When blood is donated, sodium oxalate solution is used to precipitate Ca²⁺, which triggers clotting. A 104-mL sample of blood contains 9.7x10⁻⁵g Ca²⁺/mL . A technologist treats the sample with 100.0 mL of 0.1550 M Na₂C₂O₄. Calculate [ Ca²⁺ ] after the treatment. (See Appendix C for Ksp of CaC₂o₄.H₂O.)

Answer:

88 mL of water.

Explanation:

Data obtained from the question include the following:

Volume of alcohol = 12 mL

Percentage of alcohol = 12%

Volume of water =..?

We can thus, obtain the volume of water needed to make 12% of the alcohol solution as follow:

Percentage of the solution = 100%

Percentage of alcohol = 12%

Percentage of water =?

Percentage of water = percentage of solution – percentage of alcohol

Percentage of water = 100 – 12

Percentage of water = 88%

Since 12% of alcohol is equivalent to 12 mL of alcohol, therefore 88% of water will also be equivalent to 88 mL.

Therefore, 88 mL of water is needed to make 12% of alcohol.

Answer:

microbiology

Explanation:

1. The formula has too many H atoms bound to the right-most C atom.

Explanation:

Carbon atoms can only have four bonds. = means a double bond so there should only be 2 H atoms as two bonds are already taken up by the last Carbon.

"the number of ions produced by one formula unit of the electrolyte," refers to the van't Hoff factor (i) in an ideal solution of a strong electrolyte. It represents the extent of dissociation of the electrolyte into ions.

In an ideal solution of a strong electrolyte, the van't Hoff factor (i) represents the number of ions that are produced when one formula unit of the electrolyte dissociates completely in the solution. It is a measure of the extent of dissociation of the electrolyte.

For example, for a strong electrolyte such as sodium chloride (NaCl), when it dissolves in water, it completely dissociates into sodium ions (Na+) and chloride ions (Cl-). In this case, the van't Hoff factor (i) would be 2 because one formula unit of NaCl produces two ions (Na+ and Cl-).

Similarly, for other strong electrolytes, the van't Hoff factor (i) can be determined based on the number of ions produced per formula unit. It is important to note that for non-electrolytes or weak electrolytes, the van't Hoff factor (i) is typically less than 1, indicating partial dissociation or no dissociation in the solution.

learn more about ions here:

https://brainly.com/question/30663970

#SPJ11

Answer:

Principle of Original Horizontality

The relation between amino acids and polypeptide is that amino acid is monomer and polypeptide is polymer.

A member of the class of organic molecules known as amino acids, each of which is made up of a special organic R group, an acidic carboxyl group (COOH), a basic amino group (NH2), and an amino group (NH2) (or side chain). Alpha-amino [alpha-amino] carboxylic acid is the colloquial term for an amino acid. Every molecule has a central carbon (C), also known as the -carbon, that is attached to an amino group and a carboxyl group. Typically, a hydrogen (H) atom and a R group are used to fill the final two bonds of the -carbon atom. Standard (or common) amino acids can be divided into groups according to the polarity (i.e., the distribution of electric charge) of the R group (e.g., side chain).

To know more about amino acids visit : https://brainly.com/question/4686866

#SPJ4

The species would be an anuran (an amphibian)

We need to answer this in English.

Here we want to find "A species that mates on the surface and then deposits its eggs in the water to be surrounded by sperm"

This would be known as a species of amphibian called an anuran, specifically a frog or toad.

Frogs and toads belong to the order Anura and have a characteristic reproductive cycle that involves external fertilization. During reproduction, the male releases his sperm into the water, and the female deposits her eggs in the water as well. The eggs are externally fertilized by sperm that swim around them. This process is known as external or external fertilization.

Learn more about eggs:

https://brainly.com/question/1151355

#SPJ1

(a) The reaction with Delta H = 12.6 kJ/mol and Delta S = 93 J/K·mol is spontaneous at 25°C.

(b) The reaction with Delta H = 9.5 kJ/mol and Delta S = -94.0 J/K·mol is not spontaneous at 25°C.

To determine whether a reaction is spontaneous at a given temperature, we can use the Gibbs free energy equation: Delta G = Delta H - T·Delta S, where Delta G is the change in Gibbs free energy, Delta H is the change in enthalpy, Delta S is the change in entropy, and T is the temperature in Kelvin.

For a reaction to be spontaneous, Delta G must be negative. If Delta H is negative (exothermic) and Delta S is positive (increase in disorder), the reaction is more likely to be spontaneous.

(a) For the reaction with Delta H = 12.6 kJ/mol and Delta S = 93 J/K·mol, we have Delta G = 12.6 kJ/mol - (25 + 273) K·(93 J/K·mol/1000 J/kJ) = -5.25 kJ/mol. Since Delta G is negative, the reaction is spontaneous at 25°C.

(b) For the reaction with Delta H = 9.5 kJ/mol and Delta S = -94.0 J/K·mol, we have Delta G = 9.5 kJ/mol - (25 + 273) K·(-94.0 J/K·mol/1000 J/kJ) = 3.57 kJ/mol. Since Delta G is positive, the reaction is not spontaneous at 25°C.

To determine the minimum temperature at which a non-spontaneous reaction becomes spontaneous, we can set Delta G equal to zero and solve for T in the equation Delta G = Delta H - T·Delta S. However, in this case, both reactions are either spontaneous or non-spontaneous at 25°C, so we do not need to calculate the minimum temperature.

To know more about Gibbs free energy refer here:

https://brainly.com/question/29753420#

#SPJ11

The following options are correct for parts of measurement:

A number (magnitude) , An indication of uncertainty,  Aunit , A captive zero and A decimel place.

A quantitative observation or assessment of a physical quantity is referred to as a measurement. While taking a measurement, it's critical to explain the amount of the quantity as well as the degree of uncertainty associated with the measurement.

The following are the components of a measurement:

The value of the quantity being measured is represented by a number (magnitude). Based on the precision of the measurement device, it should be recorded to the appropriate number of significant numbers.

Uncertainty: This is a statement about how much the measurement is predicted to depart from the real value of the quantity. It may be stated in several ways, including absolute error, relative error, and confidence interval.

A unit is the unit of measurement for the quantity being measured. To minimise ambiguity or confusion, it is critical to provide the unit.

At least one notable figure: A measurement should always include at least one significant figure, which is the first non-zero digit in the reported number. The number of significant numbers should represent the measuring instrument's accuracy and the degree of uncertainty in the measurement.

A decimal place: Depending on the magnitude and quality of the measuring device, a measurement may or may not have a decimal place.

A captive zero: A captive zero is a zero that appears between major digits in a measurement. It is not significant in and of itself, however it aids in displaying the decimal point location and the number of significant digits.

For more such questions on measurement, click on:

https://brainly.com/question/28771966

#SPJ4

Answer

383.42 mL

Explanation

Given:

Mass of the empty beaker = 26.33 g

Total mass (filled with water and contents) = 409.75 g

Density of water = 1.00 g/mL

What to find:

The volume that the beaker holds.

Step-by-step solution:

The volume that the beaker holds will be equal to the volume of water in the beaker.

Mass of water = Total mass - Mass of empty beaker

Mass of water = 409.75 g - 26.33 g

Mass of water = 383.42 g

Since Density = Mass/Volume, then

Volume = Mass/Density

Putting mass = 383.42 g and density = 1.00 g/mL

Volume = 383.42 g/1.00 g/mL

Volume = 383.42 mL

Hence, the volume that the beaker holds is 383.42 L

We know the standard reduction potentials of the half-cells involved, so we can find the cell voltage and the spontaneous reaction. Thus;

The anode reaction is:

Pb(s) → Pb2+(aq) + 2e-

This is the oxidation half-reaction that occurs in the Pb half-cell.

The cathode reaction is:F2(g) + 2e- → 2F-(aq).

This is the reduction half-reaction that occurs in the F2 half-cell.

The spontaneous cell reaction is

:Pb(s) + F2(g) → Pb2+(aq) + 2F-(aq).

This is the combination of the oxidation and reduction half-reactions, with the electrons canceled out from both sides.

The cell voltage is 2.996 V The standard cell potential is calculated as follows:

standard cell potential = E°(reduction) - E°(oxidation)standard cell potential = 2.870 V - (-0.126 V)standard cell potential = 2.996 V, The cell voltage is positive, indicating that the reaction is spontaneous.

To know more about oxidation half-reaction visit;

https://brainly.com/question/12686471

#SPJ11

Answer:

Ammonium dichromate is an inorganic compound with the formula (NH₄)₂Cr₂O₇. In this compound, as in all chromates and dichromates, chromium is in a +6 oxidation state, commonly known as hexavalent chromium. It is a salt consisting of ammonium ions and dichromateions

Explanation:

Answer:

6 moles

Explanation:

3 moles of O2 produce 2 moles of Al2O3 so in order to produce 4 moles pf AL2O3 you need 4 x 3 /2 moles of O.

Answer:

2.775 g

Explanation:

Given that;

Number of moles = concentration × volume

Concentration = 0.10M

Volume =250 mL

Number of moles = 250/1000 × 0.10

Number of moles = 0.025 moles

Also;

Number of moles = mass/molar mass

Molar mass of CaCl2= 111 g/mol

Mass = Number of moles × molar mass

Mass = 0.025 moles × 111 g/mol

Mass= 2.775 g

Answer:

7. Chemical

8. Chemical

9. Physical

10. Physical

11. Physical

12. Physical

Explanation:

The chemical equilibrium is also dynamic just like the physical equilibrium. Among the given conditions, the reaction is irreversible is not a condition for dynamic equilibrium. The correct option is C.

The chemical equilibrium is dynamic in nature. The observable properties of the system like pressure, concentration, colour, etc. become constant at equilibrium and remain unchanged thereafter.

It is in chemical equilibrium the rate of forward reaction becomes equal to the rate of reverse reaction (reversible). The chemical equilibrium can be attained only if the system is a closed one.

Thus the correct option is C.

To know more about chemical equilibrium, visit;

https://brainly.com/question/12920261

#SPJ1

Your question is incomplete, but most probably your full question was:

Which of these is NOT a condition for dynamic equilibrium?

A. The rate of the forward is constant

B. The concentration changes

C. The reaction is irreversible

D. The reaction must be reversible (Can go forward and backward)

Answer:

Rods

Explanation:

Rods are photoreceptor cells in the eye that help us see in low light but play little to no role in color vision. Therefore, they would help Phineas to see shades of grey and large shapes in the dark,

Answer:

rods

Explanation:

Answer:

hola no ablo inglés porfavor

Answer:

dicot

Explanation:

I looked it up lmoooo

Answer:

D

Explanation:

The electrons revolve around the nucleus and they contain negative charge

The electrons that should be outer of the nucleus also contains the negative charge should represent the location & electrons charge in the atom.

The following information should be considered:

Therefore we can conclude that the electrons that should be outer of the nucleus also contains the negative charge should represent the location & electrons charge in the atom.

Learn more about the atom here: brainly.com/question/1641336

Explanation

NH4Cl(s) = NH4+(aq) + Cl-(aq) AH = +3.5 kcal/mole

We have some changes that shift the equilibrium to the right, according to Le Châtelier's principle.

I will write some of them:

By Adding amount of NH4Cl or by increasing the temperature because according to the heat of the reaction this is an endothermic reaction.

Answer: Increasing the temperature of the system.

Answer:

It should be 28 degrees C

Explanation:

Answer:

28°C

Explanation:

Answer:

Cold fronts can produce dramatic changes in the weather.  

Explanation: They move fast, up to twice as fast as a warm front. As a cold front moves into an area, the heavier (more dense) cool air pushes under the lighter (less dense) warm air, causing it to rise up into the troposphere.

Answer:

the person above is correct

Explanation:

just to confirm it

hope th8s helps!

have a good day :)

Answer:

Ok 15 miles NO2 you need the salt and pepper trick so mix it add water sit in it when you get cold write down uh temperature then you need to get out or it may kill you when it starts to get cold then go to the y- axis then you need to ask your teacher for help after you do the y-axis

The rubidium ion has the same electron structure as a krypton atom because they have the same number of electrons.

The rate of diffusion of the bromine is 0.158 that of helium according to the calculation here. Option C

We know that the term diffusion as to do with the movement of the molecules of a gas from one point to the other. By the use of the Graham's law, we know that the ratio of the rate of diffusion of the gases is inversely proportional to the molar masses of the gases.

We can then write that;

\(R_{1} /R_{2} = \sqrt{M2} /M_{1}\)

\(R_{1}\) = Rate of diffusion of helium

\(R_{2}\) = Rate of diffusion of bromine

\(M_{2}\) = Molar mass of helium

\(M_{1}\) = Molar mass of bromine

Then;

\(R_{1}\) /  \(R_{2}\)  = √4/160

= 0.158

Bromine then effuses 0.158 as fast as helium.

Learn more about rate of diffusion:https://brainly.com/question/29302841

#SPJ1

Answer:

animals

Explanation:

I think I remember this from a quiz I took so exotic species

The highest oxidation state for Nb (niobium) is +5.

Oxidation is the loss of electrons in a chemical reaction. For the element niobium (Nb), the highest oxidation state is +5. This is because niobium has five valence electrons in its outermost shell, which it can lose to form a +5 oxidation state.

This is commonly seen in compounds such as Nb₂O₅ (niobium pentoxide) and NbF₅ (niobium pentafluoride). That being said, it is important to note that niobium can also form lower oxidation states, such as oxidation state +3 and +4. However, the +5 state is the highest possible for niobium.

Learn more about oxidation at https://brainly.com/question/25886015

#SPJ11