What normal force does a horizontal table exert on a 3.5 kg book that sits at rest?

Answers

Answer 1

Answer:

34.3N

Explanation:

The normal force, denoted by F(N), is the force exerted on an object by a surface. The normal force in this case is acting in an opposite manner but equal magnitude to the force of gravity.

F(N) = Fg

Where;

F(N) = Normal force

Fg = gravitational force

Fg = mg

Where;

m = mass (kg)

g = acceleration due to gravity

F(N) = mg

F(N) = 3.5kg × 9.8m/s²

F(N) = 34.3N

Hence, the normal force acting on the object is 34.3N.


Related Questions

7. State condition of equilibrium when a borly is acted upon by a number of parallel forces. A uniform metal tube of length 5cm and mass 9 kg is suspended horizontally by two vertical wire attaches at 50cm and 150cm respectively from the ends of the tuber Find the tension in each wire. in tril Solution -​

Answers

According to the question the tension in each wire is 1.96 N.

What is tension?

Tension is a term that describes the psychological and physical state of a person or system in which there is a high degree of stress, uncertainty, and anxiety. It is often associated with conflict and is often experienced when individuals or groups feel threatened or constrained in some way. Tension can be experienced in a variety of different contexts, from interpersonal relationships to the workplace. It can result from a variety of different factors, including a lack of communication, conflicting goals or expectations, and unmet needs.

The body is in equilibrium when the sum of all forces acting on it is equal to zero. In this case, the forces acting on the metal tube are the two wires and the weight of the tube due to gravity.

The tension in each wire is equal to the weight of the tube divided by the length of the tube. This is because the tube is suspended horizontally, so the forces in each wire must be equal in order to keep the tube in equilibrium.

Therefore, the tension in each wire is:

T = (9 kg × 9.8 m/s2) / (5 cm × 0.01 m)

= 1.96 N

Therefore, the tension in each wire is 1.96 N.

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It you balance a weight of 20 N at the 15 cm MARK and want to balance a weight of on the other side of the meter stick at 70 cm MARK, what weight should you place there

Answers

Answer:

The weight that will balance the meter stick at 70 cm mark is 35N

Explanation:

Given;

first weight at 15 cm mark, W₁ = 20 N

second weight at 70 cm mark, W₂ = ?

A sketch of the question in diagram form;

The center of gravity of the meter stick is 50 cm

                     15cm               50cm         70cm

0---------------------------------------Δ------------------------------------------100cm

                     ↓                                           ↓

                     20N                                      W₂

                     <------------------>|<--------------->

                                35cm               20cm

Take moment about the pivot;

Clockwise moment = anticlockwise moment

W₂(20cm) = 20N(35 cm)

W₂ = (20 x 35) / (20)

W₂ = 35 N

Therefore, the weight that will balance the meter stick at 70 cm mark is 35N

What force acts on a projectile in the horizontal direction?

Answers

The force that acts on a projectile in the horizontal direction is Gravitational force.


A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.

Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Horizontal forces are not required to keep a projectile moving horizontally. Hence, The only force acting upon a projectile is gravity.


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A particle performing circular motion along the path of radius 2 metre with linear acceleration 5 metre per second square find its angular acceleration​

Answers

Answer:

What is the question though?

Explanation:

Mudflows composed of soil, volcanic debris, and water can occur as the result of an explosive volcanic eruption. What are these mudflows called?

Answers

These mudflows are called Lahar.

A quickly moving mixture of rock debris and water that begins on a volcano's slopes is referred to as a lahar in Indonesian. Other names for lahars are volcanic mudflows and debris floods. The size, pace, and volume of material transported by a moving lahar can constantly alter as it rushes downstream. It resembles a swirling slurry of wet concrete.

The melting of snow and ice as well as the ingestion of river or lake water by the moving slurry may both add to its water consumption. A lahar's starting flow may be quite tiny, but as it entrains and integrates everything in its path, including rocks, dirt, vegetation, even structures like houses and bridges, it may increase in volume.

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Jamal has a fan that plugs into the wall. When Jamal plugs in the fan and turns it on, the blades spin and make the air around them move.


Jamal's fan uses _______ energy to cause motion.
A.
electrical
B.
light
C.
sound
D.
heat

Answers

The answer is A,electrical energy
A because when he is plugging it it is using electrical energy to move the fan

What is a pendulum?

A.)A pendulum is a grandfather clock.

B.)A pendulum is a mass suspended on the bottom of a string.

C.)A pendulum is several weights tied together and arranged in a circle.

D.) A pendulum is the time it takes for a bob to swing back and forth one time.

Answers

B) A pendulum is a mass suspended on the bottom of a string.

A pendulum is a simple mechanical device that consists of a mass (known as the bob) suspended from a fixed point by a string, wire, or rod. When the bob is pulled to one side and released, it swings back and forth under the influence of gravity, forming a regular pattern of motion. The time it takes for the pendulum to complete one full swing (i.e., from one extreme position to the other and back again) is known as its period. The period of a pendulum is affected by the length of the string and the strength of gravity. The longer the string, the longer the period, and the stronger the gravity, the shorter the period.Pendulums have a wide range of practical applications, such as timekeeping, as seen in grandfather clocks. They are also used in scientific experiments to measure time intervals and gravitational acceleration.

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4. What is stellar parallax?

Answers

Answer:

I don't k own what it is dad fjf f fjff

Answer:

Explanation:

Stellar parallax is the apparent shift of position of any nearby star against the background of distant objects

Which of the following means that an
image is real?
A. +do
B. +di
c. -di
D.-do

Answers

Answer:

B

Explanation:

A train is slowing down with an average acceleration of −6.0 m/s2. If its initial velocity is 60.0 m/s, how far does it travel in 5.0 seconds?

140 m
230 m
270 m
530 m

Answers

If its initial velocity is 60.0 m/s, The velocity is 210 m.

What is Average acceleration?

Acceleration is crucial for understanding everything from the small world of subatomic physics to the huge expanses of space and our everyday experience.

In ordinary language, to accelerate is to increase speed; to depress the brakes will make a car slow down. For instance, we are familiar with our car's acceleration. The magnitude of the change in velocity over a particular period of time increases with acceleration.

linear particle accelerator studies, subatomic particles are accelerated to extremely high velocities in collision investigations, which reveal details about the structure of the subatomic world and the universe's beginning.

Therefore, If its initial velocity is 60.0 m/s, The velocity is 210 m.

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A spring scale hung from the ceiling stretches by 5.9 cm
when a 1.6 kg
mass is hung from it. The 1.6 kg
mass is removed and replaced with a 2.1 kg
mass.
Part A
What is the stretch of the spring?
Express your answer with the appropriate units.

Answers

The stretch of the spring is proportional to the weight of the mass hung from it. Since the spring stretches by 5.9 cm when a 1.6 kg mass is hung from it, we can use this information to find the stretch when a 2.1 kg mass is hung from it.

The stretch of the spring is given by:

stretch = (mass x gravity x length) / (spring constant)

where mass is the mass hung from the spring, gravity is the acceleration due to gravity (9.81 m/s^2), length is the stretch of the spring, and the spring constant is a measure of the stiffness of the spring (measured in N/m).

We can rearrange this equation to solve for the stretch of the spring:

stretch = (mass x gravity x length) / (spring constant)

length = (spring constant x stretch) / (mass x gravity)

Substituting the given values, we get:

length = (spring constant x 0.059 m) / (1.6 kg x 9.81 m/s^2)

Simplifying, we get:

length = 0.236 m

Therefore, the stretch of the spring when a 2.1 kg mass is hung from it is 0.236 m.

Suppose the student in (Figure 1) is 68kg, and the board being stood on has a 12kg mass. What is the reading on the left scale? What is the reading on the right scale?

Suppose the student in (Figure 1) is 68kg, and the board being stood on has a 12kg mass. What is the

Answers

The equilibrium conditions allow to find the results for the balance forces are:

F₁ = 225.4 N F₂ = 558.6 N

When the acceleration is zero we have the equilibrium conditions for both linear and rotational motion.

            ∑ F = 0

            ∑ τ = 0

           

Where F are the forces and τ the torques.

The torque  is the product of the force and the perpendicular distance to the point of support,

The free-body diagrams are diagrams of the forces without the details of the bodies, see attached for the free-body diagram of the system.

We write the translational equilibrium condition.

           F₁ - W₁ - W₂ + F₂ = 0

We write the equation for the rotational motion, set our point of origin at scale 1, and the counterclockwise turns are positive.

         F₂ 2 - W₁ 1 - W₂ 1.5 = 0\(\frac{W_1 \ 1 + W_2 \ 1.5}{2}\)

Let's calculate F₂

         F₂ = \(\frac{W_1 \ 1 + W_2 \ 1.5 }{2}\)  

         F₂ = (m g + M g 1.5)/ 2

         F₂ = \(\frac{(12 + 68 \ 1.5 ) \ 9.8}{2}\)  

         F₂ = 558.6 N

We substitute in the translational equilibrium equation.

         F₁ = W₁ + W₂ - F₂

         F₁ = (m + M) g - F₂

         F₁ = (12 +68) 9.8 - 558.6

         F₁ = 225.4 N

In conclusion using the equilibrium conditions we can find the forces of the balance are:

F₁ = 225.4 N F2 = 558.6 N

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Suppose the student in (Figure 1) is 68kg, and the board being stood on has a 12kg mass. What is the

Answer ONLY if you know 100% that it's correct.

Using the data below, what would be the independent variable?

A. Type of Coke (Diet Coke or Coca Cola)

B. Trial number

C. Height of Explosion

D. Number of Mentos

Answers

A. Type of Coke (Diet Coke or Coca Cola)

. If an object has a mass of 200 kg ant a velocity of 30 m/s... what is the Kinetic Energy
(KE) of the object?

Answers

Answer:

90,000 J

Explanation:

The kinetic energy (KE) of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass

v is the velocity

From the question we have

\(k = \frac{1}{2} \times 200 \times {30}^{2} \\ = 100 \times 900\)

We have the final answer as

90,000 J

Hope this helps you

Answer:

When it hits a wooden target, the ball exerts a force on the fibers in the wood, splintering. First, heavier objects that are moving have more kinetic energy than lighter ones: a In equation form: kinetic energy (joules) = 1/2 x mass (kg) x velocity2 (m/s)  Note that: 200 kg-m2/s2 = 200 (kg-m/s2) x m = 200 N x m = 200 joules.

Explanation:

Which of the following is true at the point where you reach the top of your jump on a trampoline?

The mechanical energy is zero
he potential energy is at maximum
The kinetic energy and potential energy are equal.
The potential energy is zero.

Answers

The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.

What is Potential Energy

Potential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.

This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.

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Using the given data table, calculate the acceleration of the skateboarder. You can use either form of the
equation:

Using the given data table, calculate the acceleration of the skateboarder. You can use either form of

Answers

The acceleration of skateboard on road A will be 7.74 \(m/s^{2}\)

The acceleration of skateboard on road B will be 3.87 \(m/s^{2}\)

The acceleration of skateboard on road C will be 9.68 \(m/s^{2}\)

force = mass * acceleration

mass1 = 62 kg

force1 = 480 N

acceleration1 = force / mass

                     = 480 / 62 = 7.74 \(m/s^{2}\)

mass2 = 62 kg

force2  = 240 N

acceleration 2  = 240 / 62 = 3.87  \(m/s^{2}\)

mass 3 = 62 kg

force 3  = 600 N

acceleration 3  = 600 / 62  = 9.68  \(m/s^{2}\)

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A small mass is released from rest at a very great distance from a larger stationary mass. Draw a graphs best represents the gravitational potential energy U of the system of the two masses as a function of time T.

Answers

Answer:

attached below

Explanation:

Gravitational potential

energy = \(- \frac{GmM}{r}\) ,

V ∝ \(- \frac{1}{r}\)  

attached below is a graph that represents the gravitational potential energy U

A small mass is released from rest at a very great distance from a larger stationary mass. Draw a graphs

Gravitational potential energy is the energy held in an entity as a result of its vertical position or length. This gravitational pull of a planet on an object causes the information to be stored.

This is connected with gravitational pull since it takes work to lift anything against the gravity of the Earth.

Freshwater in a raised lake or kept behind a dam demonstrates gravitational force.

According to the formula:

Gravitational potential energy \(\bold{=-\frac{GMm}{r^2}}\)

Therefore

\(\to \bold{V \propto -\frac{1}{r}}\)

Therefore, the answer is "Option d"

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A small mass is released from rest at a very great distance from a larger stationary mass. Draw a graphs

7. [Honors] A turn of radius 100 m is being designed for a speed of 25 m/s. At what angle should the turn be banked?​

Answers

Answer:

The angle at which a turn should be banked depends on the speed of the vehicle, the radius of the turn, and the acceleration due to gravity. To calculate the angle, we can use the following formula:

tanθ = v^2 / (g * r)

where

θ is the angle at which the turn should be banked (in radians)

v is the speed of the vehicle (in m/s)

g is the acceleration due to gravity (approximately 9.81 m/s^2)

r is the radius of the turn (in meters)

Plugging in the values given in the problem, we get:

tanθ = (25 m/s)^2 / (9.81 m/s^2 * 100 m)

tanθ = 6.44

Taking the inverse tangent of both sides, we get:

θ = tan^-1(6.44)

θ ≈ 80.5 degrees

Therefore, the turn should be banked at an angle of approximately 80.5 degrees.

1. Two charges are separated by a distance of 1 cm. One charge has a value of 7 micro Coulombs. The other charge has a value of 10 micro Coulombs. What is the force between them, in pounds. Make sure to include the sign of the force which will be positive if the charges repel each other and negative if they attract each other.

2. 12 gauge copper wire is normally used in house wiring. When aluminum wire is used one needs to use a smaller gauge size to obtain the same resistance, 40 ft of 12 gauge copper wire was calculated. What would the resistance be if 10 gauge aluminum wire were used?

3. A 12 V automobile battery can supply 51 amps for one hour and cost $194. What is the cost of this electricity in cents per kWh?

4. Most of the body's resistance is in its skin. When wet, salts go into ion form, and the resistance is lowered. Thus, the resistance of the skin can go from 100,000 ohms when dry to 300 ohms when wet. What is the current that would be carried through the body, in milliAmperes, if you touched a 240 V power line while dry? Currents over 10 mA are almost always deadly.

Answers

1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.

3. The cost of electricity from the automobile battery is 38.6 cents per kWh.

4. The current that would be carried through the body is 0.8 mA if dry.

1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.

Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.

3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.

Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.

4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.

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Rita places a 2.5 kg block on a frictionless inclined plane that is 30 degrees above horizontal. She applies a horizontal force, which keeps the block from moving up or down the inclined plane. What is the magnitude of the force Rita applies?​

Answers

Answer:

14.2

Explanation:

find horizontal force of the weight = 2.5kg x 9.8 Sin30 = 12.3 N

to prevent the sliding she needs to pull horizontally

Fh = 12.3 /Cos 30 =14.2N

How strong would a magnetic field need to be in order to make a particle with a mass of 4 x 10−11 kg and a charge of 8 nC move in a circular path with a speed of 400 m/s and a radius of 0.5 m?

Answers

As a result, a particle with a mass of 4 x 10-11 kg and a charge of 8 nC needs a magnetic field of 1.0 Tesla to move in a circular path with a speed of 400 m/s and a radius of 0.5 m.

When is the strongest magnetic pressure acting on a charged particle in a magnetic area?

Thus, when a charged particle moves at a 90° angle to the field, the magnetic force acting on it is greatest.

In a magnetic subject, what is the pressure on a moving charge?

What force does a moving object experience in a magnetic field? As a charge moves through an electric and magnetic field, the Lorentz force acts on it. The total of magnetic and electric forces must be what it is.

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Particles q₁, 92, and q3 are in a straight line.
Particles q₁ = -5.00 10-6 C,q2 = +2.50 10-6 C, and
q3= -2.50 10-6 C. Particles q₁ and q₂ are separated
by 0.500 m. Particles q2 and q3 are separated by
0.250 m. What is the net force on q2?

Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right

Particles q, 92, and q3 are in a straight line.Particles q = -5.00 10-6 C,q2 = +2.50 10-6 C, andq3= -2.50

Answers

When three particles q1, q2, and q3 are in a straight line, the force experienced by q2 depends on the distance between the particles, the magnitude of the charges of the particles, and the relative position of the particles. The electric force on a charge q1 from a charge q3, which is at a distance r3 from the first charge, is governed by Coulomb’s Law.

In mathematical notation, Coulomb’s Law is expressed as:F = kq1q3 / r3²where F is the electric force, q1 and q3 are the magnitudes of the charges, r3 is the distance between them, and k is the Coulomb’s Law constant which is equal to 8.99 × 109 N·m2 / C2. The direction of the electric force can be positive or negative. If q1 and q3 are of the same sign, the force between them is repulsive, while if they are of opposite sign, the force is attractive.The electric force experienced by q2 due to the other two particles is the vector sum of the forces F13 and F23, which are given by:F13 = kq1q3 / r13²andF23 = kq2q3 / r23²where r13 is the distance between q1 and q3, and r23 is the distance between q2 and q3. The net force on q2 is given by:Fnet = F13 + F23The magnitude and direction of Fnet depend on the charges of the particles and the distance between them. If the two charges are of the same sign, then the force is repulsive and the net force will be in the direction of the force between them. If the two charges are of opposite signs, then the force is attractive, and the net force will be in the direction of the force between them.

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a body has a mass of 2kg.it accelerats from 20m/s to 40m/s in 4 seconds.the resultant force is

Answers

The resultant force is 8N  

Given that mass is 2kg , v= 40m/s, u =20m/s and we need to calculate resultant force
F=ma

m is given
so for a
v-u/t=a { first equation of motion }

40-20/4= 4
so a=4

F = ma =2*4 = 8N
The difference between the forces that are acting on an object as part of a system is known as the resultant force.
v = u + at is the first equation of motion. Here, v denotes the end speed, u the starting speed, an acceleration, and t the passage of time. The first equation of motion is provided by the velocity-time relation, which may be used to calculate acceleration.

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What is an increase of biodiversity over time after a natural or man-made disturbance

Answers

An increase of biodiversity over time after a natural or man-made disturbance is known as ecological succession.

What is force?

In physics, force is an influence that can cause an object to accelerate, change its direction of motion, or deform. Force is defined as any interaction that can modify the motion of an object. It is a vector quantity, meaning that it has both magnitude (or strength) and direction. Force is usually measured in units of Newtons (N) in the International System of Units (SI). The Newton is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared.

Here,

Ecological succession is the gradual process by which a community of living organisms changes over time after a disturbance has occurred. Disturbances can come in many forms, such as natural disasters like wildfires, hurricanes, or volcanic eruptions, or human-caused disturbances like clearcutting of forests or construction of roads. After a disturbance, the ecological community of the affected area undergoes a series of changes, starting with the colonization of new species that are able to survive and grow in the disturbed environment.

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why an object weighs less on moon than earth?​

Answers

Answer :

Since the moon has considerably less mass than the Earth, it will not pull objects toward itself at the strength that Earth will

A flat uniform circular disk (radius = 5.44 m, mass = 150 kg) is initially stationary. The disk is free to rotate in the horizontal plane about a frictionless axis perpendicular to the center of the disk. A 47.0-kg person, standing 1.54 m from the axis, begins to run on the disk in a circular path and has a tangential speed of 2.80 m/s relative to the ground. Find the resulting angular speed (in rad/s) of the disk.

Answers

The resulting angular speed of the flat, uniform circular disk is 0.237 rad/s.

What is angular momentum?

Angular momentum is a fundamental concept in physics that describes the rotational motion of an object around an axis. It is defined as the product of the moment of inertia of an object and its angular velocity with respect to a chosen axis.

We can use conservation of angular momentum to solve this problem. The initial angular momentum of the disk is zero because it is stationary. The final angular momentum of the system (disk + person) is:

L = Iω

where I is the moment of inertia of the disk and person about the axis of rotation, and ω is the resulting angular speed of the disk.

The moment of inertia of the disk about its axis is:

I_disk = (1/2)mr²

where the disk's radius is r and its mass is m.  Substituting the given values, we get:

I_disk = (1/2)(150 kg)(5.44 m)² = 2226.24 kg·m²

The moment of inertia of the person about the axis can be approximated as:

I_person = mr²

where r is the distance from the axis to the person. Substituting the given values, we get:

I_person = (47.0 kg)(1.54 m)² = 109.64 kg·m²

The total moment of inertia of the system is:

I = I_disk + I_person = 2226.24 kg·m² + 109.64 kg·m² = 2335.88 kg·m²

The final angular momentum of the system is:

L = Iω

where ω is the resulting angular speed of the disk. Substituting the given values, we get:

(2335.88 kg·m²)ω = (197.64 kg·m²/s)(2.80 m/s)

Solving for ω, we get:

ω = (197.64 kg·m²/s)(2.80 m/s) / (2335.88 kg·m²) = 0.237 rad/s.

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In a class experiment to determine information about free-fall acceleration, a watermelon and a pumpkin are each set to fall from the back of the stands at your football stadium.

a. If the watermelon and the pumpkin are both dropped at the same time, which one will hit the ground first?

b. If the watermelon is thrown downward with an initial speed of 10 m/s and the pumpkin is dropped, which one will hit the ground first? Show calculation to support your answer.

c. If it takes the watermelon 1 second to reach the ground when it is thrown downward at 10 m/s, how tall are the stands?

d. How long does it take the pumpkin to reach the ground if it is dropped from this height you calculated in part c?

Answers

Answer:

a) They both hit the ground at the same time

b) Watermelon will hit first, since its speed is faster than the pumpkin speed

c) h = 29,6 m

d)t = 3,02 sec

Explanation:

Equations for fall free movement are:

vf = v₀ + g*t       when   v₀ = 0   (dropped case)  vf = g*t

h = v₀*t + 1/2*g*t²

a) For both ( watermelon and pumpkin) the equation of speed is the same:

vf = g*t²    Both will have the same speed second through second

They both hit the ground at the same time

b) Now is watermelon is thrown with v₀ = 10 m/s

Watermelon will hit first since its speed is faster than the pumpkin speed

vf(watermelon) =  10 + g*t

vf₂ (pumpkin)   =  g*t

c) h = v₀*t + (1/2)*g*t²

h = (10)*1 + (1/2)*9,8*1

h = 10 + 19,6

h = 29,6 m

d)  h = g*t

t = 29,6/9,8

t = 3,02 sec

what would be the final size of the ballon in the example problem above if it were placed in a 18*C freezer?

Answers

Given data

The initial volume of the ballon is v = 2 L

The initial temperature is T = 20 C = 293 K

The ballon is placed inside the refrigerator at a temperator of T_f = - 18 C = 255 K

The pressure remains constant, the expression for the volume temperature relation is given as:

\(\frac{v}{T}=\frac{v_f}{T_{-f}}\)

Substitute the value in the above equation.

\(\begin{gathered} \frac{2\text{ L}}{293\text{ K}}=\frac{v_f}{255\text{ K}}_{} \\ v_f=1.740\text{ L} \end{gathered}\)

Thus, the final size of the ballon is 1.740 L.

A net force of 75 pounds acts on a body of 25 slugs. The body is initially at rest. What is its acceleration during the action of the force?​

Answers

The correct answer is 0.91 m/\(s^2\).

The pace at which a body increases its velocity is what is meant by the phrase "acceleration." It always moves in the same direction as the body when it moves.

The acceleration of an object is equal to the net force exerted on it divided by its mass, or a = F m, in accordance with Newton's second rule of motion. When the mass of an item and the net force acting on it are known, the acceleration of that object can be determined using this equation for acceleration.

Force F = 75 ponds = 33.62 N

initial velocity y =0

mass m = 25 slungs = 364.848 kg

time t = 12s

Acceleration of the body,

Acceleration = F/m

Acceleration = 333.62/364.848

Acceleration = 0.91 m/\(s^2\)

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Two children pull on ropes attached to a tree, as shown below:

At what angle in degrees, measured clockwise from North, does the resultant force act? Give your answer to the nearest degree without units.

Two children pull on ropes attached to a tree, as shown below:At what angle in degrees, measured clockwise

Answers

The direction of the resultant force is 48⁰.

Horizontal and vertical component of each force

The horizontal component of the force is calculated as follows;

10 N is inclined to 35⁰ to the horizontal

Fx = 10 x cos(35)

Fx = 8.19 N

6 N is inclined to 70⁰ to the horizontal

Fx = 6 x cos(70)

Fx = 2.05 N

Sum of x component forces

∑Fx = 8.19 + 2.05

∑Fx =  10.24

Vertical component of the force

The vertical component of the force is calculated as follows;

10 N is inclined to 35⁰ to the horizontal

Fy = 10 x sin(35)

Fy = 5.74 N

6 N is inclined to 70⁰ to the horizontal

Fy = 6 x sin(70)

Fy = 5.64 N

Sum of y component forces

∑Fy = 5.74 N + 5.64 N

∑Fy =  11.38 N

Direction of the resultant force

θ = arc tan(ΣFy/ΣFx)

θ = arc tan(11.38/10.24)

θ =  48⁰

Thus, the direction of the resultant force is 48⁰.

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