what type of path do the hikers observe that the pack follows?

Explanation:

Using Kinematics,

we have a = (v - u) / t.

Therefore a = (36m/s - 22m/s) / 5s = 2.8m/s².

Answer:

B

Explanation:

A tractor is the heaviest

Answer:

 R₁ = (n -1) f

Explanation:

In geometric optics the focal length and the radius of curvature are related, for the case of a lens

          1 / f = (n₂-n₀) (1 / R₁ - 1 / R₂)

where f is the focal length, n₂ is the refractive index of the material, n₀ is the refractive index of the medium surrounding the material, R₁ and R₂ are the radius of curvature of each of the material's

In our case, the most common is that the lens is in the air, so n1 = 1, in many cases one of the surfaces is flat, so its radius of curvature R₂ = ∞.

     1 / f = (n-1) (1 / R₁)

we look for the radius of curvature R₁

    1 / R₁ = 1 / f (n-1)

     R₁ = (n -1) f

With this expression we can find the radius of curvature of a concave-plane lens

Answer:    

2 : A large storm

Explanation: I hope this helps

Answer:a vertical expanse of water stretching between the surface and the floor of a body of water

Explanation:

Answer:

Explanation:

From the given information:

The speed of a synchronous motor in relation to its frequency can be represented with the formula:

\(n_{sm}= \dfrac{120f_{se}}{P}\)

where,

the electrical frequency \(f_{se}\) is measured in Hz

the number of poles = P

For us to estimate the number of poles to have 50 Hz - 60 Hz Power, then we need to relate the frequencies of the above equation.

i.e

\(\dfrac{120(50 \ Hz)}{P_1}= \dfrac{120( 60 \Hz)}{P_2} \\ \\ \dfrac{6000 \ Hz}{P_1}= \dfrac{7200 \ Hz}{P_2} \\ \\ \dfrac{P_2}{P_1}=\dfrac{7200}{6000} \\ \\ \\ \dfrac{P_2}{P_1}= \dfrac{12}{10}\)

Thus, we can conclude that 10 poles synchronous motor is attached with 12 poles synchronous generator in order to convert 50 Hz to 60 Hz power.

The change in the tension if the radii r changes from 4.0 cm to 4.1 cm, and R changed from 0.8 cm to 0.9 cm is negative, therefore, tension reduces.

Mass of the yoyo = 0.001 kg

Initial value of the spindle radius, R = 4 cm

Initial length of the radius of the yo–yo, r = 0.8 cm

The final values are;

R2 = 4.1 cm, r2 = 0.9 cm

Which gives;

\(T_{r \:R} = \frac{0.001 \cdot g \cdot R }{2 \cdot r^{2} + R^2} \)

Which gives;

\(T_{{r _1 \:R _1 }} = \frac{0.001 \times 9.8 \times 0.04 }{2 \times 0.008^{2} + 0.04²} = \frac{49}{216} \)

\(T_{{r _2 \:R _2 }} = \frac{0.001 \times 9.8 \times 0.041 }{2 \times 0.009^{2} + 0.041^2} = frac{2009}{9215} \)

Therefore;

\( \Delta T_{{r \:R }} = frac{2009}{9215} - \frac{49}{216} = - \frac{17591}{1990440} \)

Given that difference between the final and the initial states is negative, the the value of the tension decreases

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Answer:

The force of gravity on an object depends on the mass of the object and the mass and distance of the celestial body it is on or near. The formula for the force of gravity is:

F = G * (m1 * m2) / r^2

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

To compare the force of gravity on an 81 kg mass on the Moon's surface with the force on the Earth's surface, we need to calculate each force using the above formula and then compare the results.

First, let's calculate the force of gravity on an 81 kg mass on the Earth's surface:

F_Earth = G * (m1 * m2) / r^2

= 6.67 x 10^-11 Nm^2/kg^2 * (81 kg * 5.97 x 10^24 kg) / (6.38 x 10^6 m)^2

= 7.92 x 10^2 N

So the force of gravity on an 81 kg mass on the Earth's surface is 792 N.

Next, let's calculate the force of gravity on an 81 kg mass on the Moon's surface:

F_Moon = G * (m1 * m2) / r^2

= 6.67 x 10^-11 Nm^2/kg^2 * (81 kg * 7.35 x 10^22 kg) / (1.74 x 10^6 m)^2

= 1.32 x 10^3 N

So the force of gravity on an 81 kg mass on the Moon's surface is 1320 N.

Therefore, the force of gravity on the Moon's surface is greater than the force of gravity on the Earth's surface. The ratio of F_Earth to F_Moon is:

F_Earth / F_Moon = 792 N / 1320 N

= 0.6

So the force of gravity on the Moon's surface is about 60% of the force of gravity on the Earth's surface.

4764 joule is potential energy associated with the spring-nugget system

Potential energy ,P =mgh

mass= 286 kg

g=9.8 m/s^2

h= 1.70 m

P =mgh

P=×286 kg×9.8×1.70

P=4764 joule

Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is squeezed or extended, its potential energy increases. If a steel ball is lifted above the ground as opposed to falling to the ground, it has higher potential energy. It is capable of performing more work when raised. Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has greater potential energy as they get further apart.

Potential energy develops in systems having components whose configurations, or relative positions, determine the amount of the forces they apply to one another.

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Answer:

Let lo be the length of the rod in the frame in which it is at rest and s' is the frame which is moving with a speed 0.8c in a direction making an angle 60° with x-axis. The components of lo along and perpendicular to the direction of motion are lo cos 60° and lo sin 60° respectively.

Now length of the rod along the direction of motion

= lo cos 60°_/1-(0.8) 2/c2

= lo/2×0.6

= 0.3 lo.

Length of the rod perpendicular to the direction of motion.

= lo sin 60°

=_/3/2 lo

Length of moving rod

l = [(0.3lo)2+{lo_/3/2} 2] 1/2

= 0.916 lo.

Percentage contraction

= lo-0.916lo/lo×100

= 8.4%.

Explanation:

Answer:

To correct the defects of vision by measuring the radius of curvature and thus the power of the lenses.

Explanation:

A spherometer is an instrument used to measure the curvature of objects such as lenses and curved mirrors.

Generally it consists of a fine screw which is moving in a nut carried on the center of a 3 small legged table or frame. The feet forms the vertices of an equilateral triangle. The lower end of the screw and those of the table legs are finely tapered and terminate in hemispheres.

If the screw has two turns of the thread to the milli meter the head is generally divided into 50 equal parts, so that differences of 0.01 millimeter may be measured without using a vernier scale.

The spherometer is used to measure the radius of curvature of the lenses so that the opthalmologist find the focal length of the lens and then give the  power to the lens to correct the defects of vision.  

The electric force on the charge Fc = 9.439 x 10⁹N(m/C)²

To calculate the electric force on different charges and a certain distance,

Use formula,

Fc = k (q₁q₂)/r²

Where,

Fc is electric force

k is coulomb's constant

q₁ is charge at one point

q₂ is charge at second point

r is the distance

Known values,

q₁ = 15μC

q₂ = 7μC

k =  8.99 × 10⁹ Nm² /C²

r = 10cm

Fc = ?

Now, putting the values

Fc =  8.99 × 10⁹ Nm² /C² (15μC x 7μC)/(10cm)²

Fc =  8.99 × 10⁹ N(m/C)² x 1.05

Fc = 9.439 x 10⁹N(m/C)²

Hence, the electric force is Fc = 9.439 x 10⁹N(m/C)².

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The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

8 N

Explanation:

From Newtons second law of motion, we have;

F = ma

where: F is the force applied, m is the mass of the object, and a is its acceleration.

From the given question: mass of box  = 4 kg and acceleration of the box  = 2 m/\(s^{2}\), then;

F = 4 x 2

  = 8

F = 8 N

The amount of force to be used is 8 N.  

Answer:

Explanation:

The electric force between two protons is 10^36 times stronger than the gravitational force between them.

Answer:

Electric force is 1.23 x 10³⁶ times stronger than gravitational force.

Explanation:

First, we will calculate the gravitational force using Newton's Law:

\(F_G = \frac{Gm^2}{r^2}\\\\\)

where,

F_G = Gravitational Force = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

m = mass of proton = 1.67 x 10⁻²⁷ kg

r = distance between protons

Therefore,

\(F_G = \frac{(6.67\ x\ 10^{-11}\ Nm^2/kg^2)(1.67\ x\ 10^{-27}\ kg)^2}{r^2}\\\\F_G = \frac{1.86\ x\ 10^{-64}\ Nm^2}{r^2}\\\\\)

Now, we will calculate the electrostatic force using Colomb's Law:

\(F_E = \frac{kq^2}{r^2}\\\\\)

where,

F_E = Electrostatic Force = ?

k = Colomb's Constant = 9 x 10⁹ Nm²/C²

q = charge of proton = 1.6 x 10⁻¹⁹ C

r = distance between protons

Therefore,

\(F_E = \frac{(9\ x\ 10^{9}\ Nm^2/kg^2)(1.6\ x\ 10^{-19}\ C)^2}{r^2}\\\\F_E = \frac{2.3\ x\ 10^{-28}\ Nm^2}{r^2}\\\\\)

Dividing both forces:

\(\frac{F_E}{F_G} = \frac{2.3\ x\ 10^{-28}}{1.86\ x\ 10^{-64}}\)

F_E = 1.23 x 10³⁶ F_G

Therefore, electric force is 1.23 x 10³⁶ times stronger than gravitational force.

Answer: λₑ = 123pm; λₚ = 286pm

Explanation:

λ= h/√2mE where E = Kinetic Energy.

λₑ = h/√2mₑE = 6.626 X 10^-33/√2 X 9.1 X 10⁻31 X 100 X 1.6 X 10^-19 = 123pm

λₚ = h/√2mₚE = 6.626 X 10^-33/√2 X 1.6 X 10⁻27 X 100 X 1.6 X 10^-19 = 286pm

Hope this helps!!!

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The statement that is NOT true is "the spaces between the particles increased.

option D.

If we consider the solids and liquids, when the temperature increases the molecules gain energy and start moving in all directions. This expands the substance and the volume of the substance increases.

Similar, when the ball is heated, the volume of the ball increases due to thermal expansion.

As the temperature increases, the average kinetic energy of the particles within the ball also increases, causing them to move faster.

However, the spaces between the particles do not necessarily increase. In fact, the expansion of the ball occurs due to the particles themselves moving farther apart, but the intermolecular spacing within the ball remains relatively constant.

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The value of the unknown resistance is approximately 44750 Ω.

In a balanced Wheatstone bridge, the ratio of the resistances in the two arms of the bridge is equal to the ratio of the resistances in the other two arms. That is:

R1/R2 = R3/R4

where R1, R2, R3, and R4 are the resistances in the four arms of the bridge.

In this problem, the resistances in three of the arms of the bridge are all exactly 500 Ω. Let the resistance in the fourth arm (the unknown resistance) be denoted by R. The voltage across the galvanometer is zero in a balanced Wheatstone bridge, so the current through the galvanometer is also zero.

Using Ohm's law, the current through the entire circuit is given by:

I = V/(R1 + R2 + R3 + R4)

where V is the voltage of the battery, and R1, R2, R3, and R4 are the resistances in the four arms of the bridge.

The voltage drop across the 500 Ω resistances is given by:

V_500 = (500/(500+500+R)) * V

The voltage drop across the unknown resistance R is also given by:

V_R = (R/(500+500+R)) * V

Since the voltage across the galvanometer is zero, the current through the unknown resistance R is equal to the current through the 80 Ω galvanometer. Using Ohm's law, we can write:

I_R = V_R/R = I_galvanometer = 0.08 μA

Substituting the expressions for the voltages and the current into the equation for the total current, we get:

V/(500+500+500+R) = 0.08 μA

Solving for R, we get:

R = (V/0.08 μA) - 1500 Ω

Substituting the given values, we get:

R = (3.7 V)/(0.08 μA) - 1500 Ω

R = 46250 Ω - 1500 Ω

R = 44750 Ω

Therefore, the value of the unknown resistance is approximately 44750 Ω.

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The maximum height the crate reaches is 0.856 m.

To determine the maximum height the crate reaches, we need to use the conservation of mechanical energy:

Initial potential energy = final kinetic energy + final potential energy + work done by friction

Let's calculate each term:

Initial potential energy:

PE₁ = mgh₁ = 60.0 kg * 9.81 m/s² * 1.46 m = 868.98 J

Final kinetic energy:

KE₂ = (1/2)mv², where v is the final velocity of the crate after passing over the rough patch.

To find v, we can use the work-energy principle:

Work done by friction = change in kinetic energy

F * d = (1/2)mv² - 0

where F is the force of kinetic friction and d is the distance over which the force acts.

F = μ_k * N, where N is the normal force acting on the crate.

Since the crate is on an incline, we need to find the components of the gravitational force and the normal force acting on it:

mgsinθ = 60.0 kg * 9.81 m/s² * sin(25.0°) = 243.2 N

mgcosθ = 60.0 kg * 9.81 m/s² * cos(25.0°) = 550.2 N

N = mgcosθ = 550.2 N

F = μ_k * N = 0.34 * 550.2 N = 187.07 N

Now we can solve for v:

187.07 N * 1.60 m = (1/2) * 60.0 kg * v² - 0

v = √(2 * 187.07 N * 1.60 m / 60.0 kg) = 2.47 m/s

Final kinetic energy:

KE₂ = (1/2)mv² = (1/2) * 60.0 kg * (2.47 m/s)² = 183.08 J

Final potential energy:

PE₂ = mgh₂

At the maximum height, the final velocity of the crate is zero, so all the final energy is potential energy. Therefore:

PE₂ = PE₁ - KE₂ - work done by friction

mgh₂ = 868.98 J - 183.08 J - 187.07 N * 1.60 m

Solving for h₂, we get:

h₂ = (868.98 J - 183.08 J - 187.07 N * 1.60 m) / (60.0 kg * 9.81 m/s²) = 0.856 m

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The statement" The direction of the force on the charge placed in the electric field is upward" is false because the direction of the force on a negative charge (-6 C) placed in an upward-directed uniform electric field of magnitude 24 N/C would be downward.

The direction of the force on a charged particle placed in an electric field is determined by the charge of the particle and the direction of the electric field. In this case, a charge of -6 C is placed in an electric field directed upward with a magnitude of 24 N/C.

The force on a charged particle in an electric field can be calculated using the formula:

F = q * E

Where F is the force, q is the charge of the particle, and E is the electric field.

Since the charge q in this case is negative (-6 C) and the electric field E is directed upward, we can substitute the values into the formula:

F = (-6 C) * (24 N/C)

F = -144 N

The negative sign in the force value indicates that the force is in the opposite direction to the electric field. Therefore, the force on the charge placed in the electric field is downward, not upward.

The force on a negative charge is always opposite to the direction of the electric field. This is because negative charges experience an attractive force towards positive charges, and electric fields are directed from positive charges to negative charges.

Therefore, the statement "The direction of the force on the charge placed in the electric field is upward." is false.

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Answer:

The basic answer is sea flows. On the off chance that the air making a trip to New York moves via land, it will be cooler than the air and flows that reach, for instance, San Francisco. Along these lines, Rome is hotter than New York because of flows, topography and air development designs.

Explanation:

Brainliest?

Answer:

b

Explanation:

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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The total displacement as it travels between Emily and Luisa if Emily passes a soccer ball 5 m directly across the field to Ara, who then kicks the ball 12.5 m directly down the field to Luisa, is 17.5 meters.

All locations in a body that are moved from one state to another are assigned displacement vectors. The difference between a trajectory point's final and starting positions is known as displacement (for instance, the center of mass of a moving object). The precise route taken to arrive at the destination is not important.

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a lecturer moves to the right in relation to a whiteboard. Displacement describes this shift in location.

The displacement is the total distance from one place to another, so, when Emily passes a soccer ball 5 m directly to the era and then the total displacement is equal to the total distance traveled by the football.

The total distance traveled by the ball = 5 + 12.5 = 17.5 meters.

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Answer:

acceleration

Explanation:

speed=v,

In speed vs time graph, slope = dv/dt = acceleration

To find:

Why would the voice get louder and higher?

Explanation:

The loudness of a voice is associated with the amplitude of the wave. When the amplitude of the sound wave of a voice is increased the sound becomes louder.

And the higher pitch of the voice is due to the increase in the frequency.

Thus a voice gets louder when its amplitude is increased. And the voice gets higher when its frequency is increased.

Final answer:

Thus the correct answer is option C.

Answer:

A crane operator drops the cargo by turning off the electric current to the electromagnet. Electromagnets can be controlled by controlling the electric current. An electromagnet is stronger if there is more current flowing through it.

Explanation: