What type of elements are presented in the periodic table

Answers

Answer 1
metals, non-metals, and metalloids

Related Questions

Other than their charges, two conducting spheres are identical. These spheres initially have charges of -8 C and 2 C. The spheres are brought together to allow for the transfer of electrons. What is the identical charge on each of the spheres after they are separated? a 8-C b. 20 c Neutral O C d-30 11. A student combs his hair with a neutral plastic comb. The hair becomes positively charged. What is the new charge of the comb? a. The comb is positive because electrons move from the hair to the comb. b. The comb is positive because protons move from the comb to the hair. The comb is negative because electrons move from the hair to the comb. d. The comb is negative because protons move from the comb to the hair. 12. One positive and one negatively charged masses are separated by a distance, r. Which statement best describes the gravitational and electrostatic forces between the two masses? a. Both forces are attractive. b. The gravitational force is repulsive and the electrostatic force is attractive, . Both forces are repulsive d. The gravitational force is attractive and the electrostatic force is repulsive.

Answers

The identical charge on each of the spheres after they are separated is 5 C.

The new charge of the comb is negative because electrons move from the hair to the comb.

The statement that best describes the gravitational and electrostatic forces between one positive and one negatively charged mass is: The gravitational force is attractive and the electrostatic force is repulsive.

When the two identical conducting spheres with initial charges of -8 C and 2 C are brought together, they allow for the transfer of electrons. Since they are identical, the charge will distribute evenly between them. Thus, the identical charge on each sphere after they are separated is (2 C - (-8 C))/2 = 5 C.

When a neutral plastic comb is used to comb hair, the hair becomes positively charged. This happens because electrons, which are negatively charged, are transferred from the hair to the comb. As a result, the comb gains a net negative charge, making its new charge negative.

For one positive and one negatively charged mass separated by a distance, r, the gravitational force between them is always attractive, as gravity is an attractive force between masses. On the other hand, the electrostatic force between them depends on the charges.

If the positive and negative charges are of the same magnitude, the electrostatic force will be repulsive since like charges repel. Therefore, the statement that best describes the forces in this scenario is: The gravitational force is attractive, and the electrostatic force is repulsive.

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a physics instructor conducts a projectile motion demonstration. The device used will drop one steel ball and horizontally launch another. If no air resistance is presented which steel ball, the one launced or the one dropped, striked the ground first?

(a) The launched ball

(b) The dropped ball

(c) both hit a the same time

(d) neither hit the ground​

Answers

Answer:

Projectile motion is the motion of an object thrown or projected into the air, subject to only the acceleration of gravity. The object is called a projectile, and its path is called its trajectory. The motion of falling objects, as covered in Problem-Solving Basics for One-Dimensional Kinematics, is a simple one-dimensional type of projectile motion in which there is no horizontal movement. In this section, we consider two-dimensional projectile motion, such as that of a football or other object for which air resistance is negligible.

Explanation:

B the dropped ball

A high-speed train travels with an average speed of 227 km/hr. The train travels for 2 hrs. How far does the train travel?

Answers

Answer: The answer would be 454 miles.

Explanation: You multiply the average speed by time travelled

calculate the density of a substance that has a mass of 4.0 g and a volume of 1.0 ml. group of answer choices

Answers

The density of a substance that has a mass of 4.0 g and a volume of 1.0 ml is 4.0 g/ml.So option a is correct.

To calculate the density of a substance, we use the formula:

Density = Mass / Volume

Given that the mass of the substance is 4.0 g and the volume is 1.0 ml, we can substitute these values into the formula:

Density = 4.0 g / 1.0 ml

Now, since the density is typically expressed in grams per milliliter (g/ml), the density of the substance is simply 4.0 g/ml.

The density of the substance is 4.0 g/ml.

Therefore option a is correct.

The question should be:

calculate the density of a substance that has a mass of 4.0 g and a volume of 1.0 ml. group of answer choices

(1)4.0 g/ml.

(b)8.0 g/ml.

(c)9.0 g/ml.

(d)7.0 g/ml.

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Water at 10°C and 81.4 percent quality is compressed isentropically in a closed system to 3 MPa. How much work does this process require in kJ/kg? Use steam tables. The work required by the process is_____kJ/kg.

Answers

The work required by the process is _____ kJ/kg.

How much work is needed per kilogram in kJ for the compression process from 10°C and 81.4 percent quality to 3 MPa?

The work required to compress water isentropically from 10°C and 81.4 percent quality to 3 MPa can be determined using steam tables. The first step is to locate the initial state of water at 10°C and 81.4 percent quality in the steam tables. From the tables, we find the specific enthalpy (h1) and specific entropy (s1) values for the given state.

Next, we find the specific enthalpy (h2) at the final state of 3 MPa from the steam tables.

Using the isentropic compression process, we assume that the entropy remains constant (s2 = s1).

The work required (W) can be calculated using the equation:

W = h1 - h2

Substituting the values obtained from the steam tables, we can find the work required per kilogram in kJ.

Steam tables provide a comprehensive set of data for water and steam properties, including enthalpy, entropy, and other thermodynamic parameters. These tables are essential for engineers and scientists working with steam and thermal systems. By utilizing steam tables, it becomes possible to accurately calculate various processes involving water and steam, such as compression, expansion, and phase changes. They are widely used in fields like power generation, HVAC systems, and industrial processes. Understanding and effectively utilizing steam tables are crucial skills for professionals in these domains.

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Water at 10°C and 81.4 percent quality, when compressed isentropically in a closed system to 3 MPa, requires a work of _______ kJ/kg.

What is the magnitude of the work, in kJ/kg, necessary for this process?

The work required for this process can be determined by considering the initial and final states of the water percent quality and applying the principles of thermodynamics. At the given initial condition of 10°C and 81.4 percent quality, we can use steam tables to find the specific enthalpy and entropy values.

By applying the isentropic compression process, we can determine the final state of the water at a pressure o f 3 MPa. The difference in specific enthalpy between the initial and final states givesus the work required per unit mass.To calculate the specific enthalpy at te initial state, we use the steam tables to find the enthalpy of water at 10°C, which is h1. Similarly, the specific entropy at the initial state is obtained from the steam tables as s1.

By assuming an isentropic process, the specific entropy at the final state, s2, remains the same as s1. Using the final pressure of 3 MPa, we find the specific enthalpy of water at this state, h2, from the steam tables.

The work required per unit mass (w) cn be calculated using the equation:

w = h2 - h

Substituting the values obtained from the steam tables, we can determine the work required for this process in kJ/kg.

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In the figure, a
4.4 kg
block is accelerated from rest by a compressed spring of spring constant
640 N/m
. The block leaves the spring at the spring's relaxed length and then travels over a horizontal floor with a coefficient of kinetic friction
μ k

=0.296
. The frictional force stops the block in distance
D=7.7 m
. What are (a) the increase in the thermal energy of the block-floor system, (b) the maximum kinetic energy of the block, and (c) the original compression distance of the spring? (a) Number Units (b) Number Units In the figure, a
4.4 kg
block is accelerated from rest by a compressed spring of spring constant
640 N/m
. The block leives the spring at the spring's relaxed length and then travels over a horizontal floor with a coefficient of kinetic friction
μ 2

=0.296
. The frictional force stops the block in distance
D=7.7 m
. What are (a) the increase in the thermal energy of the block-floor system, (b) the maximum kineticenergy of the block, and (c) the original compression distance of the spring? (a) Number Units (b) Number Units

Answers

The (a) increase in the thermal energy of the block-floor system 139.3 J

(b), the maximum kinetic energy of the block 614.3 J

(c), and the original compression distance of the spring 0.625 m

(a) The increase in thermal energy of the block-floor system is equal to the work done by the friction force. This can be calculated using the equation

Work = Force × Distance,

where the friction force is equal to the coefficient of kinetic friction multiplied by the normal force, and the distance is equal to the stopping distance (7.7 m).

Therefore, the increase in thermal energy of the block-floor system is equal to

(0.296 x 4.4 kg x 9.8 m/s² x 7.7 m) = 139.3 J.

(b) The maximum kinetic energy of the block is equal to the kinetic energy of the block when it leaves the spring. This can be calculated using the equation

Kinetic Energy = ½ mv²,

where m is the mass of the block (4.4 kg) and v is the velocity of the block when it leaves the spring. This velocity can be found by using the equation

Force = Mass x Acceleration with the spring constant (640 N/m) and the mass of the block (4.4 kg).

Therefore, the maximum kinetic energy of the block is equal to

(0.5 x 4.4 kg x (640 N/m / 4.4 kg)²) = 614.3 J.

(c) The original compression distance of the spring can be found by using the equation

K.E (spring) 1/2 Kx² + Work done = 0

-1/2 * 640 N/m * x² + 99.93 J = 0

Solving for x, we get:

x = √(99.93 J / (1/2 * 640 N/m))

x = 0.625 m

Therefore, the original compression distance of the spring is 0.625 m.

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jon is in a raft that is 117m from the base of a 56m cliff. what is the angle of depression from the top of the cliff to the raft?

Answers

You can form a right-angled triangle from the base of the cliff to the raft (this is the opposite side to an angle), the base of the cliff to the top of the cliff (this is the adjacent side to an angle), and the top of the cliff to the raft (this is the hypotenuse of the triangle).

We know the value of the adjacent and opposite side, so we can use the trigonometric function 'tan' to work out an angle that we can find the angle of depression from.

90 minus the angle that you can work out from this will be equal to the angle of depression.

So if the angle of depression is called x, then:

Tan(90 - x) = O/A

O is the length of the opposite side of the triangle and A is the adjacent side (both have been mentioned before).

Sub in values:

Tan(90 - x) = 117/56

Rearrange for x:

90 - x = Arctan(117/56)

Therefore x = 90 - arctan(117/56)

x = 25.6 degrees to 1 decimal place.

To predict whether a star will ultimately become a black hole, what is the key property of the star we should look at?.

Answers

A star will ultimately become a black hole when it collapses due to end of fuel.

Which star becomes a black hole?

When a star burns through the last of its fuel, the object may collapse, or fall into itself. For smaller stars which are about three times the sun's mass, the new core will become a white dwarf but when a larger star collapses, it turns into a black hole.

So we can can conclude that a star will ultimately become a black hole when it collapses due to end of fuel.

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A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air? Part 1 of 2 The speed of the plane in still air is Part 2

Answers

The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.

Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.

The distance traveled with the wind in 3 hours is 408 miles.

Therefore, we can write the equation as:

3(x + y) = 408

Divide both sides by 3:

x + y = 136  .... (1)

The distance traveled against the wind in 4 hours is also 408 miles.

Therefore, the equation can be written as:

4(x - y) = 408

Divide both sides by 4:

x - y = 102  .... (2)

Now we can solve these two equations using the elimination method.

Add equations (1) and (2):

x + y + x - y = 136 + 1022x = 238x = 119 mph

Therefore, the speed of the plane in still air is 119 mph.

Now, substitute this value of x in equation (1):

119 + y = 136y = 17 mph

Therefore, the speed of the wind is 17 mph.

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The correct question is:

A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?

How did saturn gets its name?​

Answers

Answer:

Like all of the planets, Saturn is named after a character in Roman mythology. Saturn is named after the god Saturnus, the god of agriculture and harvest. Saturn is equivalent to the ancient Greek god Kronos.

why might orbiting telescope be problematic for the radio portion of the electromagnetic spectrum

Answers

Orbiting telescopes can provide many advantages for observations in the visible and other parts of the electromagnetic spectrum, they can present challenges for radio observations.

Orbiting telescopes can be problematic for the radio portion of the electromagnetic spectrum due to several reasons:

1. Interference from Earth-based sources: Radio signals can be easily disrupted by interference from sources on Earth such as cell phone towers, television transmitters, and other radio transmitters. These sources can cause interference and noise in the radio signals received by the telescope.

2. Atmosphere: Radio signals can also be affected by the Earth's atmosphere, particularly by water vapor, which can absorb or scatter radio waves. Orbiting telescopes are above the atmosphere and can therefore avoid this issue.

3. Limited bandwidth: The bandwidth available for radio telescopes is limited, and orbiting telescopes have to share this bandwidth with ground-based telescopes. This can lead to a limited amount of data that can be transmitted to Earth.

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The force of air particles over an area is ________

temperature.
pressure.
volume.
kelvins.

Answers

The answer is Pressure.

Q.3. Fill the table to describe the characteristics of the states of matter.
Do they have
definite shape?
Vapor
Water
Ice
States of
Matter
Do they have
definite volume?
Do they
compress?

Answers

Answer:

Three states of matter exist—solid, liquid, and gas. Solids have a definite shape and volume. Liquids have a definite volume,

Explanation:

According to the information, the table is completed as follows: Do they have definite shape? no (vapor), no (water), yes (ice); Do they have definite volume? no (vapor), yes (water), yes (ice); Do they compress? yes (vapor), no (water), no (ice).

How to fill the table to describe the characteristics of the states of matter?

To fill the table to describe the characteristics of the states of matter we have to look for additional information of each state of matter and then complete the table. According to the information we can infer that the correct way to complete the table is:

Do they have definite shape? no (vapor), no (water), yes (ice); Do they have definite volume? no (vapor), yes (water), yes (ice); Do they compress? yes (vapor), no (water), no (ice).

Vapor | No | No | Yes

Water | No | Yes | No

Ice | Yes | Yes | No

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let's compare this to what keplerian rotation would look like. in the case of the solar system, almost all the mass is concentrated at the center. leaving the first dark matter density slider at the best-matched value to the rotation curve, adjust the rest down to 0. how much mass is enclosed in this case? use scientific notation, as before. include one place after the decimal.

Answers

In the case of Keplerian rotation, with all the mass concentrated at the center like in the solar system, adjusting the dark matter density sliders to zero would enclose approximately 0.0 kilograms of mass.

When we consider the concept of Keplerian rotation, we are examining a system where most of the mass is concentrated at the center, as observed in the solar system. To simulate this scenario, we adjust the dark matter density sliders to zero, effectively removing any additional mass beyond what is already present. By doing so, we eliminate the contribution of dark matter to the overall mass enclosed.

In the context of the given question, the objective is to determine the amount of mass enclosed under these conditions. When the dark matter density sliders are set to zero, it means that no additional mass is added to the system. Therefore, the total mass enclosed would be equal to the mass of the central object, which in this case is the sun.

The main answer, stating that the mass enclosed is approximately 0.0 kilograms, indicates that without the presence of dark matter, the only mass considered is that of the central object, which in the solar system is the sun. This suggests that the mass enclosed is negligible when compared to the total mass of the solar system.

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GIVING BRAINLIEST
In addition to having a blue color, what other characteristic do Neptune and Uranus share?

no rings
27 moons
no axis tilt
cold temperatures

Answers

Answer:

Cold temps. . .

Explanation:

Hope it helps!

How to integrate 1/ 1 + x2

Answers

The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.

Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.

Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:

∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du

The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.

Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.

Let us work through the steps:

Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x

Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du

Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.

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three people are standing on a horizontally rotating platform in an amusement park. one person is at radius r, the second person is 3/5r away from the center, and the third person is 1/2r away from the center. let's say they are all able to not slide, compare their periods, their speeds, and their radial accelerations. for each quantity, rank each quantity from smallest to largest. explain your reasoning for each ranking. what force is keeping them on the rotating platform? the person with mass, m, at 1/2 r begins to walk towards the outside of the circle and begins to slip when they reach 1.5r. if r is 5m and the period is 9s. what is the coefficient of static friction?

Answers

All periods between 1 and 2 are equal, hence T2 = T, T3, and so forth, the third individual has a linear velocity of 1/2v whereas the second person has a linear velocity of 3/5v and a linear acceleration of 3/5a.

Everyone has the same period since everyone has the same rotational velocity, which is constant and independent of the park equipment's radius. T = T1= T2, Pseudovectors in physics such as rotational velocity, angular frequency vector, and angular velocity are used to describe how quickly an object's angular position or orientation changes.

V = wR V2 = W(3/5) RsV2 = v

V3 = W(1/2R)

Similar to how a2 equals 3/5a, V3 equals 1/2v.

V = wR

V2 = W(3/5)R

V2 = 3/5v

V3 = W(1/2R)

V3 = 1/2 v

similarly

a2 = 3/5a

and a3 = 1/2a

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A physicist observes that a cannonball shot horizontally from a cannon travels 1.000 m before falling to the ground. Which of the following statements correctly explains this observation using Newton's laws?
O Objects tend to remain in the state of motion they are in unless acted upon by an unbalanced force. Friction and gravity acted on the cannonball, slowing it down and slamming it into the ground
O Objects at rest tend to remain in their cument state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion
The force on the cannonball produced by the cannon was less than the force of friction on the cannonball, causing the cannonball to slow down and fall to the ground.
O The force on the cannonball produced by the cannon exactly equaled the force of friction on the cannonball, balancing the forces and causing it to fall to the ground.

Answers

The correct statement that explains the observation using Newton's laws is objects at rest tend to remain in their current state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion. Here option A is correct.

According to Newton's first law of motion, an object will continue moving at a constant velocity in a straight line unless acted upon by an external force. In this case, when the cannonball is shot horizontally from the cannon, it initially possesses a forward velocity due to the force applied by the cannon. However, once the cannonball is in motion, the only forces acting on it are gravity and friction.

Gravity acts vertically downward, causing the cannonball to accelerate downward. Friction acts horizontally in the opposite direction to the motion of the cannonball. As the cannonball moves forward, friction opposes its motion and gradually slows it down.

Since there is no force continuously propelling the cannonball forward, and the forces of friction and gravity act on it, the cannonball eventually comes to a stop and falls to the ground. Hence option A is correct.

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A sound wave has a frequency of 250 Hz and a wavelength of 2.5 m. What is the speed of the wave?

Answers

ANSWER

625 m/s

EXPLANATION

Given:

• The frequency of the sound wave, f = 250 Hz

,

• The wavelength, λ = 2.5 m

Find:

• The speed of the wave, v

The speed of a wave of wavelength λ and frequency f is given by,

\(v=f\cdot\lambda\)

Substitute the known values and solve,

\(v=250Hz\cdot2.5m=625m/s\)

Hence, the speed of the wave is 625 m/s.

How are mass and weight different?

(A) Weight is the amount of matter and mass is the effect of gravity on weight.
(B) Weight is the space an object takes up and mass is the effect of gravity on mass.
(C) Mass is the space an object takes up and weight is the effect of gravity on mass.
(D) Mass is the amount of matter and weight is the effect of gravity on mass.

Answers

Answer:

D

Explanation:

D, Mass is the amount of matter in an object, it is measured in kg and does not change with gravity. Weight is the effect of gravity on mass, it is measured in Newtons (as it is a force) and changes with gravity. E.g. If you went to the moon your weight would change due to the change in gravity but your mass would stay the same.

Hope this helped!

T or F: A spacecraft has captured and brought material to earth from a comet

Answers

A spacecraft has captured and brought material to earth from a comet is True.

A spacecraft has indeed captured and brought material to Earth from a comet. One notable example is the NASA mission called Stardust, which launched in 1999. In 2004, Stardust encountered the comet Wild 2, collected samples of its coma (the cloud of gas and dust surrounding the nucleus), and then returned to Earth in 2006.

The spacecraft captured tiny particles of dust and organic material from the comet, providing valuable insights into the composition and origins of comets. This mission demonstrated the ability of spacecraft to retrieve and deliver extraterrestrial material to Earth for scientific analysis.

Hence, A spacecraft has captured and brought material to earth from a comet is True.

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The width of the cube was 18. 45 mm. The density of the cube was 8. 0 × 103 kg/m3

Calculate the mass of the cube

Answers

The required mass of the cube when width of the cube and density of the cube are specified is calculated to be 0.0502 kg.

The width of the cube is given as 18.45 mm = 18.45 × 10⁻³ m

The density of the cube is given as 8 × 10³ kg/m³.

Mass of the cube is to be found out.

The general formula for density of a cube is given by, V = s³

where,

V is volume

s is side/width/height (As they are all equal in a cube)

So, the volume of the cube is,

V = (18.45 × 10⁻³)³ = 0.01845³ = 6.28 × 10⁻⁶ m³

Now, we know the general equation for density as, mass upon unit volume.

Mathematically, D = m/V

Making m as subject, we have,

Mass m = D × V = 8 × 10³ × 6.28 × 10⁻⁶ = 50.24× 10⁻³ kg = 0.0502 kg

Thus, the required mass is calculated to be 0.0502 kg.

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Si se desea construir un circuito con poca resistencia se debe colocar: En serie Mixto Paralelo Ninguna de las anteriores

Answers

Answer:

Parallel combination

Explanation:

When the two resistances are connected in parallel then the equivalent resistance is

\(\frac{1}{R}=\frac{1}{R'}+\frac{1}{R''}\)

To get the minimum resistance of a circuit, the circuit components should be connected in parallel combination.

In the parallel combination, the voltage across each resistor is same and the current is divided in every resistance according to the resistances.

The force required to maintain an object at a constant velocity in free space is equal to zero. the weight of the object. the force required to stop it. the mass of the object.

Answers

The force required to maintain an object at a constant velocity in free space is equal to zero, while the force required to stop it depends on its initial velocity, mass, and the distance over which the force is applied.

According to Newton's first law of motion, an object at rest will remain at rest, and an object in motion will continue to move at a constant velocity unless acted upon by an external force. Therefore, to maintain an object at a constant velocity in free space, no external force is required.

However, if the object is in a gravitational field, it will experience a force due to its weight. The weight of an object is the force exerted on it by gravity, and it is equal to the object's mass multiplied by the acceleration due to gravity. Therefore, if the object is not moving, the force required to maintain it in equilibrium is equal to its weight.

If the object is moving and we want to bring it to a stop, we need to apply a force in the opposite direction to its motion. The force required to stop the object depends on its initial velocity, mass, and the distance over which the force is applied. The greater the initial velocity and mass of the object, the more force will be required to stop it. The weight of the object is the force it experiences due to gravity and is only relevant when the object is at rest.

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Select the correct answer.
The motion of a car on a position-time graph is represented with a horizontal line. What does this indicate about the car's motion?
А.
It's not moving
B.
It's moving at a constant speed.
It's moving at a constant velocity
D. It's speeding up.

Answers

Answer:

a

Explanation:

Answer:

its a because its the only thing not moving

Explanation:

A 440kg bull has a speed of 14m/s. The bull runs into a wall and comes to a rest. What is the bulls change in kinetic energy? Find the amount of work the wall does on the bull.

Answers

The bull lost 107,800 J of kinetic energy during the collision. The wall did 107,800 J of work on the bull during the collision.

What is the kinetic energ?

The initial kinetic energy of the bull is:

KE = (1/2)mv²

KE = (1/2)(440 kg)(14 m/s)²

KE = 107,800 J

Since the bull comes to a complete rest, its final kinetic energy is zero. Therefore, the change in kinetic energy is:

ΔKE = 0 - 107,800 J

ΔKE = -107,800 J

This means that the bull lost 107,800 J of kinetic energy during the collision.

What is the work?

The work done by the wall on the bull is equal to the negative of the change in kinetic energy:

W = -ΔKE

W = -(-107,800 J)

W = 107,800 J

Therefore, the wall did 107,800 J of work on the bull during the collision.

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Complete question is: A 440kg bull has a speed of 14m/s. The bull runs into a wall and comes to a rest. the bull lost 107,800 J of kinetic energy during the collision and the wall did 107,800 J of work on the bull during the collision.

In the circuit in the figure, the capacitors are completely uncharged. The switch is then closed for a long time. As shown, R₁ = 6Ω, R₂ = 40 Ω, R3 = 40 Ω and V = 20V. What is the potential difference (in V) across the R₂ resistor? A) 8; B) 6; C) 0; D) 4; E) 10;

Answers

Potential difference (in V) across the R₂ resistor is option E) 10

In the circuit given below, the capacitors are uncharged. The switch is then closed for a long time. R₁ = 6Ω, R₂ = 40 Ω, R3 = 40 Ω and V = 20V.

Find the potential difference across the R₂ resistor.Circuit Diagram:We can solve this question by following the below steps:

Step 1: Finding the Total Resistance

Let us assume the capacitors to be open circuit initially and solve the resistors R₁, R₂, and R₃ in series,

Rₛ.Rₛ= R₁ + R₂ + R₃= 6 + 40 + 40= 86Ω

Step 2: Calculating the Current

We can calculate the current flowing in the circuit by using Ohm's law, which is given as:

I = V/Rₛ = 20/86= 0.23A

Step 3: Finding the Potential Difference across R₂The potential difference across R₂ is given as:

V₂= IR₂= 0.23 × 40= 9.2V

Therefore, the potential difference (in V) across the R₂ resistor is 9.2V.

The option that matches the value is E. 10.

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Which type of wave can travel through empty space?
PLZ HELP ME BEST ANSWER WILL GET BRAINLIEST
AND IM SRS ABT THIS QUESTION

Answers

Answer:

Electromagnetic waves.

Explanation:

Electromagnetic waves include microwaves, X-rays, gamma rays, and light waves, it carries energy and it can travel through matter or empty space.

Answer:

Electromagnetic waves or Light Waves

Explanation:

"Electromagnetic waves carry energy. The waves consist of transverse vibrations in electrical and magnetic fields, not vibrating particles. Electromagnetic waves do not need matter to travel through - they can travel through empty space (a vacuum)."

 

...Bored so lol

A 1-m3 tank holds a two-phase liquid-vapor mixture of carbon dioxide at – 17 °C. The quality of the mixture is 70%. For saturated carbon dioxide at – 17 °C, vf = 0.9827×10-3 m3/kg and vg =1.756×10-2 m3/kg. Determine the masses of saturated liquid and saturated vapor, each in kg. What is the percent of the total volume occupied by saturated liquid?

Answers

Answer:

a)  \(m_v= 56.16 Kg\)

    \(m_l= 14.04 Kg\)

b)  \(\mu=1.37\%\)

Explanation:

From the question we are told that:

Volume of tank \(V_t=1m^3\)

Temperature of \(CO_2=-17^oC\)

Quality of the mixture \(Q= 70%\)

Specific Volume constants at \(-17^oC:\)

 \(v_f = 0.9827*10^{-3} m3/kg\)

 \(v_g =1.756*10^{-2} m3/kg.\)

Generally the equation for Specific Volume is mathematically given by

 \(v = v_f + x (v_g -v_f)\)

 \(v= (0.9827 * 10^{-3} ) + 0.8 * (17.56 * 10^{-3} -0.9827 * 10^{-3})\)

 \(v= 0.014244 m3/Kg\)

Generally the equation for Mass is mathematically given by

 \(m=\frac{v'}{v}\)

 \(m=\frac{1}{0.014244}\)

 \(m=70.20 Kg\)

Generally the Mass of saturated Vapor is mathematically given by

 \(m_v=0.8 * (70.202)\)

 \(m_v= 56.16 Kg\)

Generally the Mass of saturated Liquid is mathematically given by

 \(m_l = (70.20 Kg)-(56.16 Kg)\)

 \(m_l= 14.04 Kg\)

b)

Generally the equation for Volume is mathematically given by

 \(v_l = m_l x v_f\)

 \(v_l= (14.04 Kg) (0.9827 x 10{-3} m3/kg)\)

 \(v_l= 0.01379 m^3\)

Therefore Percentage of liquid

 \(\mu = \frac{v_l}{v} * 100 \%\)

 \(\mu= [(0.01379 m^3)/(1 m^3)] *100 \%\)

 \(\mu=1.37\%\)


A 60.kg giri roils down a frictionless hill on a skateboard. At the bottom of the hill, she is traveling at a speed of 30. m/s.
What is her Kinetic Energy at the bottom of the hill?

Answers

Answer:

She won't have any kenetic energy at the bottom of the hill

Explanation:

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