When an object did not move (zero distance) how does the graph look?
the line is diagonal and decreasing
the line is vertical and sharply increasing
the line is horizontal and flat
the line is diagonal and increasing
Answers
Answer: c
Explanation: edpuzzel
Related Questions
Which one of the following ions outside the neuron would make it very difficult for a depolarization to occur? a) chloride. b) sodium. c) potassium. d) manganese.
Answers
Chloride ions outside the neuron would make it very difficult for a depolarization to occur.
In a normal resting state, the internal environment of a neuron has a net negative charge compared to the external environment.
This is known as the resting potential. During depolarization, this membrane potential switches from negative to positive very rapidly due to an influx of positively-charged cations (such as sodium) into the cell.
To interfere with this process, the ions outside of the neuron would have to shift the normal resting state so that the internal environment of the cell no longer has a net negative charge.
This will prevent the influx of cations that will cause depolarization. In order to do this, we would need to balance out the negative charge inside the cell with negative charge outside of the cell. In the list of options, chloride is the only negatively-charged ion. Therefore, the answer would be Chloride.
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A 1200 mL IV drip is labeled to contain 12% of a laxative. Find the number of mL of the IV drip that should be administered if a patient is to receive 21 mL of the laxative.
Answers
A 1200 mL IV drip is labelled to contain 12% of a laxative. The number of mL of the IV drip that should be administered if a patient is to receive 21 mL of the laxative is 175 mL.
To find the number of mL of the IV drip that should be administered to provide 21 mL of the laxative, we can set up a proportion using the concentration of the laxative.
Let x represent the number of mL of the IV drip to be administered.
The concentration of the laxative is given as 12% or 0.12, meaning that in 100 mL of the IV drip, there are 12 mL of the laxative.
Using the proportion:
(12 mL of laxative) / (100 mL of IV drip) = (21 mL of laxative) / (x mL of IV drip)
Cross-multiplying, we get:
12 mL * x mL of IV drip = 100 mL * 21 mL of laxative
12x = 210 IV drip0
Dividing both sides by 12:
x = 2100 / 12
x = 175
Therefore, 175 mL of the IV drip should be administered to provide 21 mL of the laxative.
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Is the copper in a copper wire a homogeneous or heterogeneous mixture
Answers
If you calculated 41.34 + 1.561 + 0.1334, how many significant figures would be in the answer?
3
4
5
6
Answers
Answer: 4
Explanation:
When adding or subtracting numbers, you round your answer to the least amount of decimal places present in any of the numbers you add.
When multiplying or dividing numbers, you round your answer to the least amount of significant figures present in any of the number you multiply or divide.
Since we are adding 41.34, 1.561, and 0.1334, we will round our answer to 2 decimal places since that is the least amount present.
After rounding, our answer is 43.03, which is 4 significant figures.
Answer:
4
Explanation:
I got it right on the test.
The diagram shows the cycling of matter in the interior of Earth.
Which statement correctly explains the cycling of matter in the interior of Earth?
Responses
The heat from Earth’s core causes material in the area under the crust to become less dense and rise, while more dense material sinks.
The heat from Earth’s core causes material in the area under the crust to become less dense and rise, while more dense material sinks.
The heat from Earth’s core causes material in the area under the crust to become more dense and rise, while less dense material sinks.
The heat from Earth’s core causes material in the area under the crust to become more dense and rise, while less dense material sinks.
The heat from Earth’s core causes material in the area under the crust to become less dense and sink, while more dense material rises.
The heat from Earth’s core causes material in the area under the crust to become less dense and sink, while more dense material rises.
The heat from Earth’s core causes material in the area under the crust to become more dense and sink, while less dense material rises.
The heat from Earth’s core causes material in the area under the crust to become more dense and sink, while less dense material rises.
Answers
Answer:
Explanation:
I think 'The heat from Earth's core causes material in the area under the crust to become denser and rinse, while less dense material sinks.
Calculate the volume of a clear liquid that has a mass of 20 g and a density of 15.77 g/mL.
Answers
Answer:
20 g g/mL. 15.77
Explanation:
i think i answer it
Which statements describe a ideal gas select all correct answers
Answers
The correct options that describes the behaviour of ideal gases are options B, E and F.
What is ideal gas ?An ideal gas is those which obeys Boyle, law, Charles's law and Avogadro's law at all temperatures and pressure.
Kinetic theory of gases is proposed for these ideal gases. According to Kinetic theory of gases, particles will collide each other when they gains energy.
Particles gains kinetic energy when they move apart and collide on the wall of the container or with each other. This kinetic energy will increase as the temperature increases.
The volume of gas doesn't affect its behavior because the volume surrounding the particle is insignificant with respect to the size of the particles.
For ideal gases, there will be no repulsion between particles and only attractive force exists. Hence, based on these concepts option B, E and F are correct.
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Your question is incomplete. But your complete question probably was as follows:
Which statements describe an ideal gas?
Select all the correct answers.
A. The average energy of the particles changes as collisions occur.
B. The particles are in constant motion.
C. Particles both attract and repel each other.
E. The average energy of the particles depends on the temperature.
F. The volume of the particles doesn't affect the behavior of the gas.
why didn’t we use the dichromate peak at 370 nm to determine the cr concentration
Answers
The dichromate peak at 370 nm cannot be used to determine the Cr concentration because it is an oxidizing agent. The oxidizing agent forms a complex with the Cr that is not measured in the sample, thus making it an unreliable measure of the Cr concentration.
The reason we did not use the dichromate peak at 370 nm to determine the Cr concentration is because the peak is too close to the UV region and the absorbance is too low for accurate measurement.
In UV-Vis spectroscopy, the absorbance of a compound is measured at different wavelengths to determine its concentration. However, the absorbance of a compound is dependent on the wavelength of the light used. At shorter wavelengths, such as those in the UV region, the absorbance is generally lower and less accurate.
The dichromate peak at 370 nm is too close to the UV region, which means that the absorbance at this wavelength is likely to be low and less accurate. Therefore, it is not a good choice for determining the Cr concentration. Instead, it is better to use a peak with a higher absorbance, such as the one at 440 nm, which is further away from the UV region and will provide a more accurate measurement.
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First DEFINE and THEN Compare and contrast the three states of matter. Draw a picture on the
molecular level for each.
Answers
There are mainly three types of state of matter and they solid, liquid as well as gas. Gas molecule has no any attraction force on the other hand solid molecule has strong attraction force.
There are four different states of matter: solids, liquids, gases, as well as plasma. Adding or subtracting heat energy from a substance can frequently modify the state of matter in that substance. For instance, adding heat may cause ice to melt into liquid water as well as water to scald.
A condition of a substance known as gas entirely conforms to the form of the container it is placed in despite having no shape of its own. Solids have a defined shape as well as volume, whereas liquids just have a defined volume as well as no shape, and gases lack both shape and volume.
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why is edta used to determine the hardness of water
Answers
EDTA (ethylenediaminetetraacetic acid) is commonly used to determine the hardness of water due to its ability to form complexes with metal ions, particularly calcium and magnesium ions.
Water hardness refers to the concentration of calcium and magnesium ions present in water. These ions can cause scaling, reduce the effectiveness of soaps, and have other negative effects. EDTA acts as a chelating agent, meaning it can bind to metal ions and form stable complexes.
In the process of determining water hardness, a known amount of EDTA solution is added to a water sample. The EDTA molecules form complexes with the calcium and magnesium ions present in the water.
The endpoint of the titration is reached when all the metal ions are complexed by the EDTA, resulting in a color change or an indicator reaching a specific endpoint.
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Hydrogen gas was collected in a burette in a water bath with a water height difference of 15. 0 cm. Please calculate the pressure in the burette if the atmospheric pressure in the room at that time was 765. 0 torr.
Answers
The pressure in the burette if the atmospheric pressure in the room at that time was 765.0 torr is 915 torr
How do I determine the pressure in the burette?The pressure in the burette can be obtained by using the following formula:
Pressure of gas = Atmospheric presure + pressure due to height
With the above formula, we can determine the pressure in the burette. This is illustrated below:
Pressure due to height = 15 cmHg = 150 mmHg = 150 torrAtmospheric pressure = 765.0 torrPressure in burette =?Pressure in burette = Atmospheric presure + pressure due to height
Pressure in burette = 765.0 + 150
Pressure in burette = 915 torr
Thus, the pressure in burette is 915 torr
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What pressure must be applied to a sample of Neon gas having a volume of 325cm3 at 20 degree Celsius and 723mmHg to permit the expansion of the gas to a volume of 975cm3 at the same temperature
Answers
To solve this problem, we can use the combined gas law equation: P₁V₁/T₁ = P₂V₂/T₂
Where P₁, V₁, and T₁ are the initial pressure, volume, and temperature, and P₂, V₂, and T₂ are the final pressure, volume, and temperature. We are given V₁ = 325 cm³, T₁ = 20°C = 293 K, P₁ = 723 mmHg, and V₂ = 975 cm³ at the same temperature T₂ = 293 K. We need to find P₂. First, we need to convert the initial pressure from mmHg to atm: P₁ = 723 mmHg × 1 atm/760 mmHg = 0.9513 atm. Now we can plug in the values and solve for P₂: P₁V₁/T₁ = P₂V₂/T₂. 0.9513 atm × 325 cm³/293 K = P₂ × 975 cm³/293 K. P₂ = 0.9513 atm × 325 cm³ × 293 K / (975 cm³ × 293 K). P₂ = 0.3164 atm. Therefore, the pressure that must be applied to the neon gas to permit its expansion to a volume of 975 cm³ is approximately 0.3164 atm.
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What concentration of the barium ion, ba2 , must be exceeded to precipitate baf2 from a solution that is 1. 00×10−2 m in the fluoride ion, f−? ksp for barium fluoride is 2. 45×10−5
Answers
The amount of barium ions that must be present in order for the salt to precipitate is 0.245 M.
A solution's solubility product is the result of raising each ion's concentration to the power of its stoichiometric ratio. It is portrayed as
A combination of 1 barium ion and 2 fluoride ions results in the ionic compound known as barium fluoride.
The following equation describes the equilibrium reaction for barium fluoride ionization:
BaF₂ → Ba²⁺ + 2F⁻
Ksp = [Ba²⁺] · [F⁻]²
2.45*\(10^{-5}\)= [Ba²⁺] * \([1. 00*10^{-2} ]^{2}\)
[Ba²⁺]=0.245 M
As a result, 0.245 M of barium ions must be present in order for the salt to precipitate.
SolubilitySolubility in chemistry refers to a chemical's capacity to dissolve in another substance, the solvent, to produce a solution. Inability of the solute to create such a solution is the opposite quality, or insolubility. A substance's degree of solubility in a given solvent is often determined by the amount of the solute present in a saturated solution, which is a solution in which no additional solute can be dissolved. The solubility equilibrium between the two compounds is considered to have been reached at this time. If there is no such restriction for a given solute and solvent, the two are referred to as being "miscible in any amounts."
What concentration of the barium ion, ba2 , must be exceeded to precipitate baf2 from a solution that is 1. 00×10−2 m in the fluoride ion, f−? ksp for barium fluoride is 2. 45×10−5
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Planets that orbit farther away from the Sun than Earth have ____ years than we do.
Answers
4. 100g of 4°C water is heated until its temperature is 37°C. If the specific heat of water is 4.18J/g °C,
calculate the amount of heat energy needed to cause this rise in temperature.
Answers
The amount of heat energy needed to cause this rise in temperature=13.794 kJ
Given :Weight m = 100 g
T = 37 - 4 = 33 C is the temperature difference.
Specific heat is 4.18 J per g of carbon.
We must discover heat energy. The following is what we know:
Q = m c Δ T
Putting values here we get :
Q = ( 100 × 4.18 × 33 ) J
= > Q = ( 418 × 33 ) J
= > Q = 13794 J
= > Q = 13.794 kJ
How does C have specific heat?Specific heat capacity (symbol: c) in SI units is the quantity of heat in joules needed to elevate 1 gram of a substance by 1 Kelvin. J/kgK is another way to put it. Specific heat capacity can also be expressed in terms of calories per gram of temperature change.
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What are the units for the rate constant of a reaction with the rate law, Rate = k[A[B]? A) S⁻¹ B) MS⁻¹ C) M⁻¹s⁻¹ D) M⁻² s⁻¹
E) SM⁻¹
Answers
The units for the rate constant of a reaction with the rate law, Rate = k[A][B], are given by M⁻¹s⁻¹.
In the rate law equation, Rate = k[A][B], the rate constant (k) represents the proportionality constant that relates the concentrations of reactants ([A] and [B]) to the rate of the reaction. The rate constant depends on the specific reaction and is determined experimentally.
To determine the units of the rate constant, we need to analyze the units of the rate and the concentrations of the reactants. In the given rate law equation, the rate is expressed in terms of concentration per unit time (M/s or mol/(L·s)).
The concentration of reactant A is represented by [A], which has units of M (molarity) or mol/L. Similarly, the concentration of reactant B is represented by [B] and also has units of M or mol/L.
By substituting the units into the rate law equation, we can deduce the units of the rate constant. The rate is given in M/s, and the concentrations [A] and [B] are in M. Therefore, the units of the rate constant k must cancel out the units of concentration, resulting in M⁻¹, and also account for the unit of time, which is s⁻¹.
Therefore, the correct answer for the units of the rate constant of a reaction with the given rate law is M⁻¹s⁻¹, which corresponds to option C.
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How did water form the Grand Canyon?.
Answers
Flowing water from the Rocky Mountains formed the mighty Colorado River. As the plateau rose, rivers cut through it, carving canyons over time.
When water freezes it expands into ice. Ice widens cracks and erodes rock in the process. During short periods of heavy rain, water rolls down cracks and erodes more rocks and stones. The canyon becomes wider at the top than at the bottom as more rock is eroded away.
The Grand Canyon is perhaps the best example of a water-sculpted canyon. Water exerts tremendous erosive power, especially when carrying large amounts of sediment and rocks, as the Colorado River does during floods. The Grand Canyon is a large deep river canyon in northwest Arizona. Water was the main cause of the erosion that formed the Grand Canyon.
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What types of R groups can exist in amino acids? (Choose all that apply)
Acidic
Non-polar
Basic
Polar
Answers
Answer:
acidic,non polar,basic
Explanation:
that’s the ones I put and I got a 100% on my test just now
The types of R groups that can exist in amino acids include acidic, non-polar, basic, and polar groups.
1. Acidic R groups: These groups have a negative charge and can donate a proton (H+). An example of an amino acid with an acidic R group is aspartic acid (Asp) or glutamic acid (Glu).
2. Non-polar R groups: These groups are hydrophobic and do not have a charge. They are composed mainly of carbon and hydrogen atoms. Examples of amino acids with non-polar R groups include alanine (Ala), valine (Val), and phenylalanine (Phe).
3. Basic R groups: These groups have a positive charge and can accept a proton. An example of an amino acid with a basic R group is lysine (Lys) or arginine (Arg).
4. Polar R groups: These groups are hydrophilic and have a partial charge. They can form hydrogen bonds with other polar molecules. Examples of amino acids with polar R groups include serine (Ser), threonine (Thr), and asparagine (Asn).
Thus, types of R groups that can exist in amino acids include acidic, non-polar, basic, and polar groups.
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Why does the emission of an alpha particle always result in transmutation? (1 point)
O The number of protons in the atom changes.
O The atom is converted to helium.
O Energy is released from the nucleus of the atom.
O The protons in the large atom change to neutrons.
Answers
The emission of an alpha particle always result in transmutation because the number of protons in the atom changes.
What is an alpha particle and does emission of an alpha particle always result in transmutation?Alpha particle is a particle consisting of two protons and two neutrons and is often called similar to a helium-4 nucleus.Generally alpha particle is released during an alpha decay but not necessarily, as it can be produced in other ways too.Here the emission of particle is resulting in transmutation because not of the number of protons in the atom is changing.Also not because of the atom is converted to helium , alpha particle is similar to helium in protons and neutrons.Hence the emission of an alpha particle always result in transmutation because the number of protons in an atom changes.To know more about alpha particle visit:
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Calculate the number of moles in 0.48 g of Cu.
Answers
1) Convert grams to moles
The molar mass of Cu is 63.546 g/mol.
\(molCu=0.48gCu\cdot\frac{1molCu_{}}{63.546gCu_{}}_{}=0.007553molCu\)0.007553 mol of Cu is equal to 7.6*10^-3 mol of Cu.
.
is the statement ""the values for cl− wet deposition were greater during the winter and early spring when road salt is typically applied"" supported by the results of study 2 ?
Answers
The conclusions or discussions presented in study 2 regarding the relationship between Cl- wet deposition and seasonal variations.
To determine if the statement is supported by the results of study 2, we need to follow a step-by-step process:
Obtain the results of study 2: Obtain the research paper or report detailing the results of study 2.
Identify the variables and data: Look for data related to Cl- wet deposition and its values during different seasons, specifically winter and early spring.
Analyze the data: Examine the data to see if it provides information on Cl- wet deposition values during different seasons.
Compare the values: Compare the Cl- wet deposition values during the winter and early spring to values from other seasons (e.g., summer, autumn) to determine if there is a notable difference.
Consider the findings: Review the conclusions or discussions presented in study 2 regarding the relationship between Cl- wet deposition and seasonal variations.
Check if the study supports the statement that Cl- wet deposition values are greater during the winter and early spring.
Evaluate the evidence: Assess the strength of the evidence provided by study 2. Consider factors such as sample size, statistical significance, and any limitations or potential biases.
Formulate a conclusion: Based on the analysis of the data and findings in study 2, determine if the statement is supported or not.
Without access to the specific results and findings of study 2, it is not possible to provide a definitive answer.
It is essential to consult the actual study and evaluate the evidence within its context to determine if the statement is supported.
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Please answer the following question using the data below: H2O vapor content: 13 grams H2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10 ∘
C 52 grams at 30 ∘
C What is the dew point for the conditions listed above? LCL 3π5 25C Relative Humidity =100%
Answers
Given data:H2O vapor content: 13 gramsH2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10∘C52 grams at 30∘CFormula used to find the dew point:$$\dfrac{13}{52}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$\frac{1}{4}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$
Where A is the constantDew Point:It is the temperature at which air becomes saturated with water vapor when the temperature drops to a point where dew, frost or ice forms. To solve this question, substitute the given data into the formula.$$13/52=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$13(17.27-A)=3\pi A(ln100)$$By simplifying the above expression, we get$$A^2-17.27A+64.78=0$$Using the quadratic formula, we get$$A=9.9,7.4$$
The dew point is 7.4 since it is less than 10°C.More than 100:The term "More than 100" has not been used in the question provided.
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How many atoms of carbon are present in 1.5 mole of carbon.
Answers
Answer:
there is one carbon atom and there are two oxygen atoms. So, in total there are three atoms.
Explanation:
Lewis dot structures are models used to show what type of subatomic particle of an
atom?
Answers
Answer: Lewis dot structures are models used to valence electrons.
Explanation:
Lewis dot structures are the structures which represent the valence electrons of the element around the chemical symbol of the element.
For example : Flourine is an element which belong to group 17 and is a halogen. Atomic number of fluorine is 9 that means it contains 9 electrons, Thus the electronic configuration is represented as:
\(1s^22s^22p^5\)
Thus the valence electrons are 7. Thus 7 electrons are represented around chemical symbol of Flourine i.e. F
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What type of circuit does this figure represent?
an open series circuit
an open parallel circuit
a closed parallel circuit
a closed series circuit
Electricity and magnetism
Answers
Answer:
a closed series circuit
Answer:
An open series circuit
Explanation:
I'm late but for future people...
I took the test.
Mixtures can be separated by chemical/physical change.
Answers
a litre container holds hydrogen gas. an electric discharge is applied to the gas, resulting in the dissociation of some of the h2 to h. after the discharge, the system is at 1.1 atm, 298 k, and the mole fraction of h is 5%. assuming that the only final product in the system is h2, what is the final system temperature and pressure? you may assume constant specific heat. properties at 298 k and 1 atm:
Answers
Q is the heat transferred, m is the mass, C is the specific
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Since we are given the pressure and temperature of the system, we need to find the volume and number of moles of gas.
First, we can find the number of moles of hydrogen that dissociates from the H₂ gas. If the mole fraction of H is 5%, then the mole fraction of H₂ is 95%. Let's assume we start with 1 mole of H₂ . Then, we have:
0.05 moles of H
0.95 moles of H2
Some of the H₂ gas dissociates to H, so let's say x moles of H₂ dissociate. Then, we have:
(0.05 + x) moles of H
(0.95 - x) moles of H₂
Since we are assuming that the only final product is H₂, we know that all of the H atoms will recombine to form H₂:
(0.05 + x - 2x) moles of H₂
(0.95 - x) moles of H2
Simplifying this, we get:
(0.05 - x) moles of H₂
(0.95 - x) moles of H₂
Since we started with 1 mole of H₂, we know that the total number of moles is:
(0.05 - x) + (0.95 - x) = 1 - 2x
Now, we can use the ideal gas law to find the volume of gas at the final pressure and temperature. Since we know the number of moles of gas and the temperature, we just need to find the volume. We can rearrange the ideal gas law to get:
V = (nRT)/P
At 298 K and 1 atm, the gas constant R is 0.08206 L·atm/(mol·K). So, for the initial conditions, we have:
V_initial = (1 mol * 0.08206 L·atm/(mol·K) * 298 K) / 1 atm = 24.4658 L
Now, we can use the mole fractions and the number of moles to find the final volume of gas. We have:
(0.05 - x) moles of H₂
(0.95 - x) moles of H₂
The total number of moles is 1 - 2x, so we have:
(0.05 - x)/(1 - 2x) moles of H₂
(0.95 - x)/(1 - 2x) moles of H₂
Using the ideal gas law again, we can find the final volume:
V final = [(0.05 - x)/(1 - 2x) + (0.95 - x)/(1 - 2x)] * (0.08206 L·atm/(mol·K) * T) / 1.1 atm
Simplifying this, we get:
V final = [1 - 2x] * (0.08206 L·atm/(mol·K) * T) / (1.1 atm)
Now, we need to use the fact that the specific heat is constant to find the final temperature. We can use the formula:
Q = mCΔT
where Q is the heat transferred, m is the mass, C is the specific
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label any polar bonds on the indigo dye bond and identify the 2 central atoms with different geometry and identify it
Answers
The N - H and the C- O and the C- N bonds in indigo dye are polar on nature.
What are the polar bonds in indigo dye?Indigo is a blue dye that is derived from the leaves of certain plants. The chemical structure of indigo consists of two benzene rings connected by a nitrogen atom. The molecule has several polar bonds due to the electronegativity differences between the atoms.
The polar bonds in indigo include:
The nitrogen-carbon bonds: The nitrogen atom in the middle of the molecule is connected to two carbon atoms, one in each benzene ring. Nitrogen is more electronegative than carbon, so the nitrogen-carbon bonds are polar.
The carbon-oxygen bonds: Indigo has two oxygen atoms that are double bonded to carbon atoms in the benzene rings. Oxygen is more electronegative than carbon, so the carbon-oxygen bonds are also polar.
The carbon-nitrogen bond: The nitrogen atom in the middle of the molecule is also connected to a carbon atom in one of the benzene rings. This bond is polar due to the electronegativity difference between carbon and nitrogen.
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Which element has a greater atomic radius Mg or Cl?
Answers
Balance the equation in the space below for the reaction of ammonia and oxygen, using the smallest whole number coefficients
NH₂(g) + O₂(g) → N₂(g) + H₂O(g) + energy
Answers
The balanced equation of the reaction is:
2 NH₂(g) + O₂(g) → N₂(g) + 2 H₂O(g) + energy What is a balanced equation of a reaction?A balanced equation is an equation of a reaction in which the moles of atoms of elements in the reaction are equal on both sides of the equation.
The given equation can be balanced as follows:
2 NH₂(g) + O₂(g) → N₂(g) + 2 H₂O(g) + energy
Therefore, the balanced equation of the reaction is the one in which the moles atoms of reacting elements are equal.
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