Answer:
electromagnetic forces and gravitational forces
Explanation:
At a macroscopic level, electromagnetic forces and gravitational forces have action at the distance.
The parallel plates in a capacitor, with a plate area of 9.30 cm2 and an air-filled separation of 4.50 mm, are charged by a 7.80 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 9.60 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.
Answer:
a) ΔV ’= 1.66 10¹ V= 16.6 V, b) U = 55.64 10⁻¹² J, c) U_f = 1.18 10⁻¹⁰ J
d) W = 6.236 10⁻¹¹ J
Explanation:
Capacitance can be found for a parallel plate capacitor
C = ε₀ \(\frac{A}{d}\)
Let's reduce the magnitudes to the SI system
A = 9.30 cm² (1 m / 10² cm) 2 = 9.30 10⁻⁴ m²
c = 4.50 mm (1 m / 1000 mm) = 4.50 10⁻³ m
Co = 8.85 10⁻¹² 9.30 10⁻⁴ /4.50 10⁻³
Co = 1.829 10⁻¹² F
when the plates separate at d = 9.60 10⁻³ m, the capcitance changes to
C = ε₀ \frac{A}{d_1}
C = 8.85 10⁻¹² 9.30 10⁻⁴/9.60 10⁻³
C = 8.57 10⁻¹³ F
a) the potential difference
C =
since the capacitor is not discharged, let's look for the initial charge
Co = \frac{Q}{ \Delta V}
Q = C₀ ΔV
Q = 1.829 10⁻¹² 7.80
Q = 14.2662 10⁻¹² C
when the condensate plates are separated
C = \frac{Q}{ \Delta V' }
ΔV ’= Q / C
ΔV ’= 14.266 10⁻¹² / 8.57 10⁻¹³
ΔV ’= 1.66 10¹ V= 16.6 V
b) the stored energy is
U = ½ C ΔV²
for initial separation
U = ½ C₀ ΔV²
U = ½ 1.829 10⁻¹² 7.80²
U = 55.64 10⁻¹² J
c) The energy for end separation;
U_f = ½ C DV’2
U_f = ½ 8.57 10⁻¹³ 16,6²2
U_f = 1.18 10⁻¹⁰ J
d) The work
as there are no losses, the work is equal to the variation of the energy
W = ΔU = U_f -U₀
W = 1.18 10⁻¹⁰ - 55.64 10-12
W = 6.236 10⁻¹¹ J
How are the values of coefficient of kinetic friction and coefficient of static friction affected by the area of contact
Answer: Both static and kinetic coefficients of friction depend on the pair of surfaces in contact. Their values are determined experimentally. For a given pair of surfaces, the coefficient of static friction is larger than the kinetic friction. The coefficient of friction depends on the materials used.
Explanation:
the coefficient of static friction is larger than the kinetic friction.
Answer:
The coefficient of kinetic friction and the coefficient of static friction are both affected by the area of contact between two surfaces in contact. The following is a detailed explanation of how the values of these coefficients are affected by the area of contact.
The coefficient of kinetic friction is defined as the ratio of the force required to maintain a constant velocity between two surfaces in contact to the normal force pressing them together. It is a measure of the resistance to motion between two surfaces in contact. The coefficient of kinetic friction is affected by several factors, including the nature of the surfaces in contact, their roughness, and their temperature. However, the area of contact between two surfaces also plays a crucial role in determining the coefficient of kinetic friction.
The larger the area of contact between two surfaces, the greater the frictional force acting between them. This is because a larger area of contact means that there are more points of interaction between the two surfaces, which leads to a greater number of intermolecular forces acting between them. As a result, it becomes more difficult to maintain a constant velocity between two surfaces with a larger area of contact, and hence, the coefficient of kinetic friction increases.
On the other hand, the coefficient of static friction is defined as the ratio of the maximum force required to initiate motion between two surfaces in contact to the normal force pressing them together. It is a measure of the resistance to motion when an object is at rest on a surface. Like the coefficient of kinetic friction, it is also affected by several factors including surface roughness and temperature. However, unlike the coefficient of kinetic friction, it is not affected significantly by changes in area of contact.
This is because when an object is at rest on a surface, it does not matter how much area it covers on that surface. The maximum force required to initiate motion remains constant regardless of whether an object has a small or large area in contact with another surface. Therefore, changes in area of contact do not significantly affect the coefficient of static friction.
In a thermodynamic process, the internal energy of a system in a container with adiabatic walls decreases by 800 J. Which statement is correct
The correct statement is, the system performed 800 J of work on its surroundings.
The given parameters:
change in internal energy, ΔU = 800 JApply first law of thermodynamics;
ΔU = Q + W
where;
Q is the heat gainedW is the work done on the system by the surroundingIn adiabatic process no heat is gained or lost by the system.
Q = 0
ΔU = W (work is positive when it is done on the system by its surrounding)
If work is done by the system to the surrounding, the new equation becomes;
ΔU = - W
W = - ΔU
W = -800 J
This implies that the system performed 800 J of work on its surroundings.
"Your question is not complete, it seems to be missing the following information";
In a thermodynamic process, the internal energy of a system in a container with adiabatic walls decreases by 800 J. Which statement is correct?
a. The system lost 800 J by heat transfer to its surroundings.
b. The system gained 800 J by heat transfer from its surroundings.
c. The system performed 800 J of work on its surroundings.
d. The surroundings performed 800 J of work on the system.
e. The 800 J of work done by the system was equal to the 800 J of heat transferred to the system from its surroundings.
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what are some possible results of constructive forces on earth's surface
Answer:
what are the choices
Explanation:
Answer:
Landforms are a result of a combination of constructive and destructive forces. Collection and analysis of data indicates that constructive forces include crustal deformation, faulting, volcanic eruption and deposition of sediment, while destructive forces include weathering and erosion.
Explanation:
a sound has a wavelength of 0.52028. If the speed is 343.00m/s, what is the musical note?
I You are driving down the road at 15.6 m/s (35 mph) when an ambu-
lance passes you with its siren blaring. The ambulance siren produces
a frequency of 700 Hz. As the ambulance approaches you from be-
hind, you hear a frequency of 740 Hz. (a) What is the speed of the am-
bulance? (b) What frequency do you hear after the ambulance passes?
The speed of the ambulance is 33.35 m/s and the frequency heard after the ambulance passes is 667.07 Hz.
Calculation:-
V = f(344 - 15.6/344 - vs)
740 = 700(344 - 15.6/344 - vs)
344 - V s = 70/74 (344 - 15.6)
344 - V s = 310.64
V s = 33.35 m/s
After pass
F = 700 ( 344 + 15.6/344 + 33.35)
= 700 × 359.6/377.35
F = 667.07 Hz
Frequency is the wide variety of occurrences of a repeating event in line with a unit of time. The time period frequency refers to the variety of waves that pass a set factor in unit time. It additionally describes the number of cycles or vibrations undergone for the duration of one unit of time with the aid of a body in periodic motion.
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eporting results (1) Fifteen measurements of a resistance are quoted here based on approximately 10 repeat measurements. Only three of them obey the five golden rules. Identify the mistakes in the other results. (i) (99.8 ± 0.270) × 103 Ω, (ii) (100±0.3)× 103 Ω, (iii) (100.0±0.3)× 1039, (iv) (100.1 ±0.3) × 103, (v) 97.1 x 103-276Q, (vi) (99.8645 ± 0.2701) × 102 Ω, (vii) 98.6 x 103 ±3 × 10-Q,
The mistakes in the results include options (v) and (vii) which do not follow the five golden rules for reporting results.
What are the golden rules for reporting results?The five golden rules for reporting results are:
Always report the uncertainty in the measurement.Report the uncertainty to the same number of decimal places as the measured value.Use the correct units and prefixes.Avoid rounding until the final calculation.Report only the significant figures.Using these rules, identify the mistakes in the given results as:
(v) 97.1 × 10³ ± 276Ω - The uncertainty is reported to an inappropriate number of significant figures and the units are not consistent.
(vii) 98.6 × 10³ ± 3 × 10^(-Q) - The uncertainty is not reported to the same number of decimal places as the measured value, and the units are not consistent.
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What is the change in potential energy of a wood mass 2kg thrown up with a velocity of 12m/s and comes down ?
When the wood comes down the change in potential energy of mass 2 kg and velocity 12 m/s is 144 J.
When the object is thrown vertically upwards, the height increases. The potential energy also increases with respect to the height. The potential energy is maximum, and the kinetic energy is zero when the stone moves vertically upwards.
When the object comes down, the potential energy decreases and results in increasing in kinetic energy. When the stone comes down, the potential energy is converted to kinetic energy, and the change in potential energy results in kinetic energy.
From the given,
mass of the wood (m) = 2kg
the velocity of the wood (v) = 12 m/s
kinetic energy (K.E) = mv² / 2
= (2×12×12) / 2
= 144 J
Thus, the change in kinetic energy is 144 J.
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does cloud spins faster due to conservation of angular momentum. or gravitational potential energy is converted to kinetic energy.happen firsty
The rules of energy conservation and angular momentum conservation ensure that any rotating, collapsing cloud will finish up as a spinning disk.
What is momentum?Momentum is defined in Newtonian physics as the product of an object's mass and velocity. It is a vector quantity with magnitude and direction. Momentum is a measure of mass in motion: how much mass is involved in how much movement. It is commonly denoted by the sign p. Momentum is clearly defined as the measure of an object's kinetic energy. In layman's terms, momentum is the product of mass and velocity. Complete response: Simply said, momentum is concerned with the quantity of motion. It can also be referred to as the preserved quantity.
Here,
The laws of energy and angular momentum conservation guarantee that any rotating, collapsing cloud will end up as a spinning disk.
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Why do hurricanes develop over oceans?
Question 5 options:
The ocean is affected by the Coriolis effect.
The ocean winds blow from north to south.
The warmer ocean adds water vapor to the air mass.
The ocean currents cause air to move toward the land.
My guess is; The warmer ocean adds water vapor to the air mass.
I'm really sorry if I'm wrong
The warmer ocean adds water vapor to the air mads
Classes are canceled due to snow, so you take advantage of the extra time to conduct some physics experiments. You fasten a large toy rocket to the back of a sled and take the modified sled to a large, flat, snowy field. You ignite the rocket and observe that the sled accelerates from rest in the forward direction at a rate of 13.513.5 m/s2 for a time period of 3.103.10 s. After this time period, the rocket engine abruptly shuts off, and the sled subsequently undergoes a constant backward acceleration due to friction of 4.654.65 m/s2. After the rocket turns off, how much time does it take for the sled to come to a stop
Answer:
The value is \(t_1 = 9 \ s \)
Explanation:
Generally the velocity attained by the sled after t = 3.10 s is mathematically evaluated using the kinematic equation as follows
\(v = u + at\)
Here u = 0 \ m/s
a = 13.5 \(m/s^2\)
So
\(v = 0 + 13.5 * 3.10 \)
=> \(v = 41.85 \ m/s \)
The is distance it covers at this time is
\(s = u * t + \frac{1}{2} a * t^2\)
=> \(s = + \frac{1}{2} * 13.5 * 3.10^2\)
=> \(s =64.87 \)
Now when sled stops its the final velocity is \( v_f = 0 m/s \) while the initial velocity will be the velocity after its acceleration i.e \(v = 41.85 \ m/s \)
So
\(v_f = v + a_1t_1\)
Here \(a_1 = - 4.65\), the negative sign shows that it is deceleration
So
\(0 = 41.85 - 4.65 * t_1\)
=> \(t_1 = 9 \ s \)
For a different power plant the power input (not output) is 3570 MW. The coal has an energy content of 28,000 kJ per kg. How much coal must be put into the plant each day
Answer:
31475404.8 kg/day
Explanation:
From the information given:
The power plant capacity W = 3570 MW
Energy content of the coal = 28000 kJ/kg
let assume that the thermal efficiency = 35%
Recall that:
1 kw = 3600 kJ/hr provided that the energy conversion is 100% efficient
But assuming the thermal efficiency = 35%.
Then:
Heat input = 3600/0.35 = 10286 kJ/kw.hr
Now, for producing 1 kw.hr, the quantity of the required coal = 10286/28000
= 0.36736 kg
For 3570 MW, the amount of coal that must be input is:
= 0.36736 kg × 3570000
= 1311475.2 kg/hr
= 1311475.2 × 24 kg/day
= 31475404.8 kg/day
List three sources of energy being transferred by radiation.
Answer: light, gamma waves, radiowaves
Explanation:
Please see the attached image
The moment of inertia of the flat square is MA²/6
What is moment of inertia?The moment of inertia of a body is a property of the body which shows its ability to ritate about an axis.
What is the moment of inertia of the flat square?To find the moment of inertia of the flat square through its center of mass, we know that the moment of inertia of a rectangular slab is given by
I = M(a² + b²)/12 where
M = mass of slab and a and b = side lengthsNow, for a flat square a = b. so,its moment of inertia is I = M(a² + b²)/12
I = M(a² + a²)/12
= 2Ma²/12
= Ma²/6
Now for the given flat square, we have that
its mass equals M and its length equals A.So, substituting these into the equation of moment of inertia for the flat square, we have that
The moment of inertia of the flat square is given by
I = Ma²/6
I = MA²/6
So, moment of inertia is MA²/6
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a roller coaster weighs 2000 kg This ride includes an initial vertical drop of 59.3 m.
Assume that the roller coaster has a speed of nearly zero as it crests the top of the hill.
If the track was frictionless, find the speed of the roller coaster at the bottom of
the hill.
The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.
Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.
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1.
In the notation, 1s2, the number 1 represents the ________ __________ where electrons are located.
energy level
outer shell
2.
The four parts, or blocks, on the periodic table are _____, _____, d, and f.
s, p
a, b
3.
The 2 in 1s2 represents the number of __________ located in that energy level.
electrons
protons
Answer:
energy level
s,p
electrons
Explanation:
I already done this trust me
In the notation 1 s² number 1 represents energy levels where electrons are located.The 4 parts on periodic table are s,p,d and f blocks.The 2 in 1 s² represents number of electrons in energy level.
What is an energy level?Electrons present in an atom revolve in different orbits which are stationary states and are also called as energy levels. The energy levels are numbered as integers which are also called as principal quantum numbers.
Energy of the stationary state is given as E= -R
1/n² where R
is the Rydberg's constant. When an electron is excited, and it moves from lower to higher energy levels there is absorption of energy, while when it moves from higher energy level to lower energy level it radiates or gives out energy in the form of radiation.
They can also be defined as the distances between electron and nucleus of an atom . Electrons present in K energy level have least energy .Energy level diagrams are studied to understand nature of bonding , placement of electrons in orbits and and elemental behavior under certain conditions.
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You are interested in retrieving a souvenir from a shipwreck located 115 feet below the water. The path of your dive is modeled by the equation y = 0.05x2 - 4x - 38. Assuming you can hold your breath for the duration of the dive, will you be able to retrieve your souvenir? why?
In order to find out if we will be able to retrieve the souvenir, let's use y = -115 (negative because it's below the water) in the equation and calculate the value of x.
If there is at least one real solution, we will be able to retrieve the souvenir.
To solve this quadratic equation, let's use the quadratic formula:
\(\begin{gathered} y=0.05x^2-4x-38 \\ -115=0.05x^2-4x-38 \\ 0.05x^2-4x-38+115=0 \\ 0.05x^2-4x+77=0 \\ a=0.05,b=-4,c=77 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x_1=\frac{-(-4)+\sqrt[]{(-4)^2-4\cdot0.05\cdot77}_{}}{2\cdot0.05} \\ x_1=\frac{4+\sqrt[]{16-15.4}_{}}{0.1} \\ x_1=\frac{4+0.77}{0.1}=47.7 \\ x_2=\frac{4-0.77}{0.1}=32.3 \end{gathered}\)Since there are real solutions for x, the answer is YES.
Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.
A.)What is the amplitude of the wave ? Include correct units.
B.)Use the graph to determine the time of one wave. Use it to find the frequency.
C.)If the speed of the wave is 25 m/s, what is the wavelength of the wave ? Show data listing, equation , substitution leading to the answer for full credit.
(a) The amplitude of the wave is 0.2 m.
(b) The period of the wave is 4 s.
(c) The wavelength of the wave is 100 m.
What is the amplitude of the wave?(a) The amplitude of the wave is the maximum displacement of the wave.
amplitude of the wave = 0.2 m
(b) The period of the wave is the time taken for the wave to make one complete cycle.
period of the wave = 5.5 s - 1.5 s = 4 s
(c) The wavelength of the wave is calculated as follows;
λ = v / f
where;
v is the speed of the wavef is the frequency of the wavef = 1/t = 1 / 4s = 0.25 Hz
λ = ( 25 m/s ) / 0.25 Hz
λ = 100 m
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Saturday. More than On the next page, write two to three paragraphs on the unemployment rate in Detroit in 2010 and the long lasting effects. Write it as if you were explaining what you have learned about unemployment to another student who has no idea how unemployment rates are calculated or why they are significant. ● bus ● Discuss the official and alternative measures of unemployment in Detroit. Explain what the difference is and why it is important to look at both. Explain how unemployment is linked to the health of the entire economy, including businesses and government. Cite evidence from the Detroit News, and the Huffington Post (include information from the sources and be clear with the reader where you got the information). Give your opinion about how and why high unemployment might also impact crime rates and high school completion rates.
In my opinion, it is crucial to address high unemployment rates in order to support the overall health and well-being of the community.
What is unemployment?LeIn 2010, the city of Detroit had one of the highest unemployment rates in the country, with an official rate of 27.8%. This means that almost one-third of the city's workforce was unemployed and actively seeking work. The unemployment rate is calculated by dividing the number of unemployed people by the total number of people in the labor force, which includes those who are employed and those who are actively seeking employment.
However, the official unemployment rate does not take into account those who have given up looking for work or those who are underemployed (working part-time or in jobs that do not match their skill level). This is where alternative measures of unemployment come into play. The Bureau of Labor Statistics (BLS) calculates different measures of unemployment, including U-4, U-5, and U-6, which take into account these additional factors. In Detroit, the U-6 rate was estimated to be around 45% in 2010, which paints a more accurate picture of the true unemployment situation in the city.
High levels of unemployment have a significant impact on the economy, both locally and nationally. When people are unemployed, they have less money to spend, which leads to reduced demand for goods and services. This can in turn lead to business closures, job losses, and a further decline in the economy. Additionally, the government must spend more on social welfare programs to support those who are unemployed, which can strain the budget.
According to the Detroit News, the high unemployment rate in Detroit was linked to a decline in population and an increase in poverty rates. The Huffington Post reported that high unemployment rates can also lead to increased crime rates and lower high school completion rates. This is because unemployed individuals may turn to crime as a means of survival, and children of unemployed parents may struggle to stay in school due to financial pressures.
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On a hike you walk 5000 m east, 3000 m north and 1000 m west at a constant speed of 1m/s calculate your velocity
Answer:
0.44 EST + 0.33 NTH
Explanation:
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What is the density of the paint if the mass of a tin containing 5000 cm3 paint is 7 kg. If the mass of the empty tin, including the lid is 0.5 kg.
We are given:
Mass of the Paint bucket (with paint) = 7000 grams
Mass of the paint bucket (without paint) = 500 grams
Volume of Paint in the Bucket = 5000 cm³
Mass of Paint in the Bucket:
To get the mass of the paint in the bucket, we will subtract the mass of the bucket from the mass of the paint bucket (with paint)
Mass of Paint = Mass of Paint bucket (with paint) - Mass of the paint Bucket (without paint)
Mass of Paint = 7000 - 500
Mass of Paint = 6500 grams
Density of the Paint:
We know that density = Mass / Volume
Density of Paint = Mass of Paint / Volume occupied by Paint
Density of Paint = 6500/5000
Density of Paint = 1.3 grams / cm³
PART ONE
A student sits on a rotating stool holding two 5 kg objects. When his arms are extended horizontally, the objects are 0.7 m from the axis of rotation, and he rotates with angular speed of 0.75 rad/sec. The moment of inertia of the student plus the stool is 3 kg m² and is assumed to be constant. The student then pulls the objects horizontally to a radius 0.31 m from the rotation axis.
Calculate the final angular speed of the
student.
Answer in units of rad/s.
PART TWO
Calculate the change in kinetic energy of the system.
Answer in units of J.
Answer:
a) 1.05rad/s
b) 1.38J
Explanation:
need help ASAP. please and thank you
(a) If the maximum acceleration that is tolerable for passengers ina subway train is 1.34 m/s2 and subway stations arelocated 806m apart, what is the maximum speed a subway train canattain between stations? (b) What is the travel time betweenstations? (c) If a subway train stops for 20s at each station, whatis the maximum average speed of the train, from one start-up to thenext?
The maximum speed a subway train can attain between stations is 38.7 m/s. The travel time between stations is 20.8 seconds. The maximum average speed of the subway train is approximately 39.5 m/s.
To find the maximum speed a subway train can attain between stations, we can use the formula:
V² = U² + 2as
Where V is the final velocity, U is the initial velocity (assumed to be 0), a is the acceleration, and s is the distance between the stations.
V = √(2as)
V = √(2 × 1.34 m/s² × 806 m) = 38.7 m/s
Therefore, the maximum speed a subway train can attain between stations is approximately 38.7 m/s.
To find the travel time between stations, we can use the formula:
t = s / V
where t is the travel time, s is the distance between the stations, and V is the maximum speed attained by the subway train.
t = 806 m / 38.7 m/s
t = 20.8 s
Therefore, the travel time between stations is approximately 20.8 seconds.
To find the maximum average speed of the subway train, we can use the formula:
average speed = total distance / total time
In one round trip between two stations, the subway train covers a distance of 2s, because it travels from one station to the other and then back to the first station. Therefore, the total distance is 2 × 806 m = 1612 m
The subway train stops for 20 seconds at each station and the travel time between stations is 20.8 seconds, the total time for each trip between two stations would be 20.8 s + 20 s = 40.8 s
Then, the maximum average speed is:
average speed = total distance / total time
average speed = 1612 m / 40.8 s
average speed = 39.5 m/s
Therefore, the maximum average speed of the subway train, from one start-up to the next, is approximately 39.5 m/s.
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Tick the correct drills you can use to practise digging in volleybell a. double decker b. shuffle steps c. knock out drill 1. toss catch drill
The correct drills that can be used to practice digging in volleyball are b. shuffle steps and c. knock out drill.
b. Shuffle steps: Shuffle steps are an essential footwork drill for improving defensive movements, including digging.
In this drill, players shuffle laterally in a low defensive stance, simulating the movements required to dig a ball. It helps players develop quick and efficient footwork, enabling them to react and move quickly to reach the ball for a dig.
c. Knock out drill: The knock out drill focuses on improving a player's reaction time and defensive skills. In this drill, players form a line and take turns receiving rapid hits or "knocks" from a coach or teammate.
The objective is to successfully dig each hit and keep the ball in play.
This drill helps players develop their reflexes, positioning, and technique when digging in various directions and angles.
a. Double decker and 1. toss catch drill are not specific drills for practicing digging in volleyball. Double decker is a term used to describe a defensive formation, while the toss catch drill is more focused on developing ball control and setting skills rather than digging.
By incorporating shuffle steps and the knock out drill into practice sessions, players can enhance their digging abilities, improve their defensive movements, and develop the necessary skills to successfully retrieve hard-driven balls in a game situation.
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The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
Consider an object moving in the plane whose location at time t seconds is given by the parametric equations:
x(t)=4cos(?t)
y(t)=3sin(?t).
Assume the distance units in the plane are meters.
(a) The object is moving around an ellipse (as in the previous problem) with equation:
x^2/a^2 + y^2/b^2 = 1
where a= ______ and b= .___________
The object moves around an ellipse with values of a=4 and b=3.
The object is moving around an ellipse with the parametric equations:
x(t) = 4cos(?t) and y(t) = 3sin(?t).
To find the values of a and b, we can compare the parametric equations with the equation of the ellipse:
x²/a² + y²/b² = 1
We can see that the coefficient of cos(?t) in the parametric equation for x(t) corresponds to the value of 'a' in the equation of the ellipse, and the coefficient of sin(?t) in the parametric equation for y(t) corresponds to the value of 'b' in the equation of the ellipse.
Therefore, the values of a and b are:
a = 4 and b = 3
So the equation of the ellipse is:
x²/4² + y²/3² = 1
The object is moving around an ellipse with the equation:
x²/16 + y²/9 = 1
where a = 4 and b = 3.
Therefore, the object is moving around an ellipse with equation x²/a² + y²/b² where a=4 and b=3.
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How is Newtons second law apply to the egg drop ?
Answer:
Newton's Second Law is applied because of the acceleration caused by natural forces as the egg is plummeting to the earth. And the amount of acceleration the egg has will be largely affected by the amount of force Mr. Baker uses to hurl the egg to the ground.
Explanation:
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a heavy ball is hung with a string from the ceiling. another string is attached to the bottom of the ball. a downward pulling force is exerted on the lower string as shown in the figure below. which of the following statements is true? a. if the lower string is pulled suddenly by a large force, the upper string will break first. b. if the lower string is pulled suddenly by a large force, the lower string will break first. c. if the lower string is pulled suddenly by a large force, the two strings will break at the same time. d. if the lower string is pulled by a slowly increasing force, the lower string will break first. e. if the lower string is pulled by a slowly increasing force, none of the string will eventually break.
The tension will be greater on the upper string because the lower string will only support the pull while the upper string will support the weight of the ball. The upper string is therefore more likely to break as a result.
What is string tension?String tension, measured in pounds or kilograms, is the force holding the strings to the racket's frame. It's important to never just say a number to your stringer when describing your preferred unit measurement! However, the majority of stringers will assume that you mean pounds. For the majority of players, the ideal string tension falls between 48 and 54 lbs. More power is available with a looser (lower) tension, but better control is possible with a tighter tension. Beginners will likely want more control, so they might initially prefer a tighter tension.
Here,
Because the upper string will be supporting the weight of the ball while the lower string will only be supporting the pull, there will be more tension on the upper string. As a result, the upper string has a higher chance of breaking.
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Describe effective communication strategies for gathering information, educating patients
Explanation:
Effective communication with patients will enable one to know the needs of the patient better as well as reducing the barriers to understanding each other for both parties.
To be an effective communicator while educating patients, the person must:
It is important to establish good rapport with the patient. By so doing they can trust you and let you in. Show empathy. Do not make them feel like you are judging themUse proper body language. Make eye contacts and try to be on the same level as the patient so you can be face to face with them.make the interaction easier for them. You have to keep questions as well as your sentences short and moderate. Stay on topic and always make sure that concepts are clear to them.show respect. try not to speak with commands. Give the patient opportunity to make choices.be patient with them. Due to age or the nature of their illnesses, the patient may be slow in speech or movement. help them to move at their own pace by not rushing them.give them time to respond and ask questions. this will make communication more effective.you cause graphics where necessary or written instructions for the patient.