When 0. 50 liter of a 12 m solution is diluted to 1. 0 liters, the molarity of the new solution is:.

Answers

Answer 1

Molarity is the concentration of a solution. It is expressed as moles of solute per liter of solution.

When 0.50 liters of a 12 M solution is diluted to 1.0 liters, the molarity of the new solution is calculated as follows:

Given, Volume of initial solution, V1 = 0.50 L

Volume of final solution, V2 = 1.0 L

Concentration of initial solution, C1 = 12 M

The amount of solute in the initial solution is given by the formula:

amount of solute = C1 * V1

So, Amount of solute in the initial solution = 12 * 0.50

= 6 moles of solute

In the final solution, the amount of solute is still 6 moles of solute.

Since the volume of the final solution has increased to 1.0 liters, the molarity of the final solution can be calculated by using the formula:

molarity = amount of solute / volume of solution

Therefore, the molarity of the final solution is:

molarity = amount of solute / volume of solution

= 6 moles / 1.0 L = 6M

Therefore, the molarity of the new solution is 6M.

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Related Questions

True or false your cell phone uses x-rays

Answers

Answer: Yes they do.

Explanation: Radiofrequency radiation (RF) is used by cordless and cell phones to transmit signals. RF is distinct from other forms of radiation that we know can be dangerous (like x-rays).

what are the 3 things needed in photosynthesis​

Answers

Answer:

Carbon dioxide, water and light are all needed for photosynthesis to take place. Photosynthesis happens in the leaves of a plant.

Explanation:




If 500. 0 mL of a gas at 1. 99 atm of pressure is increased to 5. 25 atm, what is the new


volume if the temperature is constant?

Answers

Boyle's Law states that the product of the pressure and volume of a gas is constant when the temperature is held constant. Mathematically, this can be expressed as:

PV = k, where P represents pressure, V represents volume, and k is a constant value.

From this equation, it becomes evident that if the temperature remains constant, an increase in pressure will result in a decrease in volume, and vice versa. In simpler terms, when the temperature is constant, the volume of a gas is inversely proportional to its pressure.

To further illustrate this point, consider a gas enclosed in a piston. If the temperature remains constant and you apply more pressure to the piston by compressing it, the volume of the gas will decrease. Conversely, if you decrease the pressure by allowing the piston to expand, the volume of the gas will increase.

In summary, when the temperature of a gas is constant, its volume and pressure share an inverse relationship, as described by Boyle's Law. This means that an increase in pressure will lead to a decrease in volume, while a decrease in pressure will lead to an increase in volume.

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How much energy must be added to a 2-kg piece of wood with a specific heat
of 1760 J/(kg°C) to increase its temperature from 10°C to 50°C?
A. 140,800 J
B. 1,760,000 J
C. 211,200 J
D. 35,200 J

How much energy must be added to a 2-kg piece of wood with a specific heatof 1760 J/(kgC) to increase

Answers

Answer:

A. 140,800 J

Explanation:

Specific heat of a material is defined as the amount of energy required to increase in 1°C 1kg of the material. For wood there are required 1760J perkg per °C.

The equation is:

Q = C*m*ΔT

Where Q is heat in Joules,

C is specific heat (1760J/kg°C),

m is mass (2kg)

ΔT is change in temperature (50°C - 10°C = 40°C)

Replacing:

Q = 1760J/kg°C*2kg*40°C

Q = 140800J

Right option is:

A. 140,800 J

Iron (III) chloride reacts with potassium hydroxide to produce iron (III) hydroxide and
potassium chloride.

Answers

Answer:

The balanced chemical equation is :

FeCl3 + 3KOH → Fe(OH)3 + 3KCl

Plz answer ASAP.
Why do you think that covalent compounds use prefixes for naming but ionic
compounds do not?
HINT: Think about how ionic compounds form versus how covalent
compounds form.

Answers

Answer:

Covalent compounds use prefixes for naming because it specifies the number of atoms as more than one atom of each element is present.

Explanation:

Covalent compounds use prefixes for naming because it specifies the number of atoms as more than one atom of each element is present.

For example: "mono" indicates 1 atom, "di" indicates two atoms, "Hexa" indicates 6 atoms, "octa" indicates eight atoms.

When naming binary ionic compounds, the cation is named first, then the nonmetal anion is named.

The diagram shows a Punnett square of the cross between the eye colors of two animals.
Brown eye color is dominant and blue eye color is recessive. What is the percentage of offspring with brown eyes as
shown by the data?
A 0%
B 25%
C 50%
D 100%

The diagram shows a Punnett square of the cross between the eye colors of two animals.Brown eye color

Answers

hahah i also needed this answer for ms mackos packet

also can you make me brainliest so that i get more points

The ionization energies for removing successive electrons from sodium are 496 kJ/mol, 4562 kJ/mol,
6912 kJ/mol, and 9544 kJ/mol. The great jump in ionization energy after the first electron is removed
indicates that
Select one:
O a. sodium has four or five electrons.
O b. the atomic radius has increased.
c. a d-electron has been removed.
d. the noble gas configuration has been reached.

Answers

Answer:

D

Explanation:

The high jump of ionization energy indicates that we are trying to remove electron from noble gas configuration state.

The ionization energy data specifies that the Elements are from group 1 at period 3 or greater.

Removing the first electron require 496 kJ and the second ionization energy jump significantly due to the removal of electron from the noble gas configuration which is logical because electron try to maintain the especially stable state.

How many grams of Lioh are in 1.7 moles?

How many grams of Lioh are in 1.7 moles?

Answers

Answer:

40.7g

Explanation:

so mass = moles × mr( 6.94+16+1)

=1.7 × 23.94

= 40.698

so 3 S.F = 40.7 g

hope this helps :)

Many watches are powered by small, flat batteries called button cells. One common type of button cell contains the metal zinc. When zinc in the battery combines with oxygen in the air, zinc oxide forms. This process generates the electricity that powers the watch. is this a product or reactant

Answers

The electricity generated that powers the watch by zinc in the battery combines with oxygen in the air, zinc oxide forms reaction is a product.

Zinc-air batteryIn zinc -air battery oxidation of zinc to zinc oxide in presence of oxygen from air takes place. These batteries are cost-effective and contain more density of energy as compared to others. When compared with lithium batteries these are with more capacity, environmental safe, cost-effective and easy to produce these are widely used. Metal-air batteries fueled by the oxidation of zinc with oxygen from the air include zinc-air batteries (non-rechargeable) and zinc-air fuel cells (mechanically rechargeable). These batteries are produced at comparatively low costs and have great energy densities.Effective anode materials must be developed for next-generation lithium-ion batteries (LIBs). Due to a number of intriguing characteristics, including its high theoretical capacity, simplicity in synthesis, environmental friendliness, and low cost, zinc oxide (ZnO) has been regarded as a useful material.In addition, compared to the majority of primary batteries, zinc-air batteries offer a high volumetric energy density. Such batteries have a number of drawbacks, including a reliance on ambient conditions, a propensity to dry up when exposed to air, flooding potential, a finite output, and a brief active life.

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How many grams of C2H2 are produced when water is added (in excess) to 5.00g CaC2CaC2+2H2O=C2H2+Ca(OH)2

Answers

Step 1

The reaction must be completed and balanced:

CaC2 + 2H2O = C2H2 + Ca(OH)2

---------------

Step 2

Information provided:

H2O (water) is the excess.

CaC2 is the limiting reactant. This limits the production of C2H2

Information needed:

The molar mass of CaC2 (64.0 g/mol) and C2H2 (26.0 g/mol)

---------------

Step 3

By stoichiometry:

1 mol CaC2 = 64.0 g

1 molC2H2 = 26.0 g

64.0 g CaC2 -------- 26.0 g C2H2

5.00 g CaC2 -------- X

X = 5.00 g CaC2 x 26 g C2H2/64.0 g CaC2 = 2.03 g C2H2

Answer: 2.03 g C2H2

A) 400 gramos de disolución al 6 % m/m. R: 24 g sto. Y 376 g ste. b) 56 gramos de disolución al 30 % m/m. R: 16,8 g y 39,2 g c) 450 gramos de disolución al 10 % m/m R: 45 g y 405 g d) 200 gramos de disolución al 5 % m/m R: 10 g y 190 g e) 450 gramos de disolución al 20 % v/v R: 90 mL y 360 mL f) 980 mL de disolución al 25 % v/v R: 245 mL y 735 mL. g) 50 mL de disolución al 30 % v/v R: 15 mL y 35 Ml

Answers

Answer:

A) 24g soluto y 376g solvente.

B) 16.8g soluto y 39.2g solvente

C) 45g soluto y 405g solvente

D) 10g soluto y 190g solvente

E) 90mL soluto y 360mL solvente

F) 245mL soluto y 735mL solvente

G) 15mL soluto y 35mL solvente

Explanation:

El porcentaje masa/masa (% m/m) se define como la masa de soluto presente en 100g de solución (Soluto + solvente).

De la misma manera, el porcentaje volumen/volumen se define como el volumen de soluto en 100mL de solución:

A) 400 gramos de disolución al 6 % m/m.

400g solución * (6g soluto / 100g solución) = 24g soluto

400g solución - 24g soluto = 376g solvente

b) 56 gramos de disolución al 30 % m/m.

56 gramos de disolución al 30% m/m.

56g solución * (30g soluto / 100g solución) = 16.8g soluto

56g solución - 16.8g soluto = 39.2g solvente

c) 450 gramos de disolución al 10 % m/m

450 gramos de disolución al 10% m/m.

450g solución * (10g soluto / 100g solución) = 45g soluto

450g solución - 45g soluto = 405g solvente

d) 200 gramos de disolución al 5 % m/m

200 gramos de disolución al 5% m/m.

200g solución * (5g soluto / 100g solución) = 10g soluto

200g solución - 10g soluto = 190g solvente

e) 450 mL de disolución al 20 % v/v

450 mL de disolución al 20% m/m.

450 mL * (20mL soluto / 100mL solución) = 90mL soluto

450mL solución - 90mL soluto = 360mL solvente

f) 980 mL de disolución al 25 % v/v

980 mL de disolución al 25% m/m.

980 mL * (25mL soluto / 100mL solución) = 245mL soluto

980mL solución - 245mL soluto = 735mL solvente

g) 50 mL de disolución al 30 % v/v

50 mL de disolución al 30% m/m.

50 mL * (30mL soluto / 100mL solución) = 15mL soluto

50mL solución - 15mL soluto = 35mL solvente

Which statement accurately describes cells? All living things, except bacteria, are made of cells. All living things are made of more than one cell. Cells are made of several parts that work together. Cells make up nonliving things like rocks and soil.

Answers

Answer:

Cells are made of several parts that work together.

Explanation:

It is this because bacteria are made of 1 cell, unicellular. All living things do not have to have more than 1 cell proven by bacteria which has one cell. And cells are living meaning it has to make up living things.

Hope this helps:)

Answer:

Option 3

Explanation:

Cells are made up of several parts (Organelles) that work together resulting in the functioning of the cell which further results in the functioning of the whole body.

Calculate the x and y components of the net force on the ring ΣF
x

= ΣF
y

= Is the 1
st
law of Newton obeyed? Justify. \begin{tabular}{cc|c|c} T
xN

& 0.139N & −0.220N & −0.28N \\ \hlineT
yN

& 0.209N & 0.117N & 0N \end{tabular}

Answers

Given the following: \begin{tabular}{cc|c|c} T
xN

& 0.139N & −0.220N & −0.28N \\ \hlineT
yN

& 0.209N & 0.117N & 0N \end{tabular}Calculating the x and y components of the net force on the ring ΣF: For x components of ΣF:ΣF
x

= T
x
1

 + T
x
2

 + T
x
3

ΣF
x

= 0.139 N - 0.220 N - 0.28 N ΣF
x

= -0.361 NFor y components of ΣF:ΣF
y

= T
y
1

 + T
y
2

 + T
y
3

ΣF
y

= 0.209 N + 0.117 N + 0 N ΣF
y

= 0.326 NThus, the components of the net force are: ΣF
x

= -0.361 N, ΣF
y

= 0.326 N

Newton’s 1st law: Every body will continue in a state of rest or of uniform motion in a straight line unless compelled to change that state by forces impressed upon it. This law is obeyed since the sum of the forces on the ring is not zero. It would continue in its motion, if there were no net force acting upon it.

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What would happen to the food chain, if all the plants were removed?

Answers

Answer: chain reaction there will be no carbon and animals who eat plants will die off

Explanation:

Argon is a noble gas.
Explain why no product is formed when magnesium and argon are heated together.
[2 mark

Answers

Argon is a noble gas. argon no product is formed when magnesium and argon are heated together because argon is extremely stable.

The argon is a noble gas. noble gases are extremely stable. the noble gases have their octet complete and follow the octet rule.   the outermost shell in the argon atom have the eight electron that eight valence electrons and it is fulfilling the  octet rule. this means they have very little little tendency to gain or loss the electrons and they are very unreactive.

Thus, Argon is a noble gas. argon no product is formed when magnesium and argon are heated together because argon is extremely stable.

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how many grams of magnesium cyanide would you need to add to 275 ml of water to make a 0.075 molal solution

Answers

The mass of magnesium cyanide needed to prepare the solution is 1.57 g

We'll begin by calculating the number of mole of Mg(CN)₂. This can be obtained as follow:

Volume = 275 mL = 275 / 1000 = 0.275 L

Molarity of Mg(CN)₂ = 0.075 M

Mole of Mg(CN)₂ =?

Mole = Molarity x Volume

Mole of Mg(CN)₂ = 0.075 × 0.275

Mole of Mg(CN)₂ = 0.020625 mole

Finally, we shall determine the mass of Mg(CN)₂

Mole of Mg(CN)₂ = 0.020625 mole

Molar mass of Mg(CN)₂ = 24 + 2(12 + 14) = 76 g/mol

Mass of Mg(CN)₂ =?

Mass = mole × molar mass

Mass of Mg(CN)₂ = 0.020625 × 76

Mass of Mg(CN)₂ = 1.57 g

Therefore, 1.57 g of Mg(CN)₂ is needed to prepare the solution

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The half-life of carbon-14 is 5,730 years. An artifact produces 5.4 disintegrations of 14C per minute per gram of carbon in the sample. Estimate the age of this sample assuming that its original radioactivity was 15.3 disintegrations per minute per gram of carbon.

Answers

The estimated age of the sample is approximately 10,717 years.

To estimate the age of the sample, we can use the formula for exponential decay:

\(N(t) = N(0) * (1/2)^(t / T)\)

Where:
N(t) is the current radioactivity (5.4 disintegrations per minute per gram)
N(0) is the original radioactivity (15.3 disintegrations per minute per gram)
t is the time passed (unknown)
T is the half-life of carbon-14 (5,730 years)

Substituting the given values, we have:

\(5.4 = 15.3 * (1/2)^(t / 5730)\)

To solve for t, we need to isolate it. Divide both sides of the equation by 15.3:

\(5.4 / 15.3 = (1/2)^(t / 5730)\)

\(0.3529 = (1/2)^(t / 5730)\)

Next, take the logarithm of both sides to get t / 5730 by itself:

\(log(0.3529) = log((1/2)^(t / 5730))\)

Using the logarithmic property, we can bring down the exponent:

\(log(0.3529) = (t / 5730) * log(1/2)\)

Simplify further:

\(log(0.3529) = (t / 5730) * (-0.3010)\)

Divide both sides by -0.3010:

\(log(0.3529) / -0.3010 = t / 5730\)

Solve for t by multiplying both sides by 5730:

\(t = log(0.3529) / -0.3010 * 5730\)

Using a calculator, we find:

t ≈ 10,717 years

Therefore, the estimated age of the sample is approximately 10,717 years.

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What element is this? In my family there are non-metals, metalloids, and metals. I am commonly used in the canning business and sometimes give soup a distinct taste. I've been known to "cry" if you've bend me too hard.​

Answers

The element that has in its family non-metals, metalloids, and metals, which is commonly used in the canning business and sometimes give soups a distinct taste and that is also been known to "cry" if you bend it too hard is tin.

What is tin?

Tin is a chemical element found in the periodic table with atomic number 50 and which has the symbol Sn.

The characteristics of tin include:

Tin is a silver-colored metal.Tin is a soft metal such that it can be cut even when little force is appliedPure solid tin has a shiny lustrous appearance as is similar to most metals.

Because of its high resistance to corrosion and soft nature, tin has been used for a wide variety of purposes which include:

it is used in the electroplating of steel cans used as food containers,it is used together with other metals in producing bearingsIt is used in soldering works

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An engineering company needs to
solve a design problem.
It is designing a high-speed train to transport
passengers
between Boston and Atlanta.
Which statement is a criterion for this project?
O A. The train must not take more than six years
to build
B. The train must not have wheels with bearings
that need
lubrication,
O C. The train must cost less than $150 million
to design.
D. The train must be able to maintain a speed of
250 km/h.

Answers

Answer:D.the train must be able to maintain a speed of 250km/h.

Explanation:

What would a chemist likely study about a car?
A) The amount of rotations of the wheel that occur in 1 mile.
B) The reaction of gasoline combustion in the engine.
C) The accuracy of the speedometer.
D) The strength of the car frame.

Answers

B because of the reaction between the constituents

Answer

b b b b b b b b b b b b b b b

Explanation:

Suppose you want to search for high-redshift star-forming galaxies using a telescope equipped with a spectrograph able to measure the entire optical spectrum (400-700 nm). Star-forming galaxies contain copious hydrogen gas, from which stars form. Some of this gas will be ionized by the newly-formed stars; the spectra of star-forming galaxies there exhibit bright hydrogen lines in emission. Light from the newly-formed stars is absorbed by neutral hydrogen gas as it passes through the galaxy. a) If you wish to search for Lyman-a emitting galaxies, over what redshift range can you find such galaxies? [3 points] b) If you detect only one line, you cannot be certain that this line is the Lyman-a line, and hence that the galaxy is indeed at the computed redshift. Assuming you can also observe in the infrared (wavelengths >700 nm), how can you change your strategy to make sure that the line you detect is really the Lyman-a line? Give three examples of how you can increase confidence in the correct identification of the Lyman-a line considering only hydrogen gas. [3 points] c) Limited only to optical wavelengths and considering only hydrogen gas, what strategy should you adopt to be certain that the line you detect is really the Lyman-a line while maximizing the redshift range over which you find galaxies? With this strategy, over what redshift range can you find star-forming galaxies? Justify through appropriate computations and reasoning that this is in fact the optimal strategy for maximizing the redshift range of your search. [10 points] d) Apart form hydrogen emission lines, star-forming galaxies also usually exhibit bright [OIII] forbidden lines. Why can such lines be seen from interstellar gas but not the Earth's atmosphere or in the laboratory? [4 points]

Answers

a) The maximum observable range of redshifts that produces Lyman-alpha line is 0 ≤ z ≤ 10.6

b) i) identifying the galaxy with a radio source, ii) looking for other Lyman lines, iii) a coincidence with a continuum break

c)The maximum redshift range over which galaxies can be found using this strategy is z = 7 to z = 15.5.

d)Earth's atmosphere absorbs the radiation, and the laboratory conditions are not the same as interstellar conditions.

a) Lyman-alpha line is produced by the hydrogen atoms that have electrons that are in the ground state being raised to the first excited state. Over a certain range of redshifts, the Lyman-alpha line is redshifted to longer wavelengths that are observable by an optical spectrograph. The maximum observable range of redshifts that produces Lyman-alpha line is 0 ≤ z ≤ 10.6 (depending on the exact details of the galaxy's emission profile).

b) Observing the galaxy in the infrared can help in the identification of the Lyman-alpha line as it is shifted to longer wavelengths. Three ways to increase confidence in the correct identification of the Lyman-alpha line are:

i) identifying the galaxy with a radio source, ii) looking for other Lyman lines, iii) a coincidence with a continuum break.

c) The strategy that needs to be adopted is to look for the Lyman limit, which is the point at which the spectrum is cut off by the absorption of all hydrogen in the galaxy. To be certain that the line you detect is the Lyman-alpha line, you need to look for a decrement in the flux of the galaxy at wavelengths shorter than the line and a decrement in the flux at wavelengths longer than the line. This is because the Lyman limit will be shifted to longer wavelengths at higher redshifts, so to maximize the redshift range over which galaxies can be found, you need to search for the Lyman limit at the longest wavelength possible. The maximum redshift range over which galaxies can be found using this strategy is z = 7 to z = 15.5.

d) The reason why such lines can be seen from interstellar gas but not the Earth's atmosphere or in the laboratory is that the Earth's atmosphere absorbs the radiation, and the laboratory conditions are not the same as interstellar conditions. The forbidden lines from the interstellar gas are not affected by dust absorption because they are produced in regions where dust is not present.

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How many moles of ethylenediamine (H2NCH2CH2NH2) are contained in 9.8 mL of 25.0% ethylenediamine solution? The density of the solution is 0.950 g/mL and the formula mass of ethylenediamine is 60.01 g/mole.

b)Under the conditions employed in this experiment, 9.8 mL of 25.0% ethylenediamine were reacted with 1.85 g of NiCl2•6H2O. What is the theoretical yield of [Ni(en)3]Cl2? The

density of the ethylenediamine solution is 0.950 g/mL. The formula mass of NiCl2•6H2O is 237.71 g/mole and the formula mass of [Ni(en)3]Cl2 309.91 g/mole.

Answers

a) There are approximately 0.0388 moles of ethylenediamine in 9.8 mL of the 25.0% ethylenediamine solution.

b) The theoretical yield of [Ni(en)₃]Cl₂ is approximately 2.41 grams.

a) To calculate the number of moles of ethylenediamine (H₂NCH₂CH₂NH₂) in 9.8 mL of a 25.0% ethylenediamine solution, we need to first determine the mass of ethylenediamine present in the given volume.

The density of the solution is provided as 0.950 g/mL, which means that for every 1 mL of solution, the mass is 0.950 g.

Mass of the ethylenediamine solution = volume of solution * density of the solution

                                                               = 9.8 mL * 0.950 g/mL

                                                               = 9.31 g

Now, we need to calculate the mass of ethylenediamine in the solution, which is 25.0% of the total mass of the solution.

Mass of ethylenediamine = 25.0% of the total mass of the solution

                                          = 0.250 * 9.31 g

                                          = 2.328 g

Next, we can calculate the number of moles of ethylenediamine using the formula mass of ethylenediamine.

Number of moles of ethylenediamine = mass of ethylenediamine/formula mass of ethylenediamine

                                                              = 2.328 g / 60.01 g/mol

                                                              = 0.0388 mol

b) To calculate the theoretical yield of [Ni(en)₃]Cl₂, we need to determine the limiting reactant between ethylenediamine (H₂NCH₂CH₂NH₂) and NiCl₂•6H₂O. We will use the stoichiometry of the reaction to find the molar ratio.

The balanced equation for the reaction is:

NiCl₂•6H₂O + 3 H₂NCH₂CH₂NH₂ → [Ni(en)₃]Cl₂ + 6 H₂O

From the equation, we can see that the molar ratio between NiCl₂•6H₂O and [Ni(en)₃]Cl₂ is 1:1.

First, let's calculate the number of moles of NiCl₂•6H₂O:

Molar mass of NiCl₂•6H₂O = 237.71 g/mol

Number of moles of NiCl₂•6H₂O = mass of NiCl₂•6H₂O / molar mass of NiCl₂•6H₂O

                            = 1.85 g / 237.71 g/mol

                            = 0.00778 mol

Since the molar ratio between NiCl₂•6H₂O and [Ni(en)₃]Cl₂ is 1:1, the theoretical yield of [Ni(en)₃]Cl₂ will be the same as the moles of NiCl₂•6H₂O.

Theoretical yield of [Ni(en)₃]Cl₂ = 0.00778 mol

Finally, we can calculate the mass of [Ni(en)₃]Cl₂ using the formula mass:

Formula mass of [Ni(en)₃]Cl₂ = 309.91 g/mol

Mass of [Ni(en)3]Cl2 = number of moles of [Ni(en)₃]Cl₂ * formula mass of [Ni(en)₃]Cl₂

                                 = 0.00778 mol * 309.91 g/mol

                                 = 2.41 g

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A spherical balloon of 6cm diameter containing air at 20°C and 740 mm pressure is expanded until the radius is 4cm at the same temperature and pressure. What volume of air at NTP Is required for the expansion?​

Answers

The initial volume of the balloon is given by V1 = (4/3)πr1³ = (4/3)π(3cm)³ = 113.1 cm³. The final volume of the balloon is given by V2 = (4/3)πr2³ = (4/3)π(2cm)³ = 33.5 cm³.

According to the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. We can use this equation to find the number of moles of air in the balloon before and after the expansion.

n1 = (P1V1)/(RT1) = (740 mm)(0.1131 L)/(0.08206 L atm/mol K)(293 K) = 0.00438 mol

n2 = (P2V2)/(RT2) = (740 mm)(0.0335 L)/(0.08206 L atm/mol K)(293 K) = 0.00163 mol

The difference in the number of moles is the amount of air that needs to be added to the balloon to expand it to the final volume at the same temperature and pressure.

Δn = n2 - n1 = 0.00163 mol - 0.00438 mol = -0.00275 mol

Since the volume of the balloon is changing at constant temperature and pressure, we can assume that the amount of air added is at the same temperature and pressure. At NTP (0°C and 1 atm), the volume of one mole of gas is 22.4 L. Therefore, the volume of air required for the expansion is:

V = nRT/P = (-0.00275 mol)(0.08206 L atm/mol K)(293 K)/(1 atm) = -0.06 L

The negative sign indicates that the volume of air removed from the balloon is greater than the volume of air added. This is because the balloon is contracting as it is being filled with less air. Therefore, the volume of air required for the expansion is 0.06 L.

What is the cathode in the hydrogen fuel cell? A. KOH B. O2 C. Li D. H2 E. Pt

Answers

In a hydrogen fuel cell, the cathode is where the reduction reaction occurs. The reduction reaction in a hydrogen fuel cell involves the reaction of oxygen (O2) with electrons and protons from the anode to produce water (H2O). Therefore, the correct answer is B. O2.

The other options you provided are:

A. KOH (Potassium Hydroxide) - KOH is often used as an electrolyte in alkaline fuel cells, not as the cathode material.

C. Li (Lithium) - Lithium is not typically used as the cathode material in hydrogen fuel cells.

D. H2 (Hydrogen) - Hydrogen is the fuel that is supplied to the anode of the fuel cell.

E. Pt (Platinum) - Platinum is often used as a catalyst material on the cathode side of a hydrogen fuel cell, but it is not the cathode itself.

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7. What information do you need to figure out how much ENERGY is released when 1,000,000

Uranium-235 atoms split? Find this information. To figure out how much energy is released.


Pls help me I been stuck on this for a while

Answers

The determine the energy released when 1,000,000 Uranium-235 atoms split, you need to know the energy released per fission event. Here's a step-by-step explanation Determine the energy released per fission event: Uranium-235 undergoes nuclear fission, and when it splits, it releases a certain amount of energy.

The average energy released per fission event for U-235 is approximately 200 MeV (million electron volts). Convert the energy per fission event to joules: 1 electron volt (eV) is equal to 1.602 x 10^ (-19) joules. So, 200 MeV is equivalent to 200 x 10^6 x 1.602 x 10^ (-19) joules, which is approximately 3.204 x 10^(-11) joules. Calculate the total energy released by 1,000,000 U-235 atoms: To find the total energy released by 1,000,000 Uranium-235 atoms, multiply the energy released per fission event (in joules) by the number of atoms. Therefore, 1,000,000 x 3.204 x 10^ (-11) joules = 3.204 x 10^ (-5) joules. So, the energy released when 1,000,000 Uranium-235 atoms split is approximately 3.204 x 10^ (-5) joules.

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Which of the following represents gamma emission?
A. 16 Eu+ge ¹62 Sm
B. Tc→ Tc+y
O C. 14Gd 1442 Sm+ He
O D. 180Gd→ 160Tb + je
SUBMIT

Answers

Answer:c

Explanation:

A battery contains two metals that have different tendencies to attract electrons. If one is lithium with an electron affinity of −3.05, and the other is zinc with an electron affinity of −0.76, describe how the electrons will flow. Then, describe how you could make this an even stronger battery.

Answers

This battery could be made stronger when we make lithium the anode and make zinc the cathode.

What is the electron affinity?

We know that the term electron affinity has to do with the fact the a specie is able to attract electrons. Hence, the specie that can be able to attract electrons is said to be have a greater electron affinity.

If we look at the order of the reactivity of the metals, we can see that the lithium has more tendency to exist as a positive ion as such the electron affinity of the lithium atom is very negative and it does not attract electrons.

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help me please????? ​

help me please?????

Answers

It’s rise and cool because when they heat up, the expand and when they cool down, they fall down.

Where would you expect light waves to move fastest?

A. Through an iceberg
B. On a mountaintop
C. In space
D. Under the sea

Answers

In space light waves move fastest, which is C. This is due to the fact that space is completely open and unrestricted and contains nothing that would do so.

What is Light waves?
The region of the electromagnetic spectrum that the human eye perceives as light, or visible light, is made up of electromagnetic radiation. Typically, visible light is characterised as having wavelengths between 400 and 700 nanometers (nm), or frequencies between 750 and 420 terahertz, which fall between the longer-wavelength infrared and the shorter-wavelength ultraviolet (with shorter wavelengths). The term "light" in physics can be used to more broadly describe electromagnetic radiation of any wavelength, whether or not it is visible. Gamma rays, X-rays, microwaves, and radio waves are all forms of light in this sense. Intensity, propagation direction, frequency or wavelength spectrum, and polarisation are the four main characteristics of light.

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