when calculating a battery’s capacity using: what is the main underlying assumption regarding the battery?

A "confederation" is a system of government in which member states retain almost all of their sovereign authority and delegate limited powers to a weak central body.

In a confederation, the central government has limited authority and primarily serves as a coordinating body for the member states. The member states maintain a significant degree of independence and have the power to make decisions on matters that directly affect them.

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For a planet or moon to have planet-wide convection cycles, it must have a molten or partially molten interior, a strong global magnetic field, and a thick mantle that can support convection over long periods of time.

For a planet or moon to have planet-wide convection cycles, several conditions need to be met. The first requirement is that the planet or moon must have a molten or partially molten interior, which allows for the movement of material within the mantle. This movement is driven by heat transfer from the planet's core, which creates thermal gradients that cause material to rise and fall in a convection cycle.
Another requirement is the presence of a strong, global magnetic field. This magnetic field is generated by the movement of molten material in the planet's core and helps to protect the planet from harmful solar radiation. It also plays a crucial role in driving convection cycles, as the magnetic field interacts with the convecting material in the mantle.
Finally, the planet or moon must have a relatively thick mantle that is capable of supporting convection over long periods of time. This requires a sufficient amount of heat to be generated within the core and a slow cooling rate, which allows the mantle to remain molten for billions of years.
In summary, for a planet or moon to have planet-wide convection cycles, it must have a molten or partially molten interior, a strong global magnetic field, and a thick mantle that can support convection over long periods of time.

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To find the image distance formed by a concave mirror, we can use the mirror equation:

1/f = 1/di + 1/do

Where:

f is the focal length of the mirror,

di is the image distance,

and do is the object distance.

In this case, the object distance (do) is given as 12.0 cm, and the focal length (f) is given as 15.0 cm. We can rearrange the equation to solve for the image distance (di):

1/di = 1/f - 1/do

Substituting the given values:

1/di = 1/15 - 1/12

To simplify this expression, we need to find a common denominator:

1/di = (12 - 15)/(12 * 15)

1/di = -3/180

Now, we can invert both sides to find di:

di = 180/-3

di = -60 cm

Therefore, the image distance is -60 cm. The negative sign indicates that the image is formed on the same side as the object (in this case, it is a virtual image).

Answer:

60 cm

Explanation:

the U (obj. distance)  =   12  as it is a concave mirror then u  =  -12cm

the f = -15cm

by mirror formula

1/v  +  1/u =  1/f

by substituting values

1/v  +  (1/-12)  =  1/-15

1/v = 1/-15 -(1/-12)

1/v = 1/-15 + 1/12

by taking L C M  60

1/v = -(4/60)  +  5/60

1/v = 1/60

so V = 60 cm

Answer:

Liquid

Explanation:

Thw answer is liquid

Answer:

Explanation: If a net force of 50 N pulls on a 10 kg object, how much acceleration will it cause? Then an answer is possible. Equation: Net force = mass * acceleration.

Initial velocity of 2.4 m/s and an angle of 60°.

The x component is 2.4 m/s cos(60°) = 2.4 m/s (0.5) = 1.2 m/s

The y component is 2.4 m/s sin(60°) = 2.4 m/s (0.866) = 2.08 m/s

Initial velocity is the speed an object has when it starts moving in a certain direction. It is the speed that an object has before any external forces act upon it. Initial velocity is a vector quantity, meaning it has both a magnitude, or size, and a direction. Initial velocity is usually measured in meters per second (m/s). It is important to note that the initial velocity of an object can be different depending on the reference frame from which it is measured.

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The complete question is-

A paper airplane is thrown with an initial vclocity of 2,4 m and angle of 60" Find the Voz: 012m/s 0.62 mn/& 0 1.70 m/8 208 m/$

Answer: 18

Explanation:

i think

Answer: 30

Explanation: ck-12 momentum and impulse

Answer:

Defined below

Explanation:

Climate change is simply the long term change in the average weather patterns that are associated with the local, regional and global climates of the earth. Climate change is usually driven by human activities like burning of fossils; natural processes like cyclic ocean patterns; external factors like volcanic eruptions.

We have that the new height of the crate  is mathematically given as

Hn=0.56

Question Parameters:

A 50N crate is lifted 0.86m from the ground

then is allowed to drop losing 15 J of energy.

Generally the equation for the Potential energy  is mathematically given as

P.E=mgh

Where

m=50/9.8

Therefore

h=15/(50/9.8*9.8)

h=0.3m

New height

0.86-0.3

Hn=0.56

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Answer:

y = 6

Explanation:

Given parameters:

        Given equation:

                     y = 2x + 10

And supposing; x = -2

Unknown:

y = ?

Solution:

 We are going to solve this problem by substitution;

           y = 2x + 10

  since x = -2; input this into the equation to solve for y;

           y  = 2(-2) + 10 = -4 + 10  = 6

The value of y = 6

The maximum emf produced by the generator can be calculated using Faraday's law of electromagnetic induction, and it is found to be about 47 V.

For the AC circuit, it is assumed that the resistor and capacitor are in series, and the average power consumed by the circuit is calculated using Ohm's law and it equals to 54.55 W.  The emf generated by a rotating coil in a magnetic field is given by ε_max = NBAωsin(ωt), where N is the number of turns, B is the magnetic field strength, A is the area of the coil, ω is the angular speed and t is time. At maximum emf, sin(ωt) = 1. Converting the rpm to rad/s and substituting the given values, we get ε_max to be approximately 47 V. In an AC circuit with a resistor and a capacitor in series, the current and voltage are out of phase. The average power consumed is given by P_avg = Irms^2 * R, where Irms is the root-mean-square current and equals Vrms/R. Substituting the given values, we get P_avg to be approximately 54.55 W.

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Answer:

Explanation:

We are tp calculate the range of the projectile. This is expressed as;

R = 2Usin theta/g

Given

U = 53m/s

Theta = 67°

Substitute;

R = 2(53)sin67/9.8

R = 106sin67/9.8

R = 106(0.9205)/9.8

R = 97.57/9.8

R = 9.96m

Hence the enemy is 9.98m located for a direct hit.

According to the given statement Mrs. Brown's electricity bill for the current month is $5000.00.

To calculate Mrs. Brown's electricity bill for the current month, we need to determine the total number of kilowatt-hours (kWh) she has consumed and apply the corresponding rates.

1. Calculate the electricity usage:

  Current meter reading - Previous meter reading
  20,300 kWh - 17,800 kWh = 2,500 kWh

2. Determine the cost for the first 2000 kWh:

  $1.00/kWh * 2000 kWh = $2000.00

3. Determine the cost for the remaining kWh:

  500 kWh * $3.50/kWh = $1750.00

4. Add the fuel adjustment charge:

  $0.50/kWh * 2500 kWh = $1250.00

5. Calculate the total bill:

  $2000.00 + $1750.00 + $1250.00 = $5000.00


To calculate the electricity bill, we first find the difference between the current and previous meter readings.

In this case, Mrs. Brown used 2,500 kWh.

For the first 2000 kWh, the cost is $1.00 per kWh, resulting in a charge of $2000.00.

For the remaining 500 kWh, the cost is $3.50 per kWh, totaling $1750.00.

Additionally, a fuel adjustment charge of $0.50 per kWh is added to the bill. This amounts to $1250.00.

Finally, we add up all the charges to get the total bill, which is $5000.00.

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Answer:

1). Brake pedal or lever

2). A pushrod also called an actuating rod

The acceleration of the 2.0 kg block is approximately 2.548 m/s^2.

To calculate the acceleration of the block, we use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the net force is the force of kinetic friction between the block and the table. The force of kinetic friction can be determined using the equation f_k = μ_k * N, where μ_k is the coefficient of kinetic friction and N is the normal force.

The normal force N acting on the block is equal to its weight, which can be calculated by multiplying the mass of the block (2.0 kg) by the acceleration due to gravity (9.8 m/s^2). Therefore, the force of kinetic friction can be expressed as f_k = μ_k * m * g.

By equating the force of kinetic friction to the product of the mass and acceleration (f_k = m * a), we can solve for the acceleration a. Substituting the given coefficient of kinetic friction μ_k = 0.26 and the acceleration due to gravity g = 9.8 m/s^2, we find:

a = μ_k * g

= 0.26 * 9.8 m/s^2

≈ 2.548 m/s^2.

Hence, the acceleration of the 2.0 kg block is approximately 2.548 m/s^2. This means that the block will experience an acceleration of 2.548 m/s^2 in the direction of the applied force, considering the resistive force of kinetic friction acting against its motion on the table.

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According to the research, the correct option is Aerobic exercise can last continuously for many minutes. It is the statement that correctly he can use to make in his description about aerobic exercise.

They are those physical activities that aim to burn fat using a high amount of oxygen.

In this sense, these exercises allow to improve the resistance of the person, they are not very intense but are developed in long periods, unlike anaerobic exercises that are more intense and brief.

Therefore, we can conclude that according to the research, the correct option is Aerobic exercise can last continuously for many minutes. It is the statement that correctly he can use to make in his description about aerobic exercise.

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Answer: Aerobic exercise can last continuously for many minutes.

Explanation:

Got it correct

The researcher is studying the amount of trash (in kgs per person) produced by households in city X, and previous research suggests that the amount of trash follows a distribution with density force fe (2) --1/7 torz.

The density function fe (2) --1/7 torz indicates the probability distribution of the amount of trash produced by households in city X. This means that the researcher can use this distribution to make predictions about the amount of trash that is likely to be produced by households in the city. The density function can be used to calculate the probability of producing a certain amount of trash per person, given the distribution.

A probability density function is a function that describes the likelihood of a continuous random variable taking on a specific value within a given range. In this case, the continuous random variable is the amount of trash (in kgs per person) produced by households in city X. The pdf provided in the question, f(e) = 1/7 for 2 ≤ e ≤ 9, indicates that the amount of trash follows a uniform distribution between 2 and 9 kgs per person.
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Answer: A

Explanation:Convection currents in the mantle Mantle convection is the very slow creeping motion of Earth's solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface. The Earth's surface lithosphere rides atop the asthenosphere and the two form the components of the upper mantle.

Answer:

B

Explanation:

The range of a projectile is related to its maximum height by the equation \(\begin{equation}R = \frac{2 v^2 \sin{\theta} \cos{\theta}}{g}\). For projectiles with the same range, the product of the maximum height and the cosine of the launch angle is constant.

The range (R) of a projectile is the horizontal distance traveled by the projectile before it lands. The maximum height (h) of the projectile is the vertical distance reached above the initial launch height.

To find the relation between R, h₁, and h₂, we can use the fact that the range of a projectile is related to its maximum height through a specific equation.

The equation relating the range, maximum height, and the acceleration due to gravity (g) is given by:

\(\begin{equation}R = \frac{2 v^2 \sin{\theta} \cos{\theta}}{g}\)

where:

R is the range,

v is the initial velocity of the projectile,

θ is the launch angle, and

g is the acceleration due to gravity.

Now, let's consider two projectiles with maximum heights h1 and h₂. For both projectiles, the range R is the same. Let's assume the initial velocities of the projectiles are v₁ and v₂, and the launch angles are θ₁ and θ₂, respectively.

Using the equation for range, we can write the following expressions for the ranges of the two projectiles:

\(R_1 = \frac{2 v_1^2 \sin{\theta_1} \cos{\theta_1}}{g} \\\\R_2 = \frac{2 v_2^2 \sin{\theta_2} \cos{\theta_2}}{g}\)

Since R₁ = R₂, we can equate the two expressions:

\(\frac{2 v_1^2 \sin{\theta_1} \cos{\theta_1}}{g} = \frac{2 v_2^2 \sin{\theta_2} \cos{\theta_2}}{g}\)

Canceling out the common factors and rearranging the equation, we get:

v₁² * sinθ₁ * cosθ₁ = v₂² * sinθ₂ * cosθ₂

From this equation, we can see that the product of the initial velocity squared and the sine of the launch angle and the cosine of the launch angle is the same for both projectiles. Therefore, we can conclude that the range of a projectile is the same when the maximum heights h₁ and h₂ satisfy the condition:

h₁ * cosθ₁ = h₂ * cosθ₂

This means that the product of the maximum height and the cosine of the launch angle is constant for projectiles with the same range.

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Answer:

24

Explanation:

If it took 3 hours to clean 6 houses than you can figure that is 2 houses per hours. so if there are 12 hours and 2 houses an hour, you multiply 12x2 and get 24. Another way to do it is to use proportions (aka two fractions that equal eachother):

  3 hours                12 hours

----------------    =    ---------------

 6 houses          number of houses

To calculate this, we can think about how we go from 3 to 12. Well, 3x4 is 12, so we got to 12 by doing multiplying by 4. So we can multiply 6 by 4 and you get 24.

Hope it helps! have a great day :)

Answer:dam hold up

Explanation:

Answer:

^ What he said

Explanation:

Peace out

Answer:

Natural gas was the largest source—about 40%—of U.S. electricity generation in 2020

Explanation:

hmmmmmmmmmmmmmmmmm ask someone else sorry if im not helping

Answer:

a. 26.7 cm. b. 11.4 cm.

Explanation:

a. We know h'/h = d'/d where h' = image height = + 2 cm (since it is a real image), h = object height = + 1.5 cm, d' = image distance from mirror and d = object distance from mirror = 20 cm

So, from h'/h = d'/d

d = h'd/h

= 2 cm × 20 cm/1.5 cm

= 40/1.5 cm

=  26.67 cm

≅ 26.7 cm

The position of the image is 26.7 cm from the mirror

b. Using the mirror formula

1/d + 1/d' = 1/f where d = object distance from mirror = + 20 cm, d' = image distance from mirror = + 26.7 cm (its positive since its a real image) and f = focal length of mirror.

So, 1/d + 1/d' = 1/f

⇒ f = dd'/(d + d')

= 20 cm × 26.7 cm/(20 cm + 26.7 cm)

= 534/46.7

= 11.43 cm

≅ 11.4 cm

The focal length of the mirror is 11.4 cm

Answer:

P.E = 2934.75

Explanation:

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

\( P.E = mgh\)

Where, P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Given the following data;

Weight =645

Height = 4.55

\( P.E = mgh\)

But we know that weight = mg = 645N

Substituting into the equation, we have;

\( P.E = 645 * 4.55 \)

\( P.E = 2934.75 J\)

Potential energy, P.E = 2934.75 Joules.

Considering the magnifications produced by the objective and eyepiece lenses, we get the overall magnification of the telescope as 0. The negative sign of focal length of eye piece indicates that the image formed by the objective lens is inverted.

The angular magnification of a refracting telescope is given by the ratio of the angles subtended by the object when viewed through the telescope and when viewed directly with the unaided eye. It is given by the formula:

m = -f_o / f_e

where m is the angular magnification, f_o is the focal length of the objective lens, and f_e is the focal length of the eyepiece.

In this case, the objective lens has a focal length of 13.8 m and the eyepiece has a focal length of 4.07 cm (0.0407 m). Substituting these values into the formula, we get:

m = -13.8 / 0.0407

m = -338.8

The negative sign in the answer indicates that the final image is inverted.

To describe the final image, we can use the thin lens equation:

1/f = 1/do + 1/di

where f is the focal length of the lens (either the objective or eyepiece), do is the object distance (i.e., the distance from the object to the lens), and di is the image distance (i.e., the distance from the lens to the image).

Using this equation, we can find the image distance and magnification for each lens, and then multiply them together to find the overall magnification of the telescope.

Starting with the objective lens, we have:

1/f_o = 1/do + 1/di_o

where do is the distance from the object to the objective lens (which is the same as the focal length of the objective lens, since the object is at infinity). Solving for di_o, we get:

di_o = f_o x do / (do - f_o)

di_o = 13.8 m x infinity / (infinity - 13.8 m)

di_o = -13.8 m

The negative sign indicates that the image formed by the objective lens is inverted. The magnification produced by the objective lens is:

m_o = -di_o / do

m_o = -(-13.8 m) / infinity

m_o = 0

Since the object is at infinity, the image produced by the objective lens is located at its focal point and has the same size as the object.

Next, we can use the image produced by the objective lens as the object for the eyepiece lens. The distance from the eyepiece lens to this object is equal to the focal length of the objective lens (13.8 m), and the image produced by the eyepiece lens is located at its focal point (since the object is at infinity). Thus, we have:

1/f_e = 1/do' + 1/di_e

where do' is the distance from the object (i.e., the image produced by the objective lens) to the eyepiece lens, and di_e is the distance from the eyepiece lens to the final image. Solving for di_e, we get:

di_e = f_e x do' / (do' - f_e)

di_e = 0.0407 m x (-13.8 m) / (-13.8 m - 0.0407 m)

di_e = 0.041 m

The magnification produced by the eyepiece lens is:

m_e = -di_e / do'

m_e = -0.041 m / (-13.8 m)

m_e = 0.003

Multiplying the magnifications produced by the objective and eyepiece lenses, we get the overall magnification of the telescope:

m = m_o x m_e

m = 0 x 0.003

m = 0

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Answer:

I need to talk to somone about my confusing love life

Explanation: