons and neutrons.

So being only option in which electrons are not present , option D is the correct answer.

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Supersonic flights are moving with speed greater than that of sound. This speed through air will combine the pressure waves and creates shock waves. Continuation of shock waves leads to sonic boom in air.

Sonic booms are sound created on the ground by overpressure in the air generated by fastly moving objects. Similar to someone dumping goods from a moving car, an aircraft travelling at supersonic speeds continuously produces shock waves that cause sonic booms to travel throughout its flight path.

The boom seems to be swept rearward as it moves away from the aeroplane from its point of view. The boom will strike the ground in front of the aircraft if the aircraft makes a rapid turn or pulls up.

The abrupt start and release of pressure following the building by the shock wave or "peak overpressure" is what is heard as a "sonic boom" on the ground. Only a few pounds per square foot change in pressure results from a sonic boom, which is about equivalent to the pressure shift we experience in an elevator.

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The conversion factor of 5280 feet per mile is used to convert the distance, and rounding to the nearest tenth gives us approximately 3.6 miles. The correct answer is option D: 3.6 mi.

To convert 18,900 feet to miles, we can use the conversion factor of 5280 feet per mile. By dividing the distance in feet by this conversion factor, we will obtain the equivalent distance in miles.

Distance in miles = 18,900 feet ÷ 5280 feet/mile

Calculating this expression, we find:

Distance in miles = 3.57 miles

Rounding to the nearest tenth, the distance is approximately 3.6 miles.

Therefore, the correct answer is option D: 3.6 mi.

It is important to note that the conversion factor of 5280 feet per mile is derived from the definition of a mile as 5,280 feet. This conversion factor is widely used to convert measurements between feet and miles in various contexts, such as distance calculations, road signs, and sports events. Here option D is the correct answer.

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Answer:

I'm not sure if they're right but...

1. It would erode because of the water

2. It would probably become a home for the ocean creatures

The two (2) ways in which a giant boulder by the ocean may change over time are:

1. The ocean water would change the boulder's appearance and texture.  

2. The giant boulder would be transformed into sediments due to erosion and weathering through dissolution.

A boulder can be defined as a large (giant) rounded mass of rock fragment that is formed through its detachment from a parent consolidated rock, especially due to erosion and weathering.

Basically, the size of a boulder is greater than 256 millimeters (25.6 centimeters or 10.1 inches) in diameter.

The reason why giant (large) boulders are present in steep mountain streams or oceans is mainly because they are usually too heavy for them to be moved by the body of water.

This ultimately implies that, water cannot move a giant (large) boulder that is present in an ocean because of its size and weight.

However, a giant (large) boulder that is present in an ocean would be affected in these two (2) ways:

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Answer:Power is a measure of the amount of work that can be done in a given amount of time. Power equals work (J) divided by time (s). The SI unit for power is the watt (W), which equals 1 joule of work per second (J/s). Power may be measured in a unit called the horsepower

Explanation:

Answer:

Explanation:Power equals work (J) divided by time (s).

Answer:

I agree with your answer - the acceleration of the sled and hence its velocity at any time does not depend on the mass of the sled and occupants

F = m a = m g sin θ    force accelerating sled  - and a does not depend on m

So also the total KE would be larger for a larger total mass

If the cloud is transparent, milky, thin layers, rain within the next 2 hours, then the cloud you are seeing is most likely a type of altocumulus cloud.

Altocumulus clouds are generally characterized by their white or gray color, and can sometimes appear milky or translucent. They often form in layers, and can be thin or thick depending on the conditions.

Altocumulus clouds are typically found at medium altitudes, between 6,500 and 20,000 feet and are often associated with unsettled weather conditions.

While they don't necessarily indicate that rain is imminent, altocumulus clouds can be a sign that a change in the weather is on the way.

Thus, if it is likely to rain in the next 2 hours, then the cloud must be altocumulus clouds.

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Hi there!

\(\large\boxed{\text{C. 17.7m/s}}\)

Use the following kinematic equation to solve:

vf² = vi² + 2(ad)

Since the initial velocity is 0 m/s because it started at rest, we can eliminate this part of the equation:

vf² = 2ad

Plug in the given acceleration and distance:

vf² = 2(9.8)(16)

vf ≈ 17.7. The correct answer is C.

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Our muscles need more oxygen to make energy (in the form of ATP) while we workout.

When the respiratory rate picks up to fulfill this need, more oxygen can enter the body and more carbon dioxide can be exhaled.

Student 3 is breathing more forcefully than usual in this situation because of the high temperature and physical activity.

The respiratory system is the organ system engaged in this process.

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# complete question:

A group of students were playing basketball together during recess. The temperature outside was 30.5 oC (87 oF) and the sun was out. The students ran, shot baskets, and dribbled the ball for 30 minutes. When they finished their game some of the students made the following comments:

Student 1: Wow! I am so hot and sweaty! I need some water to cool down.

Student 2: My cheeks are really red.

Student 3: I am breathing so hard, I can barely catch my breath!

Explain what is happening to the students and how their bodies are trying to maintain homeostasis. Be sure to include any of the organ systems involved with each student.

Answer:

Play tennis, nothing can train you better for the sport than the sport itself. However, tennis is one of those unique sports that combine nearly all components of fitness including power, agility, speed, flexibility, reaction time, balance, coordination, cardiovascular endurance and muscular endurance.

Explanation:

1. The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon.

2. The bright part of the moon appears bright due to the reflection of sunlight.

Introduction: The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon. By creating models of the three celestial bodies, we aimed to understand how their movements and positions influence the phases of the moon and eclipses.The bright part of the moon appears bright due to the reflection of sunlight. As sunlight hits the moon's surface, it bounces back and reflects into space. This reflected light is what we see as the bright part of the moon.

Experimental Methods: To create our model, we used a lamp to represent the Sun, a ball to represent the Earth, and a smaller ball to represent the Moon. We also used a ruler, tape, and a protractor to measure distances and angles.We created our model by placing the lamp at one end of a table, the Earth in the middle, and the Moon at the other end. We attached the Moon to a string and moved it around the Earth to simulate the Moon's orbit around the Earth.

Develop a Model: Our model consists of a lamp, a ball, and a smaller ball on a string. The lamp represents the Sun, the ball represents the Earth, and the smaller ball on the string represents the Moon. As the Moon moves around the Earth, it goes through phases, from a new moon to a full moon and back again.We used diagrams and pictures to label the components of our model and describe causal accounts for the phases of the moon and eclipses.

Use a Model: When the Moon is full, it is in a direct line with the Earth and the Sun. Using our model, we can predict that the Moon would be directly opposite the Sun in the sky during a full moon. A lunar eclipse does not occur every month when there is a full moon because the Moon's orbit around the Earth is tilted at an angle of about 5 degrees to the Earth's orbit around the Sun. Therefore, the Moon is not always in a direct line with the Earth and the Sun during a full moon, which is necessary for a lunar eclipse to occur.

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Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

The correct options for how thermal energy is transferred during conduction are " Thermal energy is transferred between particles that are in direct contact with each other.", "Thermal energy is transferred between objects of different temperatures.", and "Thermal energy is transferred from fast-moving particles to slow-moving particles." The correct options are B, C, and F.

During conduction, thermal energy is transferred through a material or between objects in direct contact with each other. The transfer of thermal energy occurs because of temperature differences between the two objects or regions. When two objects at different temperatures are in direct contact with each other, the hot object transfers thermal energy to the cold object through collisions between the particles of the two objects. The fast-moving particles in the hot object collide with the slow-moving particles in the cold object, transferring thermal energy from the hot object to the cold object. This process continues until the two objects reach thermal equilibrium, meaning they have the same temperature and there is no more net transfer of thermal energy between them.

Option A is not true because thermal energy is actually transferred between particles that are in direct contact with each other, not particles that are not touching each other.

Option D is not true because thermal energy does not transfer between objects that are already at the same temperature. Heat transfer only occurs when there is a temperature difference.

Option E is not true because thermal energy actually flows from hot objects to cold objects. Therefore, thermal energy is transferred from fast-moving particles to slow-moving particles, not the other way around.

Therefore, The correct answers are  B, C, and F.

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Answer:

Metal is cold because it is a good conductor. A conductor carries heat away from and object. Heat flows from your hand into the metal and then is conducted rapidly away into the bulk of the metal, leaving the metal surface and your skin surface relatively cool.

Explanation:

You are welcome.

Metal has EXTREME thermal conductors...meaning that the metal can easily change due to weather, even when wind blows on it, usually that is why it is cold

Hope this helps..You're welcome ;)

Answer:

3

Explanation:

because half I think is the answer

Answer:

10 m

Explanation:

5  m/s   *   2 s = 10 meters     ( see how the  ' s '  cancels out?)

Answer:Distance=6.67 (rounded)

Explanation: Work = Force x Distance.

100 Joules of work= force of 15 N x Distance (?)

The work equation given above can be rearranged to find force or distance if the other variables are known:

Distance=Work / force

Distance=100Joules/15 N

Distance=6.67 (rounded)

Answer:

Explanation:

Velocity relative to earth = .99537 c

= .99537 x 3 x 10⁸ m /s

= 2.98611 x 10⁸ m /s

distance relative to earth = 40 km = 40 x 10³ m .

Time measured by scientist

= 40 x 10³ /  2.98611 x 10⁸

= 13.395 x 10⁻⁵ s

= 134 μs.

The x-component for the vector given in the image is : \(B_{x}\) = 18.3m

A Vector can be defined as a quantity that possesses both magnitude and direction thereby giving more details.

A vector is very important when it comes to dealing with forces.

Analysis

\(B_{x}\) = B cos(Θ)

Θ = 180° - 170° = 10°

\(B_{x}\) = B cos(10°) = 18.3m

In conclusion, The x-component for this vector is : \(B_{x}\) = 18.3m

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Answer:

The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.

Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:

Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet

To find the total resistance when the conductors are in parallel, we use the formula:

1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3

Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)

Substituting the values, we get:

Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))

Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.

Explanation:

spring constant k::8.5

and displacement x::1.2

f:? f: k×x

8.5×1.2:10.2N

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

where

f is the force

m is the acceleration

From the question we have

\(a = \frac{6.2}{3.2} \\ = 1.9375\)

We have the final answer as

Hope this helps you

Answer:

\(\theta=119.06^{\circ}\)

Explanation:

The vector is :

A = -25i+45j

We need to find the angle between angle A and the positive x-axis. It can be calculated as follows :

\(\theta=180^{\circ}-\tan^{-1} (\dfrac{45}{25})\\\\=180-60.94\\\\=119.06^{\circ}\)

So, the angle of vector A with the +x axis is \(119.06^{\circ}\).

The answer is A. velocity .

Velocity is a vector quantity because it need magnitude as well as direction to be defined.

a) La Distancia entre el telescopio y el satélite es aproximadamente \(8.602\times 10^{5}\) metros.

b) La señal sale del telescopio y se desplaza \(7\times 10^{5}\) metros en Dirección + x y \(5\times 10^{5}\) metros en Dirección +y.

a) Si asumimos la Posición del telescopio como el Origen de un Marco de Referencia, entonces la Distancia entre el telescopio y el satélite (\(d\)), en metros, mediante la siguiente expresión:

\(d = \sqrt{(S(x,y) - O(x,y))\,\bullet\,(S(x,y) - O(x,y))}\) (1)

Donde:

Si sabemos que \(O(x,y) = (0, 0)\) y \(S(x,y) = (7\times 10^{5}, 5\times 10^{5})\), entonces la Distancia entre el telescopio y el satélite es:

\(d = \sqrt{(7\times 10^{5})^{2}+(5\times 10^{5})^{2}}\)

\(d \approx 8.602\times 10^{5}\,m\)

Nota - (1) es una forma vectorial del Teorema de Pitágoras.

La Distancia entre el telescopio y el satélite es aproximadamente \(8.602\times 10^{5}\) metros.

b) La señal sale del telescopio y se desplaza \(7\times 10^{5}\) metros en Dirección + x y \(5\times 10^{5}\) metros en Dirección +y.

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-27.7 x 10⁶ N is the net force on particle q₂..

Define a charged particle

A particle with an electric charge is said to be charged particle. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. It could also be an elementary particle like as an electron, proton, or another one that is thought to have the same charge (except antimatter).

F₁₂ = kq₁q₂/r²

k is Coulomb's constant

r is the distance between q₁ and q₂

q represent charges

F₁₂ = (9x 10⁹ x 18.1 x 10⁻³ x 11.2 x 10⁻³)/(0.28)²

F₁₂ = -23* 10⁶ N

F₂₃ = kq₂q₃/r²

F₂₃ = -(9 x 10⁹ x 11.3 x 10⁻³ x 5.67 x 10⁻³)/(0.35)²

F₂₃ = 4.7 x 10⁶ N

F(net) = F₁₂ + F₂₃

         = -23* 10⁶ N + -4.7 x 10⁶ N

         =  -27.7 x 10⁶ N

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Ben as a psychology student is most likely conducting a behavioral study.

What is psychology?

Psychology can simply be defined as the study of human mind, conscious and unconscious, thoughts and feelings.

In conclusion, Ben as a psychology student is most likely conducting a behavioral study.

Some few branches of psychology are:

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Answer:

920000

Explanation:

Each kg contains 1,000 grams

Explanation:

c because there is element

Answer:

C. H2 and N2 would react to produce more NH3

Explanation:

A.P.E.X