Answers
Related Questions
calculate the work done by the person who applies force of 5000N to lift a load up to a height of 2m
Answers
Answer:
W = 10000J
Explanation:
W = F • s
W = Work in J
F = Force in N
s = displacement in m
W = 5000N • 2m
W = 10000J
A lizard climbs up a building 15.5 m and then turns around and goes down the bulding 23.7 m. This takes the lizard 31.5s. what is the average velocity of the lizard?
1.24 m/s Down
0.26 m/s Down
258 m/s Down
3.8 m/s Down
Answers
The average velocity of the lizard for the whole journey is 0.26 m/s Down.
What is average velocity?The term average velocity has to do with the velocity of the lizard for the whole journey. We can see that the downward displacement is greater than the upward displacement.
Thus;
Velocity = displacement / time = 23.7 m - 15.5 m/31.5s = 0.26 m/s Down.
Thus, the average velocity of the lizard for the whole journey is 0.26 m/s Down.
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A 5.00g bullet is fired horizontally into a 1.20kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between the block and surface is .20. The bullet remains embedded in the block, which is observed to slide .31m along the surface before stopping. What was the initial speed of the bullet?
Answers
the initial speed of the bullet as it was fired horizontally into the wooden block resting on a horizontal surface is 265m/s.
What is the law of conservation of momentum?A conservation law states that the total linear momentum of a closed system remains constant through time, regardless of other possible changes within the system.
Given, A 5.00g bullet is fired horizontally into a 1.20kg wooden block resting on a horizontal surface.
In our case,
Mass of bullet = 5 gram = 0.005 kg
Mass of wooden block = 1.2 kg
the initial velocity of block = 0
Kinetic friction = 0.20
First, we get the velocity of the Wood.
From Conservation of Energy:
1/2m v² = μ mgs
v = √(2 μgs)
Where v is the velocity of the block,
μ is the coefficient of kinetic friction,
s is the displacement of the bullet
g is the acceleration due to gravity (9.81)
v = √(2 *0.2*9.81 * 0.31)
v = 1.1 m/s
so, the velocity of the wooden block after the collision will be 1.10 m/s
Now, we determine the velocity of the bullet. Using Conservation of Momentum.
m₁v₁ + m₂v₂ = MV
0.005 *v + 0 = (1.20 + 0.005) * 1.1
v = 1.325/0.005
v = 265 m/s
Therefore, the initial speed of the bullet as it was fired horizontally into the wooden block resting on a horizontal surface is 265m/s.
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Given a DC battery of voltage, V = 10.0 V connected to a resistor R = 2.00 Ohms. What is the current coming out of the battery? A)48.2 A B)7.67 A C)9.65 A D)23.4 A E)5.00 A
Answers
Given:
The voltage of the battery, V=10.0 V
The resistor of the resistance, R=2.00 Ω
To find:
The current coming out of the battery.
Explanation:
From Ohm's law, the voltage across a circuit is directly proportional to the current through the circuit.
Thus, the voltage of the battery is given by,
\(V=IR\)Where I is the current coming out of the battery.
On substituting the known values,
\(\begin{gathered} 10.0=I\times2.00 \\ \Rightarrow I=\frac{10.0}{2.00} \\ =5.00\text{ A} \end{gathered}\)Final answer:
The current coming out of the battery is 5.00 A.
Thus the correct answer is option E.
What is the net force acting on the box?
0 285 N
0 185 N
SN
0 85 N
0 65 N
Answers
Answer:
the answer would be D 65N
Explanation:
just got it correct on EDG
A yet-to-be-built spacecraft starts from Earth moving at constant speed to the yet-tobe-discovered planet Retah, which is 20 lighthours away from Earth. It takes 25 h (according to an Earth observer) for a spacecraft to reach this planet. Assuming that the clocks are synchronized at the beginning of the journey, compare the time elapsed in the spacecraft’s frame for this one-way journey with the time elapsed as measured by an Earth-based clock.
Answers
Answer:
The time elapsed at the spacecraft’s frame is less that the time elapsed at earth's frame
Explanation:
From the question we are told that
The distance between earth and Retah is \(d = 20 \ light \ hours = 20 * 3600 * c = 72000c \ m\)
Here c is the peed of light with value \(c = 3.0*10^8 m/s\)
The time taken to reach Retah from earth is \(t = 25 \ hours = 25 * 3600 =90000 \ sec\)
The velocity of the spacecraft is mathematically evaluated as
\(v_s = \frac{d }{t}\)
substituting values
\(v_s = \frac{72000 * 3.0*10^{8} }{90000}\)
\(v_s = 2.40*10^{8} \ m/s\)
The time elapsed in the spacecraft’s frame is mathematically evaluated as
\(T = t * \sqrt{ 1 - \frac{v^2}{c^2} }\)
substituting value
\(T = 90000 * \sqrt{ 1 - \frac{[2.4*10^{8}]^2}{[3.0*10^{8}]^2} }\)
\(T = 54000 \ s\)
=> \(T = 15 \ hours\)
So The time elapsed at the spacecraft’s frame is less that the time elapsed at earth's frame
The speed of sound is measured to be 340 m/s on a certain day.
What is this in Kilometers per hour?? s/km/h=
Please help and explain how to do these types of problems in very confused!!!
Answers
Explanation:
To do this, we pick the first unit and convert
Picking m first and converting to km:
Since we're converting from a non-prefix to a prefix, we divide the value by the prefix were taking it to. In this case, kilo = 10³ which means we're going to divide our value by 1000 to convert it from m to km
340 m/s ÷ 1000 = 0.34 km/s
Now, let's convert our seconds to hour:
We'll need to calculate how many hours is equivalent to one second first;
1 hr = 60×60 seconds
X hr = 1 second
*Cross multiply*
1 × 1 = X × 60 × 60
1 = 3,600 X
X = 1 / 3,600
X = 2.778×10⁻⁴ hour
So, in the place of "1 Second", we're going to be inserting 2.778×10⁻⁴ hour instead
0.34 km / s = 0.34 km / 2.778×10⁻⁴ hour
(0.34 / 2.778×10⁻⁴) km/hour
1,224 km/h.
340 m/s = 1,224 km/h
If the magnetic force is 3.5 × 10–2 N, how fast is the charge moving?
Answers
Answer:
D
Explanation:
Took it on edg
The speed of the charge at the given magnetic force and field is determined as 1.1 x 10⁴ m/s.
Speed of the chargeThe speed of the charge is calculated as follows;
F = qvBsinθ
v = F/qBsinθ
where;
F is the magnetic forceB is magnetic fieldv is speed of the chargev = (3.5 x 10⁻²)/(8.4 x 10⁻⁴ x 6.7x 10⁻³ x sin35)
v = 10,842.33 m/s
v ≅ 1.1 x 10⁴ m/s
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A local meteorologist reports the day’s weather. "Currently sunny outside, 34°F. Skies will become overcast later this afternoon, as temperatures drop to 25°F, with windy conditions out of the north at 10–15 miles per hour. Radar indicates 2–3 inches of snow expected to fall later tonight.” Which information is qualitative? These are non-numerical, descriptive data. These are numerical data that have been measured. “sunny” “25°F” “2–3 inches of snow” “10–15 miles per hour”
Answers
Answer:
sunny
Explanation:
took the test
Answer:
A.) Sunny
Explanation:
i need help question 10
Answers
What is the electric field strength at a distance of 10 cm from a charge of 2 uC
Answers
The electric field strength at a distance of 10 cm from a charge of 2 μC is 3.6 x 10⁵ N/C.
What is called electric field?If there's a charge present in any form, an electric field is linked with every point in space. The strength and direction of the electric field are expressed by the value of E, sometimes referred to as the strength of the electrical field, electric field intensity, or simply the electric field.
The following formula determines the magnitude of the electric field generated by a point charge:
where,
E = Electrical Field Strength = ?
k = 9 x 10⁹ Nm²/C²
q = magnitude of charge
q = 2 μC = 2x 10⁻⁶ C
r = distance = 10 cm
r = 0.10 m
Therefore,
When the values are entered into the equation, we obtain:
E = 9 x 10⁹ * (2 x 10⁻⁶) / (0.1)²
E = 3.6 x 10⁵ N/C
Because of this, the electric field intensity at 10 cm from a 2 μC charge is 3.6 x 10⁵ N/C.
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Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.99 ✕ 10^5 m/s in the positive x-direction. Thousands of miles from Earth, they interact with Earth's magnetic field of magnitude 2.93 ✕ 10−8 T in the positive z-direction. Find the magnitude and direction of the magnetic force on a proton. Find the magnitude and direction of the magnetic force on an electron.
Answers
Therefore, the magnetic force on an electron is 1.175 x 10⁻¹⁴N in the positive y-direction.
The force experienced by a moving charge in a magnetic field is given by the Lorentz force law. Since the charge on a proton is positive and that on an electron is negative, the direction of the magnetic force experienced by each is different.In this question, we need to find the magnitude and direction of the magnetic force on a proton and an electron as they travel from the Sun to the Earth.
Let's first calculate the magnetic force on a proton:
F = qvBsinθ
where q = charge of the particle
v = velocity of the particle
B = magnetic field strength
θ = angle between the velocity of the particle and the magnetic field = 90° (since the proton is moving perpendicular to the magnetic field)
Therefore,
F = qvBsinθ
= (1.6 x 10⁻¹⁹) x (3.99 x 10⁵) x (2.93 x 10⁻⁸) x sin 90°
= 1.175 x 10⁻¹⁴ N
Direction of magnetic force on a proton:The direction of the magnetic force on a proton can be found using the right-hand rule. According to this rule, if we point the thumb of our right hand in the direction of the particle's velocity (in the positive x-direction) and the fingers in the direction of the magnetic field (in the positive z-direction), then the magnetic force will be perpendicular to both and will be in the negative y-direction.
Therefore, the magnetic force on a proton is 1.175 x 10^-14 N in the negative y-direction.
- Now, let's calculate the magnetic force on an electron:
Again using the Lorentz force law,
F = qvBsinθ
= (1.6 x 10⁻¹⁹) x (3.99 x 10⁵) x (2.93 x 10⁻⁸) x sin 90°
= -1.175 x 10⁻¹⁴ N (the negative sign indicates that the direction of the magnetic force is opposite to that of the proton)
Direction of magnetic force on an electron:Again using the right-hand rule, we can find the direction of the magnetic force on an electron. If we point the thumb of our right hand in the direction of the particle's velocity (in the positive x-direction) and the fingers in the direction of the magnetic field (in the positive z-direction), then the magnetic force will be perpendicular to both and will be in the positive y-direction.
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Prove that the vectors A = 2i - 3j + k and B = i+ j+ k are
mùtually perpendicular
Answers
Answer:
theta = 90°
Explanation:
hope it's helpful
Explanation:
A • B = (2i - 3j + k) • (i + j + k)
= (2)(1) + (- 3)(1) + (1)(1)
= 0 = AB cos θ
∴ cos θ = 0 (as A ≠ 0,B ≠ 0)
or θ = 90°
or the vectors A and B are mutually perpendicular.
-TheUnknownScientist
Give me the real answer
Answers
Answer: 12,339
Explanation:
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
Answers
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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5. How does a jack make changing a tire easier?
Answers
Answer: An jack makes changing a tire easier because it lifts up the car to get the tire off of the ground.
Explanation:
Harnessing tidal power would involve:_______.a) letting in-flowing and/or out-flowing tide flow through turbines in a dam.b) huge floats mechanically hooked to generators.c) electrodes in the water.d) bioluminescence of marine organisms.e) all of the above
Answers
Answer:
a) letting in-flowing and/or out-flowing tide flow through turbines in a dam.
Explanation:
Tidal power makes use of the energy from the tidal force and wave action in order to generate electricity. it is a predictable source of energy.
Tidal Barrages
The system allows tides to enter, seawater flows via the dam and is trapped into the basin when the tides subside and system’s gates close.
When the tides start to move out, the gates in the dam are opened up this consist of turbines and water begins to flow out, hitting the turbines this eventually turn to produce energy.
Power is produced when the tidal range, which is the difference between low and high tide, has to be more than 5 meters.
I need help with this science work
Answers
Please tell us the question and we will try to answer.
1. Consider the position vs time graph for objects A and B .
a. Describe how the motion of object A is different from that of object B.
Answers
Answer:
obj A is making a parabolic path whereas object B is moving in a straight path . on going further the position of object A decreases whereas the position of object B goes on increasing
a ball is dropped from rest at a height of 45.0 m above the ground. ignore the effects of air resistance. What is the speed of class of the ball when it is 10.0 m above the ground
Answers
So, the final velocity of the ball when it is 10.0 m above the ground approximately 26.2 m/s.
IntroductionHi ! In this question, I will help you. This question uses the principle of final velocity in free fall. Free fall occurs only when an object is dropped (without initial velocity), so the falling object is only affected by the presence of gravity. In general, the final velocity in free fall can be expressed by this equation :
\( \boxed{\sf{\bold{v = \sqrt{2 \times g \times h}}}} \)
With the following condition :
v = final velocity (m/s)h = height or any other displacement at vertical line (m)g = acceleration of the gravity (m/s²)Problem SolvingWe know that :
\( \sf{h_1} \) = initial height = 45.0 m\( \sf{h_2} \) = final height = 10.0 mg = acceleration of the gravity = 9.8 m/s²Note :
At this point 10 m above the ground, the object can still complete its movement up to exactly 0 m above the ground.
What was asked :
v = final velocity = ... m/sStep by Step
\( \sf{v = \sqrt{2 \times g \times \Delta h}} \)
\( \sf{v = \sqrt{2 \times g \times (h_1 - h_2)}} \)
\( \sf{v = \sqrt{2 \times 9.8 \times (45 - 10)}} \)
\( \sf{v = \sqrt{19.6 \times 35}} \)
\( \sf{v = \sqrt{686}} \)
\( \boxed{\sf{v \approx 26.2 \: m/s}} \)
ConclusionSo, the final velocity of the ball when it is 10.0 m above the ground approximately 26.2 m/s.
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is lifted 2 meters.
How much work
was done?
Answers
Answer:
The answer is 8 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distanceFrom the question we have
workdone = 4 × 2
We have the final answer as
8 JHope this helps you
Which of the following statements is true? Select one:
O a. A vector can have positive or negative magnitudes.
O b. A vector's magnitude cannot be more than the magnitude of one of its components.
Oc. The magnitude of a vector cannot be zero unless all of its components are zero.
O d. If the x-component of a vector is smaller than its y-component then that vector is in the opposite direction to its y- component.
Answers
Add a suffix to each of the following words to make new words?
Answers
Where's the following words?
The NEC states the resistance of 4/0 coated
copper conductors is 0.0626 ohms per 1000
feet. What would be the total resistance of the
three 4/0 conductors installed in parallel, if the
total length for each of the three conductors is
323 feet?
Answers
Answer:
The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.
Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:
Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet
To find the total resistance when the conductors are in parallel, we use the formula:
1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3
Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)
Substituting the values, we get:
Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))
Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.
The mass of an empty cylindrical tin is
proportional to its surface area.
Two empty cylindrical tins, G and H, are
shown below.
The mass of tin G is 72 g, and the surface
area of tin H is 792π cm².
2
a) Work out the total surface area of tin G in
terms of π.
b) Work out the mass of tin H.
Tin G
12 cm
5 cm
Tin H
Not drawn accurately
Answers
a) The total surface area of tin G in terms of π is 170π cm².
b) The mass of tin H is 336 g.
To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.
a) Total surface area of tin G in terms of π:
The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:
Lateral surface area = 2πrh
where r is the radius of the base and h is the height of the cylinder.
In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:
Lateral surface area = 2π(5 cm)(12 cm)
Lateral surface area = 120π cm²
Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:
Area of a circle = πr²
The radius of the circular base of tin G is 5 cm, so the area of each circular base is:
Area of each circular base = π(5 cm)²
Area of each circular base = 25π cm²
To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:
Total surface area of tin G = Lateral surface area + 2 × Area of each circular base
Total surface area of tin G = 120π cm² + 2 × 25π cm²
Total surface area of tin G = 120π cm² + 50π cm²
Total surface area of tin G = 170π cm²
Therefore, the total surface area of tin G in terms of π is 170π cm².
b) Mass of tin H:
We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:
(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)
Using the given values, we have:
(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)
Cross-multiplying and solving for the mass of tin H, we get:
(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)
mass of tin H = (72 g) × (792π cm²) / (170π cm²)
mass of tin H = 336 g
Therefore, the mass of tin H is 336 g.
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What is the answer?
Answers
Answer: i think it is d. none of them.
Explanation: The speed of light in a vacuum is 186,282 miles per second and so when you look and the answer choices and the question it doesnt make any since.
the mathematiccal relationships between kinetic energy and the mass of an object
Answers
Answer:
The equation for Kinetic Energy is: KE = 1/2 mv2. Kinetic energy has a direct relationship with mass, meaning that as mass increases so does the Kinetic Energy of an object. The same is true of velocity. ... We must consider both the speed and mass of objects when considering the outcomes of collisions.
Answer:
Kinetic energy is directly proportional to mass, and mass to kinetic energy. Kinetic energy is proportional to the square of the velocity of the moving mass. The equation for Kinetic Energy is: KE = 1/2 mv2.
A bar has a 20 N weight at one end, as shown in Figure 7.22. You have a weight of 15 N to hang somewhere on the bar so that the bar is in equilibrium. Where would you hang the 15 N weight on each of these bars? Consider the bar to have no mass.
Answers
The weight of 15N should be hung at a distance of 4/3 units from the fulcrum, on the opposite side of the bar to a weight of 20N.
The fulcrum is attained equilibrium when the principle of moments is equal to zero. The principle of momentum is defined as the body is said to be balanced when the clockwise movement about the point is equal to the anticlockwise movement about the same point.
When a weight of 15N is hung on the bar, it produces an anticlockwise movement with the same magnitude, opposes the clockwise moment produced by the weight of 20N on the fulcrum.
To find the distance (d) at which the 15N weight should be hung, the distance from the 20N weight to the fulcrum is 1 unit.
20×1 = 15×d
d = 20/15
=4/3 m
Thus, the weight of 15N should be hung by the distance of 4/3 units from the fulcrum, on the opposite side of the bar having the weight of 20N, to make the fulcrum to be at equilibrium.
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A convex lens has a focal length of 0.33 m. The object distance is 0.7 m. What is the image distance?
Answers
Answer:
Explanation:
1/v - 1/u = 1/f
given, f = 0.3 m, u = -0.4m
so, 1/v - 1/-0.4 = 1/0.3
or, 1/v = 1/0.3 - 1/0.4 = 1/1.2
v = 1.2 m
now, differentiating 1/v - 1/u = 1/f with respect to t,
-1/v² dv/dt + 1/u² du/dt = 0
or, dv/dt = (v/u)² du/dt
putting, du/dt = 0.01 m/s , v = 1.2 m and u = -0.4 m
so, dv/dt = (1.2/-0.4)² × 0.01
= 0.09 m/s
hence, speed of image with respect to lens is 0.09 m/s .
from formula of magnification
magnification, m = v/u
differentiating with respect to time both sides,
dm/dt = (u dv/dt - vdu/dt)/u²
= (-0.4 × 0.09 - 1.2 × 0.01)/(-0.4)²
= (-0.036 - 0.012)/0.16
= -0.048/0.16
= -0.3 m/s
hence, magnitude of rate of change of lateral magnification is 0.3 m/s
f F= {mango, apple, banana, orange)
Answers
Answer:
n(F) = 4Explanation:
Cardinality of a set is the number of elements in that set. Given the set.
F= {mango, apple, banana, orange), we are to determine the cardinality of the set i.e the amount of fruit present in the set. Cardinality of the set F is represented as n(F).
Since there are 4 different fruit in the given set F, hence the cardinality of the set F is n(F) = 4