what structural units make up iconic solids

Answer:

I think the answer is A

Explanation:

the temperature of solids , liquids and gases can be easily measured

Balance the half-reactions to guarantee that the number of electrons transferred in both reactions is the same:

NO3- + 8H+ + 10e- N2 + 4H2O H2 2H+ + 2e- NO3- + 8H+ + 10e-

The next step is to figure out how many electrons are moved when 145 molecules of H2 are oxidized. We can see from the balanced equation for the H2 half-reaction that 1 molecule of H2 makes 2 electrons:

2H+ + 2e- → H2

As a result, 145 molecules of H2 will yield:

145 molecular units H2 has two protons per molecule. 290 electrons Equals H2

Finally, we can use the denitrification reaction balanced equation to calculate how many molecules of N2 are created for 290 electrons:

1 molecule of N2 is produced by 10 electrons.

Therefore, 1 molecule N2 290 electrons/10 electrons = 29 molecules N2

29 molecules of N2 gas will be created.

To answer the second query, we must balance the half-reactions:

SO42- + 8H+ + 8e- H2S + 4H2O CO2 + 8H+ + 8e- CH3COO- + 2H2O SO42- + 8H+ + 8e- H2S + 4H2O

The balanced formulae show that 8 electrons are transferred in both half-reactions. As a result, in order to oxidize 48 molecules of CH3COO-, 6 molecules of SO42- must be reduced:

There are 48 nuclei CH3COO- 8 electrons per atom 384 protons = CH3CO-

384 electrons (eight electrons per atom) 48 units of SO42- SO42-

As a result, 48 molecules of CH3COO- reduced to CO2 will yield:

six electrons 4 H2O/molecule SO42- 24 units of SO42- H2O

The answer is that 24 molecules of water will be created.

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The cardboard sleeves reduce the heatness from the coffee cup. So then the cosumer does not get a burn.

Answer:

Extreme heat

Explanation:

Because when matter is heated up The molecules move faster.

Answer:

I think it's extreme heat

Sodium carbonate, often referred to as Na2CO3, is a chemical compound composed of atoms of sodium (Na), carbon (C) and oxygen (O).

It is also sometimes called washing soda or soda ash. At room temperature, sodium carbonate is a white, crystalline solid that is very soluble in water. According to the chemical formula of the sodium carbonate molecule, Na2CO3, each molecule consists of two sodium atoms (Na), one carbon atom (C) and three oxygen atoms (O). The atomic configuration in sodium carbonate is shown in the given diagram.

A trigonal planar arrangement is formed when the central carbon atom is bonded to three oxygen atoms. The structure of sodium carbonate is completed by two sodium atoms joined to oxygen atoms.

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The heat of reaction is -334.4 J.

Heat of reaction of AgCl is -66.88KJ/mol.

Precipitation of silver chloride is an exothermic process

Calculation:

We can calculate the heat using Calorimeter.

Formula of calorimeter is,

q = c.m.ΔT

Where,

q= heat of reaction, c= specific heat capacity

Now, mass of solution= 100g

ΔT = T2 - T1

Initial temperature (T1) = 22.60°c

Final temperature (T2) = 23.40°c

ΔT = 23.40°c - 22.60°C = 0.80°c

Now put all the value in the formula of calorimeter

q= c.m.ΔT

q= (4.18J/°c.g) × 100g × 0.80°c

q= 334.4 J

Heat will be released as the solution will get warmer

So, Heat of the reaction = -334.4 J

Let's consider the reaction between AgN\(O_{3}\)  and CaC\(l_{2}\)

2 AgN\(O_{3}\) (aq) + CaC\(l_{2}\)(aq) ⇄ 2AgCl + Ca(N\(O_{3}\)\()_{2}\)

From this equation we get,

2 moles of  AgN\(O_{3}\) produce 2 moles of AgCl

Means, 1 mole AgN\(O_{3}\)  gives 1 mole AgCl.

So, the mole of AgN\(O_{3}\) in solution,

AgN\(O_{3}\); n= molarity of  AgN\(O_{3}\) × volume of  AgN\(O_{3}\) in litres

= 0.100 mol/L × 0.0500 L

= 0.0050 mol

This is mole of  AgN\(O_{3}\) in solution = moles of AgCl formed = 0.0050 mol

To get heat of reaction in moles,

q= \(\frac{-334.4J}{0.0050 mol}\)

q = -66880 J/mol

q= -66.88KJ/mol

The heat of reaction for the AgCl formed

= -66.88KJ/mol

Precipitation of silver chloride is an exothermic process since the heat is released in this case.

What is an exothermic reaction?

The part of a solution that transforms into a different state while creating the solution or the part that isn't overly abundant; the substance that dissolves in another material.

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Answer:

Protons, neutrons, and electrons

Explanation:

Both protons and neutrons have a mass of 1 amu and are found in the nucleus. However, protons have a charge of +1, and neutrons are uncharged. Electrons have a mass of approximately 0 amu, orbit the nucleus, and have a charge of -1.

Answer:

1) 0 C2H4O2 + 0 O2 -> 0 CO2 + 0 H2O (balanced)

2) V2O5 + CaS -> CaO + V2S5

just additional info: V2O5 is divanadium pentaoxide

LHS (Left hand side)

V: 2

O: 5

Ca: 1

S: 1 x 5 [to balance with the right hand side of the equation]

RHS (Right hand side)

V: 2

O: 1 x 5 [to balance with the left hand side of the equation]

Ca: 1

S: 5

When you balance any elements, you have to balance the whole chemical compound.

Thus,

V2O5 + 5 CaS -> 5 CaO + V2S5

LHS CHECK:

V: 2

O: 5

Ca: 5

S: 5

RHS CHECK:

V: 2

O: 5

Ca: 5

S: 5

3) S8 + O2 -> SO2

LHS:

S: 8

O: 2

RHS:

S: 1 x 8 [to balance with LHS]

O: 2

When you balance any elements, you have to balance the whole chemical compound.

S8 + O2 -> 8 SO2

When we add 8 to the RHS, it gives us 8S, 16 O.

In order to balance that into the RHS, I need to multiply the O2 by 8, which will give 8(O2) = 16 O particles.

Therefore, S8 + 8 O2 -> 8 SO2 is the final answer for (3).

The balanced molecular equation for the reaction between sodium hydroxide (NaOH) and aluminum chloride (\(AlCl_3\)) in aqueous solution can be written as follows: 2NaOH(aq) + 3\(AlCl_3\)(aq) → 3NaCl(aq) + \(Al(OH)_3\)(s)

In this reaction, sodium hydroxide (NaOH) reacts with aluminum chloride (\(AlCl_3\)) to form sodium chloride (NaCl) and aluminum hydroxide (\(Al(OH)_3\)). The coefficients in the balanced equation indicate the stoichiometric ratio between the reactants and products.

The physical states of the substances are indicated by the symbols (aq) for aqueous solutions and (s) for the solid precipitate.

The reaction is a double-displacement reaction, also known as a precipitation reaction. Double-displacement reactions involve the exchange of ions between two compounds, resulting in the formation of a precipitate.

In this case, sodium hydroxide and aluminum chloride react to form sodium chloride and aluminum hydroxide, with aluminum hydroxide being the white solid precipitate.

It's worth noting that the actual reaction might involve hydrated forms of the compounds, such as NaOH·x\(H_2O\) and \(AlCl_3\)·y\(H_2O\). However, for simplicity, these hydrated forms are not included in the balanced equation.

Overall, the balanced equation represents the chemical reaction between sodium hydroxide and aluminum chloride, showing the reactants, products, and their stoichiometric ratios.

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Answer:  343 Celsius

Explanation:

Gay lussac law

T2=T1V2/V1  Temp must be in Kelvin

T2= 308.15 X 9.00 / 4.50 =616.30 K - 273.15 to get back in celsius

=343.15 C

Answer:

See below ~

Explanation:

Finding the rule of the function :

Inverse rule :

Table :

\(\left[\begin{array}{ccc}x&y\\-2&-\frac{1}{2} \\-3&-1\\-4&0\\-5&1\end{array}\right]\)

A chemical element that has an atomic number less than 58 and an atomic mass greater than 135.6m is barium (atomic no. 56 and atomic mass137.13 ) and lanthanum (atomic no. 57  and atomic mass 135.6).

Barium is an element with the symbol Ba and atomic number 56. It is an alkaline earth metal that is soft and silvery, and it is the fifth element in group 2. Barium is never found in nature as a free element due to its extreme chemical reactivity. Oil well drilling fluid uses barium sulfate as an insoluble ingredient. It is employed as an X-ray radiocontrast agent in a purer form to image the human gastrointestinal tract. Barium compounds that dissolve in water have been employed as rodenticides despite being hazardous.

Chemical element lanthanum has the atomic number 57 and the symbol La. It is a silvery-white, ductile, soft metal that slowly tarnishes when exposed to air. It serves as the eponym for the group of 15 related elements in the periodic table between lanthanum and lutetium, of which lanthanum is the first and prototype. The rare earth elements traditionally include lanthanum.

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Answer: youz a dumah  

Explanation:  ah  big head ah  yo momma waz in my bed last night

Answer:

Explanation:2H2 + O2 —-> 2H2O

The mole ratio of H2 to H2O is 2 : 2 = 1:1

4 moles of H2 = 4 moles of H2O

Moles of H20 = 4mol

Molar mass of H2O = 18g/mol

Mass = moles X Molar mass

= 4mol x 18g/mol

= 72g

Explanation:

try 96 if that's not right let me know and I'll try to fix it

Answer:24

Explanation:

Powerful Electrolytes:

HCl, NaOH, HNO3

Weak electrolyte:

HF, HC2H3O2

• Non-electrolytes:

C2H5OH, C6H12O6

Further explanation

An electrolyte solution is a substance that produces ions when dissolved in water and can conduct electricity.

Strong electrolytes are the solution

Solutes have the strongest electrical conductivity because they are completely ionized when dissolved in water.

• Weak electrolytes are partially ionized solutions with low electrical conductivity.

• Non-electrolytes are solutions that cannot conduct electricity because the solute cannot form ions. One of the most important properties of water is its ability to dissolve various substances. Solutions in which water is actually the dissolution medium are called aqueous solutions. Water is the most important solvent for electrolytes.

HCl = hydrochloric acid, a strong acid.

HNO3 = nitric acid, strong acid

• NaOH = sodium hydroxide, a strong base

HF = hydrofluoric acid, a weak acid

HC2H3O2 or CH3COOH = acetic acid, a weak acid

C2H5OH = ethanol, non-electrolyte

C6H12O6 = glucose, non-electrolyte

remarks:

• Some acids are fully ionized in water, while others are partially ionized. Not all acids are equally strong in generating H+ ions in solution. When an acid is fully ionized it is a strong acid. Click here when passing through hydrogen chloride

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The correct answer is: Atoms are the building blocks that make up elements. At the center of each atom is a nucleus composed of small particles called protons and neutrons. Nuclei is the plural of nucleus; option C.

The atomic number of an element is the number of protons present in the nucleus of the atom of the element.

The nucleus is the center of the atom and is the heaviest part of the atom.

Another sub-atomic particle fund in the nucleus is the neutron.

Elements are named according to the number of protons in the nuclei.. This is because the number of protons in the nucleus of any given atom whereas the neutron number may vary, Also, electrons are easily removed from atoms of elements.

In conclusion, the number of protos in atom is used to name the atom.

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Answer:

false

Explanation:

Explanation:

Lewis Dot Diagrams are represented by the element name in the middle, the same as in the periodic table, and is surrounded by dots that represent the elements valence electrons.

Answer: A.) It is a compound

Explanation:

Water is an inorganic compound made of water molecules, which are made of oxygen and hydrogen atoms.

It is not an element because there is no such thing as a water atom.

Water is not a chemical reaction to anything.

Water is OBVIOUSLY not a metal.

Hope this helps :)

.Answer:

2kclo3 --> 2kcl + 3o2 is a decomposition reaction because it is breaking apart (thinks decompose- to break apart/down)

H2 + I2 --> 2HI is a synthesis reaction because synthesis is like creation/ building

think DNA synthesis or the book of genesis in the bible about creation

2 Na + 2 H20 --> NaOH + H2 --- not balanced at all

other one is a balanced equation- the Zn + 2HCl one

Explanation:

Answer:

The concentration is  \(   [Cu^{2+}]_a  = 10^{-10.269} \)  

Explanation:

From the question we are told that

    The voltage of the cell is  \(E =  0.22 \  V\)

Generally the reaction at the cathode is  

  \(Cu^{2+} _{(aq)} + 2e^{-} \to  Cu_{s}\) the half cell voltage is  V_c =  0.337 V

Generally the reaction at the anode is    

   \(Cu _{(s)} \to Cu^{2+} _{(aq)} +  2e^{-}\)  the half cell voltage is  V_a = -0.337 V

Gnerally the reaction of the cell is  

    \(Cu_{(s)} + Cu^{2+} _{(aq)} \to Cu^{2+}_{(aq)} +  Cu_{(s)}\)

At initial the voltage is  V  =  0 V

Generally the voltage of the cell at 25°C is  

       \(E =  V  - \frac{0.0591}{n} log \frac{[Cu^{2+}] _a}{[Cu^{2+}]_c}\)

Here n is number of  of electron and it is 2

So from the question we are told that one cell has a concentration 1.5 x 10-3 M

Let assume it is  \([Cu^{2+}]_c\)

So

      \(0.22=  0  - \frac{0.0591}{2} log \frac{[Cu^{2+}] _a}{  1.5 * 10^{-3} }\)

=>    \(-7.445 =     log \frac{[Cu^{2+}] _a}{  1.5 * 10^{-3} }\)

=>  \(-7.445 =     log [Cu^{2+}_a] - log [1.5*10^{-3}]\)

=>    \(-7.445  + log [1.5*10^{-3} =     log [Cu^{2+}_a] \)

=>    \(-7.445  - 2.824 =     log [Cu^{2+}_a] \)

Taking the antilog

=>    \(   [Cu^{2+}]_a  = 10^{-10.269} \)    

=>     \(   [Cu^{2+}]_a  = 5.38 *10^{-11} \  M  \)  

Gas Y will effuse 6.17 times faster than gas X from a small opening at the same temperature.

The rate of effusion of a gas is inversely proportional to the square root of its molar mass. Therefore, we can use Graham's law of effusion to determine how much faster or slower Gas Y effuses from a small opening than Gas X at the same temperature:

rate of effusion of Gas Y / rate of effusion of Gas X = sqrt(molar mass of Gas X / molar mass of Gas Y)

Plugging in the given molar masses, we get:

rate of effusion of Gas Y / rate of effusion of Gas X = sqrt(64.8 g/mol / 1.7 g/mol)

Simplifying this equation gives:

rate of effusion of Gas Y / rate of effusion of Gas X = sqrt(38.12)

rate of effusion of Gas Y = rate of effusion of Gas X / sqrt(38.12) = 6.17

Therefore, Gas Y effuses about 6.17 times faster than Gas X at the same temperature.

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When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.

The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.

In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.

The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.

On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.

In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.

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One mole or 12 g of carbon reacts with one of oxygen molecule weighs 32 g will produce one mole of carbon dioxide. One mole of carbon dioxide weighs 44 g.

Carbon dioxide is an inorganic gas formed by the covalent bonding between carbon and oxygen gas. Carbon dioxide is an essential gas to maintain the living atmosphere in earth.

The balanced chemical equation of the reaction between oxygen gas and carbon is given below:

\(\rm C+O_{2} \rightarrow CO_{2}\)

As per this equation, one mole of carbon reacts with one mole of oxygen gas:

Atomic mass of carbon = 12g

molecular mass of oxygen = 32 g

then molar mass of carbon dioxide = 32+ 12 = 44 h=g.

Therefore, 44 g of carbon dioxide is produced in this reaction.

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Answer:

A new substance was forming

Explanation: