What two variables is acceleration dependent on? What is the relationship between these variables and acceleration? (i.E. If you increase one variable what happens to the acceleration?)
Answers
Answer:
1. Unbalanced Force (If you increase force, the acceleration will increase)
2. Mass of Body (If you increase mass, the acceleration will decrease)
Explanation:
According to Newton's Second Law the acceleration produced in a body depends upon two variables. The law states that:
“When an unbalanced force is applied on a body then an acceleration is produced in it, in its own direction”
The magnitude of produced acceleration is directly proportional to the applied force and inversely proportional to the mass of body. Mathematically,
a α F
and, a α 1/m
where,
a = acceleration
F = Unbalanced Force
m = Mass of Body
So, the acceleration increases when the unbalanced force increase and vice versa.
And the acceleration decreases when the mass of body increase and vice versa.
combining above equations:
a α F/m
a = (Constant)F/m
here,
Constant = 1
therefore,
F = ma
Related Questions
Which example illustrates Newton's second law?
A. A wheelbarrow remains stationary when no one pushes on it.
B. More mass is added to a wheelbarrow, and a larger force is
required to move it.
C. A person pushes a wheelbarrow, causing it to move forward.
D. The force of a wheelbarrow on the ground is equal to the force of
the ground on the wheelbarrow.
Answers
Answer:B
Explanation:
Mass
More mass is added to a wheelbarrow, and a larger force is required to move it - illustrates Newton's second law.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Newton’s second law of motion states that “Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration."
Hence more mass is added to a wheelbarrow, and a larger force is required to accelerate, i.e., move it.
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Two like charges are either both ______ or both _______
Answers
Answer:
negative or posotive i think
Explanation:
Please someone answer this quickly!! I'll give 20 points for it, I just need the answers :)
Answers
The potential energy of the person mass 95 Kg sitting on top of a slid 3 m high is 2795.85 J
How do i determine the potential energy of the person?The following data were obtained from the question:
Mass of person (m) = 95 KgHeight of slid (h) = 3 mAcceleration due to gravity (g) = 9.81 m/s² Potential energy of person (PE) = ?The potential energy of the person can be obtained as follow:
PE = mgh
Inputting the given parameters, we have:
= 95 × 9.81 × 3
= 2795.85 J
Thus, the potential energy of the person is 2795.85 J
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the amount of gravitational force that acts on a space vehicle while in earth orbit is
Answers
The amount of gravitational force that acts on a space vehicle while in earth orbit is almost zero but not absolute zero.
There is no ground force or opposing natural force to gravity.
Because the earth is not a perfect sphere, the value of "g" is lowest at the equator. At the equator, its radius is at its largest. Thus, the equator is the location where g will be smallest according to the equation
g = GM/R2.
All items in the planet's gravitational field will be lost in space if gravity abruptly vanishes. We would experience levity. Essentially, if gravity is equal to zero, then there will be no acceleration caused by gravity.
Astronauts can float within their spaceship or outside during a spacewalk in microgravity. Moving heavy stuff is simple. Astronauts, for instance, can merely use their fingertips to manipulate machinery weighing hundreds of pounds.
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Killer Comet . Imagine a comet with a million-year period that swoops into the er solar system all the way to 1AU perihelion distance. (a) What is the comet's aphelion distance? (Yes, you do have enough information.) (b) What is the eccentricity of the comet's orbit? I prefer this ellipse equation: r=a(1−e
2
)/(1+ecos(θ)) where a is the semimajor axis, with perihelion defined as θ=0
∘
and aphelion as θ=180
∘
. (It can be handy to remember that (1−e
2
) can be factored. Note that you will need to find e to many significant figures in order to have perihelion at 1AU ) (c) Write an expression for the total energy (kinetic plus potential) of an object on a circular orbit with semimajor axis a. Substitute in the relationship we found for v
circ
and show that E
tot
=−GMm/2a. Rearrange E
tot
=KE+PE to solve for the object's velocity as a function of its distance r. Use it to calculate the comet's perihelion velocity v
p
. (d) Use any of the methods discussed in class to find comet velocities along the orbit in 30
∘
intervals. Include a table. What is the comet's velocity at aphelion? (e) How fast would such a comet hit the Earth, in the worst case where the comet was traveling in the opposite direction as Earth's orbital motion? What about the "best case" where both are traveling in the same direction? Neglect Earth's gravity. (f) Consider the case where the comet hits Earth from behind. It will change Earth's orbit in a miniscule way. Will these quantities increase or decrease: Earth's semimajor axis, eccentricity, aphelion, angular momentum and period?
Answers
The Earth's orbit will become more elliptical (increase in eccentricity), the semimajor axis will remain the same, and the period will be slightly altered.
(a) What is the comet's aphelion distance.If a comet has a period of one million years, its semi-major axis is half of its aphelion distance (the farthest distance from the sun) plus half of its perihelion distance (the closest distance to the sun).
From this information we can get the perihelion distance, which is 1AU (astronomical unit).
It means that the distance from the comet to the sun when it is closest is the same distance as the Earth from the sun.So, a = (1AU + x)/2Where x is the aphelion distance.
Now, we have to use Kepler's third law that states that: T² = a³ / (GM)Substitute with a, GM and T = one million years and solve for x.x = 3055 AU(b) What is the eccentricity of the comet's orbit.The eccentricity of the orbit can be found by using the formula:r = a(1-e²) / (1+e cos(θ))where θ=0 is perihelion and θ=180 is aphelion. Also, we know that the distance at perihelion is 1 AU, and we can use this information to solve for e.
So we have:r = a(1-e) = 1AUa(1+e) = x + 1AUFrom part (a), we know that x=3055AU. Substituting it above and dividing the two equations, we get: (1-e)/(1+e) = 1/3056Solving this we get e = 0.999672(c) Write an expression for the total energy (kinetic plus potential) of an object on a circular orbit with semi-major axis a. Substitute in the relationship we found for vcirc and show that Etot = −GMm/2a. Rearrange Etot = KE+PE to solve for the object's velocity as a function of its distance r.
Use it to calculate the comet's perihelion velocity vp.Substituting the value of vcirc into the expression for total energy gives:E = -GMm / 2aThe total energy is the sum of kinetic energy and potential energy. The kinetic energy (KE) of an object moving in a circular orbit is given by:KE = (1/2)mv²PE = -GMm/r Substituting the equations of KE and PE into the equation of total energy, we get the equation for velocity:v² = GM/rorv = (GM/r)^(1/2)When the comet is at perihelion, r = 1AU, and v = vp.The perihelion velocity isvp = (GM/1AU)^(1/2) = 42.1 km/s(d) Use any of the methods discussed in class to find comet velocities along the orbit in 30 ∘ intervals.
Include a table. What is the comet's velocity at aphelion?The velocity of the comet can be found using the equation:v = (GM / r(1 + e cos(θ)))^0.5where θ = 0 corresponds to perihelion, θ = 180 to aphelion, and e = 0.999672.The table for comet velocities is shown below:θ v (km/s)0 42.11830 41.77660 39.79990 36.40120 31.81950 26.28280 20.01010 13.21080 6.0958 0.3332 6.0958 13.21080 20.01010 26.28280 31.81950 36.40120 39.79990 41.7766 42.1183.
At aphelion, θ=180∘, and the velocity of the comet is:va = (GM / r(1 - e))^(0.5) = (GM / 3056AU)^(0.5) = 0.049 km/s(e) How fast would such a comet hit the Earth, in the worst case where the comet was traveling in the opposite direction as Earth's orbital motion What about the "best case" where both are traveling in the same direction? Neglect Earth's gravity.
When the comet is traveling in the opposite direction as Earth's orbital motion, the relative velocity of the comet with respect to Earth is the sum of the velocities:vr = ve + vcwhere ve is the velocity of Earth in its orbit and vc is the velocity of the comet at perihelion.
The speed of the comet with respect to Earth is:vrel = (vc - ve) = (42.118 - 29.8) km/s = 12.318 km/sWhen both are traveling in the same direction, the relative velocity of the comet with respect to Earth is the difference of the velocities:vr = vc - veThe speed of the comet with respect to Earth is:vrel = (vc - ve) = (42.118 + 29.8) km/s = 71.918 km/s(f) Consider the case where the comet hits Earth from behind.
It will change Earth's orbit in a minuscule way. Will these quantities increase or decrease: Earth's semimajor axis, eccentricity, aphelion, angular momentum, and period?When the comet hits the Earth from behind, its velocity is opposite to the velocity of the Earth in its orbit.
Therefore, the momentum of the Earth is decreased by the same amount as the momentum of the comet, according to the law of conservation of momentum.
The angular momentum of the Earth is not changed since the impact is along the line of motion. The Earth's orbit will be changed, and the change will depend on the mass and velocity of the comet, as well as the angle of impact.
In general, the Earth's orbit will become more elliptical (increase in eccentricity), the semimajor axis will remain the same, and the period will be slightly altered.
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(a) The comet's aphelion distance is a(1 - e^2) / (1 - e). (b) The eccentricity, e is equal to (-1 ± sqrt(1 + 4(a - 1))) / 2. (c) v_p = sqrt(2GM / (1 AU) - GM / a).
(e) The relative velocity between the comet and Earth would be the same as the impact velocity. and (f) The period of Earth's orbit would also be affected, but the change would be minimal.
(a) To find the comet's aphelion distance, we can use the information given. We know that the perihelion distance is 1 AU. The perihelion distance occurs at an angle of θ = 0° in the ellipse equation. Similarly, the aphelion distance occurs at an angle of θ = 180°.
Using the ellipse equation, r = a(1 - e^2) / (1 + e * cos(θ)), we can substitute θ = 180° and solve for the aphelion distance.
So, r_aphelion = a(1 - e^2) / (1 + e * cos(180°)).
Since cos(180°) = -1, the equation simplifies to r_aphelion = a(1 - e^2) / (1 - e).
(b) To find the eccentricity of the comet's orbit, we need to use the information provided and the equation r = a(1 - e^2) / (1 + e * cos(θ)).
We know that the perihelion distance is 1 AU and occurs at θ = 0°. Substituting these values into the equation, we get 1 = a(1 - e^2) / (1 + e * cos(0°)).
Since cos(0°) = 1, the equation simplifies to 1 = a(1 - e^2) / (1 + e).
Simplifying further, we have 1 + e = a(1 - e^2).
We can rearrange this equation to e^2 + e - (a - 1) = 0.
Now, we can solve this quadratic equation for e using the quadratic formula.
The eccentricity, e, is given by e = (-1 ± sqrt(1 + 4(a - 1))) / 2.
(c) The total energy (kinetic plus potential) of an object on a circular orbit with semimajor axis a is given by E_tot = -GMm / (2a), where G is the gravitational constant, M is the mass of the central body (in this case, the Sun), and m is the mass of the object.
Substituting the relationship we found for the circular orbit velocity, v_circ = sqrt(GM / a), into the equation for kinetic energy KE = (1/2)mv^2, and the equation for potential energy PE = -GMm / r, we have E_tot = KE + PE.
Substituting these values, we get E_tot = (1/2)mv_circ^2 - GMm / r.
Rearranging the equation, we can solve for the object's velocity v as a function of its distance r: v = sqrt(2GM / r - GM / a).
To calculate the comet's perihelion velocity v_p, we substitute r = 1 AU (since the perihelion distance is 1 AU) into the equation: v_p = sqrt(2GM / (1 AU) - GM / a).
(d) To find the comet's velocities along the orbit in 30° intervals, we can use the equation v = sqrt(2GM / r - GM / a), where r is the distance from the Sun and a is the semimajor axis.
By substituting the appropriate values of r at 30° intervals into the equation, we can calculate the corresponding velocities.
Here is a table showing the comet's velocities at different intervals:
Angle (°) | Distance (AU) | Velocity (km/s)
0 | 1 | v_p
30 | r_30 | v_30
60 | r_60 | v_60
90 | r_90 | v_90
...
150 | r_150 | v_150
180 | r_aphelion | v_aphelion
(e) To find the comet's velocity if it were to hit the Earth, we need to consider two cases: worst case and best case.
In the worst case scenario, the comet is traveling in the opposite direction as Earth's orbital motion. In this case, we need to add the velocities of the comet and Earth to find the relative velocity between them. The comet's velocity is v_p and Earth's orbital velocity is v_earth. The relative velocity would be the sum of these velocities.
In the best case scenario, both the comet and Earth are traveling in the same direction. In this case, we need to subtract the velocities of the comet and Earth to find the relative velocity between them.
Neglecting Earth's gravity, the relative velocity between the comet and Earth would be the same as the impact velocity.
(f) If the comet hits Earth from behind, it will change Earth's orbit in a minuscule way. The impact would alter Earth's semimajor axis, eccentricity, aphelion, angular momentum, and period.
The impact of the comet would cause Earth's semimajor axis to increase, as the momentum transferred from the comet would push Earth slightly away from the Sun.
The eccentricity of Earth's orbit would also increase, as the impact would introduce a slight asymmetry to the orbit.
The aphelion of Earth's orbit would shift slightly, depending on the direction and velocity of the impact.
The impact would affect Earth's angular momentum, causing it to change.
Finally, the period of Earth's orbit would also be affected, but the change would be minimal.
It is important to note that the changes in these quantities would be relatively small and might not be noticeable in practical terms.
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The dock workerpushes on a 1200 N crate but it doesnt move. How much work is performed by him.
Answers
Work is performed by him is zero.
What is work?Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance traveled for a constant force directed in the direction of motion.
Given in the question a force of 1200 N crate but it doesn't move.
Work = force x distance. In units, Joules = Newtons x meters.
So: Work = 1200 Newtons x 0 meters
Work = 0 joules.
Work is performed by him is zero.
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Blake is building a treehouse. He wants to make sure the wood pieces are held together very tightly since he and his friends will be standing and hanging on them! Should he use nails or screws to hold pieces of wood together? Why? i'll give the brainliest
Answers
If Blake wants to ensure that the wood pieces are held together tightly and securely, he should use screws rather than nails.
How should the nails or screws be used to hold pieces of wood together?If Blake wants to make sure that the wood pieces are held together tightly, he should use screws rather than nails to hold the pieces of wood together.
Screws have threads along their length, which create strong grip on wood and hold it tightly in place. When screw is driven into the wood, threads cut into the wood fibers and create secure connection that resists pulling and twisting forces. In contrast, nails simply rely on friction between the wood and shank of the nail to hold the pieces together.
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Disilicon Trisulfide formula?
Answers
Common Name disilicon hexabromide
CAS Number 13517-13-0 Molecular Weight
Density N/A Boiling Point
Molecular Formula Br6Si2 Melting Point
MSDS N/A Flash Point
(a) How long is the bullet in the target?
1
s
What average force does it exert on the target?
2
N (magnitudeonly)
(b) What is the target's speed just after the bullet emerges?
3
m/s
Answers
1 second is insufficient to provide details about the bullet's length. average force cannot be determined accurately with the given information. The bullet speed is insufficient to provide details about the bullet's length. average force cannot be determined accurately with the given information. The bullet's speed just after emerging from the target is 3 m/s.
(a) It is not possible to determine the length of the bullet in the target with the given information. The time duration of 1 second is insufficient to provide details about the bullet's length. The average force exerted by the bullet on the target can be calculated using Newton's second law: force = mass × acceleration. However, the mass and acceleration of the bullet are not provided, so the average force cannot be determined accurately with the given information.
(b) Assuming that the bullet emerges from the target with a speed of 3 m/s, it implies that the target imparts an equal and opposite force on the bullet according to Newton's third law of motion. The bullet's speed just after emerging from the target is 3 m/s.
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If an Isotope has a Half-life of minutes. How many Half-life's have occurred after 24 minutes?
Answers
Answer:12
Explanation:
A supply plane needs to drop a package of food to scientists working on a glacier in Greenland. The plane flies 130 m above the glacier at a speed of 160 m/s. How far short of the target should it drop the package?
Answers
The plane flies at speed of 160m/s should drop the package when it reaches at a distance of 824m.
How does Newton's second law relate to gravity?A dropped object travels quickly in the direction of the earth's center. Newton's second law states that the net force applied on an object determines its acceleration. If air resistance is small, the gravitational force, which is also known as an object's weight (w), acts as the net force on any falling object.
What other name does gravity's acceleration go by?Free-fall acceleration seems to be another name for gravitational acceleration. Gravitational fields established by masses pull other masses approach them.
\(h = ut + 1/2 gt^2 ; u=0130 = 1/2 \times 9.8 \times t^2t= 5.15sec\)
The packet travel with the time period of 5.15sec
The distance = v x t
160m/s x 5.15s = 824m
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if the raindrop comes to rest in 0.37 ms m s , what is the magnitude of the average force of the impact?
Answers
To determine the magnitude of the average force of the impact, we can use the impulse-momentum theorem, which relates the change in momentum of an object to the impulse applied to it.
What is momentum ? In this case, the impulse is the force of the impact multiplied by the time of contact, and the change in momentum is the final momentum of the raindrop, which is zero, since it comes to rest.The impulse-momentum theorem can be expressed as:Impulse = Change in momentum
or
F * Δt = m * Δv
where F is the force of the impact, Δt is the time of contact, m is the mass of the raindrop, and Δv is the change in velocity of the raindrop.Since the raindrop comes to rest, the change in velocity is:
Δv = 0 m/s - v_i
where v_i is the initial velocity of the raindrop. We don't know the initial velocity of the raindrop, but we don't need to know it since we are only interested in the magnitude of the force of the impact.Rearranging the equation for the impulse-momentum theorem to solve for the force, we get:
F = m * Δv / Δt
Substituting the given values, we get:
F = m * (-v_i) / Δt
Now, we need to find the mass of the raindrop. The density of water is approximately 1000 kg/m^3, so the mass of the raindrop can be calculated using the volume of a sphere formula:V = (4/3) * π * r^3
where V is the volume of the raindrop, and r is the radius of the raindrop.
Assuming a raindrop with a radius of 1 mm (0.001 m), the volume of the raindrop is:V = (4/3) * π * (0.001 m)^3 = 4.19 × 10^-9 m^3
The mass of the raindrop is:
m = density * volume = 1000 kg/m^3 * 4.19 × 10^-9 m^3 = 4.19 × 10^-6 kg
Substituting this expression for the mass, and assuming the time of contact is 0.37 ms (0.00037 s), we get:F = (4.19 × 10^-6 kg) * (-v_i) / (0.00037 s) = -11.3 * v_i
Note that the force is negative because it is in the opposite direction of the initial velocity of the raindrop.
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What is the acceleration of an object with an applied force of 100 N and a mass 50 kg? Q"
Answers
The acceleration of the object with an applied force of 100N and a mass of 50kg is 2m/s².
Acceleration is defined as the change in velocity per unit time. Velocity is defined as the speed of the object in a particular direction. The acceleration is a vector quantity. The unit of acceleration is m/s².
According to Newton's second law, Force is directly proportional to the acceleration of the object. F = m×a, where F is the force of the object, m is the mass of the object and a is the acceleration of the object.
From the given,
Force, F = 100N
mass of the object, m=50kg
acceleration of the object, a=?
F = m×a
a =F/m
= 100/50
=2m/s².
Thus, the acceleration of the object is 2m/s².
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Hello. If anyone could help me fill out this I would really appreciate. I'm stuck on this. Thank you.
Answers
To find the missing values in the table, we can use the formula:
Q = I² * R * t
where Q is the energy in joules, I is the current in amperes, R is the resistance in ohms, and t is the time in seconds.
Eil. nr. I R t Q
1 5A 200Ω 10s 10000J
2 2A 500Ω 5s 10000J
3 40A 50Ω 10s 20000J
4 0.1A 300Ω 1.0s 30J
Here are the calculations for each missing value:
For Eil. nr. 1, Q can be found by multiplying I² * R * t = 5² * 200 * 10 = 10000 J.For Eil. nr. 2, R can be found by dividing Q / (I² * t) = 2000 / (2² * 5) = 500 ohms.For Eil. nr. 3, I can be found by taking the square root of Q / (R * t) = sqrt(2000 / (50 * 10)) = 40 A.For Eil. nr. 4, t can be found by dividing Q / (I * R) = 300 / (0.1 * 300) = 1.0 s.What is an energy?
Energy is a fundamental concept in physics that describes the ability of a system to do work or cause a change. In other words, energy is the capacity of a system to perform a task or produce an effect. energy can take many different forms.
What is resistance?
In physics, resistance refers to the opposition of a material or device to the flow of electrical current. In other words, resistance is a measure of how much a material or device hinders the flow of electric charge through it.
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Find the volume of a box measuring 4cm by 6cm by 8cm
Answers
Answer:
192 cm.
Explanation:
Step 1:
4 cm. × 6 cm. × 8 cm. Equation
Step 2:
24 cm. × 8 cm. Multiply
Answer:
192 Multiply
Hope This Helps :)
What type of matter is 10 grams of calcium?
plz help me begging
Answers
Answer:
A pure element.
Explanation:
Calcium, being whatever weight, is a pure element.
Hope this helped! Have a good day.
Answer:
the answer is
Explanation: Calcium is a chemical element with symbol Ca and atomic number 20. Classified as an alkaline earth metal, Calcium is a solid at room temperature.
1. Write the advantages and disadvantages of connecting lamps (a) in series and (b) in parallel. A3 2. a) 0.2A Draw Fig 5.30 into your exercise book and name the way in which the lamps are connected and answer questions b and c A₂ b) If A3 read 0.2A, what do the other two ammeters read? A1 c) If one of the lamps is removed explain what would happen to the other lamp. Fig 5.30 Reading of ammeter in series circuit
Answers
Answer:
parallel connection:Advandages: 1. Every unit that is connected in a parallel circuit gets equal amount of voltage.2. It becomes easy to connect or disconnect a new element without affecting the working of other elements.3. If any fault happened to the circuit, then also the current is able to pass through the circuit through different paths.Disadvantages: 1. It requires the use of lot of wires.2. We cannot increase or multiply the voltage in a parallel circuit.3. Parallel connection fails at the time when it is required to pass exactly same amount of current through the units.series connection:Advantages: 1. Series circuits do not overheat easily. This makes them very useful in the case of something that might be around a potentially flammable source, like dry plants or cloth.2. Series circuits are easy to learn and to make. Their simple design is easy to understand, and this means that it’s simple to conduct repairs .3. we can add more power devices, they have a higher output in terms of voltage .4. The current that flows in a series circuit has to flow through every component in the circuit. Therefore, all of the components in a series connection carry the same current.Disadvantages: 1.If one point breaks in the series circuit,the total circuit will break.2. As the number of components in a circuit increases ,greater will be the circuit resistance.
a lamp is connected to 2 v dc. when cold, the current through the lamp is 0.7 a. what is its resistance?
Answers
The resistance of the lamp is approximately 2.857 ohms.
Ohm's law states that the current flowing through a conductor is directly proportional to the voltage across it, given a constant temperature. Mathematically, it can be expressed as V = IR, where V is the voltage, I is the current, and R is the resistance of the conductor.
To calculate the resistance of the lamp, we can use Ohm's law.
Given that the lamp is connected to a 2 V DC power supply and the current through the lamp is 0.7 A, we can plug these values into the equation:
R = V/I
R = 2 V / 0.7 A
R = 2.857 ohm
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Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above it. How far above the electron would the proton have to be? (k= 9.0 x 10^9 Nm^2/C^2, e= 1.6 x 10^-19 C, mass of proton = 1.67 x 10^-27kg, mass of electron= 9.11 x 10^-31kg)
Answers
The proton would need to be about 5.53 x 10^-11 meters above the electron to hold it up against the force of gravity by the attraction of the proton.
To hold up an electron against the force of gravity by the attraction of a fixed proton, we need to determine the distance between the electron and the proton at which the electric force between them is equal and opposite to the force of gravity on the electron
The force of gravity on the electron is given by the equation
Fg = mg
where m is the mass of the electron, and g is the acceleration due to gravity (9.81 m/s^2).
The electric force between the electron and the proton is given by Coulomb's law
Fe = k × (q1×q2)/r^2
where k is Coulomb's constant, q1 and q2 are the charges of the electron and proton respectively, and r is the distance between them.
At equilibrium, Fe = Fg, so we can set these two equations equal to each other and solve for r
k × (q1×q2)/r^2 = mg
r^2 = k × (q1×q2) / mg
r = sqrt(k × (q1×q2) / mg)
Substituting in the given values
r = sqrt((9.0 x 10^9 Nm^2/C^2) × (1.6 x 10^-19 C)^2 / ((9.11 x 10^-31 kg) × (1.67 x 10^-27 kg) × (9.81 m/s^2)))
r = 5.53 x 10^-11 meters
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What is the charge on an object that experiences a force of 5 Newtons in an electric field of 50 Newtons per coulomb?
Answers
Answer:
Explanation:
F = qE
F is the force in Newtons
q is the test charge
E is the electrical field produced by the source charge
\(5=q(50)\\q=1*10^-^1Coulombs\)
The magnitude of charge on the object is of 0.1 C.
Given Data:
The magnitude of electric field is, E = 50 N/C.
The magnitude of Electric force is, F = 5 N.
The region where any particle feels the effect of electric force on itself, due to other charged entities, is known as Electric field. And the relation between the electric force and electric field is given as,
F = E × q
Here,
q is the magnitude of charge on the object.
Solving as,
q = F/E
q = 5 / 50
q = 0.1 C
Thus, we can conclude that the magnitude of charge on the object is of 0.1 C.
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A charged prod, such as the one seen in the video, is brought near an identical charged hanging sphere. Consider the dependence of the electric force on distance that you found in the video. Based on this, what would happen to the force on the hanging sphere if the distance between the spheres was doubled
Answers
Based on the dependence of the electric force on distance, if the distance between the charged rod and the hanging sphere is doubled, the force on the hanging sphere would decrease by a factor of four.
The electric force between two charged objects is inversely proportional to the square of the distance between them. This means that as the distance between the charged rod and the hanging sphere is doubled, the force acting on the hanging sphere decreases by a factor of (\(2^2\)) = 4.
The reason for this relationship is rooted in Coulomb's law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. When the distance is doubled, the denominator of the equation increases by a factor of 4, resulting in a force that is one-fourth of the original force.
Therefore, if the distance between the charged rod and the hanging sphere is doubled, the force on the hanging sphere will be reduced to one-fourth of its original value. This indicates that the electrostatic force between the two objects weakens as the distance between them increases.
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two trains a and b have lengths 100 m and 80 m respectively. they move in opposite directions along parallel tracks at 72 km/hr and 54 km/hr respectively. what is the time taken by one train to cross the other?
Answers
. The relative speed of the two trains is equal to the sum of their speeds. That is,Relative speed = Speed of A + Speed of B= 72 km/hr + 54 km/hr= 126 km/hr= 126 * (5/18) m/sec= 35 m/secNow let's consider the distance covered to cross the other train.
The distance that will be covered by both the trains to cross each other is equal to the sum of their lengths. That is,Distance covered = Length of A + Length of B= 100 m + 80 m= 180 mTherefore, the main answer is:The time taken by one train to cross the other= Distance / Relative speed= 180 / 35= 5.14 seconds (approx.)Hence, the explanation of the given problem is as follows:Two trains A and B are moving in opposite directions along parallel tracks. The lengths of the two trains A and B are 100 m and 80 m, respectively.
The speeds of A and B are 72 km/hr and 54 km/hr, respectively.The relative speed of the two trains is equal to the sum of their speeds. The relative speed of the two trains is equal to 35 m/sec. The distance covered by both the trains to cross each other is equal to the sum of their lengths. The distance covered by both the trains to cross each other is equal to 180 m.The time taken by one train to cross the other is equal to the ratio of distance covered to relative speed. The time taken by one train to cross the other is equal to 5.14 seconds (approx.)
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whole numbers smaller than 20
Answers
Answer:
19 and below because a whole number is just a number that isn't a fraction. They are basic counting numbers
Explanation:
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Signals are digitized during transmissions over wireless networks. The chart lists possible features of digital communication.
Which features are correct?
1 and 2 only
3 and 4 only
1, 2, and 3
2, 3, and 4
Answers
Answer:
you got to add the chart my g
Explanation:
Answer:
You didn't add the chart fam
Explanation:
An astronaut decides to perform an experiment to monitor how much weight he loses during his stay on the International Space Station. He weighs himself prior to takeoff, daily while on the space station, and again after returning to Earth.
Explain the following for 2 points each:
Identify what data from the weights he recorded should be considered in his experiment
For any weigh-ins that should not be used in his experiment, explain your reasoning
Explain the relationship between mass, weight, and gravity
Answers
Answer:
The first one is: His weight on the Earth before take-off and the weight after take-off back on Earth once he gets back should be recorded as his Independent variable and his dependent variable.
The second one is: If he gained the weight back that he had lost while on the trip then you should disregard them unless that was the weight he was when he weighed himself after he got back.
The Third one is: The mass of an object is the amount of matter it contains, regardless of its volume or any forces acting on it. … Gravity is a force that attracts objects toward the Earth. The weight of the object is defined as the force caused by gravity on a mass.
Explanation:
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What is the acceleration of the car at t=5.0 seconds
Answers
The acceleration of the car is 0 m/s²
"Your question is not compete it seems to be missing the following information";
the initial velocity of the car at 5 seconds is 10 m/s and the final velocity of the car at 5 seconds is 10 m/s
The given parameters;
the initial velocity of the car, u = 10 m/sthe final velocity of the car, v = 10 m/stime of motion, t = 5.0 sThe acceleration of the car is defined as the change in velocity of the car per change in time of motion.
\(a = \frac{\Delta v}{\Delta t} \\\\a = \frac{v-u}{t} \\\\a = \frac{10 - 10}{5} \\\\a = 0 \ m/s^2\)
Thus, the acceleration of the car is 0 m/s²
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What happens to the speed of light if it travels from water into air?
Answers
Answer:
What happens is that light slows down when it passes from the less dense air into the denser glass or water. This slowing down of the ray of light also causes the ray of light to change direction.
Explanation:
Atoms of the same element that differ only in the number of neutrons are known as.
Answers
Answer:
They are known as isotopes
There are changes in the amounts of different energy recorded used between 2014 and 2015 explain the environmental impacts of the changes
Answers
Find the mass if the force is 18 N and the acceleration is 2 m/s2.
Answers
Answer:
The answer is 9 kgExplanation:
To find the mass given the force and acceleration we use the formula
\(m = \frac{f}{a} \\ \)
where
f is the force
a is the acceleration
We have
f = 18 N
a = 2 m/s²
We have
\(m = \frac{18}{2} \\ \)
We have the final answer as
9 kgHope this helps you