What would the RPM be if we were turning a 1. 00" diameter work piece made out of mild


steel, using HSS cutting tool?

Answer:The controlled variable is the one that you keep constant. The responding variable or variables is what happens as a result of the experiment

Explanation:Mark me brainly please

The average acceleration of the motorcycle is determined as 3 m/s².

The acceleration of the motorcycle is calculated as follows;

a = (v - u)/t

where;

a = (15 - 6)/3

a = 3 m/s²

Thus, the average acceleration of the motorcycle is determined as 3 m/s².

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The temperature drops as soon as winter arrives. Air inside car tires shrinks as the temperature drops.

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When an object rolls without slipping down an inclined plane, the true statement(s) about static friction force are: It provides the torque to cause the angular acceleration and it goes against gravity to reduce the acceleration caused by gravity. The correct answer is B and E.

Friction is the force that opposes relative motion between surfaces in contact. It is also called a contact force because it operates between the surfaces in contact when they're in motion or when a force tries to move them relative to one another.

An inclined plane is a simple machine that consists of a sloping surface that connects a lower point to a higher point. It is one of the six classical simple machines that is used to reduce the effort needed to raise a weight to a certain height.

Rolling without slipping is a combination of translational motion (movement in a straight line) and rotational motion (movement around an axis) without any slipping occurring between the surfaces in contact. A wheel or any other circular object rolls without slipping when its forward motion is the same as its rotational motion.

Static friction is the force that keeps an object at rest or in a state of uniform motion on a surface when a force is applied on it. When two surfaces are in contact, static friction is the force required to overcome the sticking between them that resists motion.

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Answer:

7.15 m

Explanation:

From the question given above, the following data were obtained:

Height (h) = 10 m

Initial velocity (u) = 5 m/s

Horizontal distance (s) =?

Next, we shall determine the time taken for the shirt to get to the ground. This can be obtained as follow:

Height (h) = 10 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h= ½gt²

10 = ½ × 9.8 × t²

10 = 4.9 × t²

Divide both side by 4.9

t² = 10 / 4.9

t² = 2.04

Take the square root of both side

t = √2.04

t = 1.43 s

Finally, we shall determine the horizontal distance travelled by the shirt. This can be obtained as follow:

Initial velocity (u) = 5 m/s

Time (t) = 1.43 s

Horizontal distance (s) =?

s = ut

s = 5 × 1.43

s = 7.15 m

Thus, the shirt will land at 7.15 m away from the stage. Thus, to catch the shirt, you must be at a point 7.15 m away from the stage.

Answer:

It depends on 2 factors

the nature of the materials

the normal force.

Explanation:

It depends on 2 factors

the nature of the materials that are in friction and the treatment that they have followed. This factor is expressed by a numerical value called the coefficient of friction or friction.

the force exerted by one body on the other, that is, the normal force.

Answer:

g ≈ 2.82 m/s^2

Explanation:

By W = mg,

W = weight (in newtons)

m = mass (in kg)

g = gravitational acceleration (in m/s^2)

\(192 = 68g\)

\(g = 2.82352941176 m/s^2\)

g ≈ 2.82 m/s^2

When considering the sum of pressure and energy per unit volume as the diameter of the pipe changes, the correct answer remains constant. Therefore, option c. is correct.

To understand this, let's look at Bernoulli's equation for an ideal fluid in a horizontal pipe:
P + 0.5 * ρ * v² + ρ * g * h = constant

Where:
- P is the pressure
- ρ is the fluid density
- v is the fluid velocity
- g is the gravitational acceleration
- h is the height (which is constant in a horizontal pipe)

In this case, we can disregard the third term (ρ * g * h) because the height is constant in a horizontal pipe. Thus, the equation becomes:
P + 0.5 * ρ * v² = constant

As the diameter of the pipe increases, the cross-sectional area also increases, and the fluid velocity decreases to maintain the same flow rate. This decrease in velocity leads to an increase in pressure.

However, the sum of the pressure and kinetic energy per unit volume remains constant according to Bernoulli's equation.

So, option c. is correct.

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The magnetic field due to a  very long wire with current A is 6.67 x 10⁻⁷ A (Tesla).

This is the region of space where the effect of magnetic force is felt.

The magnetic field due to a current carrying conductor is calculated as;

B = μI/2πd

where;

at a distance of 0.3 m

B = μI/2π(0.3)

B = 0.53μI

B = 0.53 x (4π x 10⁻⁷)I

B = 6.67 x 10⁻⁷ A (Tesla)

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When 110V is applied to the secondary coil, the voltage across the primary coil of this step-down transformer is 2420V.

A step-down transformer is a device that reduces the voltage from the primary coil to the secondary coil. In this case, the voltage across the primary coil is 110V, and the voltage across the secondary coil is 5.0V. The ratio of the number of turns in the primary coil to the number of turns in the secondary coil determines the voltage transformation.

Let's denote the primary coil's number of turns as Np and the secondary coil's number of turns as Ns. The turns ratio is Np/Ns = 110V/5.0V, which simplifies to Np/Ns = 22.

Now, if we apply 110V to the secondary coil, we can find the voltage across the primary coil (Vp) by rearranging the turns ratio formula: Vp = (Np/Ns) * Vs, where Vs is the voltage across the secondary coil.

Substituting the values, we get Vp = (22) * 110V, which results in Vp = 2420V.

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To find the specific heat capacity, we can use the formula Q = mcΔT, where Q is the amount of heat energy required, m is the mass of the object, c is the specific heat capacity, and ΔT is the change in temperature.

Given:
- Mass of the object (m) = 50.0g
- Amount of heat energy required (Q) = 1,145 joules
- Change in temperature (ΔT) = 10.0°C

Using the formula Q = mcΔT, we can rearrange it to solve for c:
c = Q / (mΔT)
Plugging in the given values, we get:
c = 1,145 J / (50.0 g x 10.0 °C)
c = 2.29 J/g°C

Therefore, the specific heat capacity of the object is 2.29 J/g°C.

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The angular momentum of the tire is 0.394KGm^2/s.

To find the answer, we have to know more about the angular momentum.

                             \(L=mvr\)

where, m is mass of th body, v is the linear velocity and r is the radius of the circular orbit.

                 \(m=1.4kg\\r=33*10^{-2}m\\w=155rpm=2.58rps\)

                   \(v=rw=33*10^{-2}*2.58=0.85m/s\)

                  \(L=mvr=1.4*0.85*33*10^{-2}=0.394Kgm^2/s\)

Thus, we can conclude that, the angular momentum of the tire is 0.394KGm^2/s.

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Explanation:

the answers are calculated in above pictures

Answer:

Batteries are systems that store chemical energy and then release it as electrical energy when they are connected to a circuit. Batteries can be made from many materials, but they all share three main components: a metal anode, a metal cathode and an electrolyte between them. The electrolyte is an ionic solution that allows charge to flow through the system. When a load, such as a light bulb, is connected, an oxidation-reduction reaction occurs that releases electrons from the anode while the cathode gains electrons

Explanation:

Answer:

Replication Crisis

Explanation:

Replication crisis in psychology- It refers to the concerns about credibility of finding the results in psychological science.

Answer: it is turned into thermal energy

C. it is transformed into thermal energy

solid particles vibrate and slip past each other when they become liquid.

The correct reaction type for the above chemical equation is decomposition reaction.

A decomposition reaction is the splitting (of e.g. a matrix, an atom or a compound) into constituent parts.

Decomposition reactions are processes in which chemical species (reactant) break up into simpler parts (products). Usually, decomposition reactions require energy input.

The general reaction template of a decomposition reaction is as follows:

AB → A + B

Where;

According to this question, pottasium chloride decomposes into pottasium element and chlorine molecule as follows:

2KCl → 2K+ Cl₂

Therefore, the chemical reaction above is exemplary of a decomposition reaction.

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The nurse's duty in avoiding polypharmacy is to keep a thorough record of all medications you take, including their brand and generic names, dosages, and intended uses.

Polypharmacy includes the usage of many drugs as well as possibly unsuitable pharmaceuticals.

Assist patients and families close to getting a complete list of drugs. Rearrange the patient's electronic health record prescription list.

Look out for unsuitable and inaccurate medications. When rescribing drugs, use caution.

Keeping a complete record of all drugs you take, including their brand and generic names, doses, and intended use is the nurse’s role in preventing polypharmacy.

Hence, nurses play an important role in preventing polypharmacy.

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The cocountable topology is coarser than the usual topology and is not Hausdorff.

Let X be an infinite set and P (X) the power set of X. We define three topologies on X: the cofinite topology, the left ray topology, and the cocountable topology. We will compare each topology to the usual topology on X. We denote the usual topology by u.  

The Cofinite Topology Let F be the family of subsets of X such that F is either finite or X. That is, F = {A ⊆ X : A is finite or A = X}. The cofinite topology on X is defined by Tcf = {U ⊆ X : X \ U ∈ F} ∪ {Ø}. The open sets in the cofinite topology are the complements of finite sets plus the empty set.

A subset A of X is closed if and only if A is either X or finite. Thus, in the cofinite topology, every infinite subset of X is dense in X. Compared to the usual topology, the cofinite topology has fewer open sets and is coarser. In other words, the cofinite topology is a weaker topology than the usual topology.

The cofinite topology is also Hausdorff since given any two distinct points x, y ∈ X, the complements of the cofinite sets containing x and y are disjoint

. The Left Ray Topology Let F be the family of subsets of X such that F contains the empty set and all sets of the form L(a) = {x ∈ X : x < a}, where a is any element of X. The left ray topology on X is defined by TL = {U ⊆ X : U = ∅ or U contains some set L(a) from F}.

The open sets in the left ray topology are the empty set, all left rays L(a), and all sets that contain a left ray L(a). A subset A of X is closed if and only if A is the empty set, X, or contains the right endpoint of every left ray it meets. The left ray topology is finer than the cofinite topology but coarser than the usual topology.

Thus, the left ray topology is a weaker topology than the usual topology but stronger than the cofinite topology.

The left ray topology is also Hausdorff. The Cocountable Topology Let F be the family of subsets of X such that F is countable or all of X. The cocountable topology on X is defined by Tcc = {U ⊆ X : X \ U ∈ F} ∪ {Ø}. The open sets in the cocountable topology are the complements of countable sets plus the empty set.

A subset A of X is closed if and only if A is either countable or all of X. Thus, in the cocountable topology, every countable subset of X is nowhere dense.

Compared to the usual topology, the cocountable topology is coarser. The cocountable topology is also not Hausdorff since any two nonempty open sets have nonempty intersection. Hence, in the cocountable topology, the closure of a singleton set is the whole space X.

Among the three topologies, the cofinite topology is the weakest topology, and it is also a Hausdorff space. The left ray topology is a topology that is weaker than the usual topology but stronger than the cofinite topology, and it is also a Hausdorff space. Finally, the cocountable topology is coarser than the usual topology and is not Hausdorff.

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When a rock is transported from the moon to the earth, both mass and weight are changed.

Explanation:

The reason why both mass and weight are changed when a rock is transported from the moon to the earth is that the gravitational field on the surface of the earth is stronger than that on the surface of the moon.

This means that the rock's mass, which is the measure of the amount of matter that an object contains, will remain the same.

However, the rock's weight, which is the force with which an object is attracted to the earth due to gravity, will be different since the gravitational pull on the moon is much weaker than that on the earth. This implies that when the rock is transported from the moon to the earth, it will experience a higher gravitational force which will cause it to weigh more compared to when it was on the moon.

Therefore, both mass and weight will change when a rock is transported from the moon to the earth.

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Answer:

ATP

During cellular respiration, a glucose molecule is gradually broken down into carbon dioxide and water. Along the way, some ATP is produced directly in the reactions that transform glucose. Much more ATP, however, is produced later in a process called oxidative phosphorylation.

Explanation:

have a nice day.

The molar solubility of cobalt(III)hydroxide in a solution containing 0.068 M KOH at 25°C is approximately 1.22e-40 M.  

To determine the molar solubility of cobalt(III) hydroxide, Co(OH)3, in a solution containing 0.068 M KOH at 25°C, given that the solubility product, Ksp, is 1.6e-44.
Step 1: Write the balanced dissolution equation:
Co(OH)3(s) ⇌ Co3+(aq) + 3OH-(aq)
Step 2: Express Ksp in terms of molar solubility:
Ksp = [Co3+][OH-]^3
Step 3: Since the solution already contains 0.068 M OH-, let x be the molar solubility of Co(OH)3. Then,
[Co3+] = x
[OH-] = 0.068 + 3x

Step 4: Substitute the molar concentrations into the Ksp expression:
1.6e-44 = (x)(0.068 + 3x)^3
Step 5: Solve the equation for x (molar solubility of Co(OH)3):
As 1.6e-44 is a very small value, we can assume that 3x is much smaller than 0.068. Hence, we can approximate the equation as follows:
1.6e-44 = (x)(0.068)^3
Now, solve for x:
x = 1.6e-44 / (0.068)^3
x = 1.22e-40, Therefore, the molar solubility of cobalt(III) hydroxide is approximately 1.22e-40 M.

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Answer:water gets hot at 212 so incress

Explanation:

Answer:

False

Explanation:

It will increase

Answer:

The best-supported theory of our universe's origin centers on an event known as the big bang. This theory was born of the observation that other galaxies are moving away from our own at great speed in all directions, as if they had all been propelled by an ancient explosive force.

Explanation:

hope this helps tho i don't quite know what you mean

The electric field from the charged plate is -6.77 kN/C.

A piece of aluminum foil was charged by touching it to a charged rod, giving it a charge of -10 µC, and then placed on top of a charged plate where it hovers motionless in the air above it.

The force of gravity acting on the piece of aluminum foil, which can be done using the equation Fg = mg, where m is the mass of the aluminum foil and g is the acceleration due to gravity.

Fg = 6.90 g x 9.81 m/s^2 = 67.7 mN.

Use the fact that the aluminum foil is motionless to conclude that the electric force on it, Fel, must be equal in magnitude to the force of gravity, Fg.

Since the electric force on a charged particle in a uniform field is given by Fel = qE, where q is the charge of the particle and E is the electric field strength, we can use this equation to solve for E.

The electric field from the charged plate = -10 µC x E = 67.7 mN. Solving for E, we get E = 67.7 mN / (-10 µC) = -6.77 kN/C.

The negative sign indicates that the electric field points in the opposite direction to the direction of the electric force on the aluminum foil.

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The distance a speaker should be placed behind  other sound to have an amplitude 1.50 times is 4.523 m.

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.

Wavelength λ = v/f

Two in-phase loudspeakers emit identical 1000 Hz sound waves along the x-axis.

λ  = 343 m/s /1000 Hz

λ = 0.343 m

Distance, one should speaker be placed behind the other for the sound to have an amplitude 1.50 times that of each speaker alone.

The amplitude of the waveform due to waves,

A = 2a cos (ΔΦ/2)

ΔΦ = 2π x Δx/λ

So, A =  2a cos (π x Δx/λ)

Substitute the values, we get

1.5a = 2a cos (3.14 x  Δx/ 0.343)

Δx = 4.523 m

Thus, the distance is 4.523 m.

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Answer: Skeletal Muscles

Explanation:

Skeletal muscles are attached to the skeleton by tough connective tissues called tendons

Answer:

El edificio tiene una altura de aproximadamente 0.548 m

Explanation:

Podemos utilizar las ecuaciones del movimiento en dos dimensiones para resolver este problema. En primer lugar, podemos descomponer la velocidad inicial en sus componentes horizontal y vertical. Dado que la velocidad inicial es únicamente horizontal, la componente horizontal de la velocidad es de 30.0 m/s, mientras que la componente vertical es cero.

A continuación, podemos utilizar la ecuación de la posición vertical para determinar la altura del edificio. Esta ecuación es:

y = y0 + v0y t + (1/2) a_y t^2

donde y es la posición vertical final, y0 es la posición vertical inicial (en este caso, la altura del lanzamiento), v0y es la componente vertical de la velocidad inicial (en este caso, cero), a_y es la aceleración vertical (en este caso, la aceleración debido a la gravedad, que es de -9.8 m/s^2), y t es el tiempo de vuelo.

La distancia horizontal recorrida durante el vuelo es de 10.0 m, y la componente horizontal de la velocidad es de 30.0 m/s, por lo que podemos calcular el tiempo de vuelo como:

t = d / v0x = 10.0 m / 30.0 m/s = 0.333 s

Sustituyendo este valor en la ecuación de la posición vertical, y teniendo en cuenta que la velocidad vertical final también es cero (ya que el rollo vuelve al nivel del suelo), podemos despejar la altura del edificio:

y = y0 + (1/2) a_y t^2

y = 0 + (1/2) (-9.8 m/s^2) (0.333 s)^2

y = 0.548 m

Por lo tanto, el edificio tiene una altura de aproximadamente 0.548 m.

When an object of mass m is pushed to relativistic speed v, its momentum is given by the equation p = mv/(√(1-(v²/c²))),

Momentum is given by

p = mv/(√(1-(v²/c²)))

where c is the speed of light. As the object approaches the speed of light, its momentum becomes larger and larger, and the equation becomes more and more sensitive to small changes in velocity. This is because as an object approaches the speed of light, its mass increases and its energy approaches infinity, making it increasingly difficult to accelerate further. At the speed of light, an object's mass would be infinite, and it would require an infinite amount of energy to accelerate it any further.

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