The first food eaten in space by an American astronaut was applesauce.
Applesauce was the first food eaten in space by American astronaut John Glenn during his orbital flight aboard Friendship 7 on February 20, 1962.
John Glenn, the first American astronaut to orbit Earth, was served pureed applesauce in a squeezable tube on board the Friendship 7 spacecraft on February 20, 1962.
The tube was made of lightweight plastic material, and the pureed applesauce was forced through a nozzle by squeezing the tube's sides.
The applesauce tube had been created by the Whirlpool Corporation to provide a handy, convenient way for astronauts to eat without needing to use utensils in zero-gravity.
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Matter must have two physical properties. 1. have mass, and 2 Select all that apply. MUST bE ,take up space, be measureable, use energy
Answer:
take up space
Explanation:
Matter is any substance that has mass and occupies space.
There are about 4 states of matter which are:
Solid Liquid Gases PlasmaSolids are have a definite shape and a fixed volume.
Liquids are not compressible and they flow
Gases are compressible and have no definite volume
Plasma are free charged particles found in the ionosphere.
The mass of any matter can be quantified and they predominantly takes up space.
Therefore, matter have two physical properties which are mass and that they take up space.
A ball rolls horizontally off a 4.5 m high shelf at 0.2 m/s, how far away from the desk does the ball hit the floor
Here is your Answer:
I need help with this will give brainly.
Remote-controlled planes may take over most hurricane-hunting missions
A. Vivid Language
B. Objective Language
Answer:
gogo
Explanation:
Light and sound waves both share what characteristic?
A: they both exhibit the doppler effect
B: light and sound are both transverse waves
C: they both move fastest in water
D: light and sound both require medium in which to travel
Answer i know they both exhibit the doppler effect, so i believe it is this one.
Explanation:
A binary star system consists of two stars very close to one another. The two stars have apparent magnitudes of m1 = 2 and m2 = 3. The apparent magnitude m is defined with a stars’ flux density F, compared to a reference star with m0 and F0: m−m0=−2.5log(F/F0) Calculate the total magnitude of the binary star system
The total magnitude of the binary star system is approximately 4.89.
To calculate the total magnitude of the binary star system, we need to consider the individual magnitudes of the two stars and combine them. The formula for combining magnitudes is:
m_total = -2.5 * log10(10^(-0.4 * m1) + 10^(-0.4 * m2))
Let's plug in the given values:
m1 = 2
m2 = 3
m_total = -2.5 * log10(10^(-0.4 * 2) + 10^(-0.4 * 3))
Using a calculator, we can evaluate this expression:
m_total ≈ -2.5 * log10(0.01 + 0.001) ≈ -2.5 * log10(0.011) ≈ -2.5 * (-1.958) ≈ 4.89
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El Burj Khalifa es la torre más alta de Dubai y mide 821 m. Si se deja caer una moneda desde lo alto de la torre, ¿cuál es la magnitud de la velocidad con la que choca con el suelo?
Answer:
Vf = 126,85 m/s
Explanation:
En este caso, vamos a asumir que la velocidad inicial de la moneda cuando se deja caer es cero, puesto que no nos lo indican. Al ser la velocidad inicial cero, lo unico que influye en la velocidad de la moneda es la gravedad y la altura, por ende, la siguiente formula nos ayudará a calcularla:
Vf² = Vo² - 2gh (1)
Pero como la velocidad inicial es cero, y si también asumimos que la dirección de bajada será nuestro eje positivo, entonces:
Vf² = 2gh (2)
Ahora solo nos queda, reemplazar los valores de altura que es 821 m, y la aceleración de gravedad que es 9.8 m/s² y resolvemos la velocidad:
Vf² = 2 * 9,8 * 821
Vf = √16091,6
Vf = 126,85 m/sEsta debería ser la velocidad con que llega al suelo.
Exitos
La magnitud de la velocidad con la que choca con el suelo es aproximadamente 126.898 metros por segundo.
Si despreciamos los efectos de la viscosidad del aire y la aceleración de Coriolis, entonces el movimiento de la moneda se describe por el movimiento de caída libre, es decir, un movimiento uniforme acelerado debido a la gravedad terrestre. La velocidad final de la moneda es determinada por la siguiente ecuación cinemática:
\(v = \sqrt{v_{o}^{2}+2\cdot a\cdot h}\) (1)
Donde:
\(v_{o}\) - Velocidad inicial, en metros por segundo.\(a\) - Aceleración, en metros por segundo al cuadrado.\(h\) - Altura, en metros.\(v\) - Velocidad final, en metros por segundo.Si sabemos que \(v_{o} = 0\,\frac{m}{s}\), \(a = 9.807\,\frac{m}{s^{2}}\) y \(h = 821\,m\), entonces la velocidad final de la moneda es:
\(v = \sqrt{\left(0\,\frac{m}{s} \right)^{2}+2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (821\,m)}\)
\(v\approx 126.898\,\frac{m}{s}\)
La magnitud de la velocidad con la que choca con el suelo es aproximadamente 126.898 metros por segundo.
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a new high speed 12 car italian train has a mass of 640 metric tons (640,000 kg). it can exert a maximum force of 400 kn horizontally against the tracks, whereas at maximum velocity (300 km/h), it exerts a force of about 100 kn. calculate its maximum acceleration.
The maximum acceleration of the Italian train is 0.16 m/s².
What is the maximum acceleration of the car?
The maximum acceleration of the car can be determined by applying Newton's second law of motion.
Newton's second law of motion states that, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma
where;
m is the mass of the objecta is the acceleration of the objectThe maximum acceleration of the Italian train is calculated as follows;
a = F/m
where;
F is the maximum force applied to the traina is the maximum acceleration of the traina = (100,000) / (640,000)
a = 0.16 m/s²
Thus, the maximum acceleration of the Italian train depends on the maximum force applied on the force and the maximum speed of the train, since the mass of the train will be constant.
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(27) Pendulum A has a 2 kg mass attached to a 1-meter length string. Pendulum B has a 4 kg mass attached to a 0.5-
meter length string. What is the frequency of each string? Does the longer or shorter string have a higher
frequency?
The 1 meter long string
b. The 0.5 meter long string
c. They are the same
(28) A pendulum has a period of 8 seconds. What is the length and frequency of the string?
a. 0.13 Hz and 16.21 meters
c. 0.79 Hz and 640 meters
b. 16.21 Hz and 0.13 meters
d. 0.13 Hz and 1579.13 meters
a.
As the length of the string attached to the pendulum increases, its frequency decreases. Hence, the frequency of shorter string will be higher. The frequency of the string is 0.13 Hz and the length of pendulum is 16 m.
What is frequency ?Frequency of an oscillation is the number of wave cycles per unit time. It is the inverse of time period. As the length of the pendulum increases, the frequency of oscillation decreases. Therefore, the shorter pendulum will have greater frequency.
Given time period of pendulum = 8 s.
then length of pendulum L = T²/4π² g.
l = 8²/4×π² × 9.8 m/s² = 16 m.
Frequency of the oscillation is the inverse of its time period. Hence, the frequency of the pendulum for a time period of 8 Hz is :
1/8 = 0.13 Hz.
Therefore, option a is correct.
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Please help thank you!
Answer:
mass, weight
Explanation:
mass is constant, and weight is dependant on your location
Answer:
I think d
Explanation:
because distance j
has to be the last one that's the only one with distance
Charlie wants to build a magnetic levitation train for his younger brother. Charlie has drawn a diagram of his train and has built the train. What should Charlie do next with his design?
A. Test the device, get feedback from other people, and revise the design if needed.
B. Show his design to other people and get feedback before selling his design.
C. Publish his design in a magazine as is and wait for investors.
D. Test the device and sell it to the local veterinarian.
Answer:
B
Explanation:
I can't explain right now, mabe later.
Two forces of magnitude 10n and 20n acting at an angle of 30 degree. what will be the x component of their resultant force?
The resultant of the forces is 29 N. Option D
What is the resultant force?The resultant force is the force that acts in a given direction. Now we have two forces as enumerated in the question.
Thus;
Resultant = √(10)^2 + (20)^2 - [2 * 10 * 20 * cos (60 - 30))
Resultant = 29 N
Thus, the resultant of the forces is 29 N.
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Missing parts;
Two forces of magnitude 10N and 20N act on a body in directions making angles 30° and 60° respectively with x-axis what is the resultant force
A.17N
B. 19N
C. 23N
D. 29N
E. 37N
Can somebody explain to me what’s 1/d^2 in electric force? And how do I graph it versus a force?
Answer:
so basically what you gotta do is, and then you can do that but you shouldn't do this
A motorcycle travels 1600m in 25s. What is the average speed of the motorcycle?
The average speed of the motorcycle is equal to 64 m/s.
What is the average speed?The average speed of a moving object can be described as the total distance traveled by it in a definite time interval. The average speed is a scalar quantity because it carries only the magnitude and no direction.
The average speed can be determined from the ratio of the total distance to the time taken to cover that distance.
The average speed formula can be written as follows:
Average speed = Total distance / total time taken
Given, the distance covered by the motorcycle = 1600 m
The total time taken by motorcycle = 25 sec
The average speed of the train = 1600/25 = 64 m/s
Therefore, the average speed of the given motorcycle is 64 m/s.
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A.
B.
C.
D.
E.
F.
G.
H.
Answer:
झझकोर देने की कोशिश की है और यह बात उस समय की है जब कुंवर जी के लिए एक ही है कि वह इस बात को भी नहीं
how far from the wall must you move to find the first quiet spot? assume a sound speed of 340 m/s .
Therefore, to find the first quiet spot, you need to move 0.17 meters away from the wall.
To find the first quiet spot, the distance from the wall needs to be calculated, assuming a sound speed of 340 m/s. The speed of sound in air is about 340 meters per second at standard temperature and pressure, making it an important factor in determining the distance from the wall.
The formula for calculating distance is as follows:
Distance = (n + 0.5) λn
Where, n = 1, 2, 3,…and λn = wavelength of the sound
The first quiet spot is where destructive interference occurs. It is also where the sound waves reflected from the wall are out of phase with the sound waves that are directly from the source. The distance to the first quiet spot from the wall is equal to one-half the wavelength of the sound.
Thus, it can be calculated as follows:
λn = v/f
Where v = speed of sound and f = frequency of the sound.
A quiet spot can be found by calculating the wavelength of the sound and then dividing it by 2.
So, we get;
λ = v/f
= 340 m/s / 1 kHz
= 0.34 m
One-half the wavelength is: (1/2)λ = 0.17 m
The first quiet spot is 0.17 meters from the wall.
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The nucleus and the _____ are held together by the electrostatic force.
Answer:
should be chemical bond
Explanation:
A 30 kg object has a frictional force of 60 N. It's coefficient of friction must be...?
A) 0.2
B) 2
C) .002
D) 20
mass = 30kg
frictional force = coefficient of friction * (mass * g)
g = 9.8 m/s^2
So:
60N = x * 294 N
x = 60 N / 294 N = 0,2
A hippo's body is 4.0 m long with front and rear feet located as in (Figure 1). The hippo carries 80% of its weight on its front foot. Part A How far from its tail is the hippo's center of gravity?
The hippo's center of gravity is located 3.2 meters from its tail.
To determine the distance of the hippo's center of gravity from its tail, we need to consider the weight distribution between its front and rear feet. Given that the hippo carries 80% of its weight on its front foot, we can assume that 80% of the hippo's total weight acts at the front. Let's denote the distance from the tail to the center of gravity as "x."
Since the rear foot is located at the tail, the remaining 20% of the weight acts at the rear foot. Using the principle of moments, we can set up the equation: (80% of the weight) * (distance from front foot to center of gravity) = (20% of the weight) * (distance from rear foot to center of gravity). Plugging in the given values, we have (0.8) * (4.0 - x) = (0.2) * x. Solving this equation, we find x = 3.2 meters. Therefore, the hippo's center of gravity is located 3.2 meters from its tail.
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How could you know that a chemical change has taken place?
___________ force is a supportive force that surfaces exert in order to prevent solid objects from passing through one another.
A. Contact
B. Regular
C. Normal
D. Field
When two swimmers are under water in a swimming pool, it is possible for
the interface between the water and the air to act as a mirror, allowing the
swimmers to see images of each other if they look up at the underside of
the surface. Explain this phenomenon.
Answer:
If they are looking at a large enoug h angle of incidence against a relatively calm surface, all the light will be internally reflected, allowing the swimmers to see each other.
Explanation:
In a 200.0-m relay race (each leg of the race is 50.0 m long), one swimmer has a 0.450 second lead
and is swimming at a constant speed of 3.90 m/s towards the opposite end of the pool. What minimum
speed must the second swimmer have in order to catch up with the first swimmer by the end of the
pool?
The minimum speed that the second swimmer must have in order to catch up with the first swimmer by the end of the pool is; 4.04 m/s
We are given the following facts;
Both swimmers swim the same distance of 50 m for a leg of the relay race.Swimmer 1 swims at constant speed of 3.9 m/s. Swimmer 1 has a 0.450 second head start.Formula for time taken is;
time = distance/speed
Time taken by swimmer 1 for one leg;
t₁ = 50/3.9
t₁ = 12.82 s
Since swimmer 1 has a head start of 0.45 s, then time that swimmer 2 must use in order to catch up is;
t₂ = 12.82 -0.45
t₂ = 12.37 s
Thus, speed of swimmer 2;
v = 50/12.37
v = 4.04 m/s
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1. Two 500 g point masses are rotating on a light frame at a radius of 0.1 m from a vertical axis. The angular speed of the system is 20 rad s-1. a a) What is the moment of inertia of the system about the axis? b) What is the angular momentum of the system about the axis? c) If the masses were pulled into a radius of 0.05 m by an internal radial force, what would the angular momentum of the system now be? d) What is the new angular speed of each mass? e) By how much did the energy of the masses change?
(a) The moment of inertia of the system about the axis can be calculated using the formula for the moment of inertia of a point mass rotating about an axis.
(b) The angular momentum of the system about the axis can be determined by multiplying the moment of inertia by the angular speed.
(c) If the masses are pulled into a smaller radius, the moment of inertia will change, resulting in a new angular momentum for the system.
(d) The new angular speed of each mass can be calculated using the principle of conservation of angular momentum.
(e) The change in energy of the masses can be determined by comparing the initial and final kinetic energies of the system.
(a) To calculate the moment of inertia of the system about the axis, we consider the two point masses rotating at a given radius. The moment of inertia for each point mass is given by the formula I = m * r², where m is the mass and r is the radius.
Since there are two masses, we can calculate the total moment of inertia by summing the individual moments of inertia.
(b) The angular momentum of the system is determined by multiplying the moment of inertia by the angular speed. Using the formula L = I * ω, where L is the angular momentum, I is the moment of inertia, and ω is the angular speed, we can find the angular momentum of the system.
(c) If the masses are pulled into a smaller radius, the moment of inertia will change. We can calculate the new moment of inertia using the same formula as in (a) but with the new radius. With the new moment of inertia, we can determine the new angular momentum of the system.
(d) To find the new angular speed of each mass, we apply the principle of conservation of angular momentum. The initial angular momentum of the system is equal to the final angular momentum. By rearranging the equation L = I * ω and solving for ω, we can calculate the new angular speed.
(e) The change in energy of the masses can be determined by comparing the initial and final kinetic energies of the system. The initial kinetic energy is given by (1/2) * I * ω², where I is the initial moment of inertia and ω is the initial angular speed.
Similarly, the final kinetic energy can be calculated using the new moment of inertia and angular speed. The difference between the initial and final kinetic energies represents the change in energy of the masses.
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(c) Life testing was made on six non-replaceable) electrical lamps and the following results were obtained. Calculate MTTF. (5 Marks)
MTTF or Mean Time to Failure can be calculated using the given data. The term MTTF is often used to describe the expected lifetime of electronic devices and other items.
Here is how to calculate MTTF when given data:(c) Life testing was made on six non-replaceable) electrical lamps and the following results were obtained.
Calculate MTTF.The following data has been given:Number of lamps, n = 6Total time, T = 10000 hoursFailures, f = 2MTTF formula is given as:MTTF = T / n * fWhere, T = total time during which the test was conducted.n = the number of items tested.f = the number of items failed.Using the given data, we can calculate the value of MTTF as follows:MTTF = T / n * f = 10000 / 6 * 2= 1666.67 hoursTherefore, the MTTF of the six non-replaceable electrical lamps is 1666.67 hours.
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A rocket leaves a launch pad at liftoff with a great deal of upward momentum. what was initially given downward momentum?
The downward momentum initially given is carried by the exhaust gases expelled from the rocket engines.
According to the law of conservation of momentum, the total momentum of a system remains constant if no external forces act on it. In the case of a rocket launching from a launch pad, the upward momentum of the rocket is balanced by an equal and opposite downward momentum given to something else in the system.
Typically, in rocket launches, the downward momentum is given to the exhaust gases expelled from the rocket engines. As the rocket engines expel gases at high speeds in the downward direction, the gases carry a significant amount of momentum in that direction. This downward momentum of the exhaust gases is equal in magnitude but opposite in direction to the upward momentum of the rocket.
So, in the scenario described, the downward momentum initially given is carried by the exhaust gases expelled from the rocket engines.
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Introduction to Physical Science: Tutorial and Asking Questions
This activity will help you meet these educational goals:
. You will ask questions to identify and clarify evidence for an argument.
. You will apply scientific principles to design a process.
Directions
Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end
of the activity, write a brief evaluation of your work.
Activity
Spend time observing or thinking about events that involve matter and energy. Which events can you explain? Which
events can't you explain? Now answer the following questions.
Part A
Describe three events that you cannot explain.
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Energy and matter are both conserved within natural processes. It follows that while energy and matter can adopt different forms, they cannot be produced or extinguished. Different types of matter and energy can combine, and energy and matter frequently cycle within a system.
Explain energy.
Energy is the ability to perform tasks. It could appear in numerous different forms, such as potential, kinetic, thermal, electrical, chemical, nuclear, etc. Additionally, there is heat and work, which is energy being transferred from one entity to another.
The most important source of chemical energy for sustaining life is found in food. The three states of matter—liquid, solid, and gas—are essential because matter and energy move in concert along food networks.
An ice cube composed of water, for instance, changes into liquid water when you add energy, and when you add even more energy, it turns into steam. The type of matter and the quantity of matter are the same as in the original cube, but the level of energy may be higher or lower.
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Which moon phase come after a new moon and before a first quarter moon?
How are the weight and the mass of an object related?
Answer:
The weight and the mass of an object are related because the weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it. w=mg
Provide three reasons for a leftward shift of the LM curve. Provide two reasons for a steep IS curve.
a. The shift of the LM curve to the left occurs due to a decrease in the money supply or an increase in the demand for money.
b. Two reasons for a steep IS curve are High Investment Demand and Inflexibility in Investment.
The LM curve shows the various combinations of interest rates and income that bring about the equality of the supply and demand for money.
Below are three reasons for the leftward shift of the LM curve:
1. Decrease in Money Supply: The leftward shift of the LM curve can occur if the money supply decreases. This causes the interest rates to rise because the demand for money is greater than the supply.
2. Increase in Money Demand: An increase in the demand for money can lead to a leftward shift of the LM curve. This happens when people want to hold more money than is available in the economy, and the interest rate rises as a result.
3. Increase in Prices: An increase in prices causes a leftward shift of the LM curve. This is because, at higher prices, people need more money to conduct their transactions, and an increase in the money supply is required to keep the interest rate constant.
Now, moving on to the steep IS curve:
1. High Investment Demand: A steep IS curve may occur if there is high investment demand. This happens when businesses are optimistic about the future and invest more, causing the demand for credit to increase and the interest rates to rise.
2. Inflexibility in Investment: A steep IS curve can also be caused by inflexibility in investment. This occurs when businesses are unwilling to change their level of investment due to economic conditions, and any changes in the interest rates have a significant effect on investment and output levels.
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A baseball rolls along a flat parking lot in a straight line at a constant speed of 3.8 m/s. How
far will the baseball roll in 15s?
This is a uniform rectilinear motion (MRU) exercise.
To start solving this exercise, we obtain the following data:
DATA:V = 3.8 m/sD = ¿?T = 15 secTo calculate the distance, multiply the speed by the time.
We apply the following formula: d = v * t
We clear our data in the formula:
\(\bf{d=3.8\dfrac{m}{\not{s}}*15 \not{s} }\)
\(\bf{d=57 \ m}\)
The baseball in 15 seconds will roll a distance of 57 meters.
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