Answer:
is the process of spreading
forces of 10 pounds and 14 pounds act on each other with an angle of 50°. the magnitude of the resultant force
The resultant force is 10.77 pounds.
We need to know about vector to solve this problem. Force is included to vector because it has magnitude and also direction. The resultant force can be determined using cosine law. It can be written as
F² = F1² + F2² - 2F1 . F2 cos(θ⁰)
From the question above, we know that:
F1 = 10 pounds
F2 = 14 pounds
θ = 50°
By substituting the parameter, we get
F² = F1² + F2² - 2F1 . F2 cos(θ⁰)
F² = 10² + 14² - 2. 10 . 14 cos(50⁰)
F² = 100 + 196 - 280 . 0.64
F² = 100 + 196 - 280 . 0.64
F² = 116.02
F = 10.77 pounds
Hence, the resultant force is 10.77 pounds.
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Diagram shows a boy pulling a crate with diffrent length of the identical rope with the same force. He felt it was easier to pull the crate by using the longer rope. Explain why? [4 marks)
Explanation:
Work is mathematically expressed as force×distance(ie:the force applied to an item to move it × the distance both the force & the item moved through)
This means an increase in force or distance while doing work will increase the intensity of the work being done,which implies that the work will be done easier & faster.
Therefore,he felt it was easier while pulling the crate with the longer rope due to its increased length or distance.
Hope this helps & I'll be hoping to receive brainliest from you if you fully understood.
“You can’t get more energy from a machine than the amount of energy you put into it,” is one way of stating the law of conservation of _____. A. work B. friction C. energy D. power
Answer:
Energy
Explanation:
One ways of stating the law of conservation of energy is that "you cannot get more energy from a machine than the amount of energy you put into it".
The law of conservation of energy states that in a system, energy is neither created nor destroyed but transformed from one form to another.
The energy in a system does not increase based on the premise of this law.
The efficiency of a machine can reduce but the energy is always conserved. This is because energy is transformed to other forms.When a +0.00235 C charge
moves from point A to point B, its
electric potential energy increases
by 0.418 J. What is the potential
difference between A and B?
Include the correct sign, + or -.
(Unit = V)
Answer:
177.87
Explanation:
acellus
The potential difference between the points A and B is 177.9 V.
What is meant by potential difference ?Potential difference between any two points is the amount of work required to move a unit positive charge along any path from point A to point B without accelerating is referred to as the electric field.
Here,
The charge on the particle, q = +0.00235 C
The change in electric potential energy, ΔU = 0.418 J
The potential difference can be defined as the electric potential energy per unit charge.
Therefore, the potential difference between A and B,
V = ΔU/q
V = 0.418/0.00235
V = 177.9 Volt
Hence,
The potential difference between the points A and B is 177.9 V.
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Find the area enclosed by a rectangle that is 1300 m wide and 1630 m long. Write your answer so that it has the correct number of significant figures.
Answer:
2120000m^2
Explanation:
1300* 1660 and there is 3 significant figures, so the 9 would make the round to a 2.
Plzzzz help meeeeee plzzz
hun I wish I can help you but I have the same problem here!! sorry
A standard card deck has 52 cards consisting of 26 black and 26 red cards. three cardsare dealt from a shuffled deck,without replacement.(a) find the probability of being dealt three black cards.
A standard card deck contains 52 cards which consist of 26 red and 26 black cards. When three cards are dealt from a shuffled deck without replacement, we are to find the probability of being dealt three black cards. There are two ways of solving this problem.
The first way is using the probability formula for dependent events, while the second way is to use combinations.
Probability formula method
We are to find the probability of drawing three black cards in a row, without replacement.
P(3 black cards) = P(first card is black) × P(second card is black) × P(third card is black),
where P(first card is black) = number of black cards / total number of cards = 26/52 = 1/2,
P(second card is black) = number of black cards / total number of remaining cards = 25/51, and
P(third card is black) = number of black cards / total number of remaining cards = 24/50.
So, P(3 black cards) = (1/2) × (25/51) × (24/50) = 1/17.
Using combinations method
There are a total of 26 black cards in the deck. We need to choose 3 of them to find the probability of being dealt three black cards.
Using the combination formula, the number of ways of choosing 3 black cards out of 26 is given by C(26,3) = (26 × 25 × 24)/(3 × 2 × 1) = 2600.
Similarly, the total number of ways of choosing 3 cards out of 52 is C(52,3) = (52 × 51 × 50)/(3 × 2 × 1) = 22100.
So, the probability of being dealt three black cards is P(3 black cards) = C(26,3)/C(52,3) = 2600/22100 = 1/17.
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As a baseball is being caught, its speed goes from 30.0 m/s to 0.0 m/s in about 0.0050 s. The mass of the baseball is 0.145 kg.
What is the baseball's acceleration?
What are the magnitude and the direction of the force acting on it?
What are the magnitude and direction of the force acting on the player who caught it?
Answer: Force = 870 N
Explanation:
acceleration = a = (final velocity - initial velocity) / time elapsed
a = (0-30)/.005 = -6000 m/s2 (negative sign means the ball is slowing down)
Force = F = mass x acceleration = ma
F = (0.145 kg)(6000 m/s2) = 870 N away from the player throwing the ball
The magnitude of the force on the player catching the ball is equal, 870N. The mitt acts on the ball with an equal and opposite force (Newton's 3rd Law of Motion)
circular loop of wire 50 mm in radius carries a current of 100 a. find the (a) magnetic field strength and (b) energy density at the center of the loop.
(a) The magnetic field strength at the center of the loop is 4π × \(10^{-4\) Tesla, and (b) The energy density at the center of the loop is 1.6 × \(10^3\) Joules per cubic meter.
(a) To find the magnetic field strength at the center of a circular loop of wire, we can use the Biot-Savart law, which relates the magnetic field at a point to the current flowing through a nearby wire segment. For a circular loop, the magnetic field at the center is given by:
B = μ₀I/2R
where μ₀ is the permeability of free space, I is the current flowing through the loop, and R is the radius of the loop. Substituting the given values, we get:
B = (4π × \(10^{-7\) T·m/A) × (100 A)/(2 × 0.05 m) = 4π × \(10^{-4\) T
Therefore, the magnetic field strength at the center of the loop is 4π × \(10^{-4\) Tesla.
(b) To find the energy density at the center of the loop, we can use the equation for magnetic energy density, which relates the magnetic field strength to the energy per unit volume of the magnetic field. The energy density is given by:
u = B²/2μ₀
Substituting the magnetic field strength we found in part (a), we get:
u = (4π × \(10^{-4\) T)²/(2 × 4π × \(10^{-7\) T·m/A) = 1.6 × \(10^3\) J/m³
Therefore, the energy density at the center of the loop is 1.6 × \(10^3\) Joules per cubic meter.
In summary, the magnetic field strength at the center of the loop is 4π × \(10^{-4\) Tesla, and the energy density at the center of the loop is 1.6 × \(10^3\) Joules per cubic meter. These values are important for understanding the behavior of magnetic fields and their interactions with other objects in the vicinity of the loop.
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For 2.5 seconds, an earthworm crawled directly toward a rock at a constant velocity. It crawled 35 millimeters in that time. What was the earthworm's velocity? Please answer in whole numbers.
The velocity of the earthworm when it crawled 35 millimeter over a time of 2.5 seconds is 0.014 m/s.
What is velocity?
Velocity can be defined as the ratio of displacement to time of a body.
To calculate the earthworm's velocity, we use the formula below.
Formula:
v = d/t........... Equation 1Where:
v = Velocity of the earthwarm's velocityd = Distance crawled 35 milimeters by the earthwormt = time.From the question,
Given:
d = 35 mm = 0.035 mt = 2.5 secondsSubstitute these values into equation 1
v = 0.035/2.5v = 0.014 m/s.Hence, the earthworm's velocity is 0.014 m/s.
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Dave and Alex push on opposite ends of a car that has a mass of 875 kg. Dave pushes the car to the right with a force of 250 N, and Alex pushes to the
left with a force of 315 N. Assume there is no friction.
What is the net force on the car in the x-direction? Help meee please
The net force acting on the car is 65 N to the left
The net force acting on an object is simply defined as the resultant force acting on the object.
From the question given, we obtained the following data:
Force applied to the right (Fᵣ) = 250 NForce applied to the left (Fₗ) = 315 NNet force (Fₙ) =?The net force acting on the car can be obtained as follow:
Fₙ = Fₗ – Fᵣ
Fₙ = 315 – 250
Fₙ = 65 N to the leftTherefore, the net force acting on the car is 65 N to the left
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Since there is no friction, the net force on the car in the x - direction will be 65 Newtons
Given that Dave and Alex push on opposite ends of a car that has a mass of 875 kg.
Dave pushes the car to the right with a force of 250 N, which is positive direction and Alex pushes to the left with a force of 315 N which is negative direction. Since there is no friction, only the horizontal forces will be considered.
To calculate the net force on the car in the x-direction, we will find the difference between the two forces because of their directions are opposite to each other.
Net force = 315 - 250
Net force = 65 Newtons
Therefore, the net force on the car in the x - direction will be 65 Newtons
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A river 800 m wide flows at the rate of 5 km/h. A swimmer who can swim at 10km/h instill, wishes to cross the river straight. (i) Along what direction must he strike. (ii) What should be his resultant velocity? (iii) How much time he would take?
The swimmer would take 258 seconds, or 4 minutes and 18 seconds, to cross the river.
To solve this problem, we can use vector addition to find the swimmer's resultant velocity.
(i) Along what direction must he strike?
Let's draw a diagram to represent the situation:
A
/|
/ |
/ |
/ |
B----C
In this diagram, the river flows from point A to point B, and the swimmer wants to cross the river from point C to point B. Let's call the velocity of the river Vr = 5 km/h and the velocity of the swimmer Vs = 10 km/h. We want to find the direction the swimmer should strike to cross the river straight.
Since the swimmer wants to cross the river straight, he needs to swim in a direction perpendicular to the river's flow. This means that the angle between the swimmer's velocity and the river's velocity should be 90 degrees.
Using trigonometry, we can find that the angle between the swimmer's velocity and the direction perpendicular to the river's flow is:
theta = arctan(Vr / Vs)
= arctan(5 / 10)
= 26.57 degrees
Therefore, the swimmer should strike at an angle of 26.57 degrees to the direction perpendicular to the river's flow.
(ii) What should be his resultant velocity?
To find the swimmer's resultant velocity, we need to add his velocity to the velocity of the river. Since the swimmer is swimming at an angle of 26.57 degrees to the direction perpendicular to the river's flow, we need to use vector addition to find his resultant velocity:
Vs
/|
/ |
/ |Vr
/ |
B----C--->river flow
Using trigonometry, we can find that the magnitude of the swimmer's resultant velocity is:
V = sqrt(Vs^2 + Vr^2)
= sqrt(10^2 + 5^2)
= 11.18 km/h
To find the direction of the swimmer's resultant velocity, we can use the following formula:
theta = arctan(Vr / Vs)
= arctan(5 / 10)
= 26.57 degrees
Therefore, the swimmer's resultant velocity is 11.18 km/h at an angle of 26.57 degrees to the direction perpendicular to the river's flow.
(iii) How much time would he take?
To find the time the swimmer would take to cross the river, we can use the following formula:
time = distance / velocity
The distance the swimmer needs to cross the river is the width of the river, which is 800 m. The swimmer's velocity is 11.18 km/h, or 3.1 m/s.
time = 800 / 3.1
= 258 seconds
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A balloon is partially inflated and sealed. A number of weights are attached to the balloon such that it is neutrally buoyant when submerged at a certain depth in a beaker of water. Describe the motion of the balloon, if you push the balloon down to a greater depth and release it. Explain.
This motion of the balloon is an example of buoyancy, which is the upward force exerted by a fluid on an object immersed in it.
Example of buoyancy motionWhen the balloon is neutrally buoyant, it means that the weight of the balloon and the weights attached to it is equal to the weight of the water displaced by the balloon.
If you push the balloon down to a greater depth and then release it, the balloon will rise back up to its original position.
This is because the balloon is still partially inflated and contains air, which is less dense than water. When you push the balloon down, the water pressure compresses the air in the balloon, causing it to become smaller in size.
When you release the balloon, the compressed air expands and pushes the balloon upwards towards the surface of the water.
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why might orbiting telescope be problematic for the radio portion of the electromagnetic spectrum
Orbiting telescopes can provide many advantages for observations in the visible and other parts of the electromagnetic spectrum, they can present challenges for radio observations.
Orbiting telescopes can be problematic for the radio portion of the electromagnetic spectrum due to several reasons:
1. Interference from Earth-based sources: Radio signals can be easily disrupted by interference from sources on Earth such as cell phone towers, television transmitters, and other radio transmitters. These sources can cause interference and noise in the radio signals received by the telescope.
2. Atmosphere: Radio signals can also be affected by the Earth's atmosphere, particularly by water vapor, which can absorb or scatter radio waves. Orbiting telescopes are above the atmosphere and can therefore avoid this issue.
3. Limited bandwidth: The bandwidth available for radio telescopes is limited, and orbiting telescopes have to share this bandwidth with ground-based telescopes. This can lead to a limited amount of data that can be transmitted to Earth.
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if the maximum torque causes the knob to rotate at 15rpm after 30s of being constantly applied, what is the knob's moment of inertia? assume the knob starts at rest.
The knob's moment of inertia is 0.25 Nm.s²
What is moment of inertia?Moment of inertia is an object's resistance to changes in its rotational speed. It is the sum of the products of the object's mass and the square of its distance from the axis of rotation. Moment of inertia depends on the shape and mass distribution of the object, and thus different objects of the same mass can have different moments of inertia. In physics, the moment of inertia is an important property of any physical object, as it is a measure of the object's resistance to angular acceleration.
The moment of inertia of the knob can be calculated using the equation
I = T × (t/ω)
Where T = applied torque
t = time in seconds
ω = angular velocity in radians second⁻¹
Using the values given,
the moment of inertia of the knob is calculated to be:
I = (T × 30)/(15 × 2π)
= 0.25 Nm.s²
This indicates that the knob has a relatively low moment of inertia, meaning that it is able to rotate quickly in response to an applied torque.
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A paperclip with the density of a neutron star would weigh (on the Earth)
A paperclip with the density of a neutron star would weigh approximately 0.0098 Newtons on Earth.
The density of a neutron star is incredibly high, estimated to be around \(10^{17\) to \(10^{18\) kilograms per cubic meter. Comparatively, the density of a typical paperclip made of metal is much lower, ranging from 6,000 to 9,000 kilograms per cubic meter.
To calculate the weight of a paperclip with the density of a neutron star on Earth, we need to consider the mass and gravitational acceleration. The gravitational acceleration on Earth is approximately 9.8 meters per second squared.
Let's assume the paperclip has a mass of 1 gram (0.001 kilograms) for simplicity. The weight can be calculated using the formula:
Weight = Mass x Gravitational acceleration
Weight = 0.001 kg x 9.8 m/s²
Weight = 0.0098 Newtons
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What climate conditions occur during La Niña?
A.stronger prevailing winds and more hurricane activity
B.warmer Pacific waters and warmer winters
C.more hurricane activity and warmer Pacific waters
D.warmer winters and stronger prevailing winds
Answer:
A. stronger prevailing winds and more hurricane activity
Explanation:
edg2020
Answer:A
Explanation:
1. Old Faithful is a geyser in Yellowstone National Park. This geyser erupts when hot water from
underground shoots up into the air through an opening in the ground. When this happens, the ground
surrounding the water increases in temperature. What happens to the molecules in the ground when
he temperature increases?
a
More heat molecules combine with the molecules in the ground.
b
The energy of the molecules in the ground decreases.
c
The energy of the molecules in the ground increases.
d
The cold energy of the molecules in the ground decreases.
Please help thanks!!
Answer:
c
Explanation:
i just did the test
The energy of the molecules in the ground increases in the given case when the temperature increases.
• The heat of the Earth is released in both conduction and convection in Yellowstone Park.
• Conduction takes place when the transferring of heat takes place from something hot to something cold.
• On the other hand, convection takes place when the transferring of heat takes place by the movement of hot gases or liquids like water, air, or magma to a cooler region.
• The same phenomenon takes place underneath the Yellowstone. The convection of the molten rock in the magma chamber underneath transfers heat via the caldera of Yellowstone.
• Near the surface of the ground, the convection of heat water results in the hot springs and geysers in the park.
Thus, when the temperature increases, the energy of the molecules in the ground also increases resulting in the formation of geysers. The correct answer is option c.
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Mintu wants to increase the heat transfer between a metal iron and another piece of metal he wants to shape. He decides to increase the time the two metals are in contact, use a larger metal iron, and use a new metal material with a higher specific heat.
Where is Mintu's error?
Mintu should have decreased the size of the metal iron.
Mintu should have decreased the time he touches the two metals.
Mintu should have chosen a material with a lower specific heat.
Mintu should have chosen a material the same temperature as the iron.
Answer:
C. Mintu should have chosen a material with a lower specific heat.
Explanation:
Sorry I'm late
I took the test and got 100%
Mintu's error is from, Mintu should have chosen a material with a lower specific heat.
Option C is correct
What is specific heat?The amount of heat required to raise the temperature of one gram of a substance by one Celsius degree is known as specific heat.
In conclusion,since Mintu wants to increase the heat transfer between a metal iron and another piece, Mintu should have chosen a material with a lower specific heat.
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An object is moving 45 m/s and a mass of 34 kg , What is the kinetic energy?
Answer: KE = 34.425 kJ
Explanation:
KE = (1/2) mv^2
KE = (0.5)*(34kg)(45m/s)^2
KE = (0.5)*(34kg)(2025m^2/s^2)
KE = 34425 kg*m^2/s^2
1 Joule = 1 kg*m^2/s^2
KE = 34.425 kJ
How much work is done when an engine generates 400 Watts of power in 25 seconds?
Answer:
10000 J or 10 KJ
Explanation:
power = workdone/time taken
400 = workdone/25
workdone = 400 * 25
=10000 J
Which observations correctly describe the second law of thermodynamics? check all that apply.
thermal energy that is not used to do work is often released to the surroundings.
thermal energy flows from a cooler object to a warmer object.
thermal energy flows from a warmer object to a cooler object.
thermal energy is released as unusable energy by a heat engine, which is never 100 percent efficient.
thermal energy flows when two objects in contact have a temperature difference.
answers: 1,3,4,5
Answer:
I would agree with the answers 1, 3, 4, 5
Obviously energy will not spontaneously flow from a cooler object to a warmer object
Answer:
A. Thermal energy that is not used to do work is often released to the surroundings.
C. Thermal energy flows from a warmer object to a cooler object.
D. Thermal energy is released as unusable energy by a heat engine, which is never 100 percent efficient.
E. Thermal energy flows when two objects in contact have a temperature difference.
Explanation:
Got it right on edge 23
A sample of diamagnetic material is initially at rest in a uniform magnetic field. if no other forces are present, how will the sample move
The sample will move very slowly in the opposite direction of the applied magnetic field, but it will eventually come to a stop when it reaches equilibrium.
Diamagnetic materials, unlike ferromagnetic or paramagnetic materials, do not possess any permanent magnetic moment or net magnetic dipole moment. The magnetic force acting on the diamagnetic material is perpendicular to its velocity, and hence it cannot accelerate the material along the direction of the magnetic field.
Since the sample is made of diamagnetic material, it will have a very weak and temporary magnetic moment induced in it when placed in a magnetic field. This induced magnetic moment will be in the opposite direction to the applied magnetic field. Therefore, the sample will experience a force in the direction opposite to the applied magnetic field. However, this force will be very weak since the diamagnetic material has a weak magnetic susceptibility.
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Your dog has been lost! He got out of the yard and is now wandering the neighborhood. You are frantic and are screaming as loud as you can, but the local elementary school recess is making so much noise that there is no way Bandit could hear you. Then you remember your special whistle. Explain how this whistle works, and be sure to use the appropriate wave terminology to explain it.
· Key words to think about: Wave type, frequency, pitch
My special whistle works by creating different types of waves with varying frequencies and pitches.
How the special whistle worksWhen I blow into the whistle, it produces sound waves in the form of longitudinal waves. These waves have a high frequency, meaning that the vibrations of the sound waves occur rapidly.
The pitch of the whistle is also high, so the sound carries far. By consistently blowing the whistle, Bandit should be able to hear it from a distance.
I also use the whistle to create a unique pattern of sound waves. The pattern is made up of a series of short and long whistles, each with its own frequency and pitch. This pattern is designed to catch Bandit’s attention and help him locate me. I can also use the whistle to call out his name and encourage him to come back home.
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Two parallel plates of area 5.68.10-³ m²
have equal and opposite charges of
4.38 10-¹1 C placed on them. What is
the electric field between the plates?
[?] N/C
Answer:
\(\vec E=871.33 \ \frac{N}{C} }\)
Explanation:
Given that two parallel plates with an area of \(5.68 \times 10^{-3} \ m^2\) have equal and opposite charges of \(4.38 \times 10^{-11} \ C\). Find the value of the electric field between them.
Using the following equation,
\(\boxed{ \vec E=\frac{Q}{A \epsilon_0}; \ \ \epsilon_0=8.85 \times 10^{-12}\frac{C^2}{Nm^2} }\)
Plug the known values into the equation.
\(\vec E=\frac{4.38 \times 10^{-11}}{(5.68 \times 10^{-3})(8.85 \times 10^{-12})}\\\\\therefore \boxed{\boxed{\vec E=871.33 \ \frac{N}{C} }}\)
Thus, the electric field is found.
A soccer ball is kicked horizontally off a 24.0 meter high hill and lands a distance of 33.0 meters from the edge of the hill. Determine the initial horizontal velocity of the soccer ball.
Answer:
ten minutes fakfdxjjnox
Answer:
Question:
A soccer ball is kicked horizontally off a
22.0
meter high hill and lands a distance of
35.0
meters from the edge of the hill. Determine the initial horizontal velocity of the soccer ball.
Projectile:
The projectile motion is a combination of uniform motion and uniform acceleration motion. When an object is thrown with a velocity (v) then, the horizontal component of the velocity (
v
h
) does not change with respect to time and therefore, the following relation holds valid for the horizontal motion:
S
p
e
e
d
=
S
p
e
e
d
T
i
m
e
The vertical component of the velocity (
v
v
) changes at the rate of
g
=
9.81
m
/
s
2
and therefore, the equations of motion are used to study the vertical motion of the object. These equations are customized for the vertical motion as:
v
=
u
+
g
t
s
=
u
t
+
0.5
g
t
2
v
2
−
u
2
=
2
g
s
For an object thrown with a horizontal velocity, the initial vertical component of the velocity will be zero. In that case, the vertical distance traveled by the object in time (t) will be,
s
=
0.5
g
t
2
⇒
t
=
√
2
s
g
Answer and Explanation:
Given:
Height of the hill,
H
=
22
m
The horizontal distance covered by the ball before it lands,
d
=
35
m
Calculating the time taken by the ball to hit the ground,
t
=
√
2
H
g
=
√
2
(
22
)
9.81
=
2.12
s
Calculating the initial horizontal velocity of the ball,
V
=
d
t
=
35
2.12
=
16.51
m
/
s
which is the answer.
Explanation:
To open and close a circuit, a
can be used.
Like linear momentum, conservation of angular momentum is a fundamental principle which can be used to solve physical problems. The angular momentum of a system may remain the same unless (select the best answer) The sum of the external forces is not zero. Acted on by an external force. The sum of the external torques is not zero.Acted on by external force.
The sum of the external torques is not zero. Conservation of angular momentum is based on the principle that the total angular momentum of a system is conserved when the sum of the external torques acting on it is zero. Option (1)
In other words, the angular momentum of an isolated system is constant. Angular momentum is a vector quantity that describes the rotational motion of a body or a system of bodies around a fixed axis. It depends on the mass distribution and velocity of the rotating objects. The conservation of angular momentum is a powerful tool in physics and is used to solve problems in a wide range of fields, from mechanics to astrophysics.
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Full Question: Like linear momentum, conservation of angular momentum is a fundamental principle which can be used to solve physical problems. The angular momentum of a system may remain the same unless (select the best answer)
The sum of the external forces is not zero. Acted on by an external force. The sum of the external torques is not zero.Acted on by external force.what part of the electromagnetic spectrum lies between the ultraviolet region and the gamma ray region?
The part of electromagnetic spectrum lying between the ultraviolet region and the gamma ray region is x-rays.
The smallest known wavelengths and greatest frequency are found in gamma rays. They are the most piercing waves because they have high energy and can travel great lengths through air. X-rays have shorter wavelengths than UV radiation, but longer wavelengths than gamma radiation, making them more energetic.
The electromagnetic energy known as ultraviolet has a frequency of 30 PHz to 750 THz and a wavelength of 10 nm to 400 nm. These particles have wavelengths that are both shorter than visible light and longer than X-rays.
Thus, the x-ray area of the electromagnetic spectrum is located between the ultraviolet and gamma ray regions.
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The lowest note on a piano is
27. 5 Hz. To fit inside the piano,
the string for the low note can't be
longer than 1. 20 m. If it takes the
full length, what is the speed of
the wave in the string?
(Unit = m/s)
The lowest note on a piano is 27. 5 Hz. To fit inside the piano, the string for the low note can't be longer than 1. 20 m. If it takes the full length, the speed of the wave in the string is 33.0 m/s.
The speed of a wave in a string can be calculated using the formula \(v = \sqrt{(T/\mu)}\), where v is the speed of the wave, T is the tension in the string, and μ is the linear density of the string.
To calculate the linear density of the string, we can use the formula μ = m/L, where m is the mass of the string and L is its length. Since we know that the length of the string for the lowest note on the piano is 1.20 m, we can assume that this is the length of the string if it takes the full length.
The frequency of the lowest note on the piano is 27.5 Hz. The wavelength (λ) of the wave can be calculated using the formula \(\lambda = v/f,\)where f is the frequency of the wave. For the lowest note on the piano, the wavelength is equal to the length of the string: λ = 1.20 m.
We can use the wavelength and frequency to calculate the speed of the wave in the string: \(v = \lambda f = 1.20 \;m \times 27.5\; Hz = 33.0\; m/s.\)
Therefore, if the string for the lowest note on the piano takes the full length of 1.20 m, the speed of the wave in the string is 33.0 m/s.
In summary, the speed of a wave in a string can be calculated using the formula \(v = \sqrt{(T/\mu)\), where T is the tension in the string and μ is the linear density of the string.
By assuming that the length of the string for the lowest note on the piano is 1.20 m and using the frequency and wavelength of the wave, we can calculate the speed of the wave in the string.
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