whats f(x) if f(x)= 5-67

Answer:

Hi! The answer is $591,013

aka D!

Step-by-step explanation:

A capital asset is property that is expected to generate value over a long period of time, such as a building, machinery, and vehicles.

The correct option is the third one; (14, 4); The vertex represents the maximum profit.

For a general quadratic equation

y = ax² + bx + c

The vertex is at the x-value:

x = -b/2a

Here the quadratic function is:

f(x)=  -x² + 28x - 192

The vertex is at:

x = -28/2*-1 = 14

Evaluating in x= 14 we get:

f(14) = -14² + 28*14 - 192 = 4

So the vertex is at (14, 4), and because the leading coefficient is negative, this is the maximum profit.

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This code allows you to create a map of Alameda County within the context of California using the "maps" and "ggplot2" packages.

In this exercise, you will create a map of Alameda County in California. To begin, you need to load the necessary map packages by using the commands "library(maps)" and "library(mapproj)".

Next, you can create a map of California with county boundaries by running the provided code. This code uses the "map_data" function from the "maps" package to retrieve the coordinates for the polygons of each county in California. The resulting data frame, called "ca", contains information about the longitude, latitude, group, order, region, and subregion of each county.

To visualize the map, you can use the "ggplot" function from the "ggplot2" package. This function takes the "ca" data frame as input and maps the longitude and latitude coordinates to the x and y axes, respectively. The "group" parameter ensures that each county is represented as a separate polygon. The "geom_polygon" function is used to draw the polygons, with the "fill" parameter set to "white" and the "color" parameter set to "black" to create a black and white map. The "coord_map" function is then used to adjust the aspect ratio and projection of the map.

By running this code, you will obtain a map of California with county boundaries. The "ca" data frame contains additional information about each county, such as the region and subregion. You can preview the first few rows of this data frame using the "head" function.

Overall, this code allows you to create a map of Alameda County within the context of California using the "maps" and "ggplot2" packages.

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To convert kilograms to pounds, multiply the number of kilograms by 2.20462. both are unit of measurement of weight

This gives the equivalent value in pounds.Converting from kilograms to pounds is a simple calculation that involves multiplying the number of kilograms by a conversion factor. One kilogram is equivalent to 2.20462 pounds.

Therefore, to convert from kilograms to pounds, simply multiply the number of kilograms by 2.20462. This conversion is used in many fields, including nutrition, sports, and medicine, where body weight or mass is often given in both metric and imperial units.

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Answer:

62.832

Step-by-step explanation:

Answer: 360 degrees.

Step-by-step explanation:

For any polygon, finding the sum of the interior angles can be found using a simple formula:

\(180(n-2)\)

n is the number of sides, and there are four sides to this polygon.

\(180(4-2); 180(2)=360\)

Using triangles, we know the sum of the interior angles for any triangle is 180 degrees; if you imagine the polygon as two triangles put together, then you can easily add up the angle sums as 360, since two triangles with an interior angle sum of 180 will have a total of 360 degrees as the interior angle sum.

Answer:

1. 12,469

2. 5.2

3. I don't know sorry!

Step-by-step explanation:

1. Divide the diameter by 2 which gives you 63

So, A = πr2 = π·63^2 ≈ 12468.98

2. Looks like the bigger triangle is twice as big as the smaller circle

so, 2.6 x 2= 5.2

An unnormalized relation refers to a table in a relational database that contains more than one row. This means that there are duplicate rows in the table, which violates the rules of normalization.

Normalization is a process in database design that aims to eliminate data redundancy and ensure data integrity. It involves breaking down a database into multiple tables and defining relationships between them. By doing so, we can efficiently store and retrieve data while minimizing inconsistencies.

In an unnormalized relation, duplicate rows can lead to various problems. For example, it can result in data inconsistencies, as updating one instance of a row may not reflect changes in other duplicate rows. Additionally, it can cause unnecessary storage and maintenance overhead.

To normalize an unnormalized relation, we need to identify the functional dependencies in the table and create separate tables for related data. This helps organize the data and reduces redundancy.

In summary, an unnormalized relation is a table in a relational database that has duplicate rows. It is important to normalize such relations to ensure data integrity and efficiency.

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The vector (3,9) as a linear combination of the unit vectors i and j is  3 * i + 9 * j

To write the vector (3, 9) as a linear combination of the unit vectors i and j, we need to find the coefficients that multiply the unit vectors to obtain the components of the given vector.

The unit vectors i and j represent the directions of the x-axis and y-axis, respectively. The vector (3, 9) can be expressed as:

(3, 9) = a * i + b * j

where a and b are the coefficients we need to find.

Since the unit vector i corresponds to the x-axis, the coefficient a represents the component of the vector (3, 9) in the x-direction. Similarly, the coefficient b represents the component of the vector (3, 9) in the y-direction.

To find the coefficients, we can equate the corresponding components:

3 = a

9 = b

Therefore, the vector (3, 9) can be written as:

(3, 9) = 3 * i + 9 * j

In this representation, the coefficient 3 indicates that the vector (3, 9) has a magnitude of 3 in the x-direction (i.e., parallel to the x-axis), and the coefficient 9 indicates that it has a magnitude of 9 in the y-direction (i.e., parallel to the y-axis).

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The required quadratic equation is: y = -0.75x² + 16x + 2

The general form of expression of a quadratic equation is:

y = ax² + bx + c

Now, from the given function table, we see that:

When x = 0, y = 2

When x = 2, y = 31

When x = 4, y = 54

When x = 6, y = 71

When x = 8, y = 82

Thus at (0, 2), we have:

a(0)² + b(0) + c = 2

Thus, c = 2

At (2, 31), we have:

a(2)² + b(2) + 2 = 31

4a + 2b = 29   -----(1)

At (4, 54), we have:

a(4)² + b(4) + 2 = 54

16a + 4b = 52   ----(2)

Solving simultaneously gives:

a = -0.75 and b = 16

Thus, the quadratic equation is:

y = -0.75x² + 16x + 2

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Answer:

If it rides 5 miles it woul be 4.5 dollars but the other one would be 55$ dollars for just 5 miles.

Step-by-step explanation:

Answer:

the correct answer to this question would be D

Answer:

-8

Step-by-step explanation:

the pattern is times 4

AM I PLAYING 2048??????

Answer:

-8

Step-by-step explanation:

This is a geometric sequence. Each term is obtained by multiplying 4 with the previous term.

common ratio = -128 ÷ (-32) = 4

-2 *4 = -8

The sample space of rolling a six-faced dice is {1, 2, 3, 4, 5, 6}.

The sample space of an experiment is the set of all possible outcomes of the experiment. In the experiment of rolling a six-faced dice, the sample space is the set of all possible values that the dice can show when it is rolled.

Since a dice has six faces, each with a distinct number (1, 2, 3, 4, 5, or 6), the sample space of the experiment of rolling a six-faced dice is {1, 2, 3, 4, 5, 6}. This means that any time the dice is rolled, it can only show one of these six values.

It's important to note that the sample space is a finite set, as there are only a limited number of possible outcomes. In this case, the sample space contains only six elements, each representing one of the faces of the dice that can show up when it is rolled.

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The duration for the workout of Plan A is (total hours trained on Tuesday - total hours trained on Monday) / 2, and the duration of Plan B is (total hours trained on Monday - total hours trained on Tuesday) / 2.

Let's assume that Plan A lasts for x hours and Plan B lasts for y hours.

We can set up a system of two linear equations using the information provided:

x + y = hours trained with Plan A and Plan B on Monday

x + y = hours trained with Plan A and Plan B on Tuesday

Adding the two equations together:

2x + 2y = total hours trained on both days

Simplifying this equation, we get:

x + y = total hours trained on both days / 2

We can substitute this expression for x + y in one of the original equations, say the first one:

x + y = hours trained with Plan A and Plan B on Monday

(total hours trained on both days / 2) = hours trained with Plan A and Plan B on Monday

Similarly, we can substitute x + y in the second equation:

(total hours trained on both days / 2) = hours trained with Plan A and Plan B on Tuesday

Now we have two equations with two variables:

x + y = total hours trained on both days / 2

x + y = hours trained with Plan A and Plan B on Monday

Subtracting the second equation from the first, we get:

0 = (total hours trained on both days / 2) - (hours trained with Plan A and Plan B on Monday)

Therefore,

hours trained with Plan A and Plan B on Monday = total hours trained on both days / 2

We can use the same logic to find the hours trained with Plan A and Plan B on Tuesday:

hours trained with Plan A and Plan B on Tuesday = total hours trained on both days / 2

Since we know the total hours trained on both days and the hours trained with Plan A and Plan B on each day, so solving for x and y:

x = hours trained with Plan A and Plan B on Monday - hours trained with Plan A and Plan B on Tuesday

y = hours trained with Plan A and Plan B on Tuesday - hours trained with Plan A and Plan B on Monday

Substituting the expressions we found earlier, we get:

x = (total hours trained on both days / 2) - hours trained with Plan A and Plan B on Tuesday

y = (total hours trained on both days / 2) - hours trained with Plan A and Plan B on Monday

We can simplify these expressions to get:

x = (total hours trained on Tuesday - total hours trained on Monday) / 2

y = (total hours trained on Monday - total hours trained on Tuesday) / 2

Therefore, the duration of Plan A is (total hours trained on Tuesday - total hours trained on Monday) / 2, and the duration of Plan B is (total hours trained on Monday - total hours trained on Tuesday) / 2.

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Answer:

Step-by-step explanation:

Let the number be x

1.x-10

3.-8x+1

4.19x-½

5.(x+15)²

Answer:

The answer is 97 pieces left

Step-by-step explanation:

You can use the equation (10*10)-3 to solve your question.

have a great day!

Probability that the drug will be ineffective in more than two cases is 0,68.

Drug is effective in 9 cases out of 10, so the drug:

If the drug is tested on 12 patients, then there are 13 possibilities, namely:

In the problem, asked to find the probability of the drug being ineffective in more than 2 patients, there are 10 possibilities, namely

The way to find out the possibility of a drug being effective in 0-9 patients is:

P(effective ≤ 9) = P(effective 9) + P(effective 8) + ... + P(effective 0)

However, quite a lot is calculated if you use the formula above, less will be calculated if you use the method below:

P(effective ≤ 9) = 1 - ( P(effective 10) + P(effective 11) + P(effective 12) )

Let's try to start by calculating P(effective 10). P(effective 10) means the probability of being effective for 10 people and ineffective for 2 people. Then the effective probability is raised to the power of 10 and multiplied by the ineffective probability raised to the power of 2.

P(effective 10) = \((\frac{9}{10})^{10} .(\frac{1}{10} )^2\)

P(effective 10) = \(\frac{9^{10} }{10^{12} }\)

P(effective 10) = \(\frac{3486784401}{1000000000000}\)

So does P(effective 11) and P(effective 12)

P(effective 11) = \((\frac{9}{10} )^{11}.(\frac{1}{10})^{1}\)

P(effective 11) = \(\frac{9^{11} }{10^{12} }\)

P(effective 11) = \(\frac{3486784401}{1000000000000}\)

P(effective 12) = \((\frac{9}{10}) ^{12} .( \frac{1}{10} )^0\)

P(effective 12) = \(\frac{9^{12}}{10^{12}}\)

P(effective 12) = \(\frac{282429536481}{1000000000000}\)

So:

P(effective ≤ 9) = 1 - ( P(effective 10) + P(effective 11) + P(effective 12) )

P(effective ≤ 9) = 1 - ( \(\frac{3486784401}{1000000000000}\)+ \(\frac{3486784401}{1000000000000}\)+ \(\frac{282429536481}{1000000000000}\))

P(effective ≤ 9) = 1 - \(\frac{317297380491}{1000000000000}\)

P(effective ≤ 9) = 1 - 0,317297380491

P(effective ≤ 9) = 0,682702619509 ≈ 0,68

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Answer:

whats your question

Step-by-step explanation:

The area of the trapezoid with bases a1 = 84 ft, a2 = 50 ft, height h = 42 ft, and sloping sides b1 = 51.67 ft and b2 = 42.8 ft is XXX square feet.

To find the area of a trapezoid, we can use the formula: Area = (a1 + a2) * h / 2, where a1 and a2 are the lengths of the parallel bases, and h is the height of the trapezoid. In this case, a1 = 84 ft, a2 = 50 ft, and h = 42 ft.

Substituting these values into the formula, we get:

Area = (84 + 50) * 42 / 2

Area = 134 * 42 / 2

Area = 5616 / 2

Area = 2808 square feet.

Thus, the area of the trapezoid is 2808 square feet.

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Answer:

Step-by-step explanation:

First term is 3

common difference = 15/2 divided by 3 = 5/2

8th term = a * r^7

3 * (5/2)^7 = 1,831.0546875

To the nearest thousandth 1,831.055

Answer:

option plz

Step-by-step explanation:

where is the option

Answer:

no. they are not. add up the angles on each triangle to find x, if the angles are not exactly the same, then they are not similar

Coordinate of circumcenter of the given triangle = (3, 2)

What is circumcenter of a triangle?

Circumcenter of a triangle is the point of intersection of the perpendicular bisectors of every sides of the triangle.

Let the coordinate of circumcenter be (x , y)

Distance of Circumcenter from (4,2) =

\(\sqrt{(x - 4)^2 + (y-2)^2\)

Distance of Circumcenter from (3, 3) =

\(\sqrt{(x - 3)^2 + (y-3)^2\)

Distance of Circumcenter from (2,2) =

\(\sqrt{(x - 2)^2 + (y-2)^2\)

By the problem,

\(\sqrt{(x - 2)^2 + (y-2)^2} = \sqrt{(x - 3)^2 + (y-3)^2}\\(x - 2)^2 + (y-2)^2} = (x - 3)^2 + (y-3)^2}\\x^2 - 4x + 4 + y^2 -4y + 4 = x^2 -6x + 9 + y^2-6y + 9\\6x - 4x +6y -4y = 18-8\\2x +2y = 10\\x+ y = 5\\\)..... (1)

Again,

\(\sqrt{(x - 4)^2 + (y-2)^2} = \sqrt{(x - 3)^2 + (y-3)^2}\\(x - 4)^2 + (y-2)^2} = (x - 3)^2 + (y-3)^2}\\x^2 - 8x + 16 + y^2 -4y + 4 = x^2 -6x + 9 + y^2-6y + 9\\8x - 6x +4y -6y = 20-18\\2x -2y = 2\\x- y = 1\\\)...... (2)

Adding (1) and (2)

\(2x = 6\\x = \frac{6}{2}\\x = 3\)

Putting the value of x in (1),

3 + y = 5

y = 5 - 3

y  = 2

Coordinate of circumcenter = (3, 2)

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Answer:

Step-by-step explanation:

\(\text{rule}=a+\frac{b}{c}=\frac{ac+b}{c}\\ \\ 5\frac{1}{2}=\frac{5(2)+1}{2}\\ \\ \frac{11}{2}\)

The solution to the given indices are 1/2^7, 11^4 and -1/64

Give the following indices expression

\(\frac{(2^{-4})^2\times 2^{-5}}{2^{-6}} \\\)

This can be further simplified according to the law of indices as:

\(\frac{(2^{-4})^2\times 2^{-5}}{2^{-6}} =\frac{2^{-8-5}}{2^{-6}}\)

Determine the result

\(\frac{2^{-8-5}}{2^{-6}} = 2^{-7} = 1/2^7\)

For the indices expression

\(11^{-4}\times 11^{8} = 11^{-4+8}=11^4\)

For the indices expression

\(-4^4\times4^{-7}\\=-(4^{4-7})\\= -4^{-3}\\=-1/4^3\\=-1/64\)

Hence the solution to the given indices are 1/2^7, 11^4 and -1/64

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Answer:

900°

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

Here n = 7 , then

sum = 180° × 5 = 900°