What principle does a heat engine take advantage of in order to use heat to perform work?

A. Magnets can convert motion into electrical energy
B. The speed of atoms increases when heat is added
C. Fluids expand when heat is added to them
D. Energy can be created from nothing​

The distance between the central bright fringe and the first bright fringe on the screen is approximately 8.52E-3 meters.

In Young's double-slit experiment, the distance between the central bright fringe (m = 0) and the first bright fringe (m = 1) can be calculated using the following formula:

y = (m * λ * L) / d

where:

y is the distance between the fringes on the screen,

m is the order of the fringe (0 for the central bright fringe, 1 for the first bright fringe),

λ is the wavelength of the light,

L is the distance from the slits to the screen, and

d is the distance between the slits.

Given the values:

λ = 4.57E-7 m (blue light wavelength)

d = 2.42E-4 m (distance between the slits)

L = 4.5 m (distance from the slits to the screen)

For the central bright fringe (m = 0), the distance (y) is:

y = (0 * 4.57E-7 m * 4.5 m) / 2.42E-4 m

y = 0

Therefore, the central bright fringe coincides with the point where the two beams of light overlap.

For the first bright fringe (m = 1), the distance (y) is:

y = (1 * 4.57E-7 m * 4.5 m) / 2.42E-4 m

y ≈ 8.52E-3 m

This calculation demonstrates how the interference pattern in Young's experiment is formed, with bright and dark fringes being produced based on the constructive and destructive interference of the light waves from the two slits. The distance between these fringes depends on the wavelength of light, the separation of the slits, and the distance between the slits and the screen.

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The velocity, expressed in terms of  ME, RE is given as \(V_0 = \sqrt{98.99R_E}\).

The maximum height that the rocket could reach if launched vertically is H = (¹/₂v₀²)/g.

The maximum height reached by the rocket can be modeled using conservation of energy as shown below;

P.Ei + K.Ei = K.Ef + P.Ef

\(M_EgR_E + \frac{1}{2} M_EV_0^2= \frac{1}{2} M_E(\frac{V_o}{10} )^2+ M_Eg(6R_E)\\\\\frac{1}{2} M_EV_0^2 - \frac{1}{2} M_E(\frac{V_o}{10} )^2 = M_Eg(6R_E) - M_EgR_E\\\\0.495M_EV_0^2= 5gM_ER_E\\\\0.495V_0^2= 5gR_E\\\\V_0 = \sqrt{\frac{5gR_E}{0.495} } \\\\V_0 = \sqrt{98.99R_E}\)

P.E = K.E

mgH = ¹/₂mv²

H = (¹/₂v₀²)/g

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The most true response is: there are many situations in which difference between energy entering in a system and leaving a system is so small that we can ignore it - so some systems can be treated as if they are closed even they are not.

Energy cannot be created or destroyed, according to the rule of conservation of energy. However, it is capable of change from one form to another. An isolated system's total energy is constant regardless of the types of energy present.

The law of energy conservation is adhered to by all energy forms. In a nutshell, the law of conservation of energy asserts that the system's total energy is conserved in closed systems, or systems that are separated from their environment.

In practical life no system is ever truly isolated from the rest of the universe. No system is truly closed. There will always be some amount of energy entering or leaving a system.

But there are many situations in which difference between energy entering in a system and leaving a system is so small that we can ignore it - so some systems can be treated as if they are closed even they are not.

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The direction of the magnetic and electric fields are equal and opposite directions. So the magnitude is in such a way they cancel out each other to give a net force of zero. So that the charged particle does not deflect.

Consider a region in which the magnetic field, electric field, and velocity of the charged particle are perpendicular to each other.  To move a charged particle undeflected, the net force on the charged particle must be zero.

qE=qVB

V= \(\frac{E}{B}\)

The direction of the magnetic and electric fields are equal and opposite directions. So the magnitude is in such a way they cancel out each other to give a net force of zero. So that the charged particle does not deflect.

An electric-powered area (occasionally E-subject) is the bodily field that surrounds electrically charged debris and exerts a force on all differently charged particles inside the discipline, both attracting or repelling them. It also refers to the bodily field of a machine of charged debris.

Electric assets are associated with each factor in the area when the fee is found in any shape. The value and direction of the electric discipline are expressed via the price of E, called electric powered field power or electric subject depth or clearly the electric discipline. An electric-powered area (every now and then E-discipline) is the bodily subject that surrounds electrically charged particles and exerts a force on all differently charged particles inside the discipline, either attracting or repelling them. It also refers to the bodily field of a system of charged particles.

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Complete Question:

Write the expression for the force f, acting on a charged particle of charge′q ′, moving with a velocity v  in the presence of both electric field  E and magnetic field B. Obtain the condition under which the particle moves undeflected through the fields.

The force that results in the decrease in speed from the midpoint to the end of the track is friction. The friction force slows down the vehicle because it acts in the opposite direction of the car's motion.

The force that would cause the Hot Wheels car to slow down from the midpoint of the track to the end of the track is friction between the car's wheels and the track.

Friction is a force that opposes motion between two surfaces in contact.

In this case, the wheels of the car and the surface of the track are in contact, and the friction force acts in the opposite direction of the car's motion, which slows it down.

As the Hot Wheels car travels down Track #2 during the Speed Lab activity, its initial velocity decreases due to friction.

Friction is a resistance force that opposes motion.

It is caused by the interaction between the surfaces in contact. In this case, the surface of the track and the wheels of the car are in contact.

When the car is moving, there is friction between the two surfaces.

The direction of the friction force is opposite to the direction of motion of the car.

This means that the friction force slows the car down.

In conclusion, the force that results in the decrease in speed from the midpoint to the end of the track is friction.

The friction force slows down the vehicle because it acts in the opposite direction of the car's motion.

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To create an electromagnetic induction portfolio, we will conduct an experiment to demonstrate the phenomenon of electromagnetic induction. The setup which will be used is explained as paragraph below.

1. A copper coil will be wound around a cylindrical core made of a non-magnetic material like wood or plastic. The number of turns of the coil will be recorded for future reference.

2. A magnet will be attached to one end of a metal rod, which can be inserted into the center of the coil.

3. A galvanometer will be connected in series with the coil to detect any current flowing through the circuit.

4. A power supply will be used to provide a constant voltage to the circuit.

5. A timer will be used to record the time taken for the magnet to move through the coil.

The independent variable in this experiment is the speed at which the magnet is moved through the coil. We will vary the speed of the magnet by changing the time taken for it to move through the coil.

The dependent variable in this experiment is the voltage induced in the coil. The voltage induced will depend on the speed at which the magnet is moved through the coil.

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This question is incomplete, the complete question is;

The vector sum of the forces acting on the beam is zero, and the sum of the moments about the left end of the beam is zero.

(a) Determine the forces and and the couple

(b) Determine the sum of the moments about the right end of the beam.

(c) If you represent the 600-N force, the 200-N force, and the 30 N-m couple by a force F acting at the left end of the beam and a couple M, what is F and M?

Answer:

a)

the x-component of the force at A is \(A_{x}\) = 0

the y-component of the force at A is \(A_{y}\)  = 400 N

the couple acting at A is; \(M_{A}\) = 146 N-m

b)

the sum of the momentum about the right end of the beam is;  ∑\(M_{R}\)  = 0

c)

the equivalent force acting at the left end is; F = -400J ( N)

the couple acting at the left end is; M = - 146 N-m

Explanation:

Given that;

The sum of the forces acting on the beam is zero ∑f = 0

Sum of the moments about the left end of the beam is also zero ∑\(M_{L}\) = 0

Vector force acting at A, \(F_{A}\) = \(A_{x}i\) + \(A_{y}j\)

Now, From the image, we have;

a)

∑f = 0

\(F_{A}\) - 600j + 200j = 0i + 0j

\(A_{x}i\) + \(A_{y}j\) - 600j + 200j = 0i + 0j

\(A_{x}i\) + (\(A_{y}\) - 400)j = 0i + 0j

now by equating i- coefficients'

\(A_{x}\) = 0

so, the x-component of the force at A is \(A_{x}\) = 0

also by equating j-coefficient

\(A_{y}\) - 400 = 0

\(A_{y}\)  = 400 N

hence, the y-component of the force at A is \(A_{y}\)  = 400 N

we also have;

∑\(M_{L}\) = 0

\(M_{A}\)  - ( 30 N-m ) - ( 0.380 m )( 600 N ) + ( 0.560 m )( 200 N ) = 0

\(M_{A}\) - 30 N-m - 228 N-m + 112 Nm = 0

\(M_{A}\) - 146 N-m = 0

\(M_{A}\) = 146 N-m

Therefore, the couple acting at A is; \(M_{A}\) = 146 N-m

b)

The sum of the moments about right end of the beam is;

∑\(M_{R}\) = (0.180 m)(600N) - (30 N-m) - ( 0.56 m)(\(A_{y}\) ) + \(M_{A}\)

∑\(M_{R}\) = (108  N-m) - (30 N-m) - ( 0.56 m)(400 N ) + 146 N-m

∑\(M_{R}\) = (108 N-m) - (30 N-m) - ( 224 N-m ) + 146 N-m

∑\(M_{R}\)  = 0

Therefore, the sum of the momentum about the right end of the beam is;  ∑\(M_{R}\)  = 0

c)

The 600-N force, the 200-N force and the 30 N-m couple by a force F which is acting at the left end of the beam and a couple M.

The equivalent force at the left end will be;

F = -600j + 200j (N)

F = -400J ( N)

Therefore, the equivalent force acting at the left end is; F = -400J ( N)

Also couple acting at the left end

M = -(30 N-m) + (0.560 m)( 200N) - ( 0.380 m)( 600 N)

M = -(30 N-m) + (112 N-m) - ( 228 N-m))

M = 112 N-m - 258 N-m

M = - 146 N-m

Therefore, the couple acting at the left end is; M = - 146 N-m

Answer:

pictures please

Explanation:

I need a picture so I can tell you

There is decreased pressure on the air molecules as one moves higher and the air is thinner

We know that the air pressure decreases with height. This implies that the air is thinner as you move up to higher altitude. This is the idea behind the use of the phrase; "Thin air".

Now, owing to the fact that there is decreased pressure on the air molecules as one moves higher and the air is thinner, it is much harder to breath until her aunt adjusts to the higher altitude.

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

where

f is the force

m is the mass

From the question

f = 20 N

m = 10 kg

We have

\(a = \frac{20}{10} \\ \)

We have the final answer as

Hope this helps you

Answer:.

Explanation:.

Take the moment car A starts to accelerate to be the origin. Then car A has position at time t

x = (20.0 m/s) t + 1/2 (2.10 m/s²) t²

and car B's position is given by

x = 300 m + (27.0 m/s) t

Car A overtakes car B at the moment their positions are equal:

(20.0 m/s) t + 1/2 (2.10 m/s²) t² = 300 m + (27.0 m/s) t

300 m + (7.00 m/s) t - (1.05 m/s²) t² = 0

==>  t ≈ 20.6 s

In his famous gold foil experiment, Ernest Rutherford discovered that the atom was mostly composed of empty space, and that a small, dense nucleus containing the majority of the atom's mass was located at its center.

What is Rutherford?
First Baron Rutherford of Nelson Ernest Rutherford, OM, FRS, HonFRSE The father of nuclear physics is, a New Zealander who lived from 30 August 1871 to 19 October 1937. He is regarded as the greatest experimenter since Michael Faraday by Encyclopaedia Britannica (1791–1867). He worked outside of his home country for a significant portion of his career, both in Canada and in the Kingdom. Early research by Rutherford led to the discovery of the radioactive element radon, the idea of radioactive half-life, and the classification and naming of alpha and beta radiation. At McGill University in Quebec, Canada, this work was completed. It served as the foundation for his 1908 Nobel Prize in Chemistry, which was given in recognition of his studies into to the disintegration of a elements.

He also found that a small percentage of alpha particles, which are positively charged particles, were deflected rather than passing straight through the gold foil. This led to the conclusion that the atom was composed of a positively charged nucleus surrounded by negatively charged electrons.

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Answer:

a. hydroelectric power plant

When L = L₁, the circuit is a series RL circuit. The voltage across the inductor is given by Vₗ = XL₁i, where XL₁ = ωL₁ is the inductive reactance and i is the current flowing through the circuit. The voltage across the resistor is given by VR = Ri. The voltage across the capacitor is zero since it is connected in series with the inductor and the resistor.

The total voltage across the circuit is given by v = V√2 cos(ωt). By Kirchhoff's voltage law, we have v = Vₗ + VR,

V√2 cos(ωt) = XL₁i + Ri

The current i can be written as i = (1/Z) V√2 cos(ωt - φ), where Z = √(R² + XL₁²) is the impedance of the circuit and φ is the phase angle between the current and the voltage. Substituting i into the equation above, we get:

V√2 cos(ωt) = XL₁/Z V√2 cos(ωt - φ) + R/Z V√2 cos(ωt - φ)

Equating the coefficients of cos(ωt) and cos(ωt - φ), we get:

1 = XL₁/Z cos φ + R/Z sin φ

XL₁ sin φ = Z - R cos φ

tan φ = XL₁ / (Z - R cos φ)

The voltage across the inductor is given by:

Vₗ = XL₁ i = XL₁/Z V√2 cos(ωt - φ)

Vₗ/V = XL₁/Z cos φ

Substituting tan φ into this equation, we get:

Vₗ/V₁ = XL₁/Z₁ √[1 - (XL₁/Z₁)²] ... (1)

When L = L₂, the circuit is a series RC circuit. The voltage across the capacitor is given by VC = XC₂i, where XC₂ = 1/(ωC₂) is the capacitive reactance.  The total voltage across the circuit is given by v = V√2 cos(ωt). By Kirchhoff's voltage law, we have v = VC + VR, which gives:

V√2 cos(ωt) = XC₂i + Ri

Following the same steps as in the previous case, we can show that:

Vₗ/V₂ = XC₂/Z₂ √[1 - (XC₂/Z₂)²] ... (2)

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The material that the magnet attracts is Iron and hence the ideal solution is option D.

The magnet is the material that produces the magnetic field on its own. The magnetic field is the invisible field but it has the ability to attract other materials. Magnets are made up of ferromagnetic materials.

Ferromagnetic materials are materials that are permanently magnetized due to the unpaired electrons in the materials. Most of the Ferromagnetic materials are metals namely nickel, iron, etc.

When the magnet is brought close to the iron, the electrons in the iron are aligned in the direction of the magnetic field which makes the iron become magnetized. Thus, the attraction takes place between two magnetized objects.

Thus, the ideal solution is option D) Iron.

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The 99% confidence interval for the average maximum HP for the experimental engine is (610.12, 689.88).

To calculate the confidence interval for the experimental engines' average maximum HP, we can use the following formula:

To find the z-score for α=0.01, we can refer to a standard normal distribution table or use a calculator. The z-score is approximately 2.58.

Substituting the given values into the formula, we get:

CI = 650 ± 2.58*(60/√25) CI = 650 ± 30.96

Rounding to two decimal places, the confidence interval for the experimental engines' average maximum HP is:

CI = [619.04 HP, 680.96 HP]

Therefore, we can say with 99% confidence that the true average maximum HP for the experimental engines falls between 619.04 HP and 680.96 HP. Thus, we can conclude that the experimental engines' average maximum HP is likely to be within this range. However, note that this range does not include the manufacturer's claimed maximum HP of 630 HP, which may indicate that the engines are performing below expectations.

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Given:

The initial distance is

The initial velocity is

The acceleration is a = 5 m/s^2.

The time interval is t = 10 s.

To find the final position, x.

Explanation:

The final position can be calculated as

Thus, the final position is 230 m

Answer:

c. more redder

def not blue cuz thats hottest and def not luminous

Answer:

it is c... redder

Explanation:

because i just look it up on googl3

Based on what you learned about the roller coaster ride, the following statements about energy transformations that are true are: A. Kinetic energy can be converted into several other types of energyC. A change in an object's speed is evidence that the object's kinetic energy is changing.

The process of energy transformation is the conversion of one form of energy into another. This term describes the scientific process by which energy, in various forms, is transformed to do work. Energy transformation occurs in every physical system in the universe.

Kinetic energy can be converted into several other types of energy.Kinetic energy is the energy of a moving object. The energy is converted into various types of energy, such as electrical and thermal energy, as a result of movement. In a roller coaster, kinetic energy is converted into potential energy as the train goes up the lift hill. The potential energy is converted back into kinetic energy as the train goes down the first drop.

A change in an object's speed is evidence that the object's kinetic energy is changing.Kinetic energy changes when an object's speed changes. If an object slows down, its kinetic energy decreases, while if it speeds up, its kinetic energy increases. On the roller coaster, as the train moves up and down the track, its speed varies, causing changes in its kinetic energy.

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The mass of the Ball B is 1.35 x 10⁻⁶ kg.

Gravitational Force is described by Newton's law of universal gravitation, which states that the force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

The law of universal gravitation is important in many fields, including astronomy, physics, and engineering.

The gravitational force F between two objects of masses m1 and m2 separated by a distance r is given by:

F = G(m₁m₂)/r²

where G is the gravitational constant.

We can rearrange the equation to solve for the mass of Ball B:

m₂ = Fr²/Gm₁

Substituting the given values, we get:

m₂ = (8.7 x 10⁻¹⁰ N)(3.0 m)²/(6.6743 x 10¹¹ N(m^2/kg²))(30 N)

m₂ = 1.35 x 10⁻⁶ kg

Therefore, the mass of Ball B is approximately 1.35 x 10⁻⁶kg.

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The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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Answer:

a. Horizontal component  v = 12 m/s

b. Magnitude of velocity v = 20.78 m / s

Explanation:

Vₓ = 12.0 m / s eastward

β = 30.0 °

So

a.

Vt = Vₐ - Vₓ

Vₐ = 0 i

Vt = 0i - 12.0 = - 12 m/s

b.

Vₙ = 12 / sin (30 °)

Vₙ = 24 m / s

Vₙ = 24 * con (30 °)

Vₙ = 20.78 m / s

Answer:

correct answer is c

v = -0.8 m / s

Explanation:

This is a problem of quantity of movement, for this we must define a system formed by the two cars, so that the forces during the collision are internal and therefore the quantity of movement is conserved

initial

    p₀ = m₁ v₁ - m₂ v₂

final

    = (m₁ + m₂) v

We have taken the direction to the right as positive

    p₀ =p_{f}

    m₁ v₁ - m₂ v₂ = (m₁ + m₂) v

    v = (m₁ v₁ - m₂ v₂) / (m₁ + m₂)

we calculate

    v = (2  4 - 8  2) / (2 + 8)

    v = (8 -16) / 10

     v = -0.8 m / s

the negative sign indicates that the set is moving to the left

correct answer is c

Time of flight = 1.6 s

Horizontal distance = 64 m

Projectile motion is the form of motion experienced by an object or particle projected into a gravitational field, such as from the surface of the Earth, and moves along a curvilinear path only under the action of gravity.

For the given case,

h = vt + ¹/₂gt²

h = height of tower

v = initial velocity

t = time of flight

55 = 50sin30t + ¹/₂9.8t²

55 = 25t + 4.9t²

4.9t² + 25t - 55 = 0

t = 1.6 s

X = vₓt

X = horizontal distance

vₓ = horizontal velocity

t = time of flight

X =  (50 x cos30) x 1.6

X =  64 m

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Answer:

milligram 1000g

kilogram 1/1000 g

electrons negative particle outside nucleus

speed km/h

potential energy at rest

mixture sawdust + salt + iron filings

Explanation:

:D

1. 1000g -kilogram

2.1/1000 g - milligram

3. negative particle outside nucleus - electrons

4. km/h - speed

5.energy at rest - potential
6.  centimeter - cm

7. Sawdust + salt + iron filings - mixture

The energy by  virtue of its position is called the potential energy.

The km/h is the unit of speed.

Milligram is written as 1/1000 g.

1000 g is equal to 1 kilogram.

Electron are the negatively charged subatomic particles rotating outside the nucleus.

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Answer: Molecules of H202, H20 and 02 are still forming. ( A P E X )

Explanation: I know this is late but for anyone looking at this later

The above question is incomplete, I think the original  question is

Belinda observes that the reaction 2H20+02 2H2O2 appears to have stopped because the concentrations of reactants and products are not changing. Which statement is true at this point in the reaction?

A. Molecules of H₂O₂ are formed only when the reaction vessel is disturbed.

B. Molecules of H2O2 have stopped forming.

C. Molecules of H20 and O₂ have stopped forming.

D. Molecules of H2O2, H2O, and O2 are still forming.

At this point in the reaction, the system has reached a state of equilibrium i.e there is no net change in the concentrations of reactants and products. So the Molecules of H2O2 have stopped forming. The correct option is B.

In chemistry, a state of equilibrium refers to a situation where the concentrations of reactants and products in a chemical reaction are no longer changing over time.

This occurs when the rates of the forward and reverse reactions are equal, and there is no net change in the concentrations of reactants and products.

At equilibrium, the system is in a dynamic state, where the forward and reverse reactions continue to occur, but at the same rate, resulting in no overall change in the concentrations of the species involved in the reaction. The equilibrium state is typically characterized by the equilibrium constant, which is a measure of the relative concentrations of reactants and products at equilibrium for a given reaction under specific conditions of temperature, pressure, and concentration.

Here in this question,

The molecules of H2O2 have stopped forming. This means that the forward reaction (2H2O + O2 → 2H2O2) and the reverse reaction (2H2O2 → 2H2O + O2) are occurring at the same rate, resulting in no net change in the concentration of H2O2. However, molecules of H2O and O2 are still being consumed and produced as they are involved in the reaction, but their concentrations are not changing because they are being replenished at the same rate that they are being consumed.

Therefore, the correct answer is B i.e Molecules of H2O2 have stopped forming.

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Answer:

False

Explanation:

Answer:

Solar and nuclear power generate more than 99 percent of our civilization's energy. Every other important source of energy is a combination of these two. The majority of them are solar in nature. We discharge previously collected solar energy when we burn wood.

and

Nuclear energy, fossil energy (oil, coal, and natural gas), and renewable energy (wind, solar, geothermal, and hydropower) are all examples of primary energy sources.

Explanation:

Answer:

\(1.60*10^{5} N\)

Explanation:

\(1.00 * 10^{5} Pa = 1.00 * 10^{5} \frac{N}{m^{2} }\)

\(1.00 * 10^{5} \frac{N}{m^{2} } * 1.60 m^{2} =1.60*10^{5} N\)