when 2.16g of h2 reacts with excess o2 by the following equation, 258kj of heat are released. the change of enthalpy associated with the reaction of 1.00mol of hydrogen gas is -241 KJ
Molar mass of H2 = 2.016 g/mol,mass(H2)= 2.16 g
use:number of mol of H2,n = mass of H2/molar mass of H2=(2.16 g)/(2.016 g/mol) = 1.071 mol
For 1.071 mol of H2, heat released = 258 KJ So,
for 1 mol, heat released = 258/1.071 KJ = 241 KJ
Since this is heat released, sign will be negative
Answer: -241 KJ. The amount of energy progressed or subsumed in a reaction at constant pressure is referred to as enthalpy change. It is represented by the symbol ΔH, read as "delta H". It should be noted that the term "enthalpy change" only pertains to reactions performed at constant pressure. As a result, if a reaction emits more electricity than it absorbs, the reaction is exothermic, and the enthalpy is negative. Consider this as a quantity of heat departing (or being deducted from) the reaction.
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which metal is liquid and has silvery-white color.
Answer:
Mercury
Explanation:
It is also highly toxic
why is no one helping me this is some bs
The distribution of grades on a final exam
line graph
scatter plot
bar graph
histogram
I'll give brainliest
Answer:
Histogram
Explanation:
Kai wants to understand how long it takes for students to get to school using different methods. on two different days, he asked `10` random students how long it took for them to get to school. for each method, make a rough estimate for how long it will take students to get to school on their next trip
Kai asked 10 random students how long it took for them to get to school using different methods on two different days. Without knowing the specific methods the students used, it is difficult to provide an accurate estimate for how long it will take students to get to school on their next trip. However, I can provide a rough estimate based on the data Kai collected.
Assuming Kai collected data for common methods such as walking, biking, driving, or taking the bus, we can analyze the average time it took for each method on the two different days. Let's say on Day 1, the average time for walking was 15 minutes, biking was 10 minutes, driving was 20 minutes, and taking the bus was 30 minutes. On Day 2, the average time for walking was 20 minutes, biking was 15 minutes, driving was 25 minutes, and taking the bus was 35 minutes.
Based on this data, we can estimate that on the next trip, it will take students around 150 minutes (10 students x 15 minutes) to walk to school, 100 minutes (10 students x 10 minutes) to bike to school, 200 minutes (10 students x 20 minutes) to drive to school, and 300 minutes (10 students x 30 minutes) to take the bus to school. Of course, this is a very rough estimate and may not accurately reflect the time it will take each individual student on their next trip, as there are many variables that can affect travel time such as traffic, weather, and distance.
Based on Kai's research, he can estimate the time it takes for students to get to school using different methods. Since we don't have specific data from his study, here's a general guideline:
1. Walking: If most students take about 15-30 minutes to walk to school, the estimated time for their next trip would be around 15-30 minutes.
2. Biking: If biking takes students about 10-20 minutes, their next trip could be estimated within that range.
3. Public transportation: Assuming students take 20-40 minutes on public transport, the estimated time for their next trip would be within this range.
4. Driving: If driving takes students approximately 5-15 minutes, their next trip could be estimated within that time frame.
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.
describe the process to electroplating with the help of an activity
Answer:
process of depositing a thin layer of any superior metal over an object of a cheaper metal, with the help of electric current
Explanation:
I hope this help have an great day and stay health
The cultures of prehistoric humans are known mostly through the excavation of stone tools and other relatively imperishable artifacts. The early tool making traditions are often referred to as being paleolithic (literally "Old Stone Age). The Oldowan and Acheulian tool traditions of the first humans were the simplest applied research basic research Scientihe thought O philosophies technologies
The cultures of prehistoric humans are primarily known through the excavation of stone tools and other durable artifacts, such as the Oldowan and Acheulian tool traditions.
Stone tools and imperishable artifacts serve as key archaeological evidence for understanding prehistoric cultures. Through meticulous excavation and analysis, archaeologists have been able to piece together the lifestyles, technological advancements, and social behaviors of early human societies. The term "paleolithic" refers to the Old Stone Age, a time when humans relied on stone tools as their primary implements.
The Oldowan tool tradition is considered the earliest stone tool industry, dating back around 2.6 million years ago. It is characterized by simple tools, such as choppers and scrapers, which were crafted by flaking off pieces from larger stones. These tools were primarily used for basic activities like butchering and processing animal carcasses.
Later, the Acheulian tool tradition emerged around 1.76 million years ago, representing an advancement in stone tool technology. Acheulian tools, such as handaxes and cleavers, were more refined and standardized, showcasing an increased level of sophistication in tool-making techniques. These tools served a wide range of purposes, including hunting, woodworking, and shaping raw materials.
By studying the Oldowan and Acheulian tool traditions, researchers gain valuable insights into the cognitive abilities, cultural development, and technological progress of early humans. The examination of these artifacts provides evidence of their adaptability, problem-solving skills, and the gradual refinement of their tool-making techniques over time.
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Analyze the given diagram of the carbon cycle below. Use complete sentences to explain your answer.
Part 1: Which process does arrow F represent?
Part 2: Explain how matter is conserved during the process.
Part 3: Justify why this process is a recycling of carbon in the carbon cycle.
Answer:
I'm not to sure I'll ask one of my frens to help
Weak acids and bases are those that do not completely dissociate in water. The dissociation of the acid or base is an equilibrium process and has a corresponding equilibrium constant. Ka is the equilibrium constant for the dissociation of a weak acid and Kb is the equilibrium constant for the dissociation of a weak base. A 0.145 M solution of a weak acid has a pH of 2.75. What is the value of Ka for the acid
The value of Kₐ for the weak acid is equal to \(10^{-pKₐ}\), which is \(10^{-2.75}\) or approximately \(1.78 * 10^{-3}\).
To find the value of Kₐ for the weak acid, we can use the pH of the solution and the Henderson-Hasselbalch equation, which relates the pH of a solution to the concentration of the acid and its conjugate base.
The Henderson-Hasselbalch equation is given by:
pH = pKₐ + log ([A⁻]/[HA])
Where:
pH is the measured pH of the solution
pKₐ is the negative logarithm of the acid dissociation constant Kₐ
[A⁻] is the concentration of the conjugate base
[HA] is the concentration of the weak acid
Given that the pH of the solution is 2.75 and the concentration of the weak acid is 0.145 M, we can rearrange the equation to solve for pKₐ:
pKₐ = pH - log ([A⁻]/[HA])
Since the weak acid is not mentioned specifically, we'll denote it as HA.
Now, we need to determine the concentration of the conjugate base [A⁻]. Since the acid is weak, we can assume that the dissociation of the acid is small, and therefore, the concentration of the conjugate base will be approximately equal to the concentration of the weak acid:
[A⁻] ≈ [HA] = 0.145 M
Substituting the values into the equation:
pKₐ = 2.75 - log (0.145/0.145)
The log of 1 is zero, so the term in the parentheses simplifies to 1:
pKₐ = 2.75 - log(1)
pKₐ = 2.75 - 0
pKₐ = 2.75
Therefore, the value of Kₐ for the weak acid is equal to \(10^{-pKₐ}\), which is \(10^{-2.75}\)or approximately\(1.78 * 10^{-3}\)
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If I have 9.7 moles of gas at a pressure of 0.12 atm and at a temperature of 46°C, what is the volume of the
container that the gas is in?
Answer:
2117.02 litres
Explanation:
Using the ideal gas equation as follows;
PV = nRT
Where:
P = pressure of the gas (atm)
V = volume of the gas (L)
n = number of moles (mol)
R = gas law constant (Latm/molK)
T = temperature (K)
According to the information given in this question,
P = 0.12 atm
V = ?
n = 9.7moles
T = 46°C = 46 + 273 = 319K
R = 0.0821 Latm/molK
Using PV = nRT
0.12 × V = 9.7 × 0.0821 × 319
0.12V = 254.04
V = 254.04 ÷ 0.12
V = 2117.02 litres
How does a carbon atom in carbon dioxide become a hydrocarbon and organic compound before becoming carbon dioxide again?
Plants use sunlight and cellular respiration to transform carbon dioxide into the hydrocarbon molecule glucose, which is then ingested by the plants.
How does photosynthesis work?During photosynthesis, oxygen and glucose are created from water and carbon dioxide; the plant uses the glucose and produces oxygen as a waste product.
In the process of cellular respiration, oxygen & glucose are transformed into carbon dioxide and water. Carbon dioxide, water, & ATP, which would be converted into energy, are the process' byproducts.
What makes photosynthesis so crucial?The main purpose of photosynthetic is to transform chemical energy into solar energy, which is then stored for future use. This mechanism primarily provides energy to the planet's life systems.
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NH3+__0->NO+H20
a) What mass ofNO2 can be produced from 8.46 x 102 molecules of oxygen?
b) 23.7 g ofNH3 would be able to produce how many moles of H0?
c) How many grams of O2 are needed to produce 1.26 x 102 molecules of H20?
d) How many moles of NH3 are needed to react completely with 22.05 L of oxygen?
a) The mass produced is 6.5 * 10^ -20 g.
b) The amount of water produced is 2.1 moles.
c) The mass of oxygen produced is 7.84 * 10^ -21 g.
d) The moles of ammonia needed is 0.56 moles.
What is stoichiometry?Let us recall that we can be able to use the principles of stoichiometry to be able to obtain the parameters that we need to solve in this question.
a) Given that;
1 mole of oxygen would contain 6.02 * 10^23 molecules
x moles of oxygen would contain 8.46 x 10^ 2 molecules
x = 1.41 * 10^ -21 moles
If 4 moles of ammonia produces 4 moles of nitrogen IV oxide. Hence the mass of the nitrogen IV oxide produced
= 1.41 * 10^ -21 moles * 46 g/mol
= 6.5 * 10^ -20 g
b) Number of moles of ammonia = 23.7 g/17 g/mol
= 1.39 moles
If 4 moles of ammonia produces 6 moles of water
1.39 moles of ammonia produces 1.39 * 6/4
=2.1 moles
c) 1 mole of water would contain 6.02 * 10^23 molecules
x moles of water would contain 1.26 x 10^ 2 molecules
x = 2.1 * 10^ -22 moles
If 7 moles of oxygen produces 6 moles of water
x moles of oxygen would produce 2.1 * 10^ -22 moles of water
x = 2.45 * 10^-22 moles
Mass of the oxygen = 2.45 * 10^-22 moles * 32 g/mol
= 7.84 * 10^ -21 g
d) If 1 mole of oxygen occupies 22.4 L
x moles of oxygen occupies 22.05 L
x = 0.98 moles
If 4 moles of ammonia reacts with 7 moles of oxygen
x moles of ammonia would reacts with 0.98 moles of oxygen
x = 4 * 0.98/7
= 0.56 moles
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Half the distance between the nuclei of two covalently bonded atoms is the ______, whereas half the shortest distance between the nuclei of identical nonbonded atoms is the ______.
Covalent radius refers to covalently bonded atoms while atomic radius refers to non-bonded atoms.
There are two terms that are easily confused for each other in chemistry, these are the covalent radius and atomic radius. Covalent radius refers to covalently bonded atoms while atomic radius refers to non-bonded atoms.
Hence, half the distance between the nuclei of two covalently bonded atoms is the covalent radius, whereas half the shortest distance between the nuclei of identical nonbonded atoms is the atomic radius.
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Esterification of propane 1,2,3-triol and unsaturated higher carboxylic acids will produce
Propan-1-ol and ethanoate are esterified Ethanoic acid and propan-1-ol combine to generate an ester. Propan-1-ol and strong acid acid ethyl ester are two isomers that make up this ester.
What byproducts of esterification are there?Esterification is a chemical reaction that produces at least one ester molecule by reacting a lactic substances (RCOOH) with such an ethanol (ROH) to create an ether (RCOOR) and water.
How is esterification rate determined?Up to around 1 moldm3, redox reactions are linked to [H+] concentration. The third kinetic equation controls with a forward reaction rate at constant [H+] concentration. where kH is the constant of proportionality of ester hydrolysis and kE is a rate constant for esterification.
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a 250 gram sample of water at the boiling point had 35.0 kj of heat added. how many grams of water were vaporized? heat of vaporization for water is 40.6 kj/mole.
The required mass of water vaporized is 15.5 grams, from a 250 gram sample of water at the boiling point had 35.0 kj
Given: Mass of water (m) = 250 gHeat added (q) = 35.0 kJHeat of vaporization (ΔHvap) = 40.6 kJ/mole
To find:Mass of water vaporized (x) Formula:q = ΔHvap × nx = (q / ΔHvap) × nMass = moles × molar mass
We know that molar mass of water (H2O) = 18 g/molMoles of water vaporized (n) = (35.0 kJ / 40.6 kJ/mol) = 0.861 mol
Therefore,Mass of water vaporized (x) = 0.861 mol × 18 g/mol= 15.5
Detailed Solution: According to the given statement,250g of water was taken at its boiling point and 35.0 kJ of heat was added to it, we need to find how many grams of water were vaporized. To solve this question, first, we need to know the heat of vaporization for water, which is 40.6 kJ/mole. It means to vaporize 1 mole of water, 40.6 kJ of heat is required.
Mass of water (m) = 250 g Heat added (q) = 35.0 kJHeat of vaporization (ΔHvap) = 40.6 kJ/molen = q / ΔHvapn = (35.0 kJ / 40.6 kJ/mol) = 0.861 molMoles of water vaporized (n) = 0.861 mol
Therefore, Mass of water vaporized (x) = 0.861 mol × 18 g/mol= 15.5 g Hence, the required mass of water vaporized is 15.5 grams.
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A 30 gram ball is at rest. Next, a force pushes the ball to the north for 2.5 seconds and the ball accelerates for a rate of 0,70 m/s/s. How fast is the ball going after the 2.5 seconds of acceleration? For credit, who work in detail
Answer:
1.75m/s or 6.3km/hr
Explanation:
here,
acceleration (a) = 0.7m/s^2
mass (m) = 30g
time (t) = 2.5s
initial velocity (u) = 0m/s
final velocity (v) = ?
now,
v = u + at
or, v = 0 + 0.7 * 2.5
hence, Final velocity (v) = 1.75 m/s
if u want to convert to km/hr
then,
1.75 * 3.6 (we know that 1m/s = 3.6km/hr)
= 6.3km/hr
Can anyone help me with this assignment? Will give Brainliest.
Answer:
i cant get the pdf im so sorry
Explanation:
Answer:
Yes if u need help?
Explanation:
A man pulled a food cart 4.5 m to the right for 15 seconds. What is the average speed of the food cart to the nearest tenth of a m/s?
The average speed of the food cart to the nearest tenth of a m/s is 0.3 meter per second.
How do we calculate speed?Speed of any moving body will be calculated by using the below formula as:
Speed = Distance / Time
Given that, Distance travelled to the right side = 4.5m
Time to travel = 15 sec
On putting values on the above equation, we get
Speed = 4.5 / 15 = 0.3 m/s
Hence required speed is 0.3m/sec.
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What is a neutrons and a proton?
Answer:
Protons are a type of subatomic particle with a positive charge
Neutrons are a type of subatomic particle with no charge (they're neutral).
(Revision) When magnesium, Mg, form magnesium ions, Mg2+, has it beer
oxidised or reduced? *
Answer:
it has oxidized because it has has given out 2 ions
Answer:
Oxidised
Explanation:
Mg -------> Mg2+ +2electrons
In this case Mg loses two electrons and loss of electron is oxidation so Mg oxidised.
How does the product of an alpha decay compare with the original nuclide?
A.
The product's mass number is the same as that of the original nuclide.
B.
The product's atomic number is two less than that of the original nuclide.
C.
The product's mass number is two more than that of the original nuclide.
D.
The product's atomic number is the same as that of the original nuclide.
When compared to the initial nuclide, the alpha decay product: The answer is B. The atomic number of the product is two less than the atomic number of the original nuclide.
What is Alpha Decay?
A nuclear process known as "alpha decay" causes the parent nucleus to emit an alpha particle. The alpha particle is made up of two neutrons and two protons. There is a radioactive decay process known as "alpha decay" in which an atomic nucleus produces an alpha particle and radioactively decays into a separate atomic nucleus with a mass number reduced by four and an atomic number reduced by two.
Alpha decay reduces atomic mass by 4 and atomic number by 2.
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A sphere of radius 0.457 m, temperature 32.2 ∘
C, and emissivity 0.924 is located in an environment of temperature 82.9 ∘
C. At what rate does the sphere (a) emit and (b) absorb thermal radiation? (c) What is the sphere's net rate of energy exchange? (a) Number (b) Number Units Units
a) The sphere emits thermal radiation at a rate of 139.75 Watts.
b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.
c) The sphere's net rate of energy exchange is 102.09 Watts.
What are the rates of thermal radiation emission, absorption, and net energy exchange for the sphere?To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.
a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:
Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))
Plugging in the given values:
Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)
Emitting Rate ≈ 139.75 Watts
b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:
Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))
Plugging in the given values:
Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)
Absorbing Rate ≈ 37.66 Watts
c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:
Net Rate = Emitting Rate - Absorbing Rate
Net Rate = 139.75 Watts - 37.66 Watts
Net Rate ≈ 102.09 Watts
Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.
Note: The units for all the rates are Watts.
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How does an enzyme’s active site relate to its substrate?
Answer:
The enzyme's active site must be the mold shape of the substrate.
Explanation:
An enzyme and a substrate bind together in order to work. If the shapes of the 2 are different, they will not be able to bond together. If the shapes of the 2 fit glove-in-hand, then they will be able to bond together.
d. i) Describe the structure of an atom.
Answer:
An atom is a complex arrangement of negatively charged electrons arranged in defined shells about a positively charged nucleus. This nucleus contains most of the atom's mass and is composed of protons and neutrons (except for common hydrogen which has only one proton).
Answer:
Atoms consist of an extremely small, positively charged nucleus in which the protons and neutrons can be found, and is surrounded by a cloud of negatively charged electrons.
Melting and boiling point of water is high?
Answer:
Yes
Explanation:
Why melting and boiling point of water is high?
The reason for the high melting and boiling temperatures is the hydrogen bonding between water molecules that causes them to stick together and to resist being pulled apart which is what happens when ice melts and water boils to become a gas
Answer:
the temperature in the hydrogen bonding between water molecules that causes them to stick together which happens when ice melts and water boil to become a gas
1. What class of drugs are being investigated in this study, and how do they get into our waterways? 2. What is a C-start and why is it important for larval fish survival? 3. What hypotheses are being tested in this investigation? 4. Briefly describe what the researchers found when they exposed larval fathead minnows to levels of antidepressants found in our waterways.
The effects of exposure were more pronounced in fish that had been raised in a less stressful environment, suggesting that environmental conditions can influence the impact of exposure to antidepressants.
1. The class of drugs being investigated in this study is antidepressants. They enter our waterways through excretion by individuals taking the medication, and disposal of unused medication into toilets or sinks that are connected to wastewater treatment plants.
2. C-start is an evasive maneuver that young fish use when they perceive a predator. This is important for larval fish survival because it helps them to avoid being eaten by predators.
3. In this investigation, researchers are testing two hypotheses. The first is that exposure to low levels of antidepressants can affect larval fathead minnows' behavior, and the second is that the effects of exposure will be more pronounced in fish that have been raised in a less stressful environment.
4. The researchers found that exposure to antidepressants at levels found in waterways can have a significant impact on the behavior of larval fathead minnows. Specifically, they found that the fish exposed to antidepressants were less likely to respond to the presence of predators, which could increase their risk of being eaten.
They also found that the effects of exposure were more pronounced in fish that had been raised in a less stressful environment, suggesting that environmental conditions can influence the impact of exposure to antidepressants.
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The hydrolysis of acetyl phosphate has ΔG = −42 kJ mol−1 under typical biological conditions. If the phosphorylation of acetic acid were to be coupled to the hydrolysis of ATP, what is the minimum number of ATP molecules that would need to be involved?
The hydrolysis of one ATP molecule has ΔG = -30.5 kJ mol⁻¹. Therefore, the minimum number of ATP molecules required to drive the hydrolysis of acetyl phosphate, with ΔG = -42 kJ mol⁻¹, is 2 ATP molecules.
The phosphorylation of acetic acid involves the transfer of a phosphate group from ATP to acetic acid, forming acetyl phosphate and ADP. The reaction can be represented as follows:
Acetic acid + ATP → Acetyl phosphate + ADPThe hydrolysis of acetyl phosphate involves the addition of a water molecule, which breaks the phosphoanhydride bond and releases the energy stored in the phosphate bond. The reaction can be represented as follows:
Acetyl phosphate + H₂O → Acetic acid + PiThe ΔG value of the hydrolysis of acetyl phosphate is -42 kJ mol⁻¹. Since the phosphorylation of acetic acid requires one ATP molecule, the minimum number of ATP molecules required to drive the hydrolysis of acetyl phosphate is calculated as follows:
ΔG = ΔG1 + ΔG2-42 kJ mol⁻¹ = -30.5 kJ mol⁻¹ + ΔG2ΔG2 = -42 kJ mol⁻¹ + 30.5 kJ mol⁻¹ΔG2 = -11.5 kJ mol⁻¹Since the hydrolysis of one ATP molecule has ΔG = -30.5 kJ mol⁻¹, the minimum number of ATP molecules required to drive the hydrolysis of acetyl phosphate is 2.
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What is the likely mechanism if the following aromatic molecule is subjected to these reaction conditions?
A. An addition-elimination mechanism using electrophilic aromatic substitution.
B. An elimination-addition mechanism using electrophilic aromatic substitution.
C. An addition-elimination mechanism using nucleophilic aromatic substitution.
D. An elimination-addition mechanism using nucleophilic aromatic substitution.
The likely mechanism if the given aromatic molecule is subjected to these reaction conditions is an addition-elimination mechanism using electrophilic aromatic substitution.
Here, correct answer is A. An addition-elimination mechanism using electrophilic aromatic substitution.
Electrophilic aromatic substitution is a type of chemical reaction in which an electron-deficient species, such as a Lewis acid, replaces a hydrogen atom on an aromatic ring. During this process, an electron-rich species, such as a Lewis base, acts as a nucleophile and attacks the electrophile, resulting in an addition-elimination reaction.
This type of mechanism involves the formation of a new bond between the electrophile and the aromatic ring, followed by the removal of a proton from the aromatic ring. This process results in the formation of a new compound with the same aromatic ring structure but with a different substituent attached.
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Question 13,34 pts Three students are asked to discuss the sources of error that might have affected the outcome of the lab. Select the student that employs correct scientific reasoning: Student 1: If the spot was placed below the solvent level; this would cause the sample to be dissolved into the solvent pool before traveling up the plate; Student 2: If the solvent used has the opposite polarity of the stationary phase this will cause unequal movement of the sample: Student 3: If the developing chamber was closed too quickly than the sample wouldn't be able to travel on the TLC plate_ Student 1 Student 2 Student }
Based on the given statements, Student 1 employs correct scientific reasoning.
How the best answer was determinedBased on the given statements, Student 1 employs correct scientific reasoning by explaining a possible source of error in terms of the physical properties of the system. They suggest that if the spot was placed below the solvent level, the sample would be dissolved into the solvent pool before it could travel up the plate, leading to inaccurate results. This is a valid explanation based on the principles of chromatography and the physical behavior of the sample and solvent.
Student 2 also provides a valid explanation based on the principle of polarity, but they do not specify how this might lead to unequal movement of the sample on the TLC plate.
Student 3's statement, on the other hand, does not provide a clear explanation of how closing the developing chamber too quickly might affect the outcome of the lab, and it does not demonstrate a clear understanding of the scientific principles involved.
Therefore, based on the given statements, Student 1 employs correct scientific reasoning.
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what are two benefits and one drawback of using models to represent scientific processes?
Two benefits of using models to represent scientific processes are that they can simplify complex systems and make predictions about how the system will behave. One drawback is that models are inherently simplified and may not fully represent the complexity of the real system.
How are models used in scientific research?
Models are used in scientific research to represent complex systems or phenomena, allowing scientists to make predictions, test hypotheses, and explore the behavior of the system under different conditions. Models can take many forms, including physical models, mathematical models, and computer simulations.
What are some examples of scientific models used in different fields of science?Examples of scientific models used in different fields of science include climate models used to predict future weather patterns, molecular models used to study chemical reactions and interactions, and ecological models used to understand the dynamics of ecosystems. Other examples include economic models used to study market behavior, anatomical models used to study the human body, and cosmological models used to study the structure of the universe.
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The answer choices are
-solid
-liquid
-gas
Answer:
solid, gas
Explanation:
gasses are very low density because there is a low mass in a large volume with lots of space between atoms, solids on the other hand are very densely packed and there is very little room between atoms