whats my top fav animal if you guess right you get brainest

Answer:

Step-by-step explanation:

A squiggly line can refer to a variety of different shapes or patterns. To create an equation using cosine that resembles a squiggly line, you can use a combination of sine and cosine functions with different frequencies and amplitudes. Here's an example equation that produces a squiggly pattern:

y = A * cos(B * x) + C * sin(D * x)

In this equation, A, B, C, and D are constants that you can adjust to modify the shape and characteristics of the squiggly line. By experimenting with different values for these constants, you can create various squiggly patterns. Keep in mind that the specific equation may vary depending on the exact shape and features you have in mind for the squiggly line.

Answer:

37.7

Step-by-step explanation:

n - 0.47n = 20

0.53n = 20

n = 37.7

Answer:

between 10 and 12

Step-by-step explanation:

Given the measure of angles:

m∠B = 70°

m∠C = 60°

m∠A = 50°

Following this information, since the side lengths are directly proportional to the angle measure they see:

Angle B is the largest angle. Therefore, side AC is the longest side of the triangle since it is opposite of the largest angle.

Angle C is the smallest angle, so the side AB is the shortest side.

Therefore, side BC must be between 10 and 12 inches.

Answer: Never(!) [assuming I understand/interpret the question properly]

Step-by-step explanation: The question wants to know how many months it will take for your neighbor's total cost be the same as yours, with three televisions. One has to interpret "total cost." I deem it to be the total accumulated costs, including installation. If you interpret it as the cost per month, then they charges are the same after the month the installation cast was paid. That's because the satellite provider charges per television, and 3*(13.32) is equal to the same 39.96/month charged by the cable provider. It the questions means total cumulative costs, the satellite customer will never exceed the cable customer's total bill, because of the installation fee ($75 for cable and free for satellite)

Waterways should retain the old backhoes equipment.

To determine whether it is more favorable to purchase new backhoes or overhaul the old ones, we will evaluate the net present value (NPV), profitability index (PI), and internal rate of return (IRR) for both options.

Net Present Value (NPV):

For the new backhoes:

The initial cost of investment = Purchase cost when new - Salvage value now

= $199,994 - $15,200 = $184,794

The net cash flow generated each year for the new backhoes remains unspecified, so we cannot calculate its NPV.

For the old backhoes:

Initial investment = Cost of the overhaul = $41,400

Net cash flow generated each year = $15,200

Using the provided PV table, we can calculate the NPV for the old backhoes:

NPV = Net cash flow generated each year * PV factor for 8 years - Initial investment

= $15,200 * 5.76162 - $41,400 ≈ $55,689.69

Since the NPV for the old backhoes is positive, retaining the old equipment is favorable.

Profitability Index (PI):

The profitability index is calculated by dividing the present value of cash inflows by the initial investment.

For the new backhoes:

Since the net cash flow generated each year is unspecified, we cannot calculate the PI.

For the old backhoes:

PI = (Net cash flow generated each year * PV factor for 8 years) / Initial investment

= ($15,200 * 5.76162) / $41,400 ≈ 2.11

The profitability index for the old backhoes is 2.11.

Based on the PI, the old backhoes have a higher profitability index than the new backhoes, indicating that retaining the old equipment is more profitable.

Internal Rate of Return (IRR):

The IRR factor for the new and old backhoes is not provided, so we cannot calculate the exact IRR.

In summary, based on the net present value (NPV) and profitability index (PI), it is more favorable for Waterways to retain the old backhoes equipment.

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Therefore , the solution of the given problem of prime factor comes out to be  HCF of 36 and 40 is 2 x 2 = 4.

A prime factor is any non-zero natural integer that can be divided only by itself and by 1. Actually, a number of the initial prime numbers are 2, 3, 8, 7, 10, along with others. a sum which was multiplied to yield a new sum. For example, if we divide 15 between 3 and 5, we receive 3 5 = 15. major components: All prime but non-composite components are referred to as prime factors. 2, 3, and 5 are a handful of the prime factors of 30.

Here,

We can first factor each number into its prime factors in order to determine the HCF (highest common factor) of 36 and 40 using prime factors.

36 is prime factorised as

=> 36 = 2 x 2 x 3 x 3.

The prime factors for the number

=> 40 are: 2 x 2 x 2 x 5

The common prime factors and their minimal powers in both numbers can then be found. The only common prime factor in this situation is 2, and it can be found in both 36 and 40 with a minimum power of 2.

The HCF of 36 and 40 is therefore 2 x 2 = 4.

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Answer:

£28 : £7

Step-by-step explanation:

sum the parts of the ratio, 4 + 1 = 5 parts

Divide the quantity by 5 to find the value of one part of the ratio

£35 ÷ 5 = £7 , then

4 parts = 4 × £7 = £28

£35 = £28 : £7 in the ratio 4 : 1

Answer: y= 3/2x - 6

Step-by-step explanation:

The equation is y=mx + b

The y-intercept is when x = 0, so on the table y-intercept = -6

The slope is rise/run, we see that y increase by three and x increase by 2, so the slope is 3/2

to get the slope of any straight line, we simply need two points off of it, let's use those ones in the picture below.

\((\stackrel{x_1}{2}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-3)}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{2}}} \implies \cfrac{3 +3}{4} \implies \cfrac{ 6 }{ 4 } \implies {\Large \begin{array}{llll} \cfrac{3 }{ 2 } \end{array}}\)

now, the y-intercept occurs when x = 0, recheck the picture below.

In this experiment, two separate random samples of over 1,000 registered voters were presented with profiles of a hypothetical candidate for U.S. Congress. One sample read a profile of Ann Clark.

While the other sample read a profile of Andrew Clark. The profiles were identical except for the gender of the candidate. The respondents were asked questions about their opinions of the candidate, including what they liked and didn't like about them, whether they considered them qualified, and if they were inclined to vote for them. The experiment aimed to explore potential gender bias in voters' perceptions and preferences for the candidate.

The experiment involved comparing the responses of two random samples of registered voters to profiles of two candidates, Ann Clark and Andrew Clark. The purpose was to investigate whether gender had any impact on voters' perceptions and preferences. By presenting identical profiles with the only difference being the gender of the candidate, the researchers aimed to isolate the influence of gender on voters' evaluations.

The respondents in both samples were asked similar questions regarding their opinions of the candidate, allowing for a comparison of their responses. By analyzing the data from both samples, researchers could assess whether there were any significant differences in how the respondents perceived the candidates based on their gender. This experiment helps shed light on potential gender biases in voters' decision-making processes and provides insights into the role of gender in political candidate evaluations.

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Answer:

\(\boxed{x=1}\)

Step-by-step explanation:

\(mean=\frac{sum \: of \: terms}{number \: of \: terms}\)

\(2=\frac{2+4+1+1+x+3+2}{7}\)

\(2=\frac{13+x}{7}\)

\(14=13+x\)

\(x=1\)

Answer:

There are 26 tickets left to be sold.

Step-by-step explanation:

Jason - 6 tickets

Heather - 6(3) = 18 tickets

6+18 = 24 tickets

50-24 = 26 tickets

We can repeat this calculation for other values of x and compare the total costs to find the minimum.

By evaluating the costs for different values of x, we can determine the least-cost number of crews the city should assign to collect recyclables.

To determine the least-cost number of crews the city should assign to collect recyclables, we need to consider the cost of operating the crews and the cost of using an outside contractor.

Let's denote the number of crews assigned to collect recyclables as "x."

The cost of operating the crews for one working day is given by:

Cost_internal = x * 1000

The cost of using the outside contractor to collect the remaining recyclables is:

Cost_contractor = (30 - 5x) * 750

The total cost is the sum of the two costs:

Total_cost = Cost_internal + Cost_contractor

To minimize the cost, we can differentiate the total cost with respect to "x" and set the derivative equal to zero:

d(Total_cost)/dx = 0

Let's calculate the derivative and solve for "x":

d(Total_cost)/dx = d(Cost_internal)/dx + d(Cost_contractor)/dx

Since d(Cost_internal)/dx = 1000 and d(Cost_contractor)/dx = -750, the equation becomes:

1000 - 750 = 0

250 = 0

This equation is not possible, as it implies 250 = 0, which is not true.

Since there is no solution to d(Total_cost)/dx = 0, we need to evaluate the cost at critical points. The critical points occur when the number of crews changes, which is at integer values of "x."

We can evaluate the cost for x = 1, 2, 3, and so on, and compare the costs to find the least-cost option. We calculate the total cost for each x value and select the value that results in the lowest cost.

For example, when x = 1:

Cost_internal = 1 * 1000 = 1000

Cost_contractor = (30 - 5 * 1) * 750 = 22500

Total_cost = 1000 + 22500 = 23500

We can repeat this calculation for other values of x and compare the total costs to find the minimum.

By evaluating the costs for different values of x, we can determine the least-cost number of crews the city should assign to collect recyclables.

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Answer:

3x + 4y + 2z = 435

Step-by-step explanation:

let x represent soccer

hence playing soccer three times = 3 × x = 3x

let y represent swimming

hence swimming four times = 4 × y = 4y

let z represent piano

hence playing piano twice = 2 × z = 2z

Victoria spends a total of 435mins doing these three activities every week,

3x + 4y + 2z = 435

Mr. Bryon used 10.25 gallons of gas to mow his lawn.

Multiplication is a mathematical operation that combines two or more numbers to find their product. It is commonly represented by the "×" or "•" symbols. When multiplying two numbers, the result is the total number of items or units in a collection made up of equal groups of those two numbers.

If Mr. Bryon used 1/4 of the gas in the can to mow his lawn, we need to find 1/4 of 41 gallons.

To do this, we can multiply 41 by 1/4:

41 * 1/4 = 10.25

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Answer:

The slope of this line is 1/5

Step-by-step explanation:

You can find the answer easily by graphing the problem. In doing so, you will find the slope (rise over run) to be one over five. This is because you rise one unit, and run five.

5) the standard deviation for the security is approximately 10.01%.

To calculate the standard deviation for a security given the probabilities and returns, we need to follow these steps:

1. Calculate the expected return (mean) of the security:

  Expected Return = (Probability 1 × Return 1) + (Probability 2 × Return 2) + (Probability 3 × Return 3)

  In this case:

  Expected Return = (0.30 × 0.24) + (0.50 × 0.08) + (0.20 × -0.09) = 0.072 + 0.040 - 0.018 = 0.094 or 9.4%

2. Calculate the squared deviation of each return from the expected return:

  Squared Deviation = (Return - Expected Return)^2

  For each return:

  Squared Deviation 1 = (0.24 - 0.094)^2

  Squared Deviation 2 = (0.08 - 0.094)^2

  Squared Deviation 3 = (-0.09 - 0.094)^2

3. Multiply each squared deviation by its corresponding probability:

  Weighted Squared Deviation 1 = Probability 1 × Squared Deviation 1

  Weighted Squared Deviation 2 = Probability 2 × Squared Deviation 2

  Weighted Squared Deviation 3 = Probability 3 × Squared Deviation 3

4. Calculate the variance as the sum of the weighted squared deviations:

  Variance = Weighted Squared Deviation 1 + Weighted Squared Deviation 2 + Weighted Squared Deviation 3

5. Take the square root of the variance to obtain the standard deviation:

  Standard Deviation = √(Variance)

Let's perform the calculations:

Expected Return = 0.094 or 9.4%

Squared Deviation 1 = (0.24 - 0.094)^2 = 0.014536

Squared Deviation 2 = (0.08 - 0.094)^2 = 0.000196

Squared Deviation 3 = (-0.09 - 0.094)^2 = 0.032836

Weighted Squared Deviation 1 = 0.30 × 0.014536 = 0.0043618

Weighted Squared Deviation 2 = 0.50 × 0.000196 = 0.000098

Weighted Squared Deviation 3 = 0.20 × 0.032836 = 0.0065672

Variance = 0.0043618 + 0.000098 + 0.0065672 = 0.010026

Standard Deviation = √(Variance) = √(0.010026) = 0.10013 or 10.01%

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Answer:

13 *2*2

or

13*2^2

Step-by-step explanation:

52 = 26*2

But 26 is not prime

52 = 13*2 *2

52 = 13 * 2^2

Step-by-step explanation:

hope it helped!! ..............

Answer:

If you are asking for the slope

Step-by-step explanation:

m = 40

Answer:

-2/5, -1/2, -3/4

Step-by-step explanation:

You have to have the same denominator.

-10/20, -15/20, -8/20

Hope this helps!

Answer:

8x² - 18x - 5

Step-by-step explanation:

2x (4x+1) -5(4x+1)

8x²+2x -20x-5

8x²-18x -5

The 2-, 10-, and 100-year peak floods for a normal distribution are 5500 cfs.

Given a mean and standard deviation of 3,500 and 2,000 cfs, respectively, the 2-, 10-, and 100-year peak floods for a normal distribution can be found as follows:

Formula used in finding the peak flood is as follows:

Q_T= Q_m + K_T

σ

Where Q_T is the flow for a given period,

Q_m is the mean flow, K_T is the coefficient of skewness, and σ is the standard deviation of the flows.

For a normal distribution, K_T= frac{\text{duration of period in years}-1}{2}\times\frac{\text{duration of period in years}+1}{2}

Substitute the mean and standard deviation to the formula above:

When the period of interest is 2 years, the coefficient of skewness is calculated below:

[{{K}_{T}}=\frac{\text{(2-1)(2+1)}}{2}=1\]

Also, K_{T} is 1 for the 10-year and 100-year flood.

When these values are computed, we get the following values:

Q_{2}=3500+1(2000)=5500 \text{ cfs}

Q_{10}=3500+1(2000)=5500 \text{ cfs}

Q_{100}=3500+1(2000)=5500 \text{ cfs}

Therefore, the 2-, 10-, and 100-year peak floods for a normal distribution are 5500 cfs.

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To find the line integral ∫C sin(2z) dz, where C is the curve given by z(t) = 2cost + i(2sint) for t in the interval [0, π/2], we can parametrize the curve and then evaluate the integral using the given parametrization.

We start by parameterizing the curve C with respect to t: z(t) = 2cost + i(2sint), where t varies from 0 to π/2. Differentiating z(t) with respect to t, we get dz = -2sint dt + 2cost dt. Now we substitute the parameterization and dz into the line integral: ∫C sin(2z) dz = ∫[0,π/2] sin(2(2cost + i(2sint))) (-2sint dt + 2cost dt). Simplifying the integral, we have: ∫[0,π/2] sin(4cost + 4isint) (-2sint dt + 2cost dt). Expanding the sine function using the angle sum formula, we get: ∫[0,π/2] sin(4t) (-2sint dt + 2cost dt). Evaluating this integral gives the final result.

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Answer:

We have the proportion: 8/10 = 100/y

We can solve for y by cross-multiplying.

That is, 8y = 100 * 10 Simplifying the right-hand side, 8y = 1000

Dividing both sides by 8 to solve for y, y = 125

Hence, the value of y is 125.

Finally, we have the expression: y = √80We can simplify this expression by factoring 80 into its prime factors:80 = 2 * 2 * 2 * 2 * 5

Taking the square root of 2 * 2 * 2 * 2, we have:√(2 * 2 * 2 * 2) = 2 * 2 = 4

Therefore, y = 4√5The value of y is 4√5.

Step-by-step explanation:

Hope this helps!! Have a good day/night!!

There are 4 vertices with degree 3, and 2 vertices with degree 4. So, there are a total of 6 vertices in this graph.

In a simple undirected graph with 10 edges, 2 vertices have a degree of 4 and the rest have a degree of 3. To determine the number of vertices in this graph, use the formula:

Sum of degrees = 2 * number of edges

Let x be the number of vertices with degree 3. Then:

(2 * 4) + (3 * x) = 2 * 10

8 + 3x = 20

3x = 12

x = 4

We also know that two of the vertices have a degree of 4, which means that together they contribute 8 to the sum of all vertex degrees. This leaves us with 20 - 8 = 12 degrees left to distribute among the other vertices. Since the remaining vertices all have a degree of 3, we can set up the equation 3x = 12, where x is the number of remaining vertices. Solving for x, we get x = 4. Therefore, the graph has a total of 6 vertices - two with a degree of 4 and four with a degree of 3.

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The triangle is an οbtuse triangle.

Tο determine if the triangle is acute, οbtuse, οr right, we need tο check if it satisfies the Pythagοrean theοrem. Accοrding tο the Pythagοrean theοrem, in a right triangle, the sum οf the squares οf the lengths οf the legs (the shοrter sides) is equal tο the square οf the length οf the hypοtenuse (the lοngest side). Sο, if the sum οf the squares οf the twο shοrter sides is equal tο the square οf the lοngest side, then the triangle is a right triangle.

Let's calculate the squares οf the three sides:

The square οf the first side (18 cm) is 324.

The square οf the secοnd side (80 cm) is 6400.

The square οf the third side (81 cm) is 6561.

Nοw, we need tο determine if the sum οf the squares οf the twο shοrter sides is greater than οr less than the square οf the lοngest side. Sο, we have:

324 + 6400 = 6724

Since 6724 is less than 6561, the triangle dοes nοt satisfy the Pythagοrean theοrem and it is nοt a right triangle. Therefοre, the triangle is either an acute οr οbtuse triangle.

Tο determine if the triangle is acute οr οbtuse, we need tο find the largest angle οf the triangle. We can use the Law οf Cοsines tο find the largest angle οf the triangle, which is οppοsite the lοngest side. The Law οf Cοsines states that in any triangle:

\(c^2 = a^2 + b^2\) - 2ab cοs(C)

where a, b, and c are the lengths οf the sides οf the triangle, and C is the angle οppοsite the side c.

In οur case, a = 18 cm, b = 80 cm, and c = 81 cm. Sο, we have:

\(81^2 = 18^2 + 80^2 - 2(18)(80) cos(C)\)

6561 = 324 + 6400 - 2880 cοs(C)

Nοw, we can sοlve fοr cοs(C):

cοs(C) = (6400 + 324 - 6561) / (2(18)(80))

cοs(C) = -0.2216

Since cοsine is negative, the angle C is οbtuse.

Therefοre, the triangle is an οbtuse triangle.

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You want to know the classification of a triangle with side lengths 18 cm, 80 cm, and 81 cm. A triangle can be classified by looking at the measure of its largest angle. The classification of the triangle is the same as the classification of that angle: obtuse if > 90°, right if = 90°, and acute if < 90°.

The largest angle is always opposite the longest side. In a triangle with angles A, B, C and their opposite sides a, b, c, we can call the largest angle C. Its measure can be computed using the Law of Cosines, which tells you ...

  C = arccos((a² +b² -c²) / (2ab))

  C = arccos((18² + 80² - 81²) / (2×18×80)) = arccos(163/2880) ≈ 86.8°

The largest angle is less than 90°, so the triangle is an acute triangle.

Sum, product, power and quotient is the combination of limit properties tat is required to evaluate the given expression.

An output value that a function approaches for the specified input values is referred to as a limit. Calculus and mathematical analysis depend on limits, which are also used to determine integrals, derivatives, and continuity.

The limit of the difference between two functions is equal to the difference between the limits of two functions, according to the difference law for limits. The law of constant multiples for limits states that the limit of a function that is a constant multiple is equal to the sum of the limits of the function and the constant.

We must understand how to obtain the limits involving sums in order to evaluate this limit. We also require the power rule because powers are involved. Because the fraction can be expressed as a product with a negative power, we apply the product rule rather than the quotient rule.

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The probability that the number of 0's in a randomly generated bit string of length 8 is different from the number of 1's is 56/256, or 7/32.

To understand why, let's consider the possible combinations of 0's and 1's in an 8-bit string. There are a total of 2^8 = 256 possible outcomes. Out of these, we need to determine the number of outcomes where the number of 0's and 1's is different.

One way to approach this is by counting the number of strings with 4 zeros and 4 ones, and then subtracting it from the total number of outcomes. The number of ways to arrange 4 zeros and 4 ones is given by the binomial coefficient C(8,4) = 70. Thus, there are 70 outcomes where the number of 0's and 1's is equal.

Subtracting this from the total number of outcomes, we get 256 - 70 = 186 outcomes where the number of 0's and 1's is different. Therefore, the probability of having an unequal number of 0's and 1's is 186/256, which simplifies to 7/32, or approximately 21.9%.

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it can be concluded that the population standard deviation is within or less than 12.

To construct a hypothesis test to determine whether the population standard deviation of σ≦12 should be rejected for Costco, we can use a chi-square test for variance.

Step 1: State the null and alternative hypotheses:
- Null hypothesis (H₀): σ ≤ 12
- Alternative hypothesis (H₁): σ > 12

Step 2: Determine the level of significance (α = 0.05) and degrees of freedom (df = n - 1 = 11 - 1 = 10).

Step 3: Calculate the test statistic:
- χ² = (n - 1) * (s² / σ²) = 10 * (11.3² / 12²) = 10 * 0.94 = 9.4

Step 4: Determine the critical value:
- The critical value at α = 0.05 with df = 10 is χ²ₐ = 18.307

Step 5: Compare the test statistic with the critical value:
- Since χ² = 9.4 < χ²ₐ = 18.307, we fail to reject the null hypothesis.

Step 6: Conclusion:
- Based on the given sample data, there is not enough evidence to reject the hypothesis that the population standard deviation of σ≤12 for Costco.

Therefore, it can be concluded that the population standard deviation is within or less than 12.

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