What type of wave does NOT need matter to carry energy? *
1 point
Sound wave
Ocean wave
Electromagnetic wave

Answer:

Golfer B hits his golf ball at a higher rate of speed and with more force. This means that golfer B's ball will travel for a longer period of time and a longer distance due to newtons first law, where it says an object in motion stays in motion, with the same speed and in the same direction.

Explanation:

Answer:

a skydiver falling at terminal (constant) velocity

Explanation:

The potential energy is at its maximum at each end of the swing and at its minimum at the bottom. Absent frictional losses, the kinetic and potential sum to a constant.

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An electric circuit containing a dry cell and a torch bulb is completed by including a metal screw driver having a wooden handle. The bulb does not glow as wood does not pass electricity through it.

An electric circuit conducting current is a closed path of wires and electrical components which allows current through them on the application of potential difference between two points in the path.

Materials are usually of two types, they are conductors and insulators. Insulators do not allow current to pass through them due to the arrangement of atoms in them.

Some of the examples of insulators are wood, plastic, stone, etc.

As wood is included in the circuit, the current is not continuous and breaks its flow at the point where wood id connected.

Thus, the bulb does not glow.

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RS is a composition of rotation and reflection in the Euclidean plane E². The precise description of RS depends on the specific properties of the rotation R and reflection S.

In general, if R and S have the same axis or line of symmetry, the composition RS results in a translation. If R and S have intersecting lines of symmetry, RS yields a glide reflection. If R and S have perpendicular lines of symmetry, RS produces a rotation.

It is important to consider special cases, such as parallel lines of symmetry, coinciding axes, or perpendicular lines of reflection, as they may lead to different outcomes. The classification of isometries in E² involves understanding how rotations and reflections combine to create different transformations in the plane.

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Answer:

Approximately \(5.40\; {\rm m\cdot s^{-1}}\) (assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\).)

Explanation:

Refer to the diagram attached. There are two forces on this tetherball: tension \(T\) in the string, and weight \(m\, g\)- where \(m\) is the mass of the tetherball.

Let \(T\) denote the tension in the string, and let \(\theta = 12^{\circ}\) denote the angle of elevation of this force. Decompose \(T\!\) into two components: horizontal and vertical:

The tetherball is moving in a horizontal plane, meaning that there is no motion in the vertical direction. Hence, the resultant force in the vertical direction should be \(0\). The vertical component of the tension \(T\, \sin(\theta)\) should exactly balance the weight of the tetherball \(m\, g\):

\(T\, \sin(\theta) = m\, g\).

Hence, the resultant (unbalanced) force on this tetherball would be equal to the horizontal component of tension: \(F_{\text{net}} = T\, \cos(\theta)\).

The length of the rope is \(l = 1.55\; {\rm m}\). Since this rope is also at the angle of \(\theta\) above the horizon, the radius of the circular motion in the horizontal plane would be \(r = l\, \cos(\theta)\).

Since the ball is in a centripetal motion, the resultant force on this ball would also be \(F_{\text{net}} = (m\, v^{2}) / (r)\), where \(v\) is the velocity of the ball.

Equate these two expressions of \(F_{\text{net}}\) to obtain:

\(\displaystyle T\, \cos(\theta) = F_{\text{net}} = \frac{m\, v^{2}}{r}\).

Additionally, \(T\, \sin(\theta) = m\, g\) since the forces on the vertical direction are balanced. Rewrite both this equation and the equation \(T\, \cos(\theta) = (m\, v^{2}) / (r)\) to isolate tension \(T\):

\(\left\lbrace \begin{aligned}& T\, \cos(\theta) = \frac{m\, v^{2}}{r} \\ &T\, \sin(\theta) = m\, g\end{aligned}\right.\).

\(\left\lbrace \begin{aligned}& T = \frac{m\, v^{2}}{r\, \cos(\theta)} \\ &T = \frac{m\, g}{\sin(\theta)}\end{aligned}\right.\).

Solve this system for velocity \(v\):

\(\begin{aligned}\frac{m\, v^{2}}{r\, \cos(\theta)} &= \frac{m\, g}{\sin(\theta)}\end{aligned}\).

Since \(r = l\, \cos(\theta)\):

\(\begin{aligned}\frac{m\, v^{2}}{l\, \cos(\theta)\, \cos(\theta)} &= \frac{m\, g}{\sin(\theta)}\end{aligned}\).

\(\displaystyle \frac{m\, v^{2}}{l\, \cos^{2}(\theta)} = \frac{m\, g}{\sin(\theta)}\).

\(\begin{aligned}v &= \sqrt{\frac{g\, l\, \cos^{2}(\theta)}{\sin(\theta)}} \\ &\approx \sqrt{\frac{9.81\, (\cos(12^{\circ}))^{2}}{(1.55)\, \sin(12^{\circ})}}\; {\rm m\cdot s^{-1}} \\ &\approx 5.40\; {\rm m\cdot s^{-1}}\end{aligned}\).

Answer:

4.27m

Explanation:

Recall that for uniform rotational motion,

the formula for centripetal acceleration is given as

Centripetal acceleration = ( velocity)² / radius

in our case we are given :

Centripetal acceleration = 9.0 m/s²

velocity = 6.2 m/s

substituting these into the formula:

9.0 = 6.2² / radius

radius = 6.2² / 9.0 = 4.27m

Answer:

False

Explanation:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

Answer:

ooooooooooooooooo

Explanation:

*makes holy water*

Answer:

625000 J

Explanation:

KE = mv^2/2

= (2000kg*(25m/s^2))/2

= 625000 J

car moved 80 km to the South. What is its displacement? 80 km South -------------------------------------

The load diagram for a 40D ocean container with 101010-inch boxes, assuming a 40*48 inch pallet that is 6 inches tall, can accommodate approximately X number of boxes.

To calculate the load diagram, we need to consider the dimensions of the container, pallet, and boxes, as well as their weights. The internal dimensions of a 40D ocean container are typically around 39'6" in length, 7'8" in width, and 7'10" in height.

First, let's calculate the number of pallets that can fit on the container floor. Since the pallet dimensions are 40*48 inches, we divide the container's width (7'8" or 92 inches) by the pallet width (48 inches). This gives us approximately 1.92, so we can fit 1 pallet in the width direction.

Next, we divide the container's length (39'6" or 474 inches) by the pallet length (40 inches) to find that we can fit approximately 11.85 pallets in the length direction. However, since the 40D container is not long enough to accommodate 12 full pallets, we can only fit 11 pallets in this direction.

Considering the height, we need to account for the 6-inch tall pallet as well as the 10-inch tall boxes. Since the container's height is 7'10" (or 94 inches), we subtract the combined height of the pallet and boxes (6 + 10 = 16 inches) from the container's height. This gives us 94 - 16 = 78 inches available for stacking.

Finally, we multiply the number of pallets (11) by the number of boxes that can be stacked (7) to find the total number of boxes that can fit in the container: 11 * 7 = 77 boxes. Therefore, the load diagram for a 40D ocean container with 101010-inch boxes and a 40*48-inch pallet that is 6 inches tall can accommodate approximately 77 boxes.

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The heaviest elements not appreciably larger than the lightest elements are the transition metals. These metals include elements like iron, copper, and gold. Although they are heavier than the lightest elements like hydrogen and helium, their size is not significantly larger.

This is because the size of an atom is determined by the number of protons in its nucleus and the number of electrons in its outermost shell. While the transition metals have more protons than the lightest elements, their outermost shells are also more tightly bound to the nucleus, making their size relatively small.

The size of an atom is also affected by the electron configuration, which determines the size of the electron cloud. The transition metals have a relatively stable electron configuration, which contributes to their small size. Additionally, the presence of multiple energy levels in the electron cloud of the transition metals means that they can have a range of sizes, with some being slightly larger than others.

In summary, the heaviest elements not appreciably larger than the lightest elements are the transition metals, which have a relatively small size due to the number of protons in their nucleus, the stability of their electron configuration, and the presence of multiple energy levels in their electron cloud.

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The similarities and differences between chemical and nuclear energy sources includes the origin of their existence and the problem of waste production respectively.

The differences between the sources of chemical energy and nuclear energy are,

• The sources of chemical energy includes batteries Biomass, Petroleum, natural gas and coal etc.

• On the other hand, sources of nuclear energy includes radioactive materials like uranium and plutonium.

The similarities between the sources of chemical energy and nuclear energy are,

Both the chemical energy sources and the nuclear energy sources are present in Limited amount.

Substances like uranium, plutonium, natural gas petroleum are not reusable.

Also, both the sources produces a great threat for the environment.

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Answer:

Significant

Explanation:

As the word suggests, significant figures or digits are numbers that are valid in measurement.

Answer:

SIGNIFICANT DIGITS

Explanation:

MARK ME BRAINLIEST PLZZZ

Answer:

6.7miles due south

Explanation:

Given parameters:

Time  = 23min(0.383hr)

Average velocity  = 17.5mph

Unknown:

How far he has ridden  = ?

Solution:

To solve this problem,

      Displacement  = Velocity x time

 Displacement = 17.5 x 0.383  = 6.7miles due south

This question involves the concept of magnification.

The distance to the magnified image will be "24 cm".

The magnification of the magnifying glass is given by the following formula:

\(M=\frac{q}{p}\\\\q=Mp\)

where,

Therefore,

q = (4)(6 cm)

q = 24 cm

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The bulk is then released after being dragged down a further 1.5 cm. We'll have 0.284 seconds The period of isolation is now.

In a nutshell, what does distance mean?

The total movement of an object independent of direction is its distance The amount of space that an object has traveled rgardless of where it started or ended is referred to as distance.

What does distance look like in physics?

By combining the two lengths traveled by an automobile the total distance can be determined for instance if the vehicle drives 100 meters north. before making a right turn and heading 300 meters further east. In this instance the vehicle traveled a total of 400 meters.

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Answer:

Assess what information you are given. Use this method if you know:

the total distance covered by one person or vehicle; and

the total time it took that person or vehicle to cover the distance.

Explanation:

Hope this helps! I might be wrong, so tell me if I am

Answer:

Average speed can be calculated by dividing the total distance the object travels by the total amount of time it takes to travel that distance.

Explanation:

This is as much as I can help you, i don't know much else on how to do that ;w; sorry

Answer:

The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).

Explanation:

Answer:

In the NBA that's true

Answer: Your weight alone can determine the percentages of your body's composition

Explanation:

C. Your weight alone can determine the percentages of your body's composition.

Body composition analysis is the assessment of the proportion of fat to fat-free mass in your body.

Performing Body Composition Assessment will tell you your own body's unique makeup and help you identify areas to work on to improve your overall health and wellness.

Thus, the statement that is NOT true about the Body Composition Assessment is your weight alone can determine the percentages of your body's composition.

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The time it takes for a disturbance to traverse the entire length of a transmission line depends on the length of the line and the speed at which the disturbance travels.

To calculate this time in nanoseconds, you can follow these steps:

step1. Determine the length of the transmission line (L) in meters.

step2. Determine the speed of the disturbance (V) in meters per nanosecond (m/ns).

step3. Calculate the time (T) it takes for the disturbance to traverse the entire length of the transmission line using the formula: T = L / V.

Without the specific values for the length of the transmission line and the speed of the disturbance, it's impossible to provide an exact answer in nanoseconds.

However, if you have those values, you can use the above formula to find the answer to one place after the decimal.

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The force between the rods are -3.486 x 10⁻⁴ N, the two rods are oppositely charged, the force is an attractive force.

Force is an influence on an object or system that will cause it to undergo acceleration, change in direction or shape, or be deformed. It is the result of an interaction between two bodies, and it is measured as a vector quantity with direction and magnitude. Force can be classified into contact forces, such as a push or pull, and non-contact forces, such as gravitation.

The force between two oppositely charged rods can be calculated using Coulomb's law. Coulomb's law states: F = k(q₁×q₂)/r²

where F is the force, k is a constant, q₁ and q₂ are the charges of the two rods (in coulombs), and r is the distance between the two rods (in meters).

Therefore, the force between the two rods in your example can be calculated as follows:

F = (8.99 x 10⁹ Nm²/C²)(7.5 x 10⁻⁷ C)( -5.1 x 10⁻⁵ C) / (0.09 m)²

F = -3.486 x 10⁻⁴ N

Since the two rods are oppositely charged, the force is an attractive force.

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Answer:

Jorge wanted to know where the apples were

Explanation:

Ya see, I don't want to explain, cuz I guessed. Also I'm on episode 499 of naruto so yeah

Answer:

B:Jorge wanted to know where the apples were.

Explanation:

Therefore, the electric field (magnitude only) at a distance of 8.0 cm from the wire is approximately 3.24 x 10^4 N/C.

The electric field of a long, thin wire can be determined by Coulomb's law. Coulomb's Law states that the electric force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

For a long, thin wire, the electric field is given by;

E = λ/2πε₀r

Where;

λ = linear charge density = 91 µC/m,

ε₀ = permittivity of free space = 8.85 x 10^-12 C^2/Nm^2

r = distance from the wire = 8.0 cm = 0.08 m.

Substitute the given values into the formula to find the electric field;

E = (91 x 10^-6)/(2 x π x 8.85 x 10^-12 x 0.08)

E≈ 32433.8 N/C

E≈ 3.24 x 10^4 N/C.

Electric field refers to the force per unit charge that one object exerts on another object due to the electric charge present in the objects. It is a vector quantity and is measured in newtons per coulomb (N/C).

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Answer:

\(Vg=200mile/hr\)

\(\theta=153 \textdegree\)

Explanation:

From the question we are told that:

Plane airspeed \(v_p=190mil/h\)

Plane direction \(\angle=150 \textdegree\)

Wind current speed \(V_w=30mil/h\)

Wind direction \(\angle=150 \textdegree\)

Generally the vector form of the forces is mathematically given by

For plane

\(\angle Q_p=90-150 \textdegree\)

\(V_p=170(cos60 \textdegree ,sin60 \textdegree)\)

\(V_p=(85,-147.224)\)

For wind

\(\angle Q_w=90-170 \textdegree\)

\(V_w=30(cos-80 \textdegree ,sin-80 \textdegree)\)

\(V_w=(5.2,-29.54)\)

Generally the equation for resultant force is mathematically given by

\(v_r=V_a+V_w\)

\(v_r=(85,-147.224)+(5.2,-29.54)\)

\(v_r=(90.21,-176.76)\)

\(v_r=198.45\angle -63\)

Therefore ground speed

\(V_g=198.5miles/hr\)

\(Vg=200mile/hr\)

Direction

\(\theta=(90+63)=153 \textdegree\)

\(\theta=153 \textdegree\)

B. Wanning gibbous. The moon transit after midnight and it is almost full (not Full Moon) and it comes after the full moon phase.

The Moon and planets don't discharge their own light - we see them overhead simply because they reflect daylight. Contingent upon the general places of the Earth, Sun and a planet or the Moon, fluctuating measures of the surface seem enlightened. How much enlightenment is known as the phase.

A total pattern of phases is noticeable for the mediocre planets, Mercury and Venus. Early adaptive perceptions of Venus by Galileo were utilized to help the Copernican view that the Sun was at the focal point of the Planetary group (a heliocentric model). Mars is seen to have a gibbous phase when it is close to quadrature (lengthening = 90o and 270o).

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