What two air masses creates hurricanes?

Answer:

We breath air for us to supply oxygens in terms of functioning the circulatory system because oxygen can be transported as blood. We breath air because it has many minerals in it.

Explanation:

Answer:

1. Distance travelled = 12 km.

2. Displacement = 8.6 km

Explanation:

From the question given above, the following data were obtained:

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance =?

Displacement =?

1. Determination of the distance travelled.

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance (dₜ) =?

dₜ = d₁ + d₂

dₜ = 7 + 5

dₜ = 12 km

2. Determination of the displacement.

In the attached photo, R is the displacement.

We can obtain the value of R by using the pythagoras theory as illustrated below:

R² = 7² + 5²

R² = 49 + 25

R² = 74

Take the square root of both side

R = √74

R = 8.6 km

At the end of the Electroweak era, matter and antimatter annihilate each other. Because of a small imbalance in the ratio, the universe is left with only matter.

The baryogenesis process refers to the hypothetical mechanism or mechanisms that generated the observed baryon asymmetry in the universe which refers to the fact that there is much more matter than antimatter

If the universe were perfectly symmetric between matter and antimatter the particles and antiparticles would have annihilated each other completely leaving behind only radiation.

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The potential difference across the each bulb and the current entering each bulb.

Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.

The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.

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Answer:

Some of the major figures of the Enlightenment included Cesare Beccaria, Denis Diderot, David Hume, Immanuel Kant, Gottfried Wilhelm Leibniz, John Locke, Montesquieu, Jean-Jacques Rousseau, Adam Smith, Hugo Grotius, Baruch Spinoza, and Voltaire.

Explanation:

hope this helps

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The efficiency of the steam engine is 78.9% because the rest of the work input is used to overcome friction.

Efficiency of a machine expresses the useful work done by a a machine as a percentage.

The efficiency of machines are always less than 100% percent due to energy losses due to friction and heat.

For the steam engine:

Work output = 225 J

Work input = 285 J

Efficiency = 225/285 × 100% = 78.9 %

Therefore, the efficiency of the steam engine is 78.9% because the rest of the work input is used to overcome friction.

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Explanation:

One way to save yourself and get to safety without any help on a frictionless frozen pond is to make use of the conservation of angular momentum. By spinning your body, you can create an angular momentum that can be used to propel yourself in the opposite direction.

To do this, you could start by extending your arms and legs outwards and then tucking them in towards your body. This will cause your body to start spinning in the opposite direction. By changing the position of your arms and legs, you can control the speed and direction of your spin.

As you spin, you can gradually increase the speed of your spin by tucking your arms and legs in closer to your body. This will cause your body to spin faster and faster, generating a larger angular momentum.

Once you have built up enough angular momentum, you can then extend your arms and legs outwards again to slow down and stop your spin. At this point, your body will be moving in the opposite direction to your initial spin, allowing you to glide across the ice without any external force.

By repeating this process, you can continue to generate angular momentum and propel yourself in the opposite direction until you reach safety. It may take some practice to master this technique, but with enough determination and persistence, it is possible to save yourself and get to safety without any help on a frictionless frozen pond.

Answer:

by using gravity to push off the floor

Explanation:

or by using ur own body heat to melt some of the ice around u

Answer:

Slowing down

Explanation:

Carlos is travelling to the right as indicated by his velocity, so his velocity is +5m/s. He is also accelerating to the left which is the opposite direction to his velocity so his acceleration is -1.2m/s2 to the right.

Since his acceleration is negative relative to his velocity and direction of motion, his speed is decreasing and he is slowing down.

Hope this helped!

Answer:

Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice

Explanation:

Answer:

a) 1 m/s²

b) -1 m/s²

c) 0 m/s² (constant speed, not accelerating)

Explanation:

A

delta speed = 10 - 0

delta time = 10 - 0

delta speed / delta time = 10/10

delta speed / delta time = 1

B

ds = 5 - 10

dt = 15 - 10

ds / dt = -5 / 5

ds / dt = -1

C

ds = 5 - 5

dt = 25 - 15

ds / dt = 0 / 10

ds / dt = 0

The average acceleration of A, B, and C will be 1 m/s², -1 m/s², and 0 m/s².

An object is considered to have been accelerated if its velocity changes. Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change. Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign. These examples demonstrate how acceleration occurs whenever a moving object modifies its direction, speed, or both.

There are different types of acceleration :

Average acceleration is defined as the average change in velocity with respect to the average change in time.

SI unit is m/s² and it is vector quantity.

According to the question,

For A, Acceleration= (v₁-v₀)/(t₁-t₀)

⇒10-0/10-0

= 1 m/s².

For B, Acceleration= (v₃-v₂)/(t₃-t₂)

⇒5-10/15-10

= -1 m/s²

For C, Acceleration will be constant because change in velocity is constant, this is the case of uniform motion, so its acceleration is also going to be constant (as per the definition of acceleration change in velocity ratio change in time).

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Answer:

Cannot say for sure which is ball 1 and ball 2 since the information on where the friends were was not specified but, one ball speed is 9 m/s and the other is 19 m/s.

Explanation:

Relative to the girl running at 5 m/s they were going 14 m/s but that could be that is was going 9 m/s towards her from the front so the combined speed is 14 m/s or that it is coming at her from behind at 19 m/s so the combined speed is once again 14 m/s.

(1) According to her friends, ball 1 was thrown with a speed of 19 m/s.(2) According to her friends, ball 2 was thrown with a speed of 19 m/s.

Given:

Anita's velocity = 5 m/s (to the right)

Apparent velocity of both balls = 14 m/s (toward Anita)

For ball 1:

Apparent velocity of ball 1 = 14 m/s

Using the concept of relative velocity:

Apparent velocity of ball 1 = Velocity of ball 1 - Anita's velocity

14  = Velocity of ball 1 - 5

Velocity of ball 1 = 14  + 5  = 19 m/s

So, according to her friends, ball 1 was thrown with a speed of 19 m/s.

(2) For ball 2:

Apparent velocity of ball 2 = 14 m/s

Using the same concept of relative velocity:

Apparent velocity of ball 2 = Velocity of ball 2 - Anita's velocity

14 = Velocity of ball 2 - 5 m/s

Velocity of ball 2 = 14  + 5 = 19 m/s

So, according to her friends, ball 2 was thrown with a speed of 19 m/s as well.

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Answer:

heat and sound.

Explanation:

Though some would argue that the heat is not useful. I guess it depends on if your hands are cold.

Based on the information, useful energy is transferred away from the MP3 player by light, heat, and sound.

It should be noted that energy transfer can be mechanically, electrically, by radiation, and by heating.

Energy can be transferred through force, an electrical current, light waves, sound waves, and heat. Based on the diagram, the useful energy is transferred away from the MP3 player by light, heat, and sound.

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The stone is travelling in a straight line can not be true in a vertical circle at a radius.

What is vertical circle?
A vertical circle is a path that follows a vertical line in a three-dimensional space. It is a type of circular trajectory, with the center point of the circle vertically above or below the starting and ending points of the path. Vertical circles are used in mathematics and engineering to describe the motion of objects in space. The path of a vertical circle is a helix, which is a spiral with a constant radius, and can be defined by a parametric equation. Vertical circles can be used to define the motion of a satellite, or an aircraft in a corkscrew maneuver. In terms of physics, a vertical circle is an example of a non-uniform circular motion, as the speed of the object changes throughout the path.

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Complete Question

a stone is tied to a string and whirled in a vertical circle at a radius. which of the following cannot be true?

A) The stone is travelling in a straight line

B) The stone is travelling in a circular path

C) The stone is travelling at a constant speed

D) The stone is travelling in an elliptical path

Two factors that determine the amount of electricity that can be generated by an individual hydroelectric power plants - It depends on the vertical distance through which the water falls and the flow rate, or amount of water that flows past a certain point per unit time, The greater the distance that the water falls, the more potential energy it had and the more electricity is generated the more kinetic energy it has and the more .

Impoundment, diversion, and pumped storage facilities are the three different types of hydroelectric facilities. Hydropower plants vary in their utilisation of dams. Despite the fact that not all dams were constructed for hydropower, they have been successful in supplying vast amounts of renewable energy to the grid. As of 2020, fewer than 2,300 of the more than 90,000 dams in the United States were producing electricity. The other dams are utilised for water supply, irrigation, flood control, stock/farm ponds, and recreation. Hydropower facilities come in a variety of sizes, from modest initiatives providing electricity for a single house or community to massive undertakings. 

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Answer:

Acceleration = Δv/Δt or change in velocity over change in time

Explanation:

Answer:

Mechanical waves are waves that require a medium. This means that they have to have some sort of matter to travel through. These waves travel when molecules in the medium collide with each other passing on energy. One example of a mechanical wave is sound.

Answer:

The objects kinetic energy increases as it falls from some height.

1 Therefore, the kinetic frictional force experienced by the block on the incline is 6.784 N.

2 The magnitude of the velocity of the block at point B is approximately 5.11 m/s.

1. The formula for the kinetic frictional force is given by f = μN, where μ is the coefficient of kinetic friction and N is the normal force. Since the block is on an incline, the normal force can be calculated as N = mg * cos(θ), where θ is the angle of inclination.

N = 4 kg * 9.8 m/s² * cos(30°) = 33.92 N

f = 0.2 * 33.92 N

= 6.784 N

2. Potential energy at point A = mgh, where h is the vertical height of the incline.

Potential energy at point A = 4 kg * 9.8 m/s² * 3 m * sin(30°)

= 58.8 J

The work done by friction is given by W = f * d, where d is the distance traveled along the incline (3 m).

Work done by friction = 6.784 N * 3 m = 20.352 J

Since the work done by friction is negative (opposite to the direction of motion), the total work done on the block is:

Total work = Potential energy at A - Work done by friction

Total work = 58.8 J - 20.352 J = 38.448 J

According to the work-energy theorem, this work done on the block is equal to the change in its kinetic energy. Therefore, we have:

38.448 J = 0.5 * 4 kg * B²

Solving for B, we find:

B = √(38.448 J / (0.5 * 4 kg)) ≈ 5.11 m/s

Therefore, the magnitude of the velocity of the block at point B is approximately 5.11 m/s.

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The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

Answer: 250

Explanation:

If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

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Answer:

chemical change in paint

Answer:

C

Explanation:

Black paint absorbs more sun light than tan. This light energy is then converted to thermal energy and it heats up the pool.

If a 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Then the total work done by the force is equal to π/2 + 1.

To calculate the total work done by the force in this scenario, we can use the formula for work:

Work = ∫F(x) dx

where F(x) is the force as a function of position and dx represents an infinitesimal displacement.

In this case, the force is given by F(x) = √(1 - x²), and we need to find the total work done as the object moves from xo = -1 to xf = 1.

Let's break down the calculation step by step:

Write the integral for work:

Work = ∫F(x) dx

Substitute the given force:

Work = ∫√(1 - x²) dx

Integrate with respect to x:

To integrate the square root of (1 - x²), we use the trigonometric substitution. Let's substitute x = sin(θ) and dx = cos(θ) dθ.

Work = ∫√(1 - sin²(θ)) cos(θ) dθ

Simplify the integrand:

Using the trigonometric identity sin²(θ) + cos²(θ) = 1, we can rewrite the integrand as cos²(θ).

Work = ∫cos²(θ) dθ

Apply the power-reducing formula:

The power-reducing formula states that cos²(θ) = (1 + cos(2θ)) / 2. We can use this formula to simplify the integrand further.

Work = ∫(1 + cos(2θ))/2 dθ

Integrate the terms separately:

Work = (1/2) ∫dθ + (1/2) ∫cos(2θ) dθ

The first integral, ∫dθ, is simply θ, and the second integral, ∫cos(2θ) dθ, can be calculated as sin(2θ)/2.

Work = (1/2) θ + (1/2) (sin(2θ)/2) + C

Evaluate the integral limits:

To find the total work done, we need to evaluate the integral at the upper and lower limits of integration.

At xf = 1, the angle θ is π/2, and at xo = -1, the angle θ is -π/2.

Work = (1/2) (π/2) + (1/2) (sin(2(π/2))/2) - [(1/2) (-π/2) + (1/2) (sin(2(-π/2))/2)]

Simplifying further:

Work = π/4 + (1/2) - (-π/4 + (1/2))

Work = π/4 + 1/2 + π/4 + 1/2

Work = π/2 + 1

Therefore, the total work done by the force is equal to π/2 + 1.

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Answer:

yes it is possible

Explanation:

if the body is travelling with uniform speed in a circular track its speed remains the same but the velocity is non-uniform as the direction of the body is changing every time.

eg: a body in uniform circular motion has constant speed but its velocity changes at every point during the course of motion. Whenever, the direction changes, velcoity changes.

A. The average speed you can use to pull the safe is 1.02 m/s

B. The time needed to pull the safe up is 17.65 s

First, we shall obtain the force. This is shown below:

F = mg

F = 60 × 9.8

F = 588 N

Finally, we shall obtain the average speed. Details below:

Power = force × average speed

600 = 588 × average speed

Divide both sides by 588

Average speed = 600 / 588

Average speed = 1.02 m/s

The time needed to pull the safe up can be obtained as follow:

Time = Total distance / average speed

Time = 18 / 1.02

Time = 17.65 s

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Complete question:

You know you can provide 600 W

of power to move large objects. You need to move a 60-kg

safe up to a storage loft, 18 m

above the floor.

Part A

With what average speed can you pull the safe straight up?

Part B

What is the time needed to pull the safe up?

Answer:

Because the half-life is as long as Earth has existed, virtually all rocks on Earth still have most of their uranium-238. So, measurements can easily be obtained.

Explanation:

exact answer from pluto/ edmentum

The significant part of the chemical composition of rocks is uranium. The half -life of uranium is close to the age of earth. Hence, by measuring the uranium content in rocks we can predict its age.

Uranium is 92nd element in periodic table. It is an actinide element. All the actinides are radioactive in which the most common is uranium. They all undergo radioactive decay process. Radioactive decay is a first order reaction. The rate constant K can be written as:

k = 1/t ln (W0/Wt)

where t is the tome of decay, W0 be the initial amount and Wt is the amount after time t.

here k = 0.693/t1/2

By this relation we can find t the age of a substance, if know the amounts and half life t1/2. Uranium is present in rocks and minerals. Uranium undergo nuclear decay and will forms its isotopes or new products.

Thus, by measuring the current amount of uranium in rocks by knowing the half life of uranium we can predict the age of rocks.

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The type of decay that has no charge associated with it is gamma decay (option C).

Gamma decay is a nuclear reaction with the emission of a gamma ray. A gamma ray is a high frequency/energy electromagnetic radiation emitted as a consequence of radioactivity.

Gamma rays are waves, not particles. This means that they have no mass and no charge.

This, therefore, suggests that when a gamma ray is emitted, no charge is involved.

Unlike alpha and beta decay that involves +2 and -1 charges respectively.

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The speed of player B before they collide is 2.75 m/s

Momentum is defined as the product of mass and velocity. It is expressed as

Momentum = mass × velocity

This is defined as the change in momentum of an object.

Impulse = change in momentum

Impulse = final moment – Initial momentum

Since net momentum after the collision is 0 Ns, it means that:

Momentum of A = Momentum of B

With the above, idea, we can obtain the speed of player B as illustrated below:

Momentum of A = Momentum of B

105 × 3.3 = 126 × speed of B

346.5 = 126 × speed of B

Divide both sides by 126

Speed of B = 346.5 / 126

Speed of B = 2.75 m/s

Thus, the speed of player B before the collision is 2.75 m/s

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Answer:

Explanation:

Matter can be broken down into two categories: pure substances and mixtures. Pure substances are further broken down into elements and compounds. Mixtures are physically combined structures that can be separated into their original components. A chemical substance is composed of one type of atom or molecule.