What type of energy change occurs as a match burns?

The frequency is 983.56Hz, will be heard by the occupants of the car moving at the given speed.

What is Frequency?

It is the number of cycles or vibrations a body in periodic motion experiences during one unit of time, as well as the number of waves that pass, a fixed point in a unit of time. After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration.

What are the calculations?

Given,

Speed of train = 28 m/s

Speed of car = 53 m/s

Frequency of car's horn = 580 Hz

Frequency of train's whistle = 340 Hz

When the car is behind the train, the frequency of the car is:

By using formula of frequency =  \(f_{c} = f_{t ( 1 + \frac{V_{c} }{V_{t} } )\)

Put the value into the formula =    \(fc = 340 * (1 + \frac{53}{28} )\)

                                                        \(fc =\) 983.56Hz

Hence, frequency is 983Hz, will be heard by the occupants of the car.

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a. The time constant for a series RC circuit connected to ξ = 12 V with a resistance of 47 kΩ and a capacitance of 3900 pF is 183.3 μs.

b. If the EMF is doubled, the time constant τ will not change, as it depends solely on the resistance and capacitance values in the circuit and is independent of the applied voltage.

To determine the time constant for a series RC circuit connected to ξ = 12 V with a resistance of 47 kΩ and a capacitance of 3900 pF can be calculated using the formula:

τ = RC

where τ is the time constant, R is the resistance, and C is the capacitance.

We are given that 1 pF = 10⁻¹² F, we can convert the capacitance to farads:

C = 3900 × 10⁻¹² F.

To find the time constant τ, multiply the resistance and capacitance:

τ = (47 × 10³ Ω) × (3900 × 10⁻¹² F)

≈ 183.3 × 10⁻⁶ s or 183.3 μs

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Answer:

31.25 m

25m/sec

Explanation:

Given :-

Time = 5sec

V = 0 (in going up)

U = 0 (in comming down)

Find :-

H and U by which it is thrown up

Since the total time is 5 sec ,therefore half time will be taken to go up and another half will be taken to go down .

We know that ,

V = U + gt

0 = U - 10*2.5

U = 25 m/sec

Also,

V² = U² +2gs

0 = 625 - 20s

s = 625/20 = 31.25 m

Answer:

im just 15 yearsold hehhez i dont know that either

The beginning of solar system development is most likely indicated by the big bang theory. An explanation for how the universe grew from a high density starting state is provided by the Big Bang theory.

And temperature. The evolution of the observable universe from the earliest known times through its later large-scale form is explained by a variety of cosmological models of the Big Bang theory. The Sun and the things that circle it make up the solar system, which is gravitationally bound. The gravitational collapse of a massive interstellar molecular cloud gave it birth 4.6 billion years ago. 99.86% of the system's mass is in the Sun, with the planet holding the majority of the remaining mass.

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The nebular hypothesis is the most widely recognized cosmogony theory to explain how the Solar System started and evolved (as well as other planetary systems). It implies that gas and dust orbiting the Sun are what created the Solar System.

Over 70 different types of meteorites have undergone radiometric dating to ascertain their ages. The findings suggest that between 4.53 and 4.58 billion years ago, the Solar System and meteorites both began to develop.

Scientists believe that the formation of terrestrial planets like Earth several billion years ago resulted from the coalescence of hot blobs of molten rock and metal from dust and gas. Before they developed into separate planets, they went through four stages of development: differentiation, cratering, flooding, and surface evolution.

The solar nebula

4.6 billion years ago, the solar nebula, a cloud of gas and dust, gave rise to the Sun and the planets.

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Answer:

Explanation:

If the force of 2000 N is directed towards the right and the friction is directed towards the left, the 2000 N force is positive and the other is negative. To find the resultant force:

2000 - 500 = 1500 N to the right

When the Earth is at point C, Equinox happens.

In Equinox, the Sun is directly above the equitor making day and night equal in both hemispheres.

The player recoils about the distance of 0.0814 meters in the time it takes the puck to reach the 16.0-meter distant goal in a frictionless ice environment.

To solve this problem, we can use the principle of conservation of momentum. The initial momentum of the system (player and puck) is zero because both are initially at rest. After the player hits the puck, the total momentum of the system remains conserved.

Let's denote the initial velocity of the player as v (which is zero) and the velocity of the player after hitting the puck as V (which we need to find). The mass of the player is given as 84.0 kg, and the mass of the puck is 0.150 kg.

According to the conservation of momentum:

(mass of player × initial velocity of player) + (mass of puck × initial velocity of puck) = (mass of player × final velocity of player) + (mass of puck × final velocity of puck)

(84.0 kg × 0) + (0.150 kg × 0) = (84.0 kg × V) + (0.150 kg × 39.0 m/s)

0 = 84.0V + 5.85

84.0V = -5.85

V = -5.85 / 84.0

V = -0.07 m/s

The negative sign indicates that the player moves in the opposite direction to the puck.

Now, to calculate the distance the player recoils, we can use the equation:

Distance = |final velocity of the player| × time

Since we have the velocity and need to find the time, we can use the equation of motion:

Distance = (1/2) × acceleration × \(time^2\)

Since the ice is frictionless, the only force acting on the player is the force exerted on them when they hit the puck. This force is equal to the change in momentum of the puck:

Force = (mass of puck × final velocity of puck) / time

= (0.150 kg × 39.0 m/s) / time

= (5.85 kg·m/s) / time

The force acting on the player can be equated to the mass of the player times its acceleration:

Force = mass of player × acceleration

mass of player × acceleration = (5.85 kg·m/s) / time

acceleration = (5.85 kg·m/s) / (time × mass of player)

Now, equating the two expressions for acceleration:

(5.85 kg·m/s) / (time × mass of player) = acceleration

(5.85 kg·m/s) / (time × 84.0 kg) = acceleration

We can now substitute this expression for acceleration into the equation for distance:

Distance = (1/2) × [(5.85 kg·m/s) / (time × 84.0 kg)] × \(time^2\)

Simplifying:

Distance = (1/2) × (5.85 kg·m/s) / 84.0 × time

Distance = (0.5 × 5.85 kg·m/s × time) / 84.0

Distance = 0.03482 × time

We need to find the time it takes for the puck to reach the goal, which is 16.0 m away. We can use the equation of motion:

Distance = initial velocity × time + (1/2) × acceleration × \(time^2\)

Since the initial velocity of the puck is 0, the equation simplifies to:

Distance = (1/2) × acceleration × \(time^2\)

Solving for time:

\(time = \sqrt{((2 * Distance) / acceleration)\)

\(= \sqrt{((2 * 16.0 m) / (5.85 kgm/s) / time)\)

\(= \sqrt{(5.479 m^2s^2/kg)}\)

= 2.34 s

Now, substituting this value of time into the expression for distance:

Distance = 0.03482 × 2.34

= 0.0814 m

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The observed slowing of a clock near a black hole is a direct consequence of general relativity and the curvature of space-time caused by the massive object.

The observed slowing of a clock in the vicinity of a black hole is a prediction of general relativity. According to general relativity, the presence of a massive object, such as a black hole, can curve space-time.

This curvature of space-time affects the flow of time itself. As you approach a black hole, the gravitational field becomes stronger, causing time to slow down relative to an observer further away from the black hole.

This phenomenon, known as time dilation, is a consequence of the warping of space-time by mass. It is a prediction of general relativity, which is Einstein's theory of gravity.

Time dilation has been confirmed through various experiments and observations, such as the slowing down of atomic clocks flown in airplanes or placed in high-gravity environments.So, the observed slowing of a clock near a black hole is a direct consequence of general relativity and the curvature of space-time caused by the massive object.

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Answer:

electrons

Explanation:

i think this is right

Answer:

Explanation:

I don't get what the relation here is. Venus is the hottest planet in our solar system. And yes, it's hotter than mercury despite mercury being closer to the sun. And your question talks about the coldest temperature measured which is -235 degrees Celsius. That surely isn't measured on Venus. I'm only wondering what Venus has got to go with cold and what exactly your question is

Answer:

Compound 'A' C5H12 does not react with phenyl hydrazine. Oxidation of 'A' with K2Cr2o7,/H" gives B' (c5H10o). Compound 'B' reacts with phenyl hydrazine but does not give Tollen's test. The

Answer:

See Below

Explanation:

1: Thermal  Energy

2: Chemical Energy

3: Nuclear Energy

4: Electrical Energy

5: Radiant Energy

6: Light Energy

7: Motion Energy

8: Sound Energy

There are 8 types are energy that are above.

Hope this helps.

Answer:

-7.5 m/s

Explanation:

\(a = \dfrac{v_f - v_i}{t}\)

Here given: a = -1.5 m/s², v = ?, vᵢ = 0, t = 5 s

Putting into formula:

\(\rightarrow -1.5 = \dfrac{v_f - 0}{5}\)

\(\rightarrow v_f = -1.5(5)\)

\(\rightarrow v_f = -7.5\)

Hence, the final velocity is -7.5 m/s.

The velocity of a car starts from rest and travels for 5.0s with a constant acceleration of -1.5 m/s² is -7.5 m/s.

The final velocity of a car can be calculated from acceleration, time, and initial velocity.

From the first equation of motion:

vf = u + (a × t)

Given:

Acceleration = -1.5 m/s²

Time taken = 5.0 seconds

The initial velocity of a car is zero.

The final velocity is:

v = 0 m/s + (-1.5 m/s² ×  5.0 s)

v = -7.5 m/s

Hence, the velocity of a car starts from rest and travels for 5.0s with a constant acceleration of -1.5 m/s² is -7.5 m/s.

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The most significant barrier to fully embracing nuclear technology to produce energy is the safe storage of radioactive waste.

Nuclear power is the only large-scale energy-producing technology that completely accepts responsibility for all waste and prices it into the product. Nuclear power generates extremely less waste in comparison to other thermal energy-producing sources. Used nuclear fuel may be used as either a resource or as waste. Nuclear waste is not exceptionally dangerous nor difficult to control in comparison to other toxic industrial waste. Technically established safe techniques for the ultimate disposal of high-level radioactive waste exist; the worldwide agreement is that geological disposal is the best choice.

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When salt is added, it makes it harder for the water molecules to escape from the pot and enter the gas phase, which happens when water boils, Giddings said. This gives salt water a higher boiling point, she said.

Answer:

Explanation:

Adding salt (independent variable) causes the boiling temperature of the water (dependent variable) to increase.

Option D : Considering a 0.5-kg meter stick with a 1.0 kg mass attached at the 50 cm mark and a 3.0 kg mass at the very end.The center of mass is located at 66 cm mark.

Center of mass refers to the point at which the system's mass is uniformly distributed, that is, a point where an object's mass is concentrated. This mass center or center of gravity is at the center of the object for a symmetrical object.A meter stick that weighs 0.5 kg has a 1.0 kg mass attached at the 50 cm point and a 3.0 kg mass attached at the end of the meter stick.

The center of mass is located at 66 cm mark.

The following formula can be used to calculate the location of the center of mass:

xcom=(m1x1+m2x2+m3x3)/mtotal

Where: xcom: The location of the center of mass

m1,m2,m3: The mass of the object

x1,x2,x3: The location of the mass on the object

mtotal: The total mass of the object

m1= 1.0 kg, x1=50 cm,

m2= 3.0 kg, x2=100 cm,

m3= 0.5 kg, x3=0 cm

mtotal= 1.0 kg+3.0 kg+0.5 kg= 4.5 kg

Now substituting the values of m1,m2,m3, x1,x2,x3, and mtotal in the above formula:

xcom=(1.0 kg * 50 cm+3.0 kg * 100 cm+0.5 kg * 0 cm)/4.5 kg

xcom=(50 cm+300 cm)/4.5 kg

xcom=66.7 cm

        ≈ 66 cm

Therefore,the correct option is D : 66 cm mark.

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Answer:

C. It transforms electrical energy into mechanical energy

Answer: C

Explanation:

Answer:

Explanation:

First we must know that the direction along the vertical are towards North and south while along the horizontal are towards east and west.

Sum of distances along the vertical

4km due north = +4km

3 Km South = -3km (south is along the negative y direction)

6 Km South = -6km

total distance along the vertical = 4-3-6 = -5km

Sum of distances along the horizontal;

8km due East = +8km

4 Km west = -4m (west is along the negative x direction)

total distance along the horizontal = 8-4 = 4km

Displacement is gotten by using Pythagoras theorem

d² = x²+y²

d² = (4)²+(-5)²

d² = 16+25

d² = 41

d = √41

d = 6.4km

Hence Tyler's displacement is 6.4km

Answer:

same as other person

Explanation:

a.  Temperature = 24.38 °C, Pressure = 27.92 Pa

b. The latent heat of sublimation and vaporization is 36349 J/mol

c.  At the triple point, the latent heat of fusion is 0 J/mol.

(a) The vapor pressure of liquid ammonia at the triple point is 3063 Pa, and the vapor pressure of solid ammonia is 27.92 Pa.

In this case, the temperature and pressure at the triple point are:

Temperature = 24.38 °C

Pressure = 27.92 Pa

(b) It can be calculated using the Clausius-Clapeyron equation:

\(Lsub = R * T * ln(Pvap/Psolid)\)

In this case, the temperature is :

24.38 °C = 297.53 K,

The vapor pressure is 3063 Pa, and the solid pressure is 27.92 Pa.

Substituting these values into the equation, we get:

\(Lsub = 8.314 J/(mol.K) * 297.53 K * ln(3063 Pa/27.92 Pa) \\\)

Lsub ≈ 36349 J/mol

(c) The latent heat of fusion can be calculated as the difference between the latent heat of sublimation and the latent heat of vaporization:

\(Lfus = Lsub - Lvap \\Lfus = 36349 J/mol - 36349 J/mol \\Lfus = 0 J/mol\)

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The student says that there is a gravitational attraction between the two of them. This student is correct.

The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them, according to Newton's universal law of gravitation.

The gravitational force is weak unless there are massive masses involved. As compared to Earth, humans have relatively low masses, which results in a very small and negligible gravitational force. As a result, although it is tiny and imperceptible, gravitational force exists between two people seated near to one another.

Hence, the student, who says that there is a gravitational attraction between the two of them, is correct.

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With a=11.43 m/s2, option 4 is the proper response. The airplane accelerates to 160+ mph in less than two seconds during a catapult launch.

The speed about which velocity decreases is known termed accelerating. Acceleration typically indicates that the speed is changing, but not necessarily. An item that is moving in a circle while maintaining a constant speed is still accelerating because the direction of its motion is shifting.

An object's velocity may alter depending on whether it is moving faster, slower, or in a different direction. The moon orbiting the earth and an apple falling to the ground are two instances of acceleration.

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.Explanation:

.......................................................

The bulk modulus of the liquid in pascals is 1.26 x 10⁹Pa.

The bulk modulus is a measure of a substance's resistance to compression. It is a mechanical property of a material and is defined as the ratio of change in pressure to the fractional change in volume. In other words, it measures the ability of a substance to withstand changes in volume due to an applied pressure. The greater the bulk modulus, the more resistant the material is to changes in volume. It is typically measured in units of pressure, such as pascals (Pa) or gigapascals (GPa). The bulk modulus is an important property for materials used in engineering and construction, as it affects how well a material can withstand loads and stresses.

To calculate the bulk modulus of a liquid, we can use the equation:

Bulk modulus = (density of the liquid) × (speed of sound in the liquid) ²

First, we need to calculate the speed of sound in the liquid.

The speed of sound in a liquid is given by:

Speed = (wavelength × frequency) / (2 × pi)

To calculate the bulk modulus of the liquid, we can use the equation:

Bulk Modulus = (density × (speed of sound)) ²

The speed of sound in the liquid can be calculated using the equation:

Speed of Sound = (frequency × wavelength)

By substituting the given values into these equations, we can calculate the bulk modulus as follows:

Speed of Sound = (410 Hz × 8.00 m) = 3280 m/s

Bulk Modulus = (1500 kg/m³) × (3280 m/s) ² = 1.26 x 10⁹ Pa

So the bulk modulus of the liquid is 1.26 x 10⁹ Pa.

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In a liquid with a density of 1500 kg/m3 , longitudinal waves with a frequency of 410 hz are found to have a wavelength of 8.00 m. The liquid has a bulk modulus of 1.26 x 10⁹ Pa  in pascals.

A substance's compression resistance is measured by its bulk modulus. A material's mechanical property is the ratio of a change in pressure to a change in volume fractionally. To put it another way, it measures a substance's capacity to withstand changes in volume caused by pressure. The material's resistance to changes in volume is inversely proportional to its bulk modulus.

It is typically measured in pascals (Pa) or gigapascals (GPa) pressure units. Because it influences how well a material can withstand loads and stresses, the bulk modulus is an important property for materials used in engineering and construction.

The equation can be used to determine a liquid's bulk modulus:

Bulk modulus = (density of the liquid) × (speed of sound in the liquid) ²

The speed of sound in the liquid must first be determined before we can calculate the bulk modulus, which is equal to the liquid's density divided by its speed of sound.

The following equation can be used to determine the liquid's bulk modulus: Speed = (wavelength x frequency) / (2 pi)

The following equation can be used to determine the liquid's sound speed: Bulk Modulus = (density/speed of sound)/2

The bulk modulus can be calculated as follows by substituting the given values into these equations: Speed of Sound = (frequency  wavelength).

The liquid's bulk modulus is therefore 1.26 x 109 Pa.

Speed of Sound = (410 Hz  8.00 m) = 3280 m/s.

Bulk Modulus = (1500 kg/m3)  (3280 m/s) 2 = 1.26 x 10⁹ Pa

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The difference in power for two people carrying the boxes up the ramp is 30 W.

Given the following data:

W = 40.0 N is the weight of a box.

The ramp's length is L = 2.00 m.

The platform height is h = 1.0 m.

t = 2.0 s is the time interval for the first person.

t' = 4.0 s is the time interval for the other person.

Power is the rate at which energy is used. The expression for the Power is given in the given question as,

P = W×(L+h)/t

Assume that you are solving for the first person.

P₁ = W(L+h)/t₁.................................................................. (1)

Substitute the following values into equation (1):

P₁ = 40(2+1)/2

P₁ = 20(3) (3)

P₁ = 60 W.

Regarding the second person,

P₂ = W(L+h)/t₂..................................................................... (2)

Fill in the blanks in equation (2) as follows:

P₂ = 40(2+1)/4

P₂ = 10*(3) *3)

P₂ = 30 W

Obtaining the difference in power as

P = P₁ - P₂

P = 60-30

P = 30 W

As a result, we can conclude that the difference in power for two people carrying the boxes up the ramp is 30 W.

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the light ray will be refracted towards the normal.

The magnitude of acceleration of the charged plastic bead can be calculated by using Coulomb's Law which  is -6.21 m/s^2.

According to Coulomb's Law, the force between two charged particles is given by the equation

F = k*(q1*q2)/(r^2), where k is the Coulomb's constant, q1 and q2 are the charges of the two particles, and r is the distance between the two particles.

In this case, k = 8.99 x 10^9 Nm^2/C^2, q1 = -4.0 nC, q2 = 8.0 nC, and r = 2.4 cm.

Using the equation, the magnitude of the force between the two particles is calculated as F = 8.99 x 10^9 x (-4.0 x 10^-9)(8.0 x 10^-9) / (2.4 x 10^-2)^2 = -14.9N.

The acceleration of the plastic bead can then be calculated using Newton's Second Law of Motion

F = ma.

Therefore, a = F/m, where m is the mass of the bead. In this case, the mass of the plastic bead is 2.4 g.

So, the magnitude of acceleration of the plastic bead is a = -14.9N/2.4g = -6.21 m/s^2.

Therefore, the magnitude of acceleration of the plastic bead is -6.21 m/s^2.

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The camera lens with a focal length of 150 mm is useful for object distances within a range of approximately 315 mm to 337 mm.

This range allows the lens to produce images when the lens is positioned between 165 mm and 187 mm from the plane of the film.

To determine the range of object distances for which the lens is useful, we can use the thin lens formula:

1/f = 1/u + 1/v

where f is the focal length of the lens, u is the object distance, and v is the image distance.

Given that the focal length of the lens is 150 mm, we can rearrange the formula to solve for the object distance u:

1/u = 1/f - 1/v

To find the maximum and minimum values of u, we consider the extreme positions of the lens. When the lens is positioned at 165 mm from the film plane, the image distance v becomes:

1/v = 1/f - 1/u

= 1/150 - 1/165

≈ 0.00667

v ≈ 150.1 mm

Similarly, when the lens is positioned at 187 mm from the film plane, the image distance v becomes:

1/v = 1/f - 1/u

= 1/150 - 1/187

≈ 0.00533

v ≈ 187.5 mm

Therefore, the lens is useful for object distances within the range of approximately 315 mm (150 mm + 165 mm) to 337 mm (150 mm + 187 mm).

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