What size will it be if 4" is at scale 3/4" = 1"

Answer:

On July 13, 1787, Congress enacts the Northwest Ordinance, structuring settlement of the Northwest Territory and creating a policy for the addition of new states to the nation. ... In 1781, Virginia began by ceding its extensive land claims to Congress, a move that made other states more comfortable in doing the same

Answer:

They divided up the Northwest Territory into acre squares and sold them.

Explanation:

Answer:

Metamorphic manufacturing

Explanation:

I don't know what form of an answer you wanted but I hope this helps :)

Answer:

Hermetic compressors are ideal for small refrigeration systems, where continuous maintenance cannot be ensured.

Stretching a flat, 2D shape vertically to produce a 3D item in a scene is called extrusion. For instance, extruding building polygons by a height value can result in three-dimensional building shapes.

By applying a force that causes the material to flow through an opening or die, a process known as extrusion allows a material to be plastically deformed. If the substance possesses the necessary qualities, it will adopt the cross-sectional profile of the die and keep that form in the final extrudate. The playdough toys used when playing with it are a straightforward illustration of extrusion. Playdough is forced through the die to form a certain shape, and the procedure is known as extrusion. The substance must be forced through the die firmly in order for it to produce the correct form.

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It is motor oil, as oil is used to reduce friction

the correct answer is option (d) ceramic tube.

A ceramic tube is most commonly used in industrial high temperature applications, and electrical and thermal insulations. Our high temperature ceramic tubes include alumina, silicon carbide, and quartz choices that have excellent thermal, anti-shock, anticorrosion, and extreme high temperature resistance properties. The uniform dimensional stability of ceramic tubing offers optimal insulation while providing reliable protection.

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The correct answer is when retentive power is restored the accumulated count will be 300.

PLC counters are normally retentive; that is, whatever count was contained in the counter at the time of a proces- sor shutdown will be restored to the counter on power-up. The counter may be reset, however, if the reset condition is activated at the time of power restoration.A counter instruction is an input instruction. A counter's input signal can come from an external device such as a sensor. Up and down counters may be programmed together to count up and down. Counters can count past their preset values.

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The largest number among three numbers, follow these steps: Compare the first two numbers to bed load determine which is larger. Compare the larger number from step 1 with the third number. If the third number is larger than the number from step 1, then the third number is the largest.

To find the largest number among three numbers, you need to compare each number with the other two. Comparing the first two numbers will give you the larger of the two. This number will then be compared with the third number to determine which is the largest. If the third number is larger, then it is the largest among the three. If not, then the larger number from step 1 is the largest among the three.

Take the three numbers (let's call them A, B, and C) that you want to compare. Compare the first two numbers (A and B). If A is greater than B, set A as the current largest number. If B is greater or equal to A, set B as the current largest number. Now, compare the current largest number with the third number (C). If the current largest number is greater than C, it remains the largest number. If C is greater or equal to the current largest number, set C as the largest number.

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The best way to mentally prepare for what may be over the hill or around the curve is to Anticipate and slow down.

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The plunger or lever is the device that pushes the starter pinion gear into mesh with the ring gear when the ignition switch is in the start position.

The pinion is a special gear and spring assembly. The gear is extended into the gearbox case and engaged with the flywheel after the starter is turned on. In order to start the combustion process, the engine spins.

Before turning to start the engine, the pinion engages with the ring gear. A free wheel clutch prevents the pre-engaged starter motor from overspeeding when the engine accelerates.

Therefore, the plunger or lever is the device that pushes the starter pinion gear into mesh with the ring gear when the ignition switch is in the start position.

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The quartiles divide a set of observations into four portions, each representing 25% of the observations, together with the minimum and maximum values of the data set. The interquartile range, a measurement of variation around the median, is calculated using quartiles.

Statistical file: {2, -6, 5}

Quartile Q1: -6

Quartile Q2: 2

Quartile Q3: 5.

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Solution :

Given data:

Diameter of the copper cylindrical rod = 16 mm

Yield strength  = 250 MPa

Calculating the percent cold work

\($\text{Percentage Cold Work} = \frac{\pi\left(\frac{d_0}{2}\right)^2-\pi\left(\frac{d_d}{2}\right)^2}{\pi\left(\frac{d_0}{2}}\right)^2} \times 100$\)

                                  \($ = \frac{\pi\left(\frac{16}{2}\right)^2-\pi\left(\frac{11.3}{2}\right)^2}{\pi\left(\frac{16}{2}}\right)^2} \times 100$\)

                                  = 50% CW

Therefore, at \(50\% \ CW\), the yield strength of copper will be of the order of 330 MPa.

The ductility will be 4% elongation (EL).

Rather than performing drawing in single operation, we draw some of the fraction of total deformation, and then the anneal them to recrystallize and also finally w do cold work on the material  for the second time to achieve its final diameter, ductility and yield strength.

\(21\% \ CW\)is required for a yield strength of \(250 \ MPa\). Similarly, a maximum of \(23\% \ CW\) is required for\(12\% \ EL\).

The average of the two values is \(22\% \ CW\). To achieve both the \(\text{specified yield strength and ductility,}\) the copper should be deformed to\(22\% \ CW\). The\(\text{ final diameter}\) after the first drawing and the initial diameter for the second drawing is \($d_0'$\) , then

\($22\% \ CW = \frac{\pi\left(\frac{d_0'}{2}\right)^2-\pi\left(\frac{11.3}{2}\right)^2}{\pi\left(\frac{d_0'}{2}}\right)^2} \times 100$\)

\($d_0'=\frac{11.3}{\sqrt{1-\frac{22\% \ CW}{100}}}$\)

\($d_0'=12.8 \ mm$\)

Answer:

Dark shadow

Explanation:

Shadow is nothing but space when the light is blocked by an opaque object. It is just that part where light does not reach. When you stand in the sun, you are able to see your shadow behind you. ... This is because our body is opaque and does not allow the light to pass through it

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The correct anwser is that this does not exceed the overall off the top of renewable of the heat box.

Renewable Insulation introductionThe largest amount of energy consumed within the average home is related tomaintaining adequate climate control through heating and cooling systems. Toconserve energy and decrease expenses associated with climate control, properhome insulation techniques are required. Insulation technologies relating tomaterials and application have advanced throughout the home building industry withtime. The home building industry once relied on straw and newspaper for insulatingmaterial. The industry currently utilizes technology such as fiberglass and blownexpandable foam. Insulation material advancement is driven by consumersdemanding insulation material designed for high insulation value along with positiveoccupant health and environmental impact.

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Electrotechnology is important to aerospace engineering for what key reason is option B. Spacecrafts need advanced electrical systems.

Electrotechnology plays a critical role in aerospace engineering because spacecrafts need advanced electrical systems to function.

These systems are responsible for powering and controlling various subsystems on the spacecraft, such as the propulsion system, the communication system, and the environmental control system.

Therefore, Electrotechnology is used to design and build these systems, as well as to troubleshoot and maintain them. It involves the use of electricity, electronics, and electromechanical systems to control and manipulate the flow of electrical energy.

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Answer:

  0.42 kg

Explanation:

Heat is proportional to mass by way of the conversion factor that is the inverse of the specific heat.

  \(\dfrac{63000\text{ J}}{\dfrac{3000\text{ J}}{\text{kg$\cdot$K}}\cdot(65-15)\text{ K}}=0.42\text{ kg}\)

The mass of the liquid is about 0.42 kg.

Answer: Hello :)

They are in the nutrient pollution category.

Explanation:

A fixed-value capacitor known as a ceramic capacitor uses ceramic material as the dielectric. It is made of two or more layers that alternate.

Ceramic capacitors are mostly employed in devices with high stability and minimal loss. The capacitance values of these capacitors are steady with regard to the applied voltage, frequency, and temperature thanks to the devices' extremely precise findings. Ceramic capacitors are non-polarized capacitors used in timing, coupling, decoupling, and filtering applications. The ceramic capacitor has a pretty high voltage rating and can withstand both DC and AC voltage. A ceramic material serves as the dielectric medium in a ceramic capacitor. A thin coating of metal oxide serves as the dielectric medium within an electrolytic capacitor. A ceramic capacitor's corresponding series resistance is little.

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If the temperature of the shield is 338 kelvin. Then the heat flux through the tank will be 25.3 Watt per square meter.

The increase in heat energy movement through a particular surface is known as heat flux, and the heat flux density is the absolute temperature per unit area.

Assume the view factor between the tank and the shield is unity; all surfaces are diffuse and gray, and the surroundings are at 0 K.

It is given that T= 100 K, ε₁ = ε₂ = 0. 10, \(\varepsilon_t\) = 0.20, and GS= 1250 W/m².

Then we have

The temperature of the shield will be

\(\rm \alpha _sG_s - \varepsilon _1 E_b (T_s) - \dot{q}_{ST} = 0\) ...1

and

\(\rm q''_{12}=\dfrac{ \sigma (T_{1}^{4} - T_{2}^{2})}{\frac{1}{\varepsilon _1 }+ \frac{1}{\varepsilon _2} -1}}\) ...2

Then from equations 1 and 2, we have

\(\rm \alpha _sG_s - \varepsilon _1 E_b (T_s) - \dfrac{ \sigma (T_{1}^{4} - T_{2}^{2})}{\frac{1}{\varepsilon _1 }+ \frac{1}{\varepsilon _2} -1}} = 0\)

Then the value of \(\rm T_s\) will be

\(\rm T_s =\left [ \dfrac{\alpha _sGs+\left ( \dfrac{\sigma T_1^4}{\frac{1}{\varepsilon _1}+\frac{1}{\varepsilon _2} - 1} \right )}{\sigma \left ( \varepsilon _1 + \dfrac{1}{\frac{1}{\varepsilon _1} + \frac{1}{\varepsilon _2}-1} \right )} \right ] ^{\dfrac{1}{4}}\)

Put all the values, then we have

\(\rm T_s = \left [ \dfrac{0.05 \times + \left ( \dfrac{\sigma (100)^4}{\frac{1}{0.1}+\frac{1}{0.05}-1} \right )}{\sigma \left ( 0.05 + \dfrac{1}{\frac{1}{0.1}+\frac{1}{0.05} - 1} \right )} \right ]^{\dfrac{1}{4}} \\\\\\T_s = 338 \ K\)

Then the heat flux will be

\(\rm q"_{ST}=\dfrac{\sigma (T_S^4 - T_t^4)}{\frac{1}{\varepsilon _1} + \frac{1}{\varepsilon _2} - 1} \\\\\\q"_{ST}=\dfrac{5.67 \times 10^{-8}(388^4-100^4)}{\frac{1}{0.1}+\frac{1}{0.05}-1}\\\\\\q"_{ST} = 25.3 \ W/m^2\)

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The common theme among generativity, kin keepers, the sandwich generation, and filial obligation is the interconnectedness and responsibilities between different generations, emphasizing the importance of nurturing, supporting, and maintaining intergenerational relationships within families and society.

Common Theme: The common theme that runs through generativity, kin keepers, the sandwich generation, and filial obligation is the concept of intergenerational relationships and responsibilities. Each of these concepts involves the interconnectedness and obligations between different generations within a family or society. They highlight the importance of nurturing, supporting, and maintaining connections across generations, whether it is through caring for older family members, guiding younger individuals, or contributing to the well-being of future generations. These concepts reflect the significance of family ties, care, and support as well as the dynamic roles and responsibilities that individuals assume within the context of their families and communities.

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Answer:

fracture will occur since ( 31.8 Mpa√m ) is greater than the \(K_{Ic\) of the material ( 30 Mpa√m )

Explanation:

Given the data in the question;

To determine whether the aircraft component will fracture, given a fracture toughness of 30 Mpa√m, stress level of 355 and maximum internal crack length of 1.39 mm.

On a similar component, it has been said that fracture results at a stress of 237 MPa when the maximum (or critical) internal crack length is 2.78 mm.

so we first of all solve for the parameter Y in the condition where fracture occurred.

\(K_{Ic\) = 30 Mpa√m

σ = 237 MPa

2α = 2.78 mm = 2.78 × 10⁻³ m  

so

Y = \(K_{Ic\) / σ√πα

we substitute

Y = (30 Mpa√m) / (237 MPa)√(π(2.78 × 10⁻³ m / 2 ) )

Y =  (30 Mpa) / (237)( 0.06608187 )

Y = 30 / 15.6614

Y = 1.9155

Next we solve for Yσ√πα for the second case;

σ = 355 Mpa, 2α = 1.39 mm = 1.39 × 10⁻³ m

so

Yσ√πα = 1.9155 × 355 Mpa × √( π × (1.39 × 10⁻³ m / 2) )

= 1.9155 × 355 × 0.0467269

= 31.8 Mpa√m

so

( 31.8 Mpa√m ) > \(K_{Ic\) ( 30 Mpa√m )

Therefore, fracture will occur since ( 31.8 Mpa√m ) is greater than the \(K_{Ic\) of the material ( 30 Mpa√m )

The steel-frame structural support was a main feature in the development of t the floors, roof, walls and  skyscraper.

Steel frame is known to be a form of a building method that is used along with a skeleton frame that is made up of steel columns and  I-beams.

Conclusively, This is often used  in the construction of grid to aid the floors, roof and walls of any kind of building. It is also used in the construction of skyscraper.

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Answer: the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

Explanation:

Given that;

Weight of soil r = 118 lb/ft³

stress parameter C = 250 lb/ft²

φ total = 29°

depth Z = 12 ft

The shear strength on a horizontal plane at a depth of 12ft

ζ = C + δtanφ

where δ = normal stress

normal stress δ = r × z = 118 × 12 = 1416

so

ζ = C + δtanφ

ζ = 250 + 1416(tan29°)

ζ = 250 + 1416(tan29°)

ζ = 250 + 784.9016

ζ = 1034.9015 lb/ft²

Therefore the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

Answer:

D

Explanation:

Your answer is D.There is nothing to do; if you do not own the car anymore, it is not your responsibility

Explanation:

Los seres humanos siempre han tenido la necesidad de explicar y comprender los hechos sobre el mundo, ellos mismos y la naturaleza. La religión se configura como un conjunto de creencias comunes a una comunidad, que busca conectar al hombre con una fe en una divinidad superior que explique una visión y construcción del mundo. En sentido antropológico, la religión es una construcción evolutiva de parámetros sociales y dogmáticos como búsqueda de la creación de un sentido de pertenencia social, además de la búsqueda de la comprensión de uno mismo y del desarrollo espiritual.

La biología y la filosofía surgen como conceptos amplios que buscan explicar otros conceptos sobre la ciencia de manera sistemática, diferente a buscar una comprensión del mundo a través de la religión. La filosofía como concepto de que el hombre puede comprender el mundo a través de sus propias visiones y descubrimientos, desarrollando el pensamiento crítico y la búsqueda del conocimiento, que desarrolló las ciencias, entre ellas la biología que ayudó en la comprensión de parámetros esenciales para la calidad de vida humana, como la medicina por ejemplo.

Entonces hay una convergencia de los conceptos de religión, biología y filosofía, y es posible que el hombre crea en cada uno sin que el otro concepto se vea afectado.

In summary, the true statements regarding the pointer reinforcement technique in the given code are: Statement 1: It makes use of the return field to help restructure the list. Statement 3: The technique separates the responsibility of deciding the next node and setting the next node to different recursive calls.

1. It makes use of the return field to help restructure the list.

True. The pointer reinforcement technique involves using the return field to modify the links between nodes in order to remove duplicates from the list. By updating the return field, the method can restructure the list and remove duplicate nodes.

2. It uses the return field to return the data we need at the end of the public method call.

False. The return field is not used to return any data in this code. Its purpose is to assist in restructuring the list, not to return data.

3. The technique separates the responsibility of deciding the next node and setting the next node to different recursive calls.

True. In the provided code, the technique separates the responsibility of deciding the next node to remove and setting the next node after removal into different recursive calls. The "removeDuplicatesHelper" method recursively calls itself to decide the next node to remove, while the setting of the next node is done by modifying the return field.

4. The technique groups the responsibility of deciding the next node and setting the next node into a single recursive call.

False. The technique separates the responsibility of deciding the next node and setting the next node into different recursive calls, as mentioned in statement 3.

5. The information that is returned is different based on which case of removing duplicates we're in.

False. In the provided code, the return field is used for restructuring the list and not for returning different information based on the case of removing duplicates.

6. The code fails to work on an empty list.

False. The code is designed to handle an empty list correctly. If the list is empty, the method simply returns null.

7. The code fails to work if there are no duplicates.

False. The code can handle a list without any duplicates correctly. In such a case, the method will traverse the entire list without making any modifications.

8. The code fails to work if the list is of size 1.

False. The code can handle a list of size 1 correctly. If the list has only one node, the method will simply return the node without making any modifications.

9.The technique serves no purpose if the list structure is not changing.

False. The technique is specifically designed to modify the list structure by removing duplicate nodes. If there are no duplicates or the list structure does not change, the technique may not be necessary or have any effect.

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