What terms of this expression -3x + 2y - 6 +13x - 6y


helppppp​

The domain and the range of the function are (-∝, ∝) and (0, ∝), respectively

From the question, we have the following parameters that can be used in our computation:

The graph

The above graph is an exponential function

The rule of an function is that

The domain is the set of all real values

In this case, the domain is (-∝, ∝)

For the range, we have

Range = (0, ∝)

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Answer:

I know B is correct. I don't know about the others

Answer:

18

Step-by-step explanation:

0.5(w) + 3x

0.5(6) + 3(5)

= 18

Answer:

the factored form of the expression is (sqrt(2)x + 3)(sqrt(2)x - 3).

Step-by-step explanation:

The expression 2x^2 - 9 can be factored using the difference of squares formula. The formula states that a^2 - b^2 can be factored as (a + b)(a - b).

In this case, the expression 2x^2 - 9 can be rewritten as (sqrt(2)x)^2 - 3^2. Now we can see that it follows the pattern of the difference of squares.

Therefore, we can factor 2x^2 - 9 as follows:

2x^2 - 9 = (sqrt(2)x + 3)(sqrt(2)x - 3)

So the factored form of the expression is (sqrt(2)x + 3)(sqrt(2)x - 3).

Answer:

60 dollars a week.

Step-by-step explanation:

Just take 15 percent of 400, then you get your answer

The mean-square end-to-end distance for the fractal line is ⟨R2⟩ = b².L^(1-D).

The mean-square end-to-end distance for the fractal line is as follows.⟨R2⟩ = ⟨(R(u)- R(v))^2⟩ for u = 0 and v = L where L is the length of the line.⟨R2⟩ = b²/L^2.D.L = b².L^(1-D).

Thus, the mean-square end-to-end distance for the fractal line is ⟨R2⟩ = b².L^(1-D).

The radius of gyration Rg is defined as follows.

Rg² = (1/N)∑_(i=1)^N▒〖(R(i)-R(mean))〗²where N is the number of monomers in the fractal line and R(i) is the position vector of the ith monomer.

R(mean) is the mean position vector of all monomers.

Since the fractal dimension is D, the number of monomers varies with the length of the line as follows.N ~ L^(D).

Therefore, the radius of gyration for the fractal line is Rg² = (1/L^D)∫_0^L▒〖(b/v^(1-D))^2 v dv〗 = b²/L^2.D(1-D). Thus, Rg² = b².L^(2-D).

The ratio R²/Rg² is given by R²/Rg² = L^(D-2).

When D = 1, R²/Rg² = 1/L. When D = 1.7, R²/Rg² = 1/L^0.7. When D = 2, R²/Rg² = 1/L.

This provides information on mean-square end-to-end distance and radius of gyration for fractal line with a given fractal dimension.

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Answer:

$14.90625

Step-by-step explanation:

Using the conversion rate

$1 = 0.8 pounds

If you buy 2.6 pounds of apples and 1.475 pounds of peaches, the total cost of apple and peaches is expressed as:

= 2.6 pounds + 1.475 pounds

= 4.075 pounds

Convert to dollars

$1 = 0.8 pounds

$x = 4.075 pounds

cross multiply

0.8x = 4.075

x = 4.075/0.8

x = $5.09375

This means that the cost of the apple and peaches is $5.09375.

If you hand the cashier a $20 bill, the change that you will receive will be: $20 - $5.09375 = $14.90625

Answer:

165

Step-by-step explanation:

first 1% of 500 is calculated and then multiplied by 33:

\(\frac{1}{100} (500)=5\)

5(33)=165

Hope this helps

To test if there is evidence that those who exercise regularly have lower resting heart rates, we can use a two-sample t-test.

Let's denote the population 1 (exercise regularly) as group 1 and population 2 (does not exercise) as group 2. We set up the following hypotheses:

Null hypothesis (H 0): The mean resting heart rate of population 1 is equal to the mean resting heart rate of population 2.

Alternative hypothesis (H 1): The mean resting heart rate of population 1 is lower than the mean resting heart rate of population 2.

Using the data provided, we calculate the sample means and sample standard deviations for each group. Group 1 has a mean of 67.71 and a standard deviation of 4.09, while Group 2 has a mean of 74.88 and a standard deviation of 3.49.

Next, we calculate the test statistic using the formula:

t = (X1 - X2) / √((s1² / n1) + (s2² / n2))

where X1 and X2 are the sample means, s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.

Plugging in the values, we get t ≈ -1.255405.

To determine the p-value, we compare the test statistic to the t-distribution with degrees of freedom equal to the smaller of (n1 - 1) and (n2 - 1). In this case, both groups have 7 observations, so the degrees of freedom is 6.

Using a t-table or statistical software, we find that the p-value is approximately 0.2274.

Comparing the p-value to the significance level of 0.07, we see that the p-value is greater than the significance level. Therefore, we fail to reject the null hypothesis.

In conclusion, based on the data and the hypothesis test, there is insufficient evidence to conclude that those who exercise regularly have lower resting heart rates at the 0.07 level of significance.

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Therefore , the solution of the given problem of variable comes out to be because a function's domain is all possible input values, not possible outcome values, b is not true.

A trait that can be measured and have different values is called a variable. A few instances of variables include height, age, salary, birthplace province,equation , academic standing, and type of residence.

Here,

A. Although all relations are functions, not all functions are relations.

c. Each input value will only have one output value if a connection is a function.

d. At least one input will have more than one exit value if a relation is not a function.

e. The input and result of a function are independent and dependent variables, respectively.

Because a function's domain is all possible input values, not possible outcome values, b is not true.

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We have the next system of equations

y=-5 ....(1)

y=4x+19​ ...(2)

we substitute the first equation into the second equation and we have

-5=4x+19

then we clear x

-4x=19+5

-4x=24

x=24/-4

x=-6

the solution is

x=-6

y=-5

Answer - 158.75

Explain - The answer is 158.75 because 125 x 1.27 = 158.75

Hope this helps. Please give brainliest. I would really appreciate it :)

The probability that student chosen at random is 16 years is 0.28.

The table shows the distribution of student by age in a high school with 1500 students. Therefore, the probability that randomly chosen student is  16 years can be found as follows:

Therefore,

probability = number of favourable outcome to age / total number of possible outcome

Hence,

probability that student chosen at random is 16 years =  420 / 150

probability that student chosen at random is 16 years = 0.28

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The volume of the cylinder with a base radius 3 and height 8 is 72π cubic units.

This question is incomplete, the complete question is:

What is the volume of a cylinder with base radius 3 and height 8?

Either enter an exact answer in terms of π or use 3.14 for π and enter your answer as a decimal.

A cylinder is simply a 3-dimensional shape having two parallel circular bases joined by a curved surface.

The volume of a cylinder is expressed as;

V = π × r² × h

Where r is radius of the circular base, h is height and π is constant pi.

Given that:

Radius r = 3 units

Height h = 8 units

Volume V = ?

Plug the values into the above formula and solve for V.

V = π × r² × h

V = π × 3² × 8

V = 72π cubic units.

Therefore, the volume is 72π cubic units.

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Every quadratic nonresidue of p is a primitive root of p, when p = 2^k + 1 is primeIf p = 2^k + 1 is a prime number, we want to show that every quadratic nonresidue of p is a primitive root of p.

In other words, we aim to prove that if an element x is a quadratic nonresidue modulo p, then it is also a primitive root of p.

Let's assume p = 2^k + 1 is a prime number. To prove that every quadratic nonresidue of p is a primitive root of p, we can use the properties of quadratic residues and quadratic nonresidues.

A quadratic residue modulo p is an element y such that y^((p-1)/2) ≡ 1 (mod p), while a quadratic nonresidue is an element x such that x^((p-1)/2) ≡ -1 (mod p).

Now, let's consider an element x that is a quadratic nonresidue modulo p. We want to show that x is a primitive root of p.

Since x is a quadratic nonresidue, we know that x^((p-1)/2) ≡ -1 (mod p). By Euler's criterion, this implies that x^((p-1)/2) ≡ -1^((p-1)/2) ≡ -1^2 ≡ 1 (mod p).

Since x^((p-1)/2) ≡ 1 (mod p), we can conclude that the order of x modulo p is at least (p-1)/2. However, since p = 2^k + 1 is a prime, the order of x modulo p must be equal to (p-1)/2.

By definition, a primitive root of p has an order of (p-1). Since the order of x modulo p is (p-1)/2, it follows that x is a primitive root of p.

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Answer:

a = 138

Step-by-step explanation:

Notice that from the figure, we can see that ∠MOQ and ∠PON are vertical angles, which means that by definition, they're congruent in measure.

∠MOQ = ∠MOR + ∠ROQ = 90 + 48 = 138°

So, this means that ∠PON is also equal to 138, which means a = 138.

Thus, the answer is a = 138.

~ an aesthetics lover

Answer:

a. 2.5 miles an hour

b. yes, she will get there before 11 am since she could walk 5 miles in 2 hours if she wanted.

Step-by-step explanation:

Answer:Its domain is all real numbers. Its range is all real numbers greater than or equal to zero. Its graph lies completely above the x-axis.

Answer:

number 1 is 0.83333333333

Step-by-step explanation:

Answer: 1. 0.83 or fraction: 5/6

2. 0.83 or fraction: 5/6

3. 1.6 or as a fraction: 1 and 3/5 or improper: 8/5

4. 0.6 or as a fraction: 3/5

Hope this helps! :)

Answer:

y = 1/4x + 17/4

Step-by-step explanation:

first lets umm find the slope

use points that you can um clearly see ?

(4, 6) and (8, 7)

so use the equation y2 - y1/ x2 - x1

soooo

7 - 6/ 8 - 4

1 / 4

so it looks like:

y = 1/4x + b

so far

now we have to find the y-intercept with a point we did not use yet

but i have a little trouble so ill try my best to estimate a point

(2, 5)

we substitue

5 = 1/4(3) + b

5 = 3/4 + b

b = 5 - 3/4

b = 17/4

i want to check but its hard looking for exact points. i think this is the answer hope this helps!

Answer:

The width is 72

Step-by-step explanation:

Answer:

Rosie is 10 years old

Step-by-step explanation:

A)

Rosie is x years old

Rosie's age (R) = x

R = x

Eva is 2 years older

Eva's age (E) = x + 2

E = x + 2

Jack is twice Rosie’s age

Jack's age (J) = 2x

J = 2x

B)

R + E + J = 42

x + (x + 2) + (2x) = 42

x + x + 2 + 2x = 42

4x + 2 = 42

4x = 42 - 2

4x = 40

\(x = \frac{40}{4} \\\\x = 10\)

Rosie is 10 years old

Answer:

1.15

2.1

3.3

45

5.3

6.8

7.4

8.5

9. 24

Step-by-step explanation:

Answer:

1. 15

2. 1

3. 3

4.  2.5

5. 3

6. 8

7. 4

8. 5

9. 24

10. 6

11. 3

12. 52

13. 44

14. 38

15. 24

16. 12

17. 2

18. 12

Step-by-step explanation:

Answer:

54, 78, 70, 47, 80, 81,

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

12- 8x = 4x -12

-12              -12

-8x=4x -24

-4x   -4x

-12x=-12

___  ___

-12    -12

x=1

Answer:

#1: $36.94

#2: 4.9 continuous

#3?

#4 $18

#5 64in squared

Step-by-step explanation:

#1 2x9.95+19.9

$19.90+$14.95=34.85

6% of 34.85=2.09

$34.85+$2.09=

$36.94

#4 8 yards = 24 feet

432/24=

18

#5 4x2=8

8x8=64

remember to make sure it is squared because it is area

An approach of assigning probabilities which assumes that all outcomes of the experiment are equally likely is referred to as the "equally likely" or "classical" probability approach

The equally likely or classical probability approach assumes that each possible outcome of an experiment is equally likely to occur. This approach is based on the principle of symmetry and assumes that there is no inherent bias or preference towards any particular outcome

This approach is used for situations where there is no inherent bias or preference towards any particular outcome, and each outcome is considered equally likely to occur.

Therefore, the approach is classical probability approach

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Answer:

A

Step-by-step explanation:

because he is rich

Therefore, the equation x^3 - 15x + c = 0 has at most one root in the interval (-2, 2).

To show that the equation x^3 - 15x + c = 0 has at most one root in the interval (-2, 2), we can use the concept of the Intermediate Value Theorem and Rolle's Theorem.

Let's assume that the equation has two distinct roots, denoted as a and b, in the interval (-2, 2). Without loss of generality, we assume a < b.

Since the function is continuous on the closed interval [-2, 2] and differentiable on the open interval (-2, 2), we can apply Rolle's Theorem. According to Rolle's Theorem, there exists a point c in the open interval (a, b) such that the derivative of the function at c is zero.

Consider the derivative of the function f(x) = x^3 - 15x + c:

f'(x) = 3x^2 - 15

Setting f'(c) = 0, we have:

3c^2 - 15 = 0

c^2 - 5 = 0

c^2 = 5

Taking the square root of both sides, we get:

c = ±√5

Now, let's consider the function values at the endpoints of the interval (-2, 2):

f(-2) = (-2)^3 - 15(-2) + c = -8 + 30 + c = 22 + c

f(2) = (2)^3 - 15(2) + c = 8 - 30 + c = -22 + c

If c = √5, then f(-2) = 22 + √5 and f(2) = -22 + √5.

If c = -√5, then f(-2) = 22 - √5 and f(2) = -22 - √5.

In either case, the function values at the endpoints have different signs. This implies that there exists at least one value, say k, in the interval (-2, 2) such that f(k) = 0, according to the Intermediate Value Theorem.

However, we assumed at the beginning that there are two distinct roots in the interval (-2, 2), denoted as a and b. This contradicts our finding that there is at most one root in the interval. Hence, our assumption of having two distinct roots is false.

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