what might happen to variables in a science experiment that would lead to unusable results?

Consider the following mechanism.

The overall balanced chemical equation : 2O₃  ---->   3O₂

The intermediates within the mechanism : O

The order with respect to each reactant :  2

The rate law for the overall reaction : R = k[O₃]²/[O]

The equations are :

O₃  ---->   O₂  +  O   fast

O₃  +   O  --->  2O₃   slow

a) The overall reaction is given as :

2O₃  ---->   3O₂

b) The intermediates within the mechanism is O.

c)  The order with respect to each reactant is 2

d) slow step rate : k[O][O₃]

at equilibrium, kc = [O][O₂] / [O₃]

The rate law = R = k[O₃]²/[O]

Thus, Consider the following mechanism.

The overall balanced chemical equation : 2O₃  ---->   3O₂

The intermediates within the mechanism : O

The order with respect to each reactant :  2

The rate law expression for the reaction : R = k[O₃]²/[O]

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Answer:

A homogeneous mixture is a solid, liquid or gaseous mixture that has the same proportions of its components throughout any given sample. Conversely, a heterogeneous mixture has components in which proportions vary throughout the sample.

Explanation:

Sugar dissolves and is spread throughout the glass of water. ... The sugar-water is a homogenous mixture while the sand-water is a heterogeneous mixture. Both are mixtures, but only the sugar-water can also be called a solution.

Answer:

I guess the answer is compound

Explanation:

Coz compound it is on there playing with me again Go ahead and paste it in the class

The frequency of gamma radiation is calculated to be = 1.11 *10^20 Hz.

A gamma radiation is also known as gamma ray. It is a penetrating form of electromagnetic radiation arising from radioactive decay of atomic nuclei. It consists of shortest wavelength electromagnetic waves, even shorter than X-rays.

Gamma rays can pass through the human body completely and as they pass through, they cause ionizations that damage tissue and DNA.

As we know that E= hf

Hence, f= E/h

Given E=  6.96 x 10-14 J

And, Planck's constant, h = 6.626 *10^-34 m² kg/s

f = 6.96 * 10^-14J  +/6.626 *10^-34

f = 1.11 *10^20 Hz

Hence, frequency of gamma radiation = 1.11 *10^20 Hz.

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The carbon that is SP2 hybridized in the compound is carbon 4 (C4).

When we talk about the hybridization of the carbon atom, we mean the fact that the orbitals that are in the carbon atom are mixed in such a way that the orbitals that have the appropriate energy to be able to participate in the chemical bonds are formed.

As such looking at the compound that we have been shown in the image, we can see that not all the carbon atoms would be at the same state of hybridization.

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Answer:

(a) Rate of formation of NO2 is also 0.066M/s

(b) Rate of reaction of O2 gas is 0.033M/s

Explanation:

(a) in one second, according to the equation,

2 moles of NO combines with 2moles of NO2.

Therefore 0.066M NO will still consume 0.066mole NO2.

(b) According to the equation,

2 moles NO consumes 1 mole O2, 0.0666M will consume 0.0333 mole O2

Answer:

5l NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

2

=5N

A

O

2

molecules

D) 5×10

23

molecules of CO

2

(g)

Molecules of 5l NO

2

(g) at STP=5l of CH

4

(g) molecules at STP

Therefore, option B is correct.

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Answer:

154 g

Explanation:

Step 1: Write the balanced decomposition equation

2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)

Step 2: Calculate the moles corresponding to 79.5 L of N₂ at STP

At STP, 1 mole of N₂ occupies 22.4 L.

79.5 L × 1 mol/22.4 L = 3.55 mol

Step 3: Calculate the number of moles of NaN₃ needed to form 3.55 moles of N₂

The molar ratio of NaN₃ to N₂ is 2:3. The moles of NaN₃ needed are 2/3 × 3.55 mol = 2.37 mol.

Step 4: Calculate the mass corresponding to 2.37 moles of NaN₃

The molar mass of NaN₃ is 65.01 g/mol.

2.37 mol × 65.01 g/mol = 154 g

Answer:

\(5.5 \times {10}^{ - 5} \: cm\)

Explanation:

We know, that:

\(1nm \: = \: 1 \times {10}^{ - 7} \: cm \)

Now, we can make a proportion according to this:

1nm - 1×10^-7 cm

550 nm - x cm

\(x = \frac{550 \times 1 \times {10}^{ - 7} }{1} = 550 \times {10}^{ - 7} = 5.5 \times {10}^{ - 5} \: cm \: = 0.000055 \: cm\)

Answer:

Explanation:

Propionic acid  has chemical formula of  C₃H₆O₂ , and smells somewhat unpleasant (like body odour).

The volume in of a 0.600 M NaCl solution that contains 0.00123 moles of NaCl is 2.05mL

The volume of a substance can be calculated using the following expression:

molarity = no. of moles ÷ volume

According to this question, a 0.600 M NaCl solution contains 0.00123 moles of NaCl.

volume = 0.00123 moles ÷ 0.600 M

volume = 0.00205L

Therefore, the volume in of a 0.600 M NaCl solution that contains 0.00123 moles of NaCl is 2.05mL.

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Answer:

cannot be measure

Hope this helps :) !!!

Answer:

57.47 grams of sodium is in the sample.

Explanation:

Given that a 100.0-g sample of sodium hydroxide contains sodium, oxygen, and hydrogen, and the sample contains 2.53 g of hydrogen and 40.0 g of oxygen, to determine what mass of sodium is in the sample the following calculation must be performed:

100 - (40 + 2.53) = X

100 - 42.53 = X

57.47 = X

Therefore, 57.47 grams of sodium is in the sample.

Using phenolphthalein instead of bromocresol green for standardizing HCl would likely give a different endpoint and thus a different titration result.

This refers to the  the process of getting the exact concentration (molarity) of a solution. Titration is one type of analytical methods often used in standardization. During a titration, an exact volume of one substance is reacted with a known amount of another substance.

Phenolphthalein has a different pH range for its color change (8.2-10.0) compared to bromocresol green (3.8-5.4), which could lead to different titration endpoints and result in an inaccurate determination of the concentration of HCl. Therefore, it is important to use the indicator specified in the experimental protocol to ensure accurate and precise results.

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Answer:

After 15 minutes,the volume of the balloon stops expanding

Answer:

i dont speak mexican

Explanation:

Answer:

ExplanationIt is moving from 4s to 8s at a constant speed of 4 cm:

Answer:

Boiling points increase as the number of carbons is increased.

Explanation:

The addition of solutes or other substances usually changes the boiling point. Additionally, changing the pressure on a liquid changes its boiling point. Sugar, salt or other non-volatile solutes in water will usually make the boiling point higher.

The relative strength of the four intermolecular forces is: Ionic > Hydrogen bonding > dipole dipole > Van der Waals dispersion forces. The influence of each of these attractive forces will depend on the functional groups present. Boiling points increase as the number of carbons is increased.

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer: it's nonmetal

Explanation: Sulfur has characteristics of nonmetals. It does not have luster, it cannot conduct electricity, and it is brittle. On the periodic table, sulfur is in group 16/VIA, in the third period. The group is called the oxygen group or the chalcogens.

Answer:

i dont know

Explanation:

This experiment shows that the elements of pure solid substance in a system closed off from the surroundings has increased temperature very fast.

Pure substances are substances that are built up of only one kind of particle and have a fixed or abiding structure. Pure substances are further confidential as elements and compounds. An element is a substance that comprises only one type or kind of atom. a pure substance has a constant chemical composition.

No affair where you sample a substance, it is the same. For chemistry, the safest examples of pure substances are elements and compounds. So, examples cover gold, silver, helium, sodium chloride, and pure water.

So we can conclude that In chemistry, a pure substance is an element or compound made up of one type of particle.

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The formula you provided calculates the percent change in pH based on the difference between the pH at 5 drops and the pH at 0 drops. Here's how you can use the formula:

1. Determine the pH at 5 drops and the pH at 0 drops.

Let's say the pH at 5 drops is 4 and the pH at 0 drops is 7.

2. Plug the values into the formula:

Percent Change of pH = 100% × (pH at 5 drops - pH at 0 drops) / pH at 0 drops

Percent Change of pH = 100% × (4 - 7) / 7

3. Calculate the numerator:

4 - 7 = -3

4. Calculate the denominator:

Percent Change of pH = 100% × (-3) / 7

5. Calculate the percent change:

Percent Change of pH = -300% / 7

Therefore, the percent change in pH from 0 drops to 5 drops is approximately -42.86%.

25.0grams of bromine is equivalent to 1.881 × 10²³ molecules.

The number of molecules of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number (6.02 × 10²³).

Avogadro's number is the number of atoms present in 12 grams of isotopically pure carbon-12, being 6.02214076 × 10²³. By definition, it is the number of elementary entities (atoms or molecules) comprising one mole of a given substance.

According to this question, sodium is combined with bromine to produce sodium bromide. If one uses 25.0g of bromine, the number of moles of bromine used is as follows:

no of moles = 25.0g ÷ 80g/mol

no of moles = 0.3125moles

no of molecules = 0.3125 × 6.02 × 10²³ = 1.881 × 10²³ molecules

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Answer:

Elements

Explanation:

Answer:

1.98 M

Explanation:

Step 1: Write the balanced reaction

2 NH₃ + 3 BrO⁻⟶ N₂ + 3 Br⁻ + 3 H₂O

Step 2: Calculate the moles corresponding to 0.325 g of ammonia

The molar mass of NH₃ is 17.03 g/mol.

0.325 g × (1 mol/17.03 g) = 0.0191 mol

Step 3: Calculate the reacting moles of hypobromite

The molar ratio of NH₃ to BrO⁻ is 2:3. The reacting moles of hypobromite are 3/2 × 0.0191 mol = 0.0287 mol

Step 3: Calculate the molar concentration of the hypobromite solution

M = 0.0287 mol / 0.0145 L = 1.98 M

The concentration of the hypobromite solution (BrO⁻) needed for the reaction is 1.97 M

We'll begin by calculating the number of mole in 0.325 g of NH₃. This can be obtained as follow:

Mass of NH₃ = 0.325 g

Molar mass of NH₃ = 17.031 g/mol

Mole = mass / molar mass

Mole of NH₃ = 0.325 / 17.031

Next, we shall determine the number of mole of BrO⁻ needed to react with 0.01908 mole of NH₃. This can be obtained as follow:

2NH₃ + 3BrO⁻ —> N₂ + 3Br⁻ + 3H₂O

From the balanced equation above,

2 moles of NH₃ reacted with 3 moles of BrO⁻.

Therefore,

0.01908 mole of NH₃ will react with = \(\frac{0.01908 * 3 }{2}\\\\\) = 0.02862 mole of BrO⁻.

Finally, we shall determine the concentration of the BrO⁻ solution.

Mole of BrO⁻ = 0.02862 mole

Volume of BrO⁻ solution = 14.5 mL = 14.5 / 1000 = 0.0145 L

Concentration = mole / Volume

Concentration of BrO⁻ = 0.02862 / 0.0145

Therefore, the concentration of the hypobromite solution (BrO⁻) is 1.97 M

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Explanation:

filling air inside an empty o2 medal containers, if air is added, the air inside, creates volume inside.

due to heat, weather,... depending on what indoor or outdoor storage said containers r placed in,;

So, I can't give you an answer, due to lack of details..sorry...

Answer:

A small amount of chemical splashes in Frank's eye. What should happen next? Frank should go to the eyewash station while his lab partner tells the teacher what happened.

Explanation:

Brainlist

Answer:

I think its Kr

Explanation:

sorry if I'm wrong

Bromine (Br₂) has the highest melting point among the given elements. Therefore, option (A) is correct.

Intermolecular forces can be described as the attractive and repulsive forces that develop between the molecules of a substance. These forces are responsible for most of the chemical and physical properties of matter. The intermolecular forces between the molecules are Vander Waals forces.

Forces that exist between the molecules themselves are known as intermolecular forces. The particles of solids and liquids are held together by intermolecular forces.

The intermolecular forces are Dipole-Dipole Interactions, Ion-Dipole Interactions, Ion-Induced Dipole Interactions, Dipole-Induced Dipole Interaction, and Dispersion Forces.

As the size of the atoms increases the strength of the intermolecular force also increases and a large amount of energy will be required to break bonds. Since Bromine has the largest size among the all other elements. Therefore, Bromine will have the highest melting point.

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Your question was incomplete, but the complete question was,

On the basis of the strength of intermolecular forces, which of the following elements would be expected to have the highest melting point?

A) Br₂

B) Cl₂

C) F₂

D) N₂