What was the average speed of the truck for this trip?

The statement that best describes the activation energy on the graph below is the vertical difference between 1 and 2 (option B).

Activation energy is the energy required to initiate a reaction. For example, the flame from the fuse of a firecracker provides a small initial amount of energy, after which the explosive reaction proceeds by itself, releasing a considerably larger quantity of energy.

According to this question, a reaction proceeds from 1 to 3. The activation energy needed for the reaction to be initiated is the vertical line that extends to the peak of 2.

Therefore, it can be said that the statement that best describes the activation energy on the graph below is the vertical difference between 1 and 2.

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Answer:

Its A - A solution with a PH of 2 is a base.

Explanation:

What is a pH of 2?

Strong acids and bases

The pH is then equal to minus the logarithm of the concentration value. Hydrochloric acid (HCl) is an example of a strong acid. The pH of a 0.01M solution of HCl is equal to −log10(0.01), that is, pH = 2.

Answer:

2.77495 moles

Explanation:

Boron= 10.811g (according to periodic table)

\(33g*\frac{1mole}{10.811g B}=2.774951 moles B\)

The number of grams of solute in 1.000 L of 0.943 M potassium iodate is  201.803g

0.943M means, 1L contains 0.943 moles KIO3.

Amount in g = no of moles× molar mass.

Molar mass of KIO3 = 214 g/mol.

So, mass of KIO3 present= 214×0.943 g = 201.803g

A substance  dissolved in a solution is called a solute.  In liquid solutions, the amount of solvent  is greater than the amount of solute. One of the best examples of a solute in our daily activities is salt and water. Salt dissolves in water and therefore salt is a solute.

The major types of solute are:

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The first hint tells us the answer. When we dissolve 1 mol of NaCl, it will ionize into its ions.

NaCl ----> Na+ + Cl-

Glucose will not ionize and will stay as a whole compound.

We have the same volume of solution and the same concentration. But, since the NaCl ionizes into two ions. The concentration of the solutes in that solution is greater (it is the double).

Answer: The NaCl solution has the more solutes.

The statement "When a photon hits an electron and some of the photon energy is transferred to the charged particle" describes Compton scattering.

Whenever a charged particle- most typically electrons- causes photons to scatter, we identify this phenomenon as Compton scattering. As photons are scattered through interactions with these particles, they unavoidably experience reductions in their initial levels of energy and become characterized by longer wavelengths.

The extent to which they lose their original energies will rely on several factors that include both scattering angles and characteristics inherent within electrons themselves.

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The standard entropy change for the given reaction is -319.1 J/K.

The standard entropy change (ΔS°) for a reaction can be determined by calculating the difference between the sum of the standard entropies of the products and the sum of the standard entropies of the reactants.

In this reaction, the reactants are CH4 (methane) and O2 (oxygen gas), and the products are CO2 (carbon dioxide gas) and H2O (water vapor).

Using the standard entropy values from the tables, the sum of the standard entropies of the reactants is 186.3 J/K, and the sum of the standard entropies of the products is 505.4 J/K.

ΔS° = (ΣS° products) - (ΣS° reactants)

    = 505.4 J/K - 186.3 J/K

    = -319.1 J/K

Therefore, the standard entropy change for this reaction is -319.1 J/K. A negative value indicates that the reaction results in a decrease in entropy, meaning the products have less disorder or randomness compared to the reactants.

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The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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Answer:

Below

Explanation:

"has its volume increased 42 L"     <===so final volume is 48+28 (as written)

P1V1 / T1   = P2V2 / T2        T must be in Kelvin (add 273.15 to °C)

Looking for P1

Re-arrange

P1 = P2 V2 / T2   * T1 / V1    sub in the values

P1 = (2)(42+28) / (47+ 273.15) * (85+273.15) /(28)

P1 = 5.59  atm

Answer:

navier

JAJDKEKWNEHSJJXIDJ (i need to do that so i can post the answer haha)

Answer: TEAM NAVIER FOR LIFEEEE

IF U SUPPORT TRASHTA, I HAVE NO WORDS TO DESCIRBE YOU

For A, there are 1 mol of N2 and 5 moles of H2 reactioning.

To state the prediction for the leftovers for A, we should find the limiting reactant.

Given the reaction, we know that for every 1 mol of N2 there's 3 moles of H2.

So, applying the stoichiometry of the reaction:

Now, we could conclude that:

We have 1 mol of N2, but we actually need 5/3 mol of N2 according to the reaction. So, N2 is the limiting reactant.

We have 5 mol of H2, but we actually need only 3 moles of H2 according to the reaction. Thus, H2 is the excess reactant.

Therefore, the leftovers for A, are 5-3 = 2 moles of H2.

Answer:

.0014 M/s ( (mol*L^-1 / s) )

Explanation:

Since the rate law of a zero order reaction is Rate = k[A]^0, the rate is .0014 * (1.65)^0 = .0014

There are 3.4 milliliters of the active ingredient in the cough syrup bottle.

To calculate the volume of the active ingredient in the cough syrup bottle, we need to multiply the total volume of the bottle by the percentage of the active ingredient.

Given:

Total volume of the bottle = 68.0 mL

Percentage of active ingredient = 5.00%

First, we convert the percentage to a decimal by dividing it by 100:

Percentage of active ingredient = 5.00% = 5.00/100 = 0.05

Next, we calculate the volume of the active ingredient:Volume of active ingredient = Total volume of the bottle × Percentage of active ingredient

Volume of active ingredient = 68.0 mL × 0.05

Volume of active ingredient = 3.4 mL

Therefore, there are 3.4 milliliters of the active ingredient in the cough syrup bottle.

It's important to note that the calculation assumes a homogeneous distribution of the active ingredient throughout the solution.

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A chemist determines that a substance is composed of 30.4% nitrogen by mass and 69.6% oxygen by mass. The molar mass of the compound is 230.5 g/mol, the molecular formula is NO₂.

We must compute the empirical formula in order to ascertain the compound's chemical composition.

If we have 100 grams of the compound.

This suggests we have:

30.4 g of nitrogen

69.6 g of oxygen

Now, we have to convert the mass of each element to moles.

The molar mass of nitrogen (N) = 14.01 g/mol

the molar mass of oxygen (O)  =  16.00 g/mol.

Number of moles of nitrogen (N):

2.17 mol

Number of moles of oxygen (O):

4.35 mol

The simplest whole-number ratio between the moles of nitrogen and oxygen must now be determined. To calculate the ratio, we divide both numbers by the smaller value.

Moles N / moles O = 2.17 mol / 2.17 mol = 1.00

Moles O / moles O = 4.35 mol / 2.17 mol = 2.00

The ratio is approximately N₁O₂.

We divide the subscripts by their greatest common divisor to obtain the simplest ratio, since we are looking for the empirical formula. The empirical formula is NO₂ since the greatest common divisor in this situation is 1.

The molecular formula of the compound is NO₂.

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Answer:

electron carriers

Explanation:

User: Nad+ and fad are called because they move electrons and hydrogen ions throughout the cell to the mitochondria Weegy: NAD+ and FAD are called "electron carriers" because they move electrons and hydrogen ions throughout the cell to the mitochondria.

Answer:

c. precipitation

Explanation:

Let's consider the following balanced net ionic equation.

Cl⁻(aq) + AgNO₃(ag) ⇒ AgCl(s) + NO₃⁻ (ag)

What kind of reaction is this?

a. acid-base. No, because the reactants are not acids and bases.

b. redox. No, because all the species have the same oxidation numbers in the reactants and the products

c. precipitation. Yes, because an insoluble compound (AgCl) is produced, which then precipitates.

After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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In the given reaction, the limiting reactant is C₆H₆ (benzene).

To determine the limiting reactant as well as calculate the mass of HCl produced, compare the moles of each reactant.

The number of moles for each reactant:

Molar mass of Cl₂ = 35.5 g/mol + 35.5 g/mol = 71 g/mol

Moles of Cl₂ = mass of Cl₂ / molar mass of Cl₂

                     = 45 g / 71 g/mol

                     = 0.634 moles of Cl₂

Molar mass of C₆H₆ (benzene) = 12 g/mol + 6(1 g/mol) = 78 g/mol

Moles of C₆H₆ = mass of C₆H₆ / molar mass of C₆H₆

                        = 45 g / 78 g/mol = 0.577 moles of C₆H₆

Determine the stoichiometry between Cl₂ and HCl:

Cl₂ + C₆H₆ → C₆H₅Cl + HCl

Here, we can see that 1 mole of Cl₂ produces 1 mole of HCl.

Thus, the limiting reactant is C₆H₆ (benzene).

Calculate the mass of HCl produced:

Molar mass of HCl = 1 g/mol + 35.5 g/mol = 36.5 g/mol

Moles of HCl produced = moles of C₆H₆ = 0.577 moles

Mass of HCl produced = moles of HCl produced × molar mass of HCl

Mass of HCl produced = 0.577 moles × 36.5 g/mol

                                     ≈ 21.04 g

Therefore, approximately 21.04 grams of HCl will be produced.

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Answer:

Covalent

Explanation:

A wave is a recurring, periodic disturbance that moves from one place to another via a medium (like water).

A wave is a disturbance that moves or propagates away from its source. Although waves can move energy between locations, they do not always move mass. Common examples of waves are light, sound, and ocean waves.

Mobile phones and radar systems are two noteworthy examples of wave applications. Even though radio waves are usually thought to be safe and contribute to background radiation, it is still advised to keep your distance from radio wave sources.

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complete question;

Using your outline and the materials you’ve gathered, write a 250- to 500-word paper using word processing software. Be sure to proofread and revise your writing to catch any errors in grammar, spelling, logic, or organization. Add a works cited page at the end to give credit to your sources. Submit your completed paper and this activity to your teacher for evaluation. This is for Unit Activity: Waves in edmentum

The new volume (in L) is 12.2 L

Information given:

Volume 1 = 15.0 L

Temperature 1 = 298 K ---------> Temperature 2 = 383 K

Pressure 1 = 3.36 Atm -----------> Pressure 2 = 5.308 Atm

Information they're asking: New Volume 2?

Substituting it with numbers (Yay! we were provided Kelvins, that's always a plus), we get;

3.36 Atm * 15.0 L * 383 K = V2  = 12.2 L

298 K * 5.308 Atm

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Answer:

C- CARBON COMPONENTS ARE IN 2 ATOMS

H- HYDROGEN IS 6

Explanation:

C IS THE ELEMENTIC FORMULAE AND C2 IS THE MOLECULAR FORMULAE.

H IS HYDROGEN AND H6 MOLECULAR FORMULAE

A dam constructed to produce tidal power does so by harnessing water flow to drive turbines and electric generators .

Tidal energy was employed in grain mills to crush grains mechanically, just like wind energy was. grain crushing Here, the tidal energy generated by the turbines was used. Hydroelectric dams, which serve as significant energy storage, also employ tidal energy to store energy.

Tidal power can harm marine life because tidal turbines' whirling blades can cause marine organisms to perish. Fish habitations in tidal power settings may be impacted by noise from the turbines' rotation. Tidal energy can also affect how sediment and water are processed.

Therefore, option B is correct.

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The increasing order of the crystal field splitting- I− < Br− < S2− < SCN− < Cl−< N3 < F−< NCO−< OH−<C2O42−< O2−< H2O < acac− < NCS− < CH3CN <gly <py < NH3 < en  < bipy  < phen  < NO2−  < PPh3 < CN− < CO.

The ligands (affections to a metal ion) are listed in the spectrochemical series according to the strength of their field. The series was created by superimposing various sequences acquired from spectroscopic research because it is impossible to generate the full series by examining complexes with the single metal ion.

The ligands cyanide and CO are classified as strong-field ligands, whereas the halides are weak-field ligands. Ligands such as water and ammonia are said to create medium field effects.

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Answer:

Mass of water  = 36 g

Explanation:

Given data:

Amount of energy released = 1367 J = 1367/4.184 = 327 cal

Initial temperature = 45.2 °C

Final temperature = 36.2 °C

Amount of water = ?

Solution:

Specific heat capacity of water is 1 cal/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 36.2 °C -  45.2 °C

ΔT = -9°C

-327 cal = m×1 cal/g.°C ×  -9°C

m = -327 cal/-9cal/g

m = 36 g

Taking into account the definition of density, the mass of ice is 198,773.6004 kg.

Density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density= mass÷ volume

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

In this case, you know that:

Replacing in the definition of density:

0.917 g/cm³= mass÷ 2.1677×10⁸ cm³

Solving:

mass= 0.917 g/cm³ ×2.1677×10⁸ cm³

mass= 198,773,600.4 g= 198,773.6004 kg

In summary, the mass of ice is 198,773.6004 kg.

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