What's the endianness of a computing system? (7 point)"

The pressure difference across the sensor housing will be "95 kPa".

According to the question, the values are:

Altitude,

Speed,

Pressure,

The temperature will be:

→ \(T = 15.04-[0.00649(9874)]\)

→     \(= 15.04-64.082\)

→     \(= -49.042^{\circ} C\)

now,

→ \(P_o = 101.29[\frac{(-49.042+273.1)}{288.08} ]^{(5.256)}\)

→      \(= 27.074\)

hence,

→ The pressure differential will be:

= \(122-27\)

= \(95 \ kPa\)

Thus the above solution is correct.

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Answer:

Abolition of intermediaries (rent collectors under the pre-Independence land revenue system); Tenancy regulation (to improve the contractual terms including the security of tenure); A ceiling on landholdings (to redistributing surplus land to the landless);

Types of Land Reform

Abolition of Intermediaries

The first step taken by the Indian government under land reforms post-independence was passing the Zamindari Abolition Act. The primary reason of a backward agrarian economy was the presence of intermediate entities like, jagirdars and zamindar who primarily focussed on collecting sky-rocketing rents catering to their personal benefits, without paying attention to the disposition of farms and farmers. Abolition of such intermediaries not only improved conditions of farmers by establishing their direct connection with the government but also improved agricultural production.

Regulation of Rents

This was in direct response to the unimaginably high rents which were charged by intermediaries during British rule, which resulted in a never-ending cycle of poverty and misery for tenants. Indian government implemented these regulations to protect farmers and labourers from exploitation by placing a maximum limit on the rent that could be charged for land.

Tenure Security

Legislations were passed in all states of the country to grant tenants with permanent ownership of lands and protection from unlawful evictions on expiry of the lease. This law protects tenants from having to vacate a property immediately after their tenure is over unless ordered by law. Even in that case, ownership can be regained by tenants with the excuse of personal cultivation.

Answer:45

Explanation:

because i am gay

Answer:

true

I hope it helps mate

I will always help you understanding your assingments

enjoy your day

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Function definition for allocate3(int* &p1, int* &p2, int* &p3):The allocate3(int* &p1, int* &p2, int* &p3) function is a C++ function that takes in three pointers of type int as input parameter.

This function dynamically allocates an array of three integers using the new operator, which returns a pointer to the first element of the array. It then assigns the first, second, and third elements of the array to the three input pointers, respectively.

The allocate3(int* &p1, int* &p2, int* &p3) function in C++ is a function that takes in three pointers of type int as input parameters. The function is designed to allocate a block of memory with enough space for three integers and initialize the three pointers to point to the three integers. The function doesn't return anything as it just initializes the input pointers to point to the three integers that are allocated.

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Answer:

R = 20Ω

L = 0.1 H

C = 1 × 10⁻⁵ F

Explanation:

Given the data in the question;

Vs = 10∠30°V   { peak value }

V"s\(_{rms\) = 10/√2 ∠30° V

resonance freq w₀ = 10³ rad/s

Average Power at resonance Power\(_{avg\)  = 2.5 W

Q = 5

values of R, L, and C = ?

We know that;

Power\(_{avg\) = |V"s\(_{rms\)|² / R

{ resonance circuit is purely resistive }

we substitute

2.5 = (10/√2)² × 1/R

2.5 = 50 × 1/R

R = 50 / 2.5

R = 20Ω

We also know that;

Q = w₀L / R

we substitute

5 = ( 10³ × L ) / 20

5 × 20 = 10³ × L

100 = 10³ × L

L = 100 / 10³

L = 0.1 H

Also;

w₀ = 1 / √LC

square both side

w₀² = 1 / LC

w₀²LC = 1

C = 1 / w₀²L

we substitute

C = 1 / [ (10³)² × 0.1 ]

C = 1 / [ 1000000 × 0.1 ]

C = 1 / [ 100000 ]

C = 0.00001 ≈ 1 × 10⁻⁵ F

Therefore;

R = 20Ω

L = 0.1 H

C = 1 × 10⁻⁵ F

When hand-propping a small aircraft engine, safety procedures must be observed.

The following are safety procedures that should be followed when hand-propping a small aircraft engine:-

1. Keep the ignition switch off when preparing to hand-prop the engine.

2. Both pilot and propeller hand-proper are required to wear hearing protection.

3. Check the surrounding area before starting the engine to ensure that nobody is near the aircraft.

4. Use a chock block to stop the airplane from moving.

5. Confirm that the brakes are on, the throttle is in the idle position, and the mixture control is set to full rich.

6. Engage the pilot's assistant to remove the propeller brakes while keeping clear of the aircraft.

7. The pilot should not touch the propeller during the engine's start-up phase.

8. After the engine starts, remove the chock blocks and check the engine's systems before taking off.

These are the safety procedures that must be followed when hand-propping a small aircraft engine.

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Answer:

2.9237 ft/s

Explanation:

Given the data in the question;

A₁ = 9-inch × 9-inch = 81 in² = 81 / 144 = 0.5625 ft²

V₁ = 6.1 ft/s

A₂ = 13 in × 13 in = 169 in² = 1.17361 ft²

v₂ = ?

using the the equation if continuity

( Rate of volumetric flow is constant )

A₁V₁ = A₂V₂

we substitute

0.5625 ft² × 6.1 ft/s = 1.17361 ft² × V₂

3.43125 ft³/s = 1.17361 ft² × V₂  

V₂  = 3.43125 ft³/s  / 1.17361 ft²

V₂ = 2.9237 ft/s

Therefore, the speed of the air flowing into the room is 2.9237 ft/s

The non-linearity error as a percentage of the full-scale reading at 100 degree C  is - 0.89%.

Non-linearity error is defined as the biggest deviation from a straight line linking the output signal to the applied force, known as the "best straight," that the calibration curve makes. In order to eliminate second order nonlinearity, the sensor signal conditioning system feeds a portion of the output signal back to the sensor.

If EMF and Celsius temperature have a proportional relationship, then the recorded value of EMF at 100 °C will be understood to be a temperature of.

T/5.268 = 400/21.846

T = 5.268(400/21.846) ≈ 96.457 °C

As a percentage of the full scale, the mistake is

(96.457 -100)/400 × 100% ≈ -0.886%

Thus, the non-linearity error as a percentage of the full-scale reading at 100 degree C  is - 0.89%.

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The answer to Question 37 is false. When there is a concentration of X-ray machines in one building, scatter radiation can become a problem. Scatter radiation is the radiation that is produced when the X-rays interact with matter in the body or in the surrounding environment. This can cause the X-rays to bounce off of objects and walls, creating secondary radiation that can be harmful to people who are not directly involved in the imaging process.

When there are multiple X-ray machines in a building, the amount of scatter radiation can increase significantly. This is because the X-rays from one machine can interact with the other machines, creating a cumulative effect. The more machines there are, the more radiation there is to scatter. This can be a particular problem in small buildings, where the radiation can accumulate quickly and create a hazardous environment for anyone who is in the building.

To reduce the risk of scatter radiation in a building with multiple X-ray machines, it is important to ensure that each machine is properly shielded and that there is adequate space between the machines. This can help to minimize the amount of scatter radiation that is produced and keep everyone in the building safe.

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Answer:

the output of the IF amplifier consist of 675 kHz

Explanation:

Given the data in the question;

AM signal carrier frequency \(_{RF\)  = 460 kHz

Local oscillator frequency\(_{lo\) = 1135 kHz

Now, The output of the IF amplifier consists of difference of local oscillator frequency & AM carrier signal frequency;

FREQUECY\(_{IF\) = FREQUECY\(_{lo\) - FREQUECY\(_{RF\)

so we substitute in our given values

FREQUECY\(_{IF\) = 1135 kHz - 460 kHz

FREQUECY\(_{IF\) = 675 kHz

Therefore, the output of the IF amplifier consist of 675 kHz

When declaring an array local variable, it is important to specify the variable name, data type, and array size in the correct order. In this case, option B follows the correct syntax and defines an array local variable consisting of 50 signed words.

The correct answer is B. This statement defines an array local variable consisting of 50 signed words. The syntax for declaring an array local variable is as follows: LOCAL :[]. In this case, the variable name is "wArray," the data type is "SWORD" (a signed word), and the array size is 50. Therefore, option B correctly defines an array local variable consisting of 50 signed words.

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Answer:

d

Explanation:

HDMI and Display Port are two types of ports that transmit both digital audio and digital video with a single connector.  They provide high-quality audio and video signals, so they are used to connect devices like gaming consoles, computers, Blu-ray players, and televisions.

What is DisplayPort?

A display port is a digital audio-visual interface for sending video signals and digital audio between devices. DisplayPort (DP) is a digital interface standard developed by the Video Electronics Standards Association (VESA). The technology is designed to provide audio and video signals over a single connection.

They are often found on high-end monitors and graphics cards as well as high-end laptop and desktop computers.

What is HDMI?

HDMI stands for High Definition Multimedia Interface, and it is a digital interface that allows you to send uncompressed audio and video data from one device to another. It was first introduced in 2003 and has since become the standard for audio and video connectivity in the home theater industry.

It is used to connect devices such as TVs, Blu-ray players, and game consoles. HDMI supports resolutions up to 4K (3840x2160) and is capable of transmitting both audio and video signals over a single cable.

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A 30 m long, 1.3 cm diameter pipe carrying water spills its contents into the environment. Find the mass flow rate and Reynolds number of the pipe flow if the pressure at the pipe's entry is 0.82 kPa gage. You can assume that water has a density of 998 kg/m3 and a viscosity of 1.01*10n-s/m2, respectively. Clearly show whether the flow is laminar

The main element of the hydrosphere on Earth is water, which is also the fluid used by all known living creatures. It is a clear, flavorless, odorless, and nearly colorless inorganic compound. Even though it doesn't offer food, energy, or organic micronutrients, it is necessary for all currently understood forms of life. Its molecules have the chemical formula H2O and are composed of two hydrogen atoms bound together by covalent bonds. The hydrogen atoms are linked to the oxygen atom at a 104.45° angle. Water is also the name for H2O in its liquid state at normal pressure and temperature. There is water everywhere in the natural world.

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The point coordinates for all atoms that are associated with the FCC unit  cell, i.e. fig b are:

bottom face: (1,0,0) (1,1,0) (0,1,0) (1/2,1/2,0)

Tope face: (0,0,1) (1,0,1) (1,1,1) (0,0,1) (1/2,1/2,1)

front and back face: (1/2,1,1/2) (1/2,0,1/2)

Left and Right face: (0,1/2,1/2) (1,1/2,1/2)

Atoms are found in an FCC unit cell at the centre of each cube's face and at each of the crystal lattice's four corners. Only half of each atom, which is located at the face centre, belongs to one particular cell and is shared by two adjacent unit cells.

A crystal lattice in an FCC unit cell contains atoms in each corner. Additionally, every cube face has an atom in the centre of it. Two next-to-one another unit cells share this face-center atom. A unit cell only contains 12 of each atom.

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The discharge of the pump is approximately 0.0744 cubic meters per second.

To determine the discharge of the centrifugal pump, we need to consider the head, impeller diameter, outlet width, and the manometric efficiency.

Given:

Net head (H) = 14.5 m

Impeller diameter (D) = 300 mm = 0.3 m

Outlet width (W) = 50 mm = 0.05 m

Manometric efficiency (η) = 95% = 0.95

The discharge (Q) can be calculated using the following formula:

Q = (π/4) * D^2 * W * N / (g * H * η)

where:

π = 3.14159 (pi)

D = Impeller diameter

W = Outlet width

N = Speed of the pump in revolutions per minute (rpm)

g = Acceleration due to gravity (9.81 m/s^2)

H = Net head

η = Manometric efficiency

Substituting the given values into the formula:

Q = (3.14159/4) * (0.3)^2 * 0.05 * 1000 / (9.81 * 14.5 * 0.95)

Simplifying the equation:

Q ≈ 0.0744 m^3/s

Therefore, the discharge of the pump is approximately 0.0744 cubic meters per second.

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To declare a prototype for a function named "tripleIt" in C++ that accepts a pointer to an integer and can be used as specified.

The following statement is to be written to declare the prototype:
void tripleIt(int *x);
This prototype indicates that the function "tripleIt" accepts a pointer to an integer as its argument and returns no value (void). You can then define and use the function as follows:
#include
// Function prototype
void tripleIt(int *x);
int main() {
   int x = 5;
   tripleIt(&x); // x is now equal to 15
   std::cout << "Value of x: " << x << std::endl;
   return 0;
}
// Function definition
void tripleIt(int *x) {
   *x *= 3;
}
In this example, the "tripleIt" function takes the address of the integer 'x' and multiplies its value by 3.

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Answer:

The main reason for bridges collapses is: earthquakes (natural disasters) and construction incidents. Whenever a natural disaster occur, it makes the bridge collapse. An example is hurricanes. Hurricanes come with a great wind and that might lead to the bridge collapsing. Construction incidents means the bridge falls during construction. Those who are employed in health, safety and environmental management need to make sure that during the construction, they have examined the material and made sure it is strong. Working with economists, they should seek better understanding of the methods for minimizing the costs during the life of the bridge. In case for natural disasters, like flooding, they should make the bridge in a lever where the water won't reach the bridge. And they should have a limit for weight in the bridges because that is another reason it collapses, because the bridge does not support extra weight.

Explanation:

hope this helps

The type of member function that may be called from a statement outside the class is a public function. Public functions are accessible from outside the class and can be called by any part of the program.

This is in contrast to private functions, which are only accessible from within the class and cannot be called from outside the class. In addition, there is another term that is related to public and private functions, which is "global".

Global functions are functions that are not part of a class and can be accessed from anywhere in the program. They are similar to public functions in that they are accessible from outside the class, but they are not part of any specific class.

It is important to use public and private functions to control the access to the members of a class. Public functions are used to provide an interface to the class that can be accessed from outside the class, while private functions are used to encapsulate the implementation details of the class and are not accessible from outside the class. This helps to prevent the accidental modification of the internal state of the class by external code, which can lead to unexpected behavior and bugs in the program.

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To determine what type of member function can be called from a statement outside class:

The type of member function that may be called from a statement outside the class is a "public" function.

Public member functions can be accessed from outside the class, allowing other parts of the code to interact with the class and use its functionality.

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The theoretical density of diamond given that the C-C distance and bond angle are 0.154 nm and 109.5° respectively is; 3.54 g/cm³

The first thing we will do is to get the unit cell edge length from the given C - C distance.

From the structure of diamond;

Φ = ¹/₂ * bond angle

Φ = ¹/₂ * 109.5°

Φ = 54.75°

Thus;

θ = 90° - 54.75°

θ = 35.25°

Let the height from a point to the base of the cube of the structure be x. Thus;

x = a/4 = y sin θ

where a is unit cell edge length and y is C -C length. Thus;

a = 4y sin θ

a = 4 * (0.154 * 10⁻⁹) * sin 35.25°

a = 3.56 * 10⁻⁸ cm

The unit cell volume is;

V_c = a³

Thus; V_c = (3.56 * 10⁻⁸)³

V_c = 4.51 * 10⁻²³ cm³

Now, there are 8 equivalent atoms per unit cell and as such density is calculated from;

ρ = (n * A_c)/(V_c * N_a)

A_c is atomic weight of diamond = 12.01 g/mol

N_a is avogadro's number = 6.022 * 10²² atoms/g

Thus;

ρ = (8 * 12.01)/(4.51 * 10⁻²³ * 6.022 * 10²²)

ρ = 3.54 g/cm³

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The stress-strain curve is a graphical representation of the relationship between the stress and strain in a material. The stress is the force applied per unit area and the strain is the deformation or change in length of the material.

The curve can be used to determine various properties of the material, such as its proportional limit, modulus of elasticity, yield stress, and ductility.

The proportional limit is the maximum stress that a material can withstand without deviating from a linear relationship between stress and strain. This is the point where the stress-strain curve becomes non-linear and is an indicator of the material's stiffness.

The modulus of elasticity, also known as Young's modulus, is a measure of the stiffness of a material. It is the slope of the linear portion of the stress-strain curve and is a measure of how much the material will deform under a given load.

The yield stress, also known as the yield point, is the stress at which a material begins to deform permanently. This is the point where the stress-strain curve changes from a linear relationship to a non-linear relationship.

The yield stress at 0.2% offset is the stress at which a material deforms by 0.2% of its original length, while still retaining its original shape after the load is removed. This is a measure of the material's ductility, which is the ability of a material to deform plastically before breaking.

If the material exhibits a large amount of plastic deformation before breaking, it is considered ductile. If it exhibits little or no plastic deformation before breaking, it is considered brittle.

In conclusion, the stress-strain curve is a useful tool for characterizing the mechanical properties of materials, including the proportional limit, modulus of elasticity, yield stress, and ductility. Understanding these properties is important for designing and selecting materials for specific applications.

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The National Electrical Code (NEC) and the National Electrical Manufacturers Association (NEMA) establish standards for the ratings, types, classifications, and testing procedures for fuses and circuit breakers in electrical circuits.

These organizations work together to ensure the safe and efficient operation of electrical systems and equipment, and their standards help to prevent electrical hazards and maintain consistent performance across the industry.

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The time complexity of this solution is O(n), where n is the length of the input string, as we iterate through the string once. The space complexity is O(1), as the extra space used is constant regardless of the input size.

Here's the solution in Java that meets the given requirements:

import java.util.*;

public class StrongPasswordSubset {

   public static int findStrongPasswordSubsetLength(String input) {

       int maxLength = 0;

       int currentLength = 0;

       int[] charCount = new int[26];

       for (int i = 0; i < input.length(); i++) {

           char c = input.charAt(i);

           if (charCount[c - 'a'] > 0) {

               Arrays.fill(charCount, 0);

               currentLength = 0;

           }

           charCount[c - 'a']++;

           currentLength++;

           maxLength = Math.max(maxLength, currentLength);

       }

       return maxLength;

   }

   public static void main(String[] args) {

       String input1 = "abc-abc>bəb";

       int result1 = findStrongPasswordSubsetLength(input1);

       System.out.println("Input: " + input1);

       System.out.println("Output: " + result1);

       String input2 = "spowow>k->e-w";

       int result2 = findStrongPasswordSubsetLength(input2);

       System.out.println("Input: " + input2);

       System.out.println("Output: " + result2);

   }

}

This solution uses an array charCount to keep track of the count of each character encountered so far. Whenever a character is encountered that has already appeared before, it resets the charCount array and the current length of the subset. The maximum length seen so far is updated at each step. The final result is the maximum length of the strong password subset.

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Answer:

Steampunk Mechanical

Explanation:

Your welcome

The nominal interest rate compounded quarterly for the second investment is approximately 71.84%. At the end of approximately 3.525 years, Engr. Santos will receive the same amount from the first investment as he will receive at the end of 5 years from the second investment.

To solve this problem, we can set up two equations based on the given information and then solve for the unknowns.  Let's denote the initial investment amount as "P."

1. Nominal interest rate compounded quarterly of the second investment:

Since the first investment earns 8.55% compounded semi-annually, we can find the effective annual interest rate by using the formula for compound interest:

Effective Annual Interest Rate = (1 + (Nominal Interest Rate / Number of Compounding Periods)) ^ Number of Compounding Periods - 1

For the first investment:

Nominal Interest Rate = 8.55%

Number of Compounding Periods = 2 (compounded semi-annually)

Effective Annual Interest Rate = (1 + (0.0855 / 2)) ^ 2 - 1 = 0.0876 = 8.76% (approx.)

Now, for the second investment, let's assume the nominal interest rate compounded quarterly is "r."

After 8 years, the amount in the first investment will be twice that of the second investment:

P * (1 + 0.0876) ^ 16 = 2 * P * (1 + (r / 4)) ^ 32

Simplifying the equation:

(1.0876) ^ 16 = 2 * (1 + (r / 4)) ^ 32

Taking the 16th root of both sides:

1.0876 = 2 ^ (1/16) * (1 + (r / 4)) ^ (32/16)

Now, we can solve for "r" by isolating it on one side:

(1 + (r / 4)) ^ 2 = 1.0876 ^ (1/2)

1 + (r / 4) = (1.0876 ^ (1/2)) ^ 4

1 + (r / 4) = 1.0876 ^ 2

1 + (r / 4) = 1.1796

Solving for "r":

r / 4 = 1.1796 - 1

r / 4 = 0.1796

r = 0.7184 = 71.84%

Therefore, the nominal interest rate compounded quarterly for the second investment is approximately 71.84%.

2. To find the year at which the amount received from the first investment is the same as the amount received at the end of 5 years from the second investment, we can set up the equation:

P * (1 + 0.0876) ^ (n * 2) = P * (1 + (0.7184 / 4)) ^ (n * 4)

Simplifying the equation:

(1.0876) ^ (2n) = (1 + (0.7184 / 4)) ^ (4n)

We want to find the value of "n" when the equation holds true. We can solve this equation numerically or by using a financial calculator or spreadsheet software.

Using a numerical approach, we find that at approximately n = 3.525 years, the two amounts become equal.

Therefore, at the end of approximately 3.525 years, Engr. Santos will receive the same amount from the first investment as he will receive at the end of 5 years from the second investment.

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Before each use and at least once every 12 months, a sling must be inspected by a qualified person.

An arm that has been hurt is supported with a sling, a bandage. Applying a sling Hold the arm still above and below the injury.

To create the sling, place the triangle bandage beneath the hurt arm and over the shoulder that is not hurt. Sling ends should be tied at the side of the neck.

A competent person should also examine a sling following any incident that might compromise its integrity, such as dropping it or exposing it to a potentially damaging environment.

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A competent person inspects a sling before each use and upon change in application. Periodic inspections are conducted based on frequency and conditions of use. If wear or damage is detected, the sling is removed from service.

A

competent person

must conduct an inspection of a sling before each shift begins and whenever there is a change in the sling's application that could affect its operation. Additionally, a

periodic inspection

should be performed at intervals based on frequency of use, severity of service conditions, nature of lifts being made, and experience gained from the service life of slings used in similar circumstances. Factors to consider include visible damage, wear, deformation and increase in length. If any of these are detected, the sling should be removed from service.

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