What quantum numbers can apply to electrons in s orbitals.

Answer:

(B)

Explanation:

Because what ever angle the surface is, the light will reflect of of it perpendicular.

Answer:

The speed is equal to Distance divided by Time.

The SI Unit of Speed is m/s or meters per second.

V = S/T

= 750/25

= 30 m/s

The moment of inertia of the fan is 1.09 kg.m².

Given data:Angular speed of fan (w) = 3.66 rad/sFrictional torque (τ) = 0.125 N.mTime taken (t) = 31.8 s

We are supposed to determine the moment of inertia (I) of the fan using the given data.

Since, we have the value of angular speed (w), we can use the formula given below to determine the moment of inertia of the fan:

T = IαT

= I (w - 0)/t

= Iw/tI

= Tt/w

Now, substituting the given values in the above formula, we get:I

= 0.125 × 31.8 / 3.66I

= 1.09 kg.m².

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Answer:

1. 7.5 km/h

2. 1 hour, 52 minutes, 30 seconds

3. 0.8 Joules

4. 13.33 mph

5. 19456 Joules

6. 10.5 kg

Explanation:

Answer:

zone coverage is about sensing what the offense is attempting to accomplish against the defense. Each defensive player reacts when the ball is in the air, whereas in man-to-man coverage, he simply plays the receiver.

Explanation:

Their speed will be  half the initial speed of car A.

The speed of an item, which is a scalar quantity, is the size of the change in its location over time or the size of the change in its position per unit of time.

Any situation in which two or more objects exert forces on one another quickly is referred to as a collision. The scientific definition of the word "collision" makes no reference to the magnitude of the force involved, despite the fact that the most frequent usage of the word relates to instances in which two or more objects clash violently.

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The minimum angle so that the person can reach a distance of 0.88 m without having the ladder slip is 8⁰.

The weight of the person is calculated by applying the following formula.

W = mg

where;

W = ( 21.1 kg x 9.8 m/s² )

W = 206.78 N

The force of friction is calculated as;

Ff = μW

where;

Ff = 0.14 x 206.78

Ff = 28.95 N

If the person must not fall, the clockwise moment must be equal to anticlockwise moment.

28.95 x 0.88 x cosθ = 206.78 x 0.88 x sinθ

28.95 x cosθ = 206.78 x sinθ

28.95 / 206.78 = sinθ / coθ

28.95 / 206.78 = tanθ

θ = arc tan ( 28.95 / 206.78 )

θ = 8⁰

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Answer:

Given that the mass of the earth = 6 x 1024 kg, mass of the sun = 2 x 1030 kg, average distance between the two is 1.5 x 10-11 m and G = 6.67 x 10-11 Nm2kg-2

Explanation:

The surface area of the triangular prism as shown in the diagram is 660 cm².

To calculate the area of a triangular prism, we multiply the perimeter of the base to the length of the prism and add it to two times the area of the base.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the surface area of the triangular prism is 660 cm².

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The speed of an object orbiting another object depends on the masses of each object and the distance between them. Hence, the correct option is (c) the masses of each object and the distance between them.

According to Kepler's laws of planetary motion and the law of universal gravitation, the speed of an object in orbit is determined by the gravitational pull between the two objects. The greater the mass of the object being orbited, the stronger the gravitational force and the faster the orbiting object must travel to maintain its orbit. Similarly, the smaller the distance between the two objects, the stronger the gravitational force, requiring a higher orbital speed.

This relationship is described by the equation for orbital speed, which is given by:

Orbital Speed = √(G * (Mass of the object being orbited) / (Distance between the objects))

In this equation, G represents the gravitational constant. Therefore, the speed of an object in orbit depends on the masses of both objects involved and the distance between them. Alterations in any of these factors will result in changes to the orbital speed of the object. Option C.

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Answer:

\(15\:\mathrm{J}\)

Explanation:

The potential energy of an object is given by \(PE=mgh\).

Recall that the weight of an object is equal to the force of gravity on the object. From this, we can set up the following equation and solve for the mass of the object:

\(F=mg,\\5=mg,\\m=\frac{5}{9.81}\approx 0.51\:\mathrm{kg}\)

Now we can plug in values to \(PE=mgh\) and solve:

\(PE=0.51\cdot9.81\cdot3=\fbox{$15\:\mathrm{J}$}\).

Answer:

The potential energy of the body is 15J.

Explanation:

The energy possessed to a body due to position is called Potential energy.

U=mgh

U=mgh

U=5×3=15J

Hence, the potential energy of the body is 15J.

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The given statement: Charged particles escaping from Jupiter's magnetosphere cause aurora when they collide with Jupiter's atmosphere is TRUE.

Jupiter has a strong magnetic field that traps charged particles from the solar wind, forming a magnetosphere around the planet. The trapped particles spiral along the magnetic field lines and interact with Jupiter's atmosphere when they collide with it, creating auroras.

These auroras are similar to Earth's northern and southern lights and are visible in the ultraviolet, infrared, and visible light ranges.

Jupiter's magnetosphere is also larger and more powerful than Earth's, so its auroras are much more intense and can be seen even with small telescopes. In addition to charged particles from the magnetosphere, Jupiter's auroras can also be caused by electric currents generated in the planet's atmosphere.

The study of Jupiter's auroras provides insights into the behavior of magnetospheres, the interactions between planets and their environment, and the processes that create auroras in general.

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Explanation:

First train has 2 hr * 45 km/hr = 90 km   head start

  Closing speed between the two trains   745 - 45 = 30 km

to cover the 90 km between them will take 3 hours

  and the second train will be at  75 km/hr * 3 hr = 225 km from the station

Answer:

pushes is the correct answer

Answer: You have the right answer xD

Its AC/DC

This follows directly from the definition for average acceleration:

\(a_{\rm ave}=\dfrac{\Delta v}{\Delta t}=\dfrac{v_f-v_i}t\)

Under constant acceleration, acceleration and average acceleration are interchangeable. So we have

\(0.69\dfrac{\rm m}{\mathrm s^2}=\dfrac{v_f-3.5\frac{\rm m}{\rm s}}{8.3\,\mathrm s}\)

\(\implies v_f=3.5\dfrac{\rm m}{\rm s}+\left(0.69\dfrac{\rm m}{\mathrm s^2}\right)(8.3\,\mathrm s)\)

\(\implies\boxed{v_f=9.227\dfrac{\rm m}{\rm s}}\)

Answer: They will fall at the same time

Explanation:I had a google doc about this

When air resistance is considered, the effect of the air resistance will cause the rock to fall faster than the pebble which will be delayed due to its lesser weight. In the absence of air resistance, both rock and pebble will fall down at the same time.

Free fall is a motion of an object in which the force of gravity is the only force acting upon it. A body moving upwards would not be considered to be falling. But if the body falls under the effect of the force of gravity, it is said to be in free fall.

Free fall is a type of motion in which no air resistance is considered and the force acting upon an object is only gravity. All bodies under such conditions fall with an equal rate of acceleration, regardless of their masses.

As a body falls through the air, have suffered some degree of air resistance. Air resistance is the collisions of the surface of an object with molecules present in the air. The factors that have a direct effect on the amount of air resistance are the cross-sectional area and the speed of the object.

As the rock had greater weight than the pebble in the absence of air resistance it will fall faster than the pebble.

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The beetle's actual distance beneath the surface is 1.70 cm.

The given information states that the beetle appears to be 1.70 cm within the plastic. This means that the beetle is located at a distance of 1.70 cm from the outer surface of the cube of polystyrene plastic. However, the actual distance of the beetle beneath the surface is also 1.70 cm since it is embedded within the cube.

The phrase "appears to be" suggests that the observation of the beetle's position within the plastic is deceiving. The beetle is not deeper or closer to the surface than the given measurement. Therefore, the beetle's true depth beneath the surface is equivalent to the stated distance of 1.70 cm.

Distances and interpreting spatial relationships within objects like the embedded beetle.

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Newton's second law allows us to find that the correct answer is:

   A) The mass of the baseball never changes so the more force in the pitchers arm, the higher the acceleration of the baseball before it leaves the pitcher's hand.

Newton's second law gives a relationship between force and the product of mass and acceleration of the body

          F = m a

Where F is the force, m the mass and the acceleration of the body.  The bold indicate vectors

The baseball ball is a solid body that has a fixed mass, therefore the pitcher uses different forces in the arm, the acceleration must change proportionally, as the force increases, the acceleration must increase (fastball).

Let's review the different claims

A) true. These statements are in accordance with Newton's second law

B) False. If the force changes any of the other two parameters must change

C) false. Force and acceleration are proportional

D) False. When the ball is in the air it is subjected to the acceleration of gravity

With Newton's second law we find that the correct answer is:

   A) The mass of the baseball never changes so the more force in the pitchers arm, the higher the acceleration of the baseball before it leaves the pitcher's hand.

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Answer:

Cu2+

Explanation:

Answer:

E......1,800 meters

Explanation:

distance = speed × time

convert 1 min to seconds because speed is give in meters per seconds so it's which is 60 seconds

Then...60 ×30 = 1,800

The most important force that shapes the market environment for mobile banking on the African continent is technological advancement. The increased availability of mobile phones, improved mobile network infrastructure, the emergence of mobile money solutions, and the promotion of financial inclusion have all contributed to the growth of mobile banking in Africa.

The force that is most important to the growth of mobile banking on the African continent is technological advancement.

Technological advancement plays a significant role in the growth of mobile banking in Africa. Here's a step-by-step explanation:

1. Access to Mobile Phones: With the rapid expansion of mobile phone usage in Africa, more people have access to mobile banking services. Mobile phones have become an essential tool for communication and financial transactions in many African countries.

2. Mobile Network Infrastructure: The improvement in mobile network infrastructure has allowed for better coverage and connectivity, enabling the widespread adoption of mobile banking. It has also led to the development of more reliable and secure mobile banking platforms.

3. Mobile Money Solutions: Mobile money solutions, such as M-Pesa in Kenya, have gained popularity across Africa. These platforms allow users to transfer money, make payments, and access basic financial services through their mobile phones. The convenience and accessibility of these services have contributed to the growth of mobile banking.

4. Financial Inclusion: Mobile banking has played a crucial role in promoting financial inclusion in Africa. Many individuals who previously did not have access to traditional banking services can now perform financial transactions and access basic financial services through their mobile phones.

In conclusion, the most important force that shapes the market environment for mobile banking on the African continent is technological advancement. The increased availability of mobile phones, improved mobile network infrastructure, the emergence of mobile money solutions, and the promotion of financial inclusion have all contributed to the growth of mobile banking in Africa.

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A hydrogen atom is in its ground state (nᵢ = 1) when a photon impinges upon it. The atom absorbs the photon, which has precisely the energy required to raise the atom to the nf = 3 state. (a) The photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).(b)option B and C are correct.

To determine the photon's energy and the energies of photons that might be emitted when the hydrogen atom returns to the ground state, we can use the energy level formula for hydrogen atoms:

E = -13.6 eV / n^2

where E is the energy of the electron in the atom, and n is the principal quantum number.

(a) To find the energy of the photon that was absorbed by the hydrogen atom to raise it from the ground state (nᵢ = 1) to the nf = 3 state, we need to calculate the energy difference between the two states:

ΔE = Ef - Ei = (-13.6 eV / 3^2) - (-13.6 eV / 1^2)

Calculating the value of ΔE:

ΔE = -13.6 eV / 9 + 13.6 eV

= -1.51 eV

Therefore, the photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).

(b) When the hydrogen atom returns to the ground state, it can emit photons with energies corresponding to the energy differences between the excited states and the ground state. We need to calculate these energy differences and check which values are present among the given options.

ΔE1 = (-13.6 eV / 1^2) - (-13.6 eV / 3^2) = 10.20 eV

ΔE2 = (-13.6 eV / 1^2) - (-13.6 eV / 4^2) = 10.20 eV

ΔE3 = (-13.6 eV / 1^2) - (-13.6 eV / 5^2) = 12.10 eV

ΔE4 = (-13.6 eV / 1^2) - (-13.6 eV / 6^2) = 12.10 eV

ΔE5 = (-13.6 eV / 1^2) - (-13.6 eV / 7^2) = 13.55 eV

ΔE6 = (-13.6 eV / 1^2) - (-13.6 eV / 8^2) = 13.55 eV

ΔE7 = (-13.6 eV / 1^2) - (-13.6 eV / 9^2) = 13.55 eV

Comparing the calculated energy differences with the given options:

(A) 1.89 eV: This energy difference does not match any of the calculated values.

(B) 12.1 eV: This energy difference matches ΔE3 and ΔE4.

(C) 10.2 eV: This energy difference matches ΔE1 and ΔE2.

(D) 13.6 eV: This energy difference does not match any of the calculated values.

Therefore option B and C are correct.

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Both the car and truck will experience the equal magnitude of force during the collision.

According to Newton's Third Law of Motion, the forces experienced by the truck and the car after a collision are equal and opposing.

Due to the automobile's lighter weight and smaller size compared to the truck, the damage brought on by the accident can be more severe for the car.

The car will, sustain far greater damage. This is due to the car's inability to withstand as much exertion as the truck can. They would both feel the same force in the event of a collision between two cars, but the smaller vehicle would be far less able to withstand it, which would cause it to be damaged.

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The collisions that are considered inelastic are the ball of clay dropped onto the floor (clay sticks to the floor) and the bullet colliding with a block of wood (bullet embedded in the wood).

The collision of a golf club hitting a golf ball and the rubber ball dropped onto the floor are not specified as inelastic in the given options.An inelastic collision is one in which kinetic energy is not conserved, meaning that the total kinetic energy of the system before the collision is different from the total kinetic energy after the collision. In the case of the ball of clay dropped onto the floor, the clay sticks to the floor, resulting in a loss of kinetic energy and deformation of the clay, indicating an inelastic collision.

Similarly, when a bullet collides with a block of wood and gets embedded, there is a loss of kinetic energy and deformation, indicating an inelastic collision. On the other hand, the golf club hitting a golf ball and the rubber ball dropped onto the floor do not provide sufficient information to determine if the collisions are specifically inelastic.

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The cost of energy production is X SR/kWh. Maximum efficiency occurs at Y MW load. To increase output from 60MW to 90MW, Z MW additional input is needed.

a. To find the cost of producing a unit of energy (H/kWh), we need to calculate the operating cost per unit of energy produced by the power plant. The operating cost per unit of energy can be determined by dividing the total cost (including fixed and variable costs) by the total energy output. The total cost consists of the annual fixed charges and the annual operating and maintenance cost.

First, let's calculate the fixed charges per year:

Fixed charges = Installed capacity × Capital cost × FCR

Fixed charges = 140 MW × 2400 SR/kW × 11%

Fixed charges = 369,600 SR/year

Next, let's calculate the variable cost per year:

The variable cost is based on the fuel price and the energy output. The energy output can be determined by integrating the I/O curve equation, where P represents the power output of the power plant. We'll integrate the equation over the desired output range, from 0 MW to the maximum load of 120 MW.

Variable cost = ∫[0, P] (80 + 6P + 0.009P^2) dP

Variable cost = [80P + 3P^2 + 0.003P^3/3] evaluated from 0 to P

Variable cost = 80P + 3P^2 + 0.003P^3/3

Now, we can calculate the total cost per year:

Total cost = Fixed charges + Annual O&M cost + Variable cost

Total cost = 369,600 SR/year + 45,000,000 SR/year + (80P + 3P^2 + 0.003P^3/3)

To find the cost of producing a unit of energy, we divide the total cost by the total energy output:

H/kWh = Total cost / Total energy output

b. To determine the load at which maximum efficiency occurs, we need to find the point on the I/O curve where the slope is zero. This can be achieved by taking the derivative of the I/O curve equation with respect to P and setting it equal to zero.

d(I/O curve)/dP = 6 + 0.018P = 0

P = -6 / 0.018

P = -333.33 MW

Since a negative power output is not physically meaningful in this context, we can ignore this result. Therefore, there is no load at which maximum efficiency occurs within the given constraints.

c. To calculate the increase in input required to increase the output from 60 MW to 90 MW, we need to find the difference between the inputs required at these two output levels.

Input required at 60 MW: P1 = 60 MW

Input required at 90 MW: P2 = 90 MW

Increase in input = P2 - P1

Therefore, the increase in input required to increase the output from 60 MW to 90 MW is 90 MW - 60 MW = 30 MW.

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Answer:

c 0.10

Explanation:

V=IR

12.0V=I x 120.12ohms

I=0.099

I= 0.10