What would be the gauge pressure in the tire when it’s temperature rises to 44 degrees Celsius

The number of peas that fit in a gallon jar is 7279634.

Space is occupied by every three-dimensional object. Its volume serves as a gauge for this space. The space contained by an object's limits in three-dimensional space is referred to as its volume. 

Given parameters:

Diameter of peas: d = 0.1 cm

Volume of the jar: V = 1 gallon = 3785.41 cm³.

Hence, radius of a pea: r = 0.1 cm /2 = 0.05 cm.

Volume of each pea = 4/3 πr³ cm³ = 4/3 π (0.05)³ cm³ = 0.00052 cm³

Hence, estimate number of peas that fit in a gallon jar = 3785.41 /0.00052  = 7279634.

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Answer:

atmosphere, gravitational pull, magnetic field

Explanation:

the astroids burn up in the atmosphere, gravitational pull alters the path of the astroids, and the magnanetic field deflects them of path.

Answer:

A. the rate that something moves and is calculated by taking distance divided by time

\(\text{Given that,}\\ \\\text{Power,} ~P=24~ KW = 24000~ W\\\\\text{Force,} ~F=600~N\\\\\text{We know that,}\\\\P=Fv\\\\\implies v = \dfrac{P}{F} = \dfrac{24000}{600}=40~ ms^{-1}\\\\\\\text{It travels at 40 m/s}\)

Answer:

1. conduction

2. a convection current

3. Heat is always transferred from the object at the higher temperature to the object with the lower temperature

4. noooooo!Heat is always transferred from the object at the higher temperature to the object with the lower temperature

5.convection

6. Thermal radiation

7. convection again!

A. Conduction is the transfer of thermal energy through direct contact. Convection is the transfer of thermal energy through the movement of a liquid or gas.

B. Radiation is the transfer of thermal energy through thermal emission.

C. the heat required to raise the temperature of the unit mass of a given substance by a given amount

1. conduction, 2. convection current, 3. hotter objects to cooler objects. 4. Radiation, 5. convection, 6. radiation, 7. convection.

There are three main modes of heat transfer:

Conduction: This is the transfer of heat through a material by direct contact between molecules. In this mode, heat flows from hotter to colder regions within the material until the temperature is equalized.

Convection: This is the transfer of heat through a fluid (liquid or gas) by the movement of the fluid itself. This mode of heat transfer can occur by natural convection (due to density differences in the fluid) or forced convection (due to an external source such as a fan).

Radiation: This is the transfer of heat through electromagnetic waves, without the need for a medium to transfer the heat. All objects emit and absorb radiation, and the amount of radiation emitted depends on the temperature of the object. This mode of heat transfer is important for heating and cooling applications, such as radiators or refrigerators.

Here in the question,

1. Heat is transferred directly from one particle of matter to another by the process of conduction.

2. A circular flow of warmer fluid and cooler fluid is called a convection current.

3. Heat is always transferred from hotter objects to cooler objects.

4. Radiation is the transfer of energy by electromagnetic waves.

5. Heat that is transferred by the movement of currents within a fluid is called convection.

6. The only form of heat transfer that does not require matter is radiation.

7. Water bubbling up through a hot spring at Yellowstone National Park is an example of convection.

Therefore, The Answers to those questions are 1. conduction, 2. convection current,3. hotter objects to cooler objects. 4. Radiation, 5. convection, 6. radiation, 7. convection.

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According to the question the tension in each wire is 1.96 N.

Tension is a term that describes the psychological and physical state of a person or system in which there is a high degree of stress, uncertainty, and anxiety. It is often associated with conflict and is often experienced when individuals or groups feel threatened or constrained in some way. Tension can be experienced in a variety of different contexts, from interpersonal relationships to the workplace. It can result from a variety of different factors, including a lack of communication, conflicting goals or expectations, and unmet needs.

The body is in equilibrium when the sum of all forces acting on it is equal to zero. In this case, the forces acting on the metal tube are the two wires and the weight of the tube due to gravity.

The tension in each wire is equal to the weight of the tube divided by the length of the tube. This is because the tube is suspended horizontally, so the forces in each wire must be equal in order to keep the tube in equilibrium.

Therefore, the tension in each wire is:

T = (9 kg × 9.8 m/s2) / (5 cm × 0.01 m)

= 1.96 N

Therefore, the tension in each wire is 1.96 N.

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Answer:

8.33 meters/sec.

time = 30 sec. 30 sec. = 8.33 meters/sec.

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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A force of 1 n accelerates a 1-kg box at the rate of 1 m/s2. the acceleration of a 2-kg box by a net force of 2 n is the same.

In physics, a force is an influence that could alternate the movement of an item. A force can motivate an item with mass to exchange its pace, i.e., to accelerate. pressure also can be described intuitively as a push or a pull. A pressure has each magnitude and route, making it a vector quantity.

it can also purpose a change in the direction, shape, size, and so forth., of the frame. Pushing or pushing a door with pressure is an example. force is a vector amount, which means it has each magnitude and route. Newton's 2d regulation defines force as the "manufactured from a frame's mass and acceleration."A force is not something that an item consists of or 'has in it'. Pressure is exerted on one object with the aid of another. The idea of a force isn't restrained to residing things or non-residing matters.

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Answer:

(B) a whole number of wavelengths.

Explanation:

Two beams of coherent light start out at the same point in phase and travel different paths to arrive at point P. If the maximum destructive interference is to occur at point P, the two beams must travel paths that differ by a whole number of wavelengths.

When the resultant effect of the combination of two identical waves result in their annihilation or complete cancellation of the effect of each other, destructive interference takes place. Hence to have two wave sources producing waves that have the same frequency wavelength and amplitude and which are always in phase with each other or have a constant phase difference are said to be Coherent source

The time taken for the box to get to the storage area, given that the box is moving at a constant velocity of 40 meters per minute is 0.2 minutes

Speed is defined as the distance travelled per time as shown below:

Speed = Distance / time

Cross multiply

Speed × time = distance

Divide both sides by speed

Time = Distance / speed

The following data were obtained from the question:

The time take can be obtained as follow:

Time = Distance / speed

Time = 8 / 40

Time = 0.2 minutes

Thus, the time taken to get the storage area is 0.2 minutes

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Plate tectonic theory is the movement of the plates or slabs of rigid rocks over the surface of the earth or the molten rocks that is the mantel.  

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If a 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Then the total work done by the force is equal to π/2 + 1.

To calculate the total work done by the force in this scenario, we can use the formula for work:

Work = ∫F(x) dx

where F(x) is the force as a function of position and dx represents an infinitesimal displacement.

In this case, the force is given by F(x) = √(1 - x²), and we need to find the total work done as the object moves from xo = -1 to xf = 1.

Let's break down the calculation step by step:

Write the integral for work:

Work = ∫F(x) dx

Substitute the given force:

Work = ∫√(1 - x²) dx

Integrate with respect to x:

To integrate the square root of (1 - x²), we use the trigonometric substitution. Let's substitute x = sin(θ) and dx = cos(θ) dθ.

Work = ∫√(1 - sin²(θ)) cos(θ) dθ

Simplify the integrand:

Using the trigonometric identity sin²(θ) + cos²(θ) = 1, we can rewrite the integrand as cos²(θ).

Work = ∫cos²(θ) dθ

Apply the power-reducing formula:

The power-reducing formula states that cos²(θ) = (1 + cos(2θ)) / 2. We can use this formula to simplify the integrand further.

Work = ∫(1 + cos(2θ))/2 dθ

Integrate the terms separately:

Work = (1/2) ∫dθ + (1/2) ∫cos(2θ) dθ

The first integral, ∫dθ, is simply θ, and the second integral, ∫cos(2θ) dθ, can be calculated as sin(2θ)/2.

Work = (1/2) θ + (1/2) (sin(2θ)/2) + C

Evaluate the integral limits:

To find the total work done, we need to evaluate the integral at the upper and lower limits of integration.

At xf = 1, the angle θ is π/2, and at xo = -1, the angle θ is -π/2.

Work = (1/2) (π/2) + (1/2) (sin(2(π/2))/2) - [(1/2) (-π/2) + (1/2) (sin(2(-π/2))/2)]

Simplifying further:

Work = π/4 + (1/2) - (-π/4 + (1/2))

Work = π/4 + 1/2 + π/4 + 1/2

Work = π/2 + 1

Therefore, the total work done by the force is equal to π/2 + 1.

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The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

Answer:

it can change an objects motion

Explanation:

an unblanaced force can make an object start moving

Answer:

2.64 x 10⁻⁶T

Explanation:

The magnitude of the magnetic field produced by a long straight wire carrying current is given by Biot-Savart law as follows: "The magnetic field strength is directly proportional to the current on the wire and inversely proportional to the distance from the wire". This can be written mathematically as;

B = (μ₀ I) / (2π r)                ----------------(i)

B is magnetic field

I is current through the wire

r is the distance from the wire

μ₀  is the magnetic constant = 4π x 10⁻⁷Hm⁻¹

From the question;

I = 0.7A

r = 0.053m

Substitute these values into equation (i) as follows;

B =  (4π x 10⁻⁷ x 0.7) / (2π x 0.053)

B = 2.64 x 10⁻⁶T

Therefore the approximate magnitude of the magnetic field at that location is 2.64 x 10⁻⁶T

Answer:

The characteristics that determine how easily two substances change temperature are:

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.

To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:

C = A × B

Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.

Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:

C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)

Now, let's expand the cross product using the properties of vector products:

C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +

   (3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +

   (1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)

Now, let's calculate each of these cross products:

C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +

   (3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +

   (1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)

Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:

C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k

Combining like terms, we get:

C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)

Simplifying further:

C = 6.00i - 12.00j + k

Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.

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The vector product of A and B is -3i - 5j - 9k.

The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.

In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.

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Answer:

200 N

Explanation:

Applying,

The force a golie must exert on the ball is,

F = ma...................... Equation 1

Where m = mass of the ball, a = acceleration of the ball.

But,

a = Δv/t............... Equation 2

Where Δv = change in velocity, t = time.

Substitute equation 2 into equation 1

F = m(Δv/t)............... Equation 3

From the question,

Given: m = 0.8 g, t = 0.1 s, Δv = 25 m/s

Substitute these values into equation 3

F = 0.8×25/0.1

F = 200 N

The net force on particle q₁ is approximately +25.6 N.

The electrostatic forces between particle q1 and the other two particles, q2 and q3, must be taken into account in order to determine the net force on particle q1. Coulomb's Law describes the electrostatic force between two charged particles:

F = k * |q₁ * q₂| / r²

F is the force, k is the electrostatic constant (9 x 109 N m2/C2), q1 and q2 are the charges' magnitudes, and r is the distance separating them.

Let's first determine the force between q1 and q2:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9 x 10^9 N m²/C²) * |(-29.6 μC) * (+37.7 μC)| / (0.630 m)²

F₁₂ = (9 x 10^9 N m²/C²) * (29.6 x 10^-6 C) * (37.7 x 10^-6 C) / (0.630 m)²

F₁₂ ≈ -7.45 N

The absence of a positive sign suggests an attractive force between q1 and q2.

Let's next determine the force between q2 and q3:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9 x 10^9 N m²/C²) * |(+37.7 μC) * (-10.8 μC)| / (0.315 m)²

F₂₃ = (9 x 10^9 N m²/C²) * (37.7 x 10^-6 C) * (10.8 x 10^-6 C) / (0.315 m)²

F₂₃ ≈ +33.05 N

The presence of a positive sign suggests a repulsive force between q2 and q3.

We must now add all the forces in order to determine the net force on q1:

Net force = F₁₂ + F₂₃

Net force ≈ -7.45 N + 33.05 N

Net force ≈ +25.6 N

The presence of a positive sign implies that the net force is pointing to the right, in the same direction as particle q2.

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(a) The work done by the 150 N force is 877.5 Joules.

(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.

To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.

(a) The applied force's work may be estimated using the following formula:

Work = Force * Distance * cos(theta)

where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.

As a result, the applied force's work is:

Work = 150 N * 5.85 m * cos(0) = 877.5 J

So, the work done by the 150 N force is 877.5 Joules.

(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.

The frictional work may be estimated using the following formula:

Work = Force of Friction * Distance * cos(theta)

The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.

Thus, the work done by friction is:

Work = 150 N * 5.85 m * cos(180) = -877.5 J

Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.

The coefficient of kinetic friction may be calculated using the following equation:

Friction Force = Kinetic Friction Coefficient * Normal Force

The normal force equals the crate's weight, which may be computed as:

Normal Force = mass * gravity

where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N

Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:

Force of Friction = coefficient of kinetic friction * Normal Force

150 N = coefficient of kinetic friction * 343 N

coefficient of kinetic friction = 150 N / 343 N ≈ 0.437

As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.

In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.

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Answer:

28 m/s

Explanation:

v(final)^2=v(initial)^2+2a(delta y)

=sqrt(2*-9.8 m/s^2*-40)

28 m/s

The speed of the camera with which it hits the water is 27.93 meters per second.

The speed of an object is the rate of change of position of an object in any of the directions. Speed can be measured as the ratio of distance covered by the object to the total time taken in which the distance was covered by the object. Speed is a scalar quantity because it has only magnitude and no direction.

v = gt

where, v is the velocity,

g is the acceleration due to gravity,

and t is the time taken by the object

v = (9.8 m/s²) (2.85s)

v = 27.93 m/s

Therefore, the speed of the camera as it hits the water is 27.93 meters per second.

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Answer:

d. an object immersed in a fluid is buoyed up by a force equal to the weight of the displaced fluid.

A. The English system uses one unit for each category of measurement.

Answer:

A

Explanation:

The normal forces that the wall applies to the pusher in ascending order are :Normal force in the third drawing (large angle),Normal force in the first drawing (medium angle),Normal force in the second drawing (small angle).

The normal force is the force that an object exerts on another object that is in contact with it. In the case of a person pushing against a wall, the normal force is the force that the wall applies to the person.

The magnitude of the normal force is determined by the angle at which the person is pushing against the wall. For a given magnitude of the pushing force, the normal force will be smaller when the angle is larger and larger when the angle is smaller.

In the first drawing, the angle is medium, so the normal force will be between the normal force in the second and third drawings.

In the second drawing, the angle is small, so the normal force will be larger than the normal force in the first drawing and smaller than the normal force in the third drawing.

In the third drawing, the angle is large, so the normal force will be the smallest of the three.

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The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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The focal length of the curved mirror is 6.67 meters.

The focal length of a curved mirror can be calculated using the mirror equation:

1/F = 1/Do + 1/Di

Where:

F = focal length of the mirror,

Do = distance of the object from the mirror and

Di = distance of the image from the mirror

In the given case, the object is located 2 meters in front of the mirror and the image is located 1.3 meters behind the mirror. Therefore:

according to the given data:

Do = 2 m

Di = -1.3 m (negative sign indicates that the image is behind the mirror)

Substituting in the equation, we get:

1/f = 1/2 - 1/1.3

Simplifying:

1/f = 0.15

Multiplying both sides by f:

= 6.67 meters

Therefore, the focal length of the curved mirror is 6.67 meters.

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Answer:

The answer is B. longitude wave