when 36.8 l of carbon monoxide reascvts with 4.9 l of oxygen gas at stp, what is the quantity of heat released to the surroundings

Answers

Answer 1

The amount of heat released is 105.41 kJ which is calculated by determining the limiting reactant.

The complete chemical reaction is:

2CO(g)+O2(g)---> 2CO2(g)

Volume of CO= 36.8 L

Mole of CO= 1/22.4 Lx 36.8 L=1.6428 moles

Volume of O2= 4.9 L

Mole of O2=1/22.4 Lx 4.9 L=0.2187 moles

The formation of products is dependent on the number of reactants. The reactant that is consumed first is known as the limiting reactant, when this reactant is consumed completely, then there will be no more formation of products.

The limiting reactant is found out by dividing with stoichiometry coefficients.

CO= 1.6428/2=0.8214

O2=0.2187/1=0.2187

Therefore, the limiting reactant is O2.

If 1 moles of O2 produce 482 kJ heat.

Then, 0.2187 of O2 will produce 4.82x0.2187=105.41 kJ heat.

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Related Questions

a pure lc circuit has an angular frequency of oscillation ω. if both l and c are doubled, what is the new angular frequency of oscillation?

Answers

when both L and C are doubled, the new angular frequency of oscillation is half of the original angular frequency.

In a pure LC circuit, the angular frequency of oscillation (ω) is given by the formula:
ω =\frac{1}{\sqrt{(LC)}}
Where L is the inductance and C is the capacitance.
Now, you've mentioned that both L and C are doubled. So, the new values of L and C will be:
L_new = 2L
C_new = 2C
Let's find the new angular frequency of oscillation (ω_new) using the same formula:
ω_new =\frac{ 1}{\sqrt(L_new * C_new)}
Substitute the new values of L and C:
ω_new = \frac{1}{\sqrt((2L) * (2C))}
Factor out the constant 2 from the square root:
ω_new = \frac{1}{\sqrt(4 * LC)}
Since √4 = 2, we can rewrite the equation as:
ω_new =\frac{ 1}{(2 * \sqrt(LC))}
Recall that the original angular frequency (ω) is given by:
ω =\frac{ 1}{\sqrt(LC)}
Comparing both equations, we find:
ω_new = ω/2

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when both L and C are doubled, the new angular frequency of oscillation is half of the original angular frequency.

In a pure LC circuit, the angular frequency of oscillation (ω) is given by the formula:
ω =\frac{1}{\sqrt{(LC)}}
Where L is the inductance and C is the capacitance.
Now, you've mentioned that both L and C are doubled. So, the new values of L and C will be:
L_new = 2L
C_new = 2C
Let's find the new angular frequency of oscillation (ω_new) using the same formula:
ω_new =\frac{ 1}{\sqrt(L_new * C_new)}
Substitute the new values of L and C:
ω_new = \frac{1}{\sqrt((2L) * (2C))}
Factor out the constant 2 from the square root:
ω_new = \frac{1}{\sqrt(4 * LC)}
Since √4 = 2, we can rewrite the equation as:
ω_new =\frac{ 1}{(2 * \sqrt(LC))}
Recall that the original angular frequency (ω) is given by:
ω =\frac{ 1}{\sqrt(LC)}
Comparing both equations, we find:
ω_new = ω/2

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A researcher investigated different combinations of temperature and humidity to examine how heat affects performance. The researcher compared three temperature conditions (70°,80°, and 90°) with a high humidity and a low humidity condition for each temperature. A separate group of participants was tested in each of the 6 different conditions, and for each participant, the researcher recorded the number of errors made on a problem-solving task.

Independent Variable (IV): ________________________________
Dependent Variable (DV): ________________________________
Control Group: _________________________________
Constants: _____________________________

Answers

Independent Variable IV is atmospheric temperature, Dependent Variable (DV) are 70°,80°, and 90° , Control Group are  researchers and Constants are humidity and temperature.

what is atmospheric temperature?

Atmospheric temperature is a measurement of temperature at different and various levels of the Earth's atmosphere and above it.

It is effected by many factors, including incoming solar rays, and the humidity and how far from the sea level.

Therefore, Independent Variable IV is atmospheric temperature, Dependent Variable (DV) are 70°,80°, and 90° , Control Group are  researchers and Constants are humidity and temperature.

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A sphere of radius 0.457 m, temperature 32.2 ∘
C, and emissivity 0.924 is located in an environment of temperature 82.9 ∘
C. At what rate does the sphere (a) emit and (b) absorb thermal radiation? (c) What is the sphere's net rate of energy exchange? (a) Number (b) Number Units Units

Answers

a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

What are the rates of thermal radiation emission, absorption, and net energy exchange for the sphere?

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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What was the ball's average speed during the time represented on the graph?
A) 0.2 m/s
B) 0.5 m/s
C) 5.0 m/s
D) 10.0 m/s

What was the ball's average speed during the time represented on the graph?A) 0.2 m/sB) 0.5 m/sC) 5.0

Answers

Answer:

Explanation:

0.5 i go to k12 i jus took the test

Answer:

0.5

Explanation:

took the test

Ethyl alcohol has a density of 0.80 g/mL. What is the volume of 44g of ethyl alcohol
ANSWER CHOICES
55 mL
35 mL
42 mL
0.80 mL

Answers

Answer:

55mL

Explanation:

44g / 0.8g/mL = 55mL

Which best describes most covalent compounds?
O soft
O brittle
O cold
O warm

Answers

Answer:

soft

Explanation:

bc i got it right lol also nice pfp

Answer:

brittle

Explanation:

;)

24. Check out the Lewis Dot Structures for the five fake elements. Which element(s) is/are most likely metals? *

Answers

The Neptunium is the only non-metal in the given five fake elements.

The five fake elements and their Lewis Dot Structures are given below.

Fake Element 1: Zylion (ZY) Fake Element 2: Kypton (KN) Fake Element 3: Neptunium (NU) Fake Element 4: Staxon (SX) Fake Element 5: Tydon (TD)

All of the given five elements except the Neptunium (NU) are likely to be metals.

It is due to the following reason: Metals, in general, are good conductors of heat and electricity.

They are also malleable and ductile, which means they can be bent into various shapes and pulled into wires, respectively. Furthermore, they have a shiny appearance.

The above mentioned properties are found in the Lewis Dot Structures of Fake Element 1, Fake Element 2, Fake Element 4, and Fake Element 5.

Thus, the Neptunium is the only non-metal in the given five fake elements.

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calculate the energy change of the following reaction based on the bond energies given

calculate the energy change of the following reaction based on the bond energies given

Answers

The total bond energy of the reactants and products must be subtracted to obtain the energy change in the reaction \(2H_2O --- > 2H_2 + O_2\) using the provided bond energy.

Reactants:

2H-O-H (2 molecules) = 2 * (2 * O-H) = 2 * (2 * 463 kJ/mol) = 1852 kJ/mol

Products:

2H-H (2 molecules) = 2 * (2 * H-H) = 2 * (2 * 436 kJ/mol) = 1744 kJ/mol

O=O = 1 * O=O = 1 * 495 kJ/mol = 495 kJ/mol

1852 kJ/mol is the total binding energy of the reactants.

The combined binding energy of the products is 1744 kJ/mol + 495 kJ/mol, which is equal to 2239 kJ/mol.

Energy change (ΔE) = Total bond energy of the products - Total bond energy of the reactants

ΔE = 2239 kJ/mol - 1852 kJ/mol = 387 kJ/mol

So, the answer is E.

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Your question is incomplete, most probably the complete question is:

Calculate the energy change of the following reaction

based on the bond energies given.

2H2O2H2 + O2

H-H: 436kJ/mol

O=0: 495kJ/mol

O-H: 463kJ/mol

Select one:

O-485kJ/molO-1371kJ/molO 1852kJ/molO 485kJ/molnone of the above

Question 2: Heat (5 points)
A. Describe the following heat equations, and identify the indicated variables.

i. Q = mcΔT; identify c. (1 point)
ii. Q = mLvapor; identify Lvapor. (1 point)
iii. Q = mLfusion; identify Lfusion. (1 point)

Answers

Answer:

(i) specific heat

(ii) latent heat of vaporization

(iii) latent heat of fusion

Explanation:

i. Q = mcΔT; identify c.

Here, Q is heat, m is the mass, c is the specific heat and ΔT is the change in temperature.

The amount of heat required to raise the temperature of substance of mass 1 kg by 1 degree C is known as the specific heat.  

ii. Q = mLvapor; identify Lvapor

Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg liquid into 1 kg vapor at constant temperature.  

iii. Q = mLfusion; identify Lfusion

Here, Q is the heat, m is the mass and L is the latent heat of fusion.  

Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg solid  into 1 kg liquid at constant temperature.  

(i) c is the molar heat capacity of the substance.

(ii) Lvapor is the latent heat of evaporation of the substance

(iii) Lfusion is the latent heat of fusion of the substance

All the 3 equations fall under Calorimetry.

In all the equation Q is the amount of heat required.

(i) First equation represents the amount of heat required to raise the temperature of a substance of mass m.

                          Q = mcΔT

       here c is the molar heat capacity of the substance and ΔT is the chnage in temperature.

(ii) Second equation represents the amount of heat required to convert a substance of mass m from liquid phase to vapour phase.

                          Q = mLvapor

        here Lvapor is the latent heat of evaporation of the substance

during evaporation no change in temperature occurs.      

(iii) Third equation represents the amount of heat required to convert a substance of mass m from solid phase to liquid phase.

                          Q = mLfusion

        here Lfusion is the latent heat of fusion or melting of the substance

during fusion no change in temperature occurs.    

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consider the following reaction with rate law: a b -> c rate = k [a]1/2[b]2 what are the units of the rate constant, k?

Answers

The units of the rate constant (k) for the given rate law are (mol^(-1/2) L^(3/2) s^(-1)).

The units of the rate constant (k) can be determined by analyzing the rate law equation and comparing it with the units of concentration and time.

In the given rate law equation, the rate is expressed as:

rate = k [A]^1/2[B]^2

Where [A] and [B] represent the concentrations of reactants A and B, respectively.

The rate has units of concentration per unit time, typically expressed in moles per liter per second (mol/L/s).

To match the units on both sides of the equation, the units of k must be adjusted accordingly. Since the concentration of A is raised to the power of 1/2 and the concentration of B is raised to the power of 2, the units of k should compensate for these exponents.

By inspection, the units of k would be (mol/L/s)^(-1/2) * (mol/L/s)^(-2). Simplifying this expression, we get:

(k) = (mol^(-1/2) L^(3/2) s^(-1))

So, the units of the rate constant (k) for the given rate law are (mol^(-1/2) L^(3/2) s^(-1)). This indicates that the rate constant incorporates the concentrations of the reactants and the time units required to match the rate equation.

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Zelda noticed a puddle outside her front door. She saw that the puddle got smaller every day, until the 3rd day when it was completely gone. The next week, she noticed the puddle again. This time the puddle was gone the next day. Since the sun was out the second week but not the first week, Zelda hypothesized that the heat from the sun was the reason for the water evaporating at a faster rate. If she were to set up two containers with equal amounts of water, what would be the best way for Zeldato test her hypothesis\

Answers

Answer: Zelda should place one container of water in sunlight (by a window or outdoors) and the other container in a dark room (closet) away from the sun.

Explanation: This would allow Zelda to test two different settings (sun and no sun) so she can test her hypothesis.

how many electrons are in the electron cloud of silicon?

Answers

Silicon is a chemical element having the symbol Si and atomic number 14. The electronic configuration of Silicon is [Ne] 3s2 3p2. The electron configuration of Silicon contains 14 electrons in its orbitals.

These electrons are valence electrons as they take part in chemical reactions.Valence electrons are those electrons in the outermost shell that participate in the formation of chemical bonds. Silicon has a valency of four. Silicon's electron cloud, on the other hand, contains all 14 electrons. The electron cloud of silicon refers to the probability cloud of electrons around the nucleus of the silicon atom. The term "electron cloud" is used to describe a mathematical model of the area surrounding an atomic nucleus where one or more electrons are most likely to be found.The electron cloud is not a hard and fast boundary. It's more of a statistical model, representing the most likely places for electrons to be found at any given moment. This cloud does not describe the actual movement of the electron. Instead, it serves to describe the probability of finding the electron at any given location at a specific moment

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Consider the below electrochemical cell at standard conditions. Which of the following changes
would result in a voltage larger than 1.29 V?
4MnO4- (aq) + 4H+ (aq) + 4MnO2 (s) + 3O2 (g) + 2H2O E° = 1.29 V
a. Increase the partial pressure of oxygen gas.
b. Increase the mass of solid manganese(IV) oxide present.
C. Increase the pH.
d. Increase the concentration of potassium permanganate.

Answers

girl i need help with this toofrom the electrochem lab :(

funny how i found this

Identify this reaction

C5H12 + O2 ---> CO2 + H20

A. Synthesis

B. Combustion

C. Single Displacement

D. Double Displacement


4. Particles in which state of matter are the most likely to interact with each other to cause a chemical reaction?

A. Gas

B. Liquid

C. Solution

D. Solid


2. Identify this reaction

C + S8 ---> CS2

A. Synthesis

B. Combustion

C. Single Displacement

D. Double Displacement


3. Identify this reaction

Al + S2 ---> Al2S3

A. Synthesis

B. Combustion

C. Single Displacement

D. Double Displacement

Answers

Answer:

C5H12 + O2 ---> CO2 + H20
B -> Combustion

Particles in which state of matter are the most likely to interact with each other to cause a chemical reaction?
B -> liquid

Identify this reaction

C + S8 ---> CS2

A -> Synthesis

3. Identify this reaction

Al + S2 ---> Al2S3
A -> Synthesis

Explanation:

For the first question, you must remember that when you have a chemical reaction in which the products are CO2 (Carbon Dioxide) and H2O (water), you are examining a combustion reaction.

For the second question, the answer must be "liquid" because it is simply the easiest to use in a lab reaction. Solids tend to remain intact while liquids can easily mix, causing atoms to interact much more frequently. Atoms in gases are too spread out to be as likely to interact as in liquids.

For the third question, the answer must be "synthesis" because the simple combination of two reactants that results in a single product (maintaining the proper ratio outlined by its reactants) is a synthesis.

For the final question, the answer must also be "synthesis" for the same reasons as outlined in the previous reaction.

What are some uses of filtration where the residue is useful?

Answers

Answer:

Explanation:

Filtration is any of various mechanical, physical or biological operations that separate solids from fluids (liquids or gases) by adding a medium through which only the fluid can pass. The fluid that passes through is called the filtrate.[1] In physical filters oversize solids in the fluid are retained and in biological filters particulates are trapped and ingested and metabolites are retained and removed. However, the separation is not complete; solids will be contaminated with some fluid and filtrate will contain fine particles (depending on the pore size, filter thickness and biological activity). Filtration occurs both in nature and in engineered systems; there are biological, geological, and industrial forms. For example, in animals (including humans), renal filtration removes wastes from the blood, and in water treatment and sewage treatment, undesirable constituents are removed by absorption into a biological film grown on or in the filter medium, as in slow sand filtration.

A dendrite contains
O postsynaptic endings; presynaptic endings
O oligodendrocytes; terminal buttons
O myelin sheaths; nuclei
O presynaptic endings; postsynaptic endings

Answers

A dendrite contains presynaptic and postsynaptic endings. Neurons have projections called dendrites that carry electrical impulses to the nerve cell's cell body, hence option D is correct.

The termini of the axons from other neurons that form synaptic connections with the dendrite are referred to as presynaptic ends. Neurotransmitters are released from these presynaptic ends, which then send signals to the postsynaptic endings.

Postsynaptic terminals on the dendrite are specialized areas where neurotransmitters attach to start a reaction in the receiving neuron.

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Label each of the following measurements by the quantity each represents. For instance, a measurement of 10.6kg/m3 represents density.



Measurement. Quantity the measurement represents




5.0g/mL

37s

47J

39.56g

25.3 cm3

325 m s

500m2

30.23 mL

2.7 mg

0.005L

Answers

The quantities represented by each of the measurements are

5.0g/mL - Density

37s - Time

47J - Energy or Work

39.56g - Mass

25.3 cm3 - Volume

325 m/s - Time

500m2 - Area

30.23 mL - Volume

2.7 mg - Mass

0.005L - Volume

To determine the quantity each of the measurements represents, we will observe the units.

5.0g/mL

This represents density. Density is the ratio of mass to volume, and mass is measured in grams (g) while volume is measured in milliliters (mL)

37s

This represents time because time is measured in seconds (s)

47J

This represents Energy or Work because they are measured in Joules (J)

39.56g

This represents mass because mass in measured in grams (g)

25.3 cm3

This represents volume because volume is measured in cubic meters (cm³)

325 m s

This represents time. Time can be measured in milliseconds (ms)

500m2

This represents area because area is measured in square meters (m²)

30.23 mL

This represents volume because volume is measured in milliliters (mL)

2.7 mg

This represents mass because mass could be measured in milligrams (mg)

0.005L

This represents volume because volume is measured in liters (L)

Hence, the quantities represented by each of the measurements are

5.0g/mL - Density

37s - Time

47J - Energy or Work

39.56g - Mass

25.3 cm3 - Volume

325 m s - Time

500m2 - Area

30.23 mL - Volume

2.7 mg - Mass

0.005L - Volume

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4 The Mr of sodium hydroxide is 40. How many grams of sodium hydroxide are there in: a 500 cm³ of a molar solution? b 25 cm³ of a 0.5 M solution?​

Answers

There are 20 grams of Sodium hydroxide in a molar solution that has a volume of 500 cm3.

Sodium hydroxide – what is it? (NaOH)

Caustic soda and lye are two other names for sodium hydroxide. It is a typical component of soaps and cleansers. Sodium hydroxide seems to be a white, unscented solid at room temperature. Sodium hydroxide is a colorless, odorless liquid. Strong acids and water can cause explosive reactions with it.

Molarity is calculated by

moles (solute) / volume of solution in L

No. of moles = mass / molar mass

We have to find mass of sodium hydroxide (NaOH)

As we know, in 1 L (1000 cm³) of molar solution there is 40 gram of NaOH present.

From using this statement, 500 cm³ of a molar solution, means half liter of a molar solution contain -

= 40 / 2

= 20 gram of NaOH.

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What happens in radioactive decay to the atom

Answers

Answer:

When radioactive atoms decay, they release energy in the form of ionizing radiation (alpha particles, beta particles and/or gamma rays). The energy is called ionizing radiation because it has enough energy to knock tightly bound electrons from an atom's orbit. This causes the atom to become a charged ion

what is soluminescence? How does it work?​

Answers

Answer:

Sonoluminescence can occur when a sound wave of sufficient intensity induces a gaseous cavity within a liquid to collapse quickly. [...] The bubbles are very small when they emit the light—about 1 micrometer in diameter—depending on the ambient fluid (e.g., water) and the gas content of the bubble (e.g., atmospheric air).

Explanation:

Source is Google

How to get pH from OH-

Answers

Answer:

To calculate the pH of an aqueous solution you need to know the concentration of the hydronium ion in moles per liter (molarity). The pH is then calculated using the expression: pH = - log [H3O+].

Explanation:

Ni(OH)3 +
Pb(SO4)2 →__Pb(OH)4 +
Ni2(SO4)3
what is the balance

Answers

Answer:

4+3=3+3+2

Explanation:

4Ni(oh)3+3pb(so4)2=3pb(oh)4+2Ni2(so4)3

what is the pH of a solution with [H+] = 1.25 x 10^-10M?

Answers

The pH of a solution is calculated using the equation:

pH = -log[H+]

Given [H+] = 1.25 x 10^-10 M:

pH = -log(1.25 x 10^-10)
pH = -log(1.25) + log(10^-10)
pH ≈ -9 + (-10)
pH ≈ -19

Therefore, the pH of the solution with [H+] = 1.25 x 10^-10 M is approximately -19.

Answer:

9.90

Explanation:

Given [H+] = 1.25 x 10^-10 M, we can calculate the pH using the formula:

pH = -log10([H+])

pH = -log10(1.25 x 10^-10)

Using logarithmic properties:

pH = -log10(1.25) - log10(10^-10)

Since log10(10^-10) is equal to -10:

pH = -log10(1.25) - (-10)

pH = -log10(1.25) + 10

Now, evaluating the logarithm using a calculator:

pH = -0.0969 + 10

pH = 9.9031

Therefore, the pH of the solution with [H+] = 1.25 x 10^-10 M is approximately 9.9031. Rounding it to two decimal places, the pH is approximately 9.90.

Calcium carbonate is a white solid with a density of 2.71 g/cm3. it reacts readily with an acid to produce gaseous carbon dioxide.

Answers

Calcium carbonate (CaCo3) is a white solid and gaseous with the density of 2.71 g/cm^3 that can be easily calculated or observed without a chemical reaction, so it is simply a physical property.

Now the second sentence says that it reacts readily with an acid to produce gaseous carbon dioxide.

Let's take a chemical reaction:

CaCO3( Calcium Carbonate) + 2HCl (Hydrochloric Acid) ----> CaCl2 (Calcium Chloride) + CO2 (Carbon Dioxide) + H2O (Water)

Hence it readily reacts with acids so it is clearly a chemical change and falls into chemical property.

Physical properties denote or comprises density, color, melting and boiling point where as chemical properties comprises of it goes in a particular chemical reaction and changes.

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How long would it take to deposit the mass of the experimental mass gain of cathode from run 1 during the electrolysis of copper if you used a current of 2.50 a? (answer in minutes)

Answers

The mass of an element released during electrolysis is inversely proportional to the amount of electricity flowing through the electrolyte, according to the first law.

Mathematically, this can be expressed as: deposited mass, current, I, and time, t, or deposited mass, It. Where Q=Charge, M=Molarmass, n=nfac. A) M=Qm/Fn, the mass (m) of a substance deposited on the cathode or anode during electrolysis is given. Silver atoms are added to the cathode and subtracted from the anode for each element that circles the external circuit. This indicates that the mass obtained by the cathode is equal to the mass lost by the anode (assuming the silver anode is pure; see below).

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11
When an object is dropped into a graduated cylinder, the water in the
cylinder rises from 50.OmL to 56.3 mL. The mass of the object is 15.9 g.
What is the density of the object? *

Answers

Answer:

The answer is 2.52 g/mL

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\ \)

From the question

mass of object = 15.9 g

volume = final volume of water - initial volume of water

volume = 56.3 - 50 = 6.3 mL

It's density is

\(density = \frac{15.9}{6.3} \\ = 2.523809...\)

We have the final answer as

2.52 g/mL

Hope this helps you

Write the balanced half-reactions describing the oxidation and reduction that happens in the following reaction.CuCl2(aq)+Mg(s)→MgCl2(aq)+Cu(s)

Answers

Answer:

REDUCTION: Cu^+2 - 2e --> Cu

OXIDATION: Mg --> Mg^+2 +2e-

Explanation:

Remember the acronym LEO says GER. This means:

Losing Electrons is Oxidation

Gaining Electrons is Reduction

1. The first step in writing any balanced half reactions is to assign oxidation numbers to each atom on both the reactant and product side. Oxidation numbers are essentially the charges of each atom, and are usually just the charge of the atom.

Reactant side:

Cu: +2 (to cancel out 2 Cl - atoms)

Cl2: -1 (you do not consider the amount of atoms when assigning O.N.)

Mg: 0 (all atoms in pure elements have an O.N. of zero)

Product Side:

Cu: 0 (because this is a pure atom after the reaction)

Cl2: -1 (stays the same so this is not involved in the REDOX reaction)

Mg: +2 (to cancel out the -2 from two Cl - atoms)

Compare Reactant vs Product Side:

Cu: +2 --> 0 (Cu gains electrons, so this is the reduction half reaction)

Mg: 0 --> +2 (Mg loses electrons, so this is the oxidation half reaction)

Now separate the two atoms into UNBALANCED half reactions to build a base:

REDUCTION: Cu +2 --> Cu

OXIDATION: Mg --> Mg +2

The next step in typical half reactions is to balance the number of atoms in each half, but the amount of Cu stays 1 (1 Cu +2 --> 1 Cu) and the amount of Mg stays 1 (1 Mg --> 1 Mg +2), therefore there are no atoms to balance

Balance each reaction for charge (charge = number of electrons)

REDUCTION: Cu +2  -2e - --> Cu (so the charge on both sides are zero)

OXIDATION: Mg --> Mg +2 +2e- (so the positive plus 2 electrons cancels out the positive 2 O.N. on the reactant side)

Adding electrons to balance charge will always occur to the left of the reaction arrow for reduction and to the right of the reaction arrow for oxidation.

These are considered the balanced half reactions:

REDUCTION: Cu^+2 - 2e --> Cu

OXIDATION: Mg --> Mg^+2 +2e-

If you wished to write the entire equation, the next step would be to add these two half reactions. There are no additional steps for this addition because the electrons cancel out on both sides (they have to be equal in order to add)

So the COMPLETE equation is:

Cu^+2 + Mg --> Cu + Mg^+2

The overall balanced half-reactions are:

Oxidation: 2Mg(s) → 2Mg²⁺(aq) + 4e⁻

Reduction: Cu²⁺(aq) + 2e⁻ → Cu(s)

What are redox reactions?

A chemical process in which electrons are moved between two reactants is referred to as a redox reaction. The alteration in the oxidation states of the reacting species can be used to pinpoint this electron transfer.

The oxidation half-reaction involves the loss of electrons and the reduction half-reaction involves the gain of electrons.

Oxidation half-reaction: Mg(s) → Mg²⁺(aq) + 2e⁻

Reduction half-reaction: Cu²⁺(aq) + 2e⁻ → Cu(s)

To balance the charges, we need to multiply the oxidation half-reaction by 2:

2Mg(s) → 2Mg²⁺(aq) + 4e⁻

Now the number of electrons lost in the oxidation half-reaction (4) is equal to the number of electrons gained in the reduction half-reaction (4).

Thus, the overall balanced reaction is:

2Mg(s) + CuCl₂(aq) → 2MgCl₂(aq) + Cu(s)

And the balanced half-reactions are:

Oxidation: 2Mg(s) → 2Mg²⁺(aq) + 4e⁻

Reduction: Cu²⁺(aq) + 2e⁻ → Cu(s)

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what is a coefficient

what is a coefficient

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Answer:

In mathematics, a coefficient is a multiplicative factor in some term of a polynomial, a series, or any expression; it is usually a number, but may be any expression. In the latter case, the variables appearing in the coefficients are often called parameters, and must be clearly distinguished from the other variables.

Explanation:

today, ________ has the worst acid deposition problem, primarily because of ________.

Answers

Today, China has the worst acid deposition problem, primarily because of coal-fired electrical and industrial plants .

"Although part of your question is missing , you might be referring to this full question :  Today, ________ has the worst acid deposition problem, primarily because of ________.

E) China; coal-fired electrical and industrial plants "

Acid deposition is caused when sulphur dioxide (SO2) and nitrogen oxides (NOx) are emitted into our atmosphere. These chemicals SO2 and NOx, react with water, oxygen and other chemicals to form both sulphuric and nitric acids. These then mix with water and other materials before falling to the ground.

Most of the compounds (SO2 and NOx) found in acid rain come from the burning of fossil fuels, even though there is a small portion that comes from natural sources such as volcanoes.

Major sources of SO2 and NOx in the atmosphere are burning of fossil fuels to generate electricity. In around two-thirds of SO2 and one-fourth of NOx come from electric power generators, vehicles and heavy equipment and industries such as oil refineries manufacturing etc.

SO2 and NOx can be blown over very long distances and across borders meaning that acid rain is not just a problem for the people who live close to these sources but everyone.

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what is the accepted iupac name for the compound mg3p2?

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There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, the IUPAC name of the Mg\(_3\)P\(_2\) is Tri magnesium Di phosphide.

What is chemical Compound?

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.

An ionic compound is a metal and nonmetal combined compound.  Ionic compound are very hard. They have high melting and boiling point because of strong ion bond. The IUPAC name of the Mg\(_3\)P\(_2\) is Tri magnesium Di phosphide. The oxidation state of phosphide is -3.

Therefore, the IUPAC name of the Mg\(_3\)P\(_2\) is Tri magnesium Di phosphide.

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