What name has been given to max plancks packets of light? what does it mean to say that the packets are quantized

Answer:

a.25J

Explanation:

m=0.5kg

g=10

h=5

potential energy=m×g×h

=0.5×10×5

=25J

Typically, the "refracted angle" is used to refer to the "angle of deviation."

Snell's Law is simply applied in this case.

Since n1sin1 = n2sin2,

The incidence angle is 1

The refracted angle is 2

The appropriate indices of refraction are n1 and n2.

the standard value for air, n1, is 1.

n2 = 1.5

As a result, the refractive indices of the two media may be related through the angle associated with incidence and refraction. The incident ray, the refracted ray, and the normal ray are all said to be on the same plane.

Snell's Law is particularly significant for optical technologies like fibre optics. According to Snell's Law, the refractive indices of the materials at the contact are proportional to the ratio of the sine of the angles of incidence and transmission.

The extension is obeyed by the e-ray Because the refractive index of an e-ray changes with the angle between the wave vector and optical axis, Snell's law applies. It is important to consider e-ray propagation in the uniaxial crystal.

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Answer:

Mass of substance m = 0.050Kg

Initial Temperature T₁ = 20°C

Final Temperature T₂ = 100°C

we have to calculate the heat absórbed by the lead .

Since spècific heat of lead is not gíven so we will take spècific heat of lead 128 J/kg°C

\( \diamond \bf \: Q\: = m \times c( \Delta \: t) \)Put the given value

\(\sf \longrightarrow \: Q = 0.050 \times 128 \times (100 - 20) \\ \\ \\ \sf \longrightarrow \: Q = 0.050 \times 128 \times (80) \\ \\ \\ \sf \longrightarrow \: Q = 6.4 \times 80 \\ \\ \\ \sf \longrightarrow \: Q = 512 \: joules\)

Therefore,

Answer:

[sə′plī ‚vōl·tij] (electricity) The voltage obtained from a power source for operation of a circuit or device.

Explanation:

hope this helps :)

(a) Velocity is zero (b) the time is 0.918 sec (c) the time is 1.836 sec (d) the distance is 14.688 m  (e) the angle in degree is 0 degree.

a) When the ball reaches its maximum height, its velocity is entirely in the vertical direction (y-axis) and has no horizontal component (x-axis or z-axis). The velocity vector at this point is <0, vy, 0>, where vy is the vertical component of velocity.

b) To find t when the ball reaches its maximum height, we can set the vertical component of velocity vy = 0, and use the equation of motion for vertical motion:

vy = v0y - gt

where v0y = 9m/s is the initial vertical velocity, g = 9.8 m/s^2 is the acceleration due to gravity, and t is the time since the ball was thrown.

0 = 9 - 9.8t

t = 9/9.8 = 0.918 s

c) The time t when the ball's height y returns to zero can be found by setting y = 0 in the equation of motion for vertical motion:

y = v0y x t - (1/2) x g x t^2

0 = 9t - 4.9t^2

4.9t^2 = 9t

t = 9/4.9 = 1.836 s

d) At the time calculated in part (c), when the ball's height y returns to zero, the range of the trajectory (x) can be found by using the equation of motion for horizontal motion:

x = v0x x t

x = 8 x 1.836 = 14.688 m

e) The angle in degrees with respect to the positive x-axis of the velocity at the time calculated in part (c) is found by using the horizontal component of the velocity vector.

The horizontal component of the velocity vector is vx = 8 m/s.

The angle of the velocity vector with respect to the positive x-axis is found by using the arctangent function.

angle = a tan(vy/vx) = a tan(0/8) = 0 degrees.

It's important to note that the range is the maximum distance that the ball travels horizontally, and it is reached at the time when the ball's height y returns to zero.

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Question - A small dense ball with mass 0.9 kg is thrown with initial velocity <8,9,0>m/s at time =0 from a location we choose to call the origin (<0,0,0>m). Air resistance is negligible.

(a) When the ball reaches its maximum height, what is its velocity?

(b) When the ball reaches its maximum height, what is time ?

(c) At a later time the ball's height  has returned to zero, which means that the arithmetic average value of  from =0 to this time is zero. At this instant, what is the time ?

(d) At the time calculated in part (c), when the ball's height  returns to zero, what is distance? (This is called the range of the trajectory.)

(e) What is the angle in degrees with respect to the positive x-axis of the velocity at the time calculated in part (c)? Present your answer as a positive value less than 360.

There are 4 potential models of how the expansion of the universe changes with time. The correct model description to fill in the blanks is as follows:

Since the beginning of the Big Bang, scientists believe the universe always expands. Every element of a galaxy slowly moves away from each other. There are 4 potential models for how the universe changes with time, which:

This question is incomplete. The complete query to this question is as follows:

Meanwhile, the blank sentences are as follows:

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Answer:

Venus and Earth have the diameter nearly equal in size

Answer:

Explanation:

The principle is that the slope of the line on a velocity-time graph reveals useful information about the acceleration of the object. If the acceleration is zero, then the slope is zero (i.e., a horizontal line). If the acceleration is positive, then the slope is positive (i.e., an upward sloping line).

The point of interest in the velocity time graph is the slope of the graph which represents the acceleration of the given moving body

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds², acceleration is defined as the ratio of velocity to time.

Only the constant acceleration is applicable to Newton's three equations of motion.

The acceleration of any item is represented by the slope of the velocity time graph.

The slope of the line on a velocity-time graph provides important details about the object's acceleration. The slope is 0 if the acceleration is zero. The slope is positive if the acceleration is positive and if the slope of the velocity time graph is negative the acceleration is negative

Thus, the point of interest in the velocity time graph is the slope of the graph which represents the acceleration of the given moving body.

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Projectile motion is a combination of constant motion in the horizontal direction, and accelerated motion in the vertical direction. Therefore, the correct answer option is: D. constant, accelerated.

Projectile motion can be defined as a form of motion which is experienced by a physical object (body) that is projected near the surface of planet Earth, while moving along a parabolic (u-shaped curve) path, and under the influence of a gravitational force only.

Based on scientific research and records by scientists such as Galileo, we can infer and logically deduce that the initial horizontal velocity of a physical object undergoing a projectile motion is always equal to its final horizontal velocity.

Additionally, Galileo stated that projectile motion combines constant or uniform motion in the horizontal direction and accelerated motion in the vertical direction.

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The total average power output of the sun is a complex question that requires a bit of background information. The sun is a massive ball of gas and plasma that is constantly undergoing nuclear fusion in its core.

This process releases vast amounts of energy in the form of electromagnetic radiation. The sun emits energy in all directions, which makes it an isotropic source. However, due to the vast distance between the sun and Earth, the amount of energy we receive from the sun is considerably less than its total output. The total average power output of the sun is estimated to be around 3.828 x 10^26 watts.

This figure is calculated by measuring the amount of energy emitted by the sun at all wavelengths and then integrating this over the entire surface area of the sun. This value is known as solar luminosity and is used to compare the energy output of stars of different sizes. However, it's important to note that not all of this energy reaches Earth. The atmosphere filters out some of the sun's radiation, and clouds, dust, and other particles can also block some of the energy.

Additionally, the Earth's distance from the sun also affects the amount of energy received. At the average Earth-Sun distance, the amount of energy received per unit area is known as the solar constant and is approximately 1361 watts per square meter. In summary, the total average power output of the sun is around 3.828 x 10^26 watts, but the amount of energy received on Earth is considerably less due to atmospheric and distance effects.

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The graph of the relationship between amplitude and decibel level of sound is not a linear graph but a logarithmic graph.

It is known as the Sound Intensity Level graph, where the amplitude of the sound is plotted on the x-axis, and the decibel level of sound is plotted on the y-axis.

As the amplitude of the sound increases, the decibel level increases as well. The relationship is not directly proportional, as a small change in amplitude can result in a significant change in decibel level. For example, a sound with an amplitude of 1 Pa has a decibel level of 0 dB, whereas a sound with an amplitude of 10 Pa has a decibel level of 20 dB. This indicates that the decibel level is increasing exponentially with the increase in amplitude.

Moreover, the graph shows that the human ear has a limited range of hearing, which is between 0 dB and 140 dB. Beyond this range, sounds become too loud to hear or can cause damage to the ear. Therefore, it is important to monitor the decibel level of sound to protect our hearing.

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A concave cosmetic mirror has a focal length of 52 cm . A 5.0-cm-long mascara brush is held upright 26 cm from the mirror. The ray is 17.3 cm away and height of the image is 3.3 cm.

The location of the image can be found using the mirror equation:

1/f = 1/d_o + 1/d_i

where f is the focal length, d_o is the object's distance from the mirror, and d_i is the distance of the image from the mirror. Plugging in the values given:

1/52 = 1/26 + 1/d_i

Solving for d_i, we get:

d_i = 17.3 cm

Since the object is held upright, the image will also be upright and on the same side of the mirror as the object, so the image distance is positive.

To find the height of the image, we can use similar triangles. The ratio of the height of the image (h_i) to the distance of the image from the mirror (d_i) is equal to the ratio of the height of the object (h_o) to the distance of the object from the mirror (d_o):

h_i / d_i = h_o / d_o

Plugging in the given values:

h_i / 17.3 = 5.0 / 26

Solving for h_i, we get:

h_i = 3.3 cm

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Answer:

gravity

Explanation:

the Forest of gravity causes objects to fall toward the center of the Earth.

Answer:

due to gravitational force.

The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.

Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.

Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:

∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du

The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.

Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.

Let us work through the steps:

Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x

Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du

Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.

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Answer:

it is less dense than the liquid it is placed in.  Explanation:

Answer:

The density of an object determines whether it will float or sink in another substance. An object will float if it is less dense than the liquid it is placed in. An object will sink if it is more dense than the liquid it is placed in.

A solid object will float on a liquid if the solid is less dense than the liquid.

We don’t often think about this, but ice floats on liquid water, because ice is less dense than water. It is one of the few substances whose solid is less dense than its liquid. If it weren’t, ice would drop to the bottom of the oceans and lakes, and these bodies of water would remain frozen year round. Life would almost certainly not have evolved on Earth if this were the case.

Explanation:

Answer:

You answer is C. A hamburger on the grill

What is Conduction?

Conduction is the transfer of heat through DIRECT CONTACT.

How can I tell the difference between Conduction, Convection, and Radiation?

To know how to find the difference, you must first now what each type of heat transfer is.

Conduction-the transfer of heat through DIRECT CONTACT.

Radiation-The transfer of heat without direct contact, energy

Convection-Heat rising and cold sinking

Just think about these definitions everytime you see a question like this!

Kepler's third law states that the square of the period of a planet's orbit around the sun is proportional to the cube of its average distance from the sun.

Kepler's third law, also known as the law of harmonies, is a mathematical relationship that describes the motion of planets around the sun. It states that the ratio of the cube of a planet's average distance from the sun to the square of its orbital period is constant for all planets in the solar system.

Mathematically, this can be expressed as T^2 = k*R^3, where T is the orbital period of the planet, R is its average distance from the sun, and k is a constant of proportionality. Kepler's third law is an important tool for astronomers to study and understand the dynamics of the solar system.

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(a) The angle θ is related to the angle of refraction ϕ through Snell's law, and its value can be determined using the given refractive index of linseed oil (1.48).

(b) Apply Snell's law to calculate the angle of refraction in water from the angle of incidence, θ.

How to determine angles using Snell's law?

Based on the information provided for Snell's law. it seems you are describing a situation involving the refraction of light at an interface between air, linseed oil, and water. Let's address your questions step by step:

The given angle of refraction in linseed oil (represented by φ) is 19.0° with the normal line NN. The refractive index of linseed oil is 1.48.

To determine the angle θ, we need to apply Snell's law, which states:

n₁sin(θ₁) = n₂sin(θ₂)

where n₁ and θ₁ represent the refractive index and angle of incidence in the first medium, and n₂ and θ₂ represent the refractive index and angle of refraction in the second medium.

In this case, we have air (with a refractive index close to 1) as the first medium and linseed oil as the second medium. Since the angle of incidence is not provided, we cannot directly calculate θ. However, we can relate ϕ to the angle of refraction in linseed oil.

The angle of refraction (ϕ) and the angle of incidence (θ) are related by the equation:

sin(θ) = sin(ϕ) / n

where n is the ratio of refractive indices:

n = n₁ / n₂

Given that n₁ (refractive index of air) is close to 1 and n₂ (refractive index of linseed oil) is 1.48, we can write:

sin(θ) = sin(ϕ) / 1.48

So, without the specific value of ϕ, we cannot determine θ.

The angle θ is not provided in your question. Therefore, without the value of θ, we cannot directly determine the angle of refraction in water using Snell's law. Snell's law relates the angle of incidence and the angle of refraction at an interface, provided the refractive indices of the two media.

If you provide additional information or clarify the given values, I will be able to assist you further.

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a) The frequency would a 1.6-ft-long nylon string that has a thickness of 3/32 in produce if put under an equal tension is 3.74 x \(10^{-5}\) kg/m.

b) The frequency would a 1.6-ft-long nylon string that has a thickness of 3/32 in produce if put under one-third of the original tension is 0.577.

The frequency of a string under tension is given by the equation f = (1 / 2L) × √(T / mu)

where f is the frequency, L is the length of the string, T is the tension in the string, and mu is the linear mass density of the string.

To calculate the frequency of a 1.6-ft-long nylon string with a thickness of 3/32 in, we need to first determine the linear mass density of the string. The linear mass density of a string is given by the formula:

mu = (m / L) = (p × A) / L

where mu is the linear mass density, m is the mass of the string, p is the density of the material of the string, A is the cross-sectional area of the string, and L is the length of the string.

The density of nylon is approximately 1.15 g/cm^3, and the cross-sectional area of the string can be calculated from its thickness:

A = (3/32 in)² × pi = 0.0293 in²

Converting the length of the string to inches, we get:

L = 1.6 ft × 12 in/ft = 19.2 in

Substituting these values into the equation for linear mass density, we get mu = (1.15 g/cm³ × 0.0293 in²) / 19.2 in = 0.00146 g/in

Converting this to the units used in the frequency equation, we get mu = 0.00146 g/in × 1 kg/1000 g × 1 m/39.37 in = 3.74 x \(10^{-5}\) kg/m

Now that we have calculated the linear mass density of the string, we can use the frequency equation to determine the frequency of the string under different tensions.

(a) If the string is put under equal tension, the frequency is given by f = (1 / 2L)

b) The original tension in the string is T and the string is put under a tension of T/3, the frequency will be reduced by a factor of √(1/3) = 0.577, or about 58% of the original frequency.

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Answer:

snow or rain

Explanation:

i know it has to be some kind of water , but I just don't know which one sadly . hope this helped :) !

Answer:

dust . i did this

Explanation:

Answer:

A. Proton

Explanation:

Given that an electron has a net negative charge equal in magnitude to the charge of a proton (1.602 × 10⁻¹⁹) but having an opposite (negative) sign to that of a proton, and given that like charges (negative to negative) repel and unlike charges attract, an object having;

Greater electron will be negatively charged relative to the other object, to which it is compare, which is a proton will attract the (positively charged) proton

Lesser negative charge compared to the proton; therefore, both objects will be positive, and they will repel each other

We therefore have;

Having greater or less electrons possessed by an object. Can attract or repel a proton

The correct option is option A. proton

The electric potential at the midpoint of the rectangle is 5.15 × 10^5 V.

Electric potential, also known as electric potential energy per unit charge, is a scalar quantity that describes the amount of work that must be done to move a unit charge from one point to another in an electric field. It is a measure of the electric potential energy per unit charge at a given point in an electric field.

The electric potential at a point is equal to the sum of the electric potentials due to each of the point charges. The electric potential due to a point charge is given by:

V = k * Q / r

where

V = electric potential

k = Coulomb's constant

Q = charge of the point charge

r = distance from the point charge to the location of interest

To find the electric potential at the midpoint of the rectangle, we need to find the total electric potential due to the four point charges and divide it by four to find the electric potential at the midpoint.

First, let's find the distance from each point charge to the midpoint of the rectangle. Since the midpoint is located in the center of the rectangle, the distance from each point charge to the midpoint is equal to the side length of the rectangle divided by 2. Therefore, the distance from each point charge to the midpoint is (3 cm + 4 cm) / 2 = 3.5 cm.

Next, we can find the electric potential due to each point charge using the equation:

V = k * Q / r

where

Q = 2.0 µC = 2.0 * 10^-6 C

r = 3.5 cm = 0.035 m

Substituting the values into the equation:

V = (9.0 × 10^9 N * m^2/C^2) * (2.0 * 10^-6 C) / (0.035 m)

V = 5.14 × 10^5 V

So, the electric potential due to each point charge is 5.14 × 10^5 V. The total electric potential due to the four point charges is 4 * 5.14 × 10^5 V = 2.06 × 10^6 V. Finally, the electric potential at the midpoint is the total electric potential divided by 4:

V = 2.06 × 10^6 V / 4

V = 5.15 × 10^5 V

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A precise estimation of the water temperature at Multnomah Falls using only the sheer drop height would not be possible without considering the factors mentioned above.

The steady flow energy equation, also known as Bernoulli's equation, relates the pressure, velocity, and elevation of a fluid along a streamline. However, it does not directly provide a means to estimate the water temperature.

To estimate the water temperature at Multnomah Falls, additional information and considerations are required, such as:

Ambient Temperature: The air temperature in the surrounding environment can provide an indication of the potential range of water temperature.

Source of Water: Determining the source of the water, such as a river, groundwater, or snowmelt, can help infer the temperature characteristics.

Seasonal Variation: Considering the season and the associated temperature trends can provide insight into the potential water temperature range.

Geological and Climatic Factors: Understanding the geological characteristics of the area and the prevailing climate can help in assessing temperature patterns.

Data from Local Sources: Consulting local weather reports, hydrological surveys, or other relevant sources that provide water temperature data in the vicinity of Multnomah Falls can give a more accurate estimate.

It's important to note that water temperature can vary significantly in different locations, depths, and seasons, and it is influenced by various factors such as sunlight exposure, ambient temperature, and thermal properties of the environment.

Hence, a precise estimation of the water temperature at Multnomah Falls using only the sheer drop height would not be possible without considering the factors mentioned above.

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I hope I helped you^_^

As the electric field is present at a point on diameter the electric field intensity at the electric field components are parallel to the diameter hence they cancel out .

So the field is directed perpendicular towards the diameter

Option A

Answer:

The answer is D. You're Welcome !