Answer:
a+1-2= negative 1 a+1+2=3
Step-by-step explanation:
hope this helps
The sector of a circle has an area of 104pi/9
square inches and a central angle with measure 65 degree
. What is the radius of the circle, in inches?
Answer:
Given:
Area of the sector (A) = 104π/9 square inches
Central angle (θ) = 65 degrees
The formula for the area of a sector of a circle is:
A = (θ/360) * π * r^2
We can rearrange this formula to solve for the radius (r):
r^2 = (A * 360) / (θ * π)
Plugging in the given values:
r^2 = (104π/9 * 360) / (65 * π)
r^2 = (104 * 40) / 9
r^2 = 4160 / 9
r^2 ≈ 462.22
Taking the square root of both sides:
r ≈ √462.22
r ≈ 21.49
Therefore, the radius of the circle is approximately 21.49 inches.
Answer: 8 inches
Step-by-step explanation:
Ayuda operaciones y respuesta es para ahora
The perimeter of the given window is 48 centimeter.
From the given figure,
Perimeter of window = 2(Length+Breadth)
= 2(10+14)
= 2×24
= 48 centimeter
Perimeter of house = 2(Length+Breadth)
= 2(37+35)
= 2×72
= 144 centimeter
Perimeter of roof = 2(Length+Breadth)
= 2(37+5)
= 2×42
= 84 centimeter
Therefore, the perimeter of the given window is 48 centimeter.
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If you can buy one bunch of seedless green grapes for $2, then how many can you buy with $18?
If you can buy 1 bunch of seedless green grapes for $2, then $18 we can buy 9 bunches.
The concept used here is a simple division to find out how many bunches of seedless green grapes can be purchased with a given amount of money.
In this case, we know the cost of one bunch of seedless green-grapes ($2) and we are given a total amount of money ($18) that we can spend on grapes. We can use division to find out how many bunches we can buy with that amount.
⇒ Number of bunches = ($18)/($2) per bunch,
⇒ Number of bunches = 9 bunches;
Therefore, with $18, you can buy 9 bunches of seedless green grapes.
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B.y = 4x + 2
y = -8x + 8
\(y = 4x + 2 \\ = > y - 2 = 4x \\ = > x = \frac{y - 2}{4} \)
\(y = - 8x + 8 \\ = > y = - 8( \frac{y - 2}{4} ) + 8 \\ = > y = \frac{ - 8y + 16}{4} + 8 \\ = > y = \frac{ - 8y + 16 + 32}{4} \\ = > y = \frac{ - 8y + 48}{4} \\ = > 4y = - 8y + 48 \\ = > 4y + 8y = 48 \\ = > 12y = 48 \\ = > y = 4\)
\(y = 4x + 2 \\ = > 4 = 4x + 2 \\ = > 4x = 4 - 2 \\ = > 4x = 2 \\ = > x = \frac{2}{4} = \frac{1}{2} \)
Answer:
\(x = \frac{1}{2} \\ y = 4\)
Hope you could understand.
If you have any query, feel free to ask.
\(\\ \sf\longmapsto y=4x+2\)
\(\\ \sf\longmapsto y=-8x+8\)
Graph attached as solutionThe plot below shows the amount of time Mira spent on
5
55 math problems.
All measurements are rounded to the nearest
1
4
4
1
start fraction, 1, divided by, 4, end fraction minute.
A line plot labeled Time per problem (minutes) shows, moving left to right, labeled tick marks at seven, seven and a half, eight, eight and a half, nine, nine and a half, and ten. An unlabeled tick mark appears between each labeled tick mark. Dots are plotted as follows: 2 dots above the unlabeled tick mark between eight and eight and a half and 3 dots above nine and a half.
A line plot labeled Time per problem (minutes) shows, moving left to right, labeled tick marks at seven, seven and a half, eight, eight and a half, nine, nine and a half, and ten.
If Mira had spent the same total amount of time, but spent an equal amount of time on each problem, how many minutes would each problem have taken?
If Mira had spent the same total amount of time but an equal amount of time on each problem, each problem would have taken around 2.36 minutes.
In the given plot, Mira spent varying amounts of time on each of the 55 math problems. To find out how many minutes each problem would have taken if Mira had spent an equal amount of time on each problem, we need to calculate the total time she spent and divide it by the number of problems.
Looking at the plot, we can estimate the total time Mira spent by counting the dots above each tick mark and multiplying them by the corresponding time interval. Let's break it down step by step:
The tick marks on the plot are at 7, 7.5, 8, 8.5, 9, 9.5, and 10 minutes per problem.
There are 2 dots above the unlabeled tick mark between 8 and 8.5 minutes per problem. We can assume it represents 8.25 minutes.
There are 3 dots above the 9.5 minutes per problem tick mark.
Now, let's calculate the total time Mira spent:
(7 * 2) + (7.5 * 2) + (8 * 2) + (8.25 * 2) + (9 * 2) + (9.5 * 3) + (10 * 2) = 129.5 minutes.
Since Mira spent a total of 129.5 minutes on 55 problems, each problem would have taken approximately 2.36 minutes (rounded to two decimal places) if she had spent an equal amount of time on each problem.
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Mahesh has Rs 150 and he buys a pen costing Rs 75 now he has to buy a copies costing Rs 10 each what is the maximum number of copies did he buy?
Answer:
7
Step-by-step explanation:
Rs 150- Rs 75=Rs 75 remaining
Rs 75/10= 7 as whole
Step-by-step explanation:
given,
total amnt =rs.150
cost of pen= rs.75
now,
left money =150_75
=rs.75
now,cost of 1 copy=10
then , no. of copies=75/10
=7.5
so he can buy 7 copies.
how do i find the slope of this with change in y/change in x if this table isn't changing by the same amount each time
inGiven that the slope,s, is
\(s=\frac{change\text{ in y}}{change\text{ in x}}\)Also given that:
\(\begin{gathered} \text{when:} \\ x=-5,y=-16 \\ x=-2,y=-7 \\ x=0,y=-1 \\ x=3,y=8 \\ x=5,y=14 \end{gathered}\)To find the slope from the given values of x and corresponding values of y
Taking two values of x and y
\(\begin{gathered} x=-5,y=-16 \\ x=-2,y=-7 \\ s=\frac{-7--16}{-2--5} \\ s=\frac{-7+16}{-2+5} \\ s=\frac{9}{3} \\ s=3 \end{gathered}\)\(\begin{gathered} x=-2,y=-7 \\ x=0,y=-1 \\ s=\frac{-1--7}{0--2} \\ s=\frac{-1+7}{0+2} \\ s=\frac{6}{2} \\ s=3 \end{gathered}\)Taking another values of x and y
\(\begin{gathered} x=3,y=8 \\ x=5,y=14 \\ s=\frac{14-8}{5-3} \\ s=\frac{6}{2} \\ s=3 \end{gathered}\)\(undefined\)
The slope is the same at the two instances. Hence, the slope is 3
Two sides of a rectangular garden are 3 meters long. The area of the garden is 18 square meters. How long are the other two sides? What is the perimeter of the garden?
The length of the other two sides of the rectangular garden is 6 meters and the perimeter of the garden is 18 meters.
According to the question,
We have the following information:
Two sides of a rectangular garden are 3 meters long. The area of the garden is 18 square meters.
We know that the following formula is used to find the area of rectangle:
Length*width = 18
Length*3 = 18
Length = 18/3
Length of the rectangular garden = 6 meters
Now, perimeter of the rectangular garden:
2(length+width)
2(6+3)
2*9
18 meters
Hence, the length of the other two sides of the rectangular garden is 6 meters and the perimeter of the garden is 18 meters.
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Imagine a clock with the hour hand at 12 and the minute hand at 2. Does the angle formed by the two hands have a measure greater than, less than, or equal to 1/4 turn?
The angle formed by the two hands have a measure less than 1/4 turn
How to relate the measure of the angle to 1/4 turn?From the question, we have the following parameters that can be used in our computation:
A clock with the hour hand at 12 and the minute hand at 2
The turn represented by the above is represened as
Turn = (2 * 30)/360
When simplified, we have
Turn = 1/6
Next, we have
Angle at the turn = 1/4
1/6 is less than 1/4
This means that the angle formed by the two hands have a measure less than 1/4 turn
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1 point
4. Find the value of x. *HINT: The sum of the interior angles of a
quadrilateral is 360°. Find the missing interior angle by subtracting the
given values from 360. Then use the fact that x forms a linear pair with the
angle next to it, so they add up to 180°. *
A. 40
B.50
C.80
Answer:
50 degrees.
(B) is correct
.............................
write an equation in slope intercept form for the line that has a slope of 1/3 and passes through the point (3, -20)
y = 1/3x - 21 is the equation of the line in slope-intercept form.
What is a slope?
Slope is a measure of the steepness or incline of a line. It describes how much the dependent variable (usually y) changes for a given change in the independent variable (usually x).
The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.
We are given that the slope is 1/3 and that the line passes through the point (3, -20). We can use the point-slope form of a linear equation to find the equation of the line:
y - y1 = m(x - x1)
where (x1, y1) is the point through which the line passes, and m is the slope. Plugging in the values we have:
y - (-20) = 1/3(x - 3)
Simplifying this equation:
y + 20 = 1/3x - 1
Subtracting 20 from both sides:
y = 1/3x - 21
This is the equation of the line in slope-intercept form.
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What is 42 divied by 1578 show the work
\( \rm\int_{ - \frac{\pi}{2} }^{ \frac{{\pi}}{2} } \frac{ \cos(x) }{1 + {cos}^{ \tan(x) } (x)} dx \\ \)
Split the integral at \(x=0\). In the integral over \(\left[-\frac\pi2,0\right]\), substitute \(x\mapsto-x\) to get
\(\displaystyle \int_{-\pi/2}^0 \frac{\cos(x)}{1 + \cos^{\tan(x)}(x)} \, dx = \int_0^{\pi/2} \frac{\cos(x)}{1 + \cos^{-\tan(x)}(x)} \, dx\)
Then we have
\(\displaystyle \int_{-\pi/2}^{\pi/2} \frac{\cos(x)}{1 + \cos^{\tan(x)}(x)} \, dx \\\\ ~~~~~~~~ = \left\{\int_0^{\pi/2} + \int_{-\pi/2}^0\right\} \frac{\cos(x)}{1 + \cos^{\tan(x)}(x)} \, dx \\\\ ~~~~~~~~= \int_0^{\pi/2} \cos(x) \left(\frac1{1+\cos^{\tan(x)}(x)} + \frac1{1 + \cos^{-\tan(x)}(x)}\right) \, dx \\\\ ~~~~~~~~ = \int_0^{\pi/2} \cos(x) \left(\frac1{1 + \cos^{\tan(x)}(x)} + \frac{\cos^{\tan(x)}(x)}{1 + \cos^{\tan(x)}(x)}\right) \, dx \\\\ ~~~~~~~~ = \int_0^{\pi/2} \cos(x) \, dx = \boxed{1}\)
Arrange the following temperatures in ascending order and descending order.
a) 37°C, -15°C, 16°C, -12°C, 0°C, 96°C, -73°C
b) 20°C, -1°C -15°C 0°C, -7°C, 23°C, -36°C.
Answer:
a) -73°C, -15°C, -12°C, 0°C, 16°C, 37°C, 96°C
a) 96°C, 37°C, 16°C, 0°C, -12°C, -15°C, -73°C
b) -36°C, -15°C, -7°C, -1°C, 0°C, 20°C, 23°C
b) 23°C, 20°C, 0°C, -1°C, -7°C, -15°C, -36°C
Graph the solution to the equations below. y = 1 4 x + 2 and y = −2x −7
A number x is less than 12.
Answer:
Step-by-step explanation:
Not completly sure what your looking for but it X would be any number lower then 12 (11,10,9,8,7,6,5,4,3.2,1)
Answer:
1-11
Step-by-step explanation:
its less than 12!
hope this is correct! c:
Given n objects, with r1 of type 1, r2 of type 2, . . . , rm of type m, where r1 + r2 + · · · + rm = n the formula for arrangement with repetition when considered as a product of combinations as in #1 above simplifies to:P(n; r1, r2, . . . , rm) = n!/( r1! r2! · · · rm!)Complete the proof. Hint: Show the details of the cancellation between the denominator of the (i − 1)-st combination and the numerator of the i-th combination in the product of combinations.
The proof that P(n; r1, r2, . . . , rm) = n!/( r1! r2! · · · rm!) is true is done by induction, which shows that the numerator of the i-th combination cancels with the denominator of the (i − 1)-st combination in the product of combinations for each i from 1 to m.
The proof that P(n; r1, r2, . . . , rm) = n!/( r1! r2! · · · rm!) is true is done by induction. We show that for each i from 1 to m, the numerator of the i-th combination cancels with the denominator of the (i − 1)-st combination in the product of combinations.
To start, we assume that the result holds for i = 1. We then have:
\(P(n; r1, r2, . . . , rm) = C(n, r1) * C(n-r1, r2) * ... * C(n-r1-r2-...-rm+1, rm) = n!/(r1!(r2!(...(rm-1)!rm!)...)\)
Now, to prove the result for i = 2, we have to show that the numerator of C(n-r1, r2) cancels with the denominator of C(n, r1). This is done by showing that:
\((n-r1)!/r2! = (n!/(r1!(n-r1)!))/r2! = (n!/(r1!r2!(n-r1-r2)!))\)
which is the required result. The same process can be repeated for each i from 1 to m, and hence the result follows for all values of i. Thus the proof is complete.
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8m + 5 + 13m – 5 = 42. What is the value of M?
Answer:
m = 2
Step-by-step explanation:
8m + 5 + 13m - 5 = 42
The 5s cancel each other out
8m + 13m = 42
21m = 42
Divide both sides by 21
m = 42/21
m = 2
1245 :- 14 me pueden ayudar porfa
A father and his two sons wanted to measure the distance between the two tallest trees in the City Garden by their footsteps. It was winter and there was a fresh snow in the garden, so they decided to start measuring from the same tree by walking one after another straight to the other tree. The father's footstep is 32 inches long, while the same for his sons is 28 inches and 24 inches. In what distance, in feet, the three footsteps would overlap first time?
the least common multiple is...
(32,28,24) = 2^5 * 3 * 7 = 672
what is the right answer??
Answer:
D: 2
Step-by-step explanation:
1(1/3) = 4/3
(4/3)/(2/3) = 4/3 * 3/2 = 12/6
12/6 simplified = 2.
Let me know if you have any questions
Answer:
2
Step-by-step explanation:
So i would reccomend using desmos calculator for problems like this because it has many symbols and there are different types if calculators to so it was easier to divide 1 1/3 by 2/3. hope this helps
please help, it’s due today.
Use the quadratic formula to solve 2x^2-5x-5=0
Show all your work
Answer:
https://www.calculatorsoup.com/calculators/algebra/quadratic-formula-calculator.php try this website, it shows a step by step solution, and is a calculator for your problem <3
Step-by-step explanation:
A population of a particular yeast cell develops with a constant relative growth rate of 0.4465 per hour. The initial population consists of 3.3 million cells. Find the population size (in millions of cells) after 4 hours. (Round your answer to one decimal place.)
Starting with an initial population of 3.3 million yeast cells and a constant relative growth rate of 0.4465 per hour, the population size reaches approximately 5.892 million cells after 4 hours.
To calculate the population size after 4 hours, we can use the formula for exponential growth:
Population size = Initial population * \((1 + growth rate)^t^i^m^e\)
Given that the initial population is 3.3 million cells and the relative growth rate is 0.4465 per hour, we can plug in these values into the formula:
Population size = 3.3 million *\((1 + 0.4465)^4\)
Calculating the exponent first:
\((1 + 0.4465)^4 = 1.4465^4\) ≈ 1.7879
Now, we can substitute this value back into the formula:
Population size = 3.3 million * 1.7879
Calculating the population size:
Population size = 5.892 million
Therefore, the population size after 4 hours is approximately 5.892 million cells.
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The force of gravity affects the mass of an object. True or False
Step-by-step explanation:
True
and the more mass the object had the greater gravitational force it is
P. S my opinion
What is the limit of (n!)^(1/n) as n approaches infinity?
Note: n! means n factorial, which is the product of all positive integers up to n.
Answer:
Step-by-step explanation:
To find the limit of (n!)^(1/n) as n approaches infinity, we can use the Stirling's approximation for n!, which is:
n! ≈ (n/e)^n √(2πn)
where e is the mathematical constant e ≈ 2.71828, and π is the mathematical constant pi ≈ 3.14159.
Using this approximation, we can rewrite (n!)^(1/n) as:
(n!)^(1/n) = [(n/e)^n √(2πn)]^(1/n) = (n/e)^(n/n) [√(2πn)]^(1/n)
Taking the limit as n approaches infinity, we have:
lim (n!)^(1/n) = lim (n/e)^(n/n) [√(2πn)]^(1/n)
Using the fact that lim a^(1/n) = 1 as n approaches infinity for any constant a > 0, we can simplify the second term as:
lim [√(2πn)]^(1/n) = 1
For the first term, we can rewrite (n/e)^(n/n) as [1/(e^(1/n))]^n and use the fact that lim a^n = 1 as n approaches infinity for any constant 0 < a < 1. Thus, we have:
lim (n/e)^(n/n) = lim [1/(e^(1/n))]^n = 1
Therefore, combining the two terms, we have:
lim (n!)^(1/n) = lim (n/e)^(n/n) [√(2πn)]^(1/n) = 1 x 1 = 1
Hence, the limit of (n!)^(1/n) as n approaches infinity is 1.
Answer:1
Step-by-step explanation:
Alice wants to use the stack method to pay down her debts listed in the table below. If she applies an extra $150 a month to her debts, what will be the first debt she targets to pay off and what will be the monthly amount she applies to it?
Debts Interest Rate Minimum Monthly Payment
Debt 1 5.5% $75
Debt 2 2.75% $250
Debt 3 13.25% $150
Alice wants to use the stack method to pay down her debts listed in the table below. If she applies an extra $150 a month to her debts, what will be the first debt she targets to pay off and what will be the monthly amount she applies to it?
Debts Interest Rate Minimum Monthly Payment
Debt 1 5.5% $75
Debt 2 2.75% $250
Debt 3 13.25% $150
The first debt that Alice would have to pay based on the Stack method would be the third debt. Option C
How to calculate the debt using the stack methodFrom the stack method, the debt that Alice would have to pay off first would be the debt that has the highest interest rate.
The amount of 150 dollars would then be added to the debt that has the second highest rate.
Hence the amount of debt that would be paid off first would be the first debt based on the stack method.
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4 + 5 = 5 + 4 shows which property?
Answer:
commutative property of addition
At the beach, 29% of people have red towels and 28% have white towels. If the rest have blue, what percentage of the people at the beach have blue towels?
Answer:
43%
Step-by-step explanation:
29% red = 29 out of 100, or 29/100
28% white = 28 out of 100, or 28/100
Take 100, subtract 28 and 29 from it and you're left with 43 out of 100, or 43%
Travel Rent-a-Car charges $135 to rent a car for 3 days. At this rate, what will it cost to rent a car for 5 days?
Answer:
So if every day the Car place makes u pay 45 dollars, all you gotta do is add 45 twice and then add it to 135, which is 225
Step-by-step explanation:
Certain radioactive material decays in such a way that the mass remaining after t years is given by the function m(t)=460e^-0.05t where m(t) is measured in grams.
1) The mass remaining after 0 years is; m(0) = 460 grams
2) The mass remaining after 45 years is; m(45) = 0.1054 grams
How to solve exponential decay functions?Exponential decay functions are defined as functions that reduce in value as the input value increases.
We are given the decay function as;
m(t) = 460e^(-0.05t)
where;
m(t) is the mass (in grams) remaining after t years
We want to find the mass at time t = 0 years
Thus;
m(0) = 460e^(-0.05 * 0)
m(0) = 460 grams
Now, after 45 years, the amount of mass remaining is;
m(45) = 460e^(-0.05 * 45)
m(45) = 0.1054 grams
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