what’s the triangle congruence shortcut

Answer:

Step-by-step explanation:

x = -2

F(x)=1.5(2)^x=0.375 , G(x)=-3(1/4)^x=-48

x=0

F(x)=1.5(2)^x=3, G(x)=-3(1/4)^x=-3

x=1/2

F(x)=1.5(2)^x=1.06 , G(x)=-3(1/4)^x=-6

Types of cardioid are Standard cardioid, Nephroid, Limacon, Deltoid, astroid, hypocycloid, and epitrochoid, each with its own unique properties and applications in mathematics and science.

A cardioid is a geometric shape that is formed by tracing a point on a circle as it rotates around another circle of the same size. There are several types of cardioids, each with its own unique properties and characteristics.

Standard cardioid: This is the most common type of cardioid and is formed by tracing a point on a circle as it rotates around another circle of the same size, with the point always being twice as far from the center of the second circle as it is from the center of the first circle.

Nephroid: This is a type of cardioid that is formed by tracing a point on a circle as it rotates around another circle that is twice its size. The name "nephroid" comes from the Greek word "nephros," which means kidney, as the shape of the curve resembles a kidney.

Limacon: This is a type of cardioid that is formed by tracing a point on a circle as it rotates around another circle that is slightly larger than itself. The shape of the curve resembles a figure eight.

Deltoid: This is a type of cardioid that is formed by tracing a point on a circle as it rotates around another circle that is three times its size. The shape of the curve resembles a triangle.

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Hey!! Glad I can help!!!

Answer:

-16.25+20=3.75

Step-by-step explanation:

the negative sign is outside the box so it does not affect the absolute value.

then do -16.25+20 and you get 3.75.

If satisfied leave a review and feel free to give brainiest.

Answer: 1. You have to solve -|16.25| first, which the answer is -16.25. 2. Now you add 20. -16.25+20=3.75

Step-by-step explanation:

Answer:

491,315.

Step-by-step explanation:

Population in 10 years = 340000(1.0375)^10

= 491,315.

Answer:

a^2 + 2ab + b^2

Step-by-step explanation:

the equation of the line tangent to f(x) = -2sin(x) at x = 34π is y = -2x + 68π + 2sin(34π).

To find the equation of the line tangent to the function f(x) = -2sin(x) at x = 34π, we need to find the slope of the tangent line at that point, and then use the point-slope form of the equation of a line.

The slope of the tangent line is equal to the derivative of the function at x = 34π. We can find the derivative of f(x) using the chain rule:

f'(x) = -2cos(x)

Therefore, f'(34π) = -2cos(34π) = -2.

This means that the slope of the tangent line is -2 at x = 34π.

To find the equation of the tangent line, we also need a point on the line. Since the tangent line passes through the point (34π, f(34π)), we can use this point as the point-slope form of the equation of the line:

y - f(34π) = m(x - 34π)

Substituting the values we have found, we get:

y - (-2sin(34π)) = -2(x - 34π)

Simplifying, we get:

y = -2x + 68π + 2sin(34π)

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The equilibrium solutions of the nonhomogeneous linear system are y(t) = [-1/12] + c[1]

The system: y'(t) = [-33/3 -3/3]y(t) + [-2/2]

Setting y'(t) = 0, we have:

0 = [-33/3 -3/3]y(t) + [-2/2]

Simplifying the equation, we get:

0 = [-11 -1]y(t) + [-1]

This equation can be rewritten as:

0 = -11y(t) - y(t) - 1

Combining like terms, we have:

0 = -12y(t) - 1

To solve for y(t), we isolate y(t) by dividing both sides by -12:

0 = y(t) + 1/12

Therefore, the equilibrium solution is y(t) = -1/12.

In the form y(t) = [] + c[], the equilibrium solution is y(t) = [-1/12] + c[1].

So, the equilibrium solutions of the nonhomogeneous linear system are y(t) = [-1/12] + c[1], where c is any constant.

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The correct option is c) Easier interpretation. One of the main advantages of simple models is their ease of interpretation. Simple models tend to have fewer parameters and less complex mathematical equations, making it easier to understand and interpret how the model is making predictions.

This interpretability can be valuable in various domains, such as medicine, finance, or legal systems, where it is important to have transparent and understandable decision-making processes.

Complex models, on the other hand, often involve intricate relationships and numerous parameters, which can make it challenging to comprehend the underlying reasoning behind their predictions. While complex models can sometimes offer higher accuracy or make more detailed predictions, they often sacrifice interpretability in the process.

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Yes it is possible to make the prediction about Ramiro's School but not completely.

It is possible to use the information from Ramiro's sample to make predictions about the school-wide results, but it is important to note that the sample may not be fully representative of the entire population of students at the school. There may be sampling biases or other factors that affect the results.

With that said, based on the information provided, we can calculate the proportion of students in Ramiro's sample who use the library in a certain way, and then use that proportion to estimate the number of students at the school who use the library in that way.

For example, if Ramiro's sample shows that 40 out of the 60 people he surveyed use the library to study, we can estimate that approximately 40/60 = 67% of the school's students use the library to study. We can then use this proportion to estimate that approximately 540 x 67% = 361 students at the school use the library to study.

It's important to note that these predictions are based on sample data and they may not be accurate. To make more accurate predictions, a larger, more representative sample would be needed.

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Answer:

1378

Step-by-step explanation:

once you’ve decided on your New Year’s resolutions, the best way to make sure you actually follow through is by developing a plan for how to accomplish your new goals.

For anyone with “saving money” at the top of their list in 2020, the 52-week money challenge is a simple and effective way to stay on track. And at the end of the year, you’ll have $1,378 extra dollars to bulk up your emergency savings or put towards next year’s vacation.

Take some time now to determine what, exactly, you want to save for so you’ll be more motivated to stay the course throughout the year. Once your savings goals are set, jump in and start saving with the 52-week money challenge.

What is the 52-week money challenge?

Using the 52-week money challenge, you should deposit an increasing amount of money each week for one year.

Match each week’s savings amount with the number of the week in your challenge. In other words, you’ll save $1 the first week, $2 the second week, $3 the third week, and so on until you put away $52 in week 52. You can also get creative with the amount you save each week if you’d like to save more over the year or you don’t have enough extra cash available for the regular challenge.

If you stick to this challenge throughout the entire year, you’ll save a total of $1,378.

WEEK NUMBER WEEKLY DEPOSIT TOTAL SAVINGS

Week 1 $1 $1

Week 2 $2 $3

Week 3 $3 $6

Week 4 $4 $10

Week 5 $5 $15

Week 6 $6 $21

Week 7 $7 $28

Week 8 $8 $36

Week 9 $9 $45

Week 10 $10 $55

Week 11 $11 $66

Week 12 $12 $78

Week 13 $13 $91

Week 14 $14 $105

Week 15 $15 $120

Week 16 $16 $136

Week 17 $17 $153

Week 18 $18 $171

Week 19 $19 $190

Week 20 $20 $210

Week 21 $21 $231

Week 22 $22 $253

Week 23 $23 $276

Week 24 $24 $300

Week 25 $25 $325

Week 26 $26 $351

Week 27 $27 $378

Week 28 $28 $406

Week 29 $29 $435

Week 30 $30 $465

Week 31 $31 $496

Week 32 $32 $528

Week 33 $33 $561

Week 34 $34 $595

Week 35 $35 $630

Week 36 $36 $666

Week 37 $37 $703

Week 38 $38 $741

Week 39 $39 $780

Week 40 $40 $820

Week 41 $41 $861

Week 42 $42 $903

Week 43 $43 $946

Week 44 $44 $990

Week 45 $45 $1,035

Week 46 $46 $1,081

Week 47 $47 $1,128

Week 48 $48 $1,176

Week 49 $49 $1,225

Week 50 $50 $1,275

Week 51 $51 $1,326

Week 52 $52 $1,378

Component 3 must be started on day 197 to meet the delivery date of day 200.

To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.

(a) Backward schedule:

Operation    |  Work Center  |  Time (hours)  |  Start Day

--------------------------------------------------------

Final Assembly |   Work Center 1  |        1       |     200

Sub-assembly 1 |   Work Center 2  |        2       |     199

Component 4     |   Work Center 3  |        3       |     197

Component 2     |   Work Center 4  |        4       |     196

Component 3     |   Work Center 5  |        3       |     ????

(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.

From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.

Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.

Hence, component 3 must be started on day 197 to meet the delivery date of day 200.

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Answer:

3

Step-by-step explanation:

Answer:

3b/2 + 3

Step-by-step explanation:

The formula to calculate perimeter of rectangle is 2l + 2w

The length is half the width so length is 1/2 (b/2 +1), which when simplified is b/4 + 1/2

Using the formula to calculate perimeter you can substitute and calculate

p= 2l + 2w

p= 2(b/4 + 1/2) + 2(b/2 + 1)

p= 2b/4 +2/2 + 2b/2 +2

p= 1/2b + 1 + b + 2

p= 3/2b + 3

Simplified it's 3b/2 +3

Step-by-step explanation:

I'm sorry, but the statement you provided is not correct. The transitive property of angle congruence actually states that if ∠QRS ≅ ∠PQR and ∠PQR ≅ ∠XYZ, then ∠QRS ≅ ∠XYZ. In other words, if two angles are congruent to a third angle, then they are congruent to each other.

So, in your statement, if ∠QRS ≅ ∠PQR and ∠PQR ≅ ∠XYZ, then you can conclude that ∠QRS ≅ ∠XYZ.

Main answer:Long multiplication is a method of multiplying two difficult-to-multiply numbers.

supporting answer:

what is multiple long?

Finding the product is not always this simple. In such cases, the long method of multiplication is used.

body of the answer:

let us understand long multiplication by taking an example

     6.Add the two partial products

final answer: by following above steps we can perform long multiplication

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Long multiplication is a method of multiplying two difficult-to-multiply numbers.

What is multiple long?

Finding the product is not always this simple. In such cases, the long method of multiplication is used.

Let us understand long multiplication by taking an example

1. Write the two numbers one beneath the other in the order of their digits. On top, write the larger number, and on the left, a multiplication sign.

2. Multiply the top number's one digit by the bottom number's one digit.

3. Put a 0 below the one's digit,

4. Multiply the top number's ones digit by the bottom number's tens digit.

5. Multiply the top number's tens digit by the bottom number's tens digit.

6. Add the two partial products

By following the above steps we can perform long multiplication

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Two methods...

How can we divide easily by 5?

We know

Then

The common method

The probability that , Xb exceeds Xa , by 3.0 or more if ub and ua, are equal is 0.2537.

The probability of an occurrence is a figure that represents how likely it is that the event will take place. In terms of percentage notation, it is stated as a number between 0 and 1, or between 0% and 100%. The higher the likelihood, the more probable it is that the event will take place.

Probability is a way to gauge how likely something is to happen. Several things are difficult to forecast with absolute confidence. With it, we can only make predictions about the likelihood of an event happening, or how likely it is.

n1 = n2 = 25,

hypothesis,

standard error for difference,

\(\sqrt{\frac{16^2}{25} +\frac{16^2}{25} }\)

=4.525

z =(3-0)/4.525

z=0.663

P(z ≥ 0.663) = 0.2537.

No, there is not strong evidence that \(\mu _B\) is greater than \(\mu _A\).

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Complete question;

A consumer electronics company is comparing the brightness of two different types of picture tubes for use in its television sets. Tube type A has mean brightness of 100 and standard deviation of 16, and tube type B has unknown mean brightness, but the standard deviation is assumed to be identical to that for type A. A random sample of n = 25 tubes of each type is selected, and X -X, is computed. If u, equals or exceeds u,, the manufacturer would like to adopt type B for use. The observed difference is X,X, - 3.0. a. What is the probability that , exceeds X, by 3.0 or more if ug and u, are equal? b. Is there strong evidence that ug is greater than u,?

The minimum ratio of cation to anion size for an octahedral (6-fold coordinated) site to be stable is 0.414.

The minimum ratio of cation to anion size for an octahedral (6-fold coordinated) site to be stable is 0.414 can be shown by using the radius ratio rules.

The radius ratio rules state that the ratio of the radius of the cation to the radius of the anion determines the coordination number and the structure of the compound. The minimum and maximum radius ratios for different coordination numbers are as follows:

- Coordination number 2: minimum ratio = 0.155, maximum ratio = 0.225
- Coordination number 3: minimum ratio = 0.225, maximum ratio = 0.414
- Coordination number 4: minimum ratio = 0.414, maximum ratio = 0.732
- Coordination number 6: minimum ratio = 0.732, maximum ratio = 1.000

For an octahedral (6-fold coordinated) site, the minimum ratio of cation to anion size is 0.732. If the ratio is smaller than this, the cation will be too small to fit into the octahedral site and the structure will be unstable. Therefore, the minimum ratio of cation to anion size for an octahedral (6-fold coordinated) site to be stable is 0.414.

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The distance between (8, 24) and (12, 36) is one-third of the distance between (0, 0) and (12, 36).

We know that:

And point B is between these two, such that:

OA/BA = 3

Meaning, OA is 3 times BA.

Now, if we apply a factor of 1/3 to point A, we get:

(12/3, 36/3) = (4, 12)

So, the distance between A and B is equal to the distance between the origin and (4, 12) (a change of 4 units in the x-component and 12 units in the y-component).

The point that meets that condition is (8, 24), which is given by multiplying by 2 the previous coordinates.

The distance between (8, 24) and (12, 36) is one-third of the distance between (0, 0) and (12, 36).

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Answer:

\((a)\ x = 3y - 2\)

\((b)\ y = -3x - 2\)

\((e)\ 3y - x = -2\)

Step-by-step explanation:

Given

\(y =3x -2\)

Required

Equations that can create consistent and independent systems

For a pair of equation to have consistent and independent systems, the equations must have different slopes.

An equation of the form \(y = mx + c\) has m has its slope.

In \(y =3x -2\)

\(m = 3\) --- slope

Considering the options

\((a)\ x = 3y - 2\)

Make y the subject

\(x = 3y - 2\)

\(3y = x+2\)

Divide by 3

\(y = \frac{1}{3}x+\frac{2}{3}\)

The slope is:

\(m_1 = \frac{1}{3}\)

Hence, (a) can make a consistent and independent system with \(y =3x -2\)

\((b)\ y = -3x - 2\)

The slope is:

\(m= -3\)

Hence, (b) can make a consistent and independent system with \(y =3x -2\)

\((c)\ y = 3x + 2\)

The slope is:

\(m=3\)

Hence, (c) cannot make a consistent and independent system with \(y =3x -2\)

\((d)\ 6x - 2y = 4\)

Make y the subject

\(2y = 6x -4\)

Divide by 2

\(y = 3x -2\)

The slope is

\(m =3\)

Hence, (d) cannot make a consistent and independent system with \(y =3x -2\)

\((e)\ 3y - x = -2\)

Make y the subject

\(3y = x -2\)

Divide by 3

\(y = \frac{1}{3}x -\frac{2}{3}\)

The slope is:

\(m = \frac{1}{3}\)

Hence, (e) can make a consistent and independent system with \(y =3x -2\)

The variance-stabilizing transformation of Yi in linear regression can be found using the Fisher transformation. By taking the square root of the variance of Yi and dividing it by the expectation of Yi, we can apply the inverse hyperbolic tangent function to obtain the transformed Yi.

This results in the expression: tanh^-1(sqrt(V ar(Yi))/E[Yi]). This transformation is useful because it stabilizes the variance of Yi, making it easier to analyze and model. It allows us to make more accurate predictions and inferences about the relationship between the predictors and the response variable in linear regression.

We can find the variance-stabilizing transformation of Yi as follows:

1. Take the square root of both sides of the equation:
sqrt(V ar(Yi)) = sqrt((E[Yi])^2)

2. Simplify the equation:
sqrt(V ar(Yi)) = E[Yi]

3. Define the transformation function, T(Yi), which transforms Yi into the square root of its variance:
T(Yi) = sqrt(Yi)

So, the variance-stabilizing transformation of Yi is T(Yi) = sqrt(Yi). By applying this transformation, the relationship between predictors and Yi should exhibit more constant variance, improving the performance of the linear regression model.

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Answer: Just dropout

Step-by-step explanation: What kinda classes are you taking

Answer: do it by your self and marry Christmas you filthy animal.

Step-by-step explanation:

Answer:

The number of grams of fat in each portion of fried shrimp

Step-by-step explanation:

See attached image.

Answer: The number of grams of fat in each portion of fried shrimp

Step-by-step explanation:

Since Y = 1/X, then X = 1/Y. The PDF of Y, g(y) is 4/y⁵, where 0 < y ≤ 1. If Y < 0 or y > 1, the PDF of Y is equal to z of Y, g(y) is 4/y⁵, where 0 < y ≤ 1. If Y < 0 or y > 1, the PDF of Y is equal to zero.

The PDF of X is given by fx(x) = { 4x³, 0 < x ≤ 1}When 0 < Y ≤ 1, the values of X would be 1/Y < x ≤ ∞ .Thus, the PDF of Y, g(y) would be g(y) = fx(1/y) × |dy/dx| where;dy/dx = -1/y², y < 0 (since X ≤ 1, then 1/X > 1). The absolute value is used since the derivative of Y with respect to X is negative. Note that;g(y) = 4[(1/y)³] |-(1/y²)|g(y) = 4/y⁵ , 0 < y ≤ 1. The PDF of Y is 4/y⁵, where 0 < y ≤ 1. When Y < 0 or y > 1, the PDF of Y is equal to zero. The above can be verified by integrating the PDF of Y from 0 to 1.

∫ g(y) dy  = ∫ 4/y⁵ dy, from 0 to 1∫ g(y) dy  = (-4/y⁴) / 4, from 0 to 1∫ g(y) dy  = -1/[(1/y⁴) - 1], from 0 to 1∫ g(y) dy  = -1/[(1/1⁴) - 1] - (-1/[(1/0⁴) - 1])∫ g(y) dy  = -1/[1 - 1] - (-1/[(1/0) - 1])∫ g(y) dy  = 1 + 1 = 2. From the above, it can be observed that the integral of g(y) is equal to 2, which confirms that the PDF of Y is valid. The PDF of Y, g(y) is 4/y⁵, where 0 < y ≤ 1. If Y < 0 or y > 1, the PDF of Y is equal to zero.

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The measure of angle B is approximately 42°.

Use the given ratios to determine the measure of the variable in each problem.

Round angles to the nearest degree and lengths to the nearest tenth.

A = 50°, b = 12, c = 14

We can use the law of cosines to find angle B.

The law of cosines states that c² = a² + b² - 2abcos(C),

where C is the angle opposite side c.

We can rearrange this formula to find cos(C):

cos(C) = (a² + b² - c²) / 2ab

Now, we can substitute the given values and solve for cos(C):

cos(B) = (12² + 14² - 20²) / (2 × 12 × 14)

cos(B) = 0.7436

Now, we can use the inverse cosine function to find angle B:

B = cos⁻¹(0.7436)B = 41.6°

Therefore, the measure of angle B is approximately 42°.

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The amount accumulated after investing a principal P for t years at an interest rate compounded annually is  $46,057.58.

Compound interest is the interest you earn on interest. Compound interest is the interest calculated on the principal and the interest accumulated over the previous period.

Therefore, let's find the amount accumulated after investing a principal P for t years at an interest rate compounded annually.

\(A = p(1 + \frac{r}{n} )^{nt}\)

where

p = 15,500

r = 9.5%

t = 12

n = 1

\(A = 15500(1 + \frac{0.095}{1} )^{1(12)}\)

A = 15,500.00(1 + 0.095)¹²

A = $46,057.58

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$46,057.58, answer for acellus

Answer:

>

Step-by-step explanation:

because

16/24 > 9/24 :)

The formula for the volume of a cone, V = (1/3)·π·r²·h, indicates that doubling the radius, quadruples the volume while doubling the height doubles the volume. Therefore;

A cone is a three dimensional figure formed by lines that extend between a point and the circumference of the circular base, where the point is located on the a line perpendicular to and passing through the center of the circular base.

The formula for the volume of a cone is; V = (1/3) × π × r² × h

Where;

V = The volume of the cone

r = The radius of the cone

h = The height of the cone

Therefore;

When the radius is doubled, we get;

V₁ = (1/3) × π × (2·r)² × h = (1/3) × π × 4 × r² × h = 4 × (1/3) × π × r² × h

When the radius of the cone is doubled, the volume of the cone increases 4 times the initial volume

When the height of the cone is doubled, we get;

V₂ = (1/3) × π × r² × 2·h = 2 × (1/3) × π × r² × h = 2·V

When the height of the cone is doubled, the volume of the cone is doubled.

Therefore, doubling the radius of the cone which increases the volume to four times the initial volume has the greater effect on the volume of the cone than doubling the height which doubles the volume of the cone.

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