what will be the area of the given shape? (please help)

The expression for the total amount of sales the store makes will be:25s + 28.8p

Expression simply refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both.

From the information, the shoe store stocks x pair of sneakers and y pairs of sandals. During a promotion, a pair of sneakers is priced at $50 and a pair of sandals at $36. The shop manages to sell half the sneakers and 80% of the sandal.

Let sneakers = s

Let sandals = p

An expression for the total amount of sales the store makes will be: 1/2(50s) + 0.8(36p).

= 25s + 28.8p

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The transformation is not isometric because the side lengths did not remain the same and hence option C is the correct answer.

An isometric transformation is one that keeps the angles and distances between the original and changed shapes the same. There are numerous techniques that can be used to alter any image in a plane.

The two figures are isometric only if they are congruent. In the given figure the angles remain the same however the lengths of the side are transformed as the figure is dilated.

Hence, the transformation is not isometric because the side lengths did not remain the same and hence option C is the correct answer.

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Answer:

third one helps to get the median the best measure from centre.

Answer:

C. H 0 : μ = 7 vs. Ha : μ ≠ 7

Since the calculated value of t = -9.462 falls in the critical region  t ≤-2.048

We conclude that the  springtime water the tributary water basin around the Shavers Fork watershed is not neutral. We accept our alternate hypothesis and reject the null hypothesis.

Step-by-step explanation:

The null hypothesis the usually the test to be performed. Here we want to check whether the water is neutral or not. Neutral water must have a pH of 7 . This can be stated as the null hypothesis. And the claim is treated as the alternate hypothesis that water in not neutral or not having pH= 7

In symbols it will be written as

H0: : μ = 7 vs. Ha : μ ≠ 7

So choice C is the best option for this hypothesis testing.

Let the significance level be 0.05

The degrees of freedom = n-1= 29-1 = 28

The critical value is  t ≥ 2.048 and t ≤ - 2.048 for 0.05 two tailed test with 28 df.

The test statistic to use is t- test

t= x- u/ s/√n

The total sum is 170.9 and mean = x= 5.893

The u = 7

And the sample standard deviation is =s= 0.63

Putting the values

t= 5.893-7/0.63/√29

t= - 1.107/0.11699

t= -9.4623

Since the calculated value of t = -9.462 falls in the critical region  t ≤-2.048

We conclude that the  springtime water the tributary water basin around the Shavers Fork watershed is not neutral. We accept our alternate hypothesis and reject the null hypothesis.

Answer:

YeYEYEyYEEeeeeeeeeeeeeeeeeeeeeEE

Step-by-step explanation: kinda sounds like that epesode from squid game episode 7 i think

a. It represents the spread of the middle 50% of the data.

b. At least 50% of the students scored between 80 and 86.

c. Overall, we can say that the Math 6 class had a range of test scores, with some students performing very well and others performing less well.

How evenly distributed the middle 50% of the data is is determined by the interquartile range. In order to calculate it, the first quartile is subtracted from the third quartile.

A. The interquartile range (IQR) in a box-and-whisker plot is the distance between the first quartile (Q1) and the third quartile (Q3) of the data. It represents the spread of the middle 50% of the data.

B. To determine what percent of the students got 80% or higher, we need to find the upper fence, which is defined as 1.5 times the IQR above Q3. From the box-and-whisker plot, we can see that Q3 is approximately 86 and Q1 is approximately 71. Therefore, the IQR is 86 - 71 = 15. The upper fence is 1.5 * 15 + 86 = 108.5.

Looking at the plot, we can see that there are no data points above 100, so we can safely assume that no students scored above 100%. The highest score is 94, which is within the whiskers of the box-and-whisker plot. Therefore, we know that the percent of students who scored 80% or higher is between the percent of students who scored 80% or higher and the percent of students who scored 94% or higher.

From the plot, we can see that the median is approximately 80 and the third quartile (Q3) is approximately 86. This means that at least 50% of the students scored between 80 and 86. Additionally, we know that the maximum score is 94, so we can say that at least some students scored higher than 86. However, we don't know how many students scored between 86 and 94.

C. Based on the interquartile range, we can say that the middle 50% of the students scored between approximately 71 and 86. This suggests that there is a significant amount of variability in the test scores, as the range is quite wide. Additionally, we know that at least some students scored above 86, but we don't have enough information to determine how many or how high their scores were. Overall, we can say that the Math 6 class had a range of test scores, with some students performing very well and others performing less well.

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Answer:

-1

Explanation:

Let the number be x.

Then the equation will be:

3(x+18) = 51

=> 3x + 54 = 51

=> 3x = 51 - 54

=> 3x = -3

=> x = -3/3

=> x = -1

So, the number you thought of is -1.

Answer:

The number is 3.

Step-by-step explanation:

\(3(14+x)=51\\42+3x=51\\3x=9\\x=3\)

Answer:

33.51

Step-by-step explanation:

You need to use the equation \(\frac{4}{3} \pi r\)³.

Hope this helps.

Answer:10.7π

Step-by-step explanation:

radius=r=2

volume of sphere=4/3 x π x r x r x r

Volume of sphere=4/3xπx2x2x2

Volume of sphere=(4xπx2x2x2) ➗ 3

Volume of sphere=32π ➗ 3

Volume of sphere=10.7π

Answer & Step-by-step explanation:

In hypothesis testing, the claim being made is called the alternative hypothesis. The null hypothesis is the opposing statement, and it is presumed to be true until sufficient evidence suggests otherwise. The wording of the claim must be specific and precise, and one must clearly state the population, the parameter of interest, and the direction of the hypothesis test (i.e., one-tailed or two-tailed).

For example, a well-worded alternative hypothesis might be "The new teaching method will result in a higher mean test score for students than the traditional teaching method." In this case, the null hypothesis would be "The new teaching method will not result in a higher mean test score for students than the traditional teaching method."

An incorrectly worded claim might be "The new teaching method is better than the traditional teaching method." This claim is too vague because it does not specify in what way the new method is better, nor does it give a direction for the hypothesis test.

In summary, when conducting a hypothesis test to support a claim regarding the mean test score under a new teaching method, the wording of the claim must be specific and precise, and the claim will become the alternative hypothesis.

Applying the product rule gives

\(\displaystyle \frac{d}{dx}\int_1^{x^2}\frac{2t}{1+t^2}\,dt \times \int_1^{\ln(x)}\frac{dt}{(1+t)^2} + \int_1^{x^2}\frac{2t}{1+t^2}\,dt \times \frac{d}{dx}\int_1^{\ln(x)}\frac{dt}{(1+t)^2}\)

Use the fundamental theorem of calculus to compute the remaining derivatives.

\(\displaystyle \frac{4x^3}{1+x^4} \int_1^{\ln(x)}\frac{dt}{(1+t)^2} + \frac{1}{x(1+\ln(x))^2}\int_1^{x^2}\frac{2t}{1+t^2}\,dt\)

The remaining integrals are

\(\displaystyle \int_1^{\ln(x)}\frac{dt}{(1+t)^2} = -\frac1{1+t}\bigg|_1^{\ln(x)} = \frac12-\frac1{1+\ln(x)}\)

\(\displaystyle \int_1^{x^2}\frac{2t}{1+t^2}\,dt=\int_1^{x^2}\frac{d(1+t^2)}{1+t^2}=\ln|1+t^2|\bigg|_1^{x^2}=\ln(1+x^4)-\ln(2) = \ln\left(\frac{1+x^4}2\right)\)

and so the overall derivative is

\(\displaystyle \frac{4x^3}{1+x^4} \left(\frac12-\frac1{1+\ln(x)}\right) + \frac{1}{x(1+\ln(x))^2} \ln\left(\frac{1+x^4}2\right)\)

which could be simplified further.

Answer:

y = -1x+2

Step-by-step explanation:

(1,1)(7,-5)

y2-y1/x2-x1 = slope

-5-1/7-1 = -6/6= -1

y-y1 = slope(x-x1) // equation formula

y-1=-1(x-1)

y = -1x + 1 +1

y = -1x+2

Answer:

6

Step-by-step explanation:

the answer to the question is 6 :D

The 95th percentile of the actual losses that exceed the deductible is given as follows:

$1,198.

The exponential probability distribution, with mean m, is described by the following equation:

\(f(x) = \mu e^{-\mu x}\)

In which \(\mu = \frac{1}{m}\) is the decay parameter.

The probability of obtaining a value lower than x is given as follows:

\(P(X \leq x) = 1 - e^{-\mu x}\)

Losses incurred follow an exponential distribution with a mean of $396, hence the decay parameter is of:

\(\mu = \frac{1}{396}\)

\(\mu = 0.0025\)

The 95th percentile is x for which P(X < x) = 0.95, hence:

0.95 = 1 - e^(-0.0025x)

e^(-0.0025x) = 0.05

x = -ln(0.05)/0.0025

x = $1,198.

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The true statement based on the relationship depicted in the Venn diagram is that no rhombuses are trapezoids (option D).

To identify the true statement using the relationship represented in the Venn diagram, we need to analyze the overlapping regions and the properties of the shapes involved.

A trapezoid is a quadrilateral with at least one pair of parallel sides, while a rhombus is a quadrilateral with all sides of equal length. Let's evaluate the options:

A. All trapezoids are rhombuses: This statement is not true based on the diagram. The overlapping region between the trapezoids and rhombuses shows that there are trapezoids that are not rhombuses. Therefore, option A is incorrect.

B. All rhombuses are trapezoids: This statement is true based on the diagram. The entire region representing rhombuses is also included within the region representing trapezoids. Every rhombus can be considered a trapezoid because it has at least one pair of parallel sides. Thus, option B is correct.

C. No trapezoids are rhombuses: This statement is not true based on the diagram. The overlapping region indicates that there are trapezoids that are indeed rhombuses. Therefore, option C is incorrect.

D. No rhombuses are trapezoids: This statement is true based on the diagram. There is no overlap between the regions representing rhombuses and trapezoids, implying that no rhombus can be considered a trapezoid. Hence, option D is correct.

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The correct justification for the similarity between ∆MNO and ∆PQR is:

∆MNO was dilated by a scale factor of 3 from the origin, then rotated 90° clockwise about the origin to form ∆PQR.

To see why this is the case, we can apply the transformations to the vertices of ∆MNO and see if they match the vertices of ∆PQR.

First, we dilate ∆MNO by a scale factor of 3 from the origin:

M' = 3M = (3(3), 3(9)) = (9, 27)

N' = 3N = (3(9), 3(9)) = (27, 27)

O' = 3O = (3(12), 3(3)) = (36, 9)

Next, we rotate the dilated triangle 90° clockwise about the origin:

P' = (cos(90°)P - sin(90°)Q, sin(90°)P + cos(90°)Q)

= (0P - (-1)Q, 1P + 0Q) = (Qx + 1, Py)

Q' = (cos(90°)Q - sin(90°)P, sin(90°)Q + cos(90°)P)

= (0Q - (-3)P, 1Q + 0P) = (Px + 3, Qy)

R' = (cos(90°)R - sin(90°)S, sin(90°)R + cos(90°)S)

= (4R - 4S, -4R - 4S) = (4(R - S), -4(R + S))

Substituting the coordinates of the original vertices, we get:

P' = (-1 + 1, -3) = (0, -3)

Q' = (-3 + 1, -1) = (-2, -1)

R' = 4(-4 + 1, -1 + 3) = (-12, 8)

Comparing the coordinates of ∆PQR with those of the transformed ∆MNO, we can see that they match. Therefore, the similarity between ∆MNO and ∆PQR can be justified by dilating ∆MNO by a scale factor of 3 from the origin, then rotating it 90° clockwise about the origin to form ∆PQR.

Note that it is correct to state that LN ≅ MN and Nk ⊥ LM, so NK is the perpendicular bisector of LM and P is on NK. See attached image.

A perpendicular bisector is a line that cuts another line segment across the junction point at a straight angle. As a result, a perpendicular bisector always cuts a line segment through its midway. The phrase bisect implies dividing evenly or uniformly.

A simple technique to determine a perpendicular bisector is to measure the line segment you need to bisect. Then, divide the measured length by two to determine the midway. Draw a line at a 90-degree angle out from this middle.

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Full Question:

Tell whether the information in the diagram allows you to conclude that point P lies on the perpendicular bisector of LM. Explain your reasoning. See attached image.

A) No. You would need to know that LK ⊥ MK

B) No. You would need to know that KP ⊥ LM
C) Yes, t LN ≅ MN and Nk ⊥ LM, so NK is the perpendicular bisector of LM and P is on NK
D) Yes, NK ⊥ LM, so NK is the perpendicular bisector of LM and P is on NK

Answer:

The right answer is A (x=2,y=-1)

The temperature at the bottom of the mountain is 50.9 °C.

Let's work through the given information step by step to find the temperature at the bottom of the mountain.

The temperature in the hotel is 21 °C.

The temperature in the hotel is 26.7 °C warmer than at the top of the mountain.

Let's denote the temperature at the top of the mountain as T_top.

So, the temperature in the hotel can be expressed as T_top + 26.7 °C.

The temperature at the top of the mountain is 3.2 °C colder than at the bottom of the mountain.

Let's denote the temperature at the bottom of the mountain as T_bottom.

So, the temperature at the top of the mountain can be expressed as T_bottom - 3.2 °C.

Now, let's combine the information we have:

T_top + 26.7 °C = T_bottom - 3.2 °C

To find the temperature at the bottom of the mountain (T_bottom), we need to isolate it on one side of the equation. Let's do the calculations:

T_bottom = T_top + 26.7 °C + 3.2 °C

T_bottom = T_top + 29.9 °C

Since we know that the temperature in the hotel is 21 °C, we can substitute T_top with 21 °C:

T_bottom = 21 °C + 29.9 °C

T_bottom = 50.9 °C

Therefore, the temperature at the bottom of the mountain is 50.9 °C.

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Work Shown:

1.05*20 = 21

The 1.05 represents an increase of 5% because

100% + 5% = 1.00 + 0.05 = 1.05

Answer:

  \(cos(a-b) = \frac{117}{125}\)

Step-by-step explanation:

Explanation

Given that

 \(sina = \frac{7}{25} , cos a = \frac{24}{25} , sinb =\frac{3}{5} and cosb =\frac{4}{5}\)

Cos(a-b) = cosa cosb + sina sinb

             \(cos(a-b) = \frac{24}{25} \frac{4}{5} +\frac{7}{25} \frac{3}{5}\)

            \(cos(a-b) = \frac{96}{125} +\frac{21}{125} = \frac{117}{125}\)

Final answer:-

 \(cos(a-b) = \frac{117}{125}\)

Answer: the answer is (3,-2)

Step-by-step explanation: when you rotate a point about the origin 180 degrees clockwise, (x,y) turns into (-x,-y)

therefore

(-3,2) becomes (3,-2)

I'm pretty sure

Answer: r=11

Step-by-step explanation:

A=πr^2

A=121π

121π=πr^2

r^2=121

r=11

Answer:

None really

Step-by-step explanation:

Q=0

Answer:

2280

Step-by-step explanation:

Multiply 5 times 2325 it ain't that hard g just use google lol

Answer: -6 ( sorry im kinda rushing so cant explain )

Answer:

.25 * 5 = 1.25

.1    * 2 =  . 2

              1.45

Step-by-step explanation: